Search Results

Search found 128652 results on 5147 pages for 'user information list'.

Page 55/5147 | < Previous Page | 51 52 53 54 55 56 57 58 59 60 61 62  | Next Page >

  • print a linear linked list into a table

    - by user1796970
    I am attempting to print some values i have stored into a LLL into a readable table. The data i have stored is the following : DEBBIE STARR F 3 W 1000.00 JOAN JACOBUS F 9 W 925.00 DAVID RENN M 3 H 4.75 ALBERT CAHANA M 3 H 18.75 DOUGLAS SHEER M 5 W 250.00 SHARI BUCHMAN F 9 W 325.00 SARA JONES F 1 H 7.50 RICKY MOFSEN M 6 H 12.50 JEAN BRENNAN F 6 H 5.40 JAMIE MICHAELS F 8 W 150.00 i have stored each firstname, lastname, gender, tenure, payrate, and salary into their own List. And would like to be able to print them out in the same format that they are viewed on the text file i read them in from. i have messed around with a few methods that allow me to traverse and print the Lists, but i end up with ugly output. . . here is my code for the storage of the text file and the format i would like to print out: public class Payroll { private LineWriter lw; private ObjectList output; ListNode input; private ObjectList firstname, lastname, gender, tenure, rate, salary; public Payroll(LineWriter lw) { this.lw = lw; this.firstname = new ObjectList(); this.lastname = new ObjectList(); this.gender = new ObjectList(); this.tenure = new ObjectList(); this.rate = new ObjectList(); this.salary = new ObjectList(); this.output = new ObjectList(); this.input = new ListNode(); } public void readfile() { File file = new File("payfile.txt"); try{ Scanner scanner = new Scanner(file); while(scanner.hasNextLine()) { String line = scanner.nextLine(); Scanner lineScanner = new Scanner(line); lineScanner.useDelimiter("\\s+"); while(lineScanner.hasNext()) { firstname.insert1(lineScanner.next()); lastname.insert1(lineScanner.next()); gender.insert1(lineScanner.next()); tenure.insert1(lineScanner.next()); rate.insert1(lineScanner.next()); salary.insert1(lineScanner.next()); } } }catch(FileNotFoundException e) {e.printStackTrace();} } public void printer(LineWriter lw) { String msg = " FirstName " + " LastName " + " Gender " + " Tenure " + " Pay Rate " + " Salary "; output.insert1(msg); System.out.println(output.getFirst()); System.out.println(" " + firstname.getFirst() + " " + lastname.getFirst() + "\t" + gender.getFirst() + "\t" + tenure.getFirst() + "\t" + rate.getFirst() + "\t" + salary.getFirst()); } }

    Read the article

  • Most Astonishing Violation of the Principle of Least Astonishment

    - by Adam Liss
    The Principle of Least Astonishment suggests that a system should operate as a user would expect it to, as much as possible. In other words, it should never "astonish" the user with unexpected behavior. In your experience as the "astonishee," what types of systems are the worst offenders, and if you were the project manager, how would you correct the problem? Bonus if your answer describes how you'd retrain the developers!

    Read the article

  • WPF, C# - Making Intellisense/Autocomplete list, fastest way to filter list of strings

    - by user559548
    Hello everyone, I'm writing an Intellisense/Autocomplete like the one you find in Visual Studio. It's all fine up until when the list contains probably 2000+ items. I'm using a simple LINQ statement for doing the filtering: var filterCollection = from s in listCollection where s.FilterValue.IndexOf(currentWord, StringComparison.OrdinalIgnoreCase) >= 0 orderby s.FilterValue select s; I then assign this collection to a WPF Listbox's ItemSource, and that's the end of it, works fine. Noting that, the Listbox is also virtualised as well, so there will only be at most 7-8 visual elements in memory and in the visual tree. However the caveat right now is that, when the user types extremely fast in the richtextbox, and on every key up I execute the filtering + binding, there's this semi-race condition, or out of sync filtering, like the first key stroke's filtering could still be doing it's filtering or binding work, while the fourth key stroke is also doing the same. I know I could put in a delay before applying the filter, but I'm trying to achieve a seamless filtering much like the one in Visual Studio. I'm not sure where my problem exactly lies, so I'm also attributing it to IndexOf's string operation, or perhaps my list of string's could be optimised in some kind of index, that could speed up searching. Any suggestions of code samples are much welcomed. Thanks.

    Read the article

  • Double Linked List Insertion Sorting Bug

    - by house
    Hello, I have implemented an insertion sort in a double link list (highest to lowest) from a file of 10,000 ints, and output to file in reverse order. To my knowledge I have implemented such a program, however I noticed in the ouput file, a single number is out of place. Every other number is in correct order. The number out of place is a repeated number, but the other repeats of this number are in correct order. Its just strange how this number is incorrectly placed. Also the unsorted number is only 6 places out of sync. I have looked through my program for days now with no idea where the problem lies, so I turn to you for help. Below is the code in question, (side note: can my question be deleted by myself? rather my colleges dont thieve my code, if not how can it be deleted?) void DLLIntStorage::insertBefore(int inValue, node *nodeB) { node *newNode; newNode = new node(); newNode->prev = nodeB->prev; newNode->next = nodeB; newNode->value = inValue; if(nodeB->prev==NULL) { this->front = newNode; } else { nodeB->prev->next = newNode; } nodeB->prev = newNode; } void DLLIntStorage::insertAfter(int inValue, node *nodeB) { node *newNode; newNode = new node(); newNode->next = nodeB->next; newNode->prev = nodeB; newNode->value = inValue; if(nodeB->next == NULL) { this->back = newNode; } else { nodeB->next->prev = newNode; } nodeB->next = newNode; } void DLLIntStorage::insertFront(int inValue) { node *newNode; if(this->front == NULL) { newNode = new node(); this->front = newNode; this->back = newNode; newNode->prev = NULL; newNode->next = NULL; newNode->value = inValue; } else { insertBefore(inValue, this->front); } } void DLLIntStorage::insertBack(int inValue) { if(this->back == NULL) { insertFront(inValue); } else { insertAfter(inValue, this->back); } } ifstream& operator>> (ifstream &in, DLLIntStorage &obj) { int readInt, counter = 0; while(!in.eof()) { if(counter==dataLength) //stops at 10,000 { break; } in >> readInt; if(obj.front != NULL ) { obj.insertion(readInt); } else { obj.insertBack(readInt); } counter++; } return in; } void DLLIntStorage::insertion(int inValue) { node* temp; temp = this->front; if(temp->value >= inValue) { insertFront(inValue); return; } else { while(temp->next!=NULL && temp!=this->back) { if(temp->value >= inValue) { insertBefore(inValue, temp); return; } temp = temp->next; } } if(temp == this->back) { insertBack(inValue); } } Thankyou for your time.

    Read the article

  • Linked list in C

    - by ScReYm0
    I am still new at lists in C and i got a big problem... First i wanna show you my code for inserting item to the list: void input_books_info(int number_of_books, BOOK *current) { int i; for(i = 0; i < number_of_books; i++) { while(current->next != NULL) current = current->next; current->next = (BOOK *)malloc(sizeof(BOOK)); printf_s("%d book catalog number: ", i + 1); scanf_s("%s", &current->next->catalog_number , 20); printf_s("%d book title: ", i + 1); scanf_s("%s", current->next->title ,80); printf_s("%d book author: ", i + 1); scanf_s("%s", current->next->author ,40); printf_s("%d book publisher: ", i+1); scanf_s("%s", current->next->publisher,80); printf_s("%d book price: ", i + 1); scanf_s("%f", &current->next->price, 5); printf_s("%d book year published: ", i + 1); scanf_s("%d", &current->next->year_published, 5); current->next->next = NULL; printf_s("\n\n"); } } And this is my main function: void main (void) { int number_of_books, t = 1; char book_catalog_number[STRMAX]; char book_title[STRMAX]; char book_author[STRMAX]; char reading_file[STRMAX]; char saving_file[STRMAX]; first = malloc(sizeof(BOOK)); first->next = NULL; /* printf_s("Enter file name: "); gets(saving_file); first->next = book_open(first, saving_file); */ while(t) { char m; printf_s("1. Input \n0. Exit \n\n"); printf_s("Choose operation: "); m = getch(); switch(m) { case '1': printf_s("\ninput number of books: "); scanf_s("%d", &number_of_books); input_books_info(number_of_books, first); printf_s("\n"); break; default: printf_s("\nNo entry found!\n\n\n\n\n"); break; } } } and last maybe here is the problem the printing function: void print_books_info(BOOK *current) { while(current->next != NULL && current != NULL) { printf_s("%s, ", current->next->catalog_number); printf_s("%s, ", current->author); printf_s("%s, ", current->next->title); printf_s("%s, ", current->next->author); printf_s("%s, ", current->next->publisher); printf_s("%.2f, ", current->next->price); printf_s("%d", current->next->year_published); printf_s("\n\n"); current = current->next; } } And my problem is that, when i run the app, program is moving good. But when I start the app, the program is storing only first input of data second and third are lost ... Can you help me to figure out it... ???

    Read the article

  • Unable to add separator in list view

    - by Suru
    This is my code @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.email_list_main); emailResults = new ArrayList<GetEmailFromDatabase>(); //int[] colors = {0,0xFFFF0000,0}; //getListView().setDivider(new GradientDrawable(Orientation.RIGHT_LEFT, colors)); //getListView().setDividerHeight(2); emailListFeedAdapter = new EmailListFeedAdapter(this, R.layout.email_listview_row, emailResults); setListAdapter(this.emailListFeedAdapter); getResults(); if(emailResults != null && emailResults.size() > -1){ emailListFeedAdapter.notifyDataSetChanged(); for(int i=0;i< emailResults.size();i++){ try { Here I getting email Sent date emailListFeedAdapter.add( emailResults.get(i)); datetime_text1 = emailResults.get(i).getDate(); formatter1 = new SimpleDateFormat(); formatter1 = DateFormat.getDateInstance((DateFormat.MEDIUM)); Calendar currentDate1 = Calendar.getInstance(); Item_Date1 = formatter1.parse(datetime_text1); current_Date1 = formatter1.format(currentDate1.getTime()); current_System_Date1 = formatter1.parse(current_Date1); currentDate1.add(Calendar.DATE, -1); yesterdaydate = formatter1.format(currentDate1.getTime()); yeaterday_Date = formatter1.parse(yesterdaydate); currentDate1.add(Calendar.DATE, -2); threeDaysback = formatter1.format(currentDate1.getTime()); Three_Days_Back = formatter1.parse(threeDaysback); Here I am comparing current date with list view item date, and here is my problem, dates are matching but it is not entering in if condition I tried in so many ways but nothing worked the code for separator is bellow. if(Item_Date.compareTo(current_System_Date)==0){ if(index1){ emailListFeedAdapter.addSeparatorItem("SEPARATOR"); //i--; index1=false; } } else if(yeaterday_Date.compareTo(Item_Date1)==0){ if(index2){ emailListFeedAdapter.addSeparatorItem("SEPARATOR"); //i--; index2 = false; } } else if(Item_Date1.compareTo(Three_Days_Back)==0){ if(index3){ emailListFeedAdapter.addSeparatorItem("SEPARATOR"); //i--; index3 = false; } } } catch (ParseException e) { // TODO Auto-generated catch block e.printStackTrace(); } } } } In EmailListFeedAdapter private TreeSet<Integer> mSeparatorsSet = new TreeSet<Integer>(); public void addSeparatorItem(final String item) { //itemss.add(emailResults.get(0)); // save separator position mSeparatorsSet.add(itemss.size() - 1); notifyDataSetChanged(); } @Override public int getItemViewType(int position) { return mSeparatorsSet.contains(position) ? TYPE_SEPARATOR : TYPE_ITEM; } holder = new ViewHolder(); switch (type) { case TYPE_ITEM: emailView= inflater.inflate(R.layout.email_listview_row, null); break; case TYPE_SEPARATOR: emailView= inflater.inflate(R.layout.item2, null); holder.textView = (TextView)emailView.findViewById(R.id.textSeparator); emailView.setTag(holder); holder.textView.setText("SEPARATOR"); break; } Here is ViewHolder class public static class ViewHolder { public TextView textView; } if anybody knows then please tell me where I am doing wrong. Thanx

    Read the article

  • Access User Meta Data on User Registration in Wordpress

    - by Shadi Almosri
    Hiya, I am attempting to carry out a few functions when a user registers on a wordpress site. I have created a module for this which carries out the following function: add_action( 'user_register', 'tml_new_user_registered' ); function tml_new_user_registered( $user_id ) { //wp_set_auth_cookie( $user_id, false, is_ssl() ); //wp_redirect( admin_url( 'profile.php' ) ); $user_info = get_userdata($user_id); $subscription_value = get_user_meta( $user_id, "subscribe_to_newsletter", TRUE); if($subscription_value == "Yes") { //include("Subscriber.Add.php"); } echo "<pre>: "; print_r($user_info); print_r($subscription_value); echo "</pre>"; exit; } But it seems that i am not able to access any user meta data as at the end of this stage none of it is stored. Any ideas how i execute a function once Wordpress has completed the whole registration process of adding meta data into the relevant tables too? I attempted to use this: add_filter('user_register ','tml_new_user_registered',99); But with no luck unfortunately. Thanks in advance!

    Read the article

  • Django: getting the list of related records for a list of objects

    - by Silver Light
    Hello! I have two models related one-to many: class Person(models.Model): name = models.CharField(max_length=255); surname = models.CharField(max_length=255); age = models.IntegerField(); class Dog(models.Model): name = models.CharField(max_length=255); owner = models.ForeignKey('Person'); I want to output a list of persons below each person a list of dogs he has. Here's how I can do it: in view: persons = Person.objects.all()[0:100]; in template: {% for p in persons %} {{ p.name }} has dogs:<br /> {% for d in persons.dog_set.all %} - {{ d.name }}<br /> {% endfor %} {% endfor %} But if I do it like that, Django will execute 101 SQL queries which is very inefficient. I tried to make a custom manager, which will get all the persons, then all the dogs and links them in python, but then I can't use paginator (my another question: http://stackoverflow.com/questions/2532475/django-paginator-raw-sql-query ) and it looks quite ugly. Is there a more graceful way doing this?

    Read the article

  • AJAX TabContainer containing user controls

    - by Ali
    Hi all, Wondering if someone here can help. I have an AJAX tabcontainer which has a number of tabs and each tab contains a user control. When I add a new item from one of the tabs, it is not reflected in the user control in another tab unless a postback occurs. (e.g. the first tab has a listview where I add a new record and the second has a simple form which contains a drop-down which I expect to contain value added from first tab). How can I make the tabcontainer to refresh its tabs from a usercontrol? Any help will be most appreciated. Thanks, Ali

    Read the article

  • SQL Server 2005/2008: Identify current user

    - by Torben H.
    Hello I have a web application, which is using a SQL Server 2005 database. My problem is, that the application has no role management. So the application always accesses the database with one default user. But now I have to save and access a value only for the current user. Is there any way to do this? Maybe something like a session on the web server? The best way would be, if there is any possibility to access the current session id of the web server from T-SQL. Do anyone understand my problem? :) Torben

    Read the article

  • how to display a dialog if user can't download file

    - by tom smith
    hi. dealing with php/html/javascript. i'm trying to figure out a good/best approach to allowing a user to download a file. i can have the traditional href link, that interfaces with the back end php app to download the file. however, i want to have the app display some sort of dialog/alert if the user isn't able (basedon acl/permissions) to download the file... does this have to ba an ajax thing, as i don't want to do a page refresh... thoughts/comments/pointers to code samples are appreciated. thanks. -tom

    Read the article

  • What is the iPad user agent?

    - by Yoric
    Now that the iPad craze is officially open, it's time to think websites also for the iPad. From what I gather, the iPad is using iPhone OS, but with a different screen resolution from the iPhone/iPod touch. So suddenly, the assumption that iPhone OS = iPhone screen resolution becomes false. Sounds like many sites may have to revise their user-agent - css mapping. So, can anyone with access to the iPad or the iPad SDK give us the user-agent string? Thanks in advance.

    Read the article

  • Trying to get these list items to display inline

    - by Joel
    I have several unordered lists that I want to display like this: <ul> <li><img></li> <li><p></li> //inline </ul> //linebreak <ul> <li><img></li> <li><p></li> //inline </ul> ...etc I'm not able to get the li items to be inline with eachother. They are stacking vertically. I have stripped away most styling but still can't figure out what I'm doing wrong: html: <ul class="instrument"> <li class="imagebox"><img src="/images/matepe.jpg" width="247" height="228" alt="Matepe" /></li> <li class="textbox"><p>The matepe is a 24 key instrument that is played by the Kore-Kore people in North-Eastern Zimbabwe and Mozambique. It utilizes four fingers-each playing an individual melody. These melodies also interwieve to create resultant melodies that can be manipulated thru accenting different fingers. The matepe is used in Rattletree as the bridge from the physical world to the spirit world. The matepe is used in the Kore-Kore culture to summon the Mhondoro spirits which are thought to be able to communicate directly with Mwari (God) without the need of an intermediary.</p></li> </ul> <ul class="instrument"> <li class="imagebox"><img src="/images/soprano_little.jpg" border="0" width="247" height="170" alt="Soprano" /></li> <li class="textbox"><p>The highest voice of the Rattletree Marimba orchestra is the Soprano marimba. The soprano is used to whip up the energy on the dancefloor and help people reach ecstatic state with it's high and clear singing voice. The range of these sopranos goes much lower than 'typical' Zimbabwean style sopranos. The sopranos play the range of the right hand of the matepe and go two notes higher and five notes lower. Rattletree uses two sopranos.</p></li> </ul> <ul class="instrument"> <li class="imagebox"><img src="/images/bari_little.jpg" border="0" width="247" height="170" alt="Baritone" /></li> <li class="textbox"><p>The Baritone is the next lower voice in the orchestra. The bari is where the funk is. Generally bubbling over the Bass line, the baritone creates the syncopations and polyrhythms that messes with the 'minds' of the dancers and helps seperate the listener from the physical realm of thought. The range of the baritone covers the full range of the left hand side of the matepe.</p></li> </ul> <ul class="instrument"> <li class="imagebox"><img src="/images/darren_littlebass.jpg" border="0" width="247" height="195" alt="Bass"/><strong>Bass Marimba</strong></li> <li class="textbox"><p>The towering Bass Marimba is the foundation of the Rattletree Marimba sound. Putting out frequencies as low as 22hZ, the bass creates the drive that gets the dancefloor moving. It is 5.5' tall, 9' long, and 4' deep. It is played by standing on a platform and struck with mallets that have lacross-ball size heads (they are actually made with rubber dog balls). The Bass marimba's range covers the lowest five notes of the matepe and goes another five notes lower.</p></li> </ul> <ul class="instrument"> <li class="imagebox"><img src="/images/wayne_little.jpg" border="0" width="247" height="177" alt="Drums"/><strong>Drumset</strong></li> <li class="textbox"><p>All the intricate polyrhythms are held together tastefully with the drumset. The drums provides the consistancy and grounding that the dancers need to keep going all night. While the steady kick and high-hat provide that grounding function, the toms and snare and allowed to be another voice in the poylrhythmic texture-helping the dancers abandon the concept of a "one" within this cyclical music.</p></li> </ul> css: ul.instrument { text-align:left; display:inline; } ul.instrument li { list-style-type: none; } li.imagebox { } li.textbox { } li.textbox p{ width: 247px; }

    Read the article

  • Programming user interface advice?

    - by onurozcelik
    Hi, In my project I going to generate a user interface through programming. Scalability of this UI is very important requirement. So far I am using two dimensional graphics for generating the UI. I think there may be different solutions but for the moment I know only two. First one is supplying X,Y coordinates of each two dimensional graphic on my UI.(I do not prefer this solution because I do not want to calculate X,Y coordinates of each graphic. For the moment I don't have a logic for doing this easily) Second one(which is currently I am using now) is using layouts which organizes its contents according to size of item. In this solution I don't have to calculate X,Y coordinates of each item.(Layout is doing this for me) But this approach may have its own pitfalls. I am very new to user interface programming. Can you give me advice about this issue?

    Read the article

  • Wordpress: Create a customized role / user

    - by Mestika
    Hi, I’m farely new to Wordpress but are working on putting a page together which has a very simple purpose. I’m creating it for a customer with little or none IT experience so I want to create a user he can use to login and edit his pages – and nothing more. No settings, no comments, no posts, no links, no nothing, just create, delete and edit pages and maybe edit his own profile or at least his E-mail and password. I can see that wordpress has some predefined roles for users but none of them completely does what I want and they either has to little or to many rights. I’ve been looking at the wordpress page http://codex.wordpress.org/Roles_and_Capabilities but can’t seem to get a clear answer. Is it in any way possible for me to create my own user role (e.g. customer) where I can set the rights I want for him? Thanks Sincerely Mestika

    Read the article

  • User friendly urls in joomla1.5

    - by Aruna
    Hi , I am working Joomla 1.5 . I am unaware of how to set user-friendly Urls to the site in Joomla1.5. Give suggestions for keeping User-Friendly urls ... I have changed the configuration for SEO as yes to apache mod_rewrite and Search engine friendly Urls .It changes the url as http://localhost/joomla/Joomla_1.5.7/publicationsform but it shows me a 404 error and it works only when i put http://localhost/joomla/Joomla_1.5.7/index.php/publicationsform how to resolve this . Also even when i put http://localhost/joomla/Joomla_1.5.7/index.php/publicationsform my css is not getting added..

    Read the article

  • How to start wampp server automatically for standard user?

    - by Ashvin
    Is there a way to use WAMP in windows professional-standard user mode. I have to use wamp and i am given only a standard user account. My boss installed wamp for me through his admin account, but i am unable to open it via my user account. I have to call him everytime i have to open wamp and its being a real hazzle to me ? Is there a way my standard user account be given privileges to use wamp and other datababse related things?

    Read the article

  • How to let an average user design a boolean expression graphically

    - by Svein Bringsli
    In our application there's a list of customers, and a list of keywords (among other things). Each customer can have a number of keywords, but it's not mandatory. So for instance, one customer can have the keywords "retail" and "chain", one can have only "contractor" and a third can have none at all. I want to let the user make a selection of customers based on these keywords, but not having to write (retail AND chain) or contractor and not wholesale I would like to make it as user-friendly as possible, and ideally with only "simple" controls, like checkboxes, comboboxes etc. Does anyone have any suggestions on how to design this? Or maybe some examples of applications where there are similar functionality?

    Read the article

< Previous Page | 51 52 53 54 55 56 57 58 59 60 61 62  | Next Page >