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Redirect with .htacess - URL with regex to URL

- by nicorellius

I have a temporary need to redirect some installer files on my web site. The redirects that are working now look something like this: Redirect 301 /installer_1.0.0.zip http://www.example.com/download/installer_1.0.3.zip Redirect 301 /installer_1.0.1.zip http://www.example.com/download/installer_1.0.3.zip Redirect 301 /installer_1.0.2.zip http://www.example.com/download/installer_1.0.3.zip I would like to use a regex instead of having multiple lines for each version I need to redirect. I have tried these options with no success: Redirect 301 /installer_(.*).zip http://www.example.com/download/installer_1.0.3.zip Redirect 301 /installer_([0-9+]\.[0-9+]\.[0-9+]).zip http://www.example.com/download/installer_1.0.3.zip Should these work or am I doing something wrong? Thanks.

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rsyslog - template - regex data for insertion into db

- by Mike Purcell

I've been googling around the last few days looking for a solid example of how to regex a log entry for desired data, which is then to be inserted into a database, but apparently my google-fu is lacking. What I am trying to do is track when an email is sent, and then track the remote mta response, specifically the dsn code. At this point I have two templates setup for each situation: # /etc/rsyslog.conf ... $Template tpl_custom_header, "MPurcell: CUSTOM HEADER Template: %msg%\n" $Template tpl_response_dsn, "MPurcell: RESPONSE DSN Template: %msg%\n" # /etc/rsyslog.d/mail if $programname == 'mail-myapp' then /var/log/mail/myapp.log if ($programname == 'mail-myapp') and ($msg contains 'X-custom_header') then /var/log/mail/test.log;tpl_custom_header if ($programname == 'mail-myapp') and ($msg contains 'dsn=') then /var/log/mail/test.log;tpl_response_dsn & ~ Example log entries: MPurcell: CUSTOM HEADER Template: D921940A1A: prepend: header X-custom_header: 101 from localhost[127.0.0.1]; from=<[email protected]> to=<[email protected]> proto=ESMTP helo=<localhost>: headername: message-id MPurcell: RESPONSE DSN Template: D921940A1A: to=<[email protected]>, relay=gmail-smtp-in.l.google.com[2607:f8b0:400e:c02::1a]:25, delay=2, delays=0.12/0.01/0.82/1.1, dsn=2.0.0, status=sent (250 2.0.0 OK 1372378600 o4si2828280pac.279 - gsmtp) From the CUSTOM HEADER Template I would like to extract: D921940A1A, and X-custom_header value; 101 From the RESPONSE DSN Template I would like to extract: D921940A1A, and "dsn=2.0.0"

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Regex slow on Windows Server 2008

- by pjmyburg

Hi I have a situation where my regular expressions compile extremely slowly on Windows Server 2008. I wrote a small console application to highlight this issue. The app generates its own input and builds up a Regex from words in an XML file. I built a release version of this app and ran it both on my personal laptop (running XP) and the Windows 2008 server. The regular expression took 0.21 seconds to compile on my laptop, but 23 seconds to compile on the server. Any ideas what could be causing this? The problem is only on first use of the Regex (when it is first compiled - thereafter it is fine) I have also found another problem - when using \s+ in the regular expression on the same Windows 2008 server, the memory balloons (uses 4GB+) and the compilation of the Regex never finishes. Is there a known issue with Regex and 64 bit .net? Is there a fix/patch available for this? I cannot really find any info on the net, but I have found a few articles about this same issues in Framework 2.0 - surely this has been fixed by now? More info: The server is running the 64 bit version of the .net framework (3.5 SP1) and on my laptop I have Visual Studio 2008 and the 3.5 framework installed. The regular expression is of the following pattern: ^word$|^word$|^word$ and is constructed with the following flags: RegexOptions.IgnoreCase | RegexOptions.Compiled Edit: Here is a code snippet: StringBuilder regexString = new StringBuilder(); if (!String.IsNullOrEmpty(fileLocation)) { XmlTextReader textReader = new XmlTextReader(fileLocation); textReader.Read(); while (textReader.Read()) { textReader.MoveToElement(); if (textReader.Name == "word") { regexString.Append("^" + textReader.GetAttribute(0) + "$|"); } } ProfanityFilter = new Regex(regexString.ToString(0, regexString.Length - 1), RegexOptions.IgnoreCase | RegexOptions.Compiled); } DateTime time = DateTime.Now; Console.WriteLine("\nIsProfane:\n" + ProfanityFilter.IsMatch("test")); Console.WriteLine("\nTime: " + (DateTime.Now - time).TotalSeconds); Console.ReadKey(); This results in a time of 0.21 seconds on my laptop and 23 seconds on the 2008 server. The XML file consists of 168 words in the following format: <word text="test" />

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Using C# regex to select text based on custom tags

- by spaceman

I have a string in c# containing some data i need to extract based on certain conditions. The string contains many tenders in the following form : <TENDER> some words, don't know how many, may contain numbers and things like slashes (/) or whatever <DESCRIPTION> some more words and possibly other things like numbers or whatever describing the tender here </DESCRIPTION> some more words and possibly numbers and weird things </TENDER> This string doesn't contain any nested <TENDER> tags, its flat. The <DESCRIPTION> tags occur only once within the <TENDER> tags. I'm using : <TENDER>(.+?)</TENDER> as the regex to split up the tenders and it works fine. If this is wrong or stupid and you know a better way to write this please let me know as I have discovered I suck at regex. My problem that I now need to only select a tender if its description contains any word in a list of keywords (lets say for now i want to select a tender only if it contains either "concrete" or"brick" in the description). So far the regex I have come up with looks like this, but I don't know what to put in the middle. Also I have a vague suspicion that this might return me some false positives. <TENDER>(.+?)<DESCRIPTION>have no idea what to do here</DESCRIPTION>(.+?)</TENDER> If any of you regex guru's could point me in the right direction I would be most appreciative.

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Problem with logicalOR ( regex ) not greedy

- by Marin Doric

This is the part of a string "21xy5". I want to insert " * " surrounded with whitespace between: digit and letter, letter and digit, letter and letter. I use this regex pattern "\d[a-z]|[a-z]\d|[a-z][a-z]" to find indexs where I gona insert string " * ". Problem is that when regex OR(|) in string 21xy5 trays to match 21-x|x-y|y-5, when first condition 21-x success, second x-y is not checked, and third success. So I have 21 * xy * 5 instead 21 * x * y * 5. If input string is like this xy21, then x-y success and then I have x * y21. Problem is that logical OR is not greedy. Regex reg = new Regex(@"\d[a-z]|[a-z]\d|[a-z][a-z]" ); MatchCollection matchC; matchC = reg.Matches(input); int ii = 1; foreach (Match element in matchC) { input = input.Insert(element.Index + ii, " * "); ii += 3; } return input;

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Regex: markdown-style link matching

- by The.Anti.9

I want to parse markdown style links, but I'm having some trouble matching the reference style ones. Like this one: [id]: http://example.com/ "Optional Title Here" My regex gets the id and the url, but not the title. Heres what I have: /\[([a-zA-Z0-9_-]+)\]: (\S+)\s?("".*?"")?/ I go through and add the references to a hashtable. the id as the key and the value is an instance of a class I made called LinkReference that just contains the url and the title. In case the problem is not my regex, and my code adding the matches to the hash table, Heres my code for that too: Regex rx = new Regex(@"\[([a-zA-Z0-9_-]+)\]: (\S+)\s?("".*?"")?"); MatchCollection matches = rx.Matches(InputText); foreach (Match match in matches) { GroupCollection groups = match.Groups; string title = null; try { title = groups[3].Value; } catch (Exception) { // keep title null } LinkReferences.Add(groups[1].Value, new LinkReference(groups[2].Value, title)); }

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codingBat separateThousands using regex (and unit testing how-to)

- by polygenelubricants

This question is a combination of regex practice and unit testing practice. Regex part I authored this problem separateThousands for personal practice: Given a number as a string, introduce commas to separate thousands. The number may contain an optional minus sign, and an optional decimal part. There will not be any superfluous leading zeroes. Here's my solution: String separateThousands(String s) { return s.replaceAll( String.format("(?:%s)|(?:%s)", "(?<=\\G\\d{3})(?=\\d)", "(?<=^-?\\d{1,3})(?=(?:\\d{3})+(?!\\d))" ), "," ); } The way it works is that it classifies two types of commas, the first, and the rest. In the above regex, the rest subpattern actually appears before the first. A match will always be zero-length, which will be replaceAll with ",". The rest basically looks behind to see if there was a match followed by 3 digits, and looks ahead to see if there's a digit. It's some sort of a chain reaction mechanism triggered by the previous match. The first basically looks behind for ^ anchor, followed by an optional minus sign, and between 1 to 3 digits. The rest of the string from that point must match triplets of digits, followed by a nondigit (which could either be $ or \.). My question for this part is: Can this regex be simplified? Can it be optimized further? Ordering rest before first is deliberate, since first is only needed once No capturing group Unit testing part As I've mentioned, I'm the author of this problem, so I'm also the one responsible for coming up with testcases for them. Here they are: INPUT, OUTPUT "1000", "1,000" "-12345", "-12,345" "-1234567890.1234567890", "-1,234,567,890.1234567890" "123.456", "123.456" ".666666", ".666666" "0", "0" "123456789", "123,456,789" "1234.5678", "1,234.5678" "-55555.55555", "-55,555.55555" "0.123456789", "0.123456789" "123456.789", "123,456.789" I haven't had much experience with industrial-strength unit testing, so I'm wondering if others can comment whether this is a good coverage, whether I've missed anything important, etc (I can always add more tests if there's a scenario I've missed).

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Changing FileNames using RegEx and Recursion

- by yeahumok

Hello I'm trying to rename files that my program lists as having "illegal characters" for a SharePoint file importation. The illegal characters I am referring to are: ~ # % & * {} / \ | : < ? - "" What i'm trying to do is recurse through the drive, gather up a list of filenames and then through Regular Expressions, pick out file names from a List and try to replace the invalid characters in the actual filenames themselves. Anybody have any idea how to do this? So far i have this: (please remember, i'm a complete n00b to this stuff) class Program { static void Main(string[] args) { string[] files = Directory.GetFiles(@"C:\Documents and Settings\bob.smith\Desktop\~Test Folder for [SharePoint] %testing", "*.*", SearchOption.AllDirectories); foreach (string file in files) { Console.Write(file + "\r\n"); } Console.WriteLine("Press any key to continue..."); Console.ReadKey(true); string pattern = " *[\\~#%&*{}/:<>?|\"-]+ *"; string replacement = " "; Regex regEx = new Regex(pattern); string[] fileDrive = Directory.GetFiles(@"C:\Documents and Settings\bob.smith\Desktop\~Test Folder for [SharePoint] %testing", "*.*", SearchOption.AllDirectories); StreamWriter sw = new StreamWriter(@"C:\Documents and Settings\bob.smith\Desktop\~Test Folder for [SharePoint] %testing\File_Renames.txt"); foreach(string fileNames in fileDrive) { string sanitized = regEx.Replace(fileNames, replacement); sw.Write(sanitized + "\r\n"); } sw.Close(); } } So what i need to figure out is how to recursively search for these invalid chars, replace them in the actual filename itself. Anybody have any ideas?

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Regex to extract portions of file name

- by jakesankey

I have text files formatted as such: R156484COMP_004A7001_20100104_065119.txt I need to consistently extract the R****COMP, the 004A7001 number, 20100104 (date), and don't care about the 065119 number. the problem is that not ALL of the files being parsed have the exact naming convention. some may be like this: R168166CRIT_156B2075_SU2_20091223_123456.txt or R285476COMP_SU1_125A6025_20100407_123456.txt So how could I use regex instead of split to ensure I am always getting that serial (ex. 004A7001), the date (ex. 20100104), and the R****COMP (or CRIT)??? Here is what I do now but it only gets the files formatted like my first example. if (file.Count(c => c == '_') != 3) continue; and further down in the code I have: string RNumber = Path.GetFileNameWithoutExtension(file); string RNumberE = RNumber.Split('_')[0]; string RNumberD = RNumber.Split('_')[1]; string RNumberDate = RNumber.Split('_')[2]; DateTime dateTime = DateTime.ParseExact(RNumberDate, "yyyyMMdd", Thread.CurrentThread.CurrentCulture); string cmmDate = dateTime.ToString("dd-MMM-yyyy"); UPDATE: This is now where I am at -- I get an error to parse RNumberDate to an actual date format. "Cannot implicitly convert type 'RegularExpressions.Match' to 'string' string RNumber = Path.GetFileNameWithoutExtension(file); Match RNumberE = Regex.Match(RNumber, @"^(R|L)\d{6}(COMP|CRIT|TEST|SU[1-9])(?=_)", RegexOptions.IgnoreCase); Match RNumberD = Regex.Match(RNumber, @"(?<=_)\d{3}[A-Z]\d{4}(?=_)", RegexOptions.IgnoreCase); Match RNumberDate = Regex.Match(RNumber, @"(?<=_)\d{8}(?=_)", RegexOptions.IgnoreCase); DateTime dateTime = DateTime.ParseExact(RNumberDate, "yyyyMMdd", Thread.CurrentThread.CurrentCulture); string cmmDate = dateTime.ToString("dd-MMM-yyyy")

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Using Regex, how can I remove certain characters from inside angle-brackets, leaving the characters

- by Iain Fraser

Edit: To be clear, please understand that I am not using Regex to parse the html, that's crazy talk! I'm simply wanting to clean up a messy string of html so it will parse Edit #2: I should also point out that the control character I'm using is a special unicode character - it's not something that would ever be used in a proper tag under any normal circumstances Suppose I have a string of html that contains a bunch of control characters and I want to remove the control characters from inside tags only, leaving the characters outside the tags alone. For example Here the control character is the numeral "1". Input The quick 1<strong>orange</strong> lemming <sp11a1n 1class1='jumpe111r'11>jumps over</span> 1the idle 1frog Desired Output The quick 1<strong>orange</strong> lemming <span class='jumper'>jumps over</span> 1the idle 1frog So far I can match tags which contain the control character but I can't remove them in one regex. I guess I could perform another regex on my matches, but I'd really like to know if there's a better way. My regex Bear in mind this one only matches tags which contain the control character. <(([^>])*?`([^>])*?)*?> Thanks very much for your time and consideration. Iain Fraser

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Using Regex Replace when looking for un-escaped characters

- by Daniel Hollinrake

I've got a requirement that is basically this. If I have a string of text such as "There once was an 'ugly' duckling but it could never have been \'Scarlett\' Johansen" then I'd like to match the quotes that haven't already been escaped. These would be the ones around 'ugly' not the ones around 'Scarlett'. I've spent quite a while on this using a little C# console app to test things and have come up with the following solution. private static void RegexFunAndGames() { string result; string sampleText = @"Mr. Grant and Ms. Kelly starred in the film \'To Catch A Thief' but not in 'Stardust' because they'd stopped acting by then"; string rePattern = @"\\'"; string replaceWith = "'"; Console.WriteLine(sampleText); Regex regEx = new Regex(rePattern); result = regEx.Replace(sampleText, replaceWith); result = result.Replace("'", @"\'"); Console.WriteLine(result); } Basically what I've done is a two step process find those characters that have already been escaped, undo that then do everything again. It sounds a bit clumsy and I feel that there could be a better way.

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Insert multiple line breaks into a JavaScript string (regex) (CodeMirror)

- by PJH

I have a few strings and I would like to insert some line breaks into them at certain points. I figured out a few of the logistics but as a whole I can't seem to crack this problem, probably because I have limited experience with regex. Basically I have a long string of XML tags that is all on one line. I want to add line breaks at certain points to get the data more formatted and looking nice. I am using CodeMirror to display this data on a webpage but for some reason its all on line #1. So I need to go from something like this: <Sample><Name></Name><PhoneNumber><AreaCode></AreaCode><Number></Number></PhoneNumber></Sample> To something like this: <Sample> <Name></Name> <PhoneNumber> <AreaCode></AreaCode> <Number></Number> </PhoneNumber> </Sample> CodeMirror will take care of the rest of the formatting all I need to do is insert the line breaks in the right spot using regex or a loop of some sort. The Tags will or can change so I am guessing regex has to be used. I have had success inserting line breaks with \n and &#xD but can't seem to get regex to detect the proper locations. Any help would be greatly appreciated. Thanks. UPDATE I overlooked this but the brackets are in fact being sent as < and > So example tag would look like: <PhoneNumber> or </PhoneNumber> So basically need to insert a \n after every > that is a closing tag or a beginning tag that contains children tags.

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Regex help in java validations

- by user1697113

Hi i want to do some validations.I used to put regex in JS but im new to regex in java, so i tried to make up a code on similar lines in java. Here is what i did. 1)Check whether first character in string is alphanumeric. 2)Check whether the string atleast 1 number. so i wrote a code, but it is always returning false.I am not sure if i'm doing this correctly. private static boolean checkEmbeddedPassword(final String field) { boolean returnValue=true; String testpatternAlpha="/^[A-Za-z0-9].+$/"; String testNumber="/[0-9]/"; Pattern pattern=Pattern.compile(testpatternAlpha); Pattern pattern2=Pattern.compile(testNumber); Matcher matcher = pattern.matcher(field); Matcher matcher2 = pattern2.matcher(field); boolean firstChar=matcher.matches(); boolean numberFlag=matcher2.matches(); System.out.println("-----the value of pwd iss-----"+field); System.out.println("---------Regex---------Out--put-----"+firstChar); System.out.println("---------Regex---------Out- for numeral-put-----"+numberFlag); if(firstChar){ returnValue=false; } else if(field.contains(" ")) { System.out.println("-----------cannot have space------"); returnValue=false; } else if(numberFlag) { returnValue=false; } return returnValue; }

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Vim: how to undo a regex with a new regex?

- by Victor Tihomirov

my I have here a text that has been encrypted in Vi this way: 1,$s/\(.\)\1/&&/g 1,$s/\(.\)\(.\)\2\2\2/\2\2\2\1\2/g 1,$s/\(.\)\(.\)\(.\)\(.\)/\3\1\4\2/g 1,$s/\(...\)\(...\)/\2\1/g The task is to write a new regex for each regex in order to undo the the changes, so-called decrypting of the text. I figured out how to undo the last 2 changes: :1,$s/\(...\)\(...\)/\2\1/g :1,$s/\(.\)\(.\)\(.\)\(.\)/\2\4\1\3/g I'd like you to explain me what do the first two regex do. What does \1 or \2\2\2 mean before the forward slash? I assume that after the slash they change place (but wouldn't it be enough to just write \2\1 instead of \2\2\2\1\2(what does it mean?)? I just don't get it). And what does & or && mean? Thank you

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codingBat plusOut using regex

- by polygenelubricants

This is similar to my previous efforts (wordEnds and repeatEnd): as a mental exercise, I want to solve this toy problem using regex only. Description from codingbat.com: Given a string and a non-empty word string, return a version of the original string where all chars have been replaced by pluses ("+"), except for appearances of the word string which are preserved unchanged. plusOut("12xy34", "xy") ? "++xy++" plusOut("12xy34", "1") ? "1+++++" plusOut("12xy34xyabcxy", "xy") ? "++xy++xy+++xy" There is no mention whether or not to allow overlap (e.g. what is plusOut("+xAxAx+", "xAx")?), but my non-regex solution doesn't handle overlap and it passes, so I guess we can assume non-overlapping occurrences of word if it makes it simpler. In any case, I'd like to solve this using regex (of the same style that I did before with the other two problems), but I'm absolutely stumped. I don't even have anything to show, because I have nothing that works. So let's see what the stackoverflow community comes up with.

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Isolate SQL field using regex

- by Das123

I'm trying to isolate a specific field in a SQL dump file so I can edit it but I'm not having any luck. The regex I'm using is: ^(?:(?:'[^\r\n']*'|[^,\r\n]*),){6}('[^\r\n']*'|[^,\r\n]*) Which is supposed to grab the seventh field and place it inside reference 1. The trouble is that this is stumbling when ever it finds a comma inside a text field and counts the partial match as the allowable matches. Eg. (1, 'Title', 1, 3, '2006-09-29', 'Commas, the bane of my regex', 'This is the target', 2, 4) matches " the bane of my regex'" instead of "'This is the target'".

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Regex for capturing numbered text list

- by crunchyt

I have a test list that I am trying to capture data from using a regex. Here is a sample of the text format: (1) this is a sample string /(2) something strange /(3) another bit of text /(4) the last one/ something!/ I have a Regex that currently captures this correctly, but I am having some difficulty with making it work under outlier conditions. Here is my regex /\(?\d\d?\)([^\)]+)(\/|\z)/ Unfortunately some of the data contains parentheses like this: (1) this is a sample string (1998-1999) /(2) something strange (blah) /(3) another bit of text /(4) the last one/ something!/ The substrings '(1998-1999)' and '(blah)' make it fail! Anyone care to have a crack at this one? Thank you :D

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bash rename using regex array substitution

- by mulllhausen

hi, i have a very similar question as for this post. i would like to know how to rename occurances within a filename with designated substitutions. for example if the original file is called: 'the quick brown quick brown fox.avi' i would like to rename it to 'the slow red slow red fox.avi'. i tried this: new="(quick=>'slow',brown=>'red')" regex="quick|brown" rename -v "s/($regex)/$new{$1}/g" * but no love :( i also tried with regex="qr/quick|brown/" but this just gives errors. any idea what im doing wrong?

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Regex to extract link

- by Derin

Hi, I'm looking for a regex to extract links from a url. The url would be as below: /redirecturl?u=http://www.abc.com/&tkn=Ue4uhv&ui=fWrQfyg46CADA&scr=SSTYQFjAA&mk=4D6GHGLfbQwETR I need to extract the link http://www.abc.com from the above url. I tried the regex: redirecturl\\?u=(?<link>[^\"]+)& This works, but the problem is that it does not truncate all the characters after the first occurrence of &. It would be great if you could modify the regex so that I just get the link. Thanks in advance.

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Problems with matching emails with regex

- by Gandalf StormCrow

Hello, I'm trying to match an email address here is what I've come up with so far : String text = "[email protected]"; String regex = "(\\w+)@{1}(\\w+){2,}\\.{1}\\w{2,4}"; This however works with following cases : [email protected] [email protected] [email protected] So it matches any alphanumeric character repeated once or more that comes before one @ followed by any alphanumeric character repeated at least two times(which is minimal characters for any domain name) followed by one .(dot) and followed by any alphanumeric character repeated at least 2 times and at most 4 times(because there are domains such as .us or .mobi). This expression however does not work with emails such as : [email protected] [email protected] [email protected] [email protected] etc as many subdomains or [email protected] [email protected] [email protected] [email protected] I've just started to learn regex and I found interesting to try to solve problems such as these by using regex .. not partially but for each case, any help would be much appriciated. Thank you

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Match multiline regex in file object

- by williamx

How can I extract the groups from this regex from a file object (data.txt)? import numpy as np import re import os ifile = open("data.txt",'r') # Regex pattern pattern = re.compile(r""" ^Time:(\d{2}:\d{2}:\d{2}) # Time: 12:34:56 at beginning of line \r{2} # Two carriage return \D+ # 1 or more non-digits storeU=(\d+\.\d+) \s uIx=(\d+) \s storeI=(-?\d+.\d+) \s iIx=(\d+) \s avgCI=(-?\d+.\d+) """, re.VERBOSE | re.MULTILINE) time = []; for line in ifile: match = re.search(pattern, line) if match: time.append(match.group(1)) The problem in the last part of the code, is that I iterate line by line, which obviously doesn't work with multiline regex. I have tried to use pattern.finditer(ifile) like this: for match in pattern.finditer(ifile): print match ... just to see if it works, but the finditer method requires a string or buffer. I have also tried this method, but can't get it to work matches = [m.groups() for m in pattern.finditer(ifile)] Any idea?

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Regex to match the first file in a rar archive file set in Python

- by mridang

I need to uncompress all the files in a directory and for this I need to find the first file in the set. I'm currently doing this using a bunch of if statements and loops. Can i do this this using regex? Here's a list of files that i need to match: yes.rar yes.part1.rar yes.part01.rar yes.part001.rar yes.r01 yes.r001 These should NOT be matched: no.part2.rar no.part02.rar no.part002.rar no.part011.rar no.r002 no.r02 I found a similar regex on this thread but it seems that Python doesn't support varible length lookarounds. A single line regex would be complicated but I'll document it well and it's not a problem. It's just one of those problems you beat your heap up, over. Thanks in advance guys. :)

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Regex pattern problem in python

- by mridang

I need to extract parts of a string using regex in Python. I'm good with basic regex but I'm terrible at lookarounds. I've shown two sample records below. The last big is always a currency field e.g. in the first one it is 4,76. In the second one it is 2,00. The second has an account number that is the pattern of \d{6}-\d{6}. Anything after that is the currency. 24.02 24.02VALINTATALO MEGAHERTSI4,76- 24.02 24.02DOE MRIDANG 157235-1234582,00- Could you help me out with this regex? What I've written so far is given below but it considers everything after the 'dash' in the account number to be the currency. .*?(\d\d\.\d\d)(.*?)\s*(?<!\d{6}-\d{6})(\d*,\d\d) Thanks in advance

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codingBat last2 using regex

- by polygenelubricants

Okay guys, this is similar to my repeatEnd and wordEnds efforts; I want to solve this codingBat Warmup-2 question using only regex-based techniques as a "brain gymnastics" exercise. This solution works for codingBat tests: public int last2(String str) { return str.isEmpty() ? 0 : str.split( str.replaceAll( ".*(.)(.)", "$1(?=$2)" //.replaceAll("(\\$.)", "\\\\\\\\Q$1\\\\\\\\E") ), -1 ).length - 1 - 1; } The monstrous octo-slashes aren't needed to pass codingBat, but is needed for a proper regex-based solution. That is, if I want this (and I do!): assert last2("..+++...++") == 2; I'd have to uncomment the second .replaceAll. I'm just wondering if others can come up with a simpler, more elegant regex solution for this problem. Preferably one that doesn't contain octo-slashes.

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regex : how to eliminiate urls ending with .dtd

- by dorelal

This is JavaScript regex. regex = /(http:\/\/[^\s]*)/g; text = "I have http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd and I like http://google.com a lot"; matches = text.match(regex); console.log(matches); I get both the urls in the result. However I want to eliminate all the urls ending with .dtd . How do I do that? Note that I am saying ending with .dtd should be removed. It means a url like http://a.dtd.google.com should pass .

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