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  • After mysql_query, no result output

    - by Jerry
    I have a simple mysql_query() update command to update mysql. When a user submits my form, it will jump to an update page to update the data. The problem is that there's supposed to be some data shown after the update, but it comes out blank. My form <form id="form1" method="POST" action="scheduleUpdate.php" > <select name=std1> <option>AA</option> <option>BB</option> <option>CC</option> </select> <select name=std2> <option>DD</option> <option>EE</option> <option>FF</option> </select> .......//more drop down menu but the name is std3..std4..etc... ....... </form> scheduleUpdate.php //$i is the value posted from my main app to tell me how many std we have for($k=0;$k<$i;$k++){ $std=$_POST['std'.$k]; //if i remove the updateQuery, the html will output.I know the query is the problem but i //couldn't fix it.. $updateQuery=mysql_query("UPDATE board SET student='$std' WHERE badStudent='$std' or goodStudent='$std'",$connection); //no output below this line at all if($updateQuery){ DIE('mysql Error:'+mysql_error()); } } // I have bunch of HTML here....but no output at all!!!! MySQL will be updated after I hit submit, but it doesn't shown any HTML.

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  • Assistance with CC Processing script

    - by JM4
    I am currently implementing a credit card processing script, most as provided by the merchant gateway. The code calls functions within a class and returns a string based on the response. The end php code I am using (details removed of course) with example information is: <?php $gw = new gwapi; $gw->setLogin("username", "password"); $gw->setBilling("John","Smith","Acme, Inc.","888","Suite 200", "Beverly Hills", "CA","77777","US","555-555-5555","555-555-5556","[email protected]", "www.example.com"); // "CA","90210","US","[email protected]"); $gw->setOrder("1234","Big Order",1, 2, "PO1234","65.192.14.10"); $r = $gw->doSale("1.00","4111111111111111","1010"); print $gw->responses['responsetext']; ?> where setlogin allows me to login, setbilling takes the sample consumer information, set order takes the order id and description, dosale takes the amount charged, cc number and exp date. when all the variables are sent validated then sent off for processing, a string is returned in the following format: response=1&responsetext=SUCCESS&authcode=123456&transactionid=23456&avsresponse=M&orderid=&type=sale&response_code=100 where: response = transaction approved or declined response text = textual response authcode = transaction authorization code transactionid = payment gateway tran id avsresponse = avs response code orderid = original order id passed in tran request response_code = numeric mapping of processor response I am trying to solve for the following: How do I take the data which is passed back and display it appropriately on the page - If the transaction failed or AVS code doesnt match my liking or something is wrong, an error is displayed to the consumer; if the transaction processed, they are taken to a completion page and the transaction id is sent in SESSION as output to the consumer If the response_code value matches a table of values, certain actions are taken, i.e. if code =100, take to success page, if code = 300 print specific error on original page to customer, etc.

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  • Add values to an array after isset()

    - by user1656692
    I'm trying to add elements to an array after subsequent trials, but so far only one value is being added to the array. I've Googled and searched stackoverflow, and I seem to be getting only half the picture unless if I'm implementing it wrong. There are about 40 files, which will be needed to be submited one after another, and then a value from each trial is stored in the database. So far, this is what I've done. $_SESSION['task2'] = array(); //Submit Task 1 if (isset($_POST['submit_task_01'])) { $trial1_ac_sec = cleanInput($_POST['clockInputTask_01ac']); $trial1_est_sec = cleanInput($_POST['clockInputTask_01']); $trial1_ac = round(($trial1_ac_sec * 42.67), 2); $trial1_est = round(($trial1_est_sec * 42.67), 2); $trial1_judgErr = $trial1_ac - $trial1_est; $trial_1error = round($trial1_judgErr, 2); array_push($_SESSION['task2'],$trial_1error); header("location: Trial_2.php"); } //Submit Task2 if (isset($_POST['submit_task_02'])) { $trial2_ac_sec = cleanInput($_POST['clockInputTask_02ac']); $trial2_est_sec = cleanInput($_POST['clockInputTask_02']); $trial2_ac = round(($trial2_ac_sec * 42.67), 2); $trial2_est = round(($trial2_est_sec * 42.67), 2); $trial2_judgErr = $trial2_ac - $trial2_est; $trial_2error = round($trial2_judgErr, 2); array_push($_SESSION['task2'],$trial_2error); header("location: newEmptyPHPWebPage.php"); } ... and so on.. up until 40 I'm just wondering what am I doing wrong, I know that each time isset() will reload the page, and the previous data won't be available, so in that sense I thought I'd create an array for sessions and then push data in the session, however that doesn't seem to work. If anyone has any ideas on what I can do, I'll greatly appreciate it. Thank You.

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  • Create 2nd tables and add data

    - by Tyler Matema
    I have this task from school, and I am confuse and lost on how I got to do this. So basically I have to create 2 tables to the database but I have to created from php. I have created the first table, but not the second one for some reason. And then, I have to populate first and second tables with 10 and 20 sample records respectively, populate, does it mean like adding more fake users? if so is it like the code shown below? *I got error on the populating second part as well Thank you so much for the help. <?php $host = "host"; $user = "me"; $pswd = "password"; $dbnm = "db"; $conn = @mysqli_connect($host, $user, $pswd, $dbnm); if (!$conn) die ("<p>Couldn't connect to the server!<p>"); $selectData = @mysqli_select_db ($conn, $dbnm); if(!$selectData) { die ("<p>Database Not Selected</p>"); } //1st table $sql = "CREATE TABLE IF NOT EXISTS `friends` ( `friend_id` INT NOT NULL auto_increment, `friend_email` VARCHAR(20) NOT NULL, `password` VARCHAR(20) NOT NULL, `profile_name` VARCHAR(30) NOT NULL, `date_started` DATE NOT NULL, `num_of_friends` INT unsigned, PRIMARY KEY (`friend_id`) )"; //2nd table $sqlMyfriends = "CREATE TABLE `myfriends` ( `friend_id1` INT NOT NULL, `friend_id2` INT NOT NULL, )"; $query_result1 = @mysqli_query($conn, $sql); $query_result2 = @mysqli_query($conn, $sqlMyfriends); //populating 1st table $sqlSt3="INSERT INTO friends (friend_id, friend_email, password, profile_name, date_started, num_of_friends) VALUES('NULL','[email protected]','123','abc','2012-10-25', 5)"; $queryResult3 = @mysqli_query($dbConnect,$sqlSt3) //populating 2nd table $sqlSt13="INSERT INTO myfriends VALUES(1,2)"; $queryResult13=@mysqli_query($dbConnect,$sqlSt13); mysqli_close($conn); ?>

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  • Joomla get plugin id

    - by Christian Sciberras
    I wrote a Joomla plugin which will eventually load a library. The path to library is a plugin parameter, as such when the path is incorrect, a message pops up in the backend, together with a link to edit the plugin parameters: /administrator/index.php?option=com_plugins&view=plugin&client=site&task=edit&cid[]=36 See the 36 at the end? That's my plugin's id in the database (table jos_plugins). My issue is that this id changes on installation, ie, on different installs, it would be something else. So I need to find this id programmatically. The problem is that I couldn't find this id from the plugin object itself (as to why not, that would be joomla's arguably short-sighted design decision). So unless you know about some neat trick, (I've checked and double checked JPlugin and JPluginHelper classes), I'll be using the DB. Edit; Some useful links: http://docs.joomla.org/Plugin_Developer_Overview http://api.joomla.org/Joomla-Framework/Plugin/JPlugin.html http://api.joomla.org/Joomla-Framework/Plugin/JPluginHelper.html http://forum.joomla.org/viewtopic.php?p=2227737 Guess I'll be using the wisdom from that last link...

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  • Silverstripe: outputting DataObjectManager in template include

    - by Fraser
    I have followed the tutorial here http://doc.silverstripe.org/old/modules:dataobjectmanager to create a dataobjectmanager in my CMS. It's all working perfectly there however I am having an issue getting it to output in the template. My code is as follows <?php class InfoArea extends DataObject{ static $db = array( 'Title' => 'Varchar(255)', 'Content' => 'HTMLText' ); static $has_one = array( 'ResortPage' => 'ResortPage' ); public function getCMSFields_forPopup(){ return new FieldSet( new TextField('Title'), new SimpleTinyMCEField('Content') ); } } ResortPage.php ....... static $has_many = array ( "InfoAreas" => "InfoArea" ); ....... $fields->addFieldToTab("Root.Content.AdditionalInformation", new DataObjectManager( $this, 'InfoAreas', 'InfoArea', array('Title' => 'Title','Content'=>'Content'), 'getCMSFields_forPopup' )); ........ I have a template "ResortPage.ss" which has an include "ResortInfo.ss". It is from within this include file that I need to output the DataObject. I have tried the below but it doesn't output anything <% control InfoArea %> $Title $Content <% end_control %> What am I doing wrong here? Thanks

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  • Test a database conection without codeigniter throwing a fit, can it be done?

    - by RobertWHurst
    I'm just about finished my first release of automailer, a program I've been working on for a while now. I've just got to finish writing the installer. Its job is to rewrite the codigniter configs from templates. I've got the read/write stuff working, but I'd like to be able to test the server credentials given by the user without codingiter throwing a system error if they're wrong. Is there a function other than mysql_connect that I can use to test a connection that will return true or false and won't make codeigniter have a fit? This is what I have function _test_connection(){ if(mysql_connect($_POST['host'], $_POST['username'], $_POST['password'], TRUE)) return TRUE; else return FALSE; } Codigniter doesn't like this and throws a system error. <div style="border:1px solid #990000;padding-left:20px;margin:0 0 10px 0;"> <h4>A PHP Error was encountered</h4> <p>Severity: Warning</p> <p>Message: mysql_connect() [<a href='function.mysql-connect'>function.mysql-connect</a>]: Unknown MySQL server host 'x' (1)</p> <p>Filename: controllers/install.php</p> <p>Line Number: 57</p> </div> I'd rather not turn off error reporting.

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  • A problem of a repeated parameter in the pagination links?

    - by myaccount
    The problem is that when I load page 2 for example the URL becomes: http://domain.com/index.php?restaurant-id=45&currentpage=2 And that's fine but when I get to page 3 it becomes: http://domain.com/index.php?restaurant-id=45&currentpage=2&currentpage=3 And so on, it adds one more currentpage parameter everytime a new page is loaded from the pagination links! I wonder how this problem can be fixed? Here's some of the pagination function's code /****** build the pagination links ******/ // Getting current page URL with its parameters $current_page_url = ($_SERVER["PHP_SELF"].(isset($_SERVER["QUERY_STRING"])?"?".htmlentities($_SERVER["QUERY_STRING"]):"")); // Determine which sign to use (? or &) before the (currentpage=xx) parameter $sign = preg_match('/\?/', $current_page_url) ? '&' : '?'; $pagination_links = ''; // if not on page 1, don't show back links if ($currentpage > 1) { // show << link to go back to page 1 $pagination_links .= " <a href='{$current_page_url}{$sign}currentpage=1'>First page</a> "; // get previous page num $prevpage = $currentpage - 1; // show < link to go back 1 page $pagination_links .= " <a href='{$current_page_url}{$sign}currentpage=$prevpage'>previous</a> "; } else { $pagination_links .= "? ?"; }// end if

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  • MySQL table doesn't update, can't find the error message

    - by mobius1ski
    My knowledge level here is like zilch, but please bear with me. I have a site built in PHP/MySQL that uses the Smarty template engine. There's a registration form that, for some reason, isn't posting the data to the DB. Here's the function: $u = new H_User; $u->setFrom($p); $smarty->assign('user', $u); $val = $u->validate(); if ($val === true) { $temp = new H_User; $temp->orderBy('user_id desc'); $temp->find(true); $next_id = $temp->user_id + 1; $u->user_id = $next_id; $u->user_password = md5($p['user_password']); $u->user_regdate = mktime(); $u->user_active = 0; $u->insert(); $hash = md5($u->user_email . $u->user_regdate); $smarty->assign('hash', $hash); $smarty->assign('user', $u); $smarty->assign('registration_complete', true); $d = new H_Demographic; $d->setFrom($p); $d->insert(); How can I figure out what's wrong here? I don't get any PHP errors and I don't know how to get MySQL to display the errors that might indicate what's wrong with that syntax.

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  • cannot get FilesMatch and mod_rewrite working together

    - by neil
    Hello, I'm having a little difficulty with my .htaccess when combining a password protection on a file and a mod_rewrite: If I only have this as my .htaccess <FilesMatch "manage.php"> AuthName "Member Only" AuthType Basic AuthUserFile /home/myuser/.htpasswd require valid-user </FilesMatch> It password protects manage.php fine. If I have this as my .htaccess RewriteEngine on RewriteCond $1 !^(index\.php|manage\.php|robots\.txt) RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ index.php/$1 [L,QSA] It works as expected: robots.txt, index.php and manage.php are left alone and are called as normal, everything else is redirected to index.php/$1 HOWEVER, If I combine them then when I visit manage.php it gets redirected as index.php/$1, i.e. the FilesMatch is causing the entry in rewritecond to be ignored. If I actually enter a password in the original test and get to the file, it works in this last test. So I guess something is up with the rewrite and the file match. i.e. entering this causes .\manage.php to be called as .\index.php\manage.php <FilesMatch "manage.php"> AuthName "Member Only" AuthType Basic AuthUserFile /home/myuser/.htpasswd require valid-user </FilesMatch> RewriteEngine on RewriteCond $1 !^(index\.php|manage\.php|robots\.txt) RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ index.php/$1 [L,QSA] Thanks for any help :)

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  • Variable wont echo

    - by jonnnnnnnnnie
    I have the following code, where the var $username doesn't echo, when you type in a value. //TODO: SET AUTH TOKEN as random hash, save in session $auth_token = rand(); if (isset($_POST['action']) && $_POST['action'] == 'Login') { $errors = array(); //USED TO BUILD UP ARRAY OF ERRORS WHICH ARE THEN ECHOED $username = $_POST['username']; if ($username = '') { $errors['username'] = 'Username is required'; } echo $username; // var_dump($username) returns string 0 } require_once 'login_form.html.php'; ?> login_form is this: <form method="POST" action=""> <input type="hidden" name="auth_token" value="<?php echo $auth_token ?>"> Username: <input type="text" name="username"> Password: <input type="password" name="password1"> <input type="submit" name="action" value="Login"> </form> The auth token part isn't important, it just when I type in a value in username textbox and press the login button, the username wont echo, var_dump returns string (0) and print_r is just blank.

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  • HTML + Button with text and image on it.

    - by lucky
    Hello, I have a problem in creating a Button with text and image on it. <td> <button type="submit" name="report" value="Report" <?php if($tab == 'Excel') echo "id=\"tab_inactive\""; else echo "id=\"tab_active\"" ; ?>> <img src="images/report.gif" alt="Report"/>Report </button> <button type="submit" name="excel" value="Excel" <?php if($tab == 'Excel' ) echo "id=\"tab_active\""; else echo "id=\"tab_inactive\"" ; ?>> <img src="images/Excel.gif" alt="Excel" width="16" height="16" /> Excel </button> </td> Here $tab is $tab = strlen(trim($_POST[excel]))>0 ? $_POST[excel] : $_POST[report]; I tried this way, but this is behaving so strangely. On click the button:- The submit function is working properly in firefox, but not in IE. Instead of submitting the value(in this example values are 'Report' and 'Excel'), indeed it is submitting the label of the button. That is if i am checking the value of array PRINT_R($_POST). The value of it is Array ( [report] =>(Icon that i used) Report [excel] => (Icon that i used) Excel [frm_analysis] => [to_analysis] => ) Here i have more than 1 button, then all the labels are submitted eventhough one of them is pressed. i dont how to capture which button is pressed. I even tried changing button type=button and onclick="document.formname.submit()" Even this is resulting in the same. Can you please help me to solve this.

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  • Making more recent items more likely to be drawn

    - by bobo
    There are a few hundred of book records in the database and each record has a publish time. In the homepage of the website, I am required to write some codes to randomly pick 10 books and put them there. The requirement is that newer books need to have higher chances of getting displayed. Since the time is an integer, I am thinking like this to calculate the probability for each book: Probability of a book to be drawn = (current time - publish time of the book) / ((current time - publish time of the book1) + (current time - publish time of the book1) + ... (current time - publish time of the bookn)) After a book is drawn, the next round of the loop will minus the (current time - publish time of the book) from the denominator and recalculate the probability for each of the remaining books, the loop continues until 10 books have been drawn. Is this algorithm a correct one? By the way, the website is written in PHP. Feel free to suggest some PHP codes if you have a better algorithm in your mind. Many thanks to you all.

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  • MySQLi Wrapper -- will this slow down performance?

    - by Kerry
    I found the following code on php.net. I'm trying to write a wrapper for the MySQLi library to make things incredibly simple. If this is going to slow down performance, I'll skip it and find another way, if this works, then I'll do that. I have a single query function, if someone passes in more than one variable, I assume the function has to be prepared. The function that I would use to pass in an array to mysqli_stmt_bind_param is call_user_func_array, I have a feeling that is going to slow things down. Am I right? <?php /* just explaining how to call mysqli_stmt_bind_param with a parameter array */ $sql_link = mysqli_connect('localhost', 'my_user', 'my_password', 'world'); $type = "isssi"; $param = array("5", "File Description", "File Title", "Original Name", time()); $sql = "INSERT INTO file_detail (file_id, file_description, file_title, file_original_name, file_upload_date) VALUES (?, ?, ?, ?, ?)"; $sql_stmt = mysqli_prepare ($sql_link, $sql); call_user_func_array('mysqli_stmt_bind_param', array_merge (array($sql_stmt, $type), $param); mysqli_stmt_execute($sql_stmt); ?>

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  • pass parameter from $.post() callback to outer variable

    - by Nazmin
    basically i want to hold a parameter that retrieve value from $.post() call like this: init = function(){ var lastpage = getLastPage(); } function getLastPage(){ $.post("getInfo.php",{ last: "yes" }, function(data){ setLast(data.last); },'json'); return function setLast(data){ return data; } } so when reach at last post (last page) i should check with lastpage variable that has a value returned from getLastPage() function. I'm pretty blur with javascript pointer and all. Please help guys. update (20/4/2010): I've done the other way around, like this: init = function(){ getLastPage(); if((page+1) == $("#lastpage").val()){ alert("this is last post"); }else{ page++; //get info and display to the page here } } function getLastPage(){ $.post("getInfo.php",{ last: "yes" }, function(data){ $("#lastpage").val(data.last); },'json'); } first run the function to temporarily store the value in hidden input tag (lastpage) and then grab the value again to check it whenever i click forward button. if you all have more appropriate way please tell me.

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  • Sessions not sticking linux server

    - by Jacob Windsor
    I have just moved the dev site over to my linux server for production but the sessions don't seem to be sticking for very long. I am guessing it is the server settings and not the php because it does the same thing with the plesk panel. Whenever a script is executed the sessions seems to get unset. I see nothing in the error log so not sure what it is. It all worked fine on wamp. Anyway I uploaded the php.ini file which was in the wamp server as it had all the settings i needed and all was working on localhost. Not sure what the problem is and this is the final thing that I have to sort out before going into production. And just too add the sessions are being started as they last for a little bit just don't stick around long. Here is the relevent part of my login script just in case there is something wrong with the code: // if login is ok then we add a cookie if($flag == 0) { $pass = htmlspecialchars(mysql_real_escape_string($_POST['pass'])); $username = htmlspecialchars(mysql_real_escape_string($_POST['username'])); $_SESSION['username']=$username; $_SESSION['password']=$pass;

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  • How to current snapshot of MySQL Table and store it into CSV file(after creating it) ?

    - by Rachel
    I have large database table, approximately 5GB, now I wan to getCurrentSnapshot of Database using "Select * from MyTableName", am using PDO in PHP to interact with Database. So preparing a query and then executing it // Execute the prepared query $result->execute(); $resultCollection = $result->fetchAll(PDO::FETCH_ASSOC); is not an efficient way as lots of memory is being user for storing into the associative array data which is approximately, 5GB. My final goal is to collect data returned by Select query into an CSV file and put CSV file at an FTP Location from where Client can get it. Other Option I thought was to do: SELECT * INTO OUTFILE "c:/mydata.csv" FIELDS TERMINATED BY ',' OPTIONALLY ENCLOSED BY '"' LINES TERMINATED BY "\n" FROM my_table; But I am not sure if this would work as I have cron that initiates the complete process and we do not have an csv file, so basically for this approach, PHP Scripts will have to create an CSV file. Do a Select query on the database. Store the select query result into the CSV file. What would be the best or efficient way to do this kind of task ? Any Suggestions !!!

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  • text in div not going to next line

    - by Kia Dull
    for some reason the text in my div doesn't go to the next line, i've tried several different css elements which don't seem to work.... word-wrap:break word, just jumbles the letters... what i want is for one there is an extra word it goes down to the next line like it's supposed to here is my code this is the div it's in #top7 { width: 150px; height:auto; margin: 5px; display: block; float: left; word-wrap:break-word; } text that it's in #p6 { font-family: Myriad Pro; margin: 1px; font-size: 22px; background-color:#540f45; padding: 5px 5px 3px 4px; margin:4px; } a { text-decoration: none; color: white; text-align: right; font-family: Myriad Pro; } here is the php function that retrieves the data from the database <p id='p6'><?php echo "<a href='' "</a>"; ?></p> this is all wrapped in these two id's body { background:#603e4f; display: block; } #foursquare { background-color:#603e4f; width: 290px; display: block; position: absolute; }

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  • highlighting data values in a sql result set

    - by potatoe
    I can think of a number of ways to do this in PHP or even JavaScript, but I'm wondering if there's a SQL-based technique I'm overlooking. I have a database table, let's say 20 fields X 10 rows. I want to display the entire table on an web page, so I'd do something like SELCT * FROM data_table;, and then format the result set using HTML table tags. However, I'd also like to highlight values in the table based on whether they are the maximum or minimum value in their column. For example, I'd add bold tags around the max in each column. A resulting table might look something like this, with bold tags shown: id | field1 | field2 | field3 | ... 0 | 5 | 2 | <b>7</b> | ... 1 | 3 | <b>8</b> | 6 | ... 2 | <b>9</b> | 5 | 1 | ... ... I could do a separate SELECT with an ORDER BY for each field and then interpret the results, but that seems like a lot of extra DB access. My alternative right now is to just fetch the whole table, and then sort/search for the highlight values using PHP. Is there a better way?

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  • Update MySQl table onDrop?

    - by dougvt
    Hi all. I am writing a PHP/MySQL application (using CodeIgniter) that uses some jQuery functionality for dragging table rows. I have a table in which the user can drag rows to the desired order (kind of a queue for which I need to preserve the rank of each row). I've been trying to figure out how to (and whether I should) update the database each time the user drops a row, in order to simplify the UI and avoid a "Save" button. I have the jQuery working and can send a serialized list back to the server onDrop, but is it good design practice to run an update query this often? The table will usually have 30-40 rows max, but if the user drags row 1 far down the list, then potentially all the rows would need to be updated to update the rank field. I've been wondering whether to send a giant query to the server, to loop through the rows in PHP and update each row with its own Update query, to send a small serialized list to a stored procedure to let the server do all the work, or perhaps a better method I haven't considered. I've read that stored procedures in MySQL are not very efficient and use a separate process for each call. Any advice as to the right solution here? Thanks very much for your help!

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  • Questions about shifting from mysql to PDO

    - by Scarface
    Hey guys I have recently decided to switch all my current plain mysql queries performed with php mysql_query to PDO style queries to improve performance, portability and security. I just have some quick questions for any experts in this database interaction tool Will it prevent injection if all statements are prepared? (I noticed on php.net it wrote 'however, if other portions of the query are being built up with unescaped input, SQL injection is still possible' I was not exactly sure what this meant). Does this just mean that if all variables are run through a prepare function it is safe, and if some are directly inserted then it is not? Currently I have a connection at the top of my page and queries performed during the rest of the page. I took a look at PDO in more detail and noticed that there is a try and catch procedure for every query involving a connection and the closing of that connection. Is there a straightforward way to connecting and then reusing that connection without having to put everything in a try or constantly repeat the procedure by connecting, querying and closing? Can anyone briefly explain in layman's terms what purpose a set_exception_handler serves? I appreciate any advice from any more experienced individuals.

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  • Make a router like zend

    - by Vahan
    I have a url http://*.com/branch/module/view/id/1/cat/2/etc/3. It becomes. array ( 'module'=>'branch', 'controller'=>'module', 'action'=>'view' ); next I need to get the params. Ihave this array. /*function getNextSegments($n,$segments) { return array_slice ( $q = $this->segments, $n + 1 ); } $params = getNextSegments(3); */ array ( 0 => 'id', 1 => '1', 2 => 'cat', 3 => '2', 4 => 'etc', 5 => '3' );//params And i wanna convert it to this one: array ( 'id'=1, 'cat'=2, 'etc'=3, ); How i can do this using php function. I know I can do using for or foreach, but I think php has such function , but i cant find it :(. Thank you. class A { protected function combine($params) { $count = count ( $params ); $returnArray = array (); for($i = 0; $i < $count; $i += 2) { $g = $i % 2; if ($g == 0 or $g > 0) { if (isset ( $params [$i] ) and isset ( $params [$i + 1] )) $returnArray [$params [$i]] = $params [$i + 1]; } } return $returnArray; } } This works normaly. If anybody has better login for this please help. Thank you again.

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  • submit in html on sql query

    - by user1644661
    i need to run this sql query , which give me a list of Id and Dates i want to click each result and take with me the Id value to the next form i wrote this query above but i see in the debager that the hidden ID get his value but not pass to the next form i think i have a problem with the submit() . where should i put him ? thanks anat function ShowAllCarts($user_email) { $connB = new ProductDAO(); $connB->Connect(); $pro_query = "SELECT * FROM Cart WHERE `Email`='$user_email';"; $db_result = $connB->ExecSQL($pro_query); $html_result = '<div data-role="content"> <ul data-role="listview" data-theme="b"> '; $html_result .= '<form action="PreviouscartProduct.php" method="POST"/>'; while($row_array = $db_result->fetch_array(MYSQLI_ASSOC)) { $Id= $row_array['Id']; $Date= $row_array['Date']; //$html_result // $html_result .="<li><a href='PreviouscartProduct.php'>Cart number: $Id from Date: $Date><input type='hidden' name='Id' value'<?=$Id?>'</input></a></li>'"; $html_result .= '<a onclick="this.form.submit();" </a>; } $html_result .= ' </ul> </div>'; $html_result .= '</form>'; $connB->Disconnect(); return $html_result; } //display all carts $func_result = ShowAllCarts($Email);

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  • How can I add dynamic text from a different table where primary key is a foreign key to adynamic table being shown?

    - by Jethro Tamares Doble
    I have here a dynamic table named tb_user with column region_id and institute_id and both ids are primary key of another table tb_region (with column region_name and region_id) and tb_institute (column institute_id and institute_name). I wanted to see region_name and institute_name instead of the ids. I've used this php script <?php echo $row_institute['institution_name']; ?> and query to collect data for tb_institute mysql_select_db($database_connection_ched, $connection_ched); $query_institution = "SELECT institute_id, institute_name FROM tb_institute"; $institution = mysql_query($query_institution, $connection_ched) or die(mysql_error()); $row_institution = mysql_fetch_assoc($institution); $totalRows_institution = mysql_num_rows($institution); but it seems not to display the correct name of id. query i used to collect data: mysql_select_db($database_connection_ched, $connection_ched); $query_notification = sprintf("SELECT * FROM tb_user WHERE status = 'inactive' ORDER BY date_register ASC", GetSQLValueString($colname_notification, "text")); $query_limit_notification = sprintf("%s LIMIT %d, %d", $query_notification, $startRow_notification, $maxRows_notification); $notification = mysql_query($query_limit_notification, $connection_ched) or die(mysql_error()); $row_notification = mysql_fetch_assoc($notification); if (isset($_GET['totalRows_notification'])) { $totalRows_notification = $_GET['totalRows_notification']; } else { $all_notification = mysql_query($query_notification); $totalRows_notification = mysql_num_rows($all_notification); } $totalPages_notification = ceil($totalRows_notification/$maxRows_notification)-1;

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  • Simple iOS Get Request Not Pulling in Data

    - by user2793987
    I have a very simple get request that doesn't return data on my script. The script is fine when viewed in the web browser but the app does not pull in the data. Any other script works with this code in the app. I'm unsure of what to do because there shouldn't be a reason for this to not work. Please let me know if you need more information. Here's the script: https://shipstudent.com/complaint_desk/similarPosts.php?username=noah //retrieve saved username from user defaults (it's noah) NSUserDefaults *eUser = [NSUserDefaults standardUserDefaults]; savedUser = [eUser objectForKey:@"user"]; NSLog(@"%@",savedUser); in ViewDidLoad: NSString *categoryParam = [NSString stringWithFormat:@"https://shipstudent.com/complaint_desk/similarPosts.php?username=%@", savedUser]; NSURL *url = [NSURL URLWithString:categoryParam]; NSMutableURLRequest *request = [NSURLRequest requestWithURL:url cachePolicy:NSURLCacheStorageAllowed timeoutInterval:30.0]; NSURLConnection *connection = [[NSURLConnection alloc] initWithRequest:request delegate:self]; if (connection==nil) { NSLog(@"Invalid request"); } -(void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response { postData = [[NSMutableData alloc]init]; NSLog(@"Response received"); } -(void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data { [postData appendData:data]; NSLog(@"Data received"); } -(void)connectionDidFinishLoading:(NSURLConnection *)connection { [UIApplication sharedApplication].networkActivityIndicatorVisible = NO; similarPosts = [NSJSONSerialization JSONObjectWithData:postData options:kNilOptions error:nil]; [postsTbl reloadData]; for (id postObject in similarPosts) { NSLog(@"Relatable Post: %@",postObject); } }

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