Search Results

Search found 6841 results on 274 pages for 'outer join'.

Page 56/274 | < Previous Page | 52 53 54 55 56 57 58 59 60 61 62 63  | Next Page >

  • Help need to with MySQL query to join data spanning multiple tables and use data as column names

    - by gurun8
    I need a little help putting together a SQL query that will give me the following resultsets: and The data model looks like this: The tricky part for me is that the columns to the right of the "Product" in the resultset aren't really columns in the database but rather key/value pairs spanned across the data model. Table data is as follows: My apologies in advance for the image heavy question and the image quality. This just seemed like the easiest way to convey the information. It'll probably take someone less time to write the query statement to achieve the results than it did for me to assemble this question. By the way, the "product_option" table image is truncated but it illustrated the general idea of the data structure. The MySQL server version is 5.1.45.

    Read the article

  • Help needed with MySQL query to join data spanning multiple tables with data used as column names

    - by gurun8
    I need a little help putting together a SQL query that will give me the following resultsets: and The data model looks like this: The tricky part for me is that the columns to the right of the "Product" in the resultset aren't really columns in the database but rather key/value pairs spanned across the data model. Table data is as follows: My apologies in advance for the image heavy question and the image quality. This just seemed like the easiest way to convey the information. It'll probably take someone less time to write the query statement to achieve the results than it did for me to assemble this question. By the way, the "product_option" table image is truncated but it illustrated the general idea of the data structure. The MySQL server version is 5.1.45.

    Read the article

  • CSS - postion: absolute; - auto height

    - by superUntitled
    I am having a problem with some div's The outer div has a min-height, but the inner divs are all varying heights. Because the inner divs are absolute positioned, they do not affect the outer divs height. Is there a way to make these inner divs affect the height of the outer div? The reason I am styling these divs with position:absolute is so that they all start at the top of the container div.

    Read the article

  • C++ non-member functions for nested template classes

    - by beldaz
    I have been writing several class templates that contain nested iterator classes, for which an equality comparison is required. As I believe is fairly typical, the comparison is performed with a non-member (and non-friend) operator== function. In doing so, my compiler (I'm using Mingw32 GCC 4.4 with flags -O3 -g -Wall) fails to find the function and I have run out of possible reasons. In the rather large block of code below there are three classes: a Base class, a Composed class that holds a Base object, and a Nested class identical to the Composed class except that it is nested within an Outer class. Non-member operator== functions are supplied for each. These classes are in templated and untemplated forms (in their own respective namespaces), with the latter equivalent to the former specialised for unsigned integers. In main, two identical objects for each class are compared. For the untemplated case there is no problem, but for the templated case the compiler fails to find operator==. What's going on? #include <iostream> namespace templated { template<typename T> class Base { T t_; public: explicit Base(const T& t) : t_(t) {} bool equal(const Base& x) const { return x.t_==t_; } }; template<typename T> bool operator==(const Base<T> &x, const Base<T> &y) { return x.equal(y); } template<typename T> class Composed { typedef Base<T> Base_; Base_ base_; public: explicit Composed(const T& t) : base_(t) {} bool equal(const Composed& x) const {return x.base_==base_;} }; template<typename T> bool operator==(const Composed<T> &x, const Composed<T> &y) { return x.equal(y); } template<typename T> class Outer { public: class Nested { typedef Base<T> Base_; Base_ base_; public: explicit Nested(const T& t) : base_(t) {} bool equal(const Nested& x) const {return x.base_==base_;} }; }; template<typename T> bool operator==(const typename Outer<T>::Nested &x, const typename Outer<T>::Nested &y) { return x.equal(y); } } // namespace templated namespace untemplated { class Base { unsigned int t_; public: explicit Base(const unsigned int& t) : t_(t) {} bool equal(const Base& x) const { return x.t_==t_; } }; bool operator==(const Base &x, const Base &y) { return x.equal(y); } class Composed { typedef Base Base_; Base_ base_; public: explicit Composed(const unsigned int& t) : base_(t) {} bool equal(const Composed& x) const {return x.base_==base_;} }; bool operator==(const Composed &x, const Composed &y) { return x.equal(y); } class Outer { public: class Nested { typedef Base Base_; Base_ base_; public: explicit Nested(const unsigned int& t) : base_(t) {} bool equal(const Nested& x) const {return x.base_==base_;} }; }; bool operator==(const Outer::Nested &x, const Outer::Nested &y) { return x.equal(y); } } // namespace untemplated int main() { using std::cout; unsigned int testVal=3; { // No templates first typedef untemplated::Base Base_t; Base_t a(testVal); Base_t b(testVal); cout << "a=b=" << testVal << "\n"; cout << "a==b ? " << (a==b ? "TRUE" : "FALSE") << "\n"; typedef untemplated::Composed Composed_t; Composed_t c(testVal); Composed_t d(testVal); cout << "c=d=" << testVal << "\n"; cout << "c==d ? " << (c==d ? "TRUE" : "FALSE") << "\n"; typedef untemplated::Outer::Nested Nested_t; Nested_t e(testVal); Nested_t f(testVal); cout << "e=f=" << testVal << "\n"; cout << "e==f ? " << (e==f ? "TRUE" : "FALSE") << "\n"; } { // Now with templates typedef templated::Base<unsigned int> Base_t; Base_t a(testVal); Base_t b(testVal); cout << "a=b=" << testVal << "\n"; cout << "a==b ? " << (a==b ? "TRUE" : "FALSE") << "\n"; typedef templated::Composed<unsigned int> Composed_t; Composed_t c(testVal); Composed_t d(testVal); cout << "c=d=" << testVal << "\n"; cout << "d==c ? " << (c==d ? "TRUE" : "FALSE") << "\n"; typedef templated::Outer<unsigned int>::Nested Nested_t; Nested_t e(testVal); Nested_t f(testVal); cout << "e=f=" << testVal << "\n"; cout << "e==f ? " << (e==f ? "TRUE" : "FALSE") << "\n"; // Above line causes compiler error: // error: no match for 'operator==' in 'e == f' } cout << std::endl; return 0; }

    Read the article

  • How do I join three tables with SQLalchemy and keeping all of the columns in one of the tables?

    - by jimka
    So, I have three tables: The class defenitions: engine = create_engine('sqlite://test.db', echo=False) SQLSession = sessionmaker(bind=engine) Base = declarative_base() class Channel(Base): __tablename__ = 'channel' id = Column(Integer, primary_key = True) title = Column(String) description = Column(String) link = Column(String) pubDate = Column(DateTime) class User(Base): __tablename__ = 'user' id = Column(Integer, primary_key = True) username = Column(String) password = Column(String) sessionId = Column(String) class Subscription(Base): __tablename__ = 'subscription' userId = Column(Integer, ForeignKey('user.id'), primary_key=True) channelId = Column(Integer, ForeignKey('channel.id'), primary_key=True) And the SQL commands that are executed to create them: CREATE TABLE subscription ( "userId" INTEGER NOT NULL, "channelId" INTEGER NOT NULL, PRIMARY KEY ("userId", "channelId"), FOREIGN KEY("userId") REFERENCES user (id), FOREIGN KEY("channelId") REFERENCES channel (id) ); CREATE TABLE user ( id INTEGER NOT NULL, username VARCHAR, password VARCHAR, "sessionId" VARCHAR, PRIMARY KEY (id) ); CREATE TABLE channel ( id INTEGER NOT NULL, title VARCHAR, description VARCHAR, link VARCHAR, "pubDate" TIMESTAMP, PRIMARY KEY (id) ); NOTE: I know user.username should be unique, need to fix that, and I'm not sure why SQLalchemy creates some row names with the double-quotes. And I'm trying to come up with a way to retrieve all of the channels, as well as an indication on what channels one particular user (identified by user.sessionId together with user.id) has a subscription on. For example, say we have four channels: channel1, channel2, channel3, channel4; a user: user1; who has a subscription on channel1 and channel4. The query for user1 would return something like: channel.id | channel.title | subscribed --------------------------------------- 1 channel1 True 2 channel2 False 3 channel3 False 4 channel4 True This is a best-case result, but since I have absolutely no clue as how to accomplish the subscribed column, I've been instead trying to get the particular users id in the rows where the user has a subscription and where a subscription is missing, just leave it blank. The database engine that I'm using together with SQLalchemy atm. is sqlite3 I've been scratching my head over this for two days now, I've no problem joining together all three by way of the subscription table but then all of the channels where the user does not have a subscription gets omitted. I hope I've managed to describe my problem sufficiently, thanks in advance.

    Read the article

  • How to do a Postgresql subquery in select clause with join in from clause like SQL Server?

    - by Ricardo
    I am trying to write the following query on postgresql: select name, author_id, count(1), (select count(1) from names as n2 where n2.id = n1.id and t2.author_id = t1.author_id ) from names as n1 group by name, author_id This would certainly work on Microsft SQL Server but it does not at all on postegresql. I read its documentation a bit and it seems I could rewrite it as: select name, author_id, count(1), total from names as n1, (select count(1) as total from names as n2 where n2.id = n1.id and n2.author_id = t1.author_id ) as total group by name, author_id But that returns the following error on postegresql: "subquery in FROM cannot refer to other relations of same query level". So I'm stuck. Does anyone know how I can achieve that? Thanks

    Read the article

  • How do I join two git repos without a common root, where all modified files are the same?

    - by Evan Carroll
    I have a git-cpan-init of a repo which yielded a different root node from another already established git repo I found on github C:A:S:DBI. I've developed quite a bit on my repo, and I'd like to merge or replay my edits on a fork of the more authoritative repository. Does anyone know how to do this? I think it is safe to assume none of the file-contents of the modified files are different -- the code base hasn't been since Nov 08'. For clarity the git hub repo is the authoritative one. My local repo is the one I want to go up to git hub shown as a real git fork.

    Read the article

  • vector<vector<largeObject>> vs. vector<vector<largeObject>*> in c++

    - by Leif Andersen
    Obviously it will vary depending on the compiler you use, but I'm curious as to the performance issues when doing vector<vector<largeObject>> vs. vector<vector<largeObject>*>, especially in c++. In specific: let's say that you have the outer vector full, and you want to start inserting elements into first inner vector. How will that be stored in memory if the outer vector is just storing pointers, as apposed to storing the whole inner vector. Will the whole outer vector have to be moved to gain more space, or will the inner vector be moved (assuming that space wasn't pre-allocated), causing problems with the outer vector? Thank you

    Read the article

  • Doing a join across two databases with different collations on SQL Server and getting an error.

    - by Andrew G. Johnson
    I know, I know with what I wrote in the question I shouldn't be surprised. But my situation is slowly working on an inherited POS system and my predecessor apparently wasn't aware of JOINs so when I looked into one of the internal pages that loads for 60 seconds I see that it's a fairly quick, rewrite these 8 queries as one query with JOINs situation. Problem is that besides not knowing about JOINs he also seems to have had a fetish for multiple databases and surprise, surprise they use different collations. Fact of the matter is we use all "normal" latin characters that English speaking people would consider the entire alphabet and this whole thing will be out of use in a few months so a bandaid is all I need. Long story short is I need some kind of method to cast to a single collation so I can compare two fields from two databases. Exact error is: Cannot resolve the collation conflict between "SQL_Latin1_General_CP850_CI_AI" and "SQL_Latin1_General_CP1_CI_AS" in the equal to operation.

    Read the article

  • How do I use Criteria to make a join on a date field (in DB2) based on the year.

    - by HtmlTableGuru
    I have a java.util.Date field in my Object. I would like to use Criteria to select all rows that have a date field with a given year. The SQL would look like the following: SELECT * FROM GAME GM WHERE YEAR(GM.GAME_DATE) = 2010 How can I use Criteria to accomplish this? Thanks in advance. public Collection<Game> getGamesByDate(Date date){ Collection<Game> games = null; try { session.beginTransaction(); Criteria criteria = session.createCriteria(Game.class); criteria .... ... ... games = criteria.list(); } catch (HibernateException e) { e.printStackTrace(); } return games; }

    Read the article

  • Is it possible to join these two regex expressions into one?

    - by Pure.Krome
    Hi folks, i have the following two regular expressions (in order btw). 1. ^~/buying/(.*)\?(.*) => foo= group 1 baa= group 2. 2. ^~/buying/(.*) => foo= group 1 baa= nothing/empty/null/baibai What's i'm trying to do is, if the url has a questionmark, then split it into two groups. Otherwise, just throw all the stuff into the first group. the reason why the order is important for me, is that if i switch them round, the '?' regex will never get fired because the #2 expression (above) will catch all. So .. can this be re-fixed? NOTE: I have tried using this website** to help me debug/tweak .. but I can't figure it out. ** I have no affiliation with that site.

    Read the article

  • SQLAlchemy Expression Language problem

    - by Torkel
    I'm trying to convert this to something sqlalchemy expression language compatible, I don't know if it's possible out of box and are hoping someone more experienced can help me along. The backend is PostgreSQL and if I can't make it as an expression I'll create a string instead. SELECT DISTINCT date_trunc('month', x.x) as date, COALESCE(b.res1, 0) AS res1, COALESCE(b.res2, 0) AS res2 FROM generate_series( date_trunc('year', now() - interval '1 years'), date_trunc('year', now() + interval '1 years'), interval '1 months' ) AS x LEFT OUTER JOIN( SELECT date_trunc('month', access_datetime) AS when, count(NULLIF(resource_id != 1, TRUE)) AS res1, count(NULLIF(resource_id != 2, TRUE)) AS res2 FROM tracking_entries GROUP BY date_trunc('month', access_datetime) ) AS b ON (date_trunc('month', x.x) = b.when) First of all I got a class TrackingEntry mapped to tracking_entries, the select statement within the outer joined can be converted to something like (pseudocode):: from sqlalchemy.sql import func, select from datetime import datetime, timedelta stmt = select([ func.date_trunc('month', TrackingEntry.resource_id).label('when'), func.count(func.nullif(TrackingEntry.resource_id != 1, True)).label('res1'), func.count(func.nullif(TrackingEntry.resource_id != 2, True)).label('res2') ], group_by=[func.date_trunc('month', TrackingEntry.access_datetime), ]) Considering the outer select statement I have no idea how to build it, my guess is something like: outer = select([ func.distinct(func.date_trunc('month', ?)).label('date'), func.coalesce(?.res1, 0).label('res1'), func.coalesce(?.res2, 0).label('res2') ], from_obj=[ func.generate_series( datetime.now(), datetime.now() + timedelta(days=365), timedelta(days=1) ).label(x) ]) Then I suppose I have to link those statements together without using foreign keys: outer.outerjoin(stmt???).??(func.date_trunc('month', ?.?), ?.when) Anyone got any suggestions or even better a solution?

    Read the article

  • Which will be the best query OR there is an another one?

    - by serhan
    SELECT k.id,k.adsoyad, COUNT(DISTINCT(e.id)) as iletisimbilgisisay, COUNT(DISTINCT(f.id)) AS ilangonderensay, COUNT(DISTINCT(g.id)) AS emlaksahibisay, isNULL(MAX(eb.yonetici_kisi),0) AS yoneticiid FROM dbo.kisiler k LEFT OUTER JOIN dbo.emlaklar e ON e.iletisimbilgisi=k.id LEFT OUTER JOIN dbo.emlaklar f ON f.ilangonderen=k.id LEFT OUTER JOIN dbo.emlaklar g ON g.emlaksahibi=k.id LEFT OUTER JOIN dbo.emlakcibilgileri eb ON eb.yonetici_kisi=k.id GROUP BY k.id,k.adsoyad ORDER BY yoneticiid DESC, iletisimbilgisisay DESC, ilangonderensay DESC total execution time (above) 28 SELECT id,adsoyad, (select COUNT(id) FROM dbo.emlaklar WHERE iletisimbilgisi=k.id) AS iletisimbilgisisay, (select COUNT(id) FROM dbo.emlaklar WHERE emlaksahibi=k.id) AS emlaksahibisay, (select COUNT(id) FROM dbo.emlaklar WHERE ilangonderen=k.id) AS ilangonderensay, (Select isNULL(MAX(id),0) FROM dbo.emlakcibilgileri WHERE yonetici_kisi=k.id) AS yoneticiid FROM dbo.kisiler k total execution time 4 my tables are emlaklar: id int, ilangonderen int,iletisimbilgisi int,emlaksahibi int kisiler: id int,kisiadi emlakcibilgileri: id int,yonetici_kisi int,firma and ilangonderen,iletisimbilgisi,emlaksahibi,yonetici_kisi => kisiler.id

    Read the article

  • How can I ceil the height of a div that has "display: table-cell"?

    - by eric01
    I am trying to vertically center a div inside another div, regardless of the size of both div's I am doing this: <div id='outer_div'> <div id='inner_div'></div> </div> The CSS is #outer_div { display: table-row; height: 200px; width: 200px } #inner_div { display: table-cell; vertical-align: middle; height: 500px; width: 500px } I put larger dimensions for the inner div on purpose. What happens is that even if I put a width of 1000px, the width of the innerdiv is ceiled at 200px because of the outer div's width (and this is what I want) But for the height, it is not ceiled and I would like it to be ceiled to the height of the outer div. What i want is the innerdiv to remain at the same size as the outer_div, no matter what height I give to outer_div in CSS. I basically want it to be the same size as its parent. EDIT: I only put text inside those div's. So let's say I have an outer div of 200px*200px (it has display: table-row), and the inner div is defined by css as 500px*500px and it has dummy text inside. My expected result is to have the inner div shrunk down to 200px*200px. It is successfully 'shrunk' by the outer div for the width, but NOT for the height. What I want is to have it shrunk on the height as well (so the inner div ajusts automatically in case I change the height of the outer div) How do I go about that?

    Read the article

  • Join Where Rows Don't Exist or Where Criteria Matches...?

    - by Greg
    I'm trying to write a query to tell me which orders have valid promocodes. Promocodes are only valid between certain dates and optionally certain packages. I'm having trouble even explaining how this works (see psudo-ish code below) but basically if there are packages associated with a promocode then the order has to have one of those packages and be within a valid date range otherwise it just has to be in a valid date range. The whole "if PrmoPackage rows exist" thing is really throwing me off and I feel like I should be able to do this without a whole bunch of Unions. (I'm not even sure if that would make it easier at this point...) Anybody have any ideas for the query? if `OrderPromoCode` = `PromoCode` then if `OrderTimestamp` is between `PromoStartTimestamp` and `PromoEndTimestamp` then if `PromoCode` has packages associated with it //yes then if `PackageID` is one of the specified packages //yes code is valid //no invalid //no code is valid Order: OrderID* | OrderTimestamp | PackageID | OrderPromoCode 1 | 1/2/11 | 1 | ABC 2 | 1/3/11 | 2 | ABC 3 | 3/2/11 | 2 | DEF 4 | 4/2/11 | 3 | GHI Promo: PromoCode* | PromoStartTimestamp* | PromoEndTimestamp* ABC | 1/1/11 | 2/1/11 ABC | 3/1/11 | 4/1/11 DEF | 1/1/11 | 1/11/13 GHI | 1/1/11 | 1/11/13 PromoPackage: PromoCode* | PromoStartTimestamp* | PromoEndTimestamp* | PackageID* ABC | 1/1/11 | 2/1/11 | 1 ABC | 1/1/11 | 2/1/11 | 3 GHI | 1/1/11 | 1/11/13 | 1 Desired Result: OrderID | IsPromoCodeValid 1 | 1 2 | 0 3 | 1 4 | 0

    Read the article

  • How to join nearly identical several queries into one?

    - by Devyn
    Hi, Assume I have an order_dummy table where order_dummy_id, order_id, user_id, book_id, author_id are stored. You may complain the logic of my table but I somehow need to do it that way. I want to execute following queries. SELECT * FROM order_dummy WHERE order_id = 1 AND user_id = 1 AND book_id = 1 ORDER BY `order_dummy_id` DESC LIMIT 1 SELECT * FROM order_dummy WHERE order_id = 1 AND user_id = 1 AND book_id = 2 ORDER BY `order_dummy_id` DESC LIMIT 1 SELECT * FROM order_dummy WHERE order_id = 1 AND user_id = 1 AND book_id = 3 ORDER BY `order_dummy_id` DESC LIMIT 1 Please keep in mind that several numbers of same book is included in one order. Therefore, I list order_dummy_id by descending and limit 1 so only LATEST ORDER of A BOOK is shown. But my goal is to show other books in that way in one table. I used group by like this ... SELECT * FROM order_dummy WHERE order_id = 1 AND user_id = 1 GROUP BY book_id but it only shows order_dummy_id with ascending result. I have no idea anymore. Looking forward your kindness help!

    Read the article

  • Where do objects merge/join data in a 3-tier model?

    - by BerggreenDK
    Its probarbly a simple 3-tier problem. I just want to make sure we use the best practice for this and I am not that familiary with the structures yet. We have the 3 tiers: GUI: ASP.NET for Presentation-layer (first platform) BAL: Business-layer will be handling the logic on a webserver in C#, so we both can use it for webforms/MVC + webservices DAL: LINQ to SQL in the Data-layer, returning BusinessObjects not LINQ. DB: The SQL will be Microsoft SQL-server/Express (havent decided yet). Lets think of setup where we have a database of [Persons]. They can all have multiple [Address]es and we have a complete list of all [PostalCode] and corresponding citynames etc. The deal is that we have joined a lot of details from other tables. {Relations}/[tables] [Person]:1 --- N:{PersonAddress}:M --- 1:[Address] [Address]:N --- 1:[PostalCode] Now we want to build the DAL for Person. How should the PersonBO look and when does the joins occure? Is it a business-layer problem to fetch all citynames and possible addressses pr. Person? or should the DAL complete all this before returning the PersonBO to the BAL ? Class PersonBO { public int ID {get;set;} public string Name {get;set;} public List<AddressBO> {get;set;} // Question #1 } // Q1: do we retrieve the objects before returning the PersonBO and should it be an Array instead? or is this totally wrong for n-tier/3-tier?? Class AddressBO { public int ID {get;set;} public string StreetName {get;set;} public int PostalCode {get;set;} // Question #2 } // Q2: do we make the lookup or just leave the PostalCode for later lookup? Can anyone explain in what order to pull which objects? Constructive criticism is very welcome. :o)

    Read the article

  • t-sql - find differences for pk's in a single table (Self join?)

    - by Pace
    Hi Experts, My situation is this. I have a table of products with a pk "Parent" which has "Components" The data looks something like this Parent(PK) Component Car1 Wheel Car1 Tyre Car1 Roof Car2 Alloy Car2 Tyre Car2 Roof Car3 Alloy Car3 Tyre Car3 Roof Car3 Leather Seats Now what I want to do is some query that I can feed two codes in and see the differences... IE If I feed in "Car1", "Car2" it would return something like; Parent Component Car1 Wheel Car2 Alloy As this is the difference between the two. If I said "Car1", "Car3" I would expect; Parent Component Car1 Wheel Car3 Alloy Car3 Leather Seats Your help with this matter would be greatly appreciated.

    Read the article

  • Passing markup into a Rails Partial

    - by 1ndivisible
    Is there any way of doing something equivilant to this: <%= render partial: 'shared/outer' do %> <%= render partial: 'shared/inner' %> <% end %> Resulting in <div class="outer"> <div class="inner"> </div> </div> Obviously there would need to be a way of marking up 'shared/outer.html.erb' to indicate where the passed in partial should be rendered: <div class="outer"> <% render Here %> </div>

    Read the article

  • Rails nested attributes with a join model, where one of the models being joined is a new record

    - by gzuki
    I'm trying to build a grid, in rails, for entering data. It has rows and columns, and rows and columns are joined by cells. In my view, I need for the grid to be able to handle having 'new' rows and columns on the edge, so that if you type in them and then submit, they are automatically generated, and their shared cells are connected to them correctly. I want to be able to do this without JS. Rails nested attributes fail to handle being mapped to both a new record and a new column, they can only do one or the other. The reason is that they are a nested specifically in one of the two models, and whichever one they aren't nested in will have no id (since it doesn't exist yet), and when pushed through accepts_nested_attributes_for on the top level Grid model, they will only be bound to the new object created for whatever they were nested in. How can I handle this? Do I have to override rails handling of nested attributes? My models look like this, btw: class Grid < ActiveRecord::Base has_many :rows has_many :columns has_many :cells, :through => :rows accepts_nested_attributes_for :rows, :allow_destroy => true, :reject_if => lambda {|a| a[:description].blank? } accepts_nested_attributes_for :columns, :allow_destroy => true, :reject_if => lambda {|a| a[:description].blank? } end class Column < ActiveRecord::Base belongs_to :grid has_many :cells, :dependent => :destroy has_many :rows, :through => :grid end class Row < ActiveRecord::Base belongs_to :grid has_many :cells, :dependent => :destroy has_many :columns, :through => :grid accepts_nested_attributes_for :cells end class Cell < ActiveRecord::Base belongs_to :row belongs_to :column has_one :grid, :through => :row end

    Read the article

  • How to write simple Where Clause for dynamic filtering in linq when we use groups in join

    - by malik
    I have simple search page i want to filter the results. var TransactionStats = from trans in context.ProductTransactionSet.Include("SPL") select new { trans.InvoiceNo, ProductGroup = from tranline in trans.ProductTransactionLines group tranline by tranline.ProductTransaction.TransactionID into ProductGroupDetil select new { TransactionDateTime = ProductGroupDetil.Select (Content => Content.TransactionDateTime) } }; I want to use TransactionDateTime in where clause when required. if (_FilterCrieteria.DateFrom.HasValue) { TransactionStats.Where ( a => a.ProductGroup.Where ( dt => dt.DateofTransaction >= _FilterCrieteria.DateFrom && dt.DateofTransaction >= _FilterCrieteria.DateFrom ) ) } Can any one correct the syntax?

    Read the article

  • get-wmiobject sql join in powershell - trying to find physical memory vs. virtual memory of remote s

    - by Willy
    get-wmiobject -query "Select TotalPhysicalMemory from Win32_LogicalMemoryConfiguration" -computer COMPUTERNAME output.csv get-wmiobject -query "Select TotalPageFileSpace from Win32_LogicalMemoryConfiguration" -computer COMPUTERNAME output.csv I am trying to complete this script with an output as such: Computer Physical Memory Virtual Memory server1 4096mb 8000mb server2 2048mb 4000mb

    Read the article

  • What are some Coldfusion (mx7 and greater) "Gotchas" that I should know about?

    - by jakeonrails
    I just spent half the day troubleshooting what is apparently a rather famous gotcha for Coldfusion MX7 and below: The nested query loop bug: Where you are required to reference the current_row of the outer query or else you will only see the first record. For example: <cfloop query="outer"> <cfloop query="innner"> <p>#outer.field#</p><!--- this won't work, you'll only get the first row ---> <p>#outer.field[current_row]#</p><!--- you must do this instead ---> </cfloop> </cfloop> Are there any other ways in which ColdFusion does not work in the obvious way?

    Read the article

  • jQuery Nested Droppables

    - by John
    I have a nested set of jQuery droppables...one outer droppable that encompasses most of the page and an a set of nested inner droppables on the page. The functionality I want is: If a draggable is dropped outside of any of the inner droppables it should be accepted by the outer droppable. If a draggable is dropped onto any of the inner droppables it should NOT be accepted by the outer droppable, regardless of whether the inner droppable accepts the draggable. So that would be easy if I could guarantee 1+ inner droppables would accept the draggable, because the greedy attribute would make sure it would only get triggered once. Unfortunately the majority of the time the inner droppable will also reject the draggable, meaning the greedy option doesn't really help. Summary: The basic functionality is a set of valid/invalid inner droppables to accept the draggable, but when you toss the draggable outside any of the draggables it gets destroyed by the outer droppable. What's the best way of doing this?

    Read the article

< Previous Page | 52 53 54 55 56 57 58 59 60 61 62 63  | Next Page >