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  • Picture rendered from above and below using an Orthographic camera do not match

    - by Roy T.
    I'm using an orthographic camera to render slices of a model (in order to voxelize it). I render each slice both from above and below in order to determine what is inside each slice. I am using an orthographic camera The model I render is a simple 'T' shape constructed from two cubes. The cubes have the same dimensions and have the same Y (height) coordinate. See figure 1 for a render of it in Blender. I render this model once directly from above and once directly from below. My expectation was that I would get exactly the same image (except for mirroring over the y-axis). However when I render using a very low resolution render target (25x25) the position (in pixels) of the 'T' is different when rendered from above as opposed to rendered from below. See figure 2 and 3. The pink blocks are not part of the original rendering but I've added them so you can easily count/see the differences. Figure 2: the T rendered from above Figure 3: the T rendered from below This is probably due to what I've read about pixel and texel coordinates which might be biased to the top-left as seen from the camera. Since I'm using the same 'up' vector for both of my camera's my bias only shows on the x-axis. I've tried to change the position of the camera and it's look-at by, what I thought, should be half a pixel. I've tried both shifting a single camera and shifting both cameras and while I see some effect I am not able to get a pixel-by-pixel perfect copy from both camera's. Here I initialize the camera and compute, what I believe to be, half pixel. boundsDimX and boundsDimZ is a slightly enlarged bounding box around the model which I also use as the width and height of the view volume of the orthographic camera. Matrix projection = Matrix.CreateOrthographic(boundsDimX, boundsDimZ, 0.5f, sliceHeight + 0.5f); Vector3 halfPixel = new Vector3(boundsDimX / (float)renderTarget.Width, 0, boundsDimY / (float)renderTarget.Height) * 0.5f; This is the code where I set the camera position and camera look ats // Position camera if (downwards) { float cameraHeight = bounds.Max.Y + 0.501f - (sliceHeight * i); Vector3 cameraPosition = new Vector3 ( boundsCentre.X, // possibly adjust by half a pixel? cameraHeight, boundsCentre.Z ); camera.Position = cameraPosition; camera.LookAt = new Vector3(cameraPosition.X, cameraHeight - 1.0f, cameraPosition.Z); } else { float cameraHeight = bounds.Max.Y - 0.501f - (sliceHeight * i); Vector3 cameraPosition = new Vector3 ( boundsCentre.X, cameraHeight, boundsCentre.Z ); camera.Position = cameraPosition; camera.LookAt = new Vector3(cameraPosition.X, cameraHeight + 1.0f, cameraPosition.Z); } Main Question Now you've seen all the problems and code you can guess it. My main question is. How do I align both camera's so that they each render exactly the same image (mirrored along the Y axis)? Figure 1 the original model rendered in blender

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  • MSCC: Global Windows Azure Bootcamp - 29th March 2014

    The Mauritius Software Craftsmanship Community proudly presents you the Global Windows Azure Bootcamp 2014 in Mauritius. Global Windows Azure Bootcamp 2014 in Mauritius - MSCC together with Microsoft, Ceridian and Emtel We are very happy and excited about our participation in this global event and would like to draw your attention to the official invitation letter below. Please sign up and RSVP on the official website of the MSCC. Participation is for free! Call for action Please create more awareness of this event in Mauritius and use the hash tag #gwabmru as well as the shortened link: http://aka.ms/gwabmru And remember: Sharing is Caring! Official invitation letter to the GWAB 2014 in Mauritius With over 130 confirmed locations around the globe, the Global Windows Azure Bootcamp is going to be a truly memorable event - and now here's your chance to take part! In April of 2013 we held the first Global Windows Azure Bootcamp at more than 90 locations around the globe! This year we want to again offer up a one day deep dive class to help thousands of people get up to speed on discovering Cloud Computing Applications for Windows Azure. In addition to this great learning opportunity the hands on labs will feature pooling a huge global compute farm to perform diabetes research! In Mauritius, the event will be organised by Microsoft Indian Ocean Islands & French Pacific in partnership with The Mauritius Software Craftsmanship Community (MSCC) and sponsored by Microsoft, Ceridian and Emtel. What do I need to bring?  You will need to bring your own computer which can run Visual Studio 2012 or 2013 (i.e. Windows, OSX, Ubuntu with virtualization, etc.) and have it preloaded with the following: Visual Studio 2012 or 2013 The Windows Azure SDK - http://www.windowsazure.com/en-us/develop/net/ Optionally (or if you will not be doing just .NET labs), the following can also be installed: Node.js SDK - http://www.windowsazure.com/en-us/develop/nodejs/ JAVA SDK - http://www.windowsazure.com/en-us/develop/java/ Doing mobile? Android? iOS? Windows Phone or Windows 8? - http://www.windowsazure.com/en-us/develop/mobile/ PHP - http://www.windowsazure.com/en-us/develop/php/ More info here: http://www.windowsazure.com/en-us/documentation Important: Please do the installation upfront as there will be very little time to troubleshoot installations during the day.  

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  • Harnessing Business Events for Predictive Decision Making - part 1 / 3

    - by Sanjeev Sharma
    Businesses have long relied on data mining to elicit patterns and forecast future demand and supply trends. Improvements in computing hardware, specifically storage and compute capacity, have significantly enhanced the ability to store and analyze mountains of data in ever shrinking time-frames. Nevertheless, the reality is that data growth is outpacing storage capacity by a factor of two and computing power is still very much bounded by Moore's Law, doubling only every 18 months.Faced with this data explosion, businesses are exploring means to develop human brain-like capabilities in their decision systems (including BI and Analytics) to make sense of the data storm, in other words business events, in real-time and respond pro-actively rather than re-actively. It is more like having a little bit of the right information just a little bit before hand than having all of the right information after the fact. To appreciate this thought better let's first understand the workings of the human brain.Neuroscience research has revealed that the human brain is predictive in nature and that talent is nothing more than exceptional predictive ability. The cerebral-cortex, part of the human brain responsible for cognition, thought, language etc., comprises of five layers. The lowest layer in the hierarchy is responsible for sensory perception i.e. discrete, detail-oriented tasks whereas each of the above layers increasingly focused on assembling higher-order conceptual models. Information flows both up and down the layered memory hierarchy. This allows the conceptual mental-models to be refined over-time through experience and repetition. Secondly, and more importantly, the top-layers are able to prime the lower layers to anticipate certain events based on the existing mental-models thereby giving the brain a predictive ability. In a way the human brain develops a "memory of the future", some sort of an anticipatory thinking which let's it predict based on occurrence of events in real-time. A higher order of predictive ability stems from being able to recognize the lack of certain events. For instance, it is one thing to recognize the beats in a music track and another to detect beats that were missed, which involves a higher order predictive ability.Existing decision systems analyze historical data to identify patterns and use statistical forecasting techniques to drive planning. They are similar to the human-brain in that they employ business rules very much like mental-models to chunk and classify information. However unlike the human brain existing decision systems are unable to evolve these rules automatically (AI still best suited for highly specific tasks) and  predict the future based on real-time business events. Mistake me not,  existing decision systems remain vital to driving long-term and broader business planning. For instance, a telco will still rely on BI and Analytics software to plan promotions and optimize inventory but tap into business events enabled predictive insight to identify specifically which customers are likely to churn and engage with them pro-actively. In the next post, i will depict the technology components that enable businesses to harness real-time events and drive predictive decision making.

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  • Exalogic 2.0.1 Tea Break Snippets - Creating and using Distribution Groups

    - by The Old Toxophilist
    By default running your Exalogic in a Virtual provides you with, what to Cloud Users, is a single large resource and they can just create vServers and not care about how they are laid down on the the underlying infrastructure. All the Cloud Users will know is that they can create vServers. For example if we have a Quarter Rack (8 Nodes) and our Cloud User creates 8 vServers those 8 vServers may run on 8 distinct nodes or may all run on the same node. Although in many cases we, as Cloud Users, may not be to worried how the Virtualisation Algorithm decides where to place our vServers there are cases where it is extremely important that vServers run on distinct physical compute nodes. For example if we have a Weblogic Cluster we will want the Servers with in the cluster to run on distinct physical node to cover for the situation where one physical node is lost. To achieve this the Exalogic Virtualised implementation provides Distribution Groups that define and anti-aliasing policy that the underlying Virtualisation Algorithm will take into account when placing vServers. It should be noted that Distribution Groups must be created before you create vServers because a vServer can only be added to a Distribution Group at creation time. Creating A Distribution Group To create a Distribution Groups we will first need to select the Account in which we want the Distribution Group to be created. Once we have selected the account we will see the Interface update and Account specific Actions will be displayed within the Action Panes. From the Action pane (or Right-Click on the Account) select the "Create Distribution Group" action. This will initiate the create wizard as follows. Distribution Group Details Within the first Step of the Wizard we can specify the name of the distribution group and this should be unique. In addition we can provide a detailed description of the group. Distribution Group Configuration The second step of the configuration wizard allows you to specify the number of elements that are required within this group and will specify a maximum of the number of nodes within you Exalogic. At this point it is always better to specify a group with spare capacity allowing for future expansion. As vServers are added to group the available slots decrease. Summary Finally the last step of the wizard display a summary of the information entered.

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  • Dual-boot computer won't boot without external hard drive

    - by FrankP
    I have Ubuntu loaded on my external HDD. I tried to unplug the external drive so that this way I could run Windows as the default OS to boot when the computer turns on, but it gives me an error. I need to know how I can make it so that when my computers boots it stops saying Error: no such device: (a whole bunch of numbers and letters) then it says grub rescue>_. If I plug the external HDD in, and I let Ubuntu run the boot process, then it gives me a list of OS's/ HDD's to choose from and Windows 7 is there. The only problem is that I want Windows be my default OS, not the other way around. P.S. I have found that I dislike Ubuntu because I can't even figure out how to install the necessary programs to learn how to start writing Ruby On Rails. So installing it was a waste of my time, in my opinion. Now that I have it on the external hard drive, I will leave it installed though. I just dont want to have to keep that external drive plugged in to my computer all the time. Thank you a ton to whoever can help me! Thank you for the detail'd instructions. I am doing my best to follow you and it makes sense when I read it but, Rescatux is not doing what you said it would. None of the options you said would appear are not there. On my screen there is 4 options when MBR run's none look familiar and when I picked the best possible option based on my educated guesses it said success. I tried to restart my computer and it said Please insert windows recovery disc and hit enter. Problem being I don't have the windows recovery disc. I bought my computer from a local Computer tec and he loads windows on it for you. I have no time to run my compute over to him as sunday is my only day free. I think that I just wrecked my computer in the process of this attempted fix windows refuses to boot now WITH or WITHOUT the HDD. Please help this is getting out of hand

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  • eSTEP Newsletter for October 2013 now available

    - by uwes
    Dear Partners,We would like to let you know that the October'13 issue of our Newsletter is now available.The issue contains information on the following topics: Oracle Open World Summary Oracle Cloud: Oracle Engineered Systems Oracle Database and Middleware Oracle Applications and Software as a Service Oracle Industries Oracle Partners and the "Internet of Things" JavaOne News MySQL News Corporate News Create Your HR Strategic Vision at Oracle HCM World Oracle Database Protection Redefined A Preview: Oracle Database Backup Logging Recovery Appliance Oracle closed Tekelec acquisition Congratulations to ORACLE TEAM USA! Tech sectionARC M6 Oracle's SPARC M6 Oracle SuperCluster M6-32 - Oracle’s Most Scalable Engineered System Oracle Multitenant on SPARC Servers and Oracle Solaris Oracle Database 12c Enterprise Edition: Plug into the Cloud Oracle In-Memory Database Cache Oracle Virtual Compute Appliance New Benchmark-Results published (Sept. 2013) Video Interview: Elasticity, the Biggest Challenge Facing Data Centers Today Tech blog Announcing New Sun Storage 2500-M2 Drives SPARC Product Line Update ZFS RAID Calculator v6 What ships with ODA X3-2? Tech Article: Oracle Multitenant on SPARC Servers and Oracle Solaris New release of Sun Rack II capacity calculator available Announcing: Oracle Solaris Cluster Product Bulletin, September 2013 Learning & events Planned TechCasts Quarterly Partner Update Live Webcast: Simplify and Accelerate Oracle Database deployment with Oracle VM Templates Join us for OTN's Virtual Developer Day - Harnessing the Power of Oracle WebLogic and Oracle Coherence.Learn from OOW 2013 what is going on in Virtualization How to Implementing Early Arriving Facts in ODI, Part I and Part II: Proof of Concept Overview Multi-Factor Authentication in Oracle WebLogic Using multi-factor authentication to protect web applications deployed on Oracle WebLogic. If Virtualization Is Free, It Can't Be Any Good—Right? Looking beyond System/HW SOA and User Interfaces Overcoming the challenges to developing user interfaces in a service oriented References Vodafone Romania Improves Business Agility and Customer Satisfaction, with 10x Faster Business Intelligence Delivery and 12x Faster Processing Emirates Integrated Telecommunications Captures 47% Market Share in a Competitive Market, Thanks to 24/7 Availability Home Credit and Finance Bank Accelerates Getting New Banking Products to Market Extra A Conversation with Java Champion Johan VosYou can find the Newsletter on our portal under eSTEP News ---> Latest Newsletter. You will need to provide your email address and the pin below to get access. Link to the portal is shown below.URL: http://launch.oracle.com/PIN: eSTEP_2011Previous published Newsletters can be found under the Archived Newsletters section and more useful information under the Events, Download and Links tab. Feel free to explore and any feedback is appreciated to help us improve the service and information we deliver.Thanks and best regards,Partner HW Enablement EMEA

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  • MatheMagics - Guess My Age Method 1

    - by PointsToShare
    © 2011 By: Dov Trietsch. All rights reserved MatheMagic – Guess My Age – Method 1 The Mathemagician stands on the stage and asks an adult to do the following: ·         Do the next few steps on your calculator, or the calculator in your phone, or even on a piece of paper. ·         Do it silently! Don’t tell me the results until I ask for them directly ·         Compute a single digit multiple of 9 – any one of 9, 18, 27, … all the way to 81, will do. ·         Now multiply your age by 10 ·         Subtract the 9 multiple from this number. ·         Tell me the result. Notice that I don’t know which multiple of 9 you subtracted from 10 times your age. I will nonetheless immediately tell you what your age is. How do I do this? Let’s do the algebra. 10X – 9Y = 10X – 10Y + Y = 10(X – Y) + Y Now remember, you asked an adult, so his/her age is a two digit number (maybe even 3 digits), thus reducing it by the single digit multiplied by nine is still positive – the lowest is can be is 100 – 81 which yields 19. Now make two numbers out of the result. The last digit and the number before it. This number is X – Y or the age minus the single digit you selected. The last digit is this very single digit. This is always so regardless of the digit you selected. So… Add tis digit to the other number and you get back the age! Q.E.D Example: I am 76 years old and here is what happens when I do the steps 76 x 10 = 760 760 – 18 = 742 made of 74 and 2. My age is 74 + 2 760 – 81 = 679 made of 67 and 9. My age is 67 + 9 A note to the socially aware mathemagician – it is safer to do it with a man. The chances of a veracious answer are much, much higher! The trick may be accomplished on any 2 or 3 digit number, not just one’s age, but if you want to know your date’s age, it’s a good way to elicit it. That’s All Folks PS for more Ageless “Age” mathemagics go to www.mgsltns.com/games.htm and also here: http://geekswithblogs.net/PointsToShare/archive/2011/11/15/mathemagics---guess-my-age---method-2.aspx

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  • Microsoft Azure News: Capturing VM Images

    - by Herve Roggero
    Originally posted on: http://geekswithblogs.net/hroggero/archive/2014/05/21/microsoft-azure-news-capturing-vm-images.aspxIf you have a Virtual Machine (VM) in Microsoft Azure that has a specific configuration, it used to be difficult to clone that VM. You had to sysprep the VM, and clone the data disks. This was slow, prone to errors, and stopped you from being productive. No more! A new option, called Capture, allows you to easily select a VM, running or not. The capture will copy the OS disk and data disks and create a new image out of it automatically for you. This means you can now easily clone an entire VM without affecting productivity.  To capture a VM, simply browse to your Virtual Machines in the Microsoft Azure management website, select the VM you want to clone, and click on the Capture button at the bottom. A window will come up asking to name your image. It took less than 1 minute for me to build a clone of my server. And because it is stored as an image, I can easily create a new VM with it. So that’s what I did… And that took about 5 minutes total.  That’s amazing…  To create a new VM from your image, click on the NEW icon (bottom left), select Compute/Virtual Machine/From Gallery, and select My Images from the left menu when selecting an Image. You will find your newly created image. Because this is a clone, you will not be prompted for a new login; the user id/password is the same. About Herve Roggero Herve Roggero, Microsoft Azure MVP, @hroggero, is the founder of Blue Syntax Consulting (http://www.bluesyntaxconsulting.com). Herve's experience includes software development, architecture, database administration and senior management with both global corporations and startup companies. Herve holds multiple certifications, including an MCDBA, MCSE, MCSD. He also holds a Master's degree in Business Administration from Indiana University. Herve is the co-author of "PRO SQL Azure" and “PRO SQL Server 2012 Practices” from Apress, a PluralSight author, and runs the Azure Florida Association.

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  • Function like C# properties?

    - by alan2here
    I was directed here from SO as a better stack exchange site for this question. I've been thinking about the neatness and expression of C# properties over functions, although they only currently work where no parameters are used, and wondered. Is is possible, and if so why not, to have a stand alone function like C# property. For example: public class test { private byte n = 4; public test() { func = 2; byte n2 = func; func; } private byte func { get { return n; } set { n = value; } func { n++; } } } edit: Sorry for the vagueness first time round. I'm going to add some info and motivation. The 'n++' here is just a simple example, a placeholder, it's not intended to be representative of the actual code that would be used. I'm also looking at this from the point of view of looking at the property command as is, not in the context of using it for 'get_xyz' and 'set_xyz' member functions, which is certainly useful, but of instead comparing it more abstractly to functions and other programic elements. A 'get' property can be used instead of a function that takes no parameters, and syntactically they are perhaps only aesthetically, but as I see it noticeably nicer. However, properties also add the potential for an extra layer of polymorphism, one that relates to the 'func = 4;' getting, 'int n = func;' setting or 'func;' function like context in which they are used as well as the more common parameter based polymorphism. Potentially allowing for a lot of expression and contextual information reguarding how other would use your functions. As in many places uses and definitions would remain the same, it shouldn't break existing code. private byte func { get { } get bool { } set { } func { } func(bool) { } func(byte, myType) { } // etc... } So a read only function would look like this: private byte func { get { } } A normal function like this: private void func { func { } } A function with parameter polymorphism like this: private byte func { func(bool) { } func(byte, myType) { } } And a function that could return a value, or just compute, depending on the context it is used, that also has more conventional parameter polymorphism as well, like so: private byte func { get { } func(bool) { } func(byte, myType) { } }

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  • Need help on a problemset in a programming contest

    - by topher
    I've attended a local programming contest on my country. The name of the contest is "ACM-ICPC Indonesia National Contest 2013". The contest has ended on 2013-10-13 15:00:00 (GMT +7) and I am still curious about one of the problems. You can find the original version of the problem here. Brief Problem Explanation: There are a set of "jobs" (tasks) that should be performed on several "servers" (computers). Each job should be executed strictly from start time Si to end time Ei Each server can only perform one task at a time. (The complicated thing goes here) It takes some time for a server to switch from one job to another. If a server finishes job Jx, then to start job Jy it will need an intermission time Tx,y after job Jx completes. This is the time required by the server to clean up job Jx and load job Jy. In other word, job Jy can be run after job Jx if and only if Ex + Tx,y = Sy. The problem is to compute the minimum number of servers needed to do all jobs. Example: For example, let there be 3 jobs S(1) = 3 and E(1) = 6 S(2) = 10 and E(2) = 15 S(3) = 16 and E(3) = 20 T(1,2) = 2, T(1,3) = 5 T(2,1) = 0, T(2,3) = 3 T(3,1) = 0, T(3,2) = 0 In this example, we need 2 servers: Server 1: J(1), J(2) Server 2: J(3) Sample Input: Short explanation: The first 3 is the number of test cases, following by number of jobs (the second 3 means that there are 3 jobs for case 1), then followed by Ei and Si, then the T matrix (sized equal with number of jobs). 3 3 3 6 10 15 16 20 0 2 5 0 0 3 0 0 0 4 8 10 4 7 12 15 1 4 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 4 8 10 4 7 12 15 1 4 0 50 50 50 50 0 50 50 50 50 0 50 50 50 50 0 Sample Output: Case #1: 2 Case #2: 1 Case #3: 4 Personal Comments: The time required can be represented as a graph matrix, so I'm supposing this as a directed acyclic graph problem. Methods I tried so far is brute force and greedy, but got Wrong Answer. (Unfortunately I don't have my code anymore) Could probably solved by dynamic programming too, but I'm not sure. I really have no clear idea on how to solve this problem. So a simple hint or insight will be very helpful to me.

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  • eSTEP Newsletter for October 2013 Now Available

    - by Cinzia Mascanzoni
    The October'13 issue of our Newsletter is now available. The issue contains information on the following topics: Oracle Open World Summary Oracle Cloud: Oracle Engineered Systems Oracle Database and Middleware Oracle Applications and Software as a Service Oracle Industries Oracle Partners and the "Internet of Things" JavaOne News MySQL News Corporate News Create Your HR Strategic Vision at Oracle HCM World Oracle Database Protection Redefined A Preview: Oracle Database Backup Logging Recovery Appliance Oracle closed Tekelec acquisition Congratulations to ORACLE TEAM USA! Tech sectionARC M6 Oracle's SPARC M6 Oracle SuperCluster M6-32 - Oracle’s Most Scalable Engineered System Oracle Multitenant on SPARC Servers and Oracle Solaris Oracle Database 12c Enterprise Edition: Plug into the Cloud Oracle In-Memory Database Cache Oracle Virtual Compute Appliance New Benchmark-Results published (Sept. 2013) Video Interview: Elasticity, the Biggest Challenge Facing Data Centers Today Tech blog Announcing New Sun Storage 2500-M2 Drives SPARC Product Line Update ZFS RAID Calculator v6 What ships with ODA X3-2? Tech Article: Oracle Multitenant on SPARC Servers and Oracle Solaris New release of Sun Rack II capacity calculator available Announcing: Oracle Solaris Cluster Product Bulletin, September 2013 Learning & events Planned TechCasts Quarterly Partner Update Live Webcast: Simplify and Accelerate Oracle Database deployment with Oracle VM Templates Join us for OTN's Virtual Developer Day - Harnessing the Power of Oracle WebLogic and Oracle Coherence. Learn from OOW 2013 what is going on in Virtualization How to Implementing Early Arriving Facts in ODI, Part I and Part II: Proof of Concept Overview Multi-Factor Authentication in Oracle WebLogic Using multi-factor authentication to protect web applications deployed on Oracle WebLogic. If Virtualization Is Free, It Can't Be Any Good—Right? Looking beyond System/HW SOA and User Interfaces Overcoming the challenges to developing user interfaces in a service oriented References Vodafone Romania Improves Business Agility and Customer Satisfaction, with 10x Faster Business Intelligence Delivery and 12x Faster Processing Emirates Integrated Telecommunications Captures 47% Market Share in a Competitive Market, Thanks to 24/7 Availability Home Credit and Finance Bank Accelerates Getting New Banking Products to Market Extra A Conversation with Java Champion Johan Vos You can find the Newsletter on our portal under eSTEP News ---> Latest Newsletter. You will need to provide your email address and the pin below to get access. Link to the portal is shown below. URL: http://launch.oracle.com/ PIN: eSTEP_2011 Previous published Newsletters can be found under the Archived Newsletters section and more useful information under the Events, Download and Links tab.

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  • Setting MTU on Exalogic

    - by csoto
    For many reasons, a system administrator may want to change the MTU settings of a server. But in a system like Exalogic which contains lots of interconnected nodes and other various components, it's important to understand how this applies to the different networks. For example, when bringing up bonding of InfiniBand an error like the following may be thrown: Bringing up interface bond1: SIOCSIFMTU: Invalid argument Both scripts ifcfg-ib0 and ifcfg-ib1 (from the /etc/sysconfig/network-scripts/ direectory) have MTU set to 65500, which is a valid MTU value only if all IPoIB slaves operate in connected mode and are configured with the same value, so the line below must be added to both network scripts and then restart the network: CONNECTED_MODE=yes By the way, an error of the form “SIOCSIFMTU: Invalid argument” indicates that the requested MTU was rejected by the kernel. Typically this would be due to it exceeding the maximum value supported by the interface hardware. In that case you must either reduce the MTU to a value that is supported or obtain more capable hardware. This problem has been seen when trying to modify the MTU using the ifconfig command, like the output of the example below: [root@elxxcnxx ~]# ifconfig ib1 mtu 65520 SIOCSIFMTU: Invalid argument It's important to insist that in most cases the nodes must be rebooted after the MTU size has been changed. Although in some circumstances it may work without a reboot, it is not how it is typically documented. Now, in order to achieve a reduced memory consumption and improve performance for network traffic received on IPoIB related interfaces, it is recommend to reduce the MTU value in interface configuration files for IPoIB related bonds from 65520 to 64000. The change needs to be made to interface configuration files under the /etc/sysconfig/network-scripts directory and applies to the interface configuration files for bonds over IPoIB related slave devices, for example /etc/sysconfig/network-scripts/ifcfg-bond1. However, keep in mind that the numeric portion of the interface filenames that corresponding to IPoIB interfaces is expected to vary across compute nodes and vServers and so cannot be relied upon to identify which interface files are for bonds are over IPoIB rather than EoIB related slave interfaces. To fix these MTU values to the recommended settings, there are very useful instructions and a script on the MOS Note 1624434.1, and it's applicable physical and virtual configurations of Exalogic. Regarding the recommended MTU value for EoIB related interfaces, its maximum appropriate value is 1500. If for some reason a vServer has been created with a higher value (set on the /etc/sysconfig/network-scripts/ifcfg-bond0 file), then it must be fixed. An error like the following could be thrown under this circumstance: [root@vServer ~]# service network restart ... Bringing up interface bond0:  SIOCSIFMTU: Invalid argument Also an error like the one below can be seen on the /var/log/messages file of the vServer: kernel: T5074835532 [mlx4_vnic] eth1:vnic_change_mtu:360: failed: new_mtu 64000 2026 The MOS Note 1611657.1 is very useful for this purpose.

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  • Exalytics OBI11g Partner Training 3-day hands-on Workshops

    - by Mike.Hallett(at)Oracle-BI&EPM
    These FREE to OPN Partners hands-on workshops highlight both the hardware and software components that are engineered to work together to deliver Oracle Exalytics - an optimized version of the industry-leading Oracle TimesTen In-Memory Database with analytic extensions, a highly scalable Oracle server designed specifically for in-memory business intelligence, and Oracle's proven Business Intelligence Foundation (OBI 11g v 11.1.1.6 and Essbase) with enhanced visualization capabilities and performance optimizations. Priority will be given to Partner individuals who have passed or scheduled to take the Oracle Business Intelligence Foundation Suite 11g Essentials (1Z1-591) exam, and to Partners who have purchased an Exalytics for their own data centres to demonstrate it to their clients. Topics covered will include: Exalytics Architectural Overview Upgrade and Lifecycle Management Times Ten for Exalytics Summary Advisor Utility Essbase and EPM System on Exalytics Dashboard and Analysis Interactions OBIEE 11.1.1.6 Features and Advanced Topics After taking this course, you will be well prepared to architect, build, demo, and implement an end-to-end Exalytics solution.You will also be able to extend your current analytical and enterprise performance management application implementations with numerous Oracle technologies specifically enhanced to take advantage of the compute capacity and in-memory capabilities of Oracle Exalytics. Prerequisites Experience and understanding of OBIEE 11g is required ·       Previous attendance of Oracle Business Intelligence Foundation Suite Workshop or BIEE 11g Introduction Workshop is highly recommended, and priority will be given to Partner individuals who have passed or scheduled to take the Oracle Business Intelligence Foundation Suite 11g Essentials (1Z1-591) exam. Good understanding of data warehousing and data modelling for reporting and analysis purpose.  Strong experience with database technologies preferred Attendee to provide their own laptops which must meet the following minimum hardware/software requirements: Hardware Minimum 8GB RAM 60 GB free disk space (includes staging) USB 2.0 port (at least one available) It is strongly recommended that you bring a mouse. You will be working in a development environment and using the mouse heavily. Software One of the following operating systems: 64-bit Windows host/laptop OS 64-bit host/laptop OS with a Windows VM (XP, Server, or Win 7, BIC2g, etc.) Internet Explorer 7.x/8.x or Firefox 3.5.x WINRAR or 7ziputility to unzip workshop files: Download-able from http://www.win-rar.com/download.html Download-able from http://www.7zip.com/ Oracle VirtualBox 4.0.2 or higher Downloadable from http://www.virtualbox.org/wiki/Downloads CPU virtualization mode needs to be enabled. We will provide guidance on the day of the workshop.  Attendees will be given a VirtualBox image containing a pre-installed Oracle Exalytics environment. Register Here for 3-day Workshops: 11-Dec-12 Birmingham UK 29-Jan-13 Utrecht NL 12-Feb-13 Frankfurt Germany 12-Mar-13 Moscow Russia

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  • How to get lookahead symbol when constructing LR(1) NFA for parser?

    - by greenoldman
    I am reading an explanation (awesome "Parsing Techniques" by D.Grune and C.J.H.Jacobs; p.292 in the 2nd edition) about how to construct an LR(1) parser, and I am at the stage of building the initial NFA. What I don't understand is how to get/compute a lookahead symbol. Here is the example from the book, the grammar: S -> E E -> E - T E -> T T -> ( E ) T -> n n is terminal. The "weird" transitions for me are is the sequence: 1) S -> . E eof 2) E -> . E - T eof 3) E -> . E - T - 4) E -> E . - T - 5) E -> E - . T - (Note: In the above table, the state numbers are in front and the lookahead symbol is at the end.) What puzzles me is that transition from (4) to (5) means reading - token, right? So how is it that - is still a lookahead symbol and even more important why is it that eof is no longer a lookahead symbol? After all in an input such as n - n eof there is only one - symbol. My naive thinking tells me (5) should be written as: 5) E -> E - . T - eof And another thing -- n is terminal. Why it is not used at all as a lookahead symbol? I mean -- we expect to see - or (, it is ok, but lack of n means we are sure it won't appear in input? Update: after more reading I am only more confused ;-) I.e. what is really a lookahead? Because I see such state as (p.292, 2nd column, 2nd row): E -> E . - T eof Lookahead says eof but the incoming input says -. Isn't it a contradiction? And it is not only in this book.

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  • Silverlight and WCF caching

    - by subodhnpushpak
    There are scenarios where Silverlight client calls WCF (or REST) service for data. Now, if the data is cached on the WCF layer, the calls can take considerable resources at the server if NOT cached. Keeping that in mind along with the fact that cache is an cross-cutting aspect, and therefore it should be as easy as possible to put Cache wherever required. The good thing about the solution is that it caches based on the inputs. The input can be basic type of any complex type. If input changes the data is fetched and then cached for further used. If same input is provided again, data id fetched from the cache. The cache logic itself is implemented as PostSharp aspect, and it is as easy as putting an attribute over service call to switch on cache. Notice how clean the code is:        [OperationContract]       [CacheOnArgs(typeof(int))] // based on actual value of cache        public string DoWork(int value)        {            return string.Format("You entered: {0} @ cached time {1}", value, System.DateTime.Now);        } The cache is implemented as POST Sharp as below 1: public override void OnInvocation(MethodInvocationEventArgs eventArgs) 2: { 3: try 4: { 5: object value = new object(); 6: object[] args = eventArgs.GetArgumentArray(); 7: if (args != null || args.Count() > 0) 8: { 9:   10: string key = string.Format("{0}_{1}", eventArgs.Method.Name, XMLUtility<object>.GetDataContractXml(args[0], null));// Compute the cache key (details omitted). 11:   12: 13: value = GetFromCache(key); 14: if (value == null) 15: { 16: eventArgs.Proceed(); 17: value = XMLUtility<object>.GetDataContractXml(eventArgs.ReturnValue, null); 18: value = eventArgs.ReturnValue; 19: AddToCache(key, value); 20: return; 21: } 22:   23:   24: Log(string.Format("Data returned from Cache {0}",value)); 25: eventArgs.ReturnValue = value; 26: } 27: } 28: catch (Exception ex) 29: { 30: //ApplicationLogger.LogException(ex.Message, Source.UtilityService); 31: } 32: } 33:   34: private object GetFromCache(string inputKey) { if (ServerConfig.CachingEnabled) { return WCFCache.Current[inputKey]; } return null; }private void AddToCache(string inputKey,object outputValue) 35: { 36: if (ServerConfig.CachingEnabled) 37: { 38: if (WCFCache.Current.CachedItemsNumber < ServerConfig.NumberOfCachedItems) 39: { 40: if (ServerConfig.SlidingExpirationTime <= 0 || ServerConfig.SlidingExpirationTime == int.MaxValue) 41: { 42: WCFCache.Current[inputKey] = outputValue; 43: } 44: else 45: { 46: WCFCache.Current.Insert(inputKey, outputValue, new TimeSpan(0, 0, ServerConfig.SlidingExpirationTime), true); 47:   48: // _bw.DoWork += bw_DoWork; 49: //string arg = string.Format("{0}|{1}", inputKey,outputValue); 50: //_bw.RunWorkerAsync(inputKey ); 51: } 52: } 53: } 54: }     The cache class can be extended to support Velocity / memcahe / Nache. the attribute can be used over REST services as well. Hope the above helps. Here is the code base for the same.   Please do provide your inputs / comments.

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  • Cloud Computing Business Benefits

    - by workflowman
    If you have been living under a rock for the past year, you wouldn't have heard about cloud computing. Cloud computing is a loose term that describes anything that is hosted in data centers and accessed via the internet. It is normally associated with developers who draw clouds in diagrams indicating where services or how systems communicate with each other. Cloud computing also incorporates such well-known trends as Web 2.0 and Software as a Service (SaaS) and more recently Infrastructure as a Service (IaaS) and Platform as a Service (PaaS). Its aim is to change the way we compute, moving from traditional desktop and on-premises servers to services and resources that are hosted in the cloud.  Benefits of Cloud Computing  There are clearly benefits in building applications using cloud computing, some of which are listed here:  Zero up- front investment:  Delivering a large-scale system costs a fortune in both time and money. Often IT departments are split into hardware/network and software services. The hardware team provisions servers and so forth under the requirements of the software team. Often the hardware team has a different budget that requires approval. Although hardware and software management are two separate disciplines, sometimes what happens is developers are given the task to estimate CPU cycles, disk space, and so forth, which ends up in underutilized servers.  Usage-based costing:  You pay for what you use, no more, no less, because you never actually own the server. This is similar to car leasing, where in the long run you get a new car every three years and maintenance is never a worry.  Potential for shrinking the processing time:  If processes are split over multiple machines, parallel processing is performed, which decreases processing time.  More office space:  Walk into most offices, and guaranteed you will find a medium- sized room dedicated to servers.  Efficient resource utilization:  The resource utilization is handed by a centralized cloud administrator who is in charge of deciding exactly the right amount of resources for a system. This takes the task away from local administrators, who have to regularly monitor these servers.  Just-in-time infrastructure:  If your system is a success and needs to scale to meet demand, this can cause further time delays or a slow- performing service. Cloud computing solves this because you can add more resources at any time.  Lower environmental impact:  If servers are centralized, potentially an environment initiative is more likely to succeed. As an example, if servers are placed in sunny or windy parts of the world, then why not use these resources to power those servers?  Lower costs:  Unfortunately, this is one point that administrators will not like. If you have people administrating your e-mail server and network along with support staff doing other cloud-based tasks, this workforce can be reduced. This saves costs, though it also reduces jobs.

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  • To Obtain EPOCH Time Value from a Packed BIT Structure in C [migrated]

    - by xde0037
    This is not a home assignment! We have a binary data file which has following data structure: (It is a 12 byte structure): I need to find out Epoch time value(total time value is packed in 42 bits as described below): Field-1 : Byte 1, Byte 2, + 6 Bits from Byte 3 Time-1 : 2 Bits from Byte 3 + Byte 4 Time-2 : Byte 5, Byte 6, Byte 7, Byte 8 Field-2 : Byte 9, Byte 10, Byte 11, Byte 12 For Field-1 and Field-2 I do not have issue as they can be taken out easily. I need time value in Epoch Time (long) as it has been packed in Bytes 5,6,7,8 and 3 and 4 as follows: (the bit structure for the time value is as follows): Bytes 5 to 8 (32 bit word) Packs time value bits from 0 thru 31 (byte 5 has 0 to 7 bits, byte 6 has 8 to 15, byte 7 has 16 to 23, byte 8 has 24 to 31). the remaining 10 bits of time value are packed in Bytes 3 and byte 4 as follows: byte 3 has 2 bits:32 and 33, and Byte 4 has remaining bits : 34 to 41. So total bits for time value is 42 bits, packed as above. I need to compute epoch value coming out of these 42 bits. How do I do it? I have done something like this but not sure it gives me correct value: typedef struct P_HEADER { unsigned int tmuNumber : 21; unsigned int time1 : 10; // Bits 6,7 from Byte-3 + 8 bits from Byte-4 unsigned int time2 : 32; // 32 bits: Bytes 5,6,7,8 unsigned int traceKey : 32; } __attribute__((__packed__)) P_HEADER; Then in the code : P_HEADER *header1; //get input string in hexa,etc..etc.. //parse the input with the header as : header1 = (P_HEADER *)inputBuf; // then print the header1->time1, header1->time2 .... long ttime = header1->time1|header1->time2; //?? is this the way to get values out? Any hint tip will be appreciated. Environment is : gcc 4.1, Linux Thanks in advance.

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  • Formatting a truecrypt volume on windows: Truecrypt failed to obtain administrator privileges

    - by daveh551
    Following shaneselman's advice (http://www.hanselman.com/blog/TheComputerBackupRuleOfThree.aspx), I'm setting up a 2TB external drive as a backup, and encrypting it using TrueCrypt. This is under Windows 7. (I've used TrueCrypt before, but not since XP days.) I installed TrueCrypt with default options. After taking 23 hours to format the 2TB container, it finishes with an error saying "TrueCrypt cannot obtain administrator privileges." When I click OK on that, it says it can't format the container as NTFS, do I want to format it as FAT, and I don't so I click No, and it exits with nothing to show for 23 hours of compute time. So I set the "Run as administrator flag" on the TrueCrypt shortcut, and try again. This time, when I go to format the contain (prepared to wait ANOTHER 23 hours), it pops up a dialog saying you're formatting this as administrator. "The volume may be created with permissions that will not allow you to write to the volume when it is mounted. If you want to avoid that, close this instance of Volume Creation Wizard and launch a new one without administrator privileges." Great - I can either run as non-administrator, and it will fail to create the volume at all, or I can run as administrator and create a volume I can't write to. I think I'm doing something wrong, but it's not clear to me what. Any help?

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  • Amazon Ec2: Problem In Setting up FTP Server

    - by Muntasir
    after setting up My vsFtp Server ON Ec2 i am facing problem , my client is Filezilla and i am getting this error Response: 230 Login successful. Command: OPTS UTF8 ON Response: 200 Always in UTF8 mode. Status: Connected Status: Retrieving directory listing... Command: PWD Response: 257 "/" Command: TYPE I Response: 200 Switching to Binary mode. Command: PASV Response: 500 OOPS: invalid pasv_address Command: PORT 10,130,8,44,240,50 Response: 500 OOPS: priv_sock_get_cmd Error: Failed to retrieve directory listing Error: Connection closed by server this is the current setting in my vsftpd.conf #nopriv_user=ftpsecure #async_abor_enable=YES # ASCII mangling is a horrible feature of the protocol. #ascii_upload_enable=YES #ascii_download_enable=YES # You may specify a file of disallowed anonymous e-mail addresses. Apparently # useful for combatting certain DoS attacks. #deny_email_enable=YES # (default follows) #banned_email_file=/etc/vsftpd/banned_emails # chroot_local_user=YES #chroot_list_enable=YES # (default follows) #chroot_list_file=/etc/vsftpd/chroot_list GNU nano 2.0.6 File: /etc/vsftpd/vsftpd.conf # #ls_recurse_enable=YES # # When "listen" directive is enabled, vsftpd runs in standalone mode and # listens on IPv4 sockets. This directive cannot be used in conjunction # with the listen_ipv6 directive. listen=YES # # This directive enables listening on IPv6 sockets. To listen on IPv4 and IPv6 # sockets, you must run two copies of vsftpd with two configuration files. # Make sure, that one of the listen options is commented !! #listen_ipv6=YES pam_service_name=vsftpd userlist_enable=YES tcp_wrappers=YES pasv_enable=YES pasv_min_port=2345 pasv_max_port=2355 listen_port=1024 pasv_address=ec2-xxxxxxx.compute-1.amazonaws.com pasv_promiscuous=YES Note: i have already open those port in security group i mean listen port, min max if someone shows me how to fix this i will be very greatful thanks

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  • How to update a uniform variable in GLSL

    - by paj777
    Hi All, I am trying to get update the eye position in my shader from my appliaction but I keep getting error 1281 when I attempt this. I have no problems after the initialization just when i subsequently try to update the values. Here is my code: void GraphicsObject::SendShadersDDS(char vertFile [], char fragFile [], char filename []) { char *vs = NULL,*fs = NULL; vert = glCreateShader(GL_VERTEX_SHADER); frag = glCreateShader(GL_FRAGMENT_SHADER); vs = textFileRead(vertFile); fs = textFileRead(fragFile); const char * ff = fs; const char * vv = vs; glShaderSource(vert, 1, &vv, NULL); glShaderSource(frag, 1, &ff, NULL); free(vs); free(fs); glCompileShader(vert); glCompileShader(frag); program = glCreateProgram(); glAttachShader(program, frag); glAttachShader(program, vert); glLinkProgram(program); glUseProgram(program); LoadCubeTexture(filename, compressedTexture); GLint location = glGetUniformLocation(program, "tex"); glUniform1i(location, 0); glActiveTexture(GL_TEXTURE0); EyePos = glGetUniformLocation(program, "EyePosition"); glUniform4f(EyePos, EyePosition.X(),EyePosition.Y(), EyePosition.Z(), 1.0); DWORD bob = glGetError(); //All is fine here glEnable(GL_DEPTH_TEST); } And here's the function I call to update the eye position: void GraphicsObject::UpdateEyePosition(Vector3d& eyePosition){ glUniform4f(EyePos, eyePosition.X(),eyePosition.Y(), eyePosition.Z(), 1.0); DWORD bob = glGetError(); //bob equals 1281 after this call } I've tried a few ways now of updating the variable and this is the latest incarnation, thanks for viewing, all comments welcome.

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  • Implement QoS/Bandwidth Management or Upgrade Bandwidth?

    - by Michael
    A question that I'm faced with currently. Here's my setup: Cisco ASA 5510 15Mbps Internet Connection @ $1350/month The bandwidth was originally meant for 35-45 people but we've grown quite quickly to roughly 60-65 people. Needless to say, when I check bandwidth logs it's almost always spiked at 15Mbps. I did use Wireshark to do some poking around to see what was hogging up our bandwidth but with everything running through CDNs and Cloud Services it proved difficult to get a good grasp of where our bandwidth was going. So the question is do I ONLY implement bandwidth management through ASA OR upgrade the Internet to 50Mbps ($1600/month) and then implement bandwidth management through ASA? Any suggestions on how to segment the 15Mbps connection if we decided ONLY to go with the bandwidth management solution? Thanks. UPDATE 1 Installed PRTG and used packet content to monitor the traffic. As I suspected still pretty vague. My Top Connections include the following: a204-2-160-16.deploy.akamaitechnologies.com ec2-50-16-212-159.compute-1.amazonaws.com a204-2-160-48.deploy.akamaitechnologies.com a72-247-247-133.deploy.akamaitechnologies.com mediaserver-sv5-t1-1.pandora.com Other than the Pandora destination, the rest doesn't tell me much on how to properly control the bandwidth. Any thoughts or suggestions? Thanks. M

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  • EC2 Ubuntu - Force instance to use internal IP

    - by Peter
    I've just set up a micro instance on EC2 (AMI ID ami-e59ca991). I had hoped to avoid charges for a year as my usage falls well within the bound of the free tier. I have been charged $0.01 for "regional data transfer". I read here that this is because my instance is talking to its self via it's external IP address. From what I've Googled it looks like you can stop the charges by making sure that the instance uses its internal IP address. However, when I ping the hostname of my instance internally (via an ssh session) it resolves to the instances internal IP address. How can I configure my instance so that I do not get these charges? Is it as simple as adding a line to my hosts file? Additionally, is this the real reason for the charge? I'm concerned that I've misunderstood the pricing somewhere. I have Apace and MySQL (with phpmyadmin) running on the machine - could I be being charged for data transfer associated with these (I have only one flat HTML page and I have only logged in via phpmyadmin - I have no data in my database). Edit: Additionally, my user account on MySQL was declared as: grant all privileges on *.* to 'peter'@'localhost'; Should I have instead used the internal hostname for the instance? grant all privileges on *.* to '[email protected].compute.internal'; Cheers, Pete

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  • get-eventlog issue

    - by Jim B
    I wanted to get a quick report of some log entries I saw on a server, so I ran: Get-Eventlog -logname system -newest 10 -computer fs1 | fl I got events back however the descriptions were all wrong. Here's an example: Index : 1260055 EntryType : Warning InstanceId : 2186936367 Message : The description for Event ID '-2108030929' in Source 'W32Time' cannot be found. The local compute r may not have the necessary registry information or message DLL files to display the message, or you may not have permission to access them. The following information is part of the event:'time. windows.com,0x1' Category : (0) CategoryNumber : 0 ReplacementStrings : {time.windows.com,0x1} Source : W32Time TimeGenerated : 1/25/2010 10:43:31 AM TimeWritten : 1/25/2010 10:43:31 AM UserName : Note that if I pull the event ID property it's correct (in this case 38) Is this is known issue or is something wrong. The messages resolve fine via event viewer locally and remotely Here is the powershell version info: Name : ConsoleHost Version : 2.0 InstanceId : bc58fcf8-bba3-4ca8-8972-17dbd5d9ff08 UI : System.Management.Automation.Internal.Host.InternalHostUserInterface CurrentCulture : en-US CurrentUICulture : en-US PrivateData : Microsoft.PowerShell.ConsoleHost+ConsoleColorProxy IsRunspacePushed : False Runspace : System.Management.Automation.Runspaces.LocalRunspace Here is the revised version info: Name Value ---- ----- CLRVersion 2.0.50727.3603 BuildVersion 6.0.6002.18111 PSVersion 2.0 WSManStackVersion 2.0 PSCompatibleVersions {1.0, 2.0} SerializationVersion 1.1.0.1 PSRemotingProtocolVersion 2.1

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  • Beginning Java (Working with Arrays; Class Assignment)

    - by Jason
    I am to the point where I feel as if I correctly wrote the code for this homework assignment. We were given a skeleton and 2 classes that we had to import (FileIOHelper and Student). /* * Created: *** put the date here *** * * Author: *** put your name here *** * * The program will read information about students and their * scores from a file, and output the name of each student with * all his/her scores and the total score, plus the average score * of the class, and the name and total score of the students with * the highest and lowest total score. */ // import java.util.Scanner; import java.io.*; // C:\Users\Adam\info.txt public class Lab6 { public static void main(String[] args) throws IOException { // Fill in the body according to the following comments Scanner key boardFile = new Scanner(System.in); // Input file name String filename = getFileName(keyboardFile); //Open the file // Input number of students int numStudents = FileIOHelper.getNumberOfStudents(filename); Student students[] = new Student[numStudents]; // Input all student records and create Student array and // integer array for total scores int totalScore[] = new int[students.length]; for (int i = 0; i < students.length; i++){ for(int j = 1; j < 4; j++){ totalScore[i] = totalScore[i] + students[i].getScore(j); } } // Compute total scores and find students with lowest and // highest total score int maxScore = 0; int minScore = 0; for(int i = 0; i < students.length; i++){ if(totalScore[i] >= totalScore[maxScore]){ maxScore = i; } else if(totalScore[i] <= totalScore[minScore]){ minScore = i; } } // Compute average total score int allScores = 0; int average = 0; for (int i = 0; i < totalScore.length; i++){ allScores = allScores + totalScore[i]; } average = allScores / totalScore.length; // Output results outputResults(students, totalScore, maxScore, minScore, average); } // Given a Scanner in, this method prompts the user to enter // a file name, inputs it, and returns it. private static String getFileName(Scanner in) { // Fill in the body System.out.print("Enter the name of a file: "); String filename = in.next(); return filename; // Do not declare the Scanner variable in this method. // You must use the value this method receives in the // argument (in). } // Given the number of students records n to input, this // method creates an array of Student of the appropriate size, // reads n student records using the FileIOHelper, and stores // them in the array, and finally returns the Student array. private static Student[] getStudents(int n) { Student[] myStudents = new Student[n]; for(int i = 0; i <= n; i++){ myStudents[i] = FileIOHelper.getNextStudent(); } return myStudents; } // Given an array of Student records, an array with the total scores, // the indices in the arrays of the students with the highest and // lowest total scores, and the average total score for the class, // this method outputs a table of all the students appropriately // formatted, plus the total number of students, the average score // of the class, and the name and total score of the students with // the highest and lowest total score. private static void outputResults( Student[] students, int[] totalScores, int maxIndex, int minIndex, int average ) { // Fill in the body System.out.println("\nName \t\tScore1 \tScore2 \tScore3 \tTotal"); System.out.println("--------------------------------------------------------"); for(int i = 0; i < students.length; i++){ outputStudent(students[i], totalScores[i], average); System.out.println(); } System.out.println("--------------------------------------------------------"); outputNumberOfStudents(students.length); outputAverage(average); outputMaxStudent(students[maxIndex], totalScores[maxIndex]); outputMinStudent(students[minIndex], totalScores[minIndex]); System.out.println("--------------------------------------------------------"); } // Given a Student record, the total score for the student, // and the average total score for all the students, this method // outputs one line in the result table appropriately formatted. private static void outputStudent(Student s, int total, int avg) { System.out.print(s.getName() + "\t"); for(int i = 1; i < 4; i++){ System.out.print(s.getScore(i) + "\t"); } System.out.print(total + "\t"); if(total < avg){ System.out.print("-"); }else if(total > avg){ System.out.print("+"); }else{ System.out.print("="); } } // Given the number of students, this method outputs a message // stating what the total number of students in the class is. private static void outputNumberOfStudents(int n) { System.out.println("The total number of students in this class is: \t" + n); } // Given the average total score of all students, this method // outputs a message stating what the average total score of // the class is. private static void outputAverage(int average) { System.out.println("The average total score of the class is: \t" + average); } // Given the Student with highest total score and the student's // total score, this method outputs a message stating the name // of the student and the highest score. private static void outputMaxStudent( Student student, int score ) { System.out.println(student.getName() + " got the maximum total score of: \t" + score); } // Given the Student with lowest total score and the student's // total score, this method outputs a message stating the name // of the student and the lowest score. private static void outputMinStudent( Student student, int score ) { System.out.println(student.getName() + " got the minimum total score of: \t" + score); } } But now I get an error at the line totalScore[i] = totalScore[i] + students[i].getScore(j); Exception in thread "main" java.lang.NullPointerException at Lab6.main(Lab6.java:42)

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  • Why do AWS spot-instance prices spike above the "on demand" pricing?

    - by Laykes
    Amazon Pricing on Spot Instance Inconsistencies This is something which will be best explained through screenshots of a historical chart of instance pricings. If you look at a lot of the instance prices for spot instances, you will notice regular patterns of spikes. See here: As you can see, the price for this compute medium instance, regularly spikes above the on demand price. A c1.medium instance (on demand), would only cost $0.186 per hour. But for a period of a few weeks, in zone B, the price would regularly spike to $1.20. This is some 6 times the actual on demand price. It's also not isolated. If you look at zone-b again for small instances, there is a similar, spike frequently. Which goes 4x the on demand pricing. Does anyone know why this happens? Here are a few suggestions Someone entered $1.2 instead of $0.12 (I would discount this since it happened 20 times over the space of 3 weeks). Amazon regularly artifically inflate their prices by bidding on their own instances to get the most bang for their buck. (I would discount this since it would be ridiculous and bad business) Some company launched 1000 servers at once, and wants to make sure that they all launch. (I would discount this since they would presumably launch them at a price which would be below the minimum on demand price. Why would you pay above on demand for a single server?). It's a bug in their reporting?

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