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  • ZendFramework Zend_Form_Element_File setDestination vs rename filter

    - by bibstha
    The code says Zend_Form_element_File::setDestination() is depricated and to use the rename filter. However the rename filter is currently codes such that when path is set, only temporary name is given. Original filename is lost. <?php $file = new Zend_Form_Element_File(); $file->setDestination('/var/www/project/public'); ?> vs <?php $file = new Zend_Form_Element_File(); $file->addFilter('Rename', array('target' => '/var/www/project/public')); ?> Any solution to upload files so that it preserves original filename structure but checks for existing file and appends _1.ext or _2.ext?

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  • How to use the Zend_Log instance that was created using the Zend_Application_Resource_Log in a model

    - by Alex
    Our Zend_Log is initialized by only adding the following lines to application.ini resources.log.stream.writerName = "Stream" resources.log.stream.writerParams.mode = "a" So Zend_Application_Resource_Log will create the instance for us. We are already able to access this instance in controllers via the following: public function getLog() { $bootstrap = $this->getInvokeArg('bootstrap'); //if (is_null($bootstrap)) return false; if (!$bootstrap->hasPluginResource('Log')) { return false; } $log = $bootstrap->getResource('Log'); return $log; } So far, so good. Now we want to use the same log instance in model classes, where we can not access the bootstrap. Our first idea was to register the very same Log instance in Zend_Registry to be able to use Zend_Registry::get('Zend_Log') everywhere we want: in our Bootstrap class: protected function _initLog() { if (!$this->hasPluginResource('Log')) { throw new Zend_Exception('Log not enabled'); } $log = $this->getResource('Log'); assert( $log != null); Zend_Registry::set('Zend_Log', $log); } Unfortunately this assertion fails == $log IS NULL --- but why?? It is clear that we could just initialize the Zend_Log manually during bootstrapping without using the automatism of Zend_Application_Resource_Log, so this kind of answers will not be accepted.

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  • My store returns no code id and breaks 404 error. Magento

    - by numerical25
    I know what the issue is but I dont know how to fix it. I just migrated my magento store locally and I guess possibly some data may have been lost when transferring the DB. the DB is very large. Anyhow, when I login to my admin page, I get a 404 error, page was not found. I debugged the issue and got down to the wire. The exception is thrown in Mage/Core/Model/App.php. Line 759 to be exacted. The following is a snippet. Mage/Core/Model/App.php if (empty($this->_stores[$id])) { $store = Mage::getModel('core/store'); /* @var $store Mage_Core_Model_Store */ if (is_numeric($id)) { $store->load($id); // THIS ID IS FROM Mage_Core_Model_App::ADMIN_STORE_ID and its empty which causes the error } elseif (is_string($id)) { $store->load($id, 'code'); } if (!$store->getCode()) { // RETURNS FALSE HERE BECAUSE NO ID Specified $this->throwStoreException(); } $this->_stores[$store->getStoreId()] = $store; $this->_stores[$store->getCode()] = $store; } The store returns null because $id is null so it therefore does not load any model which explains why it returns false when calling getCode() [EDIT] If you want clarification, please ask for more before voting my post down. Remember I am still trying to get help not get neglected. I am using Version 1.4.1.1. When I type in the URL for admin, I get a 404 page. I walked through the code thouroughly and found that the Model MAGE_CORE_MODEL_STORE::getCode(); Returns Null which triggers the exception. and ends the script. I do not have any other detail. I further troubleshooted the issue by checking the database and that is what the screen shot is. Showing that there is infact data in the Code Colunn. So my question is why is the Model returning a empty column when the column clearly has a value. What can I do to further troubleshoot and figure out why its not working [EDIT UPDATE NEW] I did some research. the reason its returning NULL is because the store ID is null being passed Mage::getStoreConfigFlag('web/secure/use_in_adminhtml', Mage_Core_Model_App::ADMIN_STORE_ID); // THIS IS THE ID being specified Mage_Core_Model_App::ADMIN_STORE_ID has no value in it, so this method throws the exception. Not sure why how to fix this.

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  • ZF Site in ZF Site? How do I redirect form subdirectory to another subdirecotry?

    - by AD
    The deal is that I have a ZF site for which root directory is /public. How should I go about redirecting to a subdirectory if I want to do next? I want to have another subdirectory under /public/ that would not be linked to a main website in any way except it using save ZF. Lets say I have this: /public/newsite/ which will include a complete modular ZF (just I have it for the main site). That is the root directory for the NEWSITE would be /public/newsite/public. So my question how do I modify my .htaccess rules so it would redirect any requests from /public/newsite/ to /public/newsite/public/? Thank you in advance.

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  • Zend_Controller_Router_Route_Chain more routes - more problems

    - by epmspec
    When i use only langRoute and moduleRoute i have not any problems. But when i add pageRoute it is not work properly. I have tried many another ways do it (Regex etc) but none gives the desired result. Can anybody help me? $front = Zend_Controller_Front::getInstance(); $router = $front->getRouter(); //Route_page needs dispatcher and request $dispatcher = $front->getDispatcher(); $request = $front->getRequest(); // Add languag routes $langRoute = new Zend_Controller_Router_Route_Hostname( ':language.domain.com', array( 'language' => 'ru', ), array( 'language' => '^(ru|en)$', ) ); // Add module routes $moduleRoute = new Zend_Controller_Router_Route_Module(array(),$dispatcher,$request); // Add page routes $pageRoute = new Zend_Controller_Router_Route( ':uri\.html', array( 'controller' => 'index', 'module' => 'default', 'action' => 'index', 'uri' => 'index', ), array ('uri' => '[0-9a-z\-]+') ); // Add chain routes $chainedRoute = new Zend_Controller_Router_Route_Chain(); $chainedRoute->chain($pageRoute); $chainedRoute->chain($langRoute)->chain($moduleRoute); $router->addRoute('default', $chainedRoute);

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  • Serialising my JSON output problem in JQuery

    - by davykiash
    Am trying to validate my form using an AJAX call $("#button").click(function() { $.ajax({ type: "POST", url: "<?php echo $this->baseUrl() ?>/expensetypes/async", data: 'fs=' + JSON.stringify($('#myform').serialize(true)), contentType: "application/json; charset=utf-8", dataType: "json" }); }); On my controller my code is as follows //Map the form from the client-side call $myFormData = Zend_Json::decode($this->getRequest()->getParam("fs") ,Zend_Json::TYPE_ARRAY); $form = new Form_Expensetypes(); $form->isValid($myFormData); However from firebug my output is as follows fs="id=&expense_types_code=AAA&expense_types_desc=CCCC&expense_types_linkemail=XXXX&expense_types_budgetamount=22222&expense_types_budgetperiod=22222" What I expect is something similar to fs{"expense_types_code":"AAA","expense_types_desc":"CCCC","expense_types_linkemail":"XXXX","expense_types_budgetamount":"22222"} How do I achieve this type of serialisation?

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  • Defining a function to a Row

    - by Siedrix
    Hi, im making an application and i need to implement diferent level of user permits. I coul have the function $this->view->users->hasPermits($this->view->user); By declaring a function on the model, an things could be easy to implement. But i would like to be able to have the next function doing the same: $this->view->user->hasPermits(); Is there a way to do this? do i need to extend the Zend_Db_Table_Row class? any ideas?

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  • [Zend_Framework] Group by date with Zend_Db

    - by rasouza
    I have several entries in a table with name and date. I'd like to fetchAll with Zend_Db then get a grouped-by-date array. It happens that if I use group(), Zend_Db_Select method, it excludes some entries and I need them all. Actually, what I'm trying to do is to render several tables, one for each different date, with data inside. I have no ideia. How do I do that? Thx in advance

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  • memory leak in Zend_Db_Table_Row?

    - by Vincenzo
    This is the code I have: <?php $start = memory_get_usage(); $table = new Zend_Db_Table('user'); for ($i = 0; $i < 5; $i++) { $row = $table->createRow(); $row->name = 'Test ' . $i; $row->save(); unset($row); echo (memory_get_usage() - $start) . "\n"; } This is what I see: 90664 93384 96056 98728 101400 Isn't it a memory leak? When I have 500 objects to insert into DB in one script I'm getting memory overflow. Can anyone help?

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  • Check if the current date is between two dates + mysql select query

    - by kj7
    I have following table : id dateStart dateEnd active 1 2012-11-12 2012-12-31 0 2 2012-11-12 2012-12-31 0 I want to compare todays date in between dateStart and dateEnd. Following is my query for this : $todaysDate="2012-26-11"; $db = Zend_Registry::get("db"); $result = $db->fetchAll("SELECT * FROM `table` WHERE active=0 AND {$todaysDate} between dateStart and dateEnd"); return $result; But its not working. Any solution. Thanks in advance.

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  • 42S22 SQL error: Column not found, why?

    - by Vincenzo
    This is my SQL: SELECT `tbl`.*, 123 AS `test` FROM `tbl` GROUP BY `test` It works when I run it directly in MySQL. But PDO says: SQLSTATE[42S22]: Column not found: 1054 Unknown column 'test' in 'field list' Why so? How to cure this problem? I'm using Zend_Db.

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  • problem by displaying images stored in a MySQL database?

    - by user1400
    i have images in my blob field in database i use blow colde for displaying image but it does not show any pic , someone could tell me where is my wrong? this is my model: public function getListUser() { $select = $this->select() ->order('lastname DESC'); $adapter = new Zend_Paginator_Adapter_DbTableSelect ($select); return $adapter; } this my controller: $userModel = new Admin_Model_User(); $adapter = $userModel->getListUser(); $paginator = new Zend_Paginator ($adapter); $paginator->setItemCountPerPage(1); $page = $this->_request->getParam('page', 1); $paginator->setCurrentPageNumber($page); $this->view->paginator = $paginator; this my view code: <td style="width: 20%;"> <?php echo $this->lastname ?> </td> <td style="width: 20%;"><?php header("Content-type: image/gif"); print $this->image; ?></td>

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  • What is the difference between "render a view" and send the response using the Response's method "sendResponse()"?

    - by Green
    I've asked a question about what is "rendering a view". Got some answers: Rendering a view means showing up a View eg html part to user or browser. and So by rendering a view, the MVC framework has handled the data in the controller and done the backend work in the model, and then sends that data to the View to be output to the user. and render just means to emit. To print. To echo. To write to some source (probably stdout). but don't understand then the difference between rendering a view and using the Response class to send the output to the user using its sendResponse() method. If render a view means to echo the output to the user then why sendResponse() exists and vise versa? sendResponse() exactly sends headers and after headers outputs the body. They solve the same tasks but differently? What is the difference?

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  • How many results were returned?

    - by Pastor Bones
    I'm performing a query on a worksheet. I want to update the row if it exists or insert it if it doesn't. How can you check if a result was returned or not? $query = new Zend_Gdata_Spreadsheets_ListQuery(); $query->setSpreadsheetKey($this->currKey); $query->setWorksheetId($this->currWkshtId); $query->setSpreadsheetQuery('cid = ' . $data['cid']); $listFeed = $this->gdClient->getListFeed($query); // This does not work! if(empty($listFeed)){ echo 'No results found!'; }

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  • Hiding a HTTP Auth-Realm by sending 404 to non-known IPs?

    - by zhenech
    I have an Apache (2.2) serving a web-app on example.com. That web-app has a debug-page reachable via example.com/debug. /debug is currently protected with a HTTP basic auth. As there is only a very small user-base who has access to the debug-page, I would like to hide it based on IP address and return 404 to clients not accessing from our VPN. Serving a 404 based on IP-address only is easy and is described in http://serverfault.com/a/13071. But as soon I add authentication, the users see a 401 instead of a 404. Basically, what I need is: if ($REMOTE_ADDR ~ 10.11.12.*): do_basic_auth (aka return 401) else: return 404

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  • vsftp login errors 530 login incorrect

    - by mcktimo
    Using Ubuntu 10.04 on an aws ec2 instance. I was happy just using ssh but then a wordpress plugin needs ftp access...I just need ftp access for one site www.sitebuilt.net which is in /home/sitebuil. I installed a vftpd and pam and followed suggestions that got me to the following state /etc/vftpd.conf listen=YES anonymous_enable=NO local_enable=YES write_enable=YES dirmessage_enable=YES use_localtime=YES xferlog_enable=YES connect_from_port_20=YES xferlog_file=/var/log/vsftpd.log secure_chroot_dir=/var/run/vsftpd/empty pam_service_name=vsftpd rsa_cert_file=/etc/ssl/private/vsftpd.pem guest_enable=YES user_sub_token=$USER local_root=/home/$USER chroot_local_user=YES hide_ids=YES check_shell=NO userlist_file=/etc/vsftpd_users /etc/pam.d/vsftpd # Standard behaviour for ftpd(8). auth required pam_listfile.so item=user sense=deny file=/etc/ftpusers onerr=succeed # Note: vsftpd handles anonymous logins on its own. Do not enable pam_ftp.so. # Standard pam includes @include common-account @include common-session @include common-auth auth required pam_shells.so # Customized login using htpasswd file auth required pam_pwdfile.so pwdfile /etc/vsftpd/passwd account required pam_permit.so session optional pam_keyinit.so force revoke auth include system-auth account include system-auth session include system-auth session required pam_loginuid.so /etc/vsftpd_users sitebuil tim /etc/passwd ... sitebuil:x:1002:100:sitebuilt systems:/home/sitebuil:/bin/sh ftp:x:108:113:ftp daemon,,,:/srv/ftp:/sbin/nologin /etc/vsftpd/passwd sitebuil:Kzencryptedpwd /var/log/vftpd.log Wed Feb 29 15:15:48 2012 [pid 20084] CONNECT: Client "98.217.196.12" Wed Feb 29 15:16:02 2012 [pid 20083] [sitebuil] FAIL LOGIN: Client "98.217.196.12" Wed Feb 29 16:12:33 2012 [pid 20652] CONNECT: Client "98.217.196.12" Wed Feb 29 16:12:45 2012 [pid 20651] [sitebuil] FAIL LOGIN: Client "98.217.196.12"

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  • Linux authentication via ADS -- allowing only specific groups in PAM

    - by Kenaniah
    I'm taking the samba / winbind / PAM route to authenticate users on our linux servers from our Active Directory domain. Everything works, but I want to limit what AD groups are allowed to authenticate. Winbind / PAM currently allows any enabled user account in the active directory, and pam_winbind.so doesn't seem to heed the require_membership_of=MYDOMAIN\\mygroup parameter. Doesn't matter if I set it in the /etc/pam.d/system-auth or /etc/security/pam_winbind.conf files. How can I force winbind to honor the require_membership_of setting? Using CentOS 5.5 with up-to-date packages. Update: turns out that PAM always allows root to pass through auth, by virtue of the fact that it's root. So as long as the account exists, root will pass auth. Any other account is subjected to the auth constraints. Update 2: require_membership_of seems to be working, except for when the requesting user has the root uid. In that case, the login succeeds regardless of the require_membership_of setting. This is not an issue for any other account. How can I configure PAM to force the require_membership_of check even when the current user is root? Current PAM config is below: auth sufficient pam_winbind.so auth sufficient pam_unix.so nullok try_first_pass auth requisite pam_succeed_if.so uid >= 500 quiet auth required pam_deny.so account sufficient pam_winbind.so account sufficient pam_localuser.so account required pam_unix.so broken_shadow password ..... (excluded for brevity) session required pam_winbind.so session required pam_mkhomedir.so skel=/etc/skel umask=0077 session required pam_limits.so session required pam_unix.so require_memebership_of is currently set in the /etc/security/pam_winbind.conf file, and is working (except for the root case outlined above).

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  • Route URL laravel 4

    - by nabil l.
    How can I do this in Laravel 4 URL::route('auth.reset', array('kh34KHh4K342')) Instead of http://domain.tld/auth/reset?kh34KHh4K342 I want to get this : http://domain.tld/auth/reset/kh34KHh4K342 EDIT This my routes.php : The problem is because I have two routes with the same name? How do you explain that ? Should i set a different name event is the same kind, and different methods // Set locale $locale = Request::segment(1); if(in_array($locale, Config::get('app.languages'))) { \App::setLocale($locale); } else { $locale = null; } Route::group( array( 'prefix' => $locale ), function () { Route::get('/'), array( 'uses' => 'HomeController@getIndex', 'as' => '/' )); // Auth Route::group( array( 'prefix' => 'auth' ), function () { // Login Route::get( 'login', array( 'before' => 'guest', 'uses' => 'UserController@getLogin', 'as' => 'auth.login' ) ); Route::post( 'login', array( 'before' => 'guest|csrf', 'uses' => 'UserController@postLogin', 'as' => 'auth.login' ) ); Route::get( 'reset/{$token}', array( 'uses' => 'UserController@getReset', 'as' => 'auth.reset' ) ); Route::post( 'reset', array( 'uses' => 'UserController@postReset', 'as' => 'auth.reset' ) ); } );

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  • PostgreSQL pg_hba.conf with "password" auth wouldn't work with PHP pg_connect?

    - by tftd
    I've recently experimented with the settings in pg_hba.conf. I read the PostgreSQL documentation and I though that the "password" auth method is what I want. There are many people that have access to the server PostgreSQL is working on so I don't want the "trust" method. So I changed it. But then PHP stopped working with the database. The message I get is "Warning: pg_connect(): Unable to connect to PostgreSQL server: FATAL: password authentication failed for user "myuser" in /my/path/to/connection/class.php on line 35". It is kind of strange because I can connect via phppgadmin without any problems and also I can connect from my home computer with psql - again without any problems. This is my pg_hba.conf: # TYPE DATABASE USER CIDR-ADDRESS METHOD # "local" is for Unix domain socket connections only local all all password # IPv4 local connections: host all all 127.0.0.1/32 password # IPv6 local connections: host all all ::1/128 password The connection string I'm using with pg_conenct is: $connect_string = "host=localhost port=5432 dbname=mydbname user=auser password=apassword"; $dbConnection = pg_connect($connection_string); Does anybody know why is this happening ? Did I misconfigured something ?

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