Search Results

Search found 18803 results on 753 pages for 'link'.

Page 60/753 | < Previous Page | 56 57 58 59 60 61 62 63 64 65 66 67  | Next Page >

  • How to link different Servlet together?

    - by Harry Pham
    First of all, I did not use Spring MVC. :) :) Just want to get it out first. Now what I have is different JSP pages that making calls to different Servlets. All the pieces work great individually but I kind of need to link them together. If all of jsp pages make GET request then it would be easy, since I would just pass a type via the web address, and on my servlet side, I would just enumerated through all the parameter, determine which type is it, and delegate to the right servlet. But not all jsp pages make GET request, some make POST request via form. Let see example A.jsp $.getJSON('GenericServlet?type=A', ... GenericServlet.java String type = request.getParameter("type"); if(type.equals("A")){ //Somehow delegate to Servlet A (Not sure how to do that yet :)) } but in B.jsp I would have something like this B.jsp <form action="GenericServlet" method="post"> <table border=0 cellspacing=10 cellpadding=0> <tr> <td>User Name:</td> <td><input type="text" name="username" size=22/></td> </tr> <tr> <td>Password:</td> <td><input type="password" name="password" size=22/></td> </tr> </table> <input type="submit" value="Create User" /> </form> It kind of hard for me to determine in GenericServlet.java that this need to go to servletB

    Read the article

  • jquery delay a link from being followed

    - by Dan Sinker
    I have a short css-based animation that I want to play out before a link is followed (a card that swooped in on page load swoops out after click). Currently, however, the page called loads too quickly. I want to be able to briefly delay the href from being followed. Here's what I've got: $(document).ready(function() { $("#card").css("top","0px"); $(".clickit").click(function() { $("#card").css("top","-500"); }); }); The first line swoops the card in on page load. After that is the click call that modifies the CSS, but like I said there needs to be some kind of delay in there because the page loads immediately, instead of after the animation. The CSS that is modified looks like this: #card { width: 400px; height: 500px; position: relative; top: -500px; -webkit-transition:all .5s; } (yes, I know this is webkit-only right now) This is a problem very similar to this question from 2008, but I know jQuery has been updated significantly since then, so I wanted to see if there was a more modern solution. Thank you!

    Read the article

  • How to direct link to an attribute set?

    - by monocat
    I have created attributes; “Shop by Type” and “Shop by Color”. They work great within the layered navigation and extended search. I’ve designed graphics and placed them in the home page and would like to link to the respective attribute’s assigned products. Been searching the webs, but so far have been unsuccessful. If there’s no direct possible way, the next method would be creating cms pages and linking to it directly. How can I display products that are assigned to a specific attribute? Specifically “Multiple Select” types. I know you guys prefer at least some attempts, but as mentioned, been playing with it with no luck. I would appreciate some kind of starting point. Happy Holidays! Edit: I was able to put together this code that lists all the products assigned to said category id. Tried to filter it down where it only displays products that have an assigned same attribute with no luck yet. Any ideas? <?php $cat_id = 123; // category id $category = Mage::getModel('catalog/category')->load($cat_id); $_products = $category->getProductCollection() ->addAttributeToSelect('shop_by_color'); if (($this->getProductCollection()) && $_products->getSize()): ?> By the way, $cat_id is a sub category of root. Is there an easier way to point to it instead of using direct id number?

    Read the article

  • (RoR) How to: link multiple apps, multiple URLs, one database

    - by Samson
    Hello. I am currently developing a site using Ruby on Rails. I am still a beginner who just started around a month ago. I use InstantRails on Windows 7. Here's my question. Let's say app A is functional using MYSQL database A_development. The files such as views and controller are under folder 'A'. I now know how to, say for example, link www.app.com to this app by opening port 80 and changing some lines in the mySQL config. In this app, you can register your username, login, and post some messages. I now want to create some pretty identical apps say B and C. The only thing different will be the posts that shows, and the views. You can still log in with the same username, and everything is saved in the same database. I now want the URLs to look something like A.app.com leading to app A, B.app.com leading to app B, etc. Can that be achieved? How? I've been googling for a few days already and I'm still lost. As I'm new to this forum, I'm not quite sure what info do you guys need. Please list and I'll provide them asap. Any help will be appreciated! Thanks.

    Read the article

  • Refactor link to show/hide a table row

    - by abatishchev
    I have a table with row which cab be hidden by user. It's implemented this way: Markup: <table> <tr> <td> <table style="margin-left: auto; text-align: right;"> <tr> <td class="stats-hide"> <a href="#" onclick="hideStats();">Hide</a> </td> <td class="stats-show" style="display: none;"> <a href="#" onclick="showStats();">Show</a> </td> </tr> </table> </td> </tr> <tr class="stats-hide"> <td> <!-- data --> </td> </tr> </table> And jQuery code: <script type="text/javascript" language="javascript"> function hideStats() { hideControls(true, $('.stats-hide')); hideControls(false, $('.stats-show')); } function showStats() { hideControls(false, $('.stats-hide')); hideControls(true, $('.stats-show')); } function hideControls(value, arr) { $(arr).each(function () { if (value) { $(this).hide(); } else { $(this).show(); } }); } </script> How to implement the same behavior with one, single link and one, probably, CSS class? My idea - store somewhere a boolean variable and toggle controls visibility relatively to this variable. Are there more?

    Read the article

  • how to concatinate a link with <select> <option> value on "onchange" event

    - by atif
    <?php echo $this->getUrl(); ?> = this gives me my index page url .i.e. www.domain.com/index.php/ but now wat i want is when any particular option is selected, it should add to this url. .e.g. www.domain.com/index.php/wordpress/ i write this code for it but now don know how to get it done :( <select onchange="setLocation('<?php echo $this->getUrl(); ?>')"> <option value="">&nbsp;</option> <option value="wordpress">Wordpress</option> <option value="drupal">drupal</option> <option value="magento">Megento</option> </select> also i had searched this link but couldn't take help from it. As it didnt work for me. <select name="forma" ONCHANGE="location = this.options[this.selectedIndex].value;"> <option value="Home">Home</option> <option value="Contact">Contact</option> <option value="Sitemap">Sitemap</option> </select>

    Read the article

  • UiButton / IBAction - link from a RootView to mainView in Storyboard

    - by webschnecke
    I try to call the main ViewController on my storyboard. In my app there is a additional .h, .m file with no xib or storyboard. In this .m file T craeted a button: UIButton *button = [UIButton buttonWithType:UIButtonTypeRoundedRect]; [button addTarget:self action:@selector(home:)forControlEvents:UIControlEventTouchDown]; [button setTitle:@"Show View" forState:UIControlStateNormal]; button.frame = CGRectMake(80.0, 210.0, 160.0, 40.0); [self.view addSubview:button]; NSLog(@"Home-Button line 645"); This button should link to my main ViewController in the Storyboard. The view has the identifier HauptMenu. I got no error, but the view doesnt change to my main ViewController. What is wrong? - (IBAction)home:(id)sender { NSLog(@"Button was tapped"); ViewController *viewController = [self.storyboard instantiateViewControllerWithIdentifier:@"HauptMenu"]; NSLog(@"1"); [viewController setModalTransitionStyle:UIModalTransitionStyleFlipHorizontal]; NSLog(@"2"); [self.navigationController pushViewController:viewController animated:NO]; [viewController release]; NSLog(@"3"); }

    Read the article

  • Html image link, not working

    - by Anders Metnik
    Hey I'm doing some testing while learning js + html5 and other web/mobile frameworks. I have a problem with one of my picture links, which I also need to change the picture dynamically and the target(hopefully). But it won't work. HTML: <div data-role="content" id="firstPageContent"> <p>I'm first in the source order so I'm shown as the page.</p> <p>View internal page called <a href="#second">second</a></p> <a href = "#second" id="mapLink" name="mapLink"><img id="mapLinkImage" alt="a map which links to the mapPage" src="images/main_header.png"/></a> <Button id="loadButton" onClick="load()"/> </div><!-- /content --> js: importScripts(dataManager.js); var mapLink=second; function load(){ alert('called'); document.getElementById('mapLinkImage').src="images/store.map.png"; document.getElementById('mapLink').href = "http://google.com"; } problem: It ain't showing the image as a link, just as a plain image. i think this will work now.

    Read the article

  • Link my tag on other website search

    - by kresna kurdang
    This is my search code <div id="search"> <form method="get" action="http://www.other-website.com/search"> <input type="hidden" name="f" value=""> <input type="text" placeholder="Temukan informasi, komunitas & produk yang kamu cari disini" accesskey="s" name="q"> <input type="submit" value="Search"> </form> </div> This is the tag code (display only text "do not link") <?php $posttags = get_the_tags(); if ($posttags) { foreach($posttags as $tag) { echo $tag->name . ' '; } } ?> The code can apply well on the website, but I have to enter text to the search. I just want to place my tag on that search text so my question is How to make fixed word(my tag) automatically placed on search or where I must place the tag code, the search result is mytag linked on @www.other-website.com/search so user do not have to type? I want to search my tag on other website search

    Read the article

  • WCF hosting: Can access svc file but cannot go to wsdl link

    - by Impulse
    Hello, I have a WCF service that is hosted in IIS 7.5. I have two servers, one for test and one for production. The service works fine on test server, but on the production server I have the following error. When I access the address http//..../service.svc I can see the default page that says: You have created a service. To test this service, you will need to create a client and use it to call the service. You can do this using the svcutil.exe tool from the command line with the following syntax: svcutil.exe http://..../service.svc?wsdl This will generate a configuration file and a code file that contains the client class. Add the two files to your client application and use the generated client class to call the Service. But when I click the wsdl link, I cannot go to the wsdl page. It returns me to this default web page without any errors. I am suspecting a network/firewall authorization error but does anybody have an experience like this one? All IIS settings are the same for test and production servers. Thank you, Best Regards.

    Read the article

  • Only show link if conditional equals true

    - by Dave Morin
    I want the link to appear only when $data['block'] equals to 1, 3 or 4. Not if it equals to 2 or 5. <td style="font-size:18px;color:#f0cb01;"> <a href="kickcodes.php?id='.$data["block"].'">Reason Codes</a> </td> EDIT while ($data = mysql_fetch_array($query)) { echo ' <tr style="background-color:#576c11;"> <td style="font-size:18px; color:#f0cb01;">'.$data["keyword"].'</td> <td style="font-size:18px;color:#f0cb01;">'.$data["block"].'</td> <td style="font-size:18px;color:#f0cb01;">'.$data["phone"].'</td> <td style="font-size:18px;color:#f0cb01;">'.$data["Reason"].'</td> <td style="font-size:18px;color:#f0cb01;"><a href="kickcodes.php?id='.$data ["block"].'">Kickcodes</a></td>' echo '<td style="font-size:18px;color:#f0cb01;">'; if( $data['block'] == 1 || $data['block'] == 3 || $data['block'] == 4) { echo '<a href="kickcodes.php?id='.$data["block"].'">Reason Codes</a>'; } else { echo '<span>Reason Codes</span>'; // Or echo nothing } echo '</td>';

    Read the article

  • measure the response time of a link

    - by Ahoura Ghotbi
    I am trying to create a simple load balance script and I was wondering if it is possible to find the response time of a server live? By that I mean is it possible to measure how long it takes for a server to respond after the request has been sent out? What I am trying to do is fairly simple, I want to send a request to a link/server and do a count down, if the server took more than 5 seconds to reply, I would like to fall on the backup server. Note that it doesnt have to be in pure php, I wouldnt mind using other languages such as javascript, C/C++, asp, but I prefer to do it in PHP. if it is possible to do the task, could you just point me to the right direction so I can read up on it. Clarification What I want to do is not to download a file and see how long it took, my servers have high load and it takes a while for them to respond when you click on a file to download, what I want to do is to measure the time it takes the server to respond (in this situation, its the time it takes the server to respond and allow the user to download the file), and if it takes longer than x seconds, it should fall back on a backup server.

    Read the article

  • Target a link if that link links to the current page?

    - by Des
    this may be a stupid question as I can't seem to find an answer :P Is there a way with javascript/jQuery to Target all links on a page ONLY if they link to the current page? Say i've got a static sidebar on ALL pages, for intents and purposes: <ul id="sidebar"> <li><a href="/one">One</a></li> <li><a href="/two">Two</a></li> <li><a href="/three">Three</a></li> </ul> Notice the code for ALL of them is the same. Let's say I'm on "www.domain.com/two" - Is there a way to target <li><a href="#">Two</a></li> because it's linking to the current page? ***ANSWERED***** The guy deleted his answer - but I used it to create this - var linksToCurrentPage = $('a[href="' + window.location.href + '"]'); if (linksToCurrentPage) { $('a').addClass('currently-active'); }; which worked :)

    Read the article

  • In C/C++,how to link dynamic link lib which compiled in GCC/G++ in MS VStudio?

    - by coanor
    These days, I use Flex & Bison generated some codes to develop a SQL-parser alike tools, these code can't compiled silently(may be this another topic) in VS2005,but GCC/G++ works well, then I compiled these code with mingw in dll(in windows xp), and then linked these function facades in VS2005, but it seems can't link the dll during linking. Does MS VS2005 recognize the dll which compiled using mingw on windows? Is there anything I need to do additional? For example, adding something in the include-file that declare the exported APIs? Does any one can give some advices? The condition is, as in VS2005, if you want to export some APIs, you may show a *.def file to tell nmake which API you want to export, and then you may create a(or some) *.h file to declare somthing about these APIs(adding some stdcall alike prefix as a call protocal) and some data-type definition. But with GCC/G++, you do not need to do such boring things, just use [ar], you can get these APIs, so my *.h file do not add call protocol and no *.def, just like common function declaration. After *.dll generated, add the *.h file and [mv] generated *.dll in VS2005 project directory, then set the linking *.dll in project setting. Does these steps generated my Question? BTW, I found and tested VC6-compiled dll can be linked with mingw in Windows XP, but the reverse can't work. Anyway, forgive my poor English, and thanks for your concern.

    Read the article

  • How to remove the link if value is 0 using asp.net mvc

    - by kumar
    i have this code.. <table class="dashboard-table"> <thead> <tr> <th>&nbsp;</th> <th>Worked</th> </tr> </thead> <% foreach (var e in Model.ExceptionsByType) { %> <tr> <td> <%=Html.ActionLink(e.ExceptionTypeName, "VirtualScrollingDataRequested", Model.exceptionCategory.GetControllerName(), new { C_EXCPT_TYPE = e.ExceptionTypeID, GUI_SPEC_STAT_DSPL = 2, C_EXCPT_CATG = Model.exceptionCategory.Id, @ASSET_CLASS = string.Empty, @INST_MNEM = string.Empty, @_lock = "ALL" }, new { @title = e.BuildGridTitle(2, e.ExceptionTypeName) })%> </td> <td class="number"> <%=e.WorkedExceptions %> </td> </tr> <% } %> </table> e.WorkedExceptions is the count of exceptions.. I need to to the condition here if the e.workedexceptions == 0 I need to remove the link? please can any body hlep me out? thanks

    Read the article

  • Data Structure / Hash Function to link Sets of Ints to Value

    - by Gaminic
    Given n integer id's, I wish to link all possible sets of up to k id's to a constant value. What I'm looking for is a way to translate sets (e.g. {1, 5}, {1, 3, 5} and {1, 2, 3, 4, 5, 6, 7}) to unique values. Guarantees: n < 100 and k < 10 (again: set sizes will range in [1, k]). The order of id's doesn't matter: {1, 5} == {5, 1}. All combinations are possible, but some may be excluded. All sets and values are constant and made only once. No deletes or inserts, no value updates. Once generated, the only operations taking place will be look-ups. Look-ups will be frequent and one-directional (given set, look up value). There is no need to sort (or otherwise organize) the values. Additionally, it would be nice (but not obligatory) if "neighboring" sets (drop one id, add one id, swap one id, etc) are easy to reach, as well as "all sets that include at least this set". Any ideas?

    Read the article

  • jQuery replacement for Default Button or Link

    - by pyccki
    As everyone knows, that default button doesn't work in FF, only IE. I've tried to put in the tag or in the and it's not working. I've found a js script to fix this issue, but for some reason it's not working for me. This script for a submit button, i need to use it for a LinkButton, which is should be the same. Link: <div id="pnl"> <a id="ctl00_cphMain_lbLogin" title="Click Here to LogIn" href="javascript:WebForm_DoPostBackWithOptions(new WebForm_PostBackOptions(&quot;ctl00$cphMain$lbLogin&quot;, &quot;&quot;, true, &quot;Login1&quot;, &quot;&quot;, false, true))">Log In</a> <input name="ctl00$cphMain$UserName" type="text" id="ctl00_cphMain_UserName" /> <input name="ctl00$cphMain$UserName" type="text" id="ctl00_cphMain_UserName1" /> </div> <script> $(document).ready(function() { $("#pnl").keypress(function(e) { if ((e.which && e.which == 13) || (e.keyCode && e.keyCode == 13)) { $("a[id$='_lbLogin']").click(); return true; } }); }); I know that i can override original function "*WebForm_FireDefaultButton*" in This post, but i really wanted to get this one to work. Thanx in advance!!!

    Read the article

  • Delete file using a link

    - by user329394
    Hi all, i want to have function like delete file from database by using link instead of button. how can i do that? do i need to use href/unlink or what? Can i do like popup confirmation wther yes or no. i know how to do that, but where should i put the code? this is the part how where system will display all filename and do direct upload. Beside each files, there will be a function for 'Remove': $qry = "SELECT * FROM table1 a, table2 b WHERE b.id = '".$rs[id]."' AND a.ptkid = '".$rs[id]."' "; $sql = get_records_sql($qry); foreach($sql as $rs){ ?> <?echo '<a href="download.php?f='.$rs->faillampiran.'">'. basename($rs->faillampiran).'</a>'; ?><td><?echo '<a href=""> [Remove]</a>';?></td><? ?><br> <? } ?> thankz all

    Read the article

  • Changing PHP variable from an <a href=""> link

    - by aener
    I'm making a site using divs. I have one across the top with a row of links which I want to change what's in the main window. I would prefer to keep strictly to PHP and HTML and use a full page refresh as I am comfortable with them at current, rather than using an Ajax refresh as I don't have any knowledge of Ajax. I don't want to use iframes. I thought the best way to do this would be as follows: <div id="top"> <a href="news.html">News</a> </div> <div id="main"> <?php include($page); ?> </div> What I need is a way of changing the $page variable upon clicking the link. If this means changing the variable and then reloading the page then so be it. A command following the logic of: <a href="news.html" action="<?php $page="news.html"; ?>">News</a> would be ideal! I thought about using a form, but it seems there should be an easier way.

    Read the article

  • why my pagination link doesnt appear ?

    - by udaya
    This is my script which i have used to paginate ,,The datas are restricted to 4 but the pagination link doesn't appear <? require_once ('Pager/Pager.php'); $connection = mysql_connect( "localhost" , "root" , "" ); mysql_select_db( "ssit",$connection); $result=mysql_query("SELECT dFrindName FROM tbl_friendslist", $connection); $row = mysql_fetch_array($result); $totalItems = $row['total']; $pager_options = array( 'mode' => 'Sliding', // Sliding or Jumping mode. See below. 'perPage' => 4, // Total rows to show per page 'delta' => 4, // See below 'totalItems' => $totalItems, ); $pager = Pager::factory($pager_options); echo $pager->links; list($from, $to) = $pager->getOffsetByPageId(); $from = $from - 1; $perPage = $pager_options['perPage']; $result = mysql_query("SELECT * FROM tbl_friendslist LIMIT 5 , $perPage",$connection); while($row = mysql_fetch_array($result)) { echo $row['dFrindName'].'</br>'; } ?>

    Read the article

  • Getting a Script Error Every Time I Click a Link

    - by Flip4Life
    I have everything working perfectly on my site, but for some reason, I get an error message in console whenever I click a link anywhere on my site. The error has to do with this line of coding here: jQuery(function($){ $('.navbar a, .scroll a, .smoothscroll a').bind('click',function(event){ var $anchor = $(this); $('html, body').stop().animate({ scrollTop: $($anchor.attr('href')).offset().top }, 850,'easeInOutExpo'); event.preventDefault(); }); }); And the error I am getting is this: "SCRIPT5007: Unable to get value of the property 'top': object is null or undefined custom.min.js, line 6 character 197" The exact code it is highlighting is this part of the above code: $('html, body').stop().animate({ scrollTop: $($anchor.attr('href')).offset().top }, 850,'easeInOutExpo') All I know is that when I remove the above code, my scroll-to links stop working on pages such as these: http://www.northtownsremodeling.com/things-to-know.php You can see the popup error happen and stay in the console easily by going to a page with a filter like this: http://www.northtownsremodeling.com/bathroom/ And clicking one of the filter buttons. Ultimately, I am trying to make it so my scroll-to setting still works, but not have that error come up anymore. I made this script a long time ago, and I'm really confused as to what could be causing this error when everything is functioning perfectly otherwise? Thanks!

    Read the article

  • Save Cookies, Then Open Link in New Tab

    - by speedplane
    I have some javascript code that saves a cookie. However, if after saving the cookie, the user opens a new tab, it appears that the cookie is not saved. The new tab is on the same domain. Here is my cookie setting/getting code: function setCookie(c_name,value,exdays) { var exdate=new Date(); exdate.setDate(exdate.getDate() + exdays); var c_value=escape(value) + ((exdays==null) ? "" : "; expires="+exdate.toUTCString()); document.cookie=c_name + "=" + c_value; } function getCookie(c_name) { var i,x,y,ARRcookies=document.cookie.split(";"); for (i=0;i<ARRcookies.length;i++) { x=ARRcookies[i].substr(0,ARRcookies[i].indexOf("=")); y=ARRcookies[i].substr(ARRcookies[i].indexOf("=")+1); x=x.replace(/^\s+|\s+$/g,""); if (x==c_name) { return unescape(y); } } } If some javascript calls setCookie('mycookie', 1) and then the user clicks on a link where the _target is set to _blank, the cookie does not load in the new tab. So getCookie('mycookie') will not return 1. What is the problem here?

    Read the article

  • Drupal Adding Span inside A tags in Nice Menus

    - by Chris
    I am trying to add drop down menus to a drupal theme which uses text sliding door CSS rounding. The current version uses a primary links injection of the span into the a tags, which works fine. But doesn't support drop down menus. Working code: <?php print theme('links', $primary_links, array('class' => 'links primary-links')) ?> In the template with a template.php file addition: <?php // function for injecting spans inside anchors which we need for the theme's rounded corner background images function strands_guybrush_links($links, $attributes = array('class' => 'links')) { $output = ''; if (count($links) > 0) { $output = '<ul'. drupal_attributes($attributes) .'>'; $num_links = count($links); $i = 1; foreach ($links as $key => $link) { $class = $key; // Add first, last and active classes to the list of links to help out themers. if ($i == 1) { $class .= ' first'; } if ($i == $num_links) { $class .= ' last'; } if (isset($link['href']) && ($link['href'] == $_GET['q'] || ($link['href'] == '<front>' && drupal_is_front_page()))) { $class .= ' active'; } $output .= '<li'. drupal_attributes(array('class' => $class)) .'>'; if (isset($link['href'])) { $link['title'] = '<span class="link">' . check_plain($link['title']) . '</span>'; $link['html'] = TRUE; // Pass in $link as $options, they share the same keys. $output .= l($link['title'], $link['href'], $link); } else if (!empty($link['title'])) { // Some links are actually not links, but we wrap these in <span> for adding title and class attributes if (empty($link['html'])) { $link['title'] = check_plain($link['title']); } $span_attributes = ''; if (isset($link['attributes'])) { $span_attributes = drupal_attributes($link['attributes']); } $output .= '<span'. $span_attributes .'>'. $link['title'] .'</span>'; } $i++; $output .= "</li>\n"; } $output .= '</ul>'; } return $output; } ?> So I have added the [Nice Menu module][1] which works well and allows the drop down menu functions for my navigation which is now addressed from the template using: <?php print theme_nice_menu_primary_links() ?> The issue is that the a tags need to have spans inside to allow for the selected state markup. I have tried every angle I could find to edit the drupal function menu_item_link which is used by nice menus to build the links. E.g. I looked at the drupal forum for two days and no joy. The lines in the module that build the links are: function theme_nice_menu_build($menu) { $output = ''; // Find the active trail and pull out the menus ids. menu_set_active_menu_name('primary-links'); $trail = menu_get_active_trail('primary-links'); foreach ($trail as $item) { $trail_ids[] = $item['mlid']; } foreach ($menu as $menu_item) { $mlid = $menu_item['link']['mlid']; // Check to see if it is a visible menu item. if ($menu_item['link']['hidden'] == 0) { // Build class name based on menu path // e.g. to give each menu item individual style. // Strip funny symbols. $clean_path = str_replace(array('http://', '<', '>', '&', '=', '?', ':'), '', $menu_item['link']['href']); // Convert slashes to dashes. $clean_path = str_replace('/', '-', $clean_path); $class = 'menu-path-'. $clean_path; $class .= in_array($mlid, $trail_ids) ? ' active' : ''; // If it has children build a nice little tree under it. if ((!empty($menu_item['link']['has_children'])) && (!empty($menu_item['below']))) { // Keep passing children into the function 'til we get them all. $children = theme('nice_menu_build', $menu_item['below']); // Set the class to parent only of children are displayed. $class .= $children ? ' menuparent ' : ''; // Add an expanded class for items in the menu trail. $output .= '<li id="menu-'. $mlid .'" class="'. $class .'">'. theme('menu_item_link', $menu_item['link']); // Build the child UL only if children are displayed for the user. if ($children) { $output .= '<ul>'; $output .= $children; $output .= "</ul>\n"; } $output .= "</li>\n"; } else { $output .= '<li id="menu-'. $mlid .'" class="'. $class .'">'. theme('menu_item_link', $menu_item['link']) .'</li>'."\n"; } } } return $output; } As you can see the $output uses menu_item_link to parse the array into links and to added the class of active to the selected navigation link. The question is how do I add a span inside the a tags OR how do I wrap the a tags with a span that has the active class to style the sliding door links? drupal.org/project/nice_menus drupal.org/node/53233

    Read the article

  • MinGW/G++/g95 link problem - libf95 undefined reference to `MAIN_'

    - by pivakaka
    Hi folks, Summing up, my problem consists on compiling g95 objects inside a C++ application. Actually, I'm constructing an interface for an old fortran program. For this task, I'm using the wxWidgets GUI library, and calling fortran subroutines when necessary. At the beginning, I was developing the entire project compiling my fortran files with gfortran (which comes with GCC) and linking them with my app by the g++ -o... command. Everything was working fine but some numbers values calculated by my fotran subroutines returned NAN values. Doing some research, I realized that compiling my fortran files with gfortran with the -m32 flag, generates this NAN values problem. Although compiling with -m64 flag, my code works properly well. The only trouble here is that my App should be 32bits and then I tryed another compiller. Here I found g95 Fortran compiler, which compiles my fortran code and gives the right output on a 32bits environment. But when I'm trying to link these g95 objects into my program I see this following error: g++ -oCyclonTechTower.exe src\fortran\Modulo_Global.o src\fortran\Prop_Fisicas.o src\fortran\inversa.o src\fortran\tower.o src\fortran\PredadeCarga.o src\fortran\gota.o src\fortran\tadi.o src\view\SimulationORSATCustomDialog.o src\view\SimulationChildGUIFrame.o src\view\ParentGUIFrame.o src\view\ClientGUIFrame.o src\model\TowerData.o src\controller\SimulationController.o src\THEIACyclonTechTower.o ..\Resource\resource.o -Lc:\wxWidgets-2.6.4\lib -Lc:\MinGW\lib\gcc-lib\i686-pc-mingw32\4.1.2 -Bdynamic -Wl,--subsystem,windows -mwindows c:\wxWidgets-2.6.4\lib\libwx_mswu-2.6.a -lwxregexu-2.6 -lwxexpat-2.6 -lwxtiff-2.6 -lwxjpeg-2.6 -lwxpng-2.6 -lwxzlib-2.6 -lrpcrt4 -loleaut32 -lole32 -luuid -lwinspool -lwinmm -lshell32 -lcomctl32 -lcomdlg32 -lctl3d32 -ladvapi32 -lwsock32 -lgdi32 -lgcc -lf95 c:\MinGW\lib\gcc-lib\i686-pc-mingw32\4.1.2/libf95.a(main.o):(.text+0x32): undefined reference to `MAIN_' collect2: ld returned 1 exit status Build error occurred, build is stopped Time consumed: 1531 ms. I have already read the g95 Manual for integration with C++ and I'm actually calling these functions bellow for controlling the fortran environment: void g95_runtime_start(int argc, char *argv[]); void g95_runtime_stop(); I also included the g95 Fortran Runtime Library libf95.a and the libgcc.a into my linker command. Finishing, I don't have a main method implemented because this is managed by wxWidgets, and my fortran subroutines can not have a main function because this is a C++ program calling fortran functions. Can some of you guys help me with this problem? How can I fix this undefined reference to MAIN__ problem? Any idea will be much appreciated. Thanks in advance, George

    Read the article

  • Download And Install apk from a link.

    - by rayman
    Hi, I`am trying to download and install an apk from some link, but for some reason i get an exception. I have one method downloadfile() which downloading the file and a call to and installFile() method, which supposed to install it in the device. some code: public void downloadFile() { String fileName = "someApplication.apk"; MsgProxyLogger.debug(TAG, "TAG:Starting to download"); try { URL u = new URL( "http://10.122.233.22/test/someApplication.apk"); try { HttpURLConnection c = (HttpURLConnection) u.openConnection(); try { c.setRequestMethod("GET"); c.setDoOutput(true); try { c.connect(); FileOutputStream f = context.openFileOutput(fileName, context.MODE_WORLD_READABLE); try { InputStream in = c.getInputStream(); byte[] buffer = new byte[1024]; int len1 = 0; int totsize = 0; try { while ((len1 = in.read(buffer)) > 0) { totsize += len1; f.write(buffer, 0, len1);// .write(buffer); } } catch (IOException e) { e.printStackTrace(); } f.close(); MsgProxyLogger.debug(TAG, TAG + ":Saved file with name: " + fileName); InstallFile(fileName); } catch (IOException e) { e.printStackTrace(); } } catch (IOException e) { e.printStackTrace(); } } catch (ProtocolException e) { e.printStackTrace(); } } catch (IOException e) { e.printStackTrace(); } } catch (MalformedURLException e) { e.printStackTrace(); } } and this is the install file method: private void InstallFile(String fileName) { MsgProxyLogger.debug(TAG, TAG + ":Installing file " + fileName); String src = String.format( "file:///data/data/com.test/files/", fileName); Uri mPackageURI = Uri.parse(src); PackageManager pm = context.getPackageManager(); int installFlags = 0; try { PackageInfo pi = pm.getPackageInfo("com.mirs.agentcore.msgproxy", PackageManager.GET_UNINSTALLED_PACKAGES); if (pi != null) { MsgProxyLogger.debug(TAG, TAG + ":replacing " + fileName); installFlags |= PackageManager.REPLACE_EXISTING_PACKAGE; } } catch (NameNotFoundException e) { } try { // PackageInstallObserver observer = new PackageInstallObserver(); pm.installPackage(mPackageURI); } catch (SecurityException e) { //!!!!!!!!!!!!!here i get an security exception!!!!!!!!!!! MsgProxyLogger.debug(TAG, TAG + ":not permission? " + fileName); } this is the exception details: "Neither user 10057 nor current process has android.permission.INSTALL_PACKAGES". and i have set in my main app that permission in the manifest. anyone has any idea? thanks, ray.

    Read the article

< Previous Page | 56 57 58 59 60 61 62 63 64 65 66 67  | Next Page >