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  • Why does Saxon evaluate the result-document URI to be the same?

    - by Jan
    My XSL source document looks like this <Topology> <Environment> <Id>test</Id> <Machines> <Machine> <Id>machine1</Id> <modules> <module>m1</module> <module>m2</module> </modules> </Machine> </Machines> </Environment> <Environment> <Id>production</Id> <Machines> <Machine> <Id>machine1</Id> <modules> <module>m1</module> <module>m2</module> </modules> </Machine> <Machine> <Id>machine2</Id> <modules> <module>m3</module> <module>m4</module> </modules> </Machine> </Machines> </Environment> </Topology> I want to create one result-document per machine, so I use the following stylesheet giving modelDir as path for the result-documents as parameter. <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" name="myXML" doctype-system="http://java.sun.com/dtd/properties.dtd"/> <xsl:template match="/"> <xsl:for-each-group select="/Topology/Environment/Machines/Machine" group-by="Id"> <xsl:variable name="machine" select="Id"/> <xsl:variable name="filename" select="concat($modelDir,$machine,'.xml')" /> <xsl:message terminate="no">Writing machine description to <xsl:value-of select="$filename"/></xsl:message> <xsl:result-document href="$filename" format="myXML"> <xsl:variable name="currentMachine" select="Id"/> <xsl:for-each select="current-group()/LogicalHosts/LogicalHost"> <xsl:variable name="environment" select="normalize-space(../../../../Id)"/> <xsl:message terminate="no">Module <xsl:value-of select="."/> for <xsl:value-of select="$environment"/></xsl:message> </xsl:for-each> </xsl:result-document> </xsl:for-each-group> </xsl:template> As my messages show me this seems to work fine - if saxon would not evaluate the URI of the result-document to be the same and thus give the following output. Writing machine description to target/build/model/m1.xml Module m1 for test Module m2 for test Module m1 for production Module m2 for production Writing machine description to target/build/model/m2.xml Error at xsl:result-document on line 29 of file:/C:/Projekte/.../machine.xsl: XTDE1490: Cannot write more than one result document to the same URI, or write to a URI that has been read: file:/C:/Projekte/.../$filename file:/C:/Projekte/.../machine.xsl(29,-1) : here Cannot write more than one result document to the same URI, or write to a URI that has been read: file:/C:/Projekte/.../$filename ; SystemID: file:/C:/Projekte/.../machine.xsl; Line#: 29; Column#: -1 net.sf.saxon.trans.DynamicError: Cannot write more than one result document to the same URI, or write to a URI that has been read: file:/C:/Projekte/.../$filename at net.sf.saxon.instruct.ResultDocument.processLeavingTail(ResultDocument.java:300) at net.sf.saxon.instruct.Block.processLeavingTail(Block.java:365) at net.sf.saxon.instruct.Instruction.process(Instruction.java:91) Any ideas on how to solve this?

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  • DOCTYPE declaration getting lost when using XSL

    - by Rachel
    The input to my XSL is an XHTML. After applying the XSL the DOCTYPE declaration that was present in the input XHTML gets lost in the output. Do i have an option to copy/retain the DOCTYPE declaration in the output using XSL. The XSL processor that i am using is SAXON.

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  • XSL match some but not all

    - by Willb
    I have a solution from an earlier post that was kindly provided by Dimitre Novatchev. <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:my="my:my"> <xsl:output method="xml" version="1.0" encoding="iso-8859-1" indent="yes"/> <xsl:key name="kPhysByName" match="KB_XMod_Modules" use="Physician"/> <xsl:template match="/"> <result> <xsl:apply-templates/> </result> </xsl:template> <xsl:template match="/*/*/*[starts-with(name(), 'InfBy')]"> <xsl:variable name="vCur" select="."/> <xsl:for-each select="document('doc2.xml')"> <xsl:variable name="vMod" select="key('kPhysByName', $vCur)"/> <xsl:copy> <items> <item> <label> <xsl:value-of select="$vMod/Physician"/> </label> <value> <xsl:value-of select="$vMod/XModID"/> </value> </item> </items> </xsl:copy> </xsl:for-each> </xsl:template> </xsl:stylesheet> I now need to use additional fields in my source XML and need the existing labels intact but I'm having problems getting this going. <instance> <NewTag>Hello</newTag1> <AnotherNewTag>Everyone</AnotherNewTag> <InfBy1>Dr Phibes</InfBy1> <InfBy2>Dr X</InfBy2> <InfBy3>Dr Chivago</InfBy3> </instance> It drops the additional labels and outputs <result xmlns:my="my:my"> HelloEveryone <items> <item> <label>Dr Phibes</label> <value>60</value> </item> </items> ... I've been experimenting a lot with <xsl:otherwise> <xsl:copy-of select="."> </xsl:copy-of> </xsl:otherwise> but being an xsl newbie I can't seem to get this to work. I've a feeling I'm barking up the wrong tree! Does anyone have any ideas? Thanks, Will

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  • I would like to filter XSL output based on a Radio button selection

    - by Phil Speth
    Here is my example I am trying to filter by year based on user selection: I assume some js or jQuery code would be needed: XML file: <?xml version="1.0" encoding="ISO-8859-1"?> <catalog> <cd> <title>Empire Burlesque3</title> <artist>Bob Dylan</artist> <country>USA</country> <company>Columbia</company> <price>10.90</price> <year>1985</year> </cd> <cd> <title>Hide your heart</title> <artist>Bonnie Tyler</artist> <country>UK</country> <company>CBS Records</company> <price>9.90</price> <year>1988</year> </cd> <cd> <title>Greatest Hits</title> <artist>Dolly Parton</artist> <country>USA</country> <company>RCA</company> <price>9.90</price> <year>1982</year> </cd> <cd> <title>Still got the blues</title> <artist>Gary Moore</artist> <country>UK</country> <company>Virgin records</company> <price>10.20</price> <year>1990</year> </cd> <cd> <title>Eros</title> <artist>Eros Ramazzotti</artist> <country>EU</country> <company>BMG</company> <price>9.90</price> <year>1997</year> </cd> <cd> <title>One night only</title> <artist>Bee Gees</artist> <country>UK</country> <company>Polydor</company> <price>10.90</price> <year>1998</year> </cd> <cd> <title>Sylvias Mother</title> <artist>Dr.Hook</artist> <country>UK</country> <company>CBS</company> <price>8.10</price> <year>1973</year> </cd> <cd> <title>Maggie May</title> <artist>Rod Stewart</artist> <country>UK</country> <company>Pickwick</company> <price>8.50</price> <year>1990</year> </cd> <cd> <title>Romanza</title> <artist>Andrea Bocelli</artist> <country>EU</country> <company>Polydor</company> <price>10.80</price> <year>1996</year> </cd> <cd> <title>When a man loves a woman</title> <artist>Percy Sledge</artist> <country>USA</country> <company>Atlantic</company> <price>8.70</price> <year>1987</year> </cd> <cd> <title>Black angel</title> <artist>Savage Rose</artist> <country>EU</country> <company>Mega</company> <price>10.90</price> <year>1995</year> </cd> <cd> <title>1999 Grammy Nominees</title> <artist>Many</artist> <country>USA</country> <company>Grammy</company> <price>10.20</price> <year>1999</year> </cd> <cd> <title>For the good times</title> <artist>Kenny Rogers</artist> <country>UK</country> <company>Mucik Master</company> <price>8.70</price> <year>1995</year> </cd> <cd> <title>Big Willie style</title> <artist>Will Smith</artist> <country>USA</country> <company>Columbia</company> <price>9.90</price> <year>1997</year> </cd> <cd> <title>Tupelo Honey</title> <artist>Van Morrison</artist> <country>UK</country> <company>Polydor</company> <price>8.20</price> <year>1971</year> </cd> <cd> <title>Soulsville</title> <artist>Jorn Hoel</artist> <country>Norway</country> <company>WEA</company> <price>7.90</price> <year>1996</year> </cd> <cd> <title>The very best of</title> <artist>Cat Stevens</artist> <country>UK</country> <company>Island</company> <price>8.90</price> <year>1990</year> </cd> <cd> <title>Stop</title> <artist>Sam Brown</artist> <country>UK</country> <company>A and M</company> <price>8.90</price> <year>1988</year> </cd> <cd> <title>Bridge of Spies</title> <artist>T`Pau</artist> <country>UK</country> <company>Siren</company> <price>7.90</price> <year>1987</year> </cd> <cd> <title>Private Dancer</title> <artist>Tina Turner</artist> <country>UK</country> <company>Capitol</company> <price>8.90</price> <year>1983</year> </cd> <cd> <title>Midt om natten</title> <artist>Kim Larsen</artist> <country>EU</country> <company>Medley</company> <price>7.80</price> <year>1983</year> </cd> <cd> <title>Pavarotti Gala Concert</title> <artist>Luciano Pavarotti</artist> <country>UK</country> <company>DECCA</company> <price>9.90</price> <year>1991</year> </cd> <cd> <title>The dock of the bay</title> <artist>Otis Redding</artist> <country>USA</country> <company>Atlantic</company> <price>7.90</price> <year>1987</year> </cd> <cd> <title>Picture book</title> <artist>Simply Red</artist> <country>EU</country> <company>Elektra</company> <price>7.20</price> <year>1985</year> </cd> <cd> <title>Red</title> <artist>The Communards</artist> <country>UK</country> <company>London</company> <price>7.80</price> <year>1987</year> </cd> <cd> <title>Unchain my heart</title> <artist>Joe Cocker</artist> <country>USA</country> <company>EMI</company> <price>8.20</price> <year>1987</year> </cd> </catalog> XSL File: <?xml version="1.0" encoding="ISO-8859-1"?> <!-- Edited by XMLSpy® --> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <html> <body> <input type="radio" name="Cost" value="1980" checked="checked" /> 1980 <input type="radio" name="Cost" value="1990" /> 1990 <h2>My CD Collection</h2> <table border="1"> <tr bgcolor="#9acd32"> <th>Title</th> <th>Artist</th> </tr> <xsl:for-each select="catalog/cd"> <xsl:if test="year>1990"> <tr> <td><xsl:value-of select="title"/></td> <td><xsl:value-of select="artist"/></td> <td><xsl:value-of select="year"/></td> </tr> </xsl:if> </xsl:for-each> </table> </body> </html> </xsl:template> </xsl:stylesheet>

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  • Can I build this XPath query dynamically in XSLT?

    - by Martin Doms
    I have a document that looks something like <root> <element> <subelement1 /> <subelement2 /> </element> <element> <subelement2 /> <subelement1 /> </element> </root> In my XSLT sheet in the context of /element[2]/[someNode] I want to get a number that represents the distance of /element[1]/[someNode] (ie, the number of preceding siblings of /element1/[someNode]). For example, in the context of /element[2]/subelement1 I'd like to have some way to get the number 2, the distance from /element[1] to /element[1]/subelement2. I only ever need the distance of the given node name from the first instance of . Intuitively I thought I could construct this like <xsl:variable name="nodename" select="name()" /> <xsl:value-of select="/element[1]/$nodename/preceding-sibling::*" /> but unfortunately this sheet doesn't compile. Is what I'm trying to achieve possible in XSLT?

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  • How can I convert convert docx or wordml xml files to xsl-fo?

    - by Jon Pastore
    I've been looking for a method to convert docx or wordml xml to xsl-fo. I read this post: http://stackoverflow.com/questions/156683/what-is-the-best-xslt-engine-for-perl but I'm having exceptional problems getting apache-fop going. I was able to download the bins and run it locally but the formatting was a little off and it didn't maintain the headers and footers or section 1 or section 3 (17 page doc 3 sections) it also overlapped the text over the outline numbers and did not maintain the font used. trying a more simple test caused fop to fail completely. I would like to find a way to create a PDF that is at least close to 100% accurate reproduction of the original doc.

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  • XSLT generating attributes if source-Element is in parameterfile

    - by Siegfried
    Hi, i got an xml-file with some elements. For some of these is an aqvivalent in a parameter xml-file along with some other elements. I want to add these other elements from parm-file as parameter to output file if element-names are matching. (the Attributes should only be generated if an element "InvoiceHeader" exists in the source-xml. Here is my code... <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions"> <xsl:variable name="rpl" select="document('ParamInvoice.xml')"></xsl:variable> <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> <xsl:template match="/"> <xsl:apply-templates></xsl:apply-templates> </xsl:template> <xsl:template match="*"> <xsl:copy> <xsl:if test="$rpl/StoraInvoice/local-name()"> <xsl:call-template name="AttributeErzeugen"> <xsl:with-param name="attr" select="$rpl/StoraInvoice/local-name()"></xsl:with-param> </xsl:call-template> </xsl:if> <xsl:apply-templates></xsl:apply-templates> </xsl:copy> </xsl:template> <xsl:template name="AttributeErzeugen"> <xsl:param name="attr"></xsl:param> <xsl:for-each select="$attr"> <xsl:attribute name="{Attibute/@name}"><xsl:value-of select="."></xsl:value- of></xsl:attribute> </xsl:for-each> </xsl:template> </xsl:stylesheet> and here the param-file <?xml version="1.0" encoding="UTF-8"?> <StoraInvoice> <InvoiceHeader> <Attribute name="Fuehrend">YYY</Attribute> <Attribute name="Feld">FFFF</Attribute> <Attribute name="Format">XYZXYZ</Attribute> </InvoiceHeader> </StoraInvoice> Siegfried

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  • Actual element tags are not getting captured.

    - by user323719
    I am using the below piece of XSL code to construct a span tag calling a javascript function on mouseover. The input to the javascipt should be a html table. The output from the variable "showContent" gives just the text content but not along with the table tags. How can this be resolved. XSL: <xsl:variable name="aTable" as="element()*"> <table border="0" cellspacing="0" cellpadding="0"> <xsl:for-each select="$capturedTags"> <tr><td><xsl:value-of select="node()" /></td></tr> </xsl:for-each> </table> </xsl:variable> <xsl:variable name="start" select='concat("Tip(&#39;", "")'></xsl:variable> <xsl:variable name="end" select='concat("&#39;)", "")'></xsl:variable> <xsl:variable name="showContent"> <xsl:value-of select='concat($start,$aTable,$end)'/> </xsl:variable> <span xmlns="http://www.w3.org/1999/xhtml" onmouseout="{$hideContent}" onmouseover="{$showContent}" id="{$textNodeId}"><xsl:value-of select="$textNode"></xsl:value-of></span> Actual Output: <span onmouseout="UnTip()" onmouseover="Tip('content1')" id="d1t14"is my </span Expected output: <span onmouseout="UnTip()" onmouseover="Tip('<table><tr><td>content1</td></tr>')" id="d1t14">is my </span> What is the change that needs to done in the above XSL for the table, tr and td tags to get passed?

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  • Looping through all attributes of a XML element in XSLT

    - by TheGNUGuy
    Hey everyone, I am trying to use <xsl:for-each select="@*"> to grab all the attributes of a given element but when i do that my <xsl:choose> statement doesn't execute. Here is the element that I'm working with: <textBox id="Airfare" value="" label="text 1"/> Here is the XSLT template I'm using: <xsl:template match="textBox"> <div> <xsl:choose> <xsl:when test="@label"> <xsl:value-of select="@label"/> </xsl:when> <xsl:otherwise> <xsl:text>No Label Defined</xsl:text> </xsl:otherwise> </xsl:choose> <xsl:element name="input"> <xsl:attribute name="type">text</xsl:attribute> <xsl:for-each select="@*"> <xsl:choose> <xsl:when test="@id"> <xsl:attribute name="name">form_<xsl:value-of select="@id"/></xsl:attribute> <xsl:attribute name="id">form_<xsl:value-of select="@id"/></xsl:attribute> </xsl:when> <xsl:when test="@label"> </xsl:when> <xsl:otherwise> <xsl:copy-of select="current()"/> </xsl:otherwise> </xsl:choose> </xsl:for-each> </xsl:element> </div> And when I generate the HTML using PHP I get this: <div>text 1<input type="text" id="Airfare" value="" label="text 1"></div> As you can see it didn't add form_ to the id attribute it didn't generate a name attribute and it didn't skip over the label attribute. Thanks for your help!

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  • Get current node's local-name in XSL

    - by green67
    Here's the structure of my XML <FileRoot> <UserSet1> <User> <FirstName></FirstName> <LastName></LastName> </User> <User> <FirstName></FirstName> <LastName></LastName> </User> ... </UserSet1> <InactiveUsers> <User> <FirstName></FirstName> <LastName></LastName> </User> <User> <FirstName></FirstName> <LastName></LastName> </User> ... </InactiveUsers> </FileRoot> In my XSL template <xsl:template match="/*/*"> <File> <xsl attribute name="Name"> <xsl:value-of select="local-name(/*/*)"/> </xsl:attribute> </File> </xsl> After transforming, for both UserSet1 and InactiveUsers, gave me "UserSet1". The expected results should be "UserSet1" for UserSet1, and "InactiveUsers" for InactiveUsers. How do I correctly retrieve the value? Thanks

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  • Running XPath on child node.

    - by Jeeyoung Kim
    Hi. I'm trying to do a xpath lookup on nodes returned by xpath lookup, but it doesn't seem to work as I expected.XPaths executed on the child nodes of a document seem to be executd against hthe root node of the document (in the example, the inventory tag.), instead of the root of the provided node. Am I missing something here? I'm new to XPath. Also, please don't answer "just do //book[author='Neal Stephenson'/title". I have a legitimate use case, and this is a simplified example. Code snippet DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance(); domFactory.setNamespaceAware(true); DocumentBuilder builder = domFactory.newDocumentBuilder(); Document doc = builder.parse("src/main/java/books.xml"); XPathFactory factory = XPathFactory.newInstance(); XPath xpath = factory.newXPath(); Node book = (Node) xpath.evaluate("//book[author='Neal Stephenson']", doc, XPathConstants.NODE); Node title = (Node) xpath.evaluate("/title", book, XPathConstants.NODE); // I get null here. Node inventory = (Node) xpath.evaluate("/inventory", book, XPathConstants.NODE); // this returns a node. book.xml <inventory> <book year="2000"> <title>Snow Crash</title> <author>Neal Stephenson</author> <publisher>Spectra</publisher> <isbn>0553380958</isbn> <price>14.95</price> </book> <book year="2005"> <title>Burning Tower</title> <author>Larry Niven</author> <author>Jerry Pournelle</author> <publisher>Pocket</publisher> <isbn>0743416910</isbn> <price>5.99</price> </book> <book year="1995"> <title>Zodiac</title> <author>Neal Stephenson</author> <publisher>Spectra</publisher> <isbn>0553573862</isbn> <price>7.50</price> </book> <!-- more books... --> </inventory>

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  • Output on namespaced xpath in java

    - by user347928
    I have the following code and have had some trouble with a specific field and it's output. The namespace is connected but doesn't seem to be outputting on the required field. Any info on this would be great. import org.w3c.dom.Document; import org.xml.sax.SAXException; import javax.xml.parsers.DocumentBuilderFactory; import javax.xml.parsers.DocumentBuilder; import javax.xml.parsers.ParserConfigurationException; import javax.xml.xpath.XPathFactory; import javax.xml.xpath.XPath; import javax.xml.xpath.XPathExpressionException; import java.io.ByteArrayInputStream; import java.io.IOException; public class test { public static void main(String args[]) { String xmlStr = "<aws:UrlInfoResponse xmlns:aws=\"http://alexa.amazonaws.com/doc/2005-10-05/\">\n" + " <aws:Response xmlns:aws=\"http://awis.amazonaws.com/doc/2005-07-11\">\n" + " <aws:OperationRequest>\n" + " <aws:RequestId>blah</aws:RequestId>\n" + " </aws:OperationRequest>\n" + " <aws:UrlInfoResult>\n" + " <aws:Alexa>\n" + " <aws:TrafficData>\n" + " <aws:DataUrl type=\"canonical\">harvard.edu/</aws:DataUrl>\n" + " <aws:Rank>1635</aws:Rank>\n" + " </aws:TrafficData>\n" + " </aws:Alexa>\n" + " </aws:UrlInfoResult>\n" + " <aws:ResponseStatus xmlns:aws=\"http://alexa.amazonaws.com/doc/2005-10-05/\">\n" + " <aws:StatusCode>Success</aws:StatusCode>\n" + " </aws:ResponseStatus>\n" + " </aws:Response>\n" + "</aws:UrlInfoResponse>"; DocumentBuilderFactory xmlFact = DocumentBuilderFactory.newInstance(); xmlFact.setNamespaceAware(true); DocumentBuilder builder = null; try { builder = xmlFact.newDocumentBuilder(); } catch (ParserConfigurationException e) { e.printStackTrace(); } Document doc = null; try { doc = builder.parse( new ByteArrayInputStream( xmlStr.getBytes())); } catch (SAXException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } System.out.println(doc.getDocumentElement().getNamespaceURI()); System.out.println(xmlFact.isNamespaceAware()); String xpathStr = "//aws:OperationRequest"; XPathFactory xpathFact = XPathFactory.newInstance(); XPath xpath = xpathFact.newXPath(); String result = null; try { result = xpath.evaluate(xpathStr, doc); } catch (XPathExpressionException e) { e.printStackTrace(); //To change body of catch statement use File | Settings | File Templates. } System.out.println("XPath result is \"" + result + "\""); } }

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  • Output on namespaced xpath

    - by user347928
    Hi there, I have the following code and have had some trouble with a specific field and it's output. The namespace is connected but doesn't seem to be outputting on the required field. Any info on this would be great. import org.w3c.dom.Document; import org.xml.sax.SAXException; import javax.xml.parsers.DocumentBuilderFactory; import javax.xml.parsers.DocumentBuilder; import javax.xml.parsers.ParserConfigurationException; import javax.xml.xpath.XPathFactory; import javax.xml.xpath.XPath; import javax.xml.xpath.XPathExpressionException; import java.io.ByteArrayInputStream; import java.io.IOException; public class test { public static void main(String args[]) { String xmlStr = "<aws:UrlInfoResponse xmlns:aws=\"http://alexa.amazonaws.com/doc/2005-10-05/\">\n" + " <aws:Response xmlns:aws=\"http://awis.amazonaws.com/doc/2005-07-11\">\n" + " <aws:OperationRequest>\n" + " <aws:RequestId>blah</aws:RequestId>\n" + " </aws:OperationRequest>\n" + " <aws:UrlInfoResult>\n" + " <aws:Alexa>\n" + " <aws:TrafficData>\n" + " <aws:DataUrl type=\"canonical\">harvard.edu/</aws:DataUrl>\n" + " <aws:Rank>1635</aws:Rank>\n" + " </aws:TrafficData>\n" + " </aws:Alexa>\n" + " </aws:UrlInfoResult>\n" + " <aws:ResponseStatus xmlns:aws=\"http://alexa.amazonaws.com/doc/2005-10-05/\">\n" + " <aws:StatusCode>Success</aws:StatusCode>\n" + " </aws:ResponseStatus>\n" + " </aws:Response>\n" + "</aws:UrlInfoResponse>"; DocumentBuilderFactory xmlFact = DocumentBuilderFactory.newInstance(); xmlFact.setNamespaceAware(true); DocumentBuilder builder = null; try { builder = xmlFact.newDocumentBuilder(); } catch (ParserConfigurationException e) { e.printStackTrace(); } Document doc = null; try { doc = builder.parse( new ByteArrayInputStream( xmlStr.getBytes())); } catch (SAXException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } System.out.println(doc.getDocumentElement().getNamespaceURI()); System.out.println(xmlFact.isNamespaceAware()); String xpathStr = "//aws:OperationRequest"; XPathFactory xpathFact = XPathFactory.newInstance(); XPath xpath = xpathFact.newXPath(); String result = null; try { result = xpath.evaluate(xpathStr, doc); } catch (XPathExpressionException e) { e.printStackTrace(); //To change body of catch statement use File | Settings | File Templates. } System.out.println("XPath result is \"" + result + "\""); } } Thanks Tony

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  • xsltproc killed, out of memory

    - by David Parks
    I'm trying to split up a 13GB xml file into small ~50MB xml files with this XSLT style sheet. But this process kills xsltproc after I see it taking up over 1.7GB of memory (that's the total on the system). Is there any way to deal with huge XML files with xsltproc? Can I change my style sheet? Or should I use a different processor? Or am I just S.O.L.? <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0" xmlns:exsl="http://exslt.org/common" extension-element-prefixes="exsl" xmlns:fn="http://www.w3.org/2005/xpath-functions"> <xsl:output method="xml" indent="yes"/> <xsl:strip-space elements="*"/> <xsl:param name="block-size" select="75000"/> <xsl:template match="/"> <xsl:copy> <xsl:apply-templates select="mysqldump/database/table_data/row[position() mod $block-size = 1]" /> </xsl:copy> </xsl:template> <xsl:template match="row"> <exsl:document href="chunk-{position()}.xml"> <add> <xsl:for-each select=". | following-sibling::row[position() &lt; $block-size]" > <doc> <xsl:for-each select="field"> <field> <xsl:attribute name="name"><xsl:value-of select="./@name"/></xsl:attribute> <xsl:value-of select="."/> </field> <xsl:text>&#xa;</xsl:text> </xsl:for-each> </doc> </xsl:for-each> </add> </exsl:document> </xsl:template>

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  • XPath & XML EDI B2B

    - by PearlFactory
    GoodToGo :) Best XML Editor is Altova XMLSpy 2011 http://www.torrenthound.com/hash/bfdbf55baa4ca6f8e93464c9a42cbd66450bb950/torrent-info/Altova-XMLSpy-Enterprise-Edition-SP1-2011-v13-0-1-0-h33t-com-Full For whatever reason Piratebay has trojans and other nasties..Search in torrent.eu for Altova XMLSpy Enterprise Edition SP1 2011 v13.0.1.0 Also if you like the product purchase it in a Commercial Enviroment Any well structured/complex XML can be parsed @ the speed of light using XPATH querys and not the C# objects XPathNodeIterator and others etc ....Never do loops  or Genirics or whatever highlevel language technology. Use the power of XPATH i.e Will use a Simple (Do while) as an example. We could have many different techs all achieveing the same result Instead of   xmlNI2 = xmlNav.Select("/p:BookShop")         if (xmlNI2.Count != 0)            {                                 while ((xmlNI2.MoveNext()))              string aNode =xmlNI2.SelectSingleNode('Book', nsmgr); if (aNode =="The Book I am after")       Console.WriteLine("Found My Book);   This lengthy cumbersome task can be achieved with a simple XPATH query Console.WriteLine((xmlNavg.SelectSingleNode("/p:BookShop/Book[.='The Book I am aFter ']", nsmgr)).Value.ToString()); Use the power of the parser and eliminate the middleman C#/MSIL/JIT etc etc Get Started Fast and use the parser as Outlined 1) Open XML and goto Grid Mode 2) Select XPATH tab on the bottom viewer/window as shown  From here you get intellisense and can quickly learn how to navigate/find the data using XPATH A key component to Navigation with XPATH is to use the "../ " command . This basically says from where I am now go up 1 level . With Xpath all commands are cumalative. i.e you can search for a book title @ the 2nd level of the XML and from there traverse 15 layers to paragraphs or words on a page with expression validation occuring throughout this process etc  (So in essence you may have arrived @ a node within the XML and have met 15 conditions along the way ) Given 1-2 days with XmlSpy and XPATH you unlock a technology that is super fast and simple to use. XML is a core component to what lays under the hood of so many techs. So it is no wonder that you want to be able to goto  the atomic level to achieve the result you want Justin P.S For a long time I saw XML as slow and a bit boring but now converted

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  • How to Generate XML from Database

    - by Nisarg Mehta
    Hi , I am fetching data from two tables CARRIER_IFTA ,IFTA_NAME. My Select Query is like below.. SELECT t1.IFTA_LICENSE_NUMBER,t1.IFTA_BASE_STATE,t2.NAME_TYPE,t2.NAME from CARRIER_IFTA t1 inner join IFTA_NAME t2 on t1.IFTA_LICENSE_NUMBER=t2.IFTA_LICENSE_NUMBER My Data is coming in this way... IFTA_LICENSE_NUMBER IFTA_BASE_STATE NAME_TYPE NAME -------------------------------------------------------- 630908333 US LG XYZ 630908333 US MG PQR 730908344 US LG ABC Now using XSLT I want to generate XML like this <T0019> <IFTA_ACCOUNT> <IFTA_LICENSE_NUMBER>630908333</IFTA_LICENSE_NUMBER> <IFTA_BASE_STATE>US</IFTA_BASE_STATE> <IFTA_NAME> <NAME_TYPE>LG<NAME_TYPE> <NAME>XYZ</NAME> </IFTA_NAME> <IFTA_NAME> <NAME_TYPE>MG<NAME_TYPE> <NAME>PQR</NAME> <IFTA_NAME> </IFTA_ACCOUNT> <IFTA_ACCOUNT> <IFTA_LICENSE_NUMBER>730908344</IFTA_LICENSE_NUMBER> <IFTA_BASE_STATE>US</IFTA_BASE_STATE> <IFTA_NAME> <NAME_TYPE>LG<NAME_TYPE> <NAME>ABC</NAME> </IFTA_NAME> </IFTA_ACCOUNT> </T0019> i have used below xslt but it is not giveng me desire result ... <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> <xsl:template match="/ROWSET"> <xsl:element name="T0019"> <xsl:apply-templates select="IFTAACCOUNT"/> </xsl:element> </xsl:template> <xsl:template match="IFTAACCOUNT"> <xsl:element name="IFTAACCOUNT"> <xsl:apply-templates select="IFTA_CARRIER_ID_NUMBER"/> </xsl:element> </xsl:template> <xsl:template match="IFTA_LICENSE_NUMBER"> <xsl:element name="IFTA_LICENSE_NUMBER"> <xsl:apply-templates /> </xsl:element> </xsl:template> <xsl:template match="IFTA_BASE_STATE"> <xsl:element name="IFTA_BASE_STATE"> <xsl:apply-templates /> </xsl:element> </xsl:template> <xsl:template match="IRP_NAME"> <IRP_NAME> <xsl:apply-templates select="NAME"/> <xsl:apply-templates select="NAME_TYPE"/> </IRP_NAME> </xsl:template> <xsl:template match="NAME"> <xsl:element name="NAME"> <xsl:value-of select="." /> </xsl:element> </xsl:template> <xsl:template match="NAME_TYPE"> <xsl:element name="NAME_TYPE"> <xsl:apply-templates /> </xsl:element> </xsl:template> </xsl:stylesheet> but it is not giving desire result ... Please help me ... Thanks in Advance...

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  • Generate XML from Database using XSLT

    - by Nisarg Mehta
    Hi , I am fetching data from two tables CARRIER_IFTA ,IFTA_NAME. My Select Query is like below.. SELECT t1.IFTA_LICENSE_NUMBER,t1.IFTA_BASE_STATE,t2.NAME_TYPE,t2.NAME from CARRIER_IFTA t1 inner join IFTA_NAME t2 on t1.IFTA_LICENSE_NUMBER=t2.IFTA_LICENSE_NUMBER My Data is coming in this way... IFTA_LICENSE_NUMBER IFTA_BASE_STATE NAME_TYPE NAME -------------------------------------------------------- 630908333 US LG XYZ 630908333 US MG PQR 730908344 US LG ABC Now using XSLT I want to generate XML like this <T0019> <IFTA_ACCOUNT> <IFTA_LICENSE_NUMBER>630908333</IFTA_LICENSE_NUMBER> <IFTA_BASE_STATE>US</IFTA_BASE_STATE> <IFTA_NAME> <NAME_TYPE>LG<NAME_TYPE> <NAME>XYZ</NAME> </IFTA_NAME> <IFTA_NAME> <NAME_TYPE>MG<NAME_TYPE> <NAME>PQR</NAME> <IFTA_NAME> </IFTA_ACCOUNT> <IFTA_ACCOUNT> <IFTA_LICENSE_NUMBER>730908344</IFTA_LICENSE_NUMBER> <IFTA_BASE_STATE>US</IFTA_BASE_STATE> <IFTA_NAME> <NAME_TYPE>LG<NAME_TYPE> <NAME>ABC</NAME> </IFTA_NAME> </IFTA_ACCOUNT> </T0019> i have used below xslt but it is not giveng me desire result ... <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> <xsl:template match="/ROWSET"> <xsl:element name="T0019"> <xsl:apply-templates select="IFTAACCOUNT"/> </xsl:element> </xsl:template> <xsl:template match="IFTAACCOUNT"> <xsl:element name="IFTAACCOUNT"> <xsl:apply-templates select="IFTA_CARRIER_ID_NUMBER"/> </xsl:element> </xsl:template> <xsl:template match="IFTA_LICENSE_NUMBER"> <xsl:element name="IFTA_LICENSE_NUMBER"> <xsl:apply-templates /> </xsl:element> </xsl:template> <xsl:template match="IFTA_BASE_STATE"> <xsl:element name="IFTA_BASE_STATE"> <xsl:apply-templates /> </xsl:element> </xsl:template> <xsl:template match="IRP_NAME"> <IRP_NAME> <xsl:apply-templates select="NAME"/> <xsl:apply-templates select="NAME_TYPE"/> </IRP_NAME> </xsl:template> <xsl:template match="NAME"> <xsl:element name="NAME"> <xsl:value-of select="." /> </xsl:element> </xsl:template> <xsl:template match="NAME_TYPE"> <xsl:element name="NAME_TYPE"> <xsl:apply-templates /> </xsl:element> </xsl:template> </xsl:stylesheet> but it is not giving desire result ... Please help me ... Thanks in Advance...

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  • XSL check param length

    - by AdRock
    I need to check if a param has got a value in it and if it has then do this line otherwise do this line. I've got it working whereas I don't get errors but it's not taking the right branch Here is the template which holds the html in the XSL stylesheet <xsl:call-template name="volunteer_role"> <xsl:with-param name="volrole" select="volunteer/roles" /> </xsl:call-template> and here is the template where there is a choice whether to take this brancg or that brach depending if the param is empty <xsl:template name="volunteer_role"> <xsl:param name="volrole" select="'Not Available'" /> <div class="small bold">ROLES:</div> <div class="large"> <xsl:choose> <xsl:when test="string-length($volrole)!=0"> <xsl:value-of select="$volrole" /> </xsl:when> <xsl:otherwise> <xsl:text> </xsl:text> </xsl:otherwise> </xsl:choose> </div> </xsl:template>

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  • How to pass an xpath into an xquery function declaration

    - by topmulch
    Hi all, I use Apache Tomcat's Exist DB as an XML database and am trying to construct a sequence by passing the following xpath, defined in FLWOR's 'let' clause: $xpath := $root/second/third into a locally defined function declaration, like so: declare function local:someFunction($uuid as xs:string?, $xpath as xs:anyAtomicType?) { let $varOne := $xpath/fourth[@uuid = $uuid]/fifthRight let $varTwo := $xpath/fourth[@uuid = $uuid]/fifthLeft let $combined := ($varOne,$varTwo) return $combined }; Of course, when entering this in the exist xquery sandbox, I get Type: xs:anyAtomicType is not defined. What should I use in place of it, or should I do this a different way? Thanks in advance for any suggestions.

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  • Recoverable error while running XSL

    - by Kate
    XSL: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:ve="http://schemas.openxmlformats.org/markup-compatibility/2006" xmlns:o="urn:schemas-microsoft-com:office:office" xmlns:r="http://schemas.openxmlformats.org/officeDocument/2006/relationships" xmlns:m="http://schemas.openxmlformats.org/officeDocument/2006/math" xmlns:v="urn:schemas-microsoft-com:vml" xmlns:wp="http://schemas.openxmlformats.org/drawingml/2006/wordprocessingDrawing" xmlns:w10="urn:schemas-microsoft-com:office:word" xmlns:w="http://schemas.openxmlformats.org/wordprocessingml/2006/main" xmlns:wne="http://schemas.microsoft.com/office/word/2006/wordml" exclude-result-prefixes="wp wne w10 w ve o r m v" version="2.0"> <xsl:output method="text"/> <xsl:param name="styleName"/> <xsl:template match="w:p"> <xsl:apply-templates/><xsl:text>&#10;</xsl:text> </xsl:template> <xsl:template match="w:r[not ((parent::w:hyperlink[@w:anchor[matches(.,concat('^(',$styleName,')')),'i']]))]"> <xsl:value-of select="replace(., '.', '&#xFF00;')"/> </xsl:template> </xsl:stylesheet> While processing the above XSL, I am getting the below error, Recoverable Error: Recoverable error on line 11 FORG0006: An error occurred matching pattern {w:r[not ((parent::w:hyperlink[@w:anchor[matches(.,concat('^(',$styleName,')')),'i']]))]}: Effective boolean value is not defined for a sequence of two or more items starting with a boolean Please Help. I am not able to figure out this.

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  • placing the matched 2 different child elements xml values in a single line from xslt2.0

    - by Girikumar Mathivanan
    I have the below input xml, <GSKProductHierarchy> <GlobalBusinessIdentifier>ZGB001</GlobalBusinessIdentifier> <Hierarchy> <Material>335165140779</Material> <Level1>02</Level1> <Level2>02AQ</Level2> <Level3>02AQ006</Level3> <Level4>02AQ006309</Level4> <Level5>02AQ006309</Level5> <Level6>02AQ006309</Level6> <Level7>02AQ006309</Level7> <Level8>02AQ006309</Level8> </Hierarchy> <Hierarchy> <Material>335165140780</Material> <Level1>02</Level1> <Level2>02AQ</Level2> <Level3>02AQ006</Level3> <Level4>02AQ006309</Level4> <Level5>02AQ006309</Level5> <Level6>02AQ006309</Level6> <Level7>02AQ006309</Level7> <Level8>02AQ006310</Level8> </Hierarchy> <Texts> <ProductHierarchy>02AQ006310</ProductHierarchy> <Language>A</Language> <Description>CREAM</Description> </Texts> <Texts> <ProductHierarchy>02AQ006309</ProductHierarchy> <Language>B</Language> <Description>CREAM</Description> </Texts> as per the requirement, xsl should check the matched value of GSKProductHierarchy/Hierarchy/Level8 in the GSKProductHierarchy/Texts/ProductHierarchy elements...and its should result as below flat file. 335165140779|02|02AQ|02AQ006|02AQ006309|02AQ006309|02AQ006309|02AQ006309|02AQ006309|02AQ006309|A|CREAM| 335165140780|02|02AQ|02AQ006|02AQ006309|02AQ006309|02AQ006309|02AQ006309|02AQ006310|02AQ006310|B|CREAM| Right now I have the below xslt, <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:exsl="http://exslt.org/common" xmlns:set="http://exslt.org/sets" xmlns:str="http://exslt.org/strings" xmlns:java="http://xml.apache.org/xslt/java" xmlns:saxon="http://saxon.sf.net/" exclude-result-prefixes="exsl set str java saxon"> <xsl:output method="text" indent="yes"/> <xsl:variable name="VarPipe" select="'|'"/> <xsl:variable name="VarBreak" select="'&#xa;'"/> <xsl:template match="/"> <xsl:for-each select="GSKProductHierarchy/Hierarchy"> <xsl:variable name="currentIndex" select="position()"/> <xsl:variable name="Level8" select="Level8"/> <xsl:variable name="ProductHierarchy" select="../Texts[$currentIndex]/ProductHierarchy"/> <xsl:if test="$Level8=$ProductHierarchy"> <xsl:value-of select="Material"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level1"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level2"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level3"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level4"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level5"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level6"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level7"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level8"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="../Texts[$currentIndex]/ProductHierarchy"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="../Texts[$currentIndex]/Language"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="../Texts[$currentIndex]/Description"/> <xsl:value-of select="$VarPipe"/> <xsl:if test="not(position() = last())"> <xsl:value-of select="$VarBreak"/> </xsl:if> </xsl:if> </xsl:for-each> </xsl:template> can anyone please suggest what function should i need to use to get the desired result. Regards, Giri

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  • how to get child nodes in xsl

    - by ppp
    here my code- <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="ArrayOfLinkEntity" name="bindLink"> <ul> <xsl:for-each select="LinkEntity[ParentLinkId=0]"> <li> <xsl:variable name="linkId" select="LinkId"/> <xsl:variable name="child" select="count(/ArrayOfLinkEntity/LinkEntity[ParentLinkId=$linkId])"/> <xsl:value-of select="$child"/> <xsl:choose> <xsl:when test="($child &gt; 0)"> <a href="#" data-flexmenu="flexmenu1" onclick="javascript:setPageLinkId({$linkId});"> <xsl:value-of select="LinkTitle"/> <img src="../images/down.gif" border="0"/> </a> </xsl:when> <xsl:otherwise > <a href="#" onclick="javascript:setPageLinkId({$linkId});"> <xsl:value-of select="LinkTitle"/> </a> </xsl:otherwise> </xsl:choose> </li> </xsl:for-each> </ul> </xsl:template> </xsl:stylesheet> but I am getting $child=0 always.but there exists children. my xml structure- <ArrayOfLinkEntity xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <LinkEntity> <EntityId>00000000-0000-0000-0000-000000000000</EntityId> <LinkId>1</LinkId> <SequenceNo>1</SequenceNo> <ParentLinkId>0</ParentLinkId> <LinkTitle>Home</LinkTitle> <SubLink /> </LinkEntity> ... </ArrayOfLinkEntity> What should I do? Please suggest.

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  • XSL file handling through javascript

    - by Zaid Iqbal
    i want to handle my xsl file through my javascript code. I made my XSL file but i want to dynamically change my XSL file at run time.As in add more attributes in header or data. My javascript code as follow` <script> function loadXMLDoc(dname) { if (window.XMLHttpRequest) { xhttp=new XMLHttpRequest(); } else { xhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xhttp.open("GET",dname,false); xhttp.send(""); return xhttp.responseXML; } function displayResult() { xml=loadXMLDoc("cdcatalog.xml"); xsl=loadXMLDoc("cdcatalog.xsl"); // code for IE if (window.ActiveXObject) { ex=xml.transformNode(xsl); document.getElementById("example").innerHTML=ex; } // code for Mozilla, Firefox, Opera, etc. else if (document.implementation && document.implementation.createDocument) { xsltProcessor=new XSLTProcessor(); xsltProcessor.importStylesheet(xsl); resultDocument = xsltProcessor.transformToFragment(xml,document); document.getElementById("example").appendChild(resultDocument); } } </script> My XSL file code: <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <html> <body> <h2>My CD Collection</h2> <table border="1"> <tr bgcolor="#9acd32"> <th align="left">Title</th> <th align="left">Artist</th> <th align="left">Country</th> </tr> <xsl:for-each select="catalog/cd"> <tr> <td><xsl:value-of select="title" /></td> <td><xsl:value-of select="artist" /></td> <td><xsl:value-of select="country" /></td> </tr> </xsl:for-each> </table> </body> </html> </xsl:template> </xsl:stylesheet> `

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  • xpath/xslt to determine index of context node relative to all nodes of same name?

    - by Geoff
    Given the schema below - with a "query" node as the context, is it possible with xpath/xslt to determine the index of that "query" node relative to all "query" nodes in the document (not position() relative to its immediate siblings). TIA, Geoff <section> <name>About</name> <link>about</link> <questions> <question> <query>Question 1</query> <answer>Lorem ipsum dolor sit amet, consectetur adipiscing elit. In cursus, elit id lacinia semper, ligula nunc rhoncus ante, in euismod tortor nibh dictum tellus.</answer> </question> </questions> </section> <section> <name>Contact</name> <link>contact</link> <questions> <question> <query>Question 1</query> <answer>Lorem ipsum dolor sit amet, consectetur adipiscing elit. In cursus, elit id lacinia semper, ligula nunc rhoncus ante, in euismod tortor nibh dictum tellus.</answer> </question> <question> <query>Question 2</query> <answer>Lorem ipsum dolor sit amet, consectetur adipiscing elit. In cursus, elit id lacinia semper, ligula nunc rhoncus ante, in euismod tortor nibh dictum tellus.</answer> </question> </questions> </section>

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