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  • Detecting file upload size on the client side?

    - by DisgruntledGoat
    I'm using PHP for file uploads. In the PHP manual it shows an example using a MAX_FILE_SIZE hidden field, saying that it will detect on the client side (i.e. the browser) whether the file is too large or not. I've just tried the example in Firefox, Chrome and IE and it doesn't work. The file is always uploaded, even if it is way larger than the specified hidden field. Incidentally, if the file is larger than MAX_FILE_SIZE then calling move_uploaded_file doesn't work, so it seems the variable is having an effect server-side, but not client-side.

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  • Python text file processing speed issues

    - by Anonymouslemming
    Hi all, I'm having a problem with processing a largeish file in Python. All I'm doing is f = gzip.open(pathToLog, 'r') for line in f: counter = counter + 1 if (counter % 1000000 == 0): print counter f.close This takes around 10m25s just to open the file, read the lines and increment this counter. In perl, dealing with the same file and doing quite a bit more (some regular expression stuff), the whole process takes around 1m17s. Perl Code: open(LOG, "/bin/zcat $logfile |") or die "Cannot read $logfile: $!\n"; while (<LOG>) { if (m/.*\[svc-\w+\].*login result: Successful\.$/) { $_ =~ s/some regex here/$1,$2,$3,$4/; push @an_array, $_ } } close LOG; Can anyone advise what I can do to make the Python solution run at a similar speed to the Perl solution? I've tried just uncompressing the file and dealing with it using open instead of gzip.open, but that made a very small difference to the overall time.

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  • Splitting a file before upload?

    - by Yevgeniy Brikman
    On a webpage, is it possible to split large files into chunks before the file is uploaded to the server? For example, split a 10MB file into 1MB chunks, and upload one chunk at a time while showing a progress bar? It sounds like JavaScript doesn't have any file manipulation abilities, but what about Flash and Java applets? This would need to work in IE6+, Firefox and Chrome. Update: forgot to mention that (a) we are using Grails and (b) this needs to run over https.

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  • The ultimate c# file and directory utility library?

    - by Serge van den Oever
    I find myself writing file and directory utility functions all the time, and I was wondering if there is good file and directory library that already implements a more extensive set than available by default in System.IO. The kind of functions I'm looking for is things like: public static void GetTemporaryDirectory() { string tempDirectory = Path.Combine(Path.GetTempPath(), Path.GetRandomFileName()); Directory.CreateDirectory(tempDirectory); return tempDirectory; } public static void CreateEmptyFile(string filename) { File.Create(filename).Dispose(); } public static void CreateEmptyFile(string path, string filename) { File.Create(Path.Combine(path, filename)).Dispose(); } public static void CreateDirectory(string path) { Directory.CreateDirectory(path); } public static void CreateDirectory(string path, string childpath) { Directory.CreateDirectory(Path.Combine(path, childpath)); }

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  • Create unique file name and fetching it to commandline argument

    - by user343934
    Hi everyone, I am working on python right now and i am little bit stuck in performing some tricks. I have web form with two options- File upload and textarea, i can easily pass file name with file upload options but have problem when it's textarea. Because when i use textarea then first i have to save values passed from textarea to some files and save it on the working directory. After that i can execute commandline argument and pass same saved filename name. For this problem i have to generate unique file first and save the values passed from textarea in it. Can anybody give me some tips to solve my problem. Any algorithms, suggestions and lines of code are appreciated. Thanks for your concern

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  • local file access with javascript

    - by Jared
    is there any local file manipulation that's been done with javascript? i'm looking for a solution that can be accomplished with no install footprint like requiring AIR. specifically, i'd like to read the contents from a file and write those contents to another file. at this point i'm not worried about gaining permissions, just assuming i already have full permissions to these files.

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  • Problem with reading and writing to binary file in C++

    - by Reem
    I need to make a file that contains "name" which is a string -array of char- and "data" which is array of bytes -array of char in C++- but the first problem I faced is how to separate the "name" from the "data"? newline character could work in this case (assuming that I don't have "\n" in the name) but I could have special characters in the "data" part so there's no way to know when it ends so I'm putting an int value in the file before the data which has the size of the "data"! I tried to do this with code as follow: if((fp = fopen("file.bin","wb")) == NULL) { return false; } char buffer[] = "first data\n"; fwrite( buffer ,1,sizeof(buffer),fp ); int number[1]; number[0]=10; fwrite( number ,1,1, fp ); char data[] = "1234567890"; fwrite( data , 1, number[0], fp ); fclose(fp); but I didn't know if the "int" part was right, so I tried many other codes including this one: char buffer[] = "first data\n"; fwrite( buffer ,1,sizeof(buffer),fp ); int size=10; fwrite( &size ,sizeof size,1, fp ); char data[] = "1234567890"; fwrite( data , 1, number[0], fp ); I see 4 "NULL" characters in the file when I open it instead of seeing an integer. Is that normal? The other problem I'm facing is reading that again from the file! The code I tried to read didn't work at all :( I tried it with "fread" but I'm not sure if I should use "fseek" with it or it just read the other character after it. Forgive me but I'm a beginner :(

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  • Read from file into pointer to struct

    - by cla barzu
    I need help with pointers in C. I have to read from a file, and fill an array with pointers to struct rcftp_msg . Since now I did the next things: struct rcftp_msg { uint8_t version; uint8_t flags; uint16_t len; uint8_t buffer[512]; }; struct rcftp_msg *windows [10]; pfile = fopen(file,"r"); // Open the file I have to read from the file into the buffer, but I don't know how to do it. I tried the next: for (i = 0; i <10; i++){ leng=fread (**windows[i]->buffer**,sizeof(uint8_t),512,pfile); } I think windows[i]-buffer is bad, cuz that don't work. Sorry for my bad English :(

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  • Set registry to control working dir when associating file-type with application

    - by John
    I'm using Inno for an installer, and I want to associate a file type with my app: Root: HKCR; Subkey: ".rpl"; ValueType: string; ValueName: ""; ValueData: "MyReplay"; Flags: uninsdeletevalue; Root: HKCR; Subkey: "MyReplay"; ValueType: string; ValueName: ""; ValueData: "Replay File"; Flags: uninsdeletekey; Root: HKCR; Subkey: "MyReplay\DefaultIcon"; ValueType: string; ValueName: ""; ValueData: "{app}\bin\MyApp.ico,0"; Flags: uninsdeletekey; Root: HKCR; Subkey: "MyReplay\shell\open\command"; ValueType: string; ValueName: ""; ValueData: """{app}\bin\MyApp.exe"" ""%1"""; Flags: uninsdeletekey; Right now, double-clicking a .rpl file launches the app, but the working dir appears to be where the .rpl file is located, so the app crashes as it can't load any data. Is it posible to set the registry to control the start/working dir for file associations as well as the app that is launched? Or does my app itself need to be able to work around this?

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  • change file descriptor for socket in python

    - by Dani
    Hello everybody I'm trying to manually create the file descriptor associated with a socket in python and then loaded directly into memory with mmap. Create a file into memory with mmap is simple, but I can not find a way to associate the file with a socket. Anyone know how? thank you very much.

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  • Display only file name in FileUpload control

    - by Jagd
    I have a webpage in asp.net 3.5 that uses the FileUpload control. When a user clicks on the "Browse" button (which is part of the control) the control displays a file select popup (dialog box). When the user selects the file which they wish to upload, by default the full path to the file is shown in the textbox (which is also part of the control); however, I wish for it to only display the file name and not the full path. Anyone know of a slick and easy way to do this?

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  • Save PHP variables to a text file

    - by Ajith
    I was wondering how to save PHP variables to a txt file and then retrieve them again. Example: There is an input box, after submitted the stuff that was written in the input box will be saved to a text file. Later on the results need to be brought back as a variable. So lets say the variable is $text I need that to be saved to a text file and be able to retrieve it back again. Hope it makes sense, Thanks in advance!!!

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  • Write file in sub-directory in Android

    - by Davide Vosti
    I'm trying to save a file in a subdirectory in Android 1.5. I can successfully create a directory using _context.GetFileStreamPath("foo").mkdir(); (_context is the Activity where I start the execution of saving the file) but then if I try to create a file in foo/ by _context.GetFileStreamPath("foo/bar.txt"); I get a exception saying I can't have directory separator in a file name ("/"). I'm missing something of working with files in Android... I thought I could use the standard Java classes but they don't seem to work... I searched the Android documentation but I couldn't fine example and google is not helping me too... I'm asking the wrong question (to google)... Can you help me out with this? Thank you!

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  • What tool to use to draw file tree diagram

    - by Michael
    Given a file tree - a directory with directories in it etc, what software would you recommend to create a diagram of the file-tree as a graphic file that I can embed in a word processor document I prefer vector (SVG, EPS, EMF...) files. The tool must run on Windows, but preferably cross-platform. The tool may be commercial but preferably free.

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  • Reading parameters from External file - C#

    - by mouthpiec
    I am writing an application using C# and I would like to read some parameters from an external file like for example a text file. The parameters will be saved in the file in the form of parA = 5 parB = hello etc Can you pleas suggest a way how I can do this?

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  • Reading line by line from a file in C

    - by mh234
    What I am trying to do is print out the contents of a file line by line. I run the program in terminal by doing: ./test testText.txt. When I do this, random characters are printed out but not what is in the file. The text file is located in the same folder as the makefile. What's wrong? #include <stdio.h> FILE *fp; int main(int argc, char *argv[]) { char line[15]; fp = fopen(*argv, "r"); while((fgets(line, 15, fp)) != NULL) { printf(line); printf("\n"); } }

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  • DIR $file "File Not Found" vs DIR $filedir shows it....not permissions, not USB

    - by Kev
    I was having this problem before on a USB drive, but now it's happening on my main RAID5-backed hard disk: 2013-10-17 9:37 C:\>dir "C:\Shares\Shared\Reference\Safety Management System\Vid eo CD\AutoPlay\Docs\Manuel*" Volume in drive C has no label. Volume Serial Number is 3C18-E114 Directory of C:\Shares\Shared\Reference\Safety Management System\Video CD\AutoP lay\Docs 2003-09-09 11:29 PM 1,056,768 Manuel d'intervention d'urgence MFC.doc 2004-06-20 10:36 PM 139,849 Manuel d'intervention d'urgence MFC.pdf 2 File(s) 1,196,617 bytes 0 Dir(s) 196,068,691,968 bytes free 2013-10-17 9:38 C:\>dir "C:\Shares\Shared\Reference\Safety Management System\Vid eo CD\AutoPlay\Docs\Manuel d'intervention d'urgence MFC.doc" Volume in drive C has no label. Volume Serial Number is 3C18-E114 Directory of C:\Shares\Shared\Reference\Safety Management System\Video CD\AutoP lay\Docs File Not Found 2013-10-17 9:38 C:\> This is from a Command Prompt window where I went to Properties and told it I wanted to modify who it ran as. I opened it, had it run as me with the "restricted access" unchecked, then ran the above. The file in question has the following ACLs: Administrators, SYSTEM, and OurCompanyUsers. All three have full control of everything. Nobody has any Deny bits set. I am a member of Administrators. So I don't believe it's a permissions issue. It's not a USB drive, so this time there is no question of USB hardware. Windows Server 2003 Standard Edition SP2. What does this mean? Is this more likely a hardware or software problem?

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  • Is there such a thing as a file hosted container which deduplicates data held within?

    - by Mallow
    Background I have backups of a website which stores all of it's data into a single file. This file is several gigs large and I have many different backups of this file. Most of the data within is mostly the same plus whatever was added or changed to it. I want to keep all the concurrent backups I've made through the years in case I find a horrible surprise of data corruption along the line. However storing a 10gig file every month gets expensive. Seeking Solution I've often thought about different ways of alleviating this problem. One thought that comes up very often combines the idea of a duplicating file system which doesn't require it's own partitioned volume on a hard drive. Something like what truecrypt does, what it calls, "file hosted containers" which when using the truecrypt program allows you to mount and dismount that volume as a regular hard drive. Question Is there a virtual hard drive mounter which uses file-based container which uses data deduplicaiton file system? (This question is a little awkward to put into words, if you have a better idea on how to ask this question please feel free to help out.)

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  • Command-Line Parsing API from TestAPI library - Type-Safe Commands how to

    - by MicMit
    Library at http://testapi.codeplex.com/ Excerpt of usage from http://blogs.msdn.com/ivo_manolov/archive/2008/12/17/9230331.aspx A third common approach is forming strongly-typed commands from the command-line parameters. This is common for cases when the command-line looks as follows: some-exe COMMAND parameters-to-the-command The parsing in this case is a little bit more involved: Create one class for every supported command, which derives from the Command abstract base class and implements an expected Execute method. Pass an expected command along with the command-line arguments to CommandLineParser.ParseCommand – the method will return a strongly-typed Command instance that can be Execute()-d. // EXAMPLE #3: // Sample for parsing the following command-line: // Test.exe run /runId=10 /verbose // In this particular case we have an actual command on the command-line (“run”), which we want to effectively de-serialize and execute. public class RunCommand : Command { bool? Verbose { get; set; } int? RunId { get; set; } public override void Execute() { // Implement your "run" execution logic here. } } Command c = new RunCommand(); CommandLineParser.ParseArguments(c, args); c.Execute(); ============================ I don't get if we instantiate specific class before parsing arguments , what's the point of command line argument "run" which is very first one. I thought the idea was to instantiate and execute command/class based on a command line parameter ( "run" parameter becomes instance RunCommand class, "walk" becomes WalkCommand class and so on ). Can it be done with the latest version ?

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  • Difference in performance between Stax and DOM parsing

    - by Fazal
    I have been using DOM for a long time and as such DOM parsing performance wise has been pretty good. Even when dealing with XML of about 4-7 MB the parsing has been fast. The issue we face with DOM is the memory footprint which become huge as soon as we start dealing with large XMLs. Lately I tried moving to Stax (Streaming parsers for XML) which are supposed top be second generation parsers (reading about Stax it said its the fastest parser now). When I tried stax parser for large XML for about 4MB memory footprint definitely reduced drastically but time take to parse entire XML and create java object out of it increased almost by 5 times over DOM. I used sjsxp.jar implementation of Stax. I can deuce to some extent logically that performance may not be extremely good due to streaming nature of the parser but a reduction of 5 time (e.g. DOM takes about 8 seconds to build object for this XML, whereas Stax parsing took about 40 seconds on average) is definitely not going to be acceptable. Am I missing some point here completely as I am not able to come to terms with these performance numbers

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  • How to Upload a file from client to server using OFBIZ?

    - by SIVAKUMAR.J
    Hi all, Im new to ofbiz.So is my question is have any mistake forgive me for my mistakes.Im new to ofbiz so i did not know some terminologies in ofbiz.Sometimes my question is not clear because of lack of knowledge in ofbiz.So try to understand my question and give me a good solution with respect to my level.Because some solutions are in very high level cannot able to understand for me.So please give the solution with good examples. My problem is i created a project inside the ofbiz/hot-deploy folder namely "productionmgntSystem".Inside the folder "ofbiz\hot-deploy\productionmgntSystem\webapp\productionmgntSystem" i created a .ftl file namely "app_details_1.ftl" .The following are the coding of this file <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> <title>Insert title here</title> <script TYPE="TEXT/JAVASCRIPT" language=""JAVASCRIPT"> function uploadFile() { //alert("Before calling upload.jsp"); window.location='<@ofbizUrl>testing_service1</@ofbizUrl>' } </script> </head> <!-- <form action="<@ofbizUrl>testing_service1</@ofbizUrl>" enctype="multipart/form-data" name="app_details_frm"> --> <form action="<@ofbizUrl>logout1</@ofbizUrl>" enctype="multipart/form-data" name="app_details_frm"> <center style="height: 299px; "> <table border="0" style="height: 177px; width: 788px"> <tr style="height: 115px; "> <td style="width: 103px; "> <td style="width: 413px; "><h1>APPLICATION DETAILS</h1> <td style="width: 55px; "> </tr> <tr> <td style="width: 125px; ">Application name : </td> <td> <input name="app_name_txt" id="txt_1" value=" " /> </td> </tr> <tr> <td style="width: 125px; ">Excell sheet &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;: </td> <td> <input type="file" name="filename"/> </td> </tr> <tr> <td> <!-- <input type="button" name="logout1_cmd" value="Logout" onclick="logout1()"/> --> <input type="submit" name="logout_cmd" value="logout"/> </td> <td> <!-- <input type="submit" name="upload_cmd" value="Submit" /> --> <input type="button" name="upload1_cmd" value="Upload" onclick="uploadFile()"/> </td> </tr> </table> </center> </form> </html> the following coding is present in the file "ofbiz\hot-deploy\productionmgntSystem\webapp\productionmgntSystem\WEB-INF\controller.xml" ...... ....... ........ <request-map uri="testing_service1"> <security https="true" auth="true"/> <event type="java" path="org.ofbiz.productionmgntSystem.web_app_req.WebServices1" invoke="testingService"/> <response name="ok" type="view" value="ok_view"/> <response name="exception" type="view" value="exception_view"/> </request-map> .......... ............ .......... <view-map name="ok_view" type="ftl" page="ok_view.ftl"/> <view-map name="exception_view" type="ftl" page="exception_view.ftl"/> ................ ............. ............. The following are the coding present in the file "ofbiz\hot-deploy\productionmgntSystem\src\org\ofbiz\productionmgntSystem\web_app_req\WebServices1.java" package org.ofbiz.productionmgntSystem.web_app_req; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import java.io.DataInputStream; import java.io.FileOutputStream; import java.io.IOException; public class WebServices1 { public static String testingService(HttpServletRequest request, HttpServletResponse response) { //int i=0; String result="ok"; System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- Start"); String contentType=request.getContentType(); System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- contentType : "+contentType); String str=new String(); // response.setContentType("text/html"); //PrintWriter writer; if ((contentType != null) && (contentType.indexOf("multipart/form-data") >= 0)) { System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) after if (contentType != null)"); try { // writer=response.getWriter(); System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - try Start"); DataInputStream in = new DataInputStream(request.getInputStream()); int formDataLength = request.getContentLength(); byte dataBytes[] = new byte[formDataLength]; int byteRead = 0; int totalBytesRead = 0; //this loop converting the uploaded file into byte code while (totalBytesRead < formDataLength) { byteRead = in.read(dataBytes, totalBytesRead,formDataLength); totalBytesRead += byteRead; } String file = new String(dataBytes); //for saving the file name String saveFile = file.substring(file.indexOf("filename=\"") + 10); saveFile = saveFile.substring(0, saveFile.indexOf("\n")); saveFile = saveFile.substring(saveFile.lastIndexOf("\\")+ 1,saveFile.indexOf("\"")); int lastIndex = contentType.lastIndexOf("="); String boundary = contentType.substring(lastIndex + 1,contentType.length()); int pos; //extracting the index of file pos = file.indexOf("filename=\""); pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; int boundaryLocation = file.indexOf(boundary, pos) - 4; int startPos = ((file.substring(0, pos)).getBytes()).length; int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length; //creating a new file with the same name and writing the content in new file FileOutputStream fileOut = new FileOutputStream("/"+saveFile); fileOut.write(dataBytes, startPos, (endPos - startPos)); fileOut.flush(); fileOut.close(); System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - try End"); } catch(IOException ioe) { System.out.println("\n\n\t*********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - Catch IOException"); //ioe.printStackTrace(); return("exception"); } catch(Exception ex) { System.out.println("\n\n\t*********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - Catch Exception"); return("exception"); } } else { System.out.println("\n\n\t********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) else part"); result="exception"; } System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- End"); return(result); } } I want to upload a file to the server.The file is get from user "<input type="file"..> tag in the "app_details_1.ftl" file & it is updated into the server by using the method "testingService(HttpServletRequest request, HttpServletResponse response)" in the class "WebServices1".But the file is not uploaded. Give me a good solution for uploading a file to the server. Thanks & Regards, Sivakumar.J

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  • Java compiler error: "cannot find symbol" when trying to access local variable

    - by HH
    $ javac GetAllDirs.java GetAllDirs.java:16: cannot find symbol symbol : variable checkFile location: class GetAllDirs System.out.println(checkFile.getName()); ^ 1 error $ cat GetAllDirs.java import java.util.*; import java.io.*; public class GetAllDirs { public void getAllDirs(File file) { if(file.isDirectory()){ System.out.println(file.getName()); File checkFile = new File(file.getCanonicalPath()); }else if(file.isFile()){ System.out.println(file.getName()); File checkFile = new File(file.getParent()); }else{ // checkFile should get Initialized at least HERE! File checkFile = file; } System.out.println(file.getName()); // WHY ERROR HERE: checkfile not found System.out.println(checkFile.getName()); } public static void main(String[] args) { GetAllDirs dirs = new GetAllDirs(); File current = new File("."); dirs.getAllDirs(current); } }

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