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  • How do I mock/fake/replace/stub a base class at unit-test time in C#?

    - by MatthewMartin
    UPDATE: I've changed the wording of the question. Previously it was a yes/no question about if a base class could be changed at runtime. I may be working on mission impossible here, but I seem to be getting close. I want to extend a ASP.NET control, and I want my code to be unit testable. Also, I'd like to be able to fake behaviors of a real Label (namely things like ID generation, etc), which a real Label can't do in an nUnit host. Here a working example that makes assertions on something that depends on a real base class and something that doesn't-- in a more realistic unit test, the test would depend on both --i.e. an ID existing and some custom behavior. Anyhow the code says it better than I can: public class LabelWrapper : Label //Runtime //public class LabelWrapper : FakeLabel //Unit Test time { private readonly LabelLogic logic= new LabelLogic(); public override string Text { get { return logic.ProcessGetText(base.Text); } set { base.Text=logic.ProcessSetText(value); } } } //Ugh, now I have to test FakeLabelWrapper public class FakeLabelWrapper : FakeLabel //Unit Test time { private readonly LabelLogic logic= new LabelLogic(); public override string Text { get { return logic.ProcessGetText(base.Text); } set { base.Text=logic.ProcessSetText(value); } } } [TestFixture] public class UnitTest { [Test] public void Test() { //Wish this was LabelWrapper label = new LabelWrapper(new FakeBase()) LabelWrapper label = new LabelWrapper(); //FakeLabelWrapper label = new FakeLabelWrapper(); label.Text = "ToUpper"; Assert.AreEqual("TOUPPER",label.Text); StringWriter stringWriter = new StringWriter(); HtmlTextWriter writer = new HtmlTextWriter(stringWriter); label.RenderControl(writer); Assert.AreEqual(1,label.ID); Assert.AreEqual("<span>TOUPPER</span>", stringWriter.ToString()); } } public class FakeLabel { virtual public string Text { get; set; } public void RenderControl(TextWriter writer) { writer.Write("<span>" + Text + "</span>"); } } //System Under Test internal class LabelLogic { internal string ProcessGetText(string value) { return value.ToUpper(); } internal string ProcessSetText(string value) { return value.ToUpper(); } }

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  • Cleaner way to store to replace a scalar hash value with an array ref?

    - by user275455
    I am building a hash where the keys, associated with scalars, are not necessarily unique. I want the desired behavior to be that if the key is unique, the value is the scalar. If the key is not unique, I want the value to be an array reference of the scalars associated witht the key. Since the hash is built up iteratively, I don't know if the key is unique ahead of time. Right now, I am doing something like this: if(!defined($hash{$key})){ $hash{$key} = $val; } elseif(ref($hash{$key}) ne 'ARRAY'){ my @a; push(@a, $hash{$key}); push(@, $val); $hash{$key} = \@a; } else{ push(@{$hash{$key}}, $val); } Is there a simpler way to do this?

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  • CSS or JS max. character <h2> and replace end with "..."

    - by cr0z3r
    Hey I assume my title basically summed it all up. I have a <h2> title, and I want it to have a max character property, be it CSS or javascript, so that whenever this maximum limit is passed, the title's end is replaced by ... (three dots). Thank you very much in advance. An example can be viewed here: http://themeforest.net/forums/thread/now-accepting-bargain-submissions/23205 (see the title) P.S. Any idea why I had to create a new user? the login-feature through google doesn't recognize my previous user :(

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  • Replace carriage returns and line feeds in out.println?

    - by Mike
    I am a novice coder and I am using the following code to outprint a set of Image keywords and input a "|" between them. <% Set allKeywords = new HashSet(); for (AlbumObject ao : currentObjects) { XmpManager mgr = ao.getXmpManager(); if (mgr != null) { allKeywords.addAll(mgr.getKeywordSet()); } } //get the Iterator Iterator itr = allKeywords.iterator(); while(itr.hasNext()){ String str = itr.next(); out.println(str +"|"); } %> I want the output to be like this: red|blue|green|yellow but it prints out: red| blue| green| yellow which breaks my code. I've tried this: str.replaceAll("\n", ""); str.replaceAll("\r", ""); and str.replaceAll("(?:\\n|\\r)", ""); No luck. I'd really appreciate some help!

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  • Why doesn't this work?

    - by Kyle W
    take = raw_input('Please enter the string of numbers that compose code\n\n\t') y = str(take) l = [] for i in xrange(0, len(y), 3):         l.append(str(y[i:i+3])) b = len(l) a = 0 while(a!=b):         c = l[a].replace('444', ' ')         c = l[a].replace('111', 'a')         c = l[a].replace('112', 'b')         c = l[a].replace('113', 'c')         c = l[a].replace('114', 'd')         c = l[a].replace('115', 'e')         etc...         a = a + 1 filename = 'decmes.txt' file = open(filename, 'w') file.write(c) file.close() I can enter anything, just 111 for example and it gives me back the same thing I put in. Maybe it's something dumb, but I can't figure it out.

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  • Learning PostgreSql: polymorphism

    - by Alexander Kuznetsov
    Functions in PL/PgSql are polymorphic, which is very different from T-SQL. Demonstrating polymorphism For example, the second CREATE FUNCTION in the following script does not replace the first function - it creates a second one: CREATE OR REPLACE FUNCTION public .GetQuoteOfTheDay ( someNumber INTEGER ) RETURNS VARCHAR AS $body$ BEGIN RETURN 'Say my name.' ; END ; $body$ LANGUAGE plpgsql ; CREATE OR REPLACE FUNCTION public .GetQuoteOfTheDay ( someNumber REAL ) RETURNS VARCHAR AS $body$ BEGIN RETURN...(read more)

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  • Eclipse has multiple issues after JRE-6 (OpenJDK) upgrade

    - by Eusebius
    I'm on 12.04 LTS, and trying to use Eclipse Indigo. This morning Ubuntu made me update the following packages: Preparing to replace icedtea-6-jre-cacao 6b24-1.11.3-1ubuntu0.12.04.1 (using .../icedtea-6-jre-cacao_6b24-1.11.4-1ubuntu0.12.04.1_amd64.deb) ... Unpacking replacement icedtea-6-jre-cacao ... Preparing to replace openjdk-6-jre-lib 6b24-1.11.3-1ubuntu0.12.04.1 (using .../openjdk-6-jre-lib_6b24-1.11.4-1ubuntu0.12.04.1_all.deb) ... Unpacking replacement openjdk-6-jre-lib ... Preparing to replace icedtea-6-jre-jamvm 6b24-1.11.3-1ubuntu0.12.04.1 (using .../icedtea-6-jre-jamvm_6b24-1.11.4-1ubuntu0.12.04.1_amd64.deb) ... Unpacking replacement icedtea-6-jre-jamvm ... Preparing to replace openjdk-6-jre-headless 6b24-1.11.3-1ubuntu0.12.04.1 (using .../openjdk-6-jre-headless_6b24-1.11.4-1ubuntu0.12.04.1_amd64.deb) ... Unpacking replacement openjdk-6-jre-headless ... Preparing to replace openjdk-6-jre 6b24-1.11.3-1ubuntu0.12.04.1 (using .../openjdk-6-jre_6b24-1.11.4-1ubuntu0.12.04.1_amd64.deb) ... Unpacking replacement openjdk-6-jre ... After that (but I cannot swear it is the root cause), I have the following issues in Eclipse: When trying to launch the simplest HelloWorld program (which behaves fine with manual javac/java), I get either nothing or: An internal error occurred during: "Launching HelloWorld". org/eclipse/jdt/debug/core/JDIDebugModel I get an "Error log" tab in the console panel, with an error: Could not create the view: An unexpected exception was thrown. (Follows a consequent NullPointerException stacktrace between sun.util.calendar.ZoneInfoFile.getZoneIDs(ZoneInfoFile.java:785) and org.eclipse.equinox.launcher.Main.main(Main.java:1386)) When trying to access the Installed JREs part of the preferences, I get a popup saying: Unable to create the selected preference page. An error occurred while automatically activating bundle org.eclipse.jdt.debug.ui (162). And the preference tab says An error has occurred when creating this preference page. Until today I had a manually installed Eclipse (one of the official bundles available on their site), I've tried to replace it by the repository version and I get the same errors. What should I do to make Eclipse work again? Another person reports: Same happened to me after updating last night. Already tried reinstalling Eclipse and Java, starting Eclipse with -clean and starting new workspace and new .eclipse dir, but nothing helps.

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  • Merging paragraphs in MS Word 2007

    - by Rajneesh Jain
    My name is Rajneesh Jain from New Delhi, India. I saw your code on merging and re-formatting paragraphs in MS Word 2007. I am facing problem of text overflow. The code I used is: Sub FixParagraph() ' ' FixParagraph Macro ' ' Dim selectedText As String Dim textLength As Integer selectedText = Selection.Text ' If no text is selected, this prevents this subroutine from typing another ' copy of the character following the cursor into the document If Len(selectedText) <= 1 Then Exit Sub End If ' Replace all carriage returns and line feeds in the selected text with spaces selectedText = Replace(selectedText, vbCr, " ") selectedText = Replace(selectedText, vbLf, " ") ' Get rid of repeated spaces Do textLength = Len(selectedText) selectedText = Replace(selectedText, " ", " ") Loop While textLength <> Len(selectedText) ' Replace the selected text in the document with the modified text Selection.TypeText (selectedText) End Sub

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  • Ad-hoc String Manipulation With Visual Studio

    - by Liam McLennan
    Visual studio supports relatively advanced string manipulation via the ‘Quick Replace’ dialog. Today I had a requirement to modify some html, replacing line breaks with unordered list items. For example, I need to convert: Infrastructure<br/> Energy<br/> Industrial development<br/> Urban growth<br/> Water<br/> Food security<br/> to: <li>Infrastructure</li> <li>Energy</li> <li>Industrial development</li> <li>Urban growth</li> <li>Water</li> <li>Food security</li> This cannot be done with a simple search-and-replace but it can be done using the Quick Replace regular expression support. To use regular expressions expand ‘Find Options’, check ‘Use:’ and select ‘Regular Expressions’ Typically, Visual Studio regular expressions use a different syntax to every other regular expression engine. We need to use a capturing group to grab the text of each line so that it can be included in the replacement. The syntax for a capturing group is to replace the part of the expression to be captured with { and }. So my regular expression: {.*}\<br/\> means capture all the characters before <br/>. Note that < and > have to be escaped with \. In the replacement expression we can use \1 to insert the previously captured text. If the search expression had a second capturing group then its text would be available in \2 and so on. Visual Studio’s quick replace feature can be scoped to a selection, the current document, all open documents or every document in the current solution.

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  • Powershell – script all objects on all databases to files

    - by Nigel Rivett
    <# This simple PowerShell routine scripts out all the user-defined functions, stored procedures, tables and views in all the databases on the server that you specify, to the path that you specify. SMO must be installed on the machine (it happens if SSMS is installed) To run - set the servername and path Open a command window and run powershell Copy the below into the window and press enter - it should run It will create the subfolders for the databases and objects if necessary. #> $path = “C:\Test\Script\" $ServerName = "MyServerNameOrIpAddress" [System.Reflection.Assembly]::LoadWithPartialName('Microsoft.SqlServer.SMO') $serverInstance = New-Object ('Microsoft.SqlServer.Management.Smo.Server') $ServerName $IncludeTypes = @(“tables”,”StoredProcedures”,"Views","UserDefinedFunctions") $ExcludeSchemas = @(“sys”,”Information_Schema”) $so = new-object (‘Microsoft.SqlServer.Management.Smo.ScriptingOptions’) $so.IncludeIfNotExists = 0 $so.SchemaQualify = 1 $so.AllowSystemObjects = 0 $so.ScriptDrops = 0 #Script Drop Objects $dbs=$serverInstance.Databases foreach ($db in $dbs) { $dbname = "$db".replace("[","").replace("]","") $dbpath = "$path"+"$dbname" + "\" if ( !(Test-Path $dbpath)) {$null=new-item -type directory -name "$dbname"-path "$path"} foreach ($Type in $IncludeTypes) { $objpath = "$dbpath" + "$Type" + "\" if ( !(Test-Path $objpath)) {$null=new-item -type directory -name "$Type"-path "$dbpath"} foreach ($objs in $db.$Type) { If ($ExcludeSchemas -notcontains $objs.Schema ) { $ObjName = "$objs".replace("[","").replace("]","") $OutFile = "$objpath" + "$ObjName" + ".sql" $objs.Script($so)+"GO" | out-File $OutFile #-Append } } } }

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  • Is there a command-line utility app which can locate a specific block of lines in a text file?

    - by fred.bear
    The text "search and replace" utility programs I've seen, seem to only search on a line-by-line basis... Is there a command-line tool which can locate one block of lines (in a text file), and replace it with another block of lines.? For example: Does the test file file contain this exact group of lines: 'Twas brillig, and the slithy toves Did gyre and gimble in the wabe: All mimsy were the borogoves, And the mome raths outgrabe. 'Beware the Jabberwock, my son! The jaws that bite, the claws that catch! Beware the Jubjub bird, and shun The frumious Bandersnatch!' I want this, so that I can replace multiple lines of text in a file and know I'm not overwriting the wrong lines. I would never replace "The Jabberwocky" (Lewis Carroll), but it makes a novel example :)

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  • Which part of this simple script is breaking internet explorer?

    - by user961627
    I'm writing a simple virtual keyboard for Arabic (indic) digits. Just links that, when clicked, produce the corresponding Unicode Indic character. The following is my HTML, in the body tag: <a href="#" id='start'>Start</a> <div id='vkb' style='padding:20px;font-size:16pt; border:2px solid #eee; width:250px' dir='ltr'> <a class='key' href='#' id='0'>&#1632;</a> <a class='key' href='#' id='1'>&#1633;</a> <a class='key' href='#' id='2'>&#1634;</a> <a class='key' href='#' id='3'>&#1635;</a> <a class='key' href='#' id='4'>&#1636;</a><br /> <a class='key' href='#' id='5'>&#1637;</a> <a class='key' href='#' id='6'>&#1638;</a> <a class='key' href='#' id='7'>&#1639;</a> <a class='key' href='#' id='8'>&#1640;</a> <a class='key' href='#' id='9'>&#1641;</a> <br /> <a href="#" id='stop'>Stop</a> </div> <div id='output' /></div> This is my CSS: a { text-decoration:none; } .key { padding:7px; background-color:#fff; margin:5px; border:2px solid #eee; display:inline-block; } .key:hover { background-color:#eee; } And this is my javascript: <script type="text/javascript" src="js/jquery.js"></script> <script> $(document).ready(function(){ var toprint = ""; $('#vkb').hide(); $('#start').click(function(e){ toprint = ""; $('#vkb').show(); }); $('#stop').click(function(e){ $('#vkb').hide(); ret = ar2ind(toprint); $('#output').text(ret); toprint = ""; }); $('#vkb').click(function(e){ var $key = $(e.target).closest('.key'); var pressed = $key.attr('id'); if(pressed === undefined){ pressed = ""; } toprint = toprint + pressed; }); }); function ar2ind(str) { str = str.replace(/0/g, "?"); str = str.replace(/1/g, "?"); str = str.replace(/2/g, "?"); str = str.replace(/3/g, "?"); str = str.replace(/4/g, "?"); str = str.replace(/5/g, "?"); str = str.replace(/6/g, "?"); str = str.replace(/7/g, "?"); str = str.replace(/8/g, "?"); str = str.replace(/9/g, "?"); return str; } </script> It seems simple enough but it's crashing in IE9. (Might be crashing in earlier versions too but haven't been able to check.)

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  • Manipulating columns of numbers in elisp

    - by ~unutbu
    I have text files with tables like this: Investment advisory and related fees receivable (161,570 ) (71,739 ) (73,135 ) Net purchases of trading investments (93,261 ) (30,701 ) (11,018 ) Other receivables 61,216 (10,352 ) (69,313 ) Restricted cash 20,658 (20,658 ) - Other current assets (39,643 ) 14,752 64 Other non-current assets 71,896 (26,639 ) (26,330 ) Since these are accounting numbers, parenthesized numbers indicate negative numbers. Dashes represent 0 or no number. I'd like to be able to mark a rectangular region such as third column above, call a function (format-column), and automatically have (-73135-11018-69313+64-26330)/1000 sitting in my kill-ring. Even better would be -73.135-11.018-69.313+0.064-26.330 but I couldn't figure out a way to transform 64 -- 0.064. This is what I've come up with: (defun format-column () "format accounting numbers in a rectangular column. format-column puts the result in the kill-ring" (interactive) (let ((p (point)) (m (mark)) ) (copy-rectangle-to-register 0 (min m p) (max m p) nil) (with-temp-buffer (insert-register 0) (goto-char (point-min)) (while (search-forward "-" nil t) (replace-match "" nil t)) (goto-char (point-min)) (while (search-forward "," nil t) (replace-match "" nil t)) (goto-char (point-min)) (while (search-forward ")" nil t) (replace-match "" nil t)) (goto-char (point-min)) (while (search-forward "(" nil t) (replace-match "-" nil t) (just-one-space) (delete-backward-char 1) ) (goto-char (point-min)) (while (search-forward "\n" nil t) (replace-match " " nil t)) (goto-char (point-min)) (kill-new (mapconcat 'identity (split-string (buffer-substring (point-min) (point-max))) "+")) (kill-region (point-min) (point-max)) (insert "(") (yank 2) (goto-char (point-min)) (while (search-forward "+-" nil t) (replace-match "-" nil t)) (goto-char (point-max)) (insert ")/1000") (kill-region (point-min) (point-max)) ) ) ) (global-set-key "\C-c\C-f" 'format-column) Although it seems to work, I'm sure this function is poorly coded. The repetitive calls to goto-char, search-forward, and replace-match and the switching from buffer to string and back to buffer seems ugly and inelegant. My entire approach may be wrong-headed, but I don't know enough elisp to make this more beautiful. Do you see a better way to write format-column, and/or could you make suggestions on how to improve this code?

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  • Regex For Finding Ctypes with Int32

    - by Stefan H
    (Hey all, I am looking for a little regex help... I am trying to find all CType(expression,Int32) s and replace them with CInt(expression) This, however, is proving quite difficult, considering there could be a nested Ctype(expression, Int32) within the regex match. Does anyone have any ideas for how to best go about doing this? Here is what I have now: Dim str As String = "CType((original.Width * CType((targetSize / CType(original.Height, Single)), Single)), Int32)" Dim exp As New Regex("CType\((.+), Int32\)") str = exp.Replace(str, "CInt($1)") But this will match the entire string and replace it. I was thinking of doing a recursive function to find the outer most match, and then work inwards, but that still presents a problem with things like CType(replaceChars(I), Int32)), Chr(CType(replacementChars(I), Int32) Any tips would be appreciated. Input returnString.Replace(Chr(CType(replaceChars(I), Int32)), Chr(CType(replacementChars(I), Int32))) Output: returnString.Replace(Chr(CInt(replaceChars(I))),Chr(CInt(replacementChars(I)))) Edit: Been working on it a little more and have a recursive function that I'm still working out the kinks in. Recursion + regex. it kinda hurts. Private Function FindReplaceCInts(ByVal strAs As String) As String System.Console.WriteLine(String.Format("Testing : {0}", strAs)) Dim exp As New Regex("CType\((.+), Int32\)") If exp.Match(strAs).Success Then For Each match As Match In exp.Matches(strAs) If exp.Match(match.Value.Substring(2)).Success Then Dim replaceT As String = match.Value.Substring(2) Dim Witht As String = FindReplaceCInts(match.Value.Substring(2)) System.Console.WriteLine(strAs.IndexOf(replaceT)) strAs.Replace(replaceT, Witht) End If Next strAs = exp.Replace(strAs, "CInt($1)") End If Return strAs End Function Cheers,

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  • On IE cursor is comming always at start in textarea

    - by pravin
    I am dealing with textarea, and on click of this I am calling one replace function which will remove some specified string in textarea, this is the basic operation. Expected behavior after clicking on textarea 1) At first click : It should remove specified string from textarea Cursor should come at end of string 2) more than one click : - Cursor should come at where ever user clicks in text area Below is my replace function.... function replace(id,transFromDb) { newStr = $("#"+id).val(); var len = null; if(transFromDb == '') { newStr = newStr.replace(Lang.Message27,''); newStr = newStr.replace(Lang.Message28,''); } else { newStr = newStr.replace(Lang.Message28,''); newStr = newStr.replace(Lang.Message27,''); } /* change font weight as bold. */ $("#"+id).css({"fontWeight":"bold"}); $("#"+id).val(newStr); } Assume that Lang.Message is specified string. It's working above behavior with FF. Facing issue on IE, it always keep cursor position at first. Please provide any solution.... Thanks in Adavance Pravin

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  • I want to find the span tag beween the LI tag and its attributes but no luck.

    - by Mahesh
    I want to find the span tag beween the LI tag and its attributes. Trying with beautful soap but no luck. Details of my code. Is any one point me right methodlogy In this this code, my getId function should return me id = "0_False-2" Any one know right method? from BeautifulSoup import BeautifulSoup as bs import re html = '<ul>\ <li class="line">&nbsp;</li>\ <li class="folder-open-last" id="0">\ <img style="float: left;" class="trigger" src="/media/images/spacer.gif" border="0">\ <span class="text" id="0_False">NOC</span><ul style="display: block;"><li class="line">&nbsp;</li><li class="doc" id="1"><span class="active text" id="0_False-1">PNQAIPMS1</span></li><li class="line">&nbsp;</li><li class="doc-last" id="2"><span class="text" id="0_False-2">PNQAIPMS2</span></li><li class="line-last"></li></ul></li><li class="line-last"></li>\ </ul>' def getId(html, txt): soup = bs(html) soup.findAll('ul',recursive=False) head = soup.contents[0] temp = head elements = {} while True: # It temp is None that means no HTML tags are available if temp == None: break #print temp if re.search('li', str( temp)) != None: attr = str(temp.attrs).encode('ascii','ignore') attr = attr.replace(' ', '') attr = attr.replace('[', '') attr = attr.replace(']', '') attr = attr.replace(')', '') attr = attr.replace('(', '') attr = attr.replace('u\'', '') attr = attr.replace('\'', '') attr = attr.split(',') span = str(temp.text) if span == txt: return attr[3] temp = temp.next else: temp = temp.next id = getId(html,"PNQAIPMS2") print "ID = " + id

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  • How to append \line into RTF using RichTextBox control

    - by Steve Sheldon
    When using the Microsoft RichTextBox control it is possible to add new lines like this... richtextbox.AppendText(System.Environment.NewLine); // appends \r\n However, if you now view the generated rtf the \r\n characters are converted to \par not \line How do I insert a \line control code into the generated RTF? What does't work: Token Replacement Hacks like inserting a token at the end of the string and then replacing it after the fact, so something like this: string text = "my text"; text = text.Replace("||" "|"); // replace any '|' chars with a double '||' so they aren't confused in the output. text = text.Replace("\r\n", "_|0|_"); // replace \r\n with a placeholder of |0| richtextbox.AppendText(text); string rtf = richtextbox.Rtf; rtf.Replace("_|0|_", "\\line"); // replace placeholder with \line rtf.Replace("||", "|"); // set back any || chars to | This almost worked, it breaks down if you have to support right to left text as the right to left control sequence always ends up in the middle of the placeholder. Sending Key Messages public void AppendNewLine() { Keys[] keys = new Keys[] {Keys.Shift, Keys.Return}; SendKeys(keys); } private void SendKeys(Keys[] keys) { foreach(Keys key in keys) { SendKeyDown(key); } } private void SendKeyDown(Keys key) { user32.SendMessage(this.Handle, Messages.WM_KEYDOWN, (int)key, 0); } private void SendKeyUp(Keys key) { user32.SendMessage(this.Handle, Messages.WM_KEYUP, (int)key, 0); } This also ends up being converted to a \par Is there a way to post a messaged directly to the msftedit control to insert a control character? I am totally stumped, any ideas guys? Thanks for your help!

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  • Not allow more than 5 digits after decimal. in on javascript "OnKeyUp"?

    - by James123
    I have a javascript code for textbox that will put commas on in digits like (11,23,233) mTextbox.Attributes.Add("OnKeyUp", "javascript:this.value=Comma(this.value);") function Comma(Num) { Num += ''; Num = Num.replace(',', ''); Num = Num.replace(',', ''); Num = Num.replace(',', ''); Num = Num.replace(',', ''); Num = Num.replace(',', ''); Num = Num.replace(',', ''); x = Num.split('.'); x1 = x[0]; x2 = x.length > 1 ? '.' + x[1] : ''; var rgx = /(\d+)(\d{3})/; while (rgx.test(x1)) x1 = x1.replace(rgx, '$1' + ',' + '$2'); return x1 + x2; } Now same here I need to restrict user to enter not morethan 5 digits after decimal (ex: Allow: 12,23,221.34323 Not Allow: 12,23,232.232423 I can change above javascript to work that?

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  • i need some help with my vb.net codes..plzz

    - by akmalizhar
    currently i need to develop an application that can exctract information from few website.. this is what i have done up until now.. Imports System Imports System.Text.RegularExpressions Imports System.IO Imports System.Net Imports System.Web Imports System.Data.SqlClient Imports System.Threading Imports System.Data.DataSet Imports System.Data.OleDb Module module1 Dim url As String Dim hotelName As String = "" Sub Main() Dim url As String = "" Console.Write("enter url: ") url = Console.ReadLine() extractor(url) End Sub Public Sub extractor(ByVal url As String) Dim strConn As String = "Data Source = localhost; Initial Catalog = knowledgeBase; Integrated Security = True; Connection Timeout = 0;" Dim conn As SqlConnection = New SqlConnection(strConn) conn.Open() Dim strSQL1 As String Dim matchStn1 As String = "" Dim matchstn2 As String = "" Dim matchstn3 As String = "" Dim matchstn4 As String = "" Dim matchstn5 As String = "" Dim matchstn6 As String = "" Dim matchstn7 As String = "" Dim matchstn8 As String = "" Dim matchstn9 As String = "" Dim matchstn10 As String = "" Dim objRequest As WebRequest = HttpWebRequest.Create(url) Dim objResponse As WebResponse = objRequest.GetResponse() Dim objStreamReader As New StreamReader(objResponse.GetResponseStream()) Dim strpage As String = objStreamReader.ReadToEnd Dim RegExStr As String = "<[^>]*>" Dim R As New Regex(RegExStr) Dim sourcestring As String = strpage Dim re As Regex = New Regex("<h2 class=""name hotel""[^>]*>[\s\S]+?</h2>") Dim mc As MatchCollection = re.Matches(sourcestring) Dim mIdx As Integer = 0 For Each m As Match In mc For groupIdx As Integer = 0 To m.Groups.Count - 1 matchStn1 = m.Groups(groupIdx).Value matchStn1 = R.Replace(matchStn1, " ") matchStn1 = matchStn1.Trim() Next mIdx = mIdx + 1 Next Dim re9 As Regex = New Regex("<li class=""cuisine""[^>]*>[^>]+</li>") Dim mc9 As MatchCollection = re9.Matches(sourcestring) Dim mIdx9 As Integer = 0 For Each m As Match In mc9 For groupIdx As Integer = 0 To m.Groups.Count - 1 matchstn9 = m.Groups(groupIdx).Value matchstn9 = R.Replace(matchstn9, " ") matchstn9 = matchstn9.Trim() Next mIdx = mIdx + 1 Next Dim re2 As Regex = New Regex("<span class=""street-address""[^>]*>[^>]+</span>") Dim mc2 As MatchCollection = re2.Matches(sourcestring) Dim mIdx2 As Integer = 0 For Each m As Match In mc2 For groupIdx As Integer = 0 To m.Groups.Count - 1 matchstn2 = m.Groups(groupIdx).Value matchstn2 = R.Replace(matchstn2, " ") matchstn2 = matchstn2.Trim() Next mIdx2 = mIdx2 + 1 Next Dim re3 As Regex = New Regex("<span class=""locality""[^>]*>[\s\S]+?</span>") Dim mc3 As MatchCollection = re3.Matches(sourcestring) Dim mIdx3 As Integer = 0 For Each m As Match In mc3 For groupIdx As Integer = 0 To m.Groups.Count - 1 matchstn3 = m.Groups(groupIdx).Value matchstn3 = R.Replace(matchstn3, " ") matchstn3 = matchstn3.Trim() Next mIdx3 = mIdx3 + 1 Next Dim re4 As Regex = New Regex("<span property=""v:postal-code""[^>]*>[\s\S]+?</span>") Dim mc4 As MatchCollection = re4.Matches(sourcestring) Dim mIdx4 As Integer = 0 For Each m As Match In mc4 For groupIdx As Integer = 0 To m.Groups.Count - 1 matchstn4 = m.Groups(groupIdx).Value matchstn4 = R.Replace(matchstn4, " ") matchstn4 = matchstn4.Trim() Next mIdx4 = mIdx4 + 1 Next Dim re5 As Regex = New Regex("<span class=""country-name""[^>]*>[\s\S]+?</span>") Dim mc5 As MatchCollection = re5.Matches(sourcestring) Dim mIdx5 As Integer = 0 For Each m As Match In mc5 For groupIdx As Integer = 0 To m.Groups.Count - 1 matchstn5 = m.Groups(groupIdx).Value matchstn5 = R.Replace(matchstn5, " ") matchstn5 = matchstn5.Trim() Next mIdx5 = mIdx5 + 1 Next Dim re10 As Regex = New Regex("<address class=""adr""[^>]*>[\s\S]+?</address>") Dim mc10 As MatchCollection = re10.Matches(sourcestring) Dim mIdx10 As Integer = 0 For Each m As Match In mc10 For groupIdx As Integer = 0 To m.Groups.Count - 1 matchstn10 = m.Groups(groupIdx).Value matchstn10 = R.Replace(matchstn10, " ") matchstn10 = matchstn10.Trim() strSQL1 = "insert into infoRestaurant (nameRestaurant, cuisine, streetAddress, locality, postalCode, countryName, addressFull, tel, attractionType) values (N" & _ FormatSqlParam(matchStn1) & ",N" & _ FormatSqlParam(matchstn9) & ",N" & _ FormatSqlParam(matchstn2) & ",N" & _ FormatSqlParam(matchstn3) & ",N" & _ FormatSqlParam(matchstn4) & ",N" & _ FormatSqlParam(matchstn5) & ",N" & _ FormatSqlParam(matchstn10) & ",N" & _ FormatSqlParam(matchstn6) & ",N" & _ FormatSqlParam(matchstn7) & ")" Dim objCommand1 As New SqlCommand(strSQL1, conn) objCommand1.ExecuteNonQuery() Next mIdx4 = mIdx4 + 1 Next Dim re6 As Regex = New Regex("<span class=""tel""[^>]*>[\s\S]+?</span>") Dim mc6 As MatchCollection = re6.Matches(sourcestring) Dim mIdx6 As Integer = 0 For Each m As Match In mc6 For groupIdx As Integer = 0 To m.Groups.Count - 1 matchstn6 = m.Groups(groupIdx).Value matchstn6 = R.Replace(matchstn6, " ") matchstn6 = matchstn6.Trim() Next mIdx6 = mIdx6 + 1 Next Dim re7 As Regex = New Regex("<div><b>Attraction type:[^>]*>[\s\S]+?</div>") Dim mc7 As MatchCollection = re7.Matches(sourcestring) Dim mIdx7 As Integer = 0 For Each m As Match In mc7 For groupIdx As Integer = 0 To m.Groups.Count - 1 matchstn7 = m.Groups(groupIdx).Value matchstn7 = R.Replace(matchstn7, " ") matchstn7 = matchstn7.Trim() Next mIdx7 = mIdx7 + 1 Next Dim re8 As Regex = New Regex("(?=<p id).*(?<=</p>)") Dim mc8 As MatchCollection = re8.Matches(sourcestring) Dim mIdx8 As Integer = 0 For Each m As Match In mc8 For groupIdx As Integer = 0 To m.Groups.Count - 1 matchstn8 = m.Groups(groupIdx).Value matchstn8 = R.Replace(matchstn8, " ") matchstn8 = matchstn8.Trim() Dim strSQL2 As String = "insert into feedBackRestaurant (feedBackView) values(N" + FormatSqlParam(matchstn8) + ")" Dim objCommand2 As New SqlCommand(strSQL2, conn) objCommand2.ExecuteNonQuery() Next mIdx8 = mIdx8 + 1 Next objStreamReader.Close() conn.Close() End Sub Public Function FormatSqlParam(ByVal strParam As String) As String Dim newParamFormat As String If strParam = String.Empty Then newParamFormat = "'" & "NA" & "'" Else newParamFormat = strParam.Trim() newParamFormat = "'" & newParamFormat.Replace("'", "''") & "'" End If Return newParamFormat End Function End Module ---problems-- problem that i face are 1. the database foreign key is not working here..someone told me that need some codes to be added..but i dunno how. 2. the data repeats as i run the application. i guest it require update database function.but i hv no idea how. 3. i have to add in multithreading function as well..and last, how to make my application is flexible eventhough the HTML code changes..can anyone help me??plzzz website that i need to extract is http://www.tripadvisor.com/Tourism-g293951-Malaysia-Vacations.html i need the information about hotel, restaurant and attraction place..plzz..i need some help here..

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