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  • HTML5 development in PHP projects

    - by Tomas Mysik
    Today, we would like to show you how you can in NetBeans 7.4 develop your HTML5 applications directly in your PHP projects. And because everything has already been described on the NetBeans Web Client blog, we will just provide a link to this great blog post: HTML5 development in Java EE and PHP projects. Enjoy it! :) That's all for today, as always, please test it and report all the issues or enhancements you find in NetBeans Bugzilla. Also, please do not forget that all the comments here are moderated.

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  • Nginx config - serving index.html not working

    - by Bill
    I can't figure out how to redirect / to index.html. I've gone through the threads on serverfault and I think I've tried every suggestion including: rewrite statements within location / index index.html at the server level, within location / and within static content moving node.js proxy statements to location ~ /i instead of within location / Obviously something is wrong somewhere else in my configuration. Here is my nginx.conf: worker_processes 1; pid /home/logs/nginx.pid; events { worker_connections 1024; } http { include mime.types; default_type application/octet-stream; sendfile on; keepalive_timeout 65; error_log /home/logs/error.log; access_log /home/logs/access.log combined; include sites-enabled/*; } and my server config located in sites-enabled server { root /home/www/public; listen 80; server_name localhost; # proxy request to node location / { index index.html index.htm; proxy_set_header Host $http_host; proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; proxy_set_header X-NginX-Proxy true; proxy_pass http://127.0.0.1:3010; proxy_redirect off; break; } # static content location ~ \.(?:ico|jpe?g|jpeg|gif|css|png|js|swf|xml|woff|eot|svg|ttf|html)$ { access_log off; add_header Pragma public; add_header Cache-Control public; expires 30d; } gzip on; gzip_vary on; gzip_http_version 1.0; gzip_comp_level 2; gzip_proxied any; gzip_min_length 1000; gzip_disable "msie6"; gzip_types text/plain text/css application/json application/x-javascript text/xml application/xml application/xml+rss text/javascript; } Everything else is working just fine. Requests get proxied to node correctly and static content is served correctly. I just need to be able to forward requests made to / to /index.html.

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  • PHP : Une vulnérabilité importante a été découverte dans le CMS open source [e107]

    Les équipes de PHP Sécurity ont révélé ce Mercredi dernier une vulnérabilité importante dans le gestionnaire de contenu open source e107. Cette vulnérabilité permettrait d'exécuter du code PHP à partir du BBCODE provenant des formulaires. [IMG]http://e107.org/e107_themes/imprint/images/i_logo.png[/IMG] Saisis par l'alerte l'équipe de développement de e107 n'ont pas tardé de sortir un patch qui n'est pas encore officiel. -> Annonce de la vulnérabilité -> Annonce de l'info sur le site officiel de e107 ->

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  • Missing Password check

    - by AAA
    I am using the code below, it checks for empty fields and verifies email, but even if the password is correct it won't login. the password has been inserted with md5 protection, below is the code. I am new to this so please bare with me. Thanks! PHP: session_start(); //Checks if there is a login cookie if(isset($_COOKIE['ID_my_site'])) //if there is, it logs you in and directes you to the members page { $email = $_COOKIE['ID_my_site']; $pass = $_COOKIE['Key_my_site']; $check = mysql_query("SELECT * FROM accounts WHERE email = '$email'")or die(mysql_error()); while($info = mysql_fetch_array( $check )) { if ($pass != $info['password']) { } else { header("Location: home.php"); } } } //if the login form is submitted if (isset($_POST['submit'])) { // if form has been submitted // makes sure they filled it in if(!$_POST['email'] | !$_POST['password']) { die('You did not fill in a required field.'); } // checks it against the database if (!get_magic_quotes_gpc()) { $_POST['email'] = addslashes($_POST['email']); } $check = mysql_query("SELECT * FROM accounts WHERE email = '".$_POST['email']."'")or die(mysql_error()); //Gives error if user dosen't exist $check2 = mysql_num_rows($check); if ($check2 == 0) { die('That user does not exist in our database. <a href=add.php>Click Here to Register</a>'); } while($info = mysql_fetch_array( $check )) { $_POST['password'] = stripslashes($_POST['password']); $info['password'] = stripslashes($info['password']); $_POST['password'] = md5($_POST['password']); //gives error if the password is wrong if ($_POST['password'] != $info['password']) { die('Incorrect password, please try again.'); } else { // if login is ok then we add a cookie $_POST['email'] = stripslashes($_POST['email']); $hour = time() + 3600; setcookie(ID_my_site, $_POST['email'], $hour); setcookie(Key_my_site, $_POST['password'], $hour); //then redirect them to the members area header("Location: home.php"); } } } else { // if they are not logged in <form action="<?php echo $_SERVER['PHP_SELF']?>" method="post"> <table border="0"> <tr><td colspan=2><h1>Login</h1></td></tr> <tr><td>email:</td><td> <input type="text" name="email" maxlength="40"> </td></tr> <tr><td>Password:</td><td> <input type="password" name="password" maxlength="50"> </td></tr> <tr><td colspan="2" align="right"> <input type="submit" name="submit" value="Login"> </td></tr> </table> </form> } Here is the registration code: PHP: // here we encrypt the password and add slashes if needed $_POST['password'] = md5($_POST['password']); if (!get_magic_quotes_gpc()) { $_POST['password'] = mysql_escape_string($_POST['password']); $_POST['email'] = mysql_escape_string($_POST['email']); $_POST['full_name'] = mysql_escape_string($_POST['full_name']); $_POST['user_url'] = mysql_escape_string($_POST['user_url']); } // now we insert it into the database $insert = "INSERT INTO accounts (Uniquer, Full_name, Email, Password, User_url) VALUES ('".$uniquer."','".$_POST['full_name']."', '".$_POST['email']."','".$_POST['password']."', '".$_POST['user_url']."')"; $add_member = mysql_query($insert); After using ini_set function i got to see the error, i am getting this message but not sure what it means: Notice: Undefined index: password in /var/www/domain.com/htdocs/login.php on line 103 Notice: Use of undefined constant password - assumed 'password' in /var/www/domain.com/htdocs/login.php on line 11

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  • Wordpress and Jquery slide

    - by kwek-kwek
    I am integrating a Jquery slider inside of wordpress here is the demo of the slider. I can see the div that is their but for some reason it is not showing up. View the working site here Now my problem is that this code: <script type="text/javascript"> var _siteRoot='index.php',_root='index.php';</script> <script type="text/javascript" src="<?php bloginfo('template_url'); ?>/js/jquery.js"></script> <script type="text/javascript" src="<?php bloginfo('template_url'); ?>/js/scripts.js"></script> represents and index.html, but in wordpress I enabled permalinks. Any clue what would be the _siteRoot is? here is the complete code HEADER <script type="text/javascript"> var _siteRoot='index.php',_root='index.php';</script> <script type="text/javascript" src="<?php bloginfo('template_url'); ?>/js/jquery.js"></script> <script type="text/javascript" src="<?php bloginfo('template_url'); ?>/js/scripts.js"></script> Here are the images: <div id="slide-holder"> <div id="slide-runner"> <a href=""><img id="slide-img-1" src="images/nature-photo.png" class="slide" alt="" /></a> <a href=""><img id="slide-img-2" src="images/nature-photo1.png" class="slide" alt="" /></a> <a href=""><img id="slide-img-3" src="images/nature-photo2.png" class="slide" alt="" /></a> <a href=""><img id="slide-img-4" src="images/nature-photo3.png" class="slide" alt="" /></a> <a href=""><img id="slide-img-5" src="images/nature-photo4.png" class="slide" alt="" /></a> <a href=""><img id="slide-img-6" src="images/nature-photo4.png" class="slide" alt="" /></a> <a href=""><img id="slide-img-7" src="images/nature-photo6.png" class="slide" alt="" /></a> <div id="slide-controls"> <p id="slide-client" class="text"><strong>post: </strong><span></span></p> <p id="slide-desc" class="text"></p> <p id="slide-nav"></p> </div> </div> <!--content featured gallery here --> </div> And the footer <script type="text/javascript"> if(!window.slider) var slider={};slider.data=[{"id":"slide-img-1"},{"id":"slide-img-2"},{"id":"slide-img-3"},{"id":"slide-img-4"},{"id":"slide-img-5"},{"id":"slide-img-6"},{"id":"slide-img-7"},{"id":"slide-img-8"}]; </script>

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  • Why does my Ajax function returns my entire code?

    - by JDelage
    I'm playing with sample code from the book "Head first Ajax". Here are the salient pieces of code: Index.php - html piece: <body> <div id="wrapper"> <div id="thumbnailPane"> <img src="images/itemGuitar.jpg" width="301" height="105" alt="guitar" title="itemGuitar" id="itemGuitar" onclick="getDetails(this)"/> <img src="images/itemShades.jpg" alt="sunglasses" width="301" height="88" title="itemShades" id="itemShades" onclick="getDetails(this)" /> <img src="images/itemCowbell.jpg" alt="cowbell" width="301" height="126" title="itemCowbell" id="itemCowbell" onclick="getDetails(this)" /> <img src="images/itemHat.jpg" alt="hat" width="300" height="152" title="itemHat" id="itemHat" onclick="getDetails(this)" /> </div> <div id="detailsPane"> <img src="images/blank-detail.jpg" width="346" height="153" id="itemDetail" /> <div id="description"></div> </div> </div> </body> Index.php - script: function getDetails(img){ var title = img.title; request = createRequest(); if (request == null) { alert("Unable to create request"); return; } var url= "getDetails.php?ImageID=" + escape(title); request.open("GET", url, true); request.onreadystatechange = displayDetails; request.send(null); } function displayDetails() { if (request.readyState == 4) { if (request.status == 200) { detailDiv = document.getElementById("description"); detailDiv.innerHTML = request.responseText; }else{ return; } }else{ return; } request.send(null); } And Index.php: <?php $details = array ( 'itemGuitar' => "<p>Pete Townshend once played this guitar while his own axe was in the shop having bits of drumkit removed from it.</p>", 'itemShades' => "<p>Yoko Ono's sunglasses. While perhaps not valued much by Beatles fans, this pair is rumored to have been licked by John Lennon.</p>", 'itemCowbell' => "<p>Remember the famous \"more cowbell\" skit from Saturday Night Live? Well, this is the actual cowbell.</p>", 'itemHat' => "<p>Michael Jackson's hat, as worn in the \"Billie Jean\" video. Not really rock memorabilia, but it smells better than Slash's tophat.</p>" ); if (isset($_REQUEST['ImageID'])){echo $details[$_REQUEST['ImageID']];} ?> All this code does is that when someone clicks on a thumbnail, a corresponding text description appears on the page. Here is my question. I have tried to bring the getDetails.php code inside Index.php, and modify the getDetails function so that the var url be "Index.php?ImageID="... . When I do that, I get the following problem: the function does not display the snippet of text in the array, as it should. Instead it reproduces the entire code - the webpage, etc - and then at the bottom the expected snippet of text. Why is that?

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  • Adding to database with multiple text boxes

    - by kira423
    What I am trying to do with this script is allow users to update a url for their websites, and since each user isn't going to have the same amount of websites is is hard for me to just add $_POST['website'] for each of these. Here is the script <?php include("config.php"); include("header.php"); include("functions.php"); if(!isset($_SESSION['username']) && !isset($_SESSION['password'])){ header("Location: pubs.php"); } $getmember = mysql_query("SELECT * FROM `publishers` WHERE username = '".$_SESSION['username']."'"); $info = mysql_fetch_array($getmember); $getsites = mysql_query("SELECT * FROM `websites` WHERE publisher = '".$info['username']."'"); $postback = $_POST['website']; $webname = $_POST['webid']; if($_POST['submit']){ var_dump( $_POST['website'] ); $update = mysql_query("UPDATE `websites` SET `postback` = '$postback' WHERE name = '$webname'"); } print" <div id='center'> <span id='tools_lander'><a href='export.php'>Export Campaigns</a></span> <div id='calendar_holder'> <h3>Please define a postback for each of your websites below. The following variables should be used when creating your postback.<br /> cid = Campaign ID<br /> sid = Sub ID<br /> rate = Campaign Rate<br /> status = Status of Lead. 1 means payable 2 mean reversed<br /> A sample postback URL would be <br /> http://www.example.com/postback.php?cid=#cid&sid=#sid&rate=#rate&status=#status</h3> <table class='balances' align='center'> <form method='POST' action=''>"; while($website = mysql_fetch_array($getsites)){ print" <tr> <input type ='hidden' name='webid' value='".$website['id']."' /> <td style='font-weight:bold;'>".$website['name']."'s Postback:</td> <td><input type='text' style='width:400px;' name='website[]' value='".$website['postback']."' /></td> </tr>"; } print" <td style='float:right;position:relative;left:150px;'><input type='submit' name='submit' style='font-size:15px;height:30px;width:100px;' value='Submit' /></td> </form> </table> </div>"; include("footer.php"); ?> What I am attempting to do insert the what is inputted in the text boxes to their corresponding websites, and I cannot think of any other way to do it, and this obviously does not works and returns a notice stating Array to string conversion If there is a more logical way to do this please let me know.

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