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  • j2me or android file upload to jsp

    - by user313613
    hi i new to mobile development i like to upload the file from blackberry and android how to develop the mobile side to this jsp page. please do reply me thanks here i mention the jsp file from roseindia.net. <%@ page import="java.io.*" % <% //to get the content type information from JSP Request Header String contentType = request.getContentType(); //here we are checking the content type is not equal to Null and as well as the passed data from mulitpart/form-data is greater than or equal to 0 if ((contentType != null) && (contentType.indexOf("multipart/form-data") = 0)) { DataInputStream in = new DataInputStream(request. getInputStream()); //we are taking the length of Content type data int formDataLength = request.getContentLength(); byte dataBytes[] = new byte[formDataLength]; int byteRead = 0; int totalBytesRead = 0; //this loop converting the uploaded file into byte code while (totalBytesRead < formDataLength) { byteRead = in.read(dataBytes, totalBytesRead, formDataLength); totalBytesRead += byteRead; } String file = new String(dataBytes); //for saving the file name String saveFile = file.substring(file.indexOf("filename=\"") + 10); saveFile = saveFile.substring(0, saveFile.indexOf("\n")); saveFile = saveFile.substring(saveFile.lastIndexOf("\\") + 1,saveFile.indexOf("\"")); int lastIndex = contentType.lastIndexOf("="); String boundary = contentType.substring(lastIndex + 1, contentType.length()); int pos; //extracting the index of file pos = file.indexOf("filename=\""); pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; int boundaryLocation = file.indexOf(boundary, pos) - 4; int startPos = ((file.substring(0, pos)).getBytes()).length; int endPos = ((file.substring(0, boundaryLocation)) .getBytes()).length; // creating a new file with the same name and writing the content in new file FileOutputStream fileOut = new FileOutputStream(saveFile); fileOut.write(dataBytes, startPos, (endPos - startPos)); fileOut.flush(); fileOut.close(); %><Br><table border="2"><tr><td><b>You have successfully upload the file by the name of: <% out.println(saveFile); % <% } %

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  • Getting maximum value of float in SQL programatically

    - by Axarydax
    Is there an method for programatically (in T-SQL) retrieving the maximum (and minimum) value of a datatype? That it would act like float.MaxValue in C#. I would like to use it in some selection when the parameter does not equal any actual values in the database, so I would use something like declare @min float declare @max float /*fill @min and @max, can be null if undefined*/ select * from foo where bar between isnull(@min,0 ), isnull(@max,max(float)/*magic*/) Thanks

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  • How do you make a wrapped div fill the window horizontally?

    - by Alex Parkinson
    I have a div which is contained by another 960px-wide centered div. I'm adding a background to the inner div which should expand all the way to the window's edges horizontally, essentially escaping the boundaries of its container. If I apply a large negative margin and equal amount of padding, this works on the left side, but the right side causes a scroll bar to appear. Does anyone know how I can achieve this without causing scroll bars?

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  • Big Oh Notation - formal definition.

    - by aloh
    I'm reading a textbook right now for my Java III class. We're reading about Big-Oh and I'm a little confused by its formal definition. Formal Definition: "A function f(n) is of order at most g(n) - that is, f(n) = O(g(n)) - if a positive real number c and positive integer N exist such that f(n) <= c g(n) for all n = N. That is, c g(n) is an upper bound on f(n) when n is sufficiently large." Ok, that makes sense. But hold on, keep reading...the book gave me this example: "In segment 9.14, we said that an algorithm that uses 5n + 3 operations is O(n). We now can show that 5n + 3 = O(n) by using the formal definition of Big Oh. When n = 3, 5n + 3 <= 5n + n = 6n. Thus, if we let f(n) = 5n + 3, g(n) = n, c = 6, N = 3, we have shown that f(n) <= 6 g(n) for n = 3, or 5n + 3 = O(n). That is, if an algorithm requires time directly proportional to 5n + 3, it is O(n)." Ok, this kind of makes sense to me. They're saying that if n = 3 or greater, 5n + 3 takes less time than if n was less than 3 - thus 5n + n = 6n - right? Makes sense, since if n was 2, 5n + 3 = 13 while 6n = 12 but when n is 3 or greater 5n + 3 will always be less than or equal to 6n. Here's where I get confused. They give me another example: Example 2: "Let's show that 4n^2 + 50n - 10 = O(n^2). It is easy to see that: 4n^2 + 50n - 10 <= 4n^2 + 50n for any n. Since 50n <= 50n^2 for n = 50, 4n^2 + 50n - 10 <= 4n^2 + 50n^2 = 54n^2 for n = 50. Thus, with c = 54 and N = 50, we have shown that 4n^2 + 50n - 10 = O(n^2)." This statement doesn't make sense: 50n <= 50n^2 for n = 50. Isn't any n going to make the 50n less than 50n^2? Not just greater than or equal to 50? Why did they even mention that 50n <= 50n^2? What does that have to do with the problem? Also, 4n^2 + 50n - 10 <= 4n^2 + 50n^2 = 54n^2 for n = 50 is going to be true no matter what n is. And how in the world does picking numbers show that f(n) = O(g(n))? Please help me understand! :(

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  • How to build a tree from a list of items and their children recursively in php?

    - by k1lljoy
    I have a list of items stored in the DB, simplified schema is like this: id, parent, name I need to generate a tree structure (in a form of a multi-dimensional array) that can be infinite levels deep. Top level items would have parent = 0. Next level down would have parent equal to the the id of the parent item, fairly straight forward. What would be the best way to do this, while consuming as little resources as possible?

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  • Adding LambaExpression to an instance of IQueryable

    - by Paul Knopf
    ParameterExpression parameter = Expression.Parameter(typeof(Product), "x"); MemberExpression Left = Expression.MakeMemberAccess(parameter, typeof(Product).GetProperty("Name")); ConstantExpression Right = Expression.Constant(value, typeof(String)); BinaryExpression expression = Expression.Equal(Left, Right); LambdaExpression lambada = Expression.Lambda<Func<Product, bool>>(expression, parameter); Now how do I add this lambada to an instance of an IQuerybale, lets say _query _query.Where(lambada.Compile());?

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  • mySQL query not returning correct results!

    - by Pete Herbert Penito
    Hi! This query that I have is returning therapists whose 'therapistTable.activated' is equal to false as well as those set to true! so it's basically selecting all of the db, any advice would be appreciated! ` $query = "SELECT therapistTable.* FROM therapistTable WHERE therapistTable.activated = 'true' ORDER BY therapistTable.distance "; `

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  • Simple prolog program. Getting error: >/2: Arguments are not sufficiently instantiated

    - by user1279812
    I made a prolog program posAt(List1,P,List2) that tests whether the element at position P of List1 and List2 are equal: posAt([X|Z],1,[Y|W]) :- X=Y. posAt([Z|X],K,[W|Y]) :- K1, Kr is K - 1, posAt(X,Kr,Y). When testing: ?- posAt([1,2,3],X,[a,2,b]). I expected an output of X=2 but instead I got the following error: ERROR: /2: Arguments are not sufficiently instantiated Why am I getting this error?

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  • Help with this JET Sql Query [SOLVED]

    - by yae
    Hi: I need help to do this query select. for example I have these fields: idInvoice date amount Depending of the date I need multiply the field "amount" for x number or other one. For example, if the date is less 01/01/2010 to multiply for 20 . But if it is major or equal to multiply for 35 Select idInvoice, date, amount, amount * varNumber from invoices

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  • VB.NET SqlException Was Unhandled

    - by Daniel
    I am trying some SQL code but I get an error when I try this code. Main.database.ExecuteCommand("UPDATE Contacts SET first_name='" + c.first_name + _ "', middle='" + c.middle + _ "', last_name='" + c.last_name + _ "', age='" + c.age + _ "', mobile_phone='" + c.mobile_phone + _ "', home_phone='" + c.home_phone + _ "', work_phone='" + c.work_phone + _ "', home_street='" + c.home_street + _ "', home_city='" + c.home_city + _ "', home_state='" + c.home_state + _ "', home_zip='" + c.home_zip + _ "', work_street='" + c.work_street + _ "', work_city='" + c.work_city + _ "', work_state='" + c.work_state + _ "', work_zip='" + c.work_zip + _ "', home_www='" + c.home_www + _ "', work_www='" + c.work_www + _ "', home_email='" + c.home_email + _ "', work_email='" + c.work_email + _ "' WHERE first_name='" + c.first_name + _ "' AND last_name='" + c.last_name + "'") I get the following error Sql Exception was unhandled The data types text and varchar are incompatible in the equal to operator.

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  • A posterframe created with PHP won't work.

    - by Peter
    I am using PHP to create a poster frame for the Quicktime plugin, and all I am getting is Quicktime's broken plugin icon. I am positive that the URL is correct. (a copy-paste to the URL box works) The HTTP content-type header is equal to "image/jpeg". Does anyone have any ideas?

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  • iPhone - Track three touches

    - by Striker
    Suppose you have three points of contact on the iPhone screen and one of those touches moves... The touchesMoved method will be invoked and the [[event touchesForView:self] count] will be equal to '3' because there are three touches for the event, but how can you distinguish between the touches? For example - find out whether it was the first, second, or third touch which moved? Thanks.

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  • When is `x IS NOT NULL` not the same as `NOT(x IS NULL)`

    - by Mark Hurd
    For what x is The expression x IS NOT NULL is not equal to NOT(x IS NULL), as is the case in 2VL (quote from this answer, which is quoting Fabian Pascal Practical Issues in Database Management - A Reference for the Thinking Practitioner -- near the end of that answer) My guess is when x IS NULL is NULL, but I cannot guess when that would be (i.e. I haven't checked the SQL standard).

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  • Replace always replacing null values

    - by Mike
    Why does left(FIELD, replace(nullif(charindex('-', FIELD), 0), null, len(FIELD))) always return null? The idea behind the query is that if charindex() returns 0, then convert the results into null, then convert the null into the length of the field. So if '-' does not exist, show the whole string. For some reason it makes every row equal null. Thank you.

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  • Air/Flex concatenating a variable with a property

    - by Deyon
    I have three text boxes on the stage id=red, blue, green same as the keys in my cars Object/Array public function carsToBox():void { var cars:Object={red:"300zx",blue:"Skyline",green:"Supra"}; for(var tempObj:String in cars) { tempObj.text= cars[tempObj];//this trows errors } } So I'm thinking "tempObj.text" would equal red.text but I can't stick "tempObj" with ".text" is there a way this can be done?

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