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  • PLPGSQL : How to return a record from function executed by INSERT/UPDATE rule?

    - by seas
    Do the following scheme for my database: create sequence data_sequence; create table data_table { id integer primary key; field varchar(100); }; create view data_view as select id, field from data_table; create function data_insert(_new data_view) returns data_view as $$declare _id integer; _result data_view%rowtype; begin _id := nextval('data_sequence'); insert into data_table(id, field) values(_id, _new.field); select * into _result from data_view where id = _id; return _result; end; $$ language plpgsql; create rule insert as on insert to data_view do instead select data_insert(new); Then type in psql: insert into data_view(field) values('abc'); Would like to see something like: id | field ----+--------- 1 | abc Instead see: data_insert ------------- (1, "abc") Is it possible to fix this somehow? Thanks for any ideas. Ultimate idea is to use this in other functions, so that I could obtain id of just inserted record without selecting for it from scratch. Something like: insert into data_view(field) values('abc') returning id into my_variable would be nice but doesn't work with error: ERROR: cannot perform INSERT RETURNING on relation "data_view" HINT: You need an unconditional ON INSERT DO INSTEAD rule with a RETURNING clause. I don't really understand that HINT. I use PostgreSQL 8.4.

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  • Possible bug in ASP.net UpdatePanel control?

    - by Ben Robinson
    I have come across what seems to be an annoying bug with asp.net UpdatePanels in 2 seperate projects. If you have some kind of autopostback enabled control that can cause all of the controls in the update panel to have visible=false set, resulting in an empty update panel. When you change the autopostback control back to the postion that would re enable all of the controls in the update panel, it simply does not make a call back to the server and the update panel does not update. If you do anything else that makes a call back on the same page, then the update panel contents magically appear. It is as if asp.net has decided the update panel is empty so there is no point maikng a callback, even though making the call back would fill the updatepanel with content. The only way round this is to add a style of display:none to the controls instead of setting visible=false property. Then it works fine. Has anyone else encountered this problem? Is it a bug as i suspect or is it likely i am doing soemthing wrong? I haven't got time to post example code at the moment as the code i am using is too wrapped up in other unrealted things, if people think it would help i will create a simple example and post it when I get time.

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  • How do you update table row background color in IE using Javascript/CSS ?

    - by giulio
    I have a table that i want to "highlight" during onmouseover/onmouseout. I already know this is required in IE but not in other browsers. I have managed to detect the events triggering and this TR tag effectively works. (Note that the originating class "contentTableRow" doesn't seem to be causing any issues.) class="contentTableRow" onclick="openForm('SomeID');" onmouseover="highlight('someRowID', true);" onmouseout="highlight('someRowID', false);" id="someRowID" All is fine and dandy, the "highlight" function fires and actually sets the appropriate class. It's just that IE won't process the CSS class name change. Here is a snippet of the CSS I am using to make the change. .HighlightOn { cursor:pointer; background-color: #D1DFFF; } .HighlightOff { background-color: #E1EEFE; } I can see that the Class names are getting updated when I debug it, and also check it in Firebug. But it seems that IE doesn't like this usage of classes with a TR tag.. Is it the way I am structuring the class for Tables ? Any advice ?

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  • Issue using GAE appcfg.py

    - by JustSmith
    I get nothing out of appcfg.py besides the default output. I'm trying to upload some data to my development project with no luck at at all. From the instructions on the Google App Engine page the steps are as follows: Edit app.yaml update with appcfg.py make upload script upload with appcfg.py After step one I try to run the update and it never shows any success. The following commands product the same output: appcfg.py appcfg.py update appDir appcfg.py update appDir/ appcfg.py update /appDir If i try to follow the instructions from the appcfg.py output and type help upload and get: "help <action>" I get a response from the system, This command is not supported by the help utility. Try "update /?". cause I'm calling the system help command. If I use the command appcfg.py help upload I get the same result as just typing appcfg.py Can someone show me examples of the syntax to update the dev site, upload data to it and get appcfg.py to actually give help on its commands? Also I'm just assuming that the upload script and the .csv file that are being uploaded are in they myApp directory. Appreciate any help,

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  • Visual studio: automatically update C++ cpp/header file when the other is changed?

    - by Jon
    For example, if I change the signature in a function in either the header or the cpp, I'd like it to automatically change in the other one. If I add a new function in either, it should appear in both. If I delete a function, it could probably comment out the other one. Manually having to duplicate one's changes seems silly. Some people have mentioned http://www.lazycplusplus.com/ in response to a similar question, but it seems that that's a command line tool which would require saving and then running this external tool on a particular file. That's still more manual steps than I would have thought were necessary; I'd like this to apply changes as I type.

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  • How does Apple update the Airport menu while it is open? (How to change NSMenu when it is already op

    - by Tegeril
    I've got a statusbar item that pops open an NSMenu, and I have a delegate set and it's hooked up correctly (-(void)menuNeedsUpdate:(NSMenu *)menu works fine). That said, that method is setup to be called before the menu is displayed, I need to listen for that and trigger an asynchronous request, later updating the menu while it is open, and I can't figure out how that's supposed to be done. Thanks :)

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  • JAVA: How to use paint() method to update the previously drawn object?

    - by GamDroid
    How to use paint() such that when repaint() is called the previously drawn object should not get deleted when drawing the new object. That is the drawing area must get UPDATED only and not REDRAWN. In my code when one of many button is clicked, some aplhabet get displayed. I want to have functionality such that when other buttons are clicked the previously drawn alhabets must be present.Take is as if a string of alphabets getting created as the buttons are clicked. Im using Java Swing for coding. Some piece of my code: if(source == btnAlpha[i] ) bollyDraw.repaint(); //bollydraw is an object of a JPanel extended class having implemented the paintComponent(Graphics g) method In the paint() method: if (word[i] == key) { g.drawChars(word, i, 1, x, y); }

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  • Jquery draggable persistence either through mysql or saving cookie in the database?

    - by Muhammad Jehanzaib
    I want to know that how can I persist the divs dropped on a draggable. I have been trying since long but stuck at this point. Actually you can see the demo here. I have to save the user designed wedding floor. So whenever user logins next time he/ she is able to see the last design saved. The code is shown below: $(document).ready(function() { $("#droppable").droppable({ accept: '.draggable', drop: function(event, ui) { $(this).append($(ui.draggable).clone()); $("#droppable .draggable").addClass("objects"); $(".objects").removeClass("ui-draggable draggable"); $(".objects").draggable({ containment: 'parent', }); } }); $(".draggable").draggable({ helper: 'clone', tolerance: 'touch', cursor:'move' }); });

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  • Select list auto update on any kind of change?

    - by Tom Irons
    I have a jQuery that when you click on a select option it will show the next one, but you have to click, you cant just use the down arrow or "tab" to the next option. I am wondering what options do I have to make this work? Here is my jQuery: function typefunction() { var itemTypes = jQuery('#type'); var select = this.value; itemTypes.change(function () { if ($(this).val() == '1-Hand') { $('.1-Hand').show(); $('.2-Hand').hide(); $('.off').hide(); $('.Armor').hide(); } else $('.1-Hand').hide(); if ($(this).val() == '2-Hand') { $('.2-Hand').show(); $('.1-Hand').hide(); $('.off').hide(); $('.Armor').hide(); } else $('.2-Hand').hide(); if ($(this).val() == 'Armor') { $('.Armor').show(); $('.2-Hand').hide(); $('.off').hide(); $('.1-Hand').hide(); } else $('.Armor').hide(); if ($(this).val() == 'Off-Hand') { $('.Off').show(); $('.2-Hand').hide(); $('.1-Hand').hide(); $('.Armor').hide(); } else $('.Off').hide(); if ($(this).val() == '1-Hand') { $('.one-hand-dps').show(); $('.item-armor').hide(); $('.two-hand-dps').hide(); } else $('.one-hand-dps').hide(); if ($(this).val() == '2-Hand') { $('.two-hand-dps').show(); $('.one-hand-dps').hide(); $('.item-armor').hide(); } else $('.two-hand-dps').hide(); if ($(this).val() == 'Armor') { $('.item-armor').show(); $('.one-hand-dps').hide(); $('.two-hand-dps').hide(); } else $('.item-armor').hide(); }); } And the HTML: <div class="input-group item"> <span class="input-group-addon">Type</span> <select id="type" name="type" class="form-control" onclick="typefunction(); itemstats(); Armor(); OffHand(); TwoHand();"> <option value="Any Type">Any Type</option> <option value="1-Hand">1-Hand</option> <option value="2-Hand">2-Hand</option> <option value="Armor">Armor</option> <option value="Off-Hand">Off-Hand</option> </select> </div> <div class="input-group item"> <span class="1-Hand input-group-addon" style="display: none;">Sub-Type</span> <select class="1-Hand form-control" name="sub[1]" style="display: none;"> <option value="All 1-Hand Item Types">All 1-Hand Item Types</option> <option>Axe</option> <option>Ceremonial Knife</option> <option>Hand Crossbow</option> <option>Dagger</option> <option>Fist Weapon</option> <option>Mace</option> <option>Mighty Weapon</option> <option>Spear</option> <option>Sword</option> <option>Wand</option> </select> </div> <div class="input-group"> <span class="2-Hand input-group-addon" style="display: none; ">Sub-Type</span> <select class="2-Hand form-control" name="sub[2]" style="display: none;"> <option>All 2-Hand Item Types</option> <option>Two-Handed Axe</option> <option>Bow</option> <option>Diabo</option> <option>Crossbow</option> <option>Two-Handed Mace</option> <option>Two-Handed Mighty Weapon</option> <option>Polearm</option> <option>Staff</option> <option>Two-Handed Sword</option> </select> </div> <div class="input-group"> <span class="Armor input-group-addon" style="display: none;">Sub-Type</span> <select class="Armor form-control" name="sub[3]" style="display:none;"> <option>All Armor Item Types</option> <option>Amulet</option> <option>Belt</option> <option>Boots</option> <option>Bracers</option> <option>Chest Armor</option> <option>Cloak</option> <option>Gloves</option> <option>Helm</option> <option>Pants</option> <option>Mighty Belt</option> <option>Ring</option> <option>Shoulders</option> <option>Spirit Stone</option> <option>Voodoo Mask</option> <option>Wizard Hat</option> </select> </div> <div class="input-group"> <span class="Off input-group-addon" style="display: none;">Sub-Type</span> <select class="Off form-control" name="sub[4]" style="display:none;"> <option>All Off-Hand Item Types</option> <option>Mojo</option> <option>Source</option> <option>Quiver</option> <option>Shield</option> </select> </div>

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  • PHP / MySQL - How to retrieve 2 separate sets of objects?

    - by Dan
    Hi, I have a set of models which correspond to tables in my database. I have been retrieving them easily enough, for example. $result = $mysqli->query('SOME SQL'); $post = $result->fetch_object; What would be the best approach for performing a join and also returning the related objects? For example, each post is created by a user, so for each row returned in the joined statement, both a page and user object should be returned. Any advice appreciated. Thanks.

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  • How do I update blackberry UI items from a thread?

    - by Andrei T. Ursan
    public class PlayText extends Thread { private int duration; private String text; private PlayerScreen playerscrn; public PlayText(String text, int duration) { this.duration = duration; this.text = text; this.playerscrn = (PlayerScreen)UiApplication.getUiApplication().getActiveScreen(); } public void run() { synchronized(UiApplication.getEventLock()) { try{ RichTextField text1player = new RichTextField(this.text, Field.NON_FOCUSABLE); playerscrn.add(text1player); playerscrn.invalidate(); Thread.sleep(this.duration); RichTextField text2player = new RichTextField("hahhaha", Field.NON_FOCUSABLE); playerscrn.add(text2player); playerscrn.invalidate(); Thread.sleep(1000); RichTextField text3player = new RichTextField("Done", Field.NON_FOCUSABLE); playerscrn.add(text3player); playerscrn.invalidate(); }catch(Exception e){ System.out.println("I HAVE AN ERROR"); } } } } With the above code I'm trying to create a small text player. Instead to get all the text labels one by one, something like display text1player wait this.duration milliseconds display text2player wait 1000 milliseconds display text3player thread done. The screens waits this.duration + 1000 milliseconds and displays all the labels at once. I tried with a runnable and calling .invokeLater or .invokeAndWait but I still get the same behavior, and even if I get dirty like above using synchronized it still doesn't work. Does anyone know how I can display each label at a time? Thank you!

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  • Drupal - How to update a CCK NodeReference field programmatically?

    - by Leszek Laszka
    I'm trying to create a node (B type) & assign it to a A type node's CCK nodereference field using node_save() method. $node_type_A = node_load($some_nid); $node_type_A->field_type_B_node_ref[]['nid'] = $node_type_B_nid; $node_type_A = node_submit($node_type_A); node_save($node_type_A); As the result, a new B type node will be created, but no reference will be assigned to the A type node. any help would be appreciated.

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  • acts_as_xapian jobs table

    - by Grnbeagle
    Hi, Can someone explain to me the inner workings of acts_as_xapian_jobs table? I ran into an issue with the acts_as_xapian plugin recently, where I kept getting the following error when it creates an object with xapian indexed fields: Mysql::Error: Duplicate entry 'String-2147483647' for key 2: INSERT INTO `acts_as_xapian_jobs` (`action`, `model`, `model_id`) VALUES ('update', 'String', 23730251831560) It turns out the model_id exceeded the max int value of 2147483647. The workaround was to update model_id to use bigint. Why would the model_id be so huge? By looking at content of acts_as_xapian_jobs, it seems it creates a row for every field that is being indexed.. Understanding how a job gets created in the table would help a great deal. Here's a sampling of the table: mysql> select * from acts_as_xapian_jobs limit 5\G *************************** 1. row *************************** id: 19 model: String model_id: 23804037900560 action: update *************************** 2. row *************************** id: 49 model: String model_id: 23804037191200 action: update *************************** 3. row *************************** id: 79 model: String model_id: 23804037932180 action: update *************************** 4. row *************************** id: 109 model: String model_id: 23804037101700 action: update *************************** 5. row *************************** id: 139 model: String model_id: 23804037722160 action: update Thanks in advance, Amie

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  • How to update the filename of a Django's FileField instance ?

    - by pierre-guillaume-degans
    Hello, Here a simple django model: class SomeModel(models.Model): title = models.CharField(max_length=100) video = models.FileField(upload_to='video') I would like to save any instance so that the video's file name would be a valid file name of the title. For example, in the admin interface, I load a new instance with title "Lorem ipsum" and a video called "video.avi". The copy of the file on the server should be "Lorem Ipsum.avi" (or "Lorem_Ipsum.avi"). Thank you :)

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  • Forcing a checkbox bound to a DataSource to update when it has not been viewed yet.

    - by Scott Chamberlain
    Here is a test framework to show what I am doing: create a new project add a tabbed control on tab 1 put a button on tab 2 put a check box paste this code for its code (use default names for controls) public partial class Form1 : Form { private List<bool> boolList = new List<bool>(); BindingSource bs = new BindingSource(); public Form1() { InitializeComponent(); boolList.Add(false); bs.DataSource = boolList; checkBox1.DataBindings.Add("Checked", bs, ""); this.button1.Click += new System.EventHandler(this.button1_Click); this.checkBox1.CheckedChanged += new System.EventHandler(this.checkBox1_CheckedChanged); } bool updating = false; private void button1_Click(object sender, EventArgs e) { updating = true; boolList[0] = true; bs.ResetBindings(false); Application.DoEvents(); updating = false; } private void checkBox1_CheckedChanged(object sender, EventArgs e) { if (!updating) MessageBox.Show("CheckChanged fired outside of updating"); } } The issue is if you run the program and look at tab 2 then press the button on tab 1 the program works as expected, however if you press the button on tab 1 then look at tab 2 the event for the checkbox will not fire untill you look at tab 2. The reason for this is the controll on tab 2 is not in the "created" state, so its binding to change the checkbox from unchecked to checked does not happen until after the control has been "Created". checkbox1.CreateControl() does not do anything because according to MSDN CreateControl does not create a control handle if the control's Visible property is false. You can either call the CreateHandle method or access the Handle property to create the control's handle regardless of the control's visibility, but in this case, no window handles are created for the control's children. I tried getting the value of Handle(there is no public CreateHandle() for CheckBox) but still the same result. Any suggestions other than have the program quickly flash all of my tabs that have data-bound check boxes when it first loads? EDIT-- per Jaxidian's suggestion I created a new class public class newcheckbox : CheckBox { public new void CreateHandle() { base.CreateHandle(); } } I call CreateHandle() right after updating = true same results as before.

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  • Is it OK to open a DB4o file for query, insert, update multiple times?

    - by Khnle
    This is the way I am thinking of using DB4o. When I need to query, I would open the file, read and close: using (IObjectContainer db = Db4oFactory.OpenFile(Db4oFactory.NewConfiguration(), YapFileName)) { try { List<Pilot> pilots = db.Query<Pilot>().ToList<Pilot>(); } finally { try { db.Close(); } catch (Exception) { }; } } At some later time, when I need to insert, then using (IObjectContainer db = Db4oFactory.OpenFile(Db4oFactory.NewConfiguration(), YapFileName)) { try { Pilot pilot1 = new Pilot("Michael Schumacher", 100); db.Store(pilot1); } finally { try { db.Close(); } catch (Exception) { }; } } In this way, I thought I will keep the file more tidy by only having it open when needed, and have it closed most of the time. But I keep getting InvalidCastException Unable to cast object of type 'Db4objects.Db4o.Reflect.Generic.GenericObject' to type 'Pilot' What's the correct way to use DB4o?

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  • How to use a c# datagridview to update a database file just like Access does?

    - by mackeyka
    I have googled everywhere and I am finally giving up and asking here. I am working in Visual Studio 2010 with C#. I have set up a form with a datagridview connected to a MSSQL database and I need to save changes made in the datagridview back to the physical database. I am having some success but I think that I am going about some of it completely wrong because I can not get it to save consistently. What I really want is for the updates to work just like they do when working with Access. When I edit a row in the datagridview and then leave that row, either by selecting another row or by selecting some other control on the form or even by changing to another form or quitting the application the row should be automatically pdated to the physical database. The first part of this question I think is, what is the proper event to use to trigger the save and then second what methods should be used to actually write the data to the database?

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  • Why does this JavaScript not correctly update input values?

    - by dmanexe
    I have two input fields, and without changing their names (i.e., I have to use the name with the brackets), how do I make this javascript code work? <script> function calc_concreteprice(mainform) { var oprice; var ototal; oprice = (eval(mainform.'estimate[concrete][sqft]'.value) * eval(mainform.'estimate[concrete][price]'.value)); ototal = (oprice); mainform.'estimate[concrete][quick_total]'.value = ototal; } </script> Here's the HTML of the input area. <tr> <td>Concrete Base Price</td> <td><input type="text" name="concrete[concrete][price]" value="" class="item_mult" onBlur="calc_concreteprice(document.forms.mainform);" /> per SF <strong>times</strong> <input type="text" name="concrete[concrete][sqft]" value="" class="item_mult" onBlur="calc_concreteprice(document.forms.mainform);" /> SF</td> <td> = <input type="text" name="concrete[concrete][quick_total]" value="" /></td> </tr> I know I can get it working by changing_the_input_name_with_underscores but I need to have the names with the brackets (storing the form contents in an array).

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  • What will the $result be when MySQL returns nothing?

    - by Teddy
    This might seem ridiculously simple, but I've been getting all kinds of error depending on how I handle a query that returns nothing. $query = "SELECT * FROM messages WHERE id > ".$messageId; $result =mysql_query($query); $time = time(); while(time()-$time<60 && $result==false) { $result = mysql_query($query); } if(result != false) //Encode response else //return nothing How do I check whether my mysql_query() returned anything?

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