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• Linked List pop() function

  - by JKid314159

  Consider the following list: [LinkNode * head -- LinkNode * node1 -- LinkNode * node2] I'm creating a stack of FIFO. I Call pop() which I want to pop node1. LinkNode::LinkNode(int numIn) { this->numIn = numIn; next = null; } . . . int LinkNode::pop() { Link * temp = head->next; head = temp->next; int popped = head->nodeNum; delete temp; Return numOut; Question: 1) head should be a pointer or a LinkNode *? 2) Link * temp is created on the call stack and when pop finishes doesn't temp delete automatically? 3) My major confusion is on what is the value of temp-next? Does this point to node1.next which equals node2? Appreciate your help? My reference is C++ for Java Programmers by Weiss.

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• sorting names in a linked list

  - by sil3nt

  Hi there, I'm trying to sort names into alphabetical order inside a linked list but am getting a run time error. what have I done wrong here? #include <iostream> #include <string> using namespace std; struct node{ string name; node *next; }; node *A; void addnode(node *&listpointer,string newname){ node *temp; temp = new node; if (listpointer == NULL){ temp->name = newname; temp->next = listpointer; listpointer = temp; }else{ node *add; add = new node; while (true){ if(listpointer->name > newname){ add->name = newname; add->next = listpointer->next; break; } listpointer = listpointer->next; } } } int main(){ A = NULL; string name1 = "bob"; string name2 = "tod"; string name3 = "thomas"; string name4 = "kate"; string name5 = "alex"; string name6 = "jimmy"; addnode(A,name1); addnode(A,name2); addnode(A,name3); addnode(A,name4); addnode(A,name5); addnode(A,name6); while(true){ if(A == NULL){break;} cout<< "name is: " << A->name << endl; A = A->next; } return 0; }

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• Best MAILING LIST solution for a CONFERENCE and its 400 participants

  - by Ole Morten Amundsen

  Dear community, what would you recommend for mailling lists? The conference is non-profit, named Smidig2010 (=Agile2010 in norwegian), will have about 400-500 participants 16.-17.november. At the time of writing this, we have not opened for registration, but would like people to be able to participate, ask questions, get informed and get inspired. We've used a forum before, but forums don't seem to be a good fit for this. I would like to set up a mailinglist, It'll have to be KISS, for the users: enter your email (a input box at our site smidig2010.no) get a confirmation mail, click a link. start posting, reading through archives, answering others etc. I like the look and feel of googlegroups, but I don't like the signup/account creation overhead imposed on the user. I've heard you may combine googlegroups with mailman and stuff, but, yeah, I can't believe our own incompetence on this subject! Btw, we are mostly developers and the conference app is being written in ruby on rails. Being non-profit, we prefer free, but we take everything into consideration. Any suggestions?

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• How to take a Serialized String from the DB and output a UL list with Coldfusion

  - by nobosh

  Given a string from the database as follows: ul[0][id]=main1&ul[0][children][0][id]=child2&ul[0][children][0][class]=&ul[1][id]=main3&ul[2][id]=main4&ul[3][id]=main5 Where what's after the equal sign is an ID, how can I take this string on the backend and build out a list as following from front-end output? <UL id="container"> <LI id="main1"> Lorem ipsum dolor sit amet, consectetur <UL> <LI id="child2"> In hac habitasse platea dictumst. <UL></UL> </LI> </UL> </LI> <LI id="main3"> In hac habitasse platea dictumst. <UL></UL> </LI> <LI id="main4"> In hac habitasse platea dictumst. <UL></UL> </LI> <LI id="main5"> In hac habitasse platea dictumst. <UL></UL> </LI> </UL> Thanks

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• GUI Freezes and Output to JTextField from user input

  - by user2929005

  I am having I hope only two issues currently. I have had help on this on a previous question that I have asked but now I am running into different issues. My current issues now is that I need to print out into a JTextField a sorted array. I do not have questions about how to sort the array I just would like help on how to get the array to print to the JTextField when the Bubble Sort button is pressed. Currently when I press the button it freezes. It freezes at this line. list.add(Integer.valueOf(input.nextInt())); please help Thank you. import java.awt.EventQueue; import javax.swing.*; import java.awt.event.*; import java.util.*; public class Sorting { private JFrame frame; private JTextArea inputArea; private JTextField outputArea; ArrayList<Integer> list = new ArrayList<Integer>(); Scanner input = new Scanner(System.in); /** * Launch the application. */ public static void main(String[] args) { EventQueue.invokeLater(new Runnable() { public void run() { try { Sorting window = new Sorting(); window.frame.setVisible(true); } catch (Exception e) { e.printStackTrace(); } } }); } /** * Create the application. */ public Sorting() { initialize(); } /** * Initialize the contents of the frame. */ private void initialize() { frame = new JFrame(); frame.setBounds(100, 100, 450, 300); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.setTitle("Sorting"); frame.getContentPane().setLayout(null); JButton bubbleButton = new JButton("Bubble Sort"); bubbleButton.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent arg0) { list.add(Integer.valueOf(input.nextInt())); // for(int i = 0; i < list.size(); i++){ // // } } }); bubbleButton.setBounds(10, 211, 114, 23); frame.getContentPane().add(bubbleButton); JButton mergeButton = new JButton("Merge Sort"); mergeButton.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent e) { } }); mergeButton.setBounds(305, 211, 114, 23); frame.getContentPane().add(mergeButton); JButton quickButton = new JButton("Quick Sort"); quickButton.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent e) { } }); quickButton.setBounds(163, 211, 114, 23); frame.getContentPane().add(quickButton); inputArea = new JTextArea(); inputArea.setBounds(10, 36, 414, 51); frame.getContentPane().add(inputArea); outputArea = new JTextField(); outputArea.setEditable(false); outputArea.setBounds(10, 98, 414, 59); frame.getContentPane().add(outputArea); outputArea.setColumns(10); JLabel label = new JLabel("Please Enter 5 Numbers"); label.setHorizontalAlignment(SwingConstants.CENTER); label.setBounds(10, 11, 414, 14); frame.getContentPane().add(label); } }

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• Weird margin in a list

  - by kevin

  I'm trying to style a menu, but I keep running into this weird margin that's appearing in both FF4 and IE. This is the only affecting css: #header ul { display: inline; } #header ul li { list-style-type: none; background: #000; display: inline; margin: 0; padding: 0; } #header ul li a { color: #fff; text-decoration: none; display: inline-block; width: 100px; text-align: center; } And this is the HTML: <div id="header"> <ul id="toplinks"> <li><a href="#">Hello</a></li> <li><a href="#">Herp</a></li> <li><a href="#">Derp</a></li> </ul> </div> As you can see, there's a margin appearing on both sides, and I'd like it so it would have no margin (or maybe 1px would be okay)...

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• pointer to a pointer in a linked list

  - by user1596497

  I'm trying to set a linked list head through pointer to a pointer. I can see inside the function that the address of the head pointer is changing but as i return to the main progran it becomes NULL again. can someone tell me what I'm doing wrong ?? #include <stdio.h> #include <stdlib.h> typedef void(*fun_t)(int); typedef struct timer_t { int time; fun_t func; struct timer_t *next; }TIMER_T; void add_timer(int sec, fun_t func, TIMER_T *head); void run_timers(TIMER_T **head); void timer_func(int); int main(void) { TIMER_T *head = NULL; int time = 1; fun_t func = timer_func; while (time < 1000) { printf("\nCalling add_timer(time=%d, func=0x%x, head=0x%x)\n", time, func, &head); add_timer(time, func, head); time *= 2; } run_timers(&head); return 0; } void add_timer(int sec, fun_t func, TIMER_T *head) { TIMER_T ** ppScan=&head; TIMER_T *new_timer = NULL; new_timer = (TIMER_T*)malloc(sizeof(TIMER_T)); new_timer->time = sec; new_timer->func = func; new_timer->next = NULL; while((*ppScan != NULL) && (((**ppScan).time)<sec)) ppScan = &(*ppScan)->next; new_timer->next = *ppScan; *ppScan = new_timer; }

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• Should xml represent a set or a list?

  - by sixtyfootersdude

  I always think of xml like a set data structure. Ie: <class> <person>john</person> <person>sarah</person> </class> Is equivalent to: <class> <person>sarah</person> <person>john</person> </class> Question One: Are these two things logicly equivalant? Are you allowed to make things like this in xml? <methodCall> <param>happy</param> <param>sad</param> </methodCall> Or do you need to do it like this: <methodCall> <param arg="1">happy</param> <param arg="2">sad</param> </methodCall> Question Two: Are these two things logically equivalent? Question Three: Is xml usually treated like a set or a list?

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• adding elements in to the doubly linked list

  - by user329820

  Hi this is my code for main class and doubly linked class and node class but when I run the program ,in the concole will show this"datastructureproject.DoublyLinkedList@19ee1ac" instead of the random numbers .please help me thanks! main class: public class Main { public static int getRandomNumber(double min, double max) { Random random = new Random(); return (int) (random.nextDouble() * (max - min) + min); } public static void main(String[] args) { int j; int i = 0; i = getRandomNumber(10, 10000); DoublyLinkedList listOne = new DoublyLinkedList(); for (j = 0; j <= i / 2; j++) { listOne.add(getRandomNumber(10, 10000)); } System.out.println(listOne); } } doubly linked list class: public class DoublyLinkedList { private Node head ; private Node tail; private long size = 0; public DoublyLinkedList() { head= new Node(0, null, null); tail = new Node(0, head, null); } public void add(int i){ head.setValue(i); Node newNode = new Node(); head.setNext(newNode); newNode.setPrev(head); newNode = head; } } and the node class is like the class that you have seen before (Node prev,Node next,int value)

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• Linked List Inserting strings in alphabetical order

  - by user69514

  I have a linked list where each node contains a string and a count. my insert method needs to inset a new node in alphabetical order based on the string. if there is a node with the same string, then i increment the count. the problem is that my method is not inserting in alphabetical order public Node findIsertionPoint(Node head, Node node){ if( head == null) return null; Node curr = head; while( curr != null){ if( curr.getValue().compareTo(node.getValue()) == 0) return curr; else if( curr.getNext() == null || curr.getNext().getValue().compareTo(node.getValue()) > 0) return curr; else curr = curr.getNext(); } return null; } public void insert(Node node){ Node newNode = node; Node insertPoint = this.findIsertionPoint(this.head, node); if( insertPoint == null) this.head = newNode; else{ if( insertPoint.getValue().compareTo(node.getValue()) == 0) insertPoint.getItem().incrementCount(); else{ newNode.setNext(insertPoint.getNext()); insertPoint.setNext(newNode); } } count++; }

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• Deleting first and last element of a linked list in C

  - by LuckySlevin

  struct person { int age; char name[100]; struct person *next; }; void delfirst(struct person **p)// For deleting the beginning { struct person *tmp,*m; m = (*p); tmp = (*p)->next; free(m); return; } void delend(struct person **p)// For deleting the end { struct person *tmp,*m; tmp=*p; while(tmp->next!=NULL) { tmp=tmp->next; } m->next=tmp; free(tmp); m->next = NULL; return; } I'm looking for two seperate functions to delete the first and last elements of a linked list. Here is what i tried. What do you suggest? Especially deleting first is so problematic for me.

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• Cleaner method for list comprehension clean-up

  - by Dan McGrath

  This relates to my previous question: Converting from nested lists to a delimited string I have an external service that sends data to us in a delimited string format. It is lists of items, up to 3 levels deep. Level 1 is delimited by '|'. Level 2 is delimited by ';' and level 3 is delimited by ','. Each level or element can have 0 or more items. An simplified example is: a,b;c,d|e||f,g|h;; We have a function that converts this to nested lists which is how it is manipulated in Python. def dyn_to_lists(dyn): return [[[c for c in b.split(',')] for b in a.split(';')] for a in dyn.split('|')] For the example above, this function results in the following: >>> dyn = "a,b;c,d|e||f,g|h;;" >>> print (dyn_to_lists(dyn)) [[['a', 'b'], ['c', 'd']], [['e']], [['']], [['f', 'g']], [['h'], [''], ['']]] For lists, at any level, with only one item, we want it as a scalar rather than a 1 item list. For lists that are empty, we want them as just an empty string. I've came up with this function, which does work: def dyn_to_min_lists(dyn): def compress(x): return "" if len(x) == 0 else x if len(x) != 1 else x[0] return compress([compress([compress([item for item in mv.split(',')]) for mv in attr.split(';')]) for attr in dyn.split('|')]) Using this function and using the example above, it returns: [[['a', 'b'], ['c', 'd']], 'e', '', ['f', 'g'], ['h', '', '']] Being new to Python, I'm not confident this is the best way to do it. Are there any cleaner ways to handle this? This will potentially have large amounts of data passing through it, are there any more efficient/scalable ways to achieve this?

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• Python - creating a list with 2 characteristics bug

  - by user2733911

  The goal is to create a list of 99 elements. All elements must be 1s or 0s. The first element must be a 1. There must be 7 1s in total. import random import math import time # constants determined through testing generation_constant = 0.96 def generate_candidate(): coin_vector = [] coin_vector.append(1) for i in range(0, 99): random_value = random.random() if (random_value > generation_constant): coin_vector.append(1) else: coin_vector.append(0) return coin_vector def validate_candidate(vector): vector_sum = sum(vector) sum_test = False if (vector_sum == 7): sum_test = True first_slot = vector[0] first_test = False if (first_slot == 1): first_test = True return (sum_test and first_test) vector1 = generate_candidate() while (validate_candidate(vector1) == False): vector1 = generate_candidate() print vector1, sum(vector1), validate_candidate(vector1) Most of the time, the output is correct, saying something like [1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0] 7 True but sometimes, the output is: [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] 2 False What exactly am I doing wrong?

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• Partner outreach on the Oracle Fusion Applications user experience begins

  - by mvaughan

  by Misha Vaughan, Architect, Applications User Experience I have been asked the question repeatedly since about December of last year: “What is the Applications User Experience group doing about partner outreach?”  My answer, at the time, was: “We are thinking about it.”  My colleagues and I were really thinking about the content or tools that the Applications UX group should be developing. What would be valuable to our partners? What will actually help grow their applications business, and fits within the applications user experience charter?In the video above, you’ll hear Jeremy Ashley, vice president of the Applications User Experience team, talk about two fundamental initiatives that our group is working on now that speaks straight to partners.  Special thanks to Joel Borellis, Kelley Greenly, and Steve Hoodmaker for helping to make this video happen so flawlessly. Steve was responsible for pulling together a day of Oracle Fusion Applications-oriented content, including David Bowin, Director, Fusion Applications Strategy, on some of the basic benefits of Oracle Fusion Applications.  Joel Borellis, Group Vice President, Partner Enablement, and David Bowin in the Oracle Studios.Nigel King, Vice President Applications Functional Architecture, was also on the list, talking about co-existence opportunities with Oracle Fusion Applications.Me and Nigel King, just before his interview with Joel. Fusion Applications User Experience 101: Basic education  Oracle has invested an enormous amount of intellectual and developmental effort in the Oracle Fusion Applications user experience. Find out more about that at the Oracle Partner Network Fusion Learning Center (Oracle ID required). What you’ll learn will help you uncover how, exactly, Oracle made Fusion General Ledger “sexy,” and that’s a direct quote from Oracle Ace Director Debra Lilley, of Fujitsu. In addition, select Applications User Experience staff members, as well as our own Fusion User Experience Advocates,  can provide a briefing to our partners on Oracle’s investment in the Oracle Fusion Applications user experience. Looking forward: Taking the best of the Fusion Applications UX to your customersBeyond a basic orientation to one of the key differentiators for Oracle Fusion Applications, we are also working on partner-oriented training.A question we are often getting right now is: “How do I help customers build applications that look like Fusion?” We also hear: “How do I help customers build applications that take advantage of the next-generation design work done in Fusion?”Our answer to this is training and a tool – our user experience design patterns – these are a set of user experience best-practices. Design patterns are re-usable, usability-tested, user experience components that make creating Fusion Applications-like experiences straightforward.  It means partners can leverage Oracle’s investment, but also gain an advantage by not wasting time solving a problem we’ve already solved. Their developers can focus on helping customers tackle the harder development challenges. Ultan O’Broin, an Apps UX team member,  and I are working with Kevin Li and Chris Venezia of the Oracle Platform Technology Services team, as well as Grant Ronald in Oracle ADF, to bring you some of the best “how-to” UX training, customized for your local area. Our first workshop will be in EMEA. Stay tuned for an assessment and feedback from the event.

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• In Windows 7 Home Premium, is it possible to grant a user account the "log on as a service" right and if so, how?

  - by Ryan Johnson

  The title says it all. I need to have the ability for a local user account to log on as a service on a computer running Windows 7 Home Premium. In Windows 7 Ultimate, this is accomplished by going to Control Panel - Administrative Tools - Local Security Policy and adding the user to the "Log on as a service" policy. In Home Premium, there is no Local Security Policy in the Control Panel. Is there another way to add the use to that policy (i.e. registry setting) or is my only recourse to upgrade the computer to Windows 7 Professional? Thanks in Advance, Ryan

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• ps ux on OSX shows user for ps command to be root? Is this normal?

  - by snies

  I am running OS X 10.6.1 . When i am logged in as a normal user of group staff and do a ps ux it lists my ps ux command as being run by root: snies 181 0.0 0.3 2774328 12500 ?? S 6:00PM 0:20.96 /System/Library... root 1673 0.0 0.0 2434788 508 s001 R+ 8:16AM 0:00.00 ps ux snies 177 0.0 0.0 2457208 984 ?? Ss 6:00PM 0:00.52 /sbin/launchd snies 1638 0.0 0.0 2435468 1064 s001 S 8:13AM 0:00.03 -bash Is this normal behaviour? And if so why? Please note that the user is not an Administrator account and is not able to sudo.

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• Using Remote Desktop, connect to a Windows 7 domain user account without first logging on locally?

  - by Robert S Ciaccio

  I have a dell laptop (henceforth we'll call this the server) running Windows 7 Enterprise. The server is part of my company's domain. My primary user account is a domain account. When I am at home and not connected to the domain, I prefer to connect to the server using Remote Desktop Connection from my MacBook Pro (we'll call this the client). The problem is, that if I do not physically login to the server, I am unable to connect to it using RDC from the client. I have a local administrator account on the server, and connecting to it via RDC works just fine. I had a feeling that the Mac RDC application was not giving me the full story, so I attempted the same procedure from a Windows 7 client. When trying to login, I get this message: So basically, If I logon to the server physically with my domain user and lock the computer, I can then successfully logon from the client. Otherwise, I am unable to connect.

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• Using Remote Desktop, connect to a Windows 7 domain user account without first logging on locally?

  - by calavera

  I have a dell laptop (henceforth we'll call this the server) running Windows 7 Enterprise. The server is part of my company's domain. My primary user account is a domain account. When I am at home and not connected to the domain, I prefer to connect to the server using Remote Desktop Connection from my MacBook Pro (we'll call this the client). The problem is, that if I do not physically login to the server, I am unable to connect to it using RDC from the client. I have a local administrator account on the server, and connecting to it via RDC works just fine. I had a feeling that the Mac RDC application was not giving me the full story, so I attempted the same procedure from a Windows 7 client. When trying to login, I get this message: So basically, If I logon to the server physically with my domain user and lock the computer, I can then successfully logon from the client. Otherwise, I am unable to connect.

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• How to restrict access to a specific wireless network to only 1 user profile in Windows 7.

  - by Mathlight

  Hi all, I'm using Win7 SP1. I've got multiple users on the laptop that can / must connect to a wireless network, lets call it Wireless1. I've got an second wireless network, (lets call it Wireless2), which I want to limit access to only the admin user of the laptop. Now I can remove Wireless2 in the network manager every time, but i want a more user friendly solution, so that only the admin can connect to Wireless2, and all the other users cannot ( they may see the network, but must enter the password, like all other networks ). Any ideas?

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• Two users using the same same user profile while not in a domain.

  - by Scott Chamberlain

  I have a windows server 2003 acting as a terminal server, this computer is not a member of any domain. We demo our product on the server by creating a user account. The person logs in uses the demo for a few weeks and when they are done we delete the user account. However every time we do this it creates a new folder in C:\Documents and Settings\. I know with domains you can have many users point at one profile and make it read only so all changes are dumped afterwords, but is there a way to do that when the machine is not on a domain? I would really like it if I didn't have to remote in and clean up the folders every time.

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• From the Active Directory Snap-In, how can I find the GUID for a user?

  - by Ben Aston

  How ca I view the GUID associated with an Active Directory user under windows 7?

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• OS X: How to create a user account with access to the applications that she has installed only.

  - by pmurillo

  Till now, I've been the sole and proud owner of an iMac. I've always logged in as an administrator and I've also installed a bunch of software following the standard procedure of dragging and dropping it into the Applications folder. This is about to change, as sharing it with a friend makes a lot of sense now that I only have time to use the computer in the mornings, and she can only use it at nights. I thought this was going to be really easy: Just create a user account for her and that's all, I thought. Unfortunately, this is not the case. When she logins into the computer using her username and password, she has access to the same applications I've installed. Even the same applications that I setup to automatically start when I login start for her when she does. How can I setup a user that has only access to the applications that she has installed, but none of the ones installed by other users? Many thanks

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• How can I continue audio playback even after switching user?

  - by klyonrad

  I just tested it with iTunes; after switching the user account (only after logging into another account, to be precise) the audio playback from the account "A" stops. However iTunes continues playing in the background; which I realized after switching back to account "A". Very frustrating because it kind-of is a deal-breaker for me; the other person should be able to have some personalized settings; while it is still my computer, and the main account has all the music obviously. The ideal solution would be audio output continuing running while user still has the ability to manually pause it... EDIT: I tested a bit more: "Desktop" apps like VLC don't output sound but continue running; the stock Music.app in Metro pauses the music and continues playing when switching back.

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• How to Install vaio-control-center from source?

  - by KasiyA

  I have a problem about turning off keyboard backlight that I asked here with no useful answers. After searching on internet I find a package for vaio control center and downloaded it from here, I don't know how to install it. This is the output of trying one solution: USER@XXXXpc:~/vaio-control-center-0.1$ ls compile Makefile run vaio-control-center vcc COPYING moc_main_window.cpp ui_main_window.h vaio-control-center.pro USER@XXXXpc:~/vaio-control-center-0.1$ ./compile make: *** No rule to make target `/usr/share/qt/mkspecs/linux-g++-64/qmake.conf', needed by `Makefile'. Stop. USER@XXXXpc:~/vaio-control-center-0.1$ ./run ./run: 3: ./run: ./vaio-control-center: not found USER@XXXXpc:~/vaio-control-center-0.1$ Updated I tried also with @pandya's suggestion from here. and the output is as follows: root@user-pc:/# cd /home/user/vaio-f11-linux.control-center root@user-pc:/home/user/vaio-f11-linux.control-center# ls compile COPYING resource.qrc run sony-acpid vaio-control-center.pro vcc root@user-pc:/home/user/vaio-f11-linux.control-center# ./compile -su: ./compile: Permission denied root@user-pc:/home/user/vaio-f11-linux.control-center# sudo ./compile sudo: ./compile: command not found root@user-pc:/home/user/vaio-f11-linux.control-center# gksudo ./compile root@user-pc:/home/user/vaio-f11-linux.control-center# <----- nothing happened here root@user-pc:/home/user/vaio-f11-linux.control-center# ./run -su: ./run: Permission denied root@user-pc:/home/user/vaio-f11-linux.control-center# sudo ./run sudo: ./run: command not found root@user-pc:/home/user/vaio-f11-linux.control-center# gksudo ./run root@user-pc:/home/user/vaio-f11-linux.control-center# <----- nothing happened here root@user-pc:/home/user/vaio-f11-linux.control-center# and after running that I didn't see any affect on keyboard backlight.

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• Software tools for allowing end users to reprogram interfaces

  - by iceman

  What would be the examples of commercial software products (specially web-services) which allow the end user to reprogram their user-interface? I mean end users who do not know programming and they are allowed to add more functionality. One way of doing it is allowing XML gadgets like iGoogle does. What are the other approaches and also the technologies enabling them? This would be a futuristic application like collaborative software development for users.

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