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  • How to access stdClass variables stdClass Object([max(id)])=>64)

    - by Theopile
    I need the very last valid entry in a database table which would be the row with the greatest primary key. So using mysqli, my query is "SELECT MAX(id) FROM table LIMIT 1". This query returns the correct number(using print_r()) but I cannot figure out how to access it. Here is the main code. Note that the $this-link refers to class with a mysqli connection. $q="select max(id) from stones limit 1"; $qed=$this->link->query($q) or die(mysqli_error()); if($qed){ $row=$qed->fetch_object(); print_r($row); echo $lastid=$row;//here is the problem } The valid line print_r($row) echos out "stdClass Object ( [max(id)] = 68 )"

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  • Search & Replace SQL

    - by Shonna
    I am messing around with one of my databases.. is there away for me to search for a string in ALL the tables.. and replace it with another everywhere it occurs? I am looking for SQL

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  • Creating a Variable that is the Sum of Two Other Variables

    - by John
    Hello, For the code below, I would like to make a new variable called totalScore2 that equals days + totalScore. How can I do this? Thanks in advance, John $sqlStr = "SELECT l.loginid, l.username, l.created, DATEDIFF(NOW(), l.created) AS days, COALESCE(s.total, 0) AS countSubmissions, COALESCE(c.total, 0) AS countComments, COALESCE(s.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore

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  • Subversion error, but I don't know what it means

    - by DaveDev
    I'm trying to do an Update on my solution but I'm getting the following subversion error: SharpSvn.SvnFileSystemException: Working copy path 'Path_to_image/logo LoRes.jpg' does not exist in repository but I can see that the image is in the repository. The stack trace is as follows: at SharpSvn.SvnClientArgs.HandleResult(SvnClientContext client, SvnException error) at SharpSvn.SvnClientArgs.HandleResult(SvnClientContext client, svn_error_t* error) at SharpSvn.SvnClient.Update(ICollection`1 paths, SvnUpdateArgs args, SvnUpdateResult& result) at SharpSvn.SvnClient.Update(String path, SvnUpdateArgs args, SvnUpdateResult& result) at Ankh.Commands.SolutionUpdateCommand.UpdateRunner.Work(Object sender, ProgressWorkerArgs e) at Ankh.ProgressRunnerService.ProgressRunner.Run(Object arg) Is there something else that could be wrong?

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  • How can I write this query in Django? (datetime)

    - by alex
    | time_before | datetime | YES | MUL | NULL | | | time_after | datetime | YES | MUL | NULL | | the_tag = Tag.objects.get(id=tag_id) Log.objects.filter(blah).extra(where=['last_updated >'+the_tag.time_before, 'last_updated' < the_tag.time_after]) Ok. Basically, I have an object that's called "the_tag". I want to select from Log where log.last_updated (which is a datetime field) is between the tag's time. But, I don't know how to write the last part of this Django query.

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  • Auto deployment of PHP applications

    - by Christopher McCann
    My team currently has a development web/database server and a live deployment web server and a live database server. We use SVN with the repository stored on the development server but the problem is our deployment process. Currently when we need to deploy an update to the live application we simply use SFTP to transfer from the repository to the live web server and then amend the database on the live server to reflect the development database. This is a really slow process as we also minify all javascript and CSS files. I have used Capistrano for Ruby and Cruise Control for java but I have never used anything for PHP. I'd rather not have to build our own if something already existed. Does anyone know of anything?

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  • ASP.net SessionState Error in Design Mode

    - by stringo0
    I'm getting a weird error in the design view for a user creation page for 2 controls: Error Creating Control - wCreateUser Session state can only be used when enableSessionState is set to true, either in a configuration file or in the Page directive. (There's some more) I've done both of these, but I'm still getting the error in design mode. The controls work fine when compiled, and on the live site - this is just in the Visual Web Developer 2010 Design view for the page. Any ideas as to how I can resolve this? Thanks!

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  • how do I insert an hidden token in my form to prevent double posts? (PHP)

    - by jpjp
    I want to prevent users from accidentally posting a comment twice. I use the PRG (post redirect get) method, so that I insert the data on another page then redirect the user back to the page which shows the comment. This allows users to refresh as many times as they want. However this doesn't work when the user goes back and clicks submit again or when they click submit 100 times really fast. I don't want 100 of the same comments. I looked at related questions on SO and found that a token is best. But I am having trouble using it. //makerandomtoken(20) returns a random 20 length char. <form method="post" ... > <input type="text" id="comments" name="comments" class="commentbox" /><br/> <input type="hidden" name="_token" value="<?php echo $token=makerandomtoken(20); ?>" /> <input type="submit" value="submit" name="submit" /> </form> if (isset($_POST['submit']) && !empty($comments)) { $comments= mysqli_real_escape_string($dbc,trim($_POST['comments'])); //how do I make the if-statment to check if the token has been already set once? if ( ____________){ //don't insert comment because already clicked submit } else{ //insert the comment into the database } } So I have the token as a hidden value, but how do I use that to prevent multiple clicking of submit.

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  • Creating search functionality with Laravel 4

    - by Mitch Glenn
    I am trying to create a way for users to search through all the products on a website. When they search for "burton snowboards", I only want the snowboards with the brand burton to appear in the results. But if they searched only "burton", then all products with the brand burton should appear. This is what I have attempted to write but isn't working for multiple reasons. Controller: public function search(){ $input = Input::all(); $v= Validator::make($input, Product::$rules); if($v->passes()) { $searchTerms = explode(' ', $input); $searchTermBits = array(); foreach ($searchTerms as $term) { $term = trim($term); if (!empty($term)){ $searchTermBits[] = "search LIKE '%$term%'"; } } $result = DB::table('products') ->select('*') ->whereRaw(". implode(' AND ', $searchTermBits) . ") ->get(); return View::make('layouts/search', compact('result')); } return Redirect::route('/'); } I am trying to recreate the first solution given for this stackoverflow.com problem The first problem I have identified is that i'm trying to explode the $input, but it's already an array. So i'm not sure how to go about fixing that. And the way I have written the ->whereRaw(". implode(' AND ', $searchTermBits) . "), i'm sure isn't correct. I'm not sure how to fix these problems though, any insights or solutions will be greatly appreciated.

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  • Update multiple rows with one query?

    - by kavoir.com
    I found something that works with updating one field at here: http://www.karlrixon.co.uk/articles/sql/update-multiple-rows-with-different-values-and-a-single-sql-query/ UPDATE person SET name = CASE id WHEN 1 THEN 'Jim' WHEN 2 THEN 'Mike' WHEN 3 THEN 'Precious' END WHERE id IN (1,2,3) My question is how to update more than one field? Such as: UPDATE person SET name = CASE, sex = CASE id WHEN 1 THEN 'Jim', 'female' WHEN 2 THEN 'Mike' 'male' WHEN 3 THEN 'Precious', 'male' END WHERE id IN (1,2,3) Which doesn't work of course. Tried a few other combination and failed. Any idea? Thanks!

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  • iPhone: error: request for member 'table' in something not a structure or union

    - by Jack Griffiths
    Hi there, When it comes to compiling my application, I get the error mentioned in the title. How would I go about remedying this error? Basically, I want to get from one table to the other. Hierarchy, navigation. NextViewController.m #import "RootViewController.h" #import "NextViewController.h" @implementation NextViewController - (void)didReceiveMemoryWarning { [super didReceiveMemoryWarning]; // Releases the view if it doesn't have a superview // Release anything that's not essential, such as cached data } - (void)dealloc { [super dealloc]; } - (IBAction) changeTable:(NSString *)str{ tblCSS.table = str; } The last line contains the error. If you need any more code, just ask. I'll amend this post with it. Cheers, Jack

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  • HTML checkbox field is being passed to PHP as checked even when it is not

    - by Ryan
    Hello all, First of all thanks in advance, this has been very frustrating and I'm hoping someone can see something I'm not, I am definitely no php expert. Well here' what is going on. I have a form where I have a checkbox for people to opt in to our newletter. The form element looks like this: <label for=newsletter accesskey=N class="checkbox">Signup for Cloverton's Newsletter</label> <input name="newsletter" type="checkbox" id="newsletter" value="Yes" style="width:20px;" /> That is then submitted to a php file with this code: if (isset($_POST['newsletter']) && $_POST['newsletter'] == 'Yes'){ echo "newletter yes"; $newsletter = 1; }else{ echo "newsletter no"; $newsletter = 0; } $newsletter is then inserted into a database field. The issue is that whether the box is checked or not it is being sent to php as true, so every entry is receiving the newsletter. Any help would be greatly appreciated! Thanks!

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  • WebConfigurationManager error after adding siteMap

    - by aron
    Hello I'm getting this error: Compiler Error Message: CS0118: 'Configuration' is a 'namespace' but is used like a 'type' Configuration myWebConfig = WebConfigurationManager.OpenWebConfiguration("~/"); This code has been in place for 5+ months without this issues, only today after adding this sitemap code do I have this issue. <siteMap defaultProvider="ExtendedSiteMapProvider" enabled="true"> <providers> <clear/> <add name="ExtendedSiteMapProvider" type="Configuration.ExtendedSiteMapProvider" siteMapFile="Web.sitemap" securityTrimmingEnabled="true"/> </providers> </siteMap> I tried adding "System.Web." before the "Configuration ", but that did not work either: System.Web.Configuration myWebConfig = WebConfigurationManager.OpenWebConfiguration("~/"); Error 1 'System.Web.Configuration' is a 'namespace' but is used like a 'type'

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  • SQLAlchemy: select over multiple tables

    - by ahojnnes
    Hi, I wanted to optimize my database query: link_list = select( columns=[link_table.c.rating, link_table.c.url, link_table.c.donations_in], whereclause=and_( not_(link_table.c.id.in_( select( columns=[request_table.c.recipient], whereclause=request_table.c.donator==donator.id ).as_scalar() )), link_table.c.id!=donator.id, ), limit=20, ).execute().fetchall() and tried to merge those two selects in one query: link_list = select( columns=[link_table.c.rating, link_table.c.url, link_table.c.donations_in], whereclause=and_( link_table.c.active==True, link_table.c.id!=donator.id, request_table.c.donator==donator.id, link_table.c.id!=request_table.c.recipient, ), limit=20, order_by=[link_table.c.rating.desc()] ).execute().fetchall() the database-schema looks like: link_table = Table('links', metadata, Column('id', Integer, primary_key=True, autoincrement=True), Column('url', Unicode(250), index=True, unique=True), Column('registration_date', DateTime), Column('donations_in', Integer), Column('active', Boolean), ) request_table = Table('requests', metadata, Column('id', Integer, primary_key=True, autoincrement=True), Column('recipient', Integer, ForeignKey('links.id')), Column('donator', Integer, ForeignKey('links.id')), Column('date', DateTime), ) There are several links (donator) in request_table pointing to one link in the link_table. I want to have links from link_table, which are not yet "requested". But this does not work. Is it actually possible, what I'm trying to do? If so, how would you do that? Thank you very much in advance!

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  • java checked exception in a catch clause compilation error

    - by srandpersonia
    Hi, I was expecting an compilation error in the following program because of the throw statement in the catch block as IOException is a checked exception and it is not caught by another try block within the catch block. But I am getting "Hurray!" printed. Any explanation would be much appreciated. According to JLS 11.2.3, http://java.sun.com/docs/books/jls/third_edition/html/exceptions.html It is a compile-time error if a method or constructor body can throw some exception type E when both of the following hold: * E is a checked exception type * E is not a subtype of some type declared in the throws clause of the method or constructor. import java.io.*; public class Test{ public static void main(String args[]) { System.out.println(method()); } public static int method() { try{ throw new Exception(); } catch(Exception e){ throw new IOException(); //No compile time error } finally{ System.out.println("Hurray!"); } } } Thanks in advance.

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  • Editing/Updating one of the results in a search query.

    - by eggman20
    Hi guys. I'm creating a page that searches for an item and then be able to edit/update it. I was able to do it when it returns just one result but when it gives me multiple results I could only edit the very last item. Below is my code: ....... $dj =$_POST[djnum]; $sql= "SELECT * From dj WHERE datajack LIKE '$dj%'"; $result = mysql_query($sql); //more code in here// while ($info =mysql_fetch_array($result)) { // display the result echo "<form action=\"dj_update.php\" method=\"POST\"><input type=\"hidden\" name=\"djnumber\" value=\"".$info['datajack']."\">"; echo "<tr><td>DJ ".$info['datajack']."</td>"; echo "<td>".$info['building']."&nbsp;</td>"; echo "<td>Rm ".$info['room']."&nbsp;</td>"; echo "<td>".$info['switch']."&nbsp;</td>"; echo "<td>".$info['port']."&nbsp;</td>"; echo "<td>".$info['notes']."&nbsp;</td>"; echo "<td style=\"text-align:center;\"><input type=\"Submit\" value=\"Edit\" ></td></tr>"; } // more code here // Then this is the screen shot of the result: The idea is the user should be able to click on "Edit" and be able to edit/update that particular item. But when I click any of the Edit button I could only edit the last item. What am I missing here? Is there an easier way to do this? Thanks guys and Happy new year!

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  • URL Rewrite query database?

    - by Liam
    Im trying to understand how URL rewriting works. I have the following link... mysite.com/profile.php?id=23 I want to rewrite the above url with the Users first and last name... mysite.com/directory/liam-gallagher From what Ive read however you specify the rule for what the url should be output as, But how do i query my table to get each users name? Sorry if this is hard to understand, ive confused myself!

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  • IF expression in SQL

    - by chupinette
    INSERT INTO item_quotation (item_id, quotation_id,name_searched,item_name,other_name,selling_price,discounted_price) SELECT DISTINCT I.item_id," . $quotation_id . ",T.item_name, I.name,I.other_name, INV.selling_price, I.discounted_price FROM temp_quotations T, item I, inventory INV<br/> WHERE ( I.name LIKE CONCAT( '%', T.item_name, '%' ) OR I.other_name LIKE CONCAT( '%', T.item_name, '%' )) AND INV.item_id = I.item_id; I have a table called temp_quotations(temp_item_id,item_name)having values (1,grinder), (2,drill), (3,kit) I have another table called item(item_id,name,other_name,discounted_price) having values (1,grinder A,100),(2,kit A,200) When I execute this sql, it insert values in table item_quotation(item_id, quotation_id,name_searched,item_name,other_name,selling_price,discounted_price) for example in this case it will insert (1,1,grinder,grinder A,150,100) (2,1,kit,kit A, 250,200) Since the item drill is not found in table item, it wont display it in table item_quotations. I want to write an if statement within that sql so that when the item_name from temp_quotation does not match the name from item, it displays not found in the place of item_name. This is what i tried but it does not display "not found": INSERT INTO item_quotation (item_id, quotation_id,name_searched,item_name,other_name,selling_price,discounted_price) SELECT DISTINCT I.item_id," . $quotation_id . ",T.item_name, IF(I.name LIKE CONCAT( '%', T.item_name, '%' ),I.name,'not found'),I.other_name, INV.selling_price, I.discounted_price FROM temp_quotations T, item I, inventory INV WHERE ( I.name LIKE CONCAT( '%', T.item_name, '%' ) OR I.other_name LIKE CONCAT( '%', T.item_name, '%' )) AND INV.item_id = I.item_id;

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  • problem parsing JSON Strings

    - by blacktooth
    var records = JSON.parse(JsonString); for(var x=0;x<records.result.length;x++) { var record = records.result[x]; ht_text+="<b><p>"+(x+1)+" " +record.EMPID+" " +record.LOCNAME+" " +record.DEPTNAME+" " +record.CUSTNAME +"<br/><br/><div class='slide'>" +record.REPORT +"</div></p></b><br/>"; } The above code works fine when the JsonString contains an array of entities but fails for single entity. result is not identified as an array! Whats wrong with it? http://pastebin.com/hgyWw5hd

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  • SQL to CodeIgniter Array Missing Data Issue

    - by SamD
    $query = $this->db->query("SELECT t1.numberofbets, t1.profit, t2.seven_profit, t3.28profit, user.user_id, username, password, email, balance, user.date_added, activation_code, activated FROM user LEFT JOIN (SELECT user_id, SUM(amount_won) AS profit, count(tip_id) AS numberofbets FROM tip GROUP BY user_id) as t1 ON user.user_id = t1.user_id LEFT JOIN (SELECT user_id, SUM(amount_won) AS seven_profit FROM tip WHERE date_settled > '$seven_daystime' GROUP BY user_id) as t2 ON user.user_id = t2.user_id LEFT JOIN (SELECT user_id, SUM(amount_won) AS 28profit FROM tip WHERE date_settled > '$twoeight_daystime' GROUP BY user_id) as t3 ON user.user_id = t3.user_id where activated = 1 GROUP BY user.user_id ORDER BY user.date_added DESC"); return $query->result_array(); The query works fine running it in phpMyAdmin and returns complete results (in image attached). However, printing the array in CodeIgniter, it has no value for one field ,seven_profit, where it is there in the SQL query ran in phpMyAdmin, just the discrepancy in this one field, from sql to php array... I just can’t see why, when printing the array, that one field, which should have value of 26, contains nothing? Any ideas? I changed the field name from starting with a number in attempt to fix it, but no difference. I know this is complex and looks horrible, any help or just people coming across something similar would be great to know about, thanks. Sam

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  • How to setup testing LAMP environment to work with outsourcing companies?

    - by Kelvin
    Hello Guys, I need to setup testing LAMP environment in my office to work with outsourcing companies. This is what I think should be done on my side: Setup testing web server with the same configuration as on production Setup testing SQL server with "fake data"? Outsourcers should have access only to some part of original code Outsourcers should use CVS to update their code Once testing is finished someone releases the update ............ How would you separate original code and database from testing environment, but keep it as close as possible to production? What is the general practice for setting up testing environment and how other companies deal with outsourcers? I will appreciate for any of your thoughts and ideas from your personal experience. Maybe someone can suggest some article on this topic. Thank you a lot!

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  • How to map to tables in database PHPMyAdmin

    - by thegrede
    I'm working now on a project which a user can save their own coupon codes on the websites, so I want to know what is the best to do that, Lets say, I have 1 table with the users, like this, userId | firstName | lastName | codeId and then I have a table of the coupon codes, like this, codeId | codeNumber So what I can do is to connect the codeId to userId so when someone saves the coupons goes the codeId from the coupon table into the codeId of the users table, But now what if when a user have multiple coupons what do I do it should be connected to the user? I have 2 options what to do, Option 1, Saving the codeId from coupons table into the codeId of users table like 1,2,3,4,5, Option 2 To make a new row into the coupons table and to connect the user to the code with adding another field in the coupon table userId and putting into it the user which has added the coupon his userId of the users table, So what of the two options is better to do? Thanks you guys.

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