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  • ODBC: when is the best time to create my database?

    - by mawg
    I have a windows program which generates PGP forms which will be filled in later. Those PHP forms will populate a database. It looks very much like MySql, but I can't be certain, so let's call it ODBC. And, yes, it does have to be a windows program. There will also be PHP forms which query the database - examine which tables and fields it contains and then generates forms which can be used to search the database (e.g, it finds a table with fields "employee_name", etc and generates a form which lets you search based on employee name. Let's call that design time and run time. At design time, some manager or IT guy or similar gets to define the nature of the database and at runtime 1) a worker fills in the form daily and 2) management can extract reports. Here's my question: given that the database is defined at "design time" (and populated at run time), where and how is best to do so? 1 I could use an ODBC interface from the windows program, but I am having difficulty finding something good to work with Delphi. Things like ADO and firebird tend to expect you to already have a database and allow you to manipulate it, but I can find no code example of how to create a database and some tables, so ... 2 I could used DOS commands from Delphi in my windows program. I just tried and got a response to MySql --version, but am not sure if MySql etc are more interactive. That is, can I use a script file or a very long stacked command with semicolons and returns separating? e.g 'CREATE DATABASE db; CREATE TABLE t1;' 3) Since the best way to work with databases seems to be PHP, perhaps my windows program could spit out a PHP page which would, when run in a browser, create the database. I have tried to make this as uncomplicated as I can, but please feel free to ask questions. It may be that there are several valid ways, but there is probably one 'better' solution in terms of ease of implementation or maintenance. Better scratch option 3. What if the user later wants to come back and have the windows program change the input form? It needs to update the database too.

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  • GET request, iOS

    - by phnmnn
    I need to do this GET request: http://api.testmy.co.il/api/sync?BID=1049&ClientCode=3847&Discount=2.34&Service=0&Items=[{"Name":"Tax","Price":"2.11","Quantity":"1","SerialID":"1","Remarks":"","Toppings":""}]&Payments=[] In browser I get response: { "Success":true, "Atava":[], "Pending":[], "CallWaiter":false } But in iOS it not work. i try: NSString *requestedURL=[NSString stringWithFormat:@"http://api.testmy.co.il/api/sync?BID=%i&ClientCode=%i&Discount=2.34&Service=0&Items=[{\"Name\":\"Tax\",\"Price\":\"2.11\",\"Quantity\":\"1\",\"SerialID\":\"1\",\"Remarks\":\"\",\"Toppings\":\"\"}]&Payments=[]",BID,num]; NSURL *url = [NSURL URLWithString:requestedURL]; NSURLResponse *response; NSData *GETReply = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:nil]; NSString *theReply = [[NSString alloc] initWithBytes:[GETReply bytes] length:[GETReply length] encoding: NSASCIIStringEncoding]; NSLog(@"Reply: %@", theReply); OR NSString *requestedURL=[NSString stringWithFormat:@"http://api.testmy.co.il/api/sync?BID=%i&ClientCode=%i&Discount=2.34&Service=0&Items=[{'Name':'Tax','Price':'2.11','Quantity':'1','SerialID':'1','Remarks':'','Toppings':''}]&Payments=[]",BID,num]; OR NSMutableDictionary *params = [[NSMutableDictionary alloc] init]; [params setObject:@"Tax" forKey:@"Name"]; [params setObject:@"2.11" forKey:@"Price"]; [params setObject:@"1" forKey:@"Quantity"]; [params setObject:@"1" forKey:@"SerialID"]; [params setObject:@"" forKey:@"Remarks"]; [params setObject:@"" forKey:@"Toppings"]; NSData *jsonData = nil; NSString *jsonString = nil; if([NSJSONSerialization isValidJSONObject:params]) { jsonData = [NSJSONSerialization dataWithJSONObject:params options:0 error:nil]; jsonString = [[NSString alloc]initWithData:jsonData encoding:NSUTF8StringEncoding]; NSLog(@"%@",jsonString); } NSString *get=[NSString stringWithFormat: @"&Items=%@", jsonString]; NSData *getData = [get dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES]; NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL:url]; [request setHTTPMethod:@"GET"]; [request setTimeoutInterval:8]; [request setHTTPBody:getData]; [request setValue:@"application/json;charset=UTF-8" forHTTPHeaderField:@"Content-Type"]; nothing doesn't work. How to fix it? Sorry for bad english.

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  • Using a large list of terms, search through page text and replace words with links

    - by dunc
    A while ago I posted this question asking if it's possible to convert text to HTML links if they match a list of terms from my database. I have a fairly huge list of terms - around 6000. The accepted answer on that question was superb, but having never used XPath, I was at a loss when problems started occurring. At one point, after fiddling with code, I somehow managed to add over 40,000 random characters to our database - the majority of which required manual removal. Since then I've lost faith in that idea and the more simple PHP solutions simply weren't efficient enough to deal with the amount of data and the quantity of terms. My next attempt at a solution is to write a JS script which, once the page has loaded, retrieves the terms and matches them against the text on a page. This answer has an idea which I'd like to attempt. I would use AJAX to retrieve the terms from the database, to build an object such as this: var words = [ { word: 'Something', link: 'http://www.something.com' }, { word: 'Something Else', link: 'http://www.something.com/else' } ]; When the object has been built, I'd use this kind of code: //for each array element $.each(words, function() { //store it ("this" is gonna become the dom element in the next function) var search = this; $('.message').each( function() { //if it's exactly the same if ($(this).text() === search.word) { //do your magic tricks $(this).html('<a href="' + search.link + '">' + search.link + '</a>'); } } ); } ); Now, at first sight, there is a major issue here: with 6,000 terms, will this code be in any way efficient enough to do what I'm trying to do?. One option would possibly be to perform some of the overhead within the PHP script that the AJAX communicates with. For instance, I could send the ID of the post and then the PHP script could use SQL statements to retrieve all of the information from the post and match it against all 6,000 terms.. then the return call to the JavaScript could simply be the matching terms, which would significantly reduce the number of matches the above jQuery would make (around 50 at most). I have no problem with the script taking a few seconds to "load" on the user's browser, as long as it isn't impacting their CPU usage or anything like that. So, two questions in one: Can I make this work? What steps can I take to make it as efficient as possible? Thanks in advance,

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  • jQuery .load(), don't show new content until images loaded

    - by Jarred
    Hi. I have been working on a jQuery photo slideshow. It scales the images to the browser size, and slides them left and right. There is no pre-determined size or aspect ratio, the script does everything on the fly. It requires that all images be fully loaded, so it can custom resize each individual image based on it's own aspect ratio ( width():height(), etc ), calculate the width of containing div, and calculate the slide distance from one image to another. As a stand-alone, it works pretty well (despite my lack of skills)! I simply hide the slideshow containing div at (document).ready, allow the images to load, then run the slideshow prep scripts at (window).load. Once this is done, it only then makes the slideshow divs, images, etc appear, properly sized, positioned and ready to roll. The ultimate goal is to be able to load in any number of slideshows without refreshing the page. The point of this is to be able to play uninterrupted background music. I know music on websites is annoying, but the target market likes it, a lot! I am using (target).load(page.php .element, function prepInsertNewShow() { //Prepare slideshow resizeImages(); slideArray(); //Show slideshow (target).fadeIn(); }); and it definitely works! The problem is that I cannot find a way to hold off on preparing and showing the new content until the images have finished loading. It is running the slideshow prep scripts (which are totally dependent on the images being fully loaded), before the images are loaded. This results in a completely jacked up show! What I want to do is this - (target).load(page.php .element, function prepInsertNewShow() { //Wait until images are loaded $('img').load( function() { //Prepare slideshow resizeImages(); slideArray(); //Show slideshow (target).fadeIn(); } }); But this doesn't seem to work, the new content is never shown. You can see a live version here. The initial gallery loads correctly, everything looks good. The only nav link that works is Galleries Engagement, which will load a new show (a containing div with multiple <img> tags). You will see that the images are not centered, the containing div and slide distances are much too small, as they were calculated using images that were not actually loaded. Is there any way I can delay handling and showing new content until it is fully loaded? Any suggestions would be most appreciated, thanks for your time! PS - It just occurred to me while typing this that a decent solution may be to insert "width=x" height="x" into the <img> tags, so the script can work from those values, even if the images have not loaded...hmm...

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  • How to avoid my this facebook app api login page?

    - by user1035140
    I got a problem regrading with my apps which is once I go to my apps, it sure will show me a login page instead of allow page? it always display the login page 1st then only display allow page, I had tried other apps, if I am 1st time user, It sure will appear the allow page only, it did not show me the login page. my question is how to I avoid my login page direct go to allow page? here is my login page picture here is my apps link https://apps.facebook.com/christmas_testing/ here is my facebook php jdk api coding <?php $fbconfig['appid' ] = "XXXXXXXXXXXXX"; $fbconfig['secret'] = "XXXXXXXXXXXXX"; $fbconfig['baseUrl'] = "myserverlink"; $fbconfig['appBaseUrl'] = "http://apps.facebook.com/christmas_testing/"; if (isset($_GET['code'])){ header("Location: " . $fbconfig['appBaseUrl']); exit; } if (isset($_GET['request_ids'])){ //user comes from invitation //track them if you need header("Location: " . $fbconfig['appBaseUrl']); } $user = null; //facebook user uid try{ include_once "facebook.php"; } catch(Exception $o){ echo '<pre>'; print_r($o); echo '</pre>'; } // Create our Application instance. $facebook = new Facebook(array( 'appId' => $fbconfig['appid'], 'secret' => $fbconfig['secret'], 'cookie' => true, )); //Facebook Authentication part $user = $facebook->getUser(); $loginUrl = $facebook->getLoginUrl( array( 'scope' => 'email,publish_stream,user_birthday,user_location,user_work_history,user_about_me,user_hometown' ) ); if ($user) { try { // Proceed knowing you have a logged in user who's authenticated. $user_profile = $facebook->api('/me'); } catch (FacebookApiException $e) { //you should use error_log($e); instead of printing the info on browser d($e); // d is a debug function defined at the end of this file $user = null; } } if (!$user) { echo "<script type='text/javascript'>top.location.href = '$loginUrl';</script>"; exit; } //get user basic description $userInfo = $facebook->api("/$user"); function d($d){ echo '<pre>'; print_r($d); echo '</pre>'; } ?

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  • Rails controller not rendering correct view when form is force-submitted by Javascript

    - by whazzmaster
    I'm using Rails with jQuery, and I'm working on a page for a simple site that prints each record to a table. The only editable field for each record is a checkbox. My goal is that every time a checkbox is changed, an ajax request updates that boolean attribute for the record (i.e., no submit button). My view code: <td> <% form_remote_tag :url => admin_update_path, :html => { :id => "form#{lead.id}" } do %> <%= hidden_field :lead, :id, :value => lead.id %> <%= check_box :lead, :contacted, :id => "checkbox"+lead.id.to_s, :checked => lead.contacted, :onchange => "$('#form#{lead.id}').submit();" %> <% end %> </td> In my routes.rb, admin_update_path is defined by map.admin_update 'update', :controller => "admin", :action => "update", :method => :post I also have an RJS template to render back an update. The contents of this file is currently just for testing (I just wanted to see if it worked, this will not be the ultimate functionality on a successful save)... page << "$('#checkbox#{@lead.id}').hide();" When clicked, the ajax request is successfully sent, with the correct params, and the action on the controller can retrieve the record and update it just fine. The problem is that it doesn't send back the JS; it changes the page in the browser and renders the generated Javascript as plain text rather than executing it in-place. Rails does some behind-the-scenes stuff to figure out if the incoming request is an ajax call, and I can't figure out why it's interpreting the incoming request as a regular web request as opposed to an ajax request. I may be missing something extremely simple here, but I've kind-of burned myself out looking so I thought I'd ask for another pair of eyes. Thanks in advance for any info!

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  • Stop running this script, IE7 using PHP

    - by Jomel Dicen
    I incorporate javascript in my PHP program: Try to check my codes. It loops depend on the number of records in database. for instance: $counter = 0; foreach($row_value as $data): echo $this->javascript($counter, $data->exrate, $data->tab); endforeach; private function javascript($counter=NULL, $exrate=NULL, $tab=NULL){ $js = " <script type='text/javascript'> $(function () { var textBox0 = $('input:text[id$=quantity{$counter}]').keyup(foo); var textBox1 = $('input:text[id$=mc{$counter}]').keyup(foo); var textBox2 = $('input:text[id$=lc{$counter}]').keyup(foo); function foo() { var value0 = textBox0.val(); var value1 = textBox1.val(); var value2 = textBox2.val(); var sum = add(value1, value2) * (value0 * {$exrate}); $('input:text[id$=result{$counter}]').val(parseFloat(sum).toFixed(2)); // Compute Total Quantity var qtotal = 0; $('.quantity{$tab}').each(function() { qtotal += Number($(this).val()); }); $('#tquantity{$tab}').text(qtotal); // Compute MC UNIT var mctotal = 0; $('.mc{$tab}').each(function() { mctotal += Number($(this).val()); }); $('#tmc{$tab}').text(mctotal); // Compute LC UNIT var lctotal = 0; $('.lc{$tab}').each(function() { lctotal += Number($(this).val()); }); $('#tlc{$tab}').text(lctotal); // Compute Result var result = 0; $('.result{$tab}').each(function() { result += Number($(this).val()); }); $('#tresult{$tab}').text(result); } function add() { var sum = 0; for (var i = 0, j = arguments.length; i < j; i++) { if (IsNumeric(arguments[i])) { sum += parseFloat(arguments[i]); } } return sum; } function IsNumeric(input) { return (input - 0) == input && input.length > 0; } }); </script> "; return $js; } When I running this on IE this message is always annoying me " Stop running this script? A script on this page is causing your web browser to run slowly. If it continues to run, your computer might become unresponsive." but in firefox it's functioning well.

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  • Submitting form in php file accessed by Ajax?

    - by dronnoc
    Hi people, I am trying to figure out how to submit a form in a page being accessed by Ajax? here are some code snippets to help demonstrate what i am trying to say. HTML BODY - THIS IS WHAT THE USER WILL SEE. <html> <head> <script language="javascript" src="linktoajaxfile.js"> </head> <body onLoad="gotoPage(0)"> <div id="fillThis"> </div> </body> </html> AJAX FILE var xmlhttp function gotoPage(phase) { xmlhttp=GetXmlHttpObject(); if (xmlhttp==null) { alert ("Your browser does not support AJAX!"); return; } var url="pageofstuffce.php"; url=url+"?stg="+phase; url=url+"&sid="+Math.random(); xmlhttp.onreadystatechange=stateChanged; xmlhttp.open("GET",url,true); xmlhttp.send(null); } function stateChanged() { if (xmlhttp.readyState==4) { document.getElementById("fillThis").innerHTML=xmlhttp.responseText; } } function GetXmlHttpObject() { if (window.XMLHttpRequest) { // code for IE7+, Firefox, Chrome, Opera, Safari return new XMLHttpRequest(); } if (window.ActiveXObject) { // code for IE6, IE5 return new ActiveXObject("Microsoft.XMLHTTP"); } return null; } PAGE OF DATA <?php $stage = $_GET['stg']; if($stage == 0) { echo '<a onClick="gotoPage(1)">click me</a>'; } elseif($stage == 1) { <form> <input type="text" name="name"> <input type="submit" name="submit"> </form> } elseif(somehow can reach here) { show data from form. } ?> Can anyone perhaps help me get past the form and display the data in the same page? Also, i have looked around, and i don't think anything around has what i need... correct me if i'm wrong though :) Thanks in advance, and i hope i didn't put in too much detail :) Dronnoc EDIT Forgot to mention what I've tried; I have tried submitting the form to itself (same file) and that destroyed the ajax link, and opened the page. i have also tried just having the button move the page onto another step, but the $_POST variable is empty... i am at a loss, so does anyone else have any ideas?

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  • May be an IE z-index bug?

    - by baikaishiuc
    Below is my code. when open the page in ie browser, then select the text in div, the text will be replaced by some shadow quad blank . If you delete a line z-index:0, in css class test1, the ie will perform correctly. In my project , the z-index must be set greater than zero, so I couldn't delete the line. I found a solution is to set bg_img.filter = "" when pannel.z-index greater than 0, then ie will also working good. But unfortunately, the bg_img.filter.alpha must be set, too. So how could I do? test .test1 { position:absolute; background:#ffffff; left:20px; top:20px; border:1px solid; width:198px; height:500px; filter: progid:DXImageTransform.Microsoft.Shadow(color="#999999", Direction=135, Strength=5); z-index:0; } </style> <script> function init () { var pannel = document.createElement ('div'); var bg_img = document.createElement ('div'); var head = document.createElement ('div'); pannel.setAttribute('class', 'test1'); pannel.setAttribute('className', 'test1'); bg_img.style.cssText = "position:relative;left:0px;top:0px;" + "width:198px;" + "height:500px;" + "filter:alpha(opacity=100);"; head.style.cssText = "position:absolute;" + "left:0px;" + "top:0px;" + "width:180px;" + "height:20px;"; document.body.appendChild (pannel); pannel.appendChild(bg_img); pannel.appendChild(head); head.innerHTML = "<div>yusutechasdf</div><div>innerhtml</div>" } </script>

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  • problem with logout script in php

    - by user225269
    I'm a beginner in php, and I am trying to create a login and logout. But I am having problems in logging out. My logout just calls for the login form which is this: <? session_start(); session_destroy(); ?> <table width="300" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC"> <tr> <form name="form1" method="post" action="checklogin.php"> <td> <table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF"> <tr> <td colspan="3"><strong>Member Login </strong></td> </tr> <tr> <td width="78">Username</td> <td width="6">:</td> <td width="294"><input name="myusername" type="text" id="myusername"></td> </tr> <tr> <td>Password</td> <td>:</td> <td><input name="mypassword" type="text" id="mypassword"></td> </tr> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login"></td> </tr> </table> </td> </form> </tr> </table> My problem is, when I try to press the back button in the browser. Whoever user is using it can still access what is not supposed to be accessed when a user hasn't logged in. Do I need to add a code on the user page? I have this code on the user page: <? session_start(); if(!session_is_registered(myusername)){ header("location:main_login.php"); } ?> What can you recommend that I would do so that a script will prompt to enter the username and password again when a user clicks on the back button.

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  • How can I make Google Maps icon to always appear in the center of map - when clicked?

    - by JHM_67
    For simplicity sake, lets use the XML example on Econym's site. http://econym.org.uk/gmap/example_map3.htm Once clicked, I would like icon balloon to be displayed in the middle of the map. What might I need to add to Mike's code to get this to work? I apologize for asking a lot.. Thanks in advance. <script type="text/javascript"> //<![CDATA[ if (GBrowserIsCompatible()) { side_bar var side_bar_html = ""; var gmarkers = []; function createMarker(point,name,html) { var marker = new GMarker(point); GEvent.addListener(marker, "click", function() { marker.openInfoWindowHtml(html); }); gmarkers.push(marker); side_bar_html += '<a href="javascript:myclick(' + (gmarkers.length-1) + ')">' + name + '<\/a><br>'; return marker; } function myclick(i) { GEvent.trigger(gmarkers[i], "click"); } var map = new GMap2(document.getElementById("map")); map.addControl(new GLargeMapControl()); map.addControl(new GMapTypeControl()); map.setCenter(new GLatLng( 43.907787,-79.359741), 9); GDownloadUrl("example.xml", function(doc) { var xmlDoc = GXml.parse(doc); var markers = xmlDoc.documentElement.getElementsByTagName("marker"); for (var i = 0; i < markers.length; i++) { // obtain the attribues of each marker var lat = parseFloat(markers[i].getAttribute("lat")); var lng = parseFloat(markers[i].getAttribute("lng")); var point = new GLatLng(lat,lng); var html = markers[i].getAttribute("html"); var label = markers[i].getAttribute("label"); var marker = createMarker(point,label,html); map.addOverlay(marker); } document.getElementById("side_bar").innerHTML = side_bar_html; }); } else { alert("Sorry, the Google Maps API is not compatible with this browser"); } //]]> </script>

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  • Hot to implement grails server-side-triggered dialog, or how to break out of update region after AJA

    - by werner5471
    In grails, I use the mechanism below in order to implement what I'd call a conditional server-side-triggered dialog: When a form is submitted, data must first be processed by a controller. Based on the outcome, there must either be a) a modal Yes/No confirmation in front of the "old" screen or b) a redirect to a new controller/view replacing the "old" screen (no confirmation required). So here's my current approach: In the originating view, I have a <g:formRemote name="requestForm" url="[controller:'test', action:'testRequest']", update:"dummyRegion"> and a <span id="dummyRegion"> which is hidden by CSS When submitting the form, the test controller checks if a confirmation is necessary and if so, renders a template with a yui-based dialog including Yes No buttons in front of the old screen (which works fine because the dialog "comes from" the dummyRegion, not overwriting the page). When Yes is pressed, the right other controller & action is called and the old screen is replaced, if No is pressed, the dialog is cancelled and the "old" screen is shown again without the dialog. Works well until here. When submitting the form and test controller sees that NO confirmation is necessary, I would usually directly redirect to the right other controller & action. But the problem is that the corresponding view of that controller does not appear because it is rendered in the invisble dummyRegion as well. So I currently use a GSP template including a javascript redirect which I render instead. However a javascript redirect is often not allowed by the browser and I think it's not a clean solution. So (finally ;-) my question is: How do I get a controller redirect to cause the corresponding view to "break out" of my AJAX dummyRegion, replacing the whole screen again? Or: Do you have a better approach for what I have in mind? But please note that I cannot check on the client side whether the confirmation is necessary, there needs to be a server call! Also I'd like to avoid that the whole page has to be refreshed just for the confirmation dialog to pop up (which would also be possible without AJAX). Thanks for any hints!

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  • Create table with PHP and populate from MySQL

    - by typoknig
    Hi all, I am creating a table to display on a web page and that table is populated from data in a MySQL database. I am trying to do a couple of things that are making it difficult for me. First I am trying to have call the PHP code that exists in a separate file in HTML via JavaScript. I think I have that working right but I am not 100% sure (because the table will not display). I think it is working right because some of the code for the table (which is in the PHP file) displays in FireBug. Second I am trying to make it so the rows alternate colors for easy viewing too. My PHP code so far is below. The table does not display at all in any browser. $query = "SELECT * FROM employees"; $result = mysql_query($query); $num = mysql_num_rows($result); echo '<table>'; for ($i = 0; $i < $num; $i++){ $row = mysql_fetch_array($result); $id = $row['id']; $l_name = $row['l_name']; $f_name = $row['f_name']; $ssn = $row['ssn']; $class = (($i % 2) == 0) ? "table_odd_row" : "table_even_row"; echo "<tr>"; echo "<td class=" . $class . ">$wrap_id</td>"; echo "<td class=" . $class . ">$wrap_l_name</td>"; echo "<td class=" . $class . ">$wrap_f_name</td>"; echo "<td class=" . $class . ">$wrap_ssn</td>"; echo "</tr>"; } echo '</table>'; mysql_close($link); }

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  • Is it possible to make this Flex/Flash application safe?

    - by Frank
    I'm back with another Flex/Flash security question. I've already received some help from the community on this topic, but I'm still not quite sure this is the best way to do. Here's the thing. A flex web app, a lot of users (1000+), custom configuration of the application depending of the user group. Can I make this thing safe... or safer. For the moment, when a user comes to the application, there is only one configuration possible, but for the next version we've implented a multi-configuration protocol, this way : 1. The user connect to Default.aspx, server code process the windows credentials (whe are on intranet) and give the correct xml configuration file. 2. The flex app loads with the xml conf file as a flashvar and then the app 'builds' itself with the content of the xml file. As we know, since this is a flex application the swf is downloaded on the client computer and the xml file too. If more than one user connects to the app, from the same computer, the can possibly see the other xml file in the windows temp folder. The current directory of the application looks that way : Web site |-> default.aspx |-> index.swf |-> configAdmin.xml |-> configUserType1.xml |-> configUserType2.xml |-> com |-> a lot of swf and xml files I was first thinking making another directory (without read access for the client) containing all the configurations xml files, picking the right one, copying it to the client and deleting it afterwards. But it seems like I must let know the user know when downloading/deleting content on it's computer... I'm running out of ideas, so I hope you have some great ones. It's there are some design flaws (in the way the app is build, not in Flash :p) please share. I'm always looking forward to improve. Thanks Update : In browser Flash/Flex (without AIR that is) doesn't allow deleting file localy silently (on the client computer, where the application is). It's also not yet possible to get session data.

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  • How dangerous is e.preventDefault();, and can it be replaced by keydown/mousedown tracking?

    - by yc
    I'm working on a tracking script for a fairly sophisticated CRM for tracking form actions in Google Analytics. I'm trying to balance the desire to track form actions accurately with the need to never prevent a form from not working. Now, I know that doing something like this doesn't work. $('form').submit(function(){ _gaq.push('_trackEvent', 'Form', 'Submit', $(this).attr('action')) }); The DOM unloads before this has a chance to process. So, a lot of sample code recommends something like this: $('form').submit(function(e){ e.preventDefault(); var form = this; _gaq.push('_trackEvent', 'Form', 'Submit', $(this).attr('action')); //...do some other tracking stuff... setTimeout(function(){ form.submit(); }, 400); }); This is reliable in most cases, but it makes me nervous. What if something happens between e.preventDefault();and when I get around to triggering the DOM based submit? I've totally broken the form. I've been poking around some other analytics implementations, and I've noticed something like this: $('form').mousedown(function(){ _gaq.push('_trackEvent', 'Form', 'Submit', $(this).attr('action')); }); $('form').keydown(function(e){ if(e.which===13) //if the keydown is the enter key _gaq.push('_trackEvent', 'Form', 'Submit', $(this).attr('action')); }); Basically, instead of interrupting the form submit, preempting it by assuming that if someone is mousing down or keying down on Enter, than that form is submitted. Obviously, this will result in a certain amount of false positives, but it completely eliminates use of e.preventDefault();, which in my mind eliminates the risk that I might ever prevent a form from successfully submitting. So, my question: Is it possible to take the standard form tracking snippet and prevent it from ever fully preventing the form from submitting? Is the mousedown/keydown alternative viable? Are there any submission cases it may miss? Specifically, are there other ways to end up submitting besides the mouse and the keyboard enter? And will the browser always have time to process javascript before beginning to unload the page?

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  • AJAX Div Retrieval every 60 seconds

    - by Sam
    Hello everyone! What I would like to do is retrieve the contents of a PHP file and insert it into a div every 60 seconds, basically refreshing the dynamic div. I've come up with the following code so far, however it doesn't seem to be working. The code is just like this, nothing extra, apart from the MYSQL login. PHP to grab: <?php $time = date("m/d/Y h:i:s a", time()); mysql_query("UPDATE djs SET requesttime='{$time}' WHERE username='{$djs['username']}'") or die(mysql_error()); $request_db = mysql_query("SELECT * FROM requests WHERE haveplayed='0'") or die(mysql_error()); echo "<table style=\"border:1px solid;width:99%;margin-left:auto;margin-right:auto;\" border=\"1\">"; echo "<tr><th>Title</th><th>Artist</th><th>Dedicated To...</th></tr>"; while($request = mysql_fetch_array( $request_db )) { echo "<tr><td style=\"width:33%;padding:1px;\">"; echo $request['SongName']; echo "</td><td style=\"width:33%;\">"; echo $request['Artist']; echo "</td><td style=\"width:33%;\">"; echo $request['DedicatedTo']; echo "</td></tr>"; } echo "</table>"; ?> The original PHP code is just the same, enclosed in a div with an id attribute of 'ajax_table'. The JavaScript is: // JavaScript Document var xmlHttp_moniter function moniter() { xmlHttp_moniter = GetXmlHttpObject_parcel() if(xmlHttp_moniter == null) { alert("browser does not support HTTP Request") return } var url="ajax_table.php?random=" + Math.random() xmlHttp_moniter.onreadystatechange = stateChanged xmlHttp_moniter.open("GET",url,true) xmlHttp_moniter.send(null) } function stateChanged() { if(xmlHttp_moniter.readyState==4 || xmlHttp_moniter.readyState == "complete") { document.getElementById("ajax_table").innerHTML = xmlHttp_moniter.responseText setTimeout('ajax_table()',60000); } } function GetXmlHttpObject_parcel() { var xmlHttp_moniter=null; try { xmlHttp_moniter=new XMLHttpRequest(); } catch (e) { //Internet Explorer try { xmlHttp_moniter=new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { xmlHttp_moniter=new ActiveXObject("Microsoft.XMLHTTP"); } } return xmlHttp_moniter; } and that is on the page that is requesting the other php page.

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  • Export CSV from Mysql

    - by ss888
    Hi, I'm having a bit of trouble exporting a csv file that is created from one of my mysql tables using php. The code I'm using prints the correct data, but I can't see how to download this data in a csv file, providing a download link to the created file. I thought the browser was supposed to automatically provide the file for download, but it doesn't. (Could it be because the below code is called using ajax?) Any help greatly appreciated - code below, S. include('../config/config.php'); //db connection settings $query = "SELECT * FROM isregistered"; $export = mysql_query ($query ) or die ( "Sql error : " . mysql_error( ) ); $fields = mysql_num_fields ( $export ); for ( $i = 0; $i < $fields; $i++ ) { $header .= mysql_field_name( $export , $i ) . "\t"; } while( $row = mysql_fetch_row( $export ) ) { $line = ''; foreach( $row as $value ) { if ( ( !isset( $value ) ) || ( $value == "" ) ) { $value = "\t"; } else { $value = str_replace( '"' , '""' , $value ); $value = '"' . $value . '"' . "\t"; } $line .= $value; } $data .= trim( $line ) . "\n"; } $data = str_replace( "\r" , "" , $data ); if ( $data == "" ) { $data = "\n(0) Records Found!\n"; } //header("Content-type: application/octet-stream"); //have tried all of these at sometime //header("Content-type: text/x-csv"); header("Content-type: text/csv"); //header("Content-type: application/csv"); header("Content-Disposition: attachment; filename=export.csv"); //header("Content-Disposition: attachment; filename=export.xls"); header("Pragma: no-cache"); header("Expires: 0"); echo '<a href="">Download Exported Data</a>'; //want my link to go in here... print "$header\n$data";

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  • jQuery image loop not displaying any images

    - by user1871097
    I'm trying to create a very basic image gallery in jQuery. The goal is to have 3 images fade in and out in a sequential order. So image 1 is displayed, fades to image 2 etc. then the whole thing loops again. My HTML code so far is as follows: <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Slider</title> <style type="text/css"> .slider{ width: 2848px; height: 2136px; overflow: hidden; margin: 30px auto; } .slider img{ width:2848px; height:2136px; display:none; } </style> <script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script> <script src="//ajax.googleapis.com/ajax/libs/jqueryui/1.9.2/jquery-ui.min.js"></script> <script src="Slider2.js"></script> </head> <body onload="Slider2"();> <div class="slider"> <img id="1" src="31.jpg" border="0" alt="city"/> <img id="2" src="2vrtigo2.jpg" border="0" alt="roof"/> <img id="3" src="3.jpg" border="0" alt="sea"/> </div> </body> And the jQuery code looks like this: function Slider2() { var total = $(".slider img").size(); for (i=1; i<=total; i+=1) { $(".slider #"+i).fadeIn(600); $(".slider #"+i).delay(2000).hide; }} A quick syntactical note, I've also tried using i++ in the last argument of the For Loop. The result of this code is a blank, white page. I know some of the HTML is being compiled because the enormous 2848x2136 div creates scroll bars on the browser. If anyone could help me out, that would be greatly appreciated. Obviously I'm relatively new to web programming and would love some insight into why this isn't working. Thanks!

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  • Starting jetty with spring xml as a background process/thread

    - by compass
    My goal is to set up a jetty test server and inject a custom servlet to test some REST classes in my project. I was able to launch the server with spring xml and run tests against that server. The issue I'm having is sometimes after the server started, the process stopped at the point before running the tests. It seems jetty didn't go to background. It works every time on my computer. But when I deployed to my CI server, it doesn't work. It also doesn't work when I'm on VPN. (Strange.) The server should be completed initialized as when the tests stuck, I was able to access the server using a browser. Here is my spring context xml: .... <bean id="servletHolder" class="org.eclipse.jetty.servlet.ServletHolder"> <constructor-arg ref="courseApiServlet"/> </bean> <bean id="servletHandler" class="org.eclipse.jetty.servlet.ServletContextHandler"/> <!-- Adding the servlet holders to the handlers --> <bean id="servletHandlerSetter" class="org.springframework.beans.factory.config.MethodInvokingFactoryBean"> <property name="targetObject" ref="servletHandler"/> <property name="targetMethod" value="addServlet"/> <property name="arguments"> <list> <ref bean="servletHolder"/> <value>/*</value> </list> </property> </bean> <bean id="httpTestServer" class="org.eclipse.jetty.server.Server" init-method="start" destroy-method="stop" depends-on="servletHandlerSetter"> <property name="connectors"> <list> <bean class="org.eclipse.jetty.server.nio.SelectChannelConnector"> <property name="port" value="#{settings['webservice.server.port']}" /> </bean> </list> </property> <property name="handler"> <ref bean="servletHandler" /> </property> </bean> Running latest Jetty 8.1.8 server and Spring 3.1.3. Any idea?

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  • Toggling between states on 3 containers in jQuery

    - by Saif Bechan
    Hello, i have an php/mysql/ajax auction application application. Now there is a section that can have 3 states. State one, the user can place a bid.(Bid button is shown) State two, the user has to wait before he can place a new bid(number of sec is shown) State three, the user has an auto bidding system enabled.(The price maximum and amount ate shown). Now i get these values trough jquery ajax, and i want to present the user the right section. Now the code i have is as follows: if(data[i].bidwait >= 0 && data[i].amount == ''){ // In this section the user has no autobiddings, and can place a bidding $(productContainer+' .bid-wrapper').removeClass('none'); $(productContainer+' .bidwait-wrapper').addClass('none'); $(productContainer+' .autobid-wrapper').addClass('none'); }else if(data[i].bidwait < 0 && data[i].amount == ''){ // In this section the user has to wait the amount of sec to place a new bid $(productContainer+' .bid-wrapper').addClass('none'); $(productContainer+' .bidwait-wrapper').removeClass('none'); $(productContainer+' .autobid-wrapper').addClass('none'); $(productContainer+' .bidwait-text').text(data[i].bidwait * -1); }else{ // In the last section the user has the auto bidder enabled, so that is shown $(productContainer+' .bid-wrapper').addClass('none'); $(productContainer+' .bidwait-wrapper').addClass('none'); $(productContainer+' .autobid-wrapper').removeClass('none'); $(productContainer+' .amount').html(data[i].amount == 0 ? '&#8734;' : data[i].amount); $(productContainer+' .maxprice').html(data[i].maxprice == 0 ? '&#8734;' : data[i].maxprice); } This looks like an awful lot of code for something so small. I was wondering if there is an easier method to accomplish such a thing. Speed is a huge issue for me because this has to run every second in the users browser. If there is no other option i am just going to remove this option and go with a no ajax approuch. If you have been, thank you for reading!

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  • How can I find a URL called [link] inside a block of HTML containing other URLs?

    - by DrTwox
    I'm writing a script to rewrite Reddit's RSS feeds. The script needs to find a URL named [link] inside a block of HTML that contains other URLs. The HTML is contained in an XML element called <description>. Here are two examples of the <description> element from I need to parse and the [link] I would need to get. First example: <description>submitted by &lt;a href=&#34;http://www.reddit.com/user/wildlyinaccurate&#34;&gt; wildlyinaccurate &lt;/a&gt; &lt;br/&gt; &lt;a href=&#34;http://wildlyinaccurate.com/a-hackers-guide-to-git&#34;&gt;[link]&lt;/a&gt; &lt;a href="http://www.reddit.com/r/programming/comments/26jvl7/a_hackers_guide_to_git/"&gt;[66 comments]&lt;/a&gt;</description> The [link] is: http://wildlyinaccurate.com/a-hackers-guide-to-git Second example: <description>&lt;!-- SC_OFF --&gt;&lt;div class=&#34;md&#34;&gt;&lt;p&gt;I work a support role at a company where I primarily fix issues our customers our experiencing with our software, which is a browser based application written primarily in javascript. I&amp;#39;ve been doing this for 2 years, but I want to take it to the next level (with the long term goal being that I become proficient enough to call myself a developer). I&amp;#39;ve been reading &amp;quot;Javascript The Definitive Guide&amp;quot; by O&amp;#39;Reilly but I was wondering if any of you more experienced users out there had some tips on taking it to the next level. Should I start incorporating some PHP and Jquery into my learning? Side projects on my spare time? Any good online resources? Etc. &lt;/p&gt; &lt;p&gt;Thanks! &lt;/p&gt; &lt;/div&gt;&lt;!-- SC_ON --&gt; submitted by &lt;a href=&#34;http://www.reddit.com/user/56killa&#34;&gt; 56killa &lt;/a&gt; &lt;br/&gt; &lt;a href=&#34;http://www.reddit.com/r/javascript/comments/26nduc/i_want_to_become_more_experienced_with_javascript/&#34;&gt;[link]&lt;/a&gt; &lt;a href="http://www.reddit.com/r/javascript/comments/26nduc/i_want_to_become_more_experienced_with_javascript/"&gt;[4 comments]&lt;/a&gt;</description> The [link] is: http://www.reddit.com/r/javascript/comments/26nduc/i_want_to_become_more_experienced_with_javascript/

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  • Query string problem if we use header

    - by avani-nature
    Hai frnds i am new to php actually i am facing following problems in coding please can anyone give the solution? Actually i am having one audio player and i am displaying some word dcoument if i click word document corresponding audio file should play actually when i click doc file it should pop ip with save as and open with for that i am using some header code also i am passing query string in the browser query string is not working if i use header can anyone give me a solution for it below is my code i am attaching <?php $f_name = $_POST["fn"]; $id = $_POST["id1"]; echo $id; //echo "../public_html/sites/default/files/ourfiles/$f_name"; $res2=db_query("select * from mt_files where id='".$id."' "); $row2=db_fetch_array($res2); $job_audio=$row2["audio_name"]; //echo $job_audio; //$job_audi=explode("/",$job_audio); //$job_audio=$job_audi[8]; $job_audio= "C:/xampp/htdocs/med/sites/default/files/audio/$job_audio"; //$job_audio= "C:/Documents and Settings/swuser/My Documents/$job_audio"; //echo $job_audio; echo "<object data='$job_audio' type='application/x-mplayer2' width='150' height='45'> <param name='src' value='$job_audio'> <param name='autoplay' value='true'> <param name='autoStart' value='1'> </object> "; $file = "../mts/sites/default/files/docs/$f_name"; if (file_exists($file)) { header('Content-Description: File Transfer'); header('Content-Type: application/octet-stream'); header('Content-Disposition: attachment; filename='.basename($file)); header('Content-Transfer-Encoding: binary'); header('Expires: 0'); header('Cache-Control: must-revalidate, post-check=0, pre-check=0'); header('Pragma: public'); header('Content-Length: ' . filesize($file)); ob_clean(); flush(); readfile($file); exit; } //The download table query goes here put the $f_name in insert into with the //time varible ?>

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  • How to pass multiple PHP variables to a jQuery function?

    - by jcpeden
    I'm working on a Wordpress plugin. I need to pass plugin directories (that can change depending on an individual's installation) to a jquery function. What is the best way of doing this? The version of the plugin that I can to work on had included all the javascript in the PHP file so the functions were parsed along with the rest of the content before being rendered in a browser. I'm looking at AJAX but I think it might be more complicated than I need. I can get away with just two variables in this case (directories, nothing set by the user). As I've read its good practice, I'm trying to keep the js and php separate. When the plugin initializes, it call the js file: //Wordpress calls the .js when the plugin loads wp_enqueue_script( 'wp-backitup-funtions', plugin_dir_url( __FILE__ ) . 'js/wp-backitup.js', array( 'jquery' ) ); Then I'm in the .js file and need to figure out how to generate the following variables: dir = '<?php echo content_url() ."/plugins"; ?>'; dir = '<?php echo content_url() ."/themes"; ?>'; dir = '<?php echo content_url() ."/uploads"; ?>'; And run the parse the following requests: xmlhttp.open("POST","<?php echo plugins_url() .'/wp-backitup/includes/wp-backitup-restore.php'); ?>",true); xmlhttp.open("POST","<?php echo plugins_url() .'/wp-backitup/includes/wp-backitup-start.php'); ?>",true); xmlhttp.open("POST","<?php echo plugins_url() .'/wp-backitup/wp-backitup-directory.php'); ?>",true); xmlhttp.open("POST","<?php echo plugins_url() .'/wp-backitup/wp-backitup-db.php'); ?>",true); window.location = "<?php echo plugins_url() .'/wp-backitup/backitup-project.zip'); ?>"; xmlhttp.open("POST","<?php echo plugins_url() .'/wp-backitup/wp-backitup-delete.php'); ?>",true); Content URL and Plugins URL differ only by /plugins/ so if I was hard pressed, I would only really need to make a single PHP request and then bring this into the JS.

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  • My webpage ignores changes in CSS file

    - by Pavel
    No matter what I change in my .css file, the page remains the same - what's more, neither changing the link tag so that it points to another .css file nor deleting it completely makes no difference. Other changes in html code are applied. The sourcecode of the webpage shows everything as it should be. This behavior started when I redirected the link tag from previous file to the one I use now (plus there have been some changes in the tag while this problem occured, to test the behavior of my webpage); changes in neither file affect the page. For the first time when this happened, this was caused by copies of head tag in included chunks of code (for header, left menu etc. - their head part overrode the head part of the main page) and the problem was solved by removing these redundant heads from these files. But it happened again when I changed the link tag for the next time. I couldn't find any head parts in my included files, but the problem lasts (only solution I can see now is to delete the included files and copy the code directly to the file, but this would mean lots of redundant code). How can I solve this problem, so that my page response to changes in .css files without increasing redundancy? How to ensure that I can change the link to .css file just on one place with no such problems? Do I have to unload the CSS file somehow? I saw this problem both in Firefox and in Chrome. I use PSPad to write the code, just in case it would play role. EDIT: I have cleared browser cache now, and I changed the link to .css files from one to another before, but nothing helped. Now I accept the best answer saying the problem is in caching and I start a related question to find out how to solve the caching issue. If the other question's answers would say that in this case I can be sure that problem isn't in caching (very unlikely, but fail of ordinary methods of caching-problems-solving is unlikely too), I'd update this question and start searching for other possible problems, but now the message seems to be clear: when webpage ignores changes in .css files, caching is to blame.

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  • Is there a way to have element behind a div (links) clickable in areas where the div is "transparent

    - by Adam
    I have a block element that is positioned absolutely and some other elements on page that are positioned fixed. The effect is the block on top floats over the page which works well. The links in the elements at the bottom underneath are not clickable. They shouldn't be when the content of the div is over them, but when the "marginal" areas which are transparent are over the links they are visible, but clicks only register to the covering div. The problem only happens when the padding covers the div. But if I just rely on the margin the bottom margin is ignored by browser so the scroll doesn't go high enough up. To solve this I resort to padding at the bottom. This is the problem. Is there a clean way around this? I realize I could have the underneath elements doubled and place on top, but opacity set to 0. That is an undesirable solution however. Sample of the problem: <!DOCTYPE html> <html lang='en' xml:lang='en' xmlns='http://www.w3.org/1999/xhtml'> <head> <style> #top, #bottom { position: fixed; border: 1 px solid #333; background-color: #eee; left: 100px; padding: 8px; } #top { top: 0; z-index: 1; } #bottom { bottom: 0; z-index: 2; } #contentWrapper { position: absolute; margin: 100px 0 0 0; /* Padding is used to make sure the scroll goes up further on the page */ padding: 0 0 100px 0; width: 600px; z-index: 3; } #content { border: 1 px solid #333; background-color: #eee; height: 1000px; } </style> </head> <body> <div id='top'><a href="#">Top link</a></div> <div id='bottom'><a href="#">Bottom link</a></div> <div id='contentWrapper'> <div id='content'>Some content</div> </div> </body> </html>

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