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  • Write an expression in javascript

    - by Hero
    hi everybody... I need a javascript code that split a string like below: Input string: "a=aa| b=b||b | c=cc" Output: a=>aa b=>b||b c=>cc I'd written different codes like: split(/ \ | /) or Split(/ \| (?! \ |) /) but didn't work. please help me... I really need it fast.

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  • Java regular expression: how to include '-'

    - by changed
    I am using this pattern and matching a string. String s = "//name:value /name:value"; if (s.matches("(//?\\s*\\w+:\\w+\\s*)+")) { // it fits } This works properly. But if I want to have a string like "/name-or-address:value/name-or-address:value" which has this '-' in second part, it doesn't work. I am using \w to match A-Za-z_, but how can I include - in that?

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  • Match a comma followed by a newline with a regular expression

    - by MarathonStudios
    I have a comma delimited list I want to import into a database, and in some cases the last item is blank: item1, item2, item3 item1, item2, item1, item2, I'd like to replace all of these empty columns with a placeholder value using a regexp item1, item2, item3 item1, item2, PLACEHOLDER item1, item2, PLACEHOLDER I tried preg_replace("/,\n/", ",PLACEHOLDER\n",$csv);, but this isn't working. Anyone know what regexp would work for this?

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  • Javascript: regular expression

    - by Dmitry Nesteruk
    I need to replace a substring from some string. I've already created corrected code for doing it. But I amn't sure is it best way. Please, see code below: var str = 'test ruby,ruby on rails,ruby,' var substr = 'ruby'; var reg = new RegExp(',' + substr + ',|^' + substr + ',', 'gi'); str.replace(reg, ','); //returns "test ruby,ruby on rails,"

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  • VB.net Regular Expression

    - by xzerox
    Alright so I want to grab the information on a website thats between [usernames] and [/usernames] I know how to get the string but how would I use regex to only have the information in the middle. Remember I am going to be having more then one thing on the page.

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  • How optimize by lambda expression

    - by simply denis
    I have a very similar function is only one previous report and the other future, how can I optimize and write beautiful? public bool AnyPreviousReportByGroup(int groupID) { if(this.GroupID == groupID) { return true; } else { return PreviousReport.AnyPreviousReportByGroup(groupID); } } public bool AnyNextReportByGroup(int groupID) { if (this.GroupID == groupID) { return true; } else { return NextReport.AnyNextReportByGroup(groupID); } }

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  • Complex regular expression

    - by Jose3d
    Hello, i will like to capture a substring part of a text choosing the number of characters but if any word is cut then get until de last blank. As example if this is the text: "This is an example of text lorem ipsum, etc..." and i would like to get for instance 12 characters that are: "This is an e". In this case example is cutted, then i would like to get "This is an". Its possible do this with Regular Expressions? Thanks in advance. Jose

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  • Regex "or" Expression

    - by David
    This is probably a really basic question, but I can't find any answers. I need to match a string by either one or more spaces OR an equals sign. When I split this string: 9 x 13 = (8.9 x 13.4) (89 x 134) with ( +) I get: part 0: 9 x 13 = (8.9 x 13.4) part 1: (89 x 134) When I split it with (=) I get: part 0: 9 x 13 part 1: (8.9 x 13.4) (89 x 134) How can split by BOTH? Something like: (=)OR( +) Edit: This does not work(=)|( +) Test it here: http://myregexp.com/ under "split".

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  • Python regular expression

    - by user3692739
    I have this HTTP Request and I want to display only the Authorization section (base64 Value) : any help ? This Request is stored on a variable called hreq I have tried this : reg = re.search(r"Authorization:\sBasic\s(.*)\r", hreq) print reg.group() but doesn't work Here is the request : HTTP Request: Path: /dynaform/custom.js Http-Version: HTTP/1.1 Host: 192.168.1.254 Accept-Language: en-US,en;q=0.5 Accept-Encoding: gzip, deflate Referer: http://domain.com/userRpm/StatusRpm.htm Authorization: Basic YWhtEWa6MDfGcmVlc3R6bGH I want to display the value YWhtEWa6MDfGcmVlc3R6bGH Please I need your help thanks in advance experts

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  • Regular expression Not working properly n case of multiple trailing ]]]]

    - by ronan
    I have the requirement that in a textbox a user can jump to the next word enclosed in [] on a tab out for example Hi [this] is [an] example. Testing [this] So when my cursor is at Hi and I do a tab out , the characters enclosed in the [this] are highlighted and when I again do a tabl out th next characters enclosed in following [an] are highlighted. This works fine Now the requirement is whatever the text including the special chars between [] needs to be highlighted case 1: when I have trailing ]]], it only highlights leading [[[ and ignores ]]]] e.g case 2: In case of multiple trailing ] e.e [this]]]] is [test], ideally one a single tabl out from this , it should go to next text enclosed in [] but a user has to tab out 4 times one tab per training ] to go to next [text] strong text The code is $(document).ready(function() { $('textarea').highlightTextarea({ color : '#0475D1', words : [ "/(\[.*?\])/g" ], textColor : '#000000' }); $('textarea').live('keydown', function(e) { var keyCode = e.keyCode || e.which; if (keyCode == 9) { var currentIndex = getCaret($(this).get(0)) selectText($(this), currentIndex); return false; } }); }); function selectText(element, currentIndex) { var rSearchTerm = new RegExp(/(\[.*?\])/); var ind = element.val().substr(currentIndex).search(rSearchTerm) currentIndex = (ind == -1 ? 0 : currentIndex); ind = (ind == -1 ? element.val().search(rSearchTerm) : ind); currentIndex = (ind == -1 ? 0 : currentIndex); var lasInd = (element.val().substr(currentIndex).search(rSearchTerm) == -1 ? 0 : element.val().substr(currentIndex).indexOf(']')); var input = element.get(0); if (input.setSelectionRange) { input.focus(); input.setSelectionRange(ind + currentIndex, lasInd + 1 + currentIndex); } else if (input.createTextRange) { var range = input.createTextRange(); range.collapse(true); range.moveEnd('character', lasInd + 1 + currentIndex); range.moveStart('character', ind + currentIndex); range.select(); } } function getCaret(el) { if (el.selectionEnd) { return el.selectionEnd; } else if (document.selection) { el.focus(); var r = document.selection.createRange(); if (r == null) { return 0; } var re = el.createTextRange(), rc = re.duplicate(); re.moveToBookmark(r.getBookmark()); rc.setEndPoint('EndToStart', re); return rc.text.length; } return 0; } Please let me know to handle two above cases

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  • Php regular expression to match a div

    - by Thoman
    Hello all <div id="a"> <div id="b"> Foo </div> <div id="m"> Bar </div> </div> <div id="c"> Bar </div> I want find all object in id="a" and out put is <div id="a"> <div id="b"> Foo </div> <div id="m"> Bar </div> </div> Geat thanks.

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  • Regular Expression to parse SQL Structure

    - by user351429
    I am trying to parse the MySQL data types returned by "DESCRIBE [TABLE]". It returns strings like: int(11) float varchar(200) int(11) unsigned float(6,2) I've tried to do the job using regular expressions but it's not working. PHP CODE: $string = "int(11) numeric"; $regex = '/(\w+)\s*(\w+)/'; var_dump( preg_split($regex, $string) );

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  • Regular expression on a URL

    - by alphaexe
    I need to be able to catch when the URL contains a image of multiple file types or follow this syntax. http://localhost:8080/fdlic-web/webpic/101 Here is what i have so far. (.*)(jpg|gif|png|bmp|jpeg|webpic/(\d+))$

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  • Pick up relevant information from a string using regular expression C#3.0

    - by Newbie
    Hi, I have a situation. I have been given some file name which can be like <filename>YYYYMMDD<fileextension> some valid file names that will satisfy the above pattern are as under xxx20100326.xls, xxx2v20100326.csv, x_20100326.xls, xy2z_abc_20100326_xyz.csv, abc.xyz.20100326.doc, ab2.v.20100326.doc, abc.v.20100326_xyz.xls In what ever be the above defined case, I need to pick up the dates only. So for all the cases, the output will be 20100326. I am trying to achieve the same but no luck. Here is what I have done so far string testdata = "x2v20100326.csv"; string strYYYY = @"\d{4}"; string strMM = @"(1[0-2]|0[1-9])"; string strDD = @"(3[0-1]|[1-2][0-9]|0[1-9])"; string regExPattern = @"\A" + strYYYY + strMM + strDD + @"\Z"; Regex regex = new Regex(regExPattern); Match match = regex.Match(testdata); if (match.Success) { string result = match.Groups[0].Value; } I am using c#3.0 and dotnet framework 3.5 Please help. It is very urgent Thanks in advance.

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  • regular expression not behaving as expected - Python

    - by philippe
    I have the following function which is supposed to read a .html file and search for <input> tags, and inject a <input type='hidden' > tag into the string to be shown into the page. However, that condition is never met:( e.g the if statement is never executed. ) What's wrong with my regex? def print_choose( params, name ): filename = path + name f = open( filename, 'r' ) records = f.readlines() print "Content-Type: text/html" print page = "" flag = True for record in records: if re.match( '<input*', str(record) ) != None: print record page += record page += "<input type='hidden' name='pagename' value='psychology' />" else: page += record print page Thank you

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  • How to escape regular expression in javascript ?

    - by Relax
    My codes is like pattern = 'arrayname[1]'; // fetch from dom, make literal here just for example reg = new RegExp(RegExp.quote(pattern), 'g'); mystring.replace(reg, 'arrayname[2]'); But it just cannot get running with error message says: "RegExp.quote is not a function", am i missing something simple?

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  • Correct expression for checking leap years

    - by Debanjan
    What will be the exact definition of leap year? AFAIK "A year which is divisible by 4 is a leap year. But for century years' the years which are divisible by 400 is a leap year." But that definition makes 100, 200, 300, 400.... upto 1700 NOT LEAP years! But in Gregorian calendar all of them are all leap year, check this out. You can also try "call 1700" in Linux to verify. So the correct algorithm for leap years would be: if ( (year % 4 == 0) && ( year <= 1700 || year % 100 != 0 || year % 400 == 0 )) printf("%d is a leap year.\n", year); else printf("%d is not a leap year.\n", year); But is this specific to Gregorian calendar? Even if that is the case why is it not mentioned here? Regards, PS:The history of Gregorian callender seems interesting check out the September month of 1752.

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  • antlr line after line processing

    - by pawloch
    I'm writing simple language in ANTLR, and I'd like to write shell where I can put line of code, hit ENTER and have it executed, enter another line, and have it executed. I have already written grammar which execute all alines of input at one. Example input: int a,b,c; string d; string e; d=\"dziala\"; a=4+7; b=a+33; c=(b/11)*2; grammar Kalkulator; options { language = Java; output=AST; ASTLabelType=CommonTree; } tokens { NEG; } @header { package lab4; } @lexer::header { package lab4; } line : (assignment | declaration)* EOF ; declaration : type^ IDENT (','! IDENT)* ';'! ; type : 'int' | 'string' ; assignment : IDENT '='^ expression ';'! ; term : IDENT | INTEGER | STRING_LITERAL | '('! expression ')'! ; unary : (( negation^ | '+'! ))* term ; negation : '-' -> NEG ; mult : unary ( ('*'^ | '/'^) unary )* ; exp2 :mult ( ('-'^ | '+'^) mult)* ; expression : exp2 ('&'^ exp2)* ; fragment LETTER : ('a'..'z'|'A'..'Z'); fragment DIGIT : '0'..'9'; INTEGER : DIGIT+; IDENT : LETTER (LETTER | DIGIT)* ; WS : (' ' | '\t' | '\n' | '\r' | '\f')+ {$channel=HIDDEN;}; STRING_LITERAL : '\"' .* '\"'; and: tree grammar Evaluator; options { language = Java; tokenVocab = Kalkulator; ASTLabelType = CommonTree; } @header { package lab4; import java.util.Map; import java.util.HashMap; } @members { private Map<String, Object> zmienne = new HashMap<String, Object>(); } line returns [Object result] : (declaration | assignment { result = $assignment.result; })* EOF ; declaration : ^(type ( IDENT { if("string".equals($type.result)){ zmienne.put($IDENT.text,""); //add definition } else{ zmienne.put($IDENT.text,0); //add definition } System.out.println($type.result + " " + $IDENT.text);//write output } )* ) ; assignment returns [Object result] : ^('=' IDENT e=expression) { if(zmienne.containsKey($IDENT.text)) {zmienne.put($IDENT.text, e); result = e; System.out.println(e); } else{ System.out.println("Blad: Niezadeklarowana zmienna"); } } ; type returns [Object result] : 'int' {result="int";}| 'string' {result="string";} ; expression returns [Object result] : ^('+' op1=expression op2=expression) { result = (Integer)op1 + (Integer)op2; } | ^('-' op1=expression op2=expression) { result = (Integer)op1 - (Integer)op2; } | ^('*' op1=expression op2=expression) { result = (Integer)op1 * (Integer)op2; } | ^('/' op1=expression op2=expression) { result = (Integer)op1 / (Integer)op2; } | ^('%' op1=expression op2=expression) { result = (Integer)op1 \% (Integer)op2; } | ^('&' op1=expression op2=expression) { result = (String)op1 + (String)op2; } | ^(NEG e=expression) { result = -(Integer)e; } | IDENT { result = zmienne.get($IDENT.text); } | INTEGER { result = Integer.parseInt($INTEGER.text); } | STRING_LITERAL { String t=$STRING_LITERAL.text; result = t.substring(1,t.length()-1); } ; Can I make it process line-by-line or is that easier to make it all again?

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  • regular expression on replace method of js not working

    - by user950146
    why this is not working var value = arr[row][col].replace(new RegExp('"', 'g'),'""'); Error : Webpage error details User Agent: Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 6.1; Trident/4.0; SLCC2; .NET CLR 2.0.50727; .NET CLR 3.5.30729; .NET CLR 3.0.30729; Media Center PC 6.0; InfoPath.2; Tablet PC 2.0) Timestamp: Tue, 10 Apr 2012 11:22:01 UTC Message: Object doesn't support this property or method Line: 1041 Char: 25 Code: 0 URI: http://example.com/? Message: Object doesn't support this property or method Line: 1041 Char: 25 Code: 0 URI: http://example.com/? Message: Object doesn't support this property or method Line: 1041 Char: 25 Code: 0 URI: http://example.com/? Note: : Error copied directly from debugger of IE8

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  • using regular expression / Remove special characters with linq to sql

    - by Prasad
    How can i use regular expressions with linq to sql in the asp.net mvc(C#) application? The columns in my MSSQL table (Products) has some special characters like (, - % ',.....). While searching for a product i need to search without that special chareters. For ex.: I have a product say (ABC-Camp's / One), when i search for "abccamp", it should pull the product. I am trying the query like: from p in _context.pu_Products where p.User_Id == userId && p.Is_Deleted == false && p.Product_Name.ToLower().Contains(text.ToLower()) select new Product { ProductId = p.Product_Id, ProductName = p.Product_Name.Replace("’", "").Replace("\"", ""), RetailPrice = p.Retail_Price ?? 0M, LotSize = p.Lot_Size > 0 ? p.Lot_Size ?? 1 : 1, QuantityInHand = p.Quantity_In_Hand ?? 0 } But i need to search without any special characters...

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