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  • How to order a TimeZone list in .NET?

    - by reallyJim
    I have an ASP.NET web application that requires users to select their appropriate time zone so that it can correctly show local times for events. In creating a simple approach for selecting the time zone, I started by just using the values from TimeZoneInfo.GetSystemTimeZones(), and showing that list. The only problem with this is that since our application is primarily targeted at the United States, I'd like to show those entries first, basically starting with Eastern Time and working backwards (West) until I reach Atlantic time. What's a good approach to do this in code?

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  • How to sort objects in a many-to-many relationship in ruby on rails?

    - by Kenji Kina
    I've been trying to deal with this problem for a couple of hours now and haven't been able to come up with a clean solution. It seems I'm not too good with rails... Anyway, I have the following: In code: class Article < ActiveRecord::Base has_many :line_aspects, :dependent => :destroy has_many :aspects, :through => :line_aspects #plus a name field end class LineAspect < ActiveRecord::Base belongs_to :article belongs_to :aspect end class Aspect < ActiveRecord::Base belongs_to :data_type has_many :line_aspects has_many :articles, :through => :line_aspects end Now, what I would like to do, is to sort these in two steps. First list of Articles by their Articles.name, and then inside sort them by Aspect.name (note, not the middleman). For instance, alphabetically (sorry if the notation is not correct): [{ article => 'Apple', line_aspects => [ {:value => 'red'}, #corresponding to the Attribute with :name => 'color' {:value => 'small'} #corresponding to the Attribute with :name => 'shape' ] },{ article => 'Watermelon', line_aspects => [ {:value => 'green'}, #corresponding to the Attribute with :name => 'color' {:value => 'big'} #corresponding to the Attribute with :name => 'shape' ] }] Again, note that these are ordered by the aspect name (color before shape) instead of the specific values of each line (red before green). (NOTE: My intention is to displaye these in a table in the view) I have not found a good way to do this in rails yet (without resorting to N queries). Can anyone tell me a good way to do it?

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  • Riddle: Spot the serious bug in this bubble sort implementation

    - by ripper234
    (No, this isn't a homework assignment, I just found the bug and thought it might be useful to share it here) import java.util.List; public class BubbleSorter { public <T extends Comparable<T>> void sort(List<T> list) { while (true) { boolean didWork = false; for (int i = 0; i < list.size() - 1; ++i) { if (list.get(i).compareTo(list.get(i + 1)) > 0) { swap(list, i, i + 1); didWork = true; break; } } if (!didWork) return; } } private static <T> void swap(List<T> list, int i, int j) { T tmp = list.get(i); list.set(i, list.get(j)); list.set(j, tmp); } }

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  • string categorization strategies

    - by Andrew Heath
    I'm the one-man dev team on a fledgling military history website. One aspect of the site is a catalog of ~1,200 individual battles, including the nations & formations (regiments, divisions, etc) which took part. The formation information (as well as the other battle info) was manually imported from a series of books by a 10-man volunteer team. The formations were listed in groups with varying formatting and abbreviation patterns. At the time I set up the data collection forms I couldn't think of a good way to process that data... and elected to store it all as strings in the MySQL database and sort it out later. Well, "later" - as it tends to happen - has arrived. :-) Each battle has 2+ records in the database - one for each nation that participated. Each record has a formations text string listing the formations present as the volunteer chose to add them. Some real examples: 39th Grenadier Rgmt, 26th Volksgrenadier Division 2nd Luftwaffe Field Division, 246th Infantry Division 247th Rifle Division, 255th Tank Brigade 2nd Luftwaffe Field Division, SS Cavalry Division 28th Tank Brigade, 158th Rifle Division, 135th Rifle Division, 81st Tank Brigade, 242nd Tank Brigade 78th Infantry Division 3rd Kure Special Naval Landing Force, Tulagi Seaplane Base personnel 1st Battalion 505th Infantry Regiment The ultimate goal is for each individual force to have an ID, so that its participation can be traced throughout the battle database. Formation hierarchy, such as the final item above 1st Battalion (of the) 505th Infantry Regiment also needs to be preserved. In that case, 1st Battalion and 505th Infantry Regiment would be split, but 1st Battalion would be flagged as belonging to the 505th. In database terms, I think I want to pull the formation field out of the current battle info table and create three new tables: FORMATION [id] [name] FORMATION_HIERARCHY [id] [parent] [child] FORMATION_BATTLE [f_id] [battle_id] It's simple to explain, but complicated to enact. What I'm looking for from the SO community is just some tips on how best to tackle this problem. Ideally there's some sort of method to solving this that I'm not aware of. However, as a last resort, I could always code a classification framework and call my volunteers back to sort through 2,500+ records...

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  • Mysql: i need to get the offset of a item in a query.

    - by user305270
    Mysql: i need to get the offset of a item in a query. I have a image gallery: this show 6 image per stack, so when i request image 22 it shows images from 18 to 24. It should first get the offset of the image 22, then get the images from 18 to 24. Another example: i request the image number 62(and offset 62), it will select images with offset from 60 to 66. Is possible with a single query? Thanks ;)

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  • Inserting Records in Ascending Order function- C homework assignment

    - by Aaron McRuer
    Good day, Stack Overflow. I have a homework assignment that I'm working on this weekend that I'm having a bit of a problem with. We have a struct "Record" (which contains information about cars for a dealership) that gets placed in a particular spot in a linked list according to 1) its make and 2) according to its model year. This is done when initially building the list, when a "int insertRecordInAscendingOrder" function is called in Main. In "insertRecordInAscendingOrder", a third function, "createRecord" is called, where the linked list is created. The function then goes to the function "compareCars" to determine what elements get put where. Depending on the value returned by this function, insertRecordInAscendingOrder then places the record where it belongs. The list is then printed out. There's more to the assignment, but I'll cross that bridge when I come to it. Ideally, and for the assignment to be considered correct, the linked list must be ordered as: Chevrolet 2012 25 Chevrolet 2013 10 Ford 2010 5 Ford 2011 3 Ford 2012 15 Honda 2011 9 Honda 2012 3 Honda 2013 12 Toyota 2009 2 Toyota 2011 7 Toyota 2013 20 from the a text file that has the data ordered the following way: Ford 2012 15 Ford 2011 3 Ford 2010 5 Toyota 2011 7 Toyota 2012 20 Toyota 2009 2 Honda 2011 9 Honda 2012 3 Honda 2013 12 Chevrolet 2013 10 Chevrolet 2012 25 Notice that the alphabetical order of the "make" field takes precedence, then, the model year is arranged from oldest to newest. However, the program produces this as the final list: Chevrolet 2012 25 Chevrolet 2013 10 Honda 2011 9 Honda 2012 3 Honda 2013 12 Toyota 2009 2 Toyota 2011 7 Toyota 2012 20 Ford 2010 5 Ford 2011 3 Ford 2012 15 I sat down with a grad student and tried to work out all of this yesterday, but we just couldn't figure out why it was kicking the Ford nodes down to the end of the list. Here's the code. As you'll notice, I included a printList call at each instance of the insertion of a node. This way, you can see just what is happening when the nodes are being put in "order". It is in ANSI C99. All function calls must be made as they are specified, so unfortunately, there's no real way of getting around this problem by creating a more efficient algorithm. #include <stdio.h> #include <stdlib.h> #include <string.h> #define MAX_LINE 50 #define MAX_MAKE 20 typedef struct record { char *make; int year; int stock; struct record *next; } Record; int compareCars(Record *car1, Record *car2); void printList(Record *head); Record* createRecord(char *make, int year, int stock); int insertRecordInAscendingOrder(Record **head, char *make, int year, int stock); int main(int argc, char **argv) { FILE *inFile = NULL; char line[MAX_LINE + 1]; char *make, *yearStr, *stockStr; int year, stock, len; Record* headRecord = NULL; /*Input and file diagnostics*/ if (argc!=2) { printf ("Filename not provided.\n"); return 1; } if((inFile=fopen(argv[1], "r"))==NULL) { printf("Can't open the file\n"); return 2; } /*obtain values for linked list*/ while (fgets(line, MAX_LINE, inFile)) { make = strtok(line, " "); yearStr = strtok(NULL, " "); stockStr = strtok(NULL, " "); year = atoi(yearStr); stock = atoi(stockStr); insertRecordInAscendingOrder(&headRecord,make, year, stock); } printf("The original list in ascending order: \n"); printList(headRecord); } /*use strcmp to compare two makes*/ int compareCars(Record *car1, Record *car2) { int compStrResult; compStrResult = strcmp(car1->make, car2->make); int compYearResult = 0; if(car1->year > car2->year) { compYearResult = 1; } else if(car1->year == car2->year) { compYearResult = 0; } else { compYearResult = -1; } if(compStrResult == 0 ) { if(compYearResult == 1) { return 1; } else if(compYearResult == -1) { return -1; } else { return compStrResult; } } else if(compStrResult == 1) { return 1; } else { return -1; } } int insertRecordInAscendingOrder(Record **head, char *make, int year, int stock) { Record *previous = *head; Record *newRecord = createRecord(make, year, stock); Record *current = *head; int compResult; if(*head == NULL) { *head = newRecord; printf("Head is null, list was empty\n"); printList(*head); return 1; } else if ( compareCars(newRecord, *head)==-1) { *head = newRecord; (*head)->next = current; printf("New record was less than the head, replacing\n"); printList(*head); return 1; } else { printf("standard case, searching and inserting\n"); previous = *head; while ( current != NULL &&(compareCars(newRecord, current)==1)) { printList(*head); previous = current; current = current->next; } printList(*head); previous->next = newRecord; previous->next->next = current; } return 1; } /*creates records from info passed in from main via insertRecordInAscendingOrder.*/ Record* createRecord(char *make, int year, int stock) { printf("CreateRecord\n"); Record *theRecord; int len; if(!make) { return NULL; } theRecord = malloc(sizeof(Record)); if(!theRecord) { printf("Unable to allocate memory for the structure.\n"); return NULL; } theRecord->year = year; theRecord->stock = stock; len = strlen(make); theRecord->make = malloc(len + 1); strncpy(theRecord->make, make, len); theRecord->make[len] = '\0'; theRecord->next=NULL; return theRecord; } /*prints list. lists print.*/ void printList(Record *head) { int i; int j = 50; Record *aRecord; aRecord = head; for(i = 0; i < j; i++) { printf("-"); } printf("\n"); printf("%20s%20s%10s\n", "Make", "Year", "Stock"); for(i = 0; i < j; i++) { printf("-"); } printf("\n"); while(aRecord != NULL) { printf("%20s%20d%10d\n", aRecord->make, aRecord->year, aRecord->stock); aRecord = aRecord->next; } printf("\n"); } The text file you'll need for a command line argument can be saved under any name you like; here are the contents you'll need: Ford 2012 15 Ford 2011 3 Ford 2010 5 Toyota 2011 7 Toyota 2012 20 Toyota 2009 2 Honda 2011 9 Honda 2012 3 Honda 2013 12 Chevrolet 2013 10 Chevrolet 2012 25 Thanks in advance for your help. I shall continue to plow away at it myself.

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  • Efficient method to calculate the rank vector of a list in Python

    - by Tamás
    I'm looking for an efficient way to calculate the rank vector of a list in Python, similar to R's rank function. In a simple list with no ties between the elements, element i of the rank vector of a list l should be x if and only if l[i] is the x-th element in the sorted list. This is simple so far, the following code snippet does the trick: def rank_simple(vector): return [rank for rank in sorted(range(n), key=vector.__getitem__)] Things get complicated, however, if the original list has ties (i.e. multiple elements with the same value). In that case, all the elements having the same value should have the same rank, which is the average of their ranks obtained using the naive method above. So, for instance, if I have [1, 2, 3, 3, 3, 4, 5], the naive ranking gives me [0, 1, 2, 3, 4, 5, 6], but what I would like to have is [0, 1, 3, 3, 3, 5, 6]. Which one would be the most efficient way to do this in Python? Footnote: I don't know if NumPy already has a method to achieve this or not; if it does, please let me know, but I would be interested in a pure Python solution anyway as I'm developing a tool which should work without NumPy as well.

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  • Why wont this perl array sort work?

    - by Luke
    Why wont the array sort? CODE my @data = ('PJ RER Apts to Share|PROVIDENCE', 'PJ RER Apts to Share|JOHNSTON', 'PJ RER Apts to Share|JOHNSTON', 'PJ RER Apts to Share|JOHNSTON', 'PJ RER Condo|WEST WARWICK', 'PJ RER Condo|WARWICK'); foreach my $line (@data) { $count = @data; chomp($line); @fields = split(/\|/,$line); if ($fields[0] eq "PJ RER Apts to Share"){ @city = "\u\L$fields[1]"; @city_sort = sort (@city); print "@city_sort","\n"; } } print "$count","\n"; OUTPUT Providence Johnston Johnston Johnston 6

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  • How to sort an array of structs in ColdFusion

    - by Kip
    I have an array of structs in ColdFusion. I'd like to sort this array based on one of the attributes in the structs. How can I achieve this? I've found the StructSort function, but it takes a structure and I have an array. If this is not possible purely in ColdFusion, is it possible in Java somehow (maybe using Arrays.sort(Object[], Comparator))?

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  • maintaing a sorted list that is bigger than memory

    - by tcurdt
    I have a list of tuples. [ "Bob": 3, "Alice: 2, "Jane": 1, ] When incrementing the counts "Alice" += 2 the order should be maintained: [ "Alice: 4, "Bob": 3, "Jane": 1, ] When all is in memory there rather simple ways (some more or some less) to efficiently implement this. (using an index, insert-sort etc) The question though is: What's the most promising approach when the list does not fit into memory. Bonus question: What if not even the index fits into memory? How would you approach this?

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  • How should I do custom sort in Python 3?

    - by S.Mark
    In Python 2.x, I could pass custom function to sorted and .sort functions >>> x=['kar','htar','har','ar'] >>> >>> sorted(x) ['ar', 'har', 'htar', 'kar'] >>> >>> sorted(x,cmp=customsort) ['kar', 'htar', 'har', 'ar'] Because, in My language, consonents are comes with this order "k","kh",....,"ht",..."h",...,"a" But In Python 3.x, looks like I could not pass cmp keyword >>> sorted(x,cmp=customsort) Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: 'cmp' is an invalid keyword argument for this function Is there any alternatives or should I write my own sorted function too?

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  • Wordpress order/sort problem

    - by Spencer
    Hi, The Problem: I would like to sort my posts based on custom fields, when the user clicks on a link. I don't know if there is a parameter that can be passed via url to reorder posts. Comparison: I would like it to work similar to how you can sort songs in iTunes. The user simply clicks the "Artist" button and the songs are reorder alphabetically by artist's name. Example: The custom field could be the location where I was when I wrote the post. "Location = home" or "Location = office" etc. When the user click a links the page is reload with the posts reordered. Posts from home before ones from the office. Thanks for the help.

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  • Problem with jQuery plugin TinySort

    - by Volmar
    I'm trying to sort a list with the help of jQuery and the TinySort-plugin, and it works good but one thing is not working as i want. My Code is: <!doctype html> <html> <head> <meta charset="UTF-8" /> <title>TinySort problem</title> <script type="text/javascript" src="http://so.volmar.se/www/js/jquery.js"></script> <script type="text/javascript" src="http://so.volmar.se/www/js/jquery.tinysort.min.js"></script> <script type="text/javascript"> function pktsort(way){ if($("div#paket>ul>li.sortdiv>a#s_abc").text() == "A-S"){ $("div#paket>ul>li.sortdiv>a#s_abc").text("S-A"); $("div#paket ul li.sortable").tsort("",{place:"org",returns:true,order:"desc"}); }else{ $("div#paket>ul>li.sortdiv>a#s_abc").text("A-S"); $("div#paket ul li.sortable").tsort("",{place:"org",returns:true,order:"asc"}); } } </script> </head> <body> <div id="paket" title="Paket"> <ul class="rounded"> <li class="sortdiv">Sort: <a href="#" onclick="pktsort();" class="active_sort" id="s_abc">A-S</a></li> <li class="sortable">Almost Famous</li> <li class="sortable">Children of Men</li> <li class="sortable">Coeurs</li> <li class="sortable">Colossal Youth</li> <li class="sortable">Demonlover</li> <li class="sortable">Femme Fatale</li> <li class="sortable">I'm Not There</li> <li class="sortable">In the City of Sylvia</li> <li class="sortable">Into the Wild</li> <li class="sortable">Je rentre à la maison</li> <li class="sortable">King Kong</li> <li class="sortable">Little Miss Sunshine</li> <li class="sortable">Man on Wire</li> <li class="sortable">Milk</li> <li class="sortable">Monsters Inc.</li> <li class="sortable">My Winnipeg</li> <li class="sortable">Ne touchez pas la hache</li> <li class="sortable">Nói albinói</li> <li class="sortable">Regular Lovers</li> <li class="sortable">Shaun of the Dead</li> <li class="sortable">Silent Light</li> <li class="addmore"><b>This text is not supposed to move</b></li> </ul> </div> </body> </html> you can try it out at: http://www.volmar.se/list-prob.html MY PROBLEM IS: I don't want the <li class="addmore"> to move above all the <li class="sortable">-elements when i press the sort-link. i wan't it to always be in the bottom. you can find documentation of the TinySort plugin here. i've tried loads of combinations with place and returns propertys but i just can't get it right.

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  • How to sort a date array in PHP

    - by Click Upvote
    I have an array in this format: Array ( [0] => Array ( [28th February, 2009] => 'bla' ) [1] => Array ( [19th March, 2009] => 'bla' ) [2] => Array ( [5th April, 2009] => 'bla' ) [3] => Array ( [19th April, 2009] => 'bla' ) [4] => Array ( [2nd May, 2009] => 'bla' ) ) I want to sort them out in the ascending order of the dates (based on the month, day, and year). What's the best way to do that? Originally the emails are being fetched in the MySQL date format, so its possible for me to get the array in this state: Array [ ['2008-02-28']='some text', ['2008-03-06']='some text' ] Perhaps when its in this format, I can loop through them, remove all the '-' (hyphen) marks so they are left as integars, sort them using array_sort() and loop through them yet again to sort them? Would prefer if there was another way as I'd be doing 3 loops with this per user. Thanks. Edit: I could also do this: $array[$index]=array('human'=>'28 Feb, 2009', 'db'=>'20080228', 'description'=>'Some text here'); But using this, would there be any way to sort the array based on the 'db' element alone? Edit 2: Updated initial var_dump

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  • How can I sort a Perl array of array of hashes?

    - by srk
    @aoaoh; $aoaoh[0][0]{21} = 31; $aoaoh[0][0]{22} = 31; $aoaoh[0][0]{23} = 17; for $k (0 .. $#aoaoh) { for $i(0.. $#aoaoh) { for $val (keys %{$aoaoh[$i][$k]}) { print "$val=$aoaoh[$i][$k]{$val}\n"; } } } The output is: 22=31 21=31 23=17 but i expect it to be 21=31 22=31 23=17 Please tell me where is this wrong. Also how do I sort the values so that i get the output as 23=17 22=31 21=31 (if 2 keys have same value then key with higher value come first)

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  • sort outer array based on values in inner array, javascript

    - by ptrn
    I have an array with arrays in it, where I want to sort the outer arrays based on values in a specific column in the inner. I bet that sounded more than a bit confusing, so I'll skip straight to an example. Initial data: var data = [ [ "row_1-col1", "2-row_1-col2", "c-row_1-coln" ], [ "row_2-col1", "1-row_2-col2", "b-row_2-coln" ], [ "row_m-col1", "3-row_m-col2", "a-row_m-coln" ] ]; Sort data, based on column with index 1 data.sortFuncOfSomeKind(1); where the object then would look like this; var data = [ [ "row_2-col1", "1-row_2-col2", "b-row_2-coln" ], [ "row_1-col1", "2-row_1-col2", "c-row_1-coln" ], [ "row_m-col1", "3-row_m-col2", "a-row_m-coln" ] ]; Sort data, based on column with index 2 data.sortFuncOfSomeKind(2); where the object then would look like this; var data = [ [ "row_m-col1", "3-row_m-col2", "a-row_m-coln" ], [ "row_2-col1", "1-row_2-col2", "b-row_2-coln" ], [ "row_1-col1", "2-row_1-col2", "c-row_1-coln" ] ]; The big Q Is there an existing solution to this that you know of, or would I have to write one myself? If so, which would be the easiest sort algorithm to use? QuickSort? _L

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  • Sort specific items of an array first

    - by Matt Huggins
    I have a ruby array that looks something like this: my_array = ['mushroom', 'beef', 'fish', 'chicken', 'tofu', 'lamb'] I want to sort the array so that 'chicken' and 'beef' are the first two items, then the remaining items are sorted alphabetically. How would I go about doing this?

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  • Batch INSYNC help needed...

    - by Raja Reddy
    I have a INSYNC batch to 'extract' certain conditioned data output. For instance, below insync code extracts the data if 44 pos has a value of '25'. Question here is, I wanna get the output in a sorted manner based on a particular field. Can we incorporate the SORT criteria below. Suggestions are really appreciated. FUNCTION=EXTRACT INDD=#INDD OUTDD=#OUTDD RDW=OFF LINESPERPAGE=080 CASE SEARCHDATA=(00044,002,EQ,C'25') ENDCASE PS: We can achieve the same by means of SORT utility through 'SORT FIELDS' parameter.

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  • Sort a list of tuples without case sensitivity

    - by dound
    How can I efficiently and easily sort a list of tuples without being sensitive to case? For example this: [('a', 'c'), ('A', 'b'), ('a', 'a'), ('a', 5)] Should look like this once sorted: [('a', 5), ('a', 'a'), ('A', 'b'), ('a', 'c')] The regular lexicographic sort will put 'A' before 'a' and yield this: [('A', 'b'), ('a', 5), ('a', 'a'), ('a', 'c')]

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