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  • Template with constant expression: error C2975 with VC++2008

    - by Arman
    Hello, I am trying to use elements of meta programming, but hit the wall with the first trial. I would like to have a comparator structure which can be used as following: intersect_by<ID>(L1.data, L2.data, "By ID: "); intersect_by<IDf>(L1.data, L2.data, "By IDf: "); Where: struct ID{};// Tag used for original IDs struct IDf{};// Tag used for the file position //following Boost.MultiIndex examples template<typename Tag,typename MultiIndexContainer> void intersect_by( const MultiIndexContainer& L1,const MultiIndexContainer& L2,std::string msg, Tag* =0 /* fixes a MSVC++ 6.0 bug with implicit template function parms / ) { / obtain a reference to the index tagged by Tag */ const typename boost::multi_index::index<MultiIndexContainer,Tag>::type& L1_ID_index= get<Tag>(L1); const typename boost::multi_index::index<MultiIndexContainer,Tag>::type& L2_ID_index= get<Tag>(L2); std::set_intersection( L1_ID_index.begin(), L1_ID_index.end(), L2_ID_index.begin(), L2_ID_index.end(), std::inserter(s, s.begin()), strComparator() // Here I get the C2975 error ); } template<int N> struct strComparator; template<> struct strComparator<0>{ bool operator () (const particleID& id1, const particleID& id2) const { return id1.ID struct strComparator<1{ bool operator () (const particleID& id1, const particleID& id2) const { return id1.IDf }; What I am missing? kind regards Arman.

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  • Which LINQ expression is faster

    - by Vlad Bezden
    Hi All In following code public class Person { public string Name { get; set; } public uint Age { get; set; } public Person(string name, uint age) { Name = name; Age = age; } } void Main() { var data = new List<Person>{ new Person("Bill Gates", 55), new Person("Steve Ballmer", 54), new Person("Steve Jobs", 55), new Person("Scott Gu", 35)}; // 1st approach data.Where (x => x.Age > 40).ToList().ForEach(x => x.Age++); // 2nd approach data.ForEach(x => { if (x.Age > 40) x.Age++; }); data.ForEach(x => Console.WriteLine(x)); } in my understanding 2nd approach should be faster since it iterates through each item once and first approach is running 2 times: Where clause ForEach on subset of items from where clause. However internally it might be that compiler translates 1st approach to the 2nd approach anyway and they will have the same performance. Any suggestions or ideas? I could do profiling like suggested, but I want to understand what is going on compiler level if those to lines of code are the same to the compiler, or compiler will treat it literally. Thanks in advance for your help.

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  • PHP regular expression find and append to string

    - by Gary
    I'm trying to use regular expressions (preg_match and preg_replace) to do the following: Find a string like this: {%title=append me to the title%} Then extract out the title part and the append me to the title part. Which I can then use to perform a str_replace(), etc. Given that I'm terrible at regular expressions, my code is failing... preg_match('/\{\%title\=(\w+.)\%\}/', $string, $matches); What pattern do I need? :/

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  • Matching Regular Expression in Javascript and PHP problem...

    - by Frankie
    I can't figure out how to get the same result from my Javscript as I do from my PHP. In particular, Javascript always leaves out the backslashes. Please ignore the random forward and backslashes; I put them there so that I can cover my basis on a windows system or any other system. Output: Input String: "/root\wp-cont ent\@*%'i@$@%$&^(@#@''mage6.jpg:" /root\wp-content\image6.jpg (PHP Output) /rootwp-contentimage6.jpg (Javscript Output) I would appreciate any help! PHP: <?php $path ="/root\wp-cont ent\@*%'i@$@%$&^(@#@''mage6.jpg:"; $path = preg_replace("/[^a-zA-Z0-9\\\\\/\.-]/", "", $path); echo $path; ?> Javascript: <script type="text/javascript"> var path = "/root\wp-cont ent\@*%'i@$@%$&^(@#@''mage6.jpg:"; //exact same string as PHP var regx = /[^a-zA-Z0-9\.\/-]/g; path = path.replace(regx,""); document.write("<br>"+path); </script>

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  • Convert this Linq query from query syntax to lambda expression

    - by Jinkinz
    I'm not sure I like linq query syntax...its just not my preference. But I don't know what this query would look like using lambda expressions, can someone help? from securityRoles in user.SecurityRoles from permissions in securityRoles.Permissions where permissions.SecurableEntity.Name == "Unit" && permissions.PermissionType.Name == "Read" orderby permissions.PermissionLevel.Value descending select permissions There is a many-to-many relationship between users and security roles that makes this extra confusing. Thanks! Kelly

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  • linq-to-sql combine .any expression

    - by Victor
    I need to filter out parent by property value of child collection. I am doing something like this: var results = (from c in db.Customers where c.Orders.Any(o => o.Status = (int)Status.Ordered) select c; It's fine but now I need to filter by 2 values, i.e. take all parent records that have any chilren records that have BOTH values: var results = (from c in db.Customers where c.Orders.Any(o => o.Status == (int)Status.Ordered) && (o.Status == (int).Shipped)) select c; Trying something obvious like this doesn't work.

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  • regular expression to get the filename from urls

    - by robert
    if i have a textbox with severals urls rapidshare.com/files/379028801/Fringe.S02E19.HDTV.XviD-LOL.avi rapidshare.com/files/379182651/Fringe.S02E19.720p.HDTV.X264-DIMENSION.mkv rapidshare.com/files/379180004/Fringe.S02E19.720p.HDTV.X264-DIMENSION.part1.rar rapidshare.com/files/379180444/Fringe.S02E19.720p.HDTV.X264-DIMENSION.part2.rar rapidshare.com/files/379181251/Fringe.S02E19.720p.HDTV.X264-DIMENSION.part3.rar rapidshare.com/files/379181743/Fringe.S02E19.720p.HDTV.X264-DIMENSION.part4.rar i need a the files name and its urls textbox2.text = Fringe.S02E19.HDTV.XviD-LOL.avi from here rapidshare.com/files/379028801/Fringe.S02E19.HDTV.XviD-LOL.avi Fringe.S02E19.720p.HDTV.X264-DIMENSION.part1.rar from here rapidshare.com/files/379180004/Fringe.S02E19.720p.HDTV.X264-DIMENSION.part1.rar and so on Thanks :)

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  • Difference between generator expression and generator function

    - by Neil G
    Is there any difference — performance or otherwise — between generator expressions and generator functions? In [1]: def f(): ...: yield from range(4) ...: In [2]: def g(): ...: return (i for i in range(4)) ...: In [3]: f() Out[3]: <generator object f at 0x109902550> In [4]: list(f()) Out[4]: [0, 1, 2, 3] In [5]: list(g()) Out[5]: [0, 1, 2, 3] In [6]: g() Out[6]: <generator object <genexpr> at 0x1099056e0>

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  • Regular expression to validate a Google Analytics UA Number

    - by Otis
    It's not 100 percent clear to me that the Google Analytics UA Numbers are always 6 digits, a dash, and 2 digits as Google often mentions in their documentation. There are frequent counter-examples that use fewer than 6 for the account portion and 1-4 for the profile. All of the examples always show numbers but it's not even clear that they can't be letters. Does anyone know if Google has published a regex that exactly matches allowable UA Numbers? I'm adding this feature to the admin console of an application I work on and would like to validate the user input.

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  • LINQ: Dot Notation vs Query Expression

    - by Martín Marconcini
    I am beginning to use LINQ in general (so far toXML and toSQL). I've seen that sometimes there are two or more ways to achieve the same results. Take this simple example, as far as I understand both return exactly the same thing: SomeDataContext dc = new SomeDataContext(); var queue = from q in dc.SomeTable where q.SomeDate <= DateTime.Now && q.Locked != true orderby (q.Priority, q.TimeCreated) select q; var queue2 = dc.SomeTable .Where( q => q.SomeDate <= DateTime.Now && q.Locked != true ) .OrderBy(q => q.Priority) .ThenBy(q => q.TimeCreated); Besides any mistake I may have made in the syntax or a missing parameter or difference, the idea is that there are two ways to express the same thing; I understand that the first method has some limitations and that the "dot notation" is more complete, but besides that, are there any other advantages?

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  • Regular Expression Help in .NET

    - by Matt H.
    I have a simple pattern I am trying to match, any characters captured between parenthesis at the end of an HTML paragraph. I am running into trouble any time there is additional parentheticals in that paragraph: i.e. If the input string is "..... (321)</p" i want to get the value (321) However, if the paragraph has this text: "... (123) (321)</p" my regex is returning "(123) (321)" (everything between the opening "(" and closing ")" I am using the regex pattern "\s(.+)</p" How can I grab the correct value (using VB.NET) This is what I'm doing so far: Dim reg As New Regex("\s\(.+\)</P>", RegexOptions.IgnoreCase) Dim matchC As MatchCollection = reg.Matches(su.Question) If matchC.Count > 0 Then Dim lastMatch As Match = matchC(matchC.Count - 1) Dim DesiredValue As String = lastMatch.Value End If

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  • Clips matching expression is not working

    - by Bass
    hello in clips i have this template: (deftemplate cell(slot x)(slot y)(slot alive)) and this fact : (start 1 1) then i have this claus in the LHS : ?start<-(start ?x ?y) and i want to get the variable ?a1 (cell (x (+ ?x 1) )(y ?y)(alive ?a1)) it seems that it's not allowed to add to the variable "(+ ?x 1)" so how can i achive what i want.

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  • xml regular expression/regex OR operator

    - by Naz Haque
    Hi am trying to use a regeX to read through my document to identify currency types whether they're $,£ or a €. The regex I've created doesn't seem to work, somebody please advise me what it should be. I'd really appreciate the help: The regEX I've created ("\$|£|€]")is in a simpleType within my XSD file used for validating a document. The code is show after the colon, please note to display on stackoverflow I've had to remove the open/close tags (<): xs:simpleType name="currencyType" xs:restriction base="utf8-string" xs:length value="1" / xs:pattern value="[\$|£|€]"/ /xs:restriction /xs:simpleType

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  • python regular expression for domain names

    - by user230911
    I am trying use the following regression to extract domain name from a text, but it just produce nothing, what's wrong with it? I don't know if this is suitable to ask this "fix code" question, maybe I should read more. I just want to save some time. Thanks pat_url = re.compile(r''' (?:https?://)* (?:[\w]+[\-\w]+[.])* (?P<domain>[\w\-]*[\w.](com|net)([.](cn|jp|us))*[/]*) ''') print re.findall(pat_url,"http://www.google.com/abcde") I want the output to be google.com

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  • Regex - replace only last part of an expression

    I'm attempting to find the best methodology for finding a specific pattern and then replace the ending portion of the pattern. Here is a quick example (in C#): //Find any year value starting with a bracket or underscore string patternToFind = "[[_]2007"; Regex yearFind = new Regex(patternToFind); //I want to change any of these values to x2008 where x is the bracket or underscore originally in the text. I was trying to use Regex.Replace(), but cannot figure out if it can be applied. If all else fails, I can find Matches using the MatchCollection and then switch out the 2007 value with 2008; however, I'm hoping for something more elegant MatchCollections matches = yearFind.Matches(" 2007 [2007 _2007"); foreach (Match match in matches){ //use match to find and replace value }

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  • quartz cron expression help (daily trigger)

    - by djmlog103
    Hi, i want to run a cron trigger every 5th day starting from the 16th of every month. so it should execute on every: 16th, 21st, 26th, 31st, 5th, 10th, 15th, 20th and so on i tried "0 0 1 16/5 * ?" but this gets execute on 16th, 21st, 26th, 31st, 16th, 21st.... It skips anything between 1st and 15th. Please help. thanks

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  • Regular Expression Longes Possible Matching

    - by syker
    So I have an input string which is a directory addres: Example: ProgramFiles/Micro/Telephone And I want to match it against a list of words very strictly: Example: Tel|Tele|Telephone I want to match against Telephone and not Tel. Right now my reg looks like this: my( $output ) = ( $input =~ m/($list)/o ); The regex above will match against Tel. What can I do to fix it?

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  • Treetop basic parsing and regular expression usage

    - by ucint
    I'm developing a script using the ruby Treetop library and having issues working with its syntax for regex's. First off, many regular expressions that work in other settings dont work the same in treetop. This is my grammar: (myline.treetop) grammar MyLine rule line string whitespace condition end rule string [\S]* end rule whitespace [\s]* end rule condition "new" / "old" / "used" end end This is my usage: (usage.rb) require 'rubygems' require 'treetop' require 'polyglot' require 'myline' parser = MyLineParser.new p parser.parse("randomstring new") This should find the word new for sure and it does! Now I wont to extend it so that it can find new if the input string becomes "randomstring anotherstring new yetanother andanother" and possibly have any number of strings followed by whitespace (tab included) before and after the regex for rule condition. In other words, if I pass it any sentence with the word "new" etc in it, it should be able to match it. So let's say I change my grammar to: rule line string whitespace condition whitespace string end Then, it should be able to find a match for: p parser.parse("randomstring new anotherstring") So, what do I have to do to allow the string whitespace to be repeated before and after condition? If I try to write this: rule line (string whitespace)* condition (whitespace string)* end , it goes in an infinite loop. If i replace the above () with [], it returns nil In general, regex's return a match when i use the above, but treetop regex's dont. Does anyone have any tips/points on how to go about this? Plus, since there isn't much documentation for treetop and the examples are either too trivial or too complex, is there anyone who knows a more thorough documentation/guide for treetop?

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  • PHP Regular Expression

    - by saturngod
    I want to change &lt;lang class='brush:xhtml'&gt;test&lt;/lang&gt; to <pre class='brush:xhtml'>test</pre> my code like that. <?php $content="&lt;lang class='brush:xhtml'&gt;test&lt;/lang&gt;"; $pattern=array(); $replace=array(); $pattern[0]="/&lt;lang class=([A-Za-z='\":])* &lt;/"; $replace[0]="<pre $1>"; $pattern[1]="/&lt;lang&gt;/"; $replace[1]="</pre>"; echo preg_replace($pattern, $replace,$content); ?> but it's not working. How to change my code or something wrong in my code ?

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