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• Combining Data from two MySQL tables.

  - by Nick

  I'm trying to combine data from two tables in MySQL with PHP. I want to select all the data (id, title, post_by, content and created_at) from the "posts" table. Then I would like to select the comment_id COUNT from the "comments" table IF the comment_id equals the posts id. Finally, I would like to echo/print something on this order: <? echo $row->title; ?> Posted by <? echo $row->post_by; ?> on <? echo $row->created_at; ?> CST <? echo $row->content; ?> <? echo $row->comment_id; ?> comments | <a href="comment.php?id=<? echo $row->id; ?>">view/post comments</a> I'm uncertain as to how to "combine" the data from two tables. I have tried numerous things and have spent several evenings and have had no luck. Any help would be greatly appreciated!

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• Using a join with three tables when a field might be null

  - by John

  Hello, The code below works great. It combines data from two MySQL tables. I would like to modify it by pulling in some data from a third MySQL table called "comment." In the HTML table below, "title" is a field in the MySQL table "submission." Every "title" has a corresponding "submissionid" field. The field "submissionid" is also found in the "comment" MySQL table. In the HTML table below, I would like "countComments" to equal the number of times a field called "commentid" appears in the MySQL table "comment" for any given "submissionid," where the "submissionid" is the same in both the "submission" and "comment" tables, and where the "submissionid" corresponds to the "title" being used. Here's the catch: if there is no row in the MySQL table "comment" that corresponds with the "submissionid" being used for "table", I would like "countComments" to equal to zero. How can I do this? Thanks in advance, John $sqlStr = "SELECT s.loginid, s.title, s.url, s.displayurl, l.username FROM submission AS s, login AS l WHERE s.loginid = l.loginid ORDER BY s.datesubmitted DESC LIMIT 10"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"samplesrec\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="sitename1"><a href="http://www.'.$row["url"].'">'.$row["title"].'</a></td>'; echo '</tr>'; echo '<tr>'; echo '<td class="sitename2"><a href="http://www...com/sandbox/members/index.php?profile='.$row["username"].'">'.$row["username"].'</a><a href="http://www...com/sandbox/comments/index.php?submission='.$row["title"].'">'.$row["countComments"].'</a></td>'; echo '</tr>'; } echo "</table>";

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• Codeigniter return config file as array with autoload enabled

  - by Fverswijver

  So I'm using CodeIgniter to build a website and I've made it so that all my specific settings are stored in a config file that's automatically loaded. I've also built a page that loads the settings file, makes a nice little table and allows me to edit everything from that page, afterwards it saves the entire page again (I know I could've done the same with a database but I want to try it this way). My problem is that I can't seem to use this bit when autoloading of my config file is enabled, but when I disable autoloading I can't seem to manually load it, it never finds my variables. So what I'm doing here is just taking all values from the config file and putting them in a single array so I can pass this array onto my settings administration page (edit/show all settings). $this->config->load('site_settings', TRUE); $data['settings'] = $this->config->item('site_settings'); ... $this->load->view('template', $data); config/site_settings.php <?php if ( ! defined('BASEPATH')) exit('No direct script access allowed'); $config['header_img'] = './img/header/'; $config['copyright_text'] = 'Copyright Instituto Kabu'; $config['copyright_font'] = './system/fonts/motoroil.ttf'; $config['copyright_font_color'] = 'ffffff'; $config['copyright_font_size'] = '32';

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• file cretaed using exec could not be accessed immediately after creation?

  - by Holicreature

  HI I'm using exec in php to execute a command and it will create a .png file in a temp folder.. After creating that i'm trying to open that file and read contents and process them,, but i end up file could not read error.. I think the time taken by the exec to execute and create a file is the cause for the issue.. but i dont know how to fix it? i tried sleep() but it makes my script to run slow <?php error_reporting(E_ALL); extension_loaded('ffmpeg') or die('Error in loading ffmpeg'); //db connection codes $max_width = 120; $max_height = 72; $path ="/path/"; $qry="select id, input_file, output_file from videos where thumbnail='' or thumbnail is null;"; $res=mysql_query($qry); $cnt = 1; while($row = mysql_fetch_array($res,MYSQL_ASSOC)) { $outfile = $row[output_file]; $imgname = $cnt.".png"; $srcfile = "/path/".$outfile; echo "####$srcfile####"; exec("ffmpeg -i ".$srcfile." -r 1 -ss 00:00:05 -f image2 -s 120x72 ".$path.$imgname); $nname = "./temp/".$imgname; echo "nname===== $nname"; $fileo = fopen($nname,"rb"); if($fileo) { $imgData = addslashes(file_get_contents($nname)); .. ... .... } else echo "Could not open<br><br>"; $cnt = $cnt + 1: } ?>

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• How do I make a HTTP POST request to an url from within a c++ dll?

  - by tjorriemorrie

  Hi, there's an open-source application I need to use. It allows you to use a custom dll. Unfortunately, I can't code c++; i don't like it; it don't want to learn it. I do know PHP very well however, thus you can see that I'll rather do my logic within a PHP application. Thus I'm thinking about posting the data from c++/dll to a url on my localhost. (i have my local server set up, that's not the problem). I need to post a large amount of variables (thus a POST and not GET request required). The return value will only be one (int)variable, either 0, 1 or 2. So I need a c++ function that: 1) will post variables to an url. 2) Wait for, and receive the answer. The data type can be in xml, soap, json, whatever, doesn't matter. Is there anyone that can write a little c++ http function for me? pretty please? ;)

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• Appending Comment Number Anchors to Comments

  - by John

  Hello, I am using a PHP file called comments.php that has a query that enters values into a mySQL table called "comment." As the query does this, it auto-generates a field called "commentid", which is set to auto_increment in MySQL. The file also contains a loop what echoes out all comments for a given submission. It all works fine and dandy, but I want to simultaneously pull this "commentid" and turn it into a hashtag / anchor that when appended to the end of the URL makes that comment at the top of the user's browser. Someone said on another question that in order to do this one thing I should do is create an anchor on the row where the comment is being printed out. How can I do this? Thanks in advance, John The query that inserts comments into the MySQL table "comment": $query = sprintf("INSERT INTO comment VALUES (NULL, %d, %d, '%s', NULL)", $uid, $subid, $comment); mysql_query($query) or die(mysql_error()); The fields in the table "comment": commentid loginid submissionid comment datecommented The row in a loop where the comments are echoed out: echo '<td rowspan="3" class="commentname1">'.stripslashes($row["comment"]).'</td>';

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• Getting list of Facebook friends with latest API

  - by Eric

  I'm using the most recent version of the Facebook SDK (which lets to connect to something called the 'graph API' though I'm not sure). I've adapted Facebook's example code to let me connect to Facebook and that works... but I can't get a list of my friends. $friends = $facebook->api('friends.get'); This produces the error message: "Fatal error: Uncaught OAuthException: (#803) Some of the aliases you requested do not exist: friends.get thrown in /mycode/facebook.php on line 543" No clue why that is or what that means. Can someone tell me the right syntax (for the latest Facebook API) to get a list of friends? (I tried "$friends = $facebook-api-friends_get();" and get a different error, "Fatal error: Call to a member function friends_get() on a non-object in /mycode/example.php on line 129".) I can confirm that BEFORE this point in my code, things are fine: I'm connected to Facebook with a valid session and I can get my info and dump it to the screen just... i.e. this code executes perfectly before the failed friends.get call: $session = $facebook->getSession(); if ($session) { $uid = $facebook->getUser(); $me = $facebook->api('/me'); } print_r($me);

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• Send file FTP over SSL with custom port number

  - by JM4

  I have asked the question before but in a different manner. I am trying taking form data, compiling into a temporary CSV file and trying to send over to a client via FTP over SSL (this is the only route I am interested in hearing solutions for unless there is a workaround to doing this, I cannot make changes). I have tried the following: ftp_connect - nothing happens, the page just times out ftp_ssl_connect - nothing happens, the page just times out curl library - same thing, given URL it also gives error. I am given the following information: FTPS Server IP Address TCP Port (1234) Username Password Data Directory to dump file FTP Mode: Passive very, very basic code (which I believe should initiate a connection at minimum): Code: <?php $ftp_server = "00.000.00.000"; //masked for security $ftp_port = "1234"; // masked but not 990 $ftp_user_name = "username"; $ftp_user_pass = "password"; // set up basic ssl connection $conn_id = ftp_ssl_connect($ftp_server, $ftp_port, "20"); // login with username and password $login_result = ftp_login($conn_id, $ftp_user_name, $ftp_user_pass); echo ftp_pwd($conn_id); // / echo "hello"; // close the ssl connection ftp_close($conn_id); ?> When I run this over a SmartFTP client, everything works just fine. I just can't get it to work using PHP (which is a necessity). Has anybody had success doing this in the past? I would be very interested to hear your approach.

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• Error loading il8n console in CakePHP 1.3

  - by inkedmn

  I'm trying to generate the .po files for the site I'm working with. When I run this command from within the console directory: Warning: strtotime(): It is not safe to rely on the system's timezone settings. You are *required* to use the date.timezone setting or the date_default_timezone_set() function. In case you used any of those methods and you are still getting this warning, you most likely misspelled the timezone identifier. We selected 'America/Los_Angeles' for 'PDT/-7.0/DST' instead in /Users/bkelly/Development/[redacted]/www/trunk/about/trunk/cake/libs/cache.php on line 570 Warning: strtotime(): It is not safe to rely on the system's timezone settings. You are *required* to use the date.timezone setting or the date_default_timezone_set() function. In case you used any of those methods and you are still getting this warning, you most likely misspelled the timezone identifier. We selected 'America/Los_Angeles' for 'PDT/-7.0/DST' instead in /Users/bkelly/Development/[redacted]/www/trunk/about/trunk/cake/libs/cache.php on line 570 Error: Class Il8nShell could not be loaded. This also happens if I issue ./cake il8n help . The bake console seems to load fine (no errors, takes me to the expected menu). I'm running CakePHP 1.3.0 under Mac OSX 10.6 (using MAMP). Cake appears to be functioning normally otherwise. Thanks!

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• If statement doesn't work? do download without filed name and email

  - by user1833871

  I've created some if / else statements to get a download when a user hit click jf he fields name and email but doesn"t work for my site http://my-easy-woodworking-projects.com because it is do download without field name and email contact.php is <?php $field_name = $_POST['cf_name']; $field_email = $_POST['cf_email']; $field_message = $_POST['cf_message']; $mail_to = '[email protected]'; $subject = 'Message from a site visitor '.$field_name; $body_message = 'From: '.$field_name."\n"; $body_message .= 'E-mail: '.$field_email."\n"; $body_message .= 'Message: '.$field_message; $headers = 'From: '.$field_email."\r\n"; $headers .= 'Reply-To: '.$field_email."\r\n"; $mail_status = mail($mail_to, $subject, $body_message, $headers); if ($mail_status) { echo <script>\n" echo "var str = \"download\"; \n"" echo "document.write(str.link("http://www.myshedplans.com/12BY8SHED.pdf"));\n" echo "</script>\n" } echo else { echo <script language="javascript" type="text/javascript"> echo // Print a message echo alert('Message failed. Please, send an email to [email protected]'); echo // Redirect to some page of the site. You can also specify full URL, e.g. http://template-help.com window.location = 'contact_page.html'; echo </script> }?>

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• How to add an array value to the middle of an associative array?

  - by Citizen

  Lets say I have this array: $array = array('a'=>1,'z'=>2,'d'=>4); Later in the script, I want to add the value 'c'=>3 before 'z'. How can I do this? EDIT: Yes, the order is important. When I run a foreach() through the array, I do NOT want this newly added value added to the end of the array. I am getting this array from a mysql_fetch_assoc() EDIT 2: The keys I used above are placeholders. Using ksort() will not achieve what I want. EDIT 3: http://www.php.net/manual/en/function.array-splice.php#88896 accomplishes what I'm looking for but I'm looking for something simpler. EDIT 4: Thanks for the downvotes. I gave feedback to your answers and you couldn't help, so you downvoted and requested to close the question because you didn't know the answer. Thanks. EDIT 5: Take a sample db table with about 30 columns. I get this data using mysql_fetch_assoc(). In this new array, after column 'pizza' and 'drink', I want to add a new column 'full_dinner' that combines the values of 'pizza' and 'drink' so that when I run a foreach() on the said array, 'full_dinner' comes directly after 'drink'

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• i read that for RESTful websites. it is not good to use $_SESSION. Why is it not good? how then do i

  - by keisimone

  I read that it is not good to use $_SESSION. http://www.recessframework.org/page/towards-restful-php-5-basic-tips I am creating a WEBSITE, not web service in PHP. and i am trying to make it more RESTful. at least in spirit. right now i am rewriting all the action to use Form tags POST and add in a hidden value called _method which would be "delete" for deleting action and "put" for updating action. however, i am not sure why it is recommended NOT to use $_SESSION. i would like to know why and what can i do to improve. To allow easy authorization checking, what i did was to after logging in the user, the username is stored in the $_SESSION. Everytime the user navigates to a page, the page would check if the username is stored inside $_SESSION and then based on the $_SESSION retrieves all the info including privileges from the database and then evaluates the authorization to access the page based on the info retrieved. Is the way I am implementing bad? not RESTful? how do i improve performance and security? Thank you.

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• I can't insert data into my database

  - by Ken

  I don't know why, but my data doesn't go into my database 'users' with the table 'data'. <html> <body> <?php date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "g00dfor@boy"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db(`users`, $con) or die(mysql_error()); mysql_query(INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password')) or die(mysql_error()); mysql_close($con) echo("Thank you for registering!"); ?> </body> </html> All i get is a blank page.

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• How do I use curl to display a table on a page?

  - by user272899

  I want to use curl to retrieve a table from an external page. So far my code retrieves all data from the page. I have read that using preg_match or preg_replace is the way to go about it. This is my code so far: <?php $ch = curl_init() or die(curl_error()); curl_setopt($ch, CURLOPT_URL,"http://www.megaupload.com/?d=XE30L1GA&w=631&h=392"); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); $data1=curl_exec($ch) or die(curl_error()); echo "<font color=black face=verdana size=3>".$data1."</font>"; echo curl_error($ch); curl_close($ch); ?> This is the data I want to retrieve from the page: <FORM method="POST" id="captchaform"> <INPUT type="hidden" name="captchacode" value="1a589e0a53c54f937eb8"> <INPUT type="hidden" name="megavar" value="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"> <TR> <TD>Enter this </TD> <TD width="100" align="center" height="40"><img src="http://wwwq32.megaupload.com/gencap.php?23243f17c2404dd4.gif" border="0" alt=""></TD> <TD> here:</TD> <TD><input type="text" name="captcha" id="captchafield" maxlength="4" style="border:solid 1px; border-color:#C4C4C4; background-color:#F9F9F9; width:50px; height:25px;"></TD> </TR> </FORM>

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• Generated images fail to load in browser

  - by notJim

  I've got a page on a webapp that has about 13 images that are generated by my application, which is written in the Kohana PHP framework. The images are actually graphs. They are cached so they are only generated once, but the first time the user visits the page, and the images all have to be generated, about half of the images don't load in the browser. Once the page has been requested once and images are cached, they all load successfully. Doing some ad-hoc testing, if I load an individual image in the browser, it takes from 450-700 ms to load with an empty cache (I checked this using Google Chrome's resource tracking feature). For reference, it takes around 90-150 ms to load a cached image. Even if the image cache is empty, I have the data and some of the application's startup tasks cached, so that after the first request, none of that data needs to be fetched. My questions are: Why are the images failing to load? It seems like the browser just decides not to download the image after a certain point, rather than waiting for them all to finish loading. What can I do to get them to load the first time, with an empty cache? Obviously one option is to decrease the load times, and I could figure out how to do that by profiling the app, but are there other options? As I mentioned, the app is in the Kohana PHP framework, and it's running on Apache. As an aside, I've solved this problem for now by fetching the page as soon as the data is available (it comes from a batch process), so that the images are always cached by the time the user sees them. That feels like a kludgey solution to me, though, and I'm curious about what's actually going on.

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• Need help with jQuery/AJAX call in Safari/Mac

  - by protohominid

  I've got something that works perfectly in FF and MSIE but it's not working properly in Safari. It's a form with selects that get updated via AJAX/jQuery from a MySQL DB. In Safari, when you select the first item, it correctly loads the options for the next select menu; however, when you choose one of those (which loads new options in a subsequent select menu), the whole form resets and is broken from that point on. Does anyone know of a Safari bug that would cause this? Here's the JS: $(document).ready(function(){ $("#searchForm select").change(updateSearchForm); }); function updateSearchForm() { $.ajax({ url: '/elements/search_form.php?ajax=true', data: $('#searchForm').serialize(), error:function(xhr,err){ alert("readyState: "+xhr.readyState+"\nstatus: "+xhr.status); alert("responseText: "+xhr.responseText); }, success: function(data) { $("#searchForm").html(data); $("#searchForm select").change(updateSearchForm); } }); } I can post the relevant PHP/HTML for the form, but it's lengthy. I'm relatively new to JS so I'm not sure where to start debugging this... TIA

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• What's causing this permission's error and how can I work around it?

  - by Scott B

  Warning: move_uploaded_file(/home/site/public_html/wp-content/themes/mytheme/upgrader.zip) [function.move-uploaded-file]: failed to open stream: Permission denied in /home/site/public_html/wp-content/themes/mytheme/uploader.php on line 79 Warning: move_uploaded_file() [function.move-uploaded-file]: Unable to move '/tmp/phptempfile' to '/home/site/public_html/wp-content/themes/mytheme/upgrader.zip' in /home/site/public_html/wp-content/themes/mytheme/uploader.php on line 79 There was a problem. Sorry! Code is below for that line... // permission settings for newly created folders $chmod = 0755; // Ensures that the correct file was chosen $accepted_types = array('application/zip', 'application/x-zip-compressed', 'multipart/x-zip', 'application/s-compressed'); foreach($accepted_types as $mime_type) { if($mime_type == $type) { $okay = true; break; } } $okay = strtolower($name[1]) == 'zip' ? true: false; if(!$okay) { die("This upgrader requires a zip file. Please make sure your file is a valid zip file with a .zip extension"); } //mkdir($target); $saved_file_location = $target . $filename; //Next line is 79 if(move_uploaded_file($source, $saved_file_location)) { openZip($saved_file_location); } else { die("There was a problem. Sorry!"); }

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• Retrieving ids from MySQL query

  - by Matt Maclennan

  I am having trouble accessing the "model_id" and "brand_id" from the foreach loop that I am using. They are the right field names, because I have echoed them successfully, and I have also "var_dumped" the array, and the IDs are there. It is just a case of implementing the relevant links on each list section. Below is the code I have. <? $output = mysqli_query("SELECT * FROM bikes, bikeTypes WHERE bikes.model_id = bikeTypes.model_id"); $result = array(); while($row = mysqli_fetch_array($output)) { $result[$row['model']][] = $row; } foreach ($result as $category => $values) { echo "<li><a href='test.php?id=" . $row['model_id'] . "'>".$category.'</a><ul>'; foreach ($values as $value) { echo "<li><a href='details.php?id=" . $row['brand_id'] . "'>" . $value['bikeName'] . "</a></li>"; } echo '</ul>'; echo '</li>'; } ?>

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• Specifying SOAP Headers for a Zend_Soap Service

  - by Stephen

  I have a generally straight forward web service that I've written (converting code to ZF from a Java implementation of the same service and trying to maintain the same wsdl structure as much as possible). The service loads a PHP class, rather than individual functions. The PHP class contains three different functions within it. Everything seems to be working just fine, except that I can't seem to figure out how to specify that a given function parameter should be passed as a SOAP header. I've not seen any mention of SOAP headers in the Server context, only how to pass header parameters with a client to a server. In addition to the standard parameters for the function that would be sent in the SOAP body and detailed in the docblock, I would like to specify two parameters (a username and password) that would be sent in a SOAP header. I have to assume this is possible, but haven't been able to find anything online, nor have I had any responses to a similar post on Zend's forum. Is there something that can be added in the docblock area to specify a parameter as a header (maybe in a similar fashion to using WebParam?)? Any suggestions/examples on how to get this accomplished would be greatly appreciated!

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• append to an xml file with php

  - by ralph

  test http://chuckjonescenter.org/blog_entry.php?blog_id=

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• Is this XML file correct for RSS feeding?

  - by Hermet

  Hi guys I am generating a XML-RSS type file from PHP. The output for example is like this <?xml version="1.0" encoding="iso-8859-1"?> <rss version="2.0"> <channel> <title>Mi web mola</title> <link>http://www.dominio.com/blog.php</link> <language>es-ES</language> <description>Mallas y eso</description> <generator>Autor</generator> <item> <title>Articulo de prueba</title> <link>http://www.midominio.com/2342</link> <pubDate>14/06/2010</pubDate> <description><![CDATA[Descripcion de prueba bla bla bla]]></description> <content:encoded><![CDATA[Contenido prueba]]></content:encoded> </item> </channel> </rss> ... and all I can see in the Firefox preview is the title and the description of the blog, not the items, but in the source it appears correctly, so I've thought it must be a parse error or something like that.. What could be wrong? Again, excuse me for my bad english, and thank you very much.

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• How can I debug PEAR auth?

  - by croceldon

  I have a directory on my site that I've implemented PEAR's Auth to run my authentication. It is working great. However, I've tried to make a copy of my site (it's going to be translated to a different language), and on this new site, the Auth process doesn't seem to be working correctly. I can login properly, but every time I try to go to a different page in the same directory, and use Auth to authorize, it forces me to login again. Here's my logic: $auth_options = array( 'dsn' => mysql://user:password@server/db', 'table' => 'users', 'usernamecol' => 'username', 'passwordcol' => 'password', 'db_fields' => '*' ); $auth = new Auth("DB", $auth_options, "login_function"); $auth->setFailedLoginCallback('bad_login'); $auth->start(); if (!$auth->checkAuth()) { die('cannot succeed in checkAuth') exit; } else { include("nocache.php"); } This is part of a file that's included in every php page I that I desire to require authentication. I can login properly once, but whenever I then try to go to a different page that requires authentication, it makes me login again (and I see the 'cannot succeed' die message at the bottom of the page). Again, this solution works fine on my original site, I copied all the files, and only changed the db server/password - it still doesn't work. And I'm using the same webhost for both. What am I doing wrong here? Or how can I debug this further?

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• Join with Three Tables

  - by John

  Hello, In MySQL, I am using the following three tables (their fields are listed after their titles): comment: commentid loginid submissionid comment datecommented login: loginid username password email actcode disabled activated created points submission: submissionid loginid title url displayurl datesubmitted I would like to display "datecommented" and "comment" for a given "username," where "username" equals a variable called $profile. I would also like to make the "comment" a hyperlink to http://www...com/.../comments/index.php?submission='.$rowc["title"].'&submissionid='.$rowc["submissionid"].'&url='.$rowc["url"].'&countcomments='.$rowc["countComments"].'&submittor='.$rowc["username"].'&submissiondate='.$rowc["datesubmitted"].'&dispurl='.$rowc["displayurl"].' where countComments equals COUNT(c.commentid) and $rowc is part of the query listed below. I tried using the code below to do what I want, but it didn't work. How could I change it to make it do what I want? Thanks in advance, John $sqlStrc = "SELECT s.loginid ,s.title ,s.url ,s.displayurl ,s.datesubmitted ,l.username ,l.loginid ,s.title ,s.submissionid ,c.comment ,c.datecommented ,COUNT(c.commentid) countComments FROM submission s INNER JOIN login l ON s.loginid = l.loginid LEFT OUTER JOIN comment c ON c.loginid = l.loginid WHERE l.username = '$profile' GROUP BY c.loginid ORDER BY s.datecommented DESC LIMIT 10"; $resultc = mysql_query($sqlStrc); $arrc = array(); echo "<table class=\"samplesrec1c\">"; while ($rowc = mysql_fetch_array($resultc)) { $dtc = new DateTime($rowc["datecommented"], $tzFromc); $dtc->setTimezone($tzToc); echo '<tr>'; echo '<td class="sitename3c">'.$dtc->format('F j, Y &\nb\sp &\nb\sp g:i a').'</a></td>'; echo '<td class="sitename1c"><a href="http://www...com/.../comments/index.php?submission='.$rowc["title"].'&submissionid='.$rowc["submissionid"].'&url='.$rowc["url"].'&countcomments='.$rowc["countComments"].'&submittor='.$rowc["username"].'&submissiondate='.$rowc["datesubmitted"].'&dispurl='.$rowc["displayurl"].'">'.stripslashes($rowc["comment"]).'</a></td>'; echo '</tr>'; } echo "</table>";

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• Database class is not correctly connecting to my database.

  - by blerh

  I'm just venturing into the world of OOP so forgive me if this is a n00bish question. This is what I have on index.php: $dbObj = new Database(); $rsObj = new RS($dbObj); This is the Database class: class Database { private $dbHost; private $dbUser; private $dbPasswd; private $dbName; private $sqlCount; function __construct() { $this->dbHost = 'localhost'; $this->dbUser = 'root'; $this->dbPasswd = ''; $this->dbName = 'whatever'; $this->sqlCount = 0; } function connect() { $this->link = mysql_connect($this->db_host, $this->db_user, $this->db_passwd); if(!$this->link) $this->error(mysql_error()); $this->selection = mysql_select_db($this->db_name, $this->link); if(!$this->selection) $this->error(mysql_error()); } } I've shortened it to just the connect() method to simplify things. This is the RS class: class RS { private $username; private $password; function __construct($dbObj) { // We need to get an account from the db $dbObj->connect(); } } As you can probably see, I need to access and use the database class in my RS class. But I get this error when I load the page: Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'ODBC'@'localhost' (using password: NO) in C:\xampp\htdocs\includes\database.class.php on line 22 The thing is I have NO idea where it got the idea that it needs to use ODBC as a user... I've read up on doing this stuff and from what I can gather I am doing it correctly. Could anyone lend me a hand? Thank you.

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• Bing search API and Azure

  - by Gapton

  I am trying to programatically perform a search on Microsoft Bing search engine. Here is my understanding: There was a Bing Search API 2.0 , which will be replaced soon (1st Aug 2012) The new API is known as Windows Azure Marketplace. You use different URL for the two. In the old API (Bing Search API 2.0), you specify a key (Application ID) in the URL, and such key will be used to authenticate the request. As long as you have the key as a parameter in the URL, you can obtain the results. In the new API (Windows Azure Marketplace), you do NOT include the key (Account Key) in the URL. Instead, you put in a query URL, then the server will ask for your credentials. When using a browser, there will be a pop-up asking for a/c name and password. Instruction was to leave the account name blank and insert your key in the password field. Okay, I have done all that and I can see a JSON-formatted results of my search on my browser page. How do I do this programmatically in PHP? I tried searching for the documentation and sample code from Microsoft MSDN library, but I was either searching in the wrong place, or there are extremely limited resources in there. Would anyone be able to tell me how do you do the "enter the key in the password field in the pop-up" part in PHP please? Thanks alot in advance.

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