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  • Programatically Add a AnnotationSessionFactoryBean

    - by user146714
    Hi, I have a class that implements BeanDefinitionRegistryPostProcessor. I am trying to add an AnnotationSessionFactoryBean to my Spring Context in either postProcessBeanFactory or postProcessBeanDefinitionRegistry. I need to do this programatically so that I can configure the object at runtime. I am trying to do: @Override public void postProcessBeanDefinitionRegistry(BeanDefinitionRegistry bdr) throws BeansException { RootBeanDefinition bd = new RootBeanDefinition( AnnotationSessionFactoryBean.class); // fails here.. can not cast AnnotationSessionFactoryBean asfb = (AnnotationSessionFactoryBean)bd; bdr.registerBeanDefinition("sessionFactory", asfb); thanks for your help --updated with solution: had to do a: GenericBeanDefinition bd = new GenericBeanDefinition(); bd.setBeanClass(AnnotationSessionFactoryBean.class); bd.getPropertyValues().add("dataSource", dataSource); bdr.registerBeanDefinition("sessionFactory", bd);

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  • Multivalue Mysql Inserts using HibernateTemplate

    - by Langali
    I am using Spring HibernateTemplate and need to insert hundreds of records into a mysql database every second. Not sure what is the most performant way of doing it, but I am trying to see how the multi value mysql inserts do using hibernate. String query = "insert into user(age, name, birth_date) values(24, 'Joe', '2010-05-19 14:33:14'), (25, 'Joe1', '2010-05-19 14:33:14')" getHibernateTemplate().execute(new HibernateCallback(){ public Object doInHibernate(Session session) throws HibernateException, SQLException { return session.createSQLQuery(query).executeUpdate(); } }); But I get this error: 'could not execute native bulk manipulation query.' Please check your query ..... Any idea of I can use a multi value mysql insert using Hibernate? or is my query incorrect? Any other ways that I can improve the performance? I did try the saveOrUpdateAll() method, and that wasn't good enough!

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  • Special characters incongruence

    - by Enrique
    Hello I'm building a Spring MVC web application that runs on Tomcat 6.0.20 and JDK 1.6.0_19. When I send some special characters through an HTML form some of them are stored as question marks ? For example these symbols are stored correctly: €, á, é, í, ‰, etc But some symbols are replaced with ? like: £, ?, ? MySQL tables charset is utf-8. My jsp also use utf-8 <%@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8" %> I have included org.springframework.web.filter.CharacterEncodingFilter in web.xml as suggested here When I debug the POST request when sending 3 characters €a£ with firebug I get: %E2%82%ACa%E2%82%A4 which is correct since E2 82 AC is the code for € and E2 82 A4 is the code for £ but £ is stored as ? in the database. When I save £ directly into the database it is displayed correctly in the webpage. How can I fix this?

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  • In which layer should I join 2 entities together?

    - by William
    I use Spring MVC and a regular JDBC. I've just learned that I should separate business process into layers which are presentation layer, controller layer, service layer, and repository/DAO layer. Now suppose that I have an Entity called Person that can have multiple Jobs. Job itself is another entity which have its own properties. From what I gathered, the repository layer only manages one entity. Now I have one entity that contains another entity. Where do I "join" them? The service layer? Suppose I want to get a person whose job isn't known yet (lazy loading). But the system might ask what the job of that particular person is later on. What is the role of each layer in this case? Please let me know if I need to add any detail into this question.

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  • Q about AbstractApplicationContext.getBeansOfType() and getBean()

    - by Paul Reiners
    We have the following legacy 2.0.7 Spring code: final Map<String, MyClass> secondaryFactories = (Map<String, MyClass>) context.getBeansOfType(MyClass.class, false, true); return (MyClass) context.getBean("myClass"); where context is an instance of org.springframework.context.support.AbstractApplicationContext Note that we ignore the return value of getBeansOfType(). This works just fine, but the problem is that the call to getBeansOfType() is time-consuming. However, even though we ignore the return value of this call, if we try to eliminate this call, then the instance of MyClass returned by getBean() is not fully initialized. (So, apparently, the call to getBeansOfType() is having some sort of side-effects that we need.) We suspect that the call to getBeansOfType() is overkill and we could do something more lightweight so that the instance of MyClass obtained by the call to getBean() would be fully initialized (but it's not null and no exception is thrown). So, is there a more efficient way of doing this?

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  • update portlet without refreshing portal page

    - by mike
    I'm trying to create a simple agena portlet. Now I've developed a basic one using spring-portlet-mvc, it allows you to navigate to the next and previous month with thusly named links that invoke a previousMonth or nextMonth function in my controller. Now the problem I'm having is that this navigation causes my whole page to refresh. Now I was wondering what the best way to fix this was. I've been looking around a bit and it looks like jquery/ajax will do the trick, but since I don't have any experience yet with that technology I was wondering if anyone had any pointers/better ideas to solve my problem.

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  • How to map a search object to a class with more fields with JPA annotations

    - by Moli
    Hi all, I'm a newbie with JPA. I need to map a search object to a table. The search object has only and id, name. The big object has more fileds id, name, adress and more. I use this as big object view plaincopy to clipboardprint? I use this as big object @Entity @Table(name="users") public class User { @Id @GeneratedValue(strategy = GenerationType.AUTO) private long id; private String name; private String adress; private String keywords; } //this is my search object @XXX public class UserSearch { @Id @GeneratedValue(strategy = GenerationType.AUTO) private long id; private String name; } What annotations I need to use to map the search object to the table users? I'm using spring+struts2+hibernate+JPA. Help is appreciated! Thanks!

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  • How to avoid StaleObjectStateException when transaction updates thousands of entities?

    - by ThinkFloyd
    We are using Hibernate 3.6.0.Final with JPA 2 and Spring 3.0.5 for a large scale enterprise application running on tomcat 7 and MySQL 5.5. Most of the transactions in application, lives for less than a second and update 5-10 entities but in some use cases we need to update more than 10-20K entities in single transaction, which takes few minutes and hence more than 70% of times such transaction fails with StaleObjectStateException because some of those entities got updated by some other transaction. We generally maintain version column in all tables and in case of StaleObjectStateException we generally retry but since these longs transactions are anyways very long so if we keep on retrying then also I am not very sure that we'll be able to escape StaleObjectStateException. Also lot of activities keep updating these entities in busy hours so we cannot go with pessimistic approach because it can potentially halt many activities in system. Please suggest how to fix such long transaction issue because we cannot spawn thousands of independent and small transactions because we cannot afford messed up data in case of some failed & some successful transactions.

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  • Streaming large result sets with MySQL

    - by configurator
    I'm developing a spring application that uses large MySQL tables. When loading large tables, I get an OutOfMemoryException, since the driver tries to load the entire table into application memory. I tried using statement.setFetchSize(Integer.MIN_VALUE); but then every ResultSet I open hangs on close(); looking online I found that that happens because it tries loading any unread rows before closing the ResultSet, but that is not the case since I do this: ResultSet existingRecords = getTableData(tablename); try { while (existingRecords.next()) { // ... } } finally { existingRecords.close(); // this line is hanging, and there was no exception in the try clause } The hangs happen for small tables (3 rows) as well, and if I don't close the RecordSet (which happened in one method) then connection.close() hangs.

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  • Use from value from backing bean in javascript

    - by AlfonsSocken
    What I want is to use a boolean value from applicationContext.xml (Jboss configuration file) in my javascript. Currently I use Spring to inject a value configured in applicationContext.xml into my backingbean. Then I put an output text in my jsp like this <h:outputText id="idValue" styleClass="foo" value="" rendered="#{bean.isRendered}"/> In my JavaScript I try following jQuery(function(){ bRedirect = jQuery("#foo").value != undefined; ... All this looks so terrible to me, even though it works fine. There must be a smarter way than doing what I do. Note that I am running JSF1.2 and therefore must use jQuery instead of $ and also select by unique class (foo) and not by id, which may be bad practice as well. Thank you in advance. alfons

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  • Formal name of Magento’s Class Override Design Pattern?

    - by Alan Storm
    Magento is a newish (past 5 years) PHP based Ecommerce system with an architecture that's similar to the Java Spring framework (or so I've been told) One of the features of the Framework is certain classes are not directly instantiated. Rather than do something like $model = new Mage_Foo_Model_Name(); you pass an identifier into a static method on a global application object $model = Mage::getModel('foo/name'); and this instantiates the class for you. One of the wins with this approach is getModel checks a global configuration system for the foo/name identifier, and instantiates the class name it finds in the configuration system. This allows you to change the behavior of a Model system wide with a single configuration change. Is there a formal, Gang of Four or otherwise, name that describes this system/design pattern? The instantiation itself looks like a classic Factory pattern, but I'm specifically interested in the whole "override a class in the system via configuration" aspect. Is there a name/concept that covers this, or is it contained within the worldview of a Factory?

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  • Using jQuery, how do I way attach a string array as a http parameter to a http request?

    - by predhme
    I have a spring controller with a request mapping as follows @RequestMapping("/downloadSelected") public void downloadSelected(@RequestParam String[] ids) { // retrieve the file and write it to the http response outputstream } I have an html table of objects which for every row has a checkbox with the id of the object as the value. When they submit, I have a jQuery callback to serialize all ids. I want to stick those ids into an http request parameter called, "ids" so that I can grab them easily. I figured I could do the following var ids = $("#downloadall").serializeArray(); Then I would need to take each of the ids and add them to a request param called ids. But is there a "standard" way to do this? Like using jQuery?

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  • How to deal with the Hibernate hql multi-join query result in an Object-Oriented Way?

    - by EugeneP
    How to deal with the Hibernate hql multi-join query result in an Object-Oriented Way? As I see it returns a list of Objects. yes, it is tricky and only you who write the query know what should the query return (what objects). But are there ways to simplify things, so that it returned specific objects with no need in casting Object to a specific class according to its position in the query ? Maybe Spring can simplify things here? It has the similar functionality for JDBC, but I don't see if it can help in a similar way with Hibernate.

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  • Restrict confirm message on page reload with f5

    - by Max
    In my JSP page I am using post method while submitting the page. So once I go from Page 1 to page 2. In Page 2, If I press F5 I am getting alert as "To display this page, Firefox must send information that will repeat any action (such as a search or order confirmation) that was performed earlier." I knew this question is a bit sarcastic but please give me an Idea. I can't change my method from POST to GET because I need to send large amount of data. Thanks in advance... Edited: In my Page1.JSP I call onClick function in that function I call action as "/page2servlet.do". Now, In Java side I use Spring Framework. With MVC Object I return to page2.jsp. So where do the response.sendRedirect Fit.

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  • Creating a page selector with JSP/JSTL

    - by zakSyed
    I am working on a project where I am required to build a page somewhat similar to the one you see when you visit a website like blockbuster. When you click on browse more you are taken to a page with a bar on top with different page numbers and a drop down to select the number of pages you want to view on that page. I want to include a feature like that on my page but I am not sure where to start. In my page I have list of 200 items which I want to display page by page. I was suggested to use custom tags, but is there a more simpler or efficient way to create that functionality. My web application uses Spring MVC framework and is coded entirely in Java. Any suggestions will be appreciated.

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  • Unable to pass attribute from controller to view

    - by MDS
    I'm using Spring MVC 3 for a web app. In the app a URI template is supposed to be handled by a controller method, which then passes an attribute to a view. Currently, the controller does handle the request, and it even forwards to the correct view. However, it does NOT pass the attribute to the view. Below are the URI template, controller method and relevent jsp tags. Anyone see what is wrong? URI: /home/{status} Controller: @RequestMapping("/home") @Controller public class HomeController { ... ... @RequestMapping(value="/{status}") public String homeStatusView(@PathVariable("status") String status, ModelMap model) { model.addAttribute("status", status); return "home"; } } JSP: ... <c:if test="${not empty status}"> <span class="status">Your status is available...</span> </c:if> ...

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  • A typical lifecycle of a Hibernate object in a web app - ?

    - by EugeneP
    Describe please a typical lifecycle of a Hibernate object (that maps to a db table) in a web app. Suppose, you create a new instance of an object and persist in the db. But during the app lifetime you'll be working on a detached object and finally you need to update it in the database, for example on exit. How does it look like with hibernate and spring? p.s. Can transactions and sessions live between servlet transitions? So that we opened 1 session and use it in all servlets without a need to reopen it?

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  • org.hibernate.MappingException: Unknown entity:

    - by tsegay
    I tried to see all the questions on this topic but none of them helped me. And I really want to understand what is going on with my code. I have a standalone application which uses spring and Hibernate as JPA and I am trying to run the test using a single main Class My main class package edu.acct.tsegay.common; import edu.acct.tsegay.model.User; import edu.acct.tsegay.business.IUserBusinessObject; import org.springframework.context.ApplicationContext; import org.springframework.context.support.ClassPathXmlApplicationContext; public class App { public static void main(String[] args) { try { ApplicationContext context = new ClassPathXmlApplicationContext( "Spring3AndHibernate-servlet.xml"); IUserBusinessObject userBusinessObject = (IUserBusinessObject) context .getBean("userBusiness"); User user = (User) context.getBean("user1"); user.setPassword("pass"); user.setUsername("tsegay"); System.out.println(user.getPassword()); userBusinessObject.delete(user); User user2 = new User(); user2.setUsername("habest"); user2.setPassword("pass1"); System.out.println(user2.getPassword()); /* * userBusinessObject.save(user2); * * User user3 = userBusinessObject.searchUserbyId("tsegay"); * System.out.println("Search Result: " + user3.getUsername()); */ System.out.println("Success"); } catch (Exception e) { e.printStackTrace(); } } } my application context is: <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd"> <!-- data source --> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="com.mysql.jdbc.Driver" /> <property name="url" value="jdbc:mysql://localhost:3306/test" /> <property name="username" value="test" /> <property name="password" value="password" /> </bean> <!-- session factory --> <bean id="sessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean"> <property name="dataSource"> <ref bean="dataSource" /> </property> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect</prop> <prop key="hibernate.show_sql">true</prop> </props> </property> </bean> <!-- exposed person business object --> <bean id="userBusiness" class="edu.acct.tsegay.business.UserBusinessObject"> <property name="userDao" ref="userDao" /> </bean> <bean id="user1" class="edu.acct.tsegay.model.User"> <property name="username" value="tse" /> <property name="password" value="pass" /> </bean> <!-- Data Access Object --> <bean id="userDao" class="edu.acct.tsegay.dao.UserDao"> <property name="sessionFactory" ref="sessionFactory" /> </bean> </beans> My User Model is: package edu.acct.tsegay.model; import java.io.Serializable; import javax.persistence.Entity; import javax.persistence.Id; import javax.persistence.Version; import org.hibernate.annotations.NaturalId; @Entity public class User implements Serializable { /** * */ private static final long serialVersionUID = 1L; private String username; private String password; private Integer VERSION; @Version public Integer getVERSION() { return VERSION; } public void setVERSION(Integer vERSION) { VERSION = vERSION; } @NaturalId public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } } My DAO is: package edu.acct.tsegay.dao; import edu.acct.tsegay.model.User; import org.hibernate.SessionFactory; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.orm.hibernate3.HibernateTemplate; import org.springframework.stereotype.Repository; @Repository public class UserDao implements IUserDao { private SessionFactory sessionFactory; private HibernateTemplate hibernateTemplate; public SessionFactory getSessionFactory() { return sessionFactory; } @Autowired public void setSessionFactory(SessionFactory sessionFactory) { this.sessionFactory = sessionFactory; this.hibernateTemplate = new HibernateTemplate(sessionFactory); } public void save(User user) { // TODO Auto-generated method stub // getHibernateTemplate().save(user); this.hibernateTemplate.save(user); } public void delete(User user) { // TODO Auto-generated method stub this.hibernateTemplate.delete(user); } public User searchUserbyId(String username) { // TODO Auto-generated method stub return this.hibernateTemplate.get(User.class, username); } } And this my stacktrace error when i run the program: pass org.springframework.orm.hibernate3.HibernateSystemException: Unknown entity: edu.acct.tsegay.model.User; nested exception is org.hibernate.MappingException: Unknown entity: edu.acct.tsegay.model.User at org.springframework.orm.hibernate3.SessionFactoryUtils.convertHibernateAccessException(SessionFactoryUtils.java:679) at org.springframework.orm.hibernate3.HibernateAccessor.convertHibernateAccessException(HibernateAccessor.java:412) at org.springframework.orm.hibernate3.HibernateTemplate.doExecute(HibernateTemplate.java:411) at org.springframework.orm.hibernate3.HibernateTemplate.executeWithNativeSession(HibernateTemplate.java:374) at org.springframework.orm.hibernate3.HibernateTemplate.delete(HibernateTemplate.java:837) at org.springframework.orm.hibernate3.HibernateTemplate.delete(HibernateTemplate.java:833) at edu.acct.tsegay.dao.UserDao.delete(UserDao.java:34) at edu.acct.tsegay.business.UserBusinessObject.delete(UserBusinessObject.java:30) at edu.acct.tsegay.common.App.main(App.java:23) Caused by: org.hibernate.MappingException: Unknown entity: edu.acct.tsegay.model.User at org.hibernate.impl.SessionFactoryImpl.getEntityPersister(SessionFactoryImpl.java:580) at org.hibernate.impl.SessionImpl.getEntityPersister(SessionImpl.java:1365) at org.hibernate.event.def.DefaultDeleteEventListener.onDelete(DefaultDeleteEventListener.java:100) at org.hibernate.event.def.DefaultDeleteEventListener.onDelete(DefaultDeleteEventListener.java:74) at org.hibernate.impl.SessionImpl.fireDelete(SessionImpl.java:793) at org.hibernate.impl.SessionImpl.delete(SessionImpl.java:771) at org.springframework.orm.hibernate3.HibernateTemplate$25.doInHibernate(HibernateTemplate.java:843) at org.springframework.orm.hibernate3.HibernateTemplate.doExecute(HibernateTemplate.java:406) ... 6 more Please let me know if you need any more of my configuration. Any help is much appreciated..

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  • java.lang.IllegalStateException: Neither BindingResult nor plain target object for bean name 'editFo

    - by mansoor
    i am working with spring frame work. Problem is that on forgot password jsp page when i enter the right name or email address the funtion send a mail to the user. But i want when user not enter username or password the calling funtion at controoler return a exception called bind exception and return not in getSuccessView() but redirct at same page and print the Invalid user name or email id. the controller code is following public class EditForgotPasswordFormController extends AbstractBaseFormController{ UserManager userManager; @Override protected ModelAndView executeOnSubmit(ExtendedHttpServletRequest request, ExtendedHttpServletResponse response, Object command, BindException errors) throws Exception { EditForgotPassword e=(EditForgotPassword)command; String s = e.getUsernameOrEmail(); try{ userManager.getNewPassword(s); }catch(RuntimeException exp) { errors.reject("Invailid Username Or EmailId",s); return new ModelAndView("normal/profile/forgot_password"); } return new ModelAndView(getSuccessView()) .addObject("heading", "Please Check You Email") .addObject("message", "Your New Account Information Is sent To At Your Email Id. "); } public UserManager getUserManager() { return userManager; } public void setUserManager(UserManager userManager) { this.userManager = userManager; } } when i am not enter the name or email id the i want redirct at following as indicate above and print message on same jsp where from request is recived........

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  • Redirect on Ajax Jquery Call

    - by Mark Estrada
    Hi, I am newbie to ajax here and I know somebody would have encountered this problem already. I have a legacy app built on Spring MVC, it has a interceptor(filter) that redirects the user to the login page whenever there is no session. public class SessionCheckerInterceptor extends HandlerInterceptorAdapter { public boolean preHandle(HttpServletRequest request, HttpServletResponse response, Object handler) throws Exception { HttpSession session = request.getSession(); // check if userInfo exist in session User user = (User) session.getAttribute("user"); if (user == null) { response.sendRedirect("login.htm"); return false; } return true; } } For non-xmlhttp request, this works fine.. but when I try to use ajax in my application, everything gets weird, it is not able to redirect to the login page correctly. As check the value of the xhr.status = 200 textStatus = parseError errorThrown = "Invalid JSON -Markup of my HTML Login Page- $(document).ready(function(){ jQuery.ajax({ type: "GET", url: "populateData.htm", dataType:"json", data:"userId=SampleUser", success:function(response){ //code here }, error: function(xhr, textStatus, errorThrown) { alert('Error! Status = ' + xhr.status); } }); }); I checked on my firebug that there is a 302 HTTP response but I am not sure how to catch the response and redirect the user to the login page. Any idea here? Thanks.

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  • SimpleJdbcCall ignoring JdbcTemplate fetch size

    - by user289429
    We are calling the pl/sql stored procedure through Spring SimpleJdbcCall, the fetchsize set on the JdbcTemplate is being ignored by SimpleJdbcCall. The rowmapper resultset fetch size is set to 10 even though we have set the jdbctemplate fetchsize to 200. Any idea why this happens and how to fix it? Have printed the fetchsize of resultset in the rowmapper in the below code snippet - Once it is 200 and other time it is 10 even though I use the same JdbcTemplate on both occassion. This direct execution through jdbctemplate returns fetchsize of 200 in the row mapper jdbcTemplate = new JdbcTemplate(ds); jdbcTemplate.setResultsMapCaseInsensitive(true); jdbcTemplate.setFetchSize(200); List temp = jdbcTemplate.query("select 1 from dual", new ParameterizedRowMapper() { public Object mapRow(ResultSet resultSet, int i) throws SQLException { System.out.println("Direct template : " + resultSet.getFetchSize()); return new String(resultSet.getString(1)); } }); This execution through SimpleJdbcCall is always returning fetchsize of 10 in the rowmapper jdbcCall = new SimpleJdbcCall(jdbcTemplate).withSchemaName(schemaName) .withCatalogName(catalogName).withProcedureName(functionName); jdbcCall.returningResultSet((String) outItValues.next(), new ParameterizedRowMapper<Map<String, Object>>() { public Map<String, Object> mapRow(ResultSet rs, int row) throws SQLException { System.out.println("Through simplejdbccall " + rs.getFetchSize()); return extractRS(rs, row); } }); outputList = (List<Map<String, Object>>) jdbcCall.executeObject(List.class, inParam);

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  • Map enum in JPA with fixed values ?

    - by Kartoch
    I'm looking for the different ways to map an enum using JPA. I especially want to set the integer value of each enum entry and to save only the integer value. @Entity @Table(name = "AUTHORITY_") public class Authority implements Serializable { public enum Right { READ(100), WRITE(200), EDITOR (300); private int value; Right(int value) { this.value = value; } public int getValue() { return value; } }; @Id @GeneratedValue(strategy = GenerationType.AUTO) @Column(name = "AUTHORITY_ID") private Long id; // the enum to map : private Right right; } A simple solution is to use the Enumerated annotation with EnumType.ORDINAL: @Column(name = "RIGHT") @Enumerated(EnumType.ORDINAL) private Right right; But in this case JPA maps the enum index (0,1,2) and not the value I want (100,200,300). Th two solutions I found do not seem simple... First Solution A solution, proposed here, uses @PrePersist and @PostLoad to convert the enum to an other field and mark the enum field as transient: @Basic private int intValueForAnEnum; @PrePersist void populateDBFields() { intValueForAnEnum = right.getValue(); } @PostLoad void populateTransientFields() { right = Right.valueOf(intValueForAnEnum); } Second Solution The second solution proposed here proposed a generic conversion object, but still seems heavy and hibernate-oriented (@Type doesn't seem to exist in JEE): @Type( type = "org.appfuse.tutorial.commons.hibernate.GenericEnumUserType", parameters = { @Parameter( name = "enumClass", value = "Authority$Right"), @Parameter( name = "identifierMethod", value = "toInt"), @Parameter( name = "valueOfMethod", value = "fromInt") } ) Is there any other solutions ? I've several ideas in mind but I don't know if they exist in JPA: use the setter and getter methods of right member of Authority Class when loading and saving the Authority object an equivalent idea would be to tell JPA what are the methods of Right enum to convert enum to int and int to enum Because I'm using Spring, is there any way to tell JPA to use a specific converter (RightEditor) ?

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  • Custom JSTL tags with body

    - by Mickel
    Hi, We are going to use JSTL and custom JSTL-tags for some sort of template-engine in our JSP/spring-project. Is there a way to create a tag that looks similar like this: <div id="site"> <div id="header">Some title</div> <div id="navigation"> SOME DYNAMIC CONTENT HERE </div> <div id="content"> ${content} </div> <div id="footer"></div> </div> and use it like this: <mytags:template> <h1>Title</h1> <p>My content!</p> </mytags:template> i.e. use body-content inside a custom JSTL-tag... This works: <mytags:template content="some content... not HTML" /> but is not very useful in our case.

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  • database design to speed up hibernate querying of large dataset

    - by paddydub
    I currently have the below tables representing a bus network mapped in hibernate, accessed from a Spring MVC based bus route planner I'm trying to make my route planner application perform faster, I load all the above tables into Lists to perform the route planner logic. I would appreciate if anyone has any ideas of how to speed my performace Or any suggestions of another method to approach this problem of handling a large set of data Coordinate Connections Table (INT,INT,INT)( Containing 50,000 Coordinate Connections) ID, FROMCOORDID, TOCOORDID 1 1 2 2 1 17 3 1 63 4 1 64 5 1 65 6 1 95 Coordinate Table (INT,DECIMAL, DECIMAL) (Containing 4700 Coordinates) ID , LAT, LNG 0 59.352669 -7.264341 1 59.352669 -7.264341 2 59.350012 -7.260653 3 59.337585 -7.189798 4 59.339221 -7.193582 5 59.341408 -7.205888 Bus Stop Table (INT, INT, INT)(Containing 15000 Stops) StopID RouteID COORDINATEID 1000100001 100 17 1000100002 100 18 1000100003 100 19 1000100004 100 20 1000100005 100 21 1000100006 100 22 1000100007 100 23 This is how long it takes to load all the data from each table: stop.findAll = 148ms, stops.size: 15670 Hibernate: select coordinate0_.COORDINATEID as COORDINA1_2_, coordinate0_.LAT as LAT2_, coordinate0_.LNG as LNG2_ from COORDINATES coordinate0_ coord.findAll = 51ms , coordinates.size: 4704 Hibernate: select coordconne0_.COORDCONNECTIONID as COORDCON1_3_, coordconne0_.DISTANCE as DISTANCE3_, coordconne0_.FROMCOORDID as FROMCOOR3_3_, coordconne0_.TOCOORDID as TOCOORDID3_ from COORDCONNECTIONS coordconne0_ coordinateConnectionDao.findAll = 238ms ; coordConnectioninates.size:48132 Hibernate Annotations @Entity @Table(name = "STOPS") public class Stop implements Serializable { @Id @GeneratedValue @Column(name = "COORDINATEID") private Integer CoordinateID; @Column(name = "LAT") private double latitude; @Column(name = "LNG") private double longitude; } @Table(name = "COORDINATES") public class Coordinate { @Id @GeneratedValue @Column(name = "COORDINATEID") private Integer CoordinateID; @Column(name = "LAT") private double latitude; @Column(name = "LNG") private double longitude; } @Entity @Table(name = "COORDCONNECTIONS") public class CoordConnection { @Id @GeneratedValue @Column(name = "COORDCONNECTIONID") private Integer CoordinateID; /** * From Coordinate_id value */ @Column(name = "FROMCOORDID", nullable = false) private int fromCoordID; /** * To Coordinate_id value */ @Column(name = "TOCOORDID", nullable = false) private int toCoordID; //private Coordinate toCoordID; }

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