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  • jquery - index of click element on the list is different on IE 7

    - by surajz
    cms is generating content in this format. <ul id="slide_nav" class="tabs"> <a name="ctn2363_2465" id="ctn2363_2465" class="hidden"></a><li id="button_1"><a class="ohlord" href="javascript: void(0);" id="b1">Bookbag</a></li> <a name="ctn2363_2466" id="ctn2363_2466" class="hidden"></a><li id="button_2"><a class="ohlord" href="javascript: void(0);" id="b2">help</a></li> <a name="ctn2363_2467" id="ctn2363_2467" class="hidden"></a><li id="button_3"><a class="ohlord" href="javascript: void(0);" id="b3">Team</a></li> <a name="ctn2363_2468" id="ctn2363_2468" class="hidden"></a><li id="button_4"><a class="ohlord" href="javascript: void(0);" id="b4">At</a></li> </ul> To get a correct index of the clicked link I have to do this in IE 7 (use class info in selector) $("#slide_nav li a").click(function(){ var index = $("#slide_nav li > a.ohlord").index(this); }); On firefox $("#slide_nav li > a").index(this); works. On IE this produces incorrect index (0, 2, 4, 6 ..). Is there a way to get the correct index in IE 7 for the above html without using class information in the selector? My second question is $('#slides img')[index].attr('style', 'display: block;'); does not work. I have to iterate through each $('#slides img') elements to set the attribute. Isn't HTMLElement object returned from $('#slides img')[index] an jquery object?

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  • valid xml element in java replaceAll doesnt seem working well

    - by John
    Im trying to create a xml file from a POJO , in which i have a property that stores urls, I have been using the below method to replace all & in the url String to make the xml conform to standards and pass it as an html char entity but the string does not change. public static String forHrefAmpersand(String aURL){ return aURL.replaceAll("&", "&"); } the value might be www.abc.com/controller?a=1&next=showResults I have even tried changing the above method to use "/" as i read replaceAll uses regular expression but replaceAll is not working as exprected, Can anyone tell me what is the mistake im doing ? Thanks in advance

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  • XPath to find an element with a similar sibling

    - by user364902
    Suppose I have this XML: <x> <e a='1' b='A'/> <e a='1' b='B'/> <e a='1' b='A'/> </x> I'd like to write an xpath to find any elements e which: Have attribute @b = 'A' Have the same value for attribute @a The xpath can't reference the literal value of attribute @a, however. It can reference the literal value of attribute @b. Or more generally, I want to find if there are any instances where there are two or more elements e[@b=A'] with the same value for attribute @a. Is this possible?

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  • Actionscript 2.0 element.text always outputs "00"

    - by Mbarry
    Hi everybody, I'm fighting against a strange behaviour with my actionscript! After setting the four integer variables from the MovieTimer sprite (hour, minute, second, mili-sec) and concate them i got always double zero: 00 stop (); delete this.onEnterFrame; var str1; var str2; var mili; var second; var minute; var hour; var timer; mili = _root.MovieTimer.txt_mili.text; second = _root.MovieTimer.txt_sec.text; minute = _root.MovieTimer.txt_min.text; hour = _root.MovieTimer.txt_heures.text; timer = hour+' : '+minute+' : '+second+' : '+mili; _root.MovieSpellFinish.TextTime.text = timer; _root.MovieSpellFinish.TextTime.text outputs: 00 is there any solutions for this??

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  • XML + DOM + replace text in element

    - by yael
    from XML < NET ID="10.10.10.10, 255.255.255.0" / I need to replace the text 10.10.10.10, 255.255.255.0 with 192.9.1.1, 255.0.0.0 by VB + DOM script so the final line in the XML should be < NET ID="192.9.1.1, 255.0.0.0" / THX

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  • "Slice" out one element from a python dictionary

    - by BCS
    I have a dictionary: D = { "foo" : "bar", "baz" : "bip" } and I want to create new dictionary that has a copy of one of it's elements k. So if k = "baz": R = { "baz" : "bip" } what I'v got now is: R = { k : D[k] } But in my case k is a complex expression and I've got a whole stack of these. Caching k in a temporary looks about as ugly as the original option. What I'm looking for is a better (cleaner) way to do this.

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  • Unset an array element inside a foreach loop

    - by Summer
    I'm accessing an array by reference inside a foreach loop, but the unset() function doesn't seem to be working: foreach ( $this->result['list'] as &$row ) { if ($this_row_is_boring) { unset($row); } } print_r($this->result['list']); // Includes rows I thought I unset Ideas? Thanks!

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  • Sort a list whit element still in first position

    - by Mercer
    Hello, i have a String list List<String> listString = new ArrayList<String>(); listString.add("faq"); listString.add("general"); listString.add("contact"); I do some processing on the list and i want to sort this list but I want general is still in first position Thx ;)

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  • How do I select every 6th element from a list (using Linq)

    - by iDog
    Hi, I've got a list of 'double' values. I need to select every 6th record. It's a list of coordinates, where I need to get the minimum and maximum value of every 6th value. List of coordinates (sample): [2.1, 4.3, 1.0, 7.1, 10.6, 39.23, 0.5, ... ] with hundrets of coordinates. Result should look like: [x_min, y_min, z_min, x_max, y_max, z_max] with exactly 6 coordinates. Following code works, but it takes to long to iterate over all coordinates. I'd like to use Linq instead (maybe faster?) for (int i = 0; i < 6; i++) { List<double> coordinateRange = new List<double>(); for (int j = i; j < allCoordinates.Count(); j = j + 6) coordinateRange.Add(allCoordinates[j]); if (i < 3) boundingBox.Add(coordinateRange.Min()); else boundingBox.Add(coordinateRange.Max()); } Any suggestions? Many thanks! Greets!

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  • How can i get the selected option name or id of a select element using jQuery

    - by bill
    Hi All, i have a "questionairre" that is made up of a series of select boxes. i need to use two properties in the options. For each selected option i need the value (which i know how to get and is working fine) but i also need to store an additional value which represents the id of the specific option in a DB. One solution would be to put the two values in the "value" property and parse it out.. but if there is some other property i can use that might be easier and clearer.. can i add a custom property?? like databaseId that could be accessed with jQuery? thanks for ANY suggestions.

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  • hide XML element from appearing in browser

    - by ffsb
    HI, I have a website which I am setting up. However, I want the first page (Home) not to have any sub menu. When I change the value of true to false all the other pages where I want the drop down to appear also disappear. I want other pages to have sub menu but not the home page. I have tried to change the xml path etc, but nothing seems to work. Can somebody please advise on this. I am new to xml and finding this very challenging. I have uploaded the config.xml and the layout xml's. I have also placed the index.htm and js script there. http://www.mediafire.com/?sharekey=043102ffea137c3c67cd7f7bd65f7eef3662a86c6a842d54ea4ac78345cbe4ce Also could someone please help me understand from where it is reading the config.xml.

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  • JQuery not removeing added element

    - by Scott
    What I want to do is add and remove list items. I have got it to add new items to the list and I can remove existing ones but not the ones that have been added. It seem like it would work but it doesn't. Any help would be appreciated! Here the code: JQuery: <script type="text/javascript"> $(function(){ $('a#add').click(function(){ $('<li><a href="#" id="remove">--</a>List item</li>').appendTo('ul#list'); }); $('a#remove').click(function(){ $(this).parent().remove(); }); }); </script> HTML: <a href="#" id="add">Add List Item</a> <ul id="list"> <li><a href="#" id="remove">--</a> List item</li> <li><a href="#" id="remove">--</a> List item</li> <li><a href="#" id="remove">--</a> List item</li> <li><a href="#" id="remove">--</a> List item</li> </ul>

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  • JQuery get element from a string problem

    - by SLC
    Sorry for such a simple question but I can't seem to find the solution. I am trying to fade in and out some divs. Divs have an ID of "div1", "div2", "div3". My code is: var Divs = new Array("div1", "div2", "div3"); I want to fade out one div and then fade in the next on top of it. I have a setinterval that runs every 5 seconds and checked it works. Inside it is this code: $(Divs[1]).fadeOut(1000); $(Divs[2]).fadeIn(1000); However nothing happens when the timer method is ran. Any ideas?

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  • reading root element in xml not the child

    - by Umesha MS
    Hi I am working on an application which reads XML file. Here I am trying to read the node under the not under the node . When I tried to read the I get both. Please help me to solve the problem. Bellow is the sample. "a" "x"..."/X" "b" "name" 123 "/name" "/b" "name" main "/name" "c".."/c" "/a" QDomDocument mDocument; QDomElement mDocumentElement; if (!mDocument.setContent(file.readAll())) { return ; } mDocumentElement = mDocument.documentElement(); QDomNodeList list = mDocumentElement.elementsByTagName("a").at(0).toElement().elementsByTagName("name"); int count = list.count(); for (int i = 0; i < count; i++) { QString str = list.at(i).nodeValue(); QMessageBox::information(this, "text", str, QMessageBox::Yes, 0); }

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  • c++ template and its element type

    - by David
    This is my template matrix class: template<typename T> class Matrix { public: .... Matrix<T> operator / (const T &num); } However, in my Pixel class, I didn't define the Pixel/Pixel operator at all! Why in this case, the compiler still compiles?

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  • Python: Picking an element without replacement

    - by wpeters
    I would like to slice random letters from a string. Given s="howdy" I would like to pick elements from 's' without replacement but keep the index number. For example >>> random.sample(s,len(s)) ['w', 'h', 'o', 'd', 'y'] is close to what I want, but I would actually prefer something like [('w',2), ('h',0), ('o',1), ('d',3), ('y',4)] with letter-index pairs. This is important because the same letter appears in 's' more than once. ie) "letter" where 't' appears twice but I need to distinguish the first 't' from the 'second'. Ideally I actually only need to pick letters as I need them but scrambling and calculating all the letters in a list (as shown above) is ok.

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  • jQuery setinterval does not show first element

    - by Me-and-Coding
    Hi, I am creating this content slider, you can view/edit here: http://jsbin.com/esame4 I have put in place setInterval so that animation runs automatically, however, when it is run for the first time, google image is shown but not afterwords. Should be simple but i am unable to figure out the problem.

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  • Binding an Element to a Control Property (string)

    - by 108980470541437452574
    so, i've found a way to bind a label to a property on current Control i give it a name: <UserControl x:Class="WpfGridtest.GridControl" x:Name="GridControlControl1"> and than bind to property of this control: <Label Content="{Binding ElementName=GridControlControl1, Path=Filter}"></Label> I can see the default value i put in that property. I am guessing that this isn't working because i am binding to String property which doesn't implement INotifyPropertyChanged?? is there some other type i should be using for this property instead of String auto notify my label of changes, or am i going about this the wrong way?

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