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  • MySQL + MyISAM table size question

    - by alessandro ferrucci
    Hello, I have a test table. The test table is as follows: CREATE TABLE mytest ( num1 int(10) unsigned NOT NULL, KEY key1 (num1) ) ENGINE=MyISAM DEFAULT CHARSET=latin1; I inserted 50 million rows in this table. When I do show table status the avg_row_length is 7. I was expecting to see 4 since mySQL uses 4 bytes for integers. Does the key have an effect on the avg_row_length? When I look at my .MYD file the size is 334 MB which is exactly what it should be given that the avg_row_length is 7, however I was really expecting to see 190 MB given that I only have an int. +----------------+--------+---------+------------+----------+----------------+-------------+------------------+--------------+-----------+----------------+---------------------+---------------------+------------+-------------------+----------+----------------+---------+ | Name | Engine | Version | Row_format | Rows | Avg_row_length | Data_length | Max_data_length | Index_length | Data_free | Auto_increment | Create_time | Update_time | Check_time | Collation | Checksum | Create_options | Comment | +----------------+--------+---------+------------+----------+----------------+-------------+------------------+--------------+-----------+----------------+---------------------+---------------------+------------+-------------------+----------+----------------+---------+ | mytest | MyISAM | 10 | Fixed | 50000000 | 7 | 350000000 | 1970324836974591 | 600518656 | 0 | NULL | 2010-05-22 09:15:06 | 2010-05-22 19:32:53 | NULL | latin1_swedish_ci | NULL | | | I have included the output of show table status for mytest table. Sorry about the formatting :D Thanks in advance! Alessandro Ferrucci

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  • How to efficiently SELECT rows from database table based on selected set of values

    - by Chau Chee Yang
    I have a transaction table of 1 million rows. The table has a field name "Code" to keep customer's ID. There are about 10,000 different customer code. I have an GUI interface allow user to render a report from transaction table. User may select arbitrary number of customers for rendering. I use IN operator first and it works for few customers: SELECT * FROM TRANS_TABLE WHERE CODE IN ('...', '...', '...') I quickly run into problem if I select few thousand customers. There is limitation using IN operator. An alternate way is create a temporary table with only one field of CODE, and inject selected customer codes into the temporary table using INSERT statement. I may then using SELECT A.* FROM TRANS_TABLE A INNER JOIN TEMP B ON (A.CODE=B.CODE) This works nice for huge selection. However, there is performance overhead for temporary table creation, INSERT injection and dropping of temporary table. Do you aware of better solution to handle this situation?

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  • SSIS - Update flag of selected rows from more than one table

    - by Rob Bowman
    Hi I have a SSIS package that copies data from table A to table B and sets a flag in table A so that the same data is not copied subsequently. This works great by using the following as the SQL command text on the ADO Net Source object: update transfer set ProcessDateTimeStamp = GetDate(), LastUpdatedBy = 'legacy processed' output inserted.* where LastUpdatedBy = 'legacy' and ProcessDateTimeStamp is not null The problem I have is that I need to run a similar data copy but from two sources table, joined on a primary / foreign key - select from table A join table B update flag in table A. I don't think I can use the technique above because I don't know where I'd put the join! Is there another way around this problem? Thanks Rob.

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  • MVC Entity Model not showing my table

    - by Jessica
    I have a database with multiple tables, and some basic relationships. Here is an example of the problem I am having: My Database: **Org** ID Name etc **Detail1** ID D1name **Org_Detail1** Org_ID Detail1_ID **Detail2** ID D2Name **Org_Detail2** Org_ID Detial1_ID BooleanField My problem is, the Org_detail1 table is not showing up in the entity model, but the Org_Details2 table does. I thought it may have been because the Org_Detail1 table only contains two ID fields that are both primary keys, while the Org_Details2 table contains 2 primary key ID fields as well as a boolean field. If I add a dummy field to Org_detail1 and update it, it still won't show up and wont allow me to add a new entity relating to the Org_Detail1 table. The table won't even show up in the list, but it is listed under the tables. Is there any solution to get this table to appear in my model?

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  • Getting a linq table to be dynamically sent to a method

    - by Damian Spaulding
    I have a procedure: var Edit = (from R in Linq.Products where R.ID == RecordID select R).Single(); That I would like to make "Linq.Products" Dynamic. Something like: protected void Page_Load(object sender, EventArgs e) { something(Linq.Products); } public void something(Object MyObject) { System.Data.Linq.Table<Product> Dynamic = (System.Data.Linq.Table<Product>)MyObject; var Edit = (from R in Dynamic where R.ID == RecordID select R).Single(); My problem is that I my "something" method will not be able to know what table has been sent to it. so the static line: System.Data.Linq.Table Dynamic = (System.Data.Linq.Table)MyObject; Would have to reflect somthing like: System.Data.Linq.Table Dynamic = (System.Data.Linq.Table)MyObject; With being a dynamic catch all variable so that Linq can just execute the code just like I hand coded it statically. I have been pulling my hair out with this one. Please help.

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  • DB2 Child Table - Auto Delete With Parent

    - by gamerzfuse
    I have a bit of a task before me. (DB2 Database) I need to create a table that will be a child table (is that what it is called in SQL?) I need it so that it has a foreign key constraint with my other table, so when the parent table is modified (record deleted) the child table also loses that record. Once I have the table, I also need to populate it with the data from the other table (if there is an easy way to UPDATE this). If you could point me in the right direction, this would help alot, as I do not even know what syntax to look for. Thanks in advance

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  • How to add a sequence column to an existing table with records

    - by user1888543
    I had created a new table named USERLOG with two fields from a previous VIEW. The table already consist of about 9000 records. The two fields taken from the VIEW, i.e. weblog_views consist of IP (consists of IP address), and WEB_LINK (consists of URL). This is the code I used, CREATE TABLE USERLOG AS SELECT C_IP, WEB_LINK FROM weblog_views; I want to add another column to this table called the USER_ID, which would consists of a sequence starting with 1 to 9000 records to create a unique id for each existing rows. I need help with this part. I'm using Oracle SQL Developer: ODMiner version 3.0.04. I tried using the AUTO-INCREMENT option, ALTER TABLE USERLOG ADD USER_ID INT UNSIGNED NOT NULL AUTO_INCREMENT; But I get an error with this, Error report: SQL Error: ORA-01735: invalid ALTER TABLE option 01735. 00000 - "invalid ALTER TABLE option" So, I would really appreciate any help that I can get!

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  • problem with TEMPORARY TABLE

    - by Z77
    Within PHP I do: 1.) A temporary table is created: CREATE TEMP TABLE new_table AS SELECT .... FROM ...; 2.) AFter that I want to use this table to create a shape file: shell_exec ("pgsql2shp .... -u username -P password ...); Separetly those two things work, but by creating a temporary table and after that using this table in pgsql2shp does not work. I pressume this is because temporary table duration is to the end of session. But to create shp file I need to use username and password what means new session starts and temporary table is dropped before I use it for shape creation. Any tip how to solve it? Thank you!

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  • Copy a Table's data from a Stored Procedure

    - by Niike2
    I am learning how to use SQL and Stored Procedures. I know the syntax is incorrect: Copy data from one table into another table on another Database with a Stored Procedure. The problem is I don't know what table or what database to copy to. I want it to use parameters and not specify the columns specifically. I have 2 Databases (Master_db and Master_copy) and the same table structure on each DB. I want to quickly select a table in Master_db and copy that table's data into Master_copy table with same name. I have come up with something like this: USE Master_DB CREATE PROCEDURE TransferData DEFINE @tableFrom, @tableTo, @databaseTo; INSERT INTO @databaseTo.dbo.@databaseTo SELECT * FROM Master_DB.dbo.@tableFrom GO;

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  • How to handle huge table ?

    - by misha-moroshko
    I would like to display to user a table which contains ~500,000 rows. The table should be calculated based on a file (i.e. the table is known at the beginning, and does not change). I guess that building the HTML text of this table is not a good idea in terms of memory performance. So how can I build such table ? I would like user to be able to scroll the table using a vertical scroll bar. Is it possible to build on the fly only the visible part of the table ? I'm afraid to see delays because of this. Is it a better idea to use server side programming rather than Javascript ? Any advise would be appreciated.

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  • Using calculated fields over and over again with a new table

    - by Sin5k4
    I'm fairly new to SQL and i had to do some calculations using a table.Imagine we have a table with fields : ID - Name - Val1 - Val2 ; Lets say i want to add up 2 values and add it to my query result.I can do that easily with a sub query such as: select val1+val2 as valtotal,* from my table. Now if i want to do some more process on valtotal, i use a derived table such as; select valtotal*3 as ValMoreCalculated,* from (select val1+val2 as valtotal,* from my table) AS A A bit more code maybe?? select ValMoreCalculated/valtotal as ValEvenMoreCalc ,* from (select valtotal*3 as ValMoreCalculated,* from (select val1+val2 as valtotal,* from my table) AS A)AS B So if i want to do more calculations with the ValMoreCalculated do i have to go through another derived table? Name it as B for example? Is there an easier way to achieve this in SQL? PS:the title is a bit off i know,but couldn't figure out what to name it :P

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  • what's wrong with mysql to create very long table fields?

    - by peng
    mysql> create table balance_sheet( -> Cash_and_cash_equivalents VARCHAR(20), -> Trading_financial_assets VARCHAR(20), -> Note_receivable VARCHAR(20), -> Account_receivable VARCHAR(20), -> Advance_money VARCHAR(20), -> Interest_receivable VARCHAR(20), -> Dividend_receivable VARCHAR(20), -> Other_notes_receivable VARCHAR(20), -> Due_from_related_parties VARCHAR(20), -> Inventory VARCHAR(20), -> Consumptive_biological_assets VARCHAR(20), -> Non_current_asset(expire_in_a_year) VARCHAR(20), -> Other_current_assets VARCHAR(20), -> Total_current_assets VARCHAR(20), -> Available_for_sale_financial_assets VARCHAR(20), -> Held_to_maturity_investment VARCHAR(20), -> Long_term_account_receivable VARCHAR(20), -> Long_term_equity_investment VARCHAR(20), -> Investment_real_eastate VARCHAR(20), -> Fixed_assets VARCHAR(20), -> Construction_in_progress VARCHAR(20), -> Project_material VARCHAR(20), -> Liquidation_of_fixed_assets VARCHAR(20), -> Capitalized_biological_assets VARCHAR(20), -> Oil_and_gas_assets VARCHAR(20), -> Intangible_assets VARCHAR(20), -> R&d_expense VARCHAR(20), -> Goodwill VARCHAR(20), -> Deferred_assets VARCHAR(20), -> Deferred_income_tax_assets VARCHAR(20), -> Other_non_current_assets VARCHAR(20), -> Total_non_current_assets VARCHAR(20), -> Total_assets VARCHAR(20), -> Short_term_borrowing VARCHAR(20), -> Transaction_financial_liabilities VARCHAR(20), -> Notes_payable VARCHAR(20), -> Account_payable VARCHAR(20), -> Item_received_in_advance VARCHAR(20), -> Employee_pay_payable VARCHAR(20), -> Tax_payable VARCHAR(20), -> Interest_payable VARCHAR(20), -> Dividend_payable VARCHAR(20), -> Other_account_payable VARCHAR(20), -> Due_to_related_parties VARCHAR(20), -> Non_current_liabilities_due_within_one_year VARCHAR(20), -> Other_current_liabilities VARCHAR(20), -> Total_current_liabilities VARCHAR(20), -> Long_term_loan VARCHAR(20), -> Bonds_payable VARCHAR(20), -> Long_term_payable VARCHAR(20), -> Specific_payable VARCHAR(20), -> Estimated_liabilities VARCHAR(20), -> Deferred_income_tax_liabilities VARCHAR(20), -> Other_non_current_liabilities VARCHAR(20), -> Total_non_current_liabilities VARCHAR(20), -> Total_liabilities VARCHAR(20), -> Paid_in_capital VARCHAR(20), -> Contributed_surplus VARCHAR(20), -> Treasury_stock VARCHAR(20), -> Earned_surplus VARCHAR(20), -> Retained_earnings VARCHAR(20), -> Translation_reserve VARCHAR(20), -> Nonrecurring_items VARCHAR(20), -> Total_equity(non) VARCHAR(20), -> Minority_interests VARCHAR(20), -> Total_equity VARCHAR(20), -> Total_liabilities_&_shareholder's_equity VARCHAR(20)); '> '> when i press enter,there is the output of ' ,no other reaction ,what's wrong?

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  • Conflicting ip routes with local table on attaching a virtual network interface

    - by user1071840
    I have an EC2 instance with these ip rules: $ sudo ip rule show 0: from all lookup local 32766: from all lookup main 32767: from all lookup default I can attach an elastic network interface to it with a private IP. Say the IP of my machine is 10.1.3.12 and the IP of the interface is 10.1.1.190. As soon as I attach the interface to my machine a new entry is added to the routing policy and local routing table: sudo ip rule show 0: from all lookup local 32765: from 10.1.1.190 lookup 10003 32766: from all lookup main 32767: from all lookup default $ sudo ip route show table local broadcast 10.1.1.0 dev eth3 proto kernel scope link src 10.1.1.190 local 10.1.1.190 dev eth3 proto kernel scope host src 10.1.1.190 broadcast 10.1.1.255 dev eth3 proto kernel scope link src 10.1.1.190 broadcast 10.1.3.0 dev eth0 proto kernel scope link src 10.1.3.12 local 10.1.3.12 dev eth0 proto kernel scope host src 10.1.3.12 broadcast 10.1.3.255 dev eth0 proto kernel scope link src 10.1.3.12 broadcast 127.0.0.0 dev lo proto kernel scope link src 127.0.0.1 local 127.0.0.0/8 dev lo proto kernel scope host src 127.0.0.1 local 127.0.0.1 dev lo proto kernel scope host src 127.0.0.1 broadcast 127.255.255.255 dev lo proto kernel scope link src 127.0.0.1 I can send traffic to this ENI directly from a host that can have the same IP as the host the ENI is attached to. This is where the problem starts. I ran tcpdump on the port in question and saw multiple SYNs going to the ENI with src '10.1.3.12' and destination '10.1.1.190' but didn't see even a single ACK. In my understanding if ACKs were being sent from the ENI they'd have destination as 10.1.3.12 i.e. the same as the local machine's IP and such packets will now be routed as local packets matching local routing policy: local 10.1.3.12 dev eth0 proto kernel scope host src 10.1.3.12 I'd like to send all the packets originating from 10.1.1.190 (my ENI) to go back on the same interface i.e. eth3 in this case. Contents of the nee table 10003 are: $ sudo ip route show table 10003 default via 10.1.1.1 dev eth3 I think I can do the following: I don't know if its possible but probably decrease the priority of local table so the packets match the table 10003. Use iptables to mangle these packets and update the local table route to include the mark information But I'm not sure if these are the right approaches.

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  • Can I select a set of rows from a table and directly insert that into a table or the same table in S

    - by VJ
    Hi I guess we cannot do this but was just curious if I could do something like - Select * from Employee where EmployeeId=1 and then use the data in the above statement and directly insert into a table with just changing the employeeid...or just this way- insert into Employee ( Select * from Employee where EmployeeId=1) its probably stupid from my side...but I just felt the need to do this a lot of times...so just was curious if there was any way to achieve it..

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  • NHibernate HiLo - new column per entity and HiLo catches

    - by Gareth
    Im currently using the hilo id generator for my classes but have just been using the minimal of settings eg <class name="ClassA" <id name="Id" column="id" unsaved-value="0" <generator class="hilo" / </id ... But should I really be specifying a new column for NHibernate to use foreach entity and providing it with a max lo? <class name="ClassA" <id name="Id" column="id" unsaved-value="0" <generator class="hilo" <param name="table"hibernate_unique_key</param <param name="column"classA_nexthi</param <param name="max_lo"20</param </generator </id ... <class name="ClassB" <id name="Id" column="id" unsaved-value="0" <generator class="hilo" <param name="table"hibernate_unique_key</param <param name="column"classB_nexthi</param <param name="max_lo"20</param </generator </id ... Also I've noticed that when I do the above the SchemaExport will not create all the columns - only classB_nexthi, is there something else im doing wrong. Thanks

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  • Oracle Linux and Oracle VM pricing guide

    - by wcoekaer
    A few days ago someone showed me a pricing guide from a Linux vendor and I was a bit surprised at the complexity of it. Especially when you look at larger servers (4 or 8 sockets) and when adding virtual machine use into the mix. I think we have a very compelling and simple pricing model for both Oracle Linux and Oracle VM. Let me see if I can explain it in 1 page, not 10 pages. This pricing information is publicly available on the Oracle store, I am using the current public list prices. Also keep in mind that this is for customers using non-oracle x86 servers. When a customer purchases an Oracle x86 server, the annual systems support includes full use (all you can eat) of Oracle Linux, Oracle VM and Oracle Solaris (no matter how many VMs you run on that server, in case you deploy guests on a hypervisor). This support level is the equivalent of premier support in the list below. Let's start with Oracle VM (x86) : Oracle VM support subscriptions are per physical server on which you deploy the Oracle VM Server product. (1) Oracle VM Premier Limited - 1- or 2 socket server : $599 per server per year (2) Oracle VM Premier - more than 2 socket server (4, or 8 or whatever more) : $1199 per server per year The above includes the use of Oracle VM Manager and Oracle Enterprise Manager Cloud Control's Virtualization management pack (including self service cloud portal, etc..) 24x7 support, access to bugfixes, updates and new releases. It also includes all options, live migrate, dynamic resource scheduling, high availability, dynamic power management, etc If you want to play with the product, or even use the product without access to support services, the product is freely downloadable from edelivery. Next, Oracle Linux : Oracle Linux support subscriptions are per physical server. If you plan to run Oracle Linux as a guest on Oracle VM, VMWare or Hyper-v, you only have to pay for a single subscription per system, we do not charge per guest or per number of guests. In other words, you can run any number of Oracle Linux guests per physical server and count it as just a single subscription. (1) Oracle Linux Network Support - any number of sockets per server : $119 per server per year Network support does not offer support services. It provides access to the Unbreakable Linux Network and also offers full indemnification for Oracle Linux. (2) Oracle Linux Basic Limited Support - 1- or 2 socket servers : $499 per server per year This subscription provides 24x7 support services, access to the Unbreakable Linux Network and the Oracle Support portal, indemnification, use of Oracle Clusterware for Linux HA and use of Oracle Enterprise Manager Cloud control for Linux OS management. It includes ocfs2 as a clustered filesystem. (3) Oracle Linux Basic Support - more than 2 socket server (4, or 8 or more) : $1199 per server per year This subscription provides 24x7 support services, access to the Unbreakable Linux Network and the Oracle Support portal, indemnification, use of Oracle Clusterware for Linux HA and use of Oracle Enterprise Manager Cloud control for Linux OS management. It includes ocfs2 as a clustered filesystem (4) Oracle Linux Premier Limited Support - 1- or 2 socket servers : $1399 per server per year This subscription provides 24x7 support services, access to the Unbreakable Linux Network and the Oracle Support portal, indemnification, use of Oracle Clusterware for Linux HA and use of Oracle Enterprise Manager Cloud control for Linux OS management, XFS filesystem support. It also offers Oracle Lifetime support, backporting of patches for critical customers in previous versions of package and ksplice zero-downtime updates. (5) Oracle Linux Premier Support - more than 2 socket servers : $2299 per server per year This subscription provides 24x7 support services, access to the Unbreakable Linux Network and the Oracle Support portal, indemnification, use of Oracle Clusterware for Linux HA and use of Oracle Enterprise Manager Cloud control for Linux OS management, XFS filesystem support. It also offers Oracle Lifetime support, backporting of patches for critical customers in previous versions of package and ksplice zero-downtime updates. (6) Freely available Oracle Linux - any number of sockets You can freely download Oracle Linux, install it on any number of servers and use it for any reason, without support, without right to use of these extra features like Oracle Clusterware or ksplice, without indemnification. However, you do have full access to all errata as well. Need support? then use options (1)..(5) So that's it. Count number of 2 socket boxes, more than 2 socket boxes, decide on basic or premier support level and you are done. You don't have to worry about different levels based on how many virtual instance you deploy or want to deploy. A very simple menu of choices. We offer, inclusive, Linux OS clusterware, Linux OS Management, provisioning and monitoring, cluster filesystem (ocfs), high performance filesystem (xfs), dtrace, ksplice, ofed (infiniband stack for high performance networking). No separate add-on menus. NOTE : socket/cpu can have any number of cores. So whether you have a 4,6,8,10 or 12 core CPU doesn't matter, we count the number of physical CPUs.

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  • Advanced SQL Data Compare throught multiple tables

    - by podosta
    Hello, Consider the situation below. Two tables (A & B), in two environments (DEV & TEST), with records in those tables. If you look the content of the tables, you understand that functionnal data are identical. I mean except the PK and FK values, the name Roger is sill connected to Fruit & Vegetable. In DEV environment : Table A 1 Roger 2 Kevin Table B (italic field is FK to table A) 1 1 Fruit 2 1 Vegetable 3 2 Meat In TEST environment : Table A 4 Roger 5 Kevin Table B (italic field is FK to table A) 7 4 Fruit 8 4 Vegetable 9 5 Meat I'm looking for a SQL Data Compare tool which will tell me there is no difference in the above case. Or if there is, it will generate insert & update scripts with the right order (insert first in A then B) Thanks a lot guys, Grégoire

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  • How to define cell width for 2 HTML tables with different column counts?

    - by DaveDev
    If I have 2 tables: <table id="Table1"> <tr> <td></td><td></td><td></td> </tr> </table> <table id="Table2"> <tr> <td></td><td></td><td></td><td></td> </tr> </table> The first has 3 columns, the second has 4 columns. How can I define a style to represent both tables when I want Table1's cell width to be 1/3 the width of the full table, and Table2's cells are 1/4 the width of the table?

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  • Turn RSS into array, explode the 'description' and insert words into MySQL table one per row

    - by K.I
    I have only recently gotten into php and MySQL and I want to take an RSS feed, turn it into an array, take only the description part of the XML, explode it and insert it into a table on a MySQL base. I feel like this should be possible, but is a little over my head right now. I tried using magpie as a parser, but if possible I want to do it in simpler php code. The result I am looking for would take a description "This is a cat" and insert it into a table with two fields ID term 1 This 2 is 3 a 4 cat I've been stumped on this for a couple days. Any help would be great.

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  • Ruby Exception or Error?

    - by Ell
    I have noticed that in the Ruby exception hierarchy, there are "errors" such as ArgumentError and there are "exceptions" such as SignalException. Is there a certain practise of naming exceptions? thanks in advance, ell.

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  • Colspan in IE7/8 not respected

    - by Stefan Kendall
    The DOM looks like this: <table> <tr> <td>a</td>...<td>g</td> </tr> <tr> <td colspan="3"> <table> ... </table> </td> </tr> <tr> <td></td>...<td></td> </tr> </table> Any idea why this wouldn't work in IE? I tried setting width:auto on the TD holding the inner table, and table-layout:fixed isn't viable because the tabular data is generated dynamically. What could be going wrong?

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  • Closure Tables - Is this enough data to display a tree view?

    - by James Pitt
    Here is the table I have created by testing the closure table method. | id | parentId | childId | hops | | | | | 270 | 6 | 6 | 0 | 271 | 7 | 7 | 0 | 272 | 8 | 8 | 0 | 273 | 9 | 9 | 0 | 276 | 10 | 10 | 0 | 281 | 9 | 10 | 1 | 282 | 7 | 9 | 1 | 283 | 7 | 10 | 2 | 285 | 7 | 8 | 1 | 286 | 6 | 7 | 1 | 287 | 6 | 9 | 2 | 288 | 6 | 10 | 3 | 289 | 6 | 8 | 2 | 293 | 6 | 9 | 1 | 294 | 6 | 10 | 2 I am trying to create a simple tree of this using PHP. There does not seem to be enough data to create the table. For example, when I look purely at parentId = 6: -Part 6 -Part 7 - ? - ? -Part 9 - ? - ? We know that parts 8 and 10 exists below Part 7 or 9, but not which. We know that part 10 exists at both 3 and 4 nodes deep but where? If I look at other data in the table it is possible to tell it should be: - Part 6 - Part 7 - Part 9 - Part 10 - Part 9 - Part 10 I thought one of the benefits of closure tables was there was no need for recursive queries? Could you help explain what I am doing wrong? EDIT: For clarification, this is a mapping table. There is another table called "parts" which has a column called part_id that correlates to both the parentId and childId columns in the "closure" table. The "id" column in the table above (closure) is just for the purposes of maintaining a primary key. It is not really necessary. The methods I have used to create this closure table is described in the following article: http://dirtsimple.org/2010/11/simplest-way-to-do-tree-based-queries.html EDIT2: It can have two and three hops. I will explain easier by assigning names to the items. Part 6 = Bicycle Part 7 = Gears Part 8 = Chain Part 9 = Bolt Part 10 = Nut Nut is part of Bolt. The Bolt and Nut combo exists directly within Bicycle and within Gears which is part of Bicycle. In relation to what method to use I have looked at Adjacency, Edges, Enum Paths, Closures, DAGS(networks) and the Nested Set Model. I am still trying to work out what is what, but this is an extremely complex component database where there are multiple parents and any modification to a sub-tree must propogate through the other trees. More importantly there will be insertions, deletions and tree views that I wish to avoid recursion during general use, even at the cost of database space and query time during entry.

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  • Lua class instance with nested tables

    - by Anonnobody
    Hello, Simple lua game with simple class like so: creature = class({ name = "MONSTER BADDY!", stats = { power = 10, agility = 10, endurance = 10, filters = {} }, other_things = ... }) creatureA = creature.new() creatureB = creature.new() creatureA.name = "Frank" creatureB.name = "Zappa" creatureA.stats.agility = 20 creatureB.stats.power = 12 -- blah blah blah Non table values are individual to each instance, but table values are shared among all instances and if I modify a stats.X value in one instance, all other instances see the same stats table. Q1: Is my OO implementation flawed? I tried LOOP and the same result occured, is there a fundamental flaw in my logic? Q2: How would you have each instance of creature have it's own stats table (and sub tables)? PS. I cannot flatten my class table as it's a bit more complicated than the example and other parts of the code are simplified with this nested table implementation. Thanks a bunch.

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  • Select row data as ColumnName and Value

    - by Bobcat1506
    I have a history table and I need to select the values from this table in ColumnName, ColumnValue form. I am using SQL Server 2008 and I wasn’t sure if I could use the PIVOT function to accomplish this. Below is a simplified example of what I need to accomplish: This is what I have: The table’s schema is CREATE TABLE TABLE1 (ID INT PRIMARY KEY, NAME VARCHAR(50)) The “history” table’s schema is CREATE TABLE TABLE1_HISTORY( ID INT, NAME VARCHAR(50), TYPE VARCHAR(50), TRANSACTION_ID VARCHAR(50)) Here is the data from TABLE1_HISTORY ID NAME TYPE TRANSACTION_ID 1 Joe INSERT a 1 Bill UPDATE b 1 Bill DELETE c I need to extract the data from TABLE1_HISTORY into this format: TransactionId Type ColumnName ColumnValue a INSERT ID 1 a INSERT NAME Joe b UPDATE ID 1 b UPDATE NAME Bill c DELETE ID 1 c DELETE NAME Bill Other than upgrading to Enterprise Edition and leveraging the built in change tracking functionality, what is your suggestion for accomplishing this task?

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  • iPhone: Grouped tables and navigation controller issues

    - by Jack Griffiths
    Hi there, I've set up a grouped table on my app, and pushing to new views works fine. Except for one thing. The titles and stack layout are all weird. Here's the breakdown: I have two sections in my table. When I tap on the first row in the first section, it takes me to the correct view, but the title of the new view is the name of the first row in the second section of the table. In turn, the second row in the first section's title is the second row in the second section's title. If I tap on the second row in the second section of the root view table, the navigation button goes to the second row in the first section of the table. So here's a diagram of my table: Table Section 1 Row 1 Row 2 Row 3 Table Section 2 Row A Row B Row C So if I tap on row 3, the title of the pushed view is Row C. The navigation button tells me to go back to Row 3, then eventually ending up at the root view. Here's my implementation file pushing the views: - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { //CSS if ([[arryClientSide objectAtIndex:indexPath.row] isEqual:@"CSS"]) { CSSViewController *css = [[CSSViewController alloc] initWithNibName:@"CSSViewController" bundle:nil]; [css setTitle:@"CSS"]; [self.navigationController pushViewController:css animated:YES]; } //HTML if ([[arryClientSide objectAtIndex:indexPath.row] isEqual:@"HTML"]) { HTMLViewController *html = [[HTMLViewController alloc] initWithNibName:@"HTMLViewController" bundle:nil]; [html setTitle:@"HTML"]; [self.navigationController pushViewController:html animated:YES]; } //JS if ([[arryClientSide objectAtIndex:indexPath.row] isEqual:@"JavaScript"]) { JSViewController *js = [[JSViewController alloc] initWithNibName:@"JSViewController" bundle:nil]; [js setTitle:@"JavaScript"]; [self.navigationController pushViewController:js animated:YES]; } //PHP if ([[arryServerSide objectAtIndex:indexPath.row] isEqual:@"PHP"]) { PHPViewController *php = [[PHPViewController alloc] initWithNibName:@"PHPViewController" bundle:nil]; [php setTitle:@"PHP"]; [self.navigationController pushViewController:php animated:YES]; } //SQL if ([[arryServerSide objectAtIndex:indexPath.row] isEqual:@"SQL"]) { SQLViewController *sql = [[SQLViewController alloc] initWithNibName:@"SQLViewController" bundle:nil]; [sql setTitle:@"SQL"]; [self.navigationController pushViewController:sql animated:YES]; } & the array feeding the table's data: - (void)viewDidLoad { [super viewDidLoad]; arryClientSide = [[NSArray alloc] initWithObjects:@"CSS",@"HTML",@"JavaScript",nil]; arryServerSide = [[NSArray alloc] initWithObjects:@"Objective-C", @"PHP",@"SQL",nil]; // arryResources = [[NSArray alloc] initWithObjects:@"HTML Colour Codes", @"Useful Resources", @"About",nil]; self.title = @"Select a Language"; [super viewDidLoad]; // Uncomment the following line to display an Edit button in the navigation bar for this view controller. // self.navigationItem.rightBarButtonItem = self.editButtonItem; } Any help would be greatly appreciated. Jack

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