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  • Why won't my images align properly?

    I'm trying to make a dynamically sizable title banner, using fairly simple image tricks. I place the banner image in a table cell, and set the background-image of the table row to a one-pixel-wide repeat of the banner's right-most pixel column. Thus, the banner image appears to stretch to fit the screen width without stretching the logo. The code below is my entire page so far, and the problem is shown in a red circle in the screenshot. This is the transition where the main image ends and the one-pixel-wide background image begins. It appears that the one-pixel-wide bar at the end is compressed by one pixel - making the tops align properly, while the bottoms are one pixel off. I should add that I have checked the images more than once to make cure they the image data is correct. They are %100 accurate as far as MSPaint is concerned. <%@ Page Language="C#" AutoEventWireup="true" CodeFile="Default.aspx.cs" Inherits="_Default" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server"> <title></title> </head> <body bgcolor="#000000"> <form id="form1" runat="server"> <div> <table style="width:100%; "> <tr style="background-image: url('Images/Banners/WebBannerWideBar.png')"> <!--WebBannerWideBar is 1x100 px--> <td> <img alt="Angry Octopus" src="Images/Banners/WebBannerWide.png" /> <!--WebBannerWide is 760x100 px--> </td> </tr> </table> </div> </form> </body> </html>

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  • Architectural Design for a Data-Driven Silverlight WP7 app

    - by Rosarch
    I have a Silverlight Windows Phone 7 app that pulls data from a public API. I find myself doing much of the same thing over and over again: In the UI, set a loading message or loading progress bar in place of where the content is Get the content, which may be already in memory, cached in isolated file storage, or require an HTTP request If the content can not be acquired (no network connection, etc), display an error message If the content is acquired, display it in the UI Keep the content in main memory for subsequent queries The content that is displayed to the user can be taken directly from a data source, such as an ObservableCollection, or it may be a query on a data source. I would like to factor out this repetitive process into a framework where ideally only the following needs to be specified: Where to display the content in the UI The UI elements to show while loading, on failure, and on success The URI of the HTTP request How to parse the HTTP response into the data structure that will kept in memory The location of the file in isolated storage, if it exists How to parse the file contents into the data structure that will be kept in memory It may sound like a lot, but two strings, three FrameworkElements, and two methods is less than the overhead that I currently have. Also, this needs to work for however the data is maintained in memory, and needs to work for direct collections and queries on those collections. My questions are: Has something like this already been implemented? Are my thoughts about the topic above fundamentally wrong in some way? Here is a design I'm thinking of: There are two components, a View and a Model. The View is given the FrameworkElements for loading, failure, and success. It is also given a reference to the corresponding Model. The View is a UserControl that is placed somewhere in the UI. The Model a class that is given the URI for the data, a method of how to parse the data, and optionally a filename and how to parse the file. It is responsible for retrieving the data and notifying the View whenever the current status (loading/fail/success) changes. If the data downloaded from the network is different from the cache, the network data takes precedence. When the app closes or is tombstoned, the model writes the data to the cache. How does that sound?

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  • Sencha Touch 2 - Can't get list to display // or load a store? [UPDATED X2]

    - by Jordan
    I have been trying to get a list to display for quite a while now. I have tried all sorts of tips from various people without success. Now I am running into a new problem. I have taken the exact code from an example and I can't seem to get it to work either. First of all, here is the code. Station.js Ext.define('Syl.model.Station', { extend: 'Ext.data.Model', config: { fields: [ { name: 'id', type: 'string' }, { name: 'stop', type: 'string' } ] } }); Stations.js Ext.define('Syl.store.Stations', { extend : 'Ext.data.Store', requires: ['Syl.model.Station'], id: 'stations', xtype: 'stations', config : { model : 'Syl.model.Station', //storeId: 'stationsStore', autoLoad : true, //sorters: 'stop', /* proxy: { type: 'ajax', url: 'stations.json' }*/ data: [ { "id": "129", "stop": "NY Station" }, { "id": "13", "stop": "Newark Station" } ] } }); MyService.js Ext.define('Syl.view.MyService', { extend: 'Ext.Panel', xtype: 'stationsformPage', requires: [ 'Syl.store.Stations', 'Ext.form.FieldSet', 'Ext.field.Password', 'Ext.SegmentedButton', 'Ext.List' ], config: { fullscreen: true, layout: 'vbox', //iconCls: 'settings', //title: 'My Service', items: [ { docked: 'top', xtype: 'toolbar', title: 'My Service' }, { [OLDER CODE BEGIN] xtype: 'list', title: 'Stations', //store: 'Stations', store: stationStore, //UPDATED styleHtmlContent: true, itemTpl: '<div><strong>{stop}</strong> {id}</div>' [OLDER CODE END] [UPDATE X2 CODE BEGIN] xtype: 'container', layout: 'fit', flex: 10, items: [{ xtype: 'list', title: 'Stations', width: '100%', height: '100%', store: stationStore, styleHtmlContent: true, itemTpl: '<div><strong>{stop}</strong> {id}</div>' }] [UPDATE X2 CODE END] }, ] } }); app.js (edited down to the basics) var stationStore; //UPDATED Ext.application({ name: 'Syl', views: ['MyService'], store: ['Stations'], model: ['Station'], launch: function() { stationStore = Ext.create('Syl.store.Stations');//UPDATED var mainPanel = Ext.Viewport.add(Ext.create('Syl.view.MyService')); }, }); Okay, now when I run this in the browser, I get this error: "[WARN][Ext.dataview.List#applyStore] The specified Store cannot be found". The app runs but there is no list. I can't understand how this code could work for the people who gave the example and not me. Could it be a difference in the Sencha Touch version? I am using 2.0.1.1. To add to this, I have been having problems in general with lists not displaying. I had originally tried a stripped down list without even having a store. I tried to just set the data property in the list's config. I didn't get this error, but I also didn't get a list to display. That is why I thought I would try someone else's code. I figured if I could at least get a working list up and running, I could manipulate it into doing what I want. Any help would be greatly appreciated. Thanks. [UPDATED] Okay, so I did some more hunting and someone told me I needed to have an instance of my store to load into the list, not the store definition. So I updated the code as you can see and the error went away. The problem is that I still don't get a list. I have no errors at all, but I can't see a list. Am I not loading the data correctly? Or am I not putting the list in the view correctly? [UPDATED X2] Okay, so I learned that the list should be in a container and that I should give it a width and a height. I'm not totally sure on this being correct, but I do now have a list that I can drag up and down. The problem is there is still nothing in it. Anyone have a clue why?

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  • CSS- removing horizontal space in list menu using display inline property

    - by Kayote
    Hi All, Im new to CSS and have a set target of learning & publishing my website in CSS by the end of the month. My question: Im trying to build a CSS horizontal menu with hover drop downs, however, when I use the 'display: inline' property with li (list) items, I get horizontal spaces between the li (list) items in the bar. How do I remove this space? Here is the html: <div id="tabas_menu"> <ul> <li id="tabBut0" class="tabBut">Overview</li> <li id="tabBut1" class="tabBut">Collar</li> <li id="tabBut2" class="tabBut">Sleeves</li> <li id="tabBut3" class="tabBut">Body</li> </ul> </div> And here is the CSS: #tabas_menu { position: absolute; background: rgb(123,345,567); top: 110px; left: 200px; } ul#tabas_menu { padding: 0; margin: 0; } .tabBut { display: inline; white-space: list-style: none; background: -webkit-gradient(linear, 0% 0%, 0% 100%, from(rgba(255,142,190,1)),to(rgba(188,22,93,1))); background: -moz-linear-gradient(top, rgba(255,142,190,1), rgba(188,22,93,1)); font-family: helvetica, calibri, sans-serif; font-size: 16px; font-weight: bold; line-height: 20px; text-shadow: 1px 1px 1px rgba(99,99,99,0.5); -moz-border-radius: 0.3em; -moz-box-shadow: 0px 0px 2px rgba(0,0,0,0.5); -webkit-border-radius: 0.3em; -webkit-box-shadow: 0px 0px 2px rgba(0,0,0,0.5); padding: 6px 18px; border: 1px solid rgba(0,0,0,0.4); margin: 0; } I can get the space removed using the 'float: left/right' property but its bugging me as to why I cannot achieve the same effect by just using the display property.

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  • How to Automatically Refresh Data on Page Using Ajax on an Interval?

    - by Karnak
    I would like to load an XML file every 30 seconds and display its contents inside an HTML page. So far I know how to load the file, but I don't know how to automatically refresh it and display its updated contents. It would also be great if it did some error checking and if it displayed error.png image when it's not able to load data.xml file. Here is my code: <head> <script> window.XMLHttpRequest { xmlhttp = new XMLHttpRequest(); } xmlhttp.open("GET", "data.xml", false); xmlhttp.send(); loadXMLDoc = xmlhttp.responseXML; f = loadXMLDoc.getElementsByTagName("foo") function buildBar(i) { qux = (f[i].getElementsByTagName("qux")[0].childNodes[0].nodeValue); document.getElementById("displayBar").innerHTML = qux; } </script> </head> <body> <script> document.write("<ul>"); for (var i = 0; i < f.length; i++) { document.write("<li onclick='buildBar(" + i + ")'>"); document.write(f[i].getElementsByTagName("bar")[0].childNodes[0].nodeValue); document.write("</li>"); } document.write("</ul>"); </script> <div id="displayBar"> </div> </body> After searching the internet for a few hours I found many examples on how to do this, but I didn't know how to implement it in my particular case. I am not a programmer, so please be kind. I would really appriciate any help. It would mean a lot.

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  • Crossthread exception and invokerequired solution doesn't change my control value

    - by Pilouk
    EDIT Solution : Here i'm setting my byref value in each object then i'm running a backgroundworker Private Sub TelechargeFichier() Dim DocManquant As Boolean = False Dim docName As String = "" Dim lg As String = "" Dim telechargementFini As Boolean = False lblMessage.Text = EasyDealChangeLanguage.Instance.GetStringFromResourceName("1478") prgBar.Maximum = m_listeFichiers.Count For i As Integer = 0 To m_listeFichiers.Count - 1 m_listeFichiers(i).Set_ByRefLabel(lblMessage) m_listeFichiers(i).Set_ByRefPrgbar(prgBar) m_listeThreads.Add(New Thread(AddressOf m_listeFichiers(i).DownloadMe)) Next m_bgWorker = New BackgroundWorker m_bgWorker.WorkerReportsProgress = True AddHandler m_bgWorker.DoWork, AddressOf DownloadFiles m_bgWorker.RunWorkerAsync() ''Completed 'lblMessage.Text = EasyDealChangeLanguage.Instance.GetStringFromResourceName("1383") 'Me.DialogResult = System.Windows.Forms.DialogResult.OK End Sub Here is my downloadFiles function : Note that each start will do the downloadMe function see below too Private Sub DownloadFiles(sender As Object, e As DoWorkEventArgs) For i As Integer = 0 To m_listeThreads.Count - 1 m_listeThreads(i).Start() Next For i As Integer = 0 To m_listeThreads.Count - 1 m_listeThreads(i).Join() Next End Sub I have multiple thread that each will download a ftp file. I would like that each file that have been completed will set a value to a progress bar and a label from my UI thread. For some reason invokerequired never change to false. Here is my little function that start all the thread Private Sub TelechargeFichier() Dim DocManquant As Boolean = False Dim docName As String = "" Dim lg As String = "" Dim telechargementFini As Boolean = False lblMessage.Text = EasyDealChangeLanguage.Instance.GetStringFromResourceName("1478") prgBar.Maximum = m_listeFichiers.Count For i As Integer = 0 To m_listeFichiers.Count - 1 m_listeFichiers(i).Set_ByRefLabel(lblMessage) m_listeFichiers(i).Set_ByRefPrgbar(prgBar) m_listeThreads.Add(New Thread(AddressOf m_listeFichiers(i).DownloadMe)) Next For i As Integer = 0 To m_listeThreads.Count - 1 m_listeThreads(i).Start() Next For i As Integer = 0 To m_listeThreads.Count - 1 m_listeThreads(i).Join() Next 'Completed lblMessage.Text = EasyDealChangeLanguage.Instance.GetStringFromResourceName("1383") Me.DialogResult = System.Windows.Forms.DialogResult.OK End Sub Here my property that hold the Byref control from the UI thread. This is in my object which content the addressof function that will download the file (DownloadMe) Public Sub Set_ByRefPrgbar(ByRef prgbar As ProgressBar) m_prgBar = prgbar End Sub Public Sub Set_ByRefLabel(ByRef lbl As EasyDeal.Controls.EasyDealLabel3D) m_lblMessage = lbl End Sub Here is the download function : Public Sub DownloadMe() Dim ftpReq As FtpWebRequest Dim ftpResp As FtpWebResponse = Nothing Dim streamInput As Stream Dim fileStreamOutput As FileStream Try ftpReq = CType(WebRequest.Create(EasyDeal.Controls.Common.FTP_CONNECTION & m_downloadFtpPath & m_filename), FtpWebRequest) ftpReq.Credentials = New NetworkCredential(FTP_USER, FTP_PASS) ftpReq.Method = WebRequestMethods.Ftp.DownloadFile ftpResp = ftpReq.GetResponse streamInput = ftpResp.GetResponseStream() fileStreamOutput = New FileStream(m_outputPath, FileMode.Create, FileAccess.ReadWrite) ReadWriteStream(streamInput, fileStreamOutput) Catch ex As Exception 'Au pire la fichier sera pas downloader Finally If ftpResp IsNot Nothing Then ftpResp.Close() End If Dim nomFichier As String = m_displaynameEN If EasyDealChangeLanguage.GetCurrentLanguageTypes = EasyDealChangeLanguage.EnumLanguageType.Francais Then nomFichier = m_displaynameFR End If If m_lblMessage IsNot Nothing Then EasyDealCommon.TH_SetControlText(m_lblMessage, String.Format(EasyDealChangeLanguage.Instance.GetStringFromResourceName("1479"), nomFichier)) End If If m_prgBar IsNot Nothing Then EasyDealCommon.TH_SetPrgValue(m_prgBar, 1) End If End Try End Sub Here is the crossthread invoke solution function : Public Sub TH_SetControlText(ByVal ctl As Control, ByVal text As String) If ctl.InvokeRequired Then ctl.BeginInvoke(New Action(Of Control, String)(AddressOf TH_SetControlText), ctl, text) Else ctl.Text = text End If End Sub Public Sub TH_SetPrgValue(ByVal prg As ProgressBar, ByVal value As Integer) If prg.InvokeRequired Then prg.BeginInvoke(New Action(Of ProgressBar, Integer)(AddressOf TH_SetPrgValue), prg, value) Else prg.Value += value End If End Sub The problem is the invokerequired never get to false it actually goes in to beginInvoke but never end in the Else section to set the value.

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  • Navigating to rootViewController of non-visible UINavigationController CRASH

    - by Bertie
    First off I'n not sure if this is exactly the issue... but it appears to be central to the problem. There are vast gaps in what I know and this may be something very obvious. I have a split view controller with various Master and Detail Views. From one 'menu' branch I want to return to the rootView of both the Master & Detail Navigation Controllers when the user taps a 'Done' button. Initially I had the button positioned on the navigation bar of the master view. This is the code I was using: - (IBAction)doneClicked:(id)sender { UINavigationController *detailNav = [self.splitViewController.viewControllers objectAtIndex:1]; NSArray *allDetailViewControllers = detailNav.viewControllers; HomePage *destinationDetailVC = [allDetailViewControllers objectAtIndex:0]; destinationDetailVC.splitViewBarButtonItem = self.splitViewButton; [detailNav popToRootViewControllerAnimated:NO]; [self.navigationController popToRootViewControllerAnimated:NO]; } That works fine but if the device is in portrait mode it means the user has to open the menus to access the button. So I decided to put the 'Done' button onto the detail view NavBar instead. Using a delegate declared in the detailVC and adopted by the masterVC I am now using this method: - (void)theUserClickedDoneInTheDetailView:(DetailVC *)controller withButton:(UIBarButtonItem *)splitViewButton { UINavigationController *detailNav = [self.splitViewController.viewControllers objectAtIndex:1]; NSArray *allDetailViewControllers = detailNav.viewControllers; HomePage *destinationDetailVC = [allDetailViewControllers objectAtIndex:0]; destinationDetailVC.splitViewBarButtonItem = splitViewButton; [detailNav popToRootViewControllerAnimated: NO]; [self.navigationController popToRootViewControllerAnimated:NO]; } Both methods are in the MasterVC.m file The only difference between the two is that on is passed a UIBarButtonItem to use and the other has already had it passed when it is set in the detail view. That seems to be working because I do get a button. When the device is in Landscape mode both methods work fine. All behaviour as expected. When the device is in Portrait the first method still works fine. The second appears to work fine and the detail view is the rootView, the button for the menus is there BUT, as soon as I turn the device to landscape it crashes. The only thing I can think of is that it is because the masterView is hidden. Can anyone help...?

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  • Help with doctype issues

    - by James
    Hi I am having issues making my footer stick to the bottom of the page in all browsers. I have the following document structure: <html> <head> </head> <body> <div id="wrapper"> <div id="header"> <ul> <li>home</li> </ul> </div> <div class="expander"></div> </div> <div id="footer" class="expander"> </div> </body> </html> Relevant CSS is: body { margin: 0; height: 100%; } #wrapper { min-height: 100%; height: auto !important; height: 100%; margin: 0 auto -116px; } .expander { height: 116px; } #footer { width: 100%; } #header ul { list-style: none outside none; clear: both; margin: 0; } #header li { margin: 0; margin-right: 20px; padding: 0; display: inline-block; height: 85px; padding-top: 20px; margin-bottom: -20px; } When used without any doc type, the page renders as I intend it to in Chrome and Firefox. In IE8, however, the list item tabs are on separate lines When I add an XHTML doctype, the page renders correctly in IE8 except the footer is not drawn at the bottom of the page in IE8, Chrome or Firefox, i.e. the footer sits directly below the menu bar. Example doctype: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd"> What am I doing wrong?

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  • Code to generate random numbers in C++

    - by user1678927
    Basically I have to write a program to generate random numbers to simulate the rolling of a pair of dice. This program should be constructed in multiple files. The main function should be in one file, the other functions should be in a second source file, and their prototypes should be in a header file. First I write a short function that returns a random value between 1 and 6 to simulate the rolling of a single 6-sided die.Second, i write a function that pretends to roll a pair of dice by calling this function twice. My program starts by asking the user how many rolls should be made. Then I write a function to simulate rolling the dice this many times, keeping a count of exactly how many times the values 2,3,4,5,6,7,8,9,10,11,12(each number is the sum of a pair of dice) occur in an array. Later I write a function to display a small bar chart using these counts that ideally would look something like below for a sample of 144 rolls, where the number of asterisks printed corresponds to the count: 2 3 4 5 6 7 8 9 10 11 12 * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * Next, to see how well the random number generator is doing, I write a function to compute the average value rolled. Compare this to the ideal average of 7. Also, print out a small table showing the counts of each roll made by the program, the ideal count based on the frequencies above given the total number of rolls, and the difference between these values in separate columns. This is my incomplete code so far: "Compiler visual studio 2010" int rolling(){ //Function that returns a random value between 1 and 6 rand(unsigned(time(NULL))); int dice = 1 + (rand() %6); return dice; } int roll_dice(int num1,int num2){ //it calls 'rolling function' twice int result1,result2; num1 = rolling(); num2 = rolling(); result1 = num1; result2 = num2; return result1,result2; } int main(void){ int times,i,sum,n1,n2; int c1,c2,c3,c4,c5,c6,c7,c8,c9,c10,c11;//counters for each sum printf("Please enter how many times you want to roll the dice.\n") scanf_s("%i",&times); I pretend to use counters to count each sum and store the number(the count) in an array. I know i need a loop (for) and some conditional statements (if) but m main problem is to get the values from roll_dice and store them in n1 and n2 so then i can sum them up and store the sum in 'sum'.

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  • Dynamic form in PHP not processing correctly

    - by user1497265
    My last question regarding this suggested I incorporate AJAX with PHP. However, I really wanted to try PHP exclusively for this project, and I seem to have made it about 95% there. I just need help on this one issue. Here's a quick background. My project requires a dynamic form to be populated with a max limit of 10 questions. Each form contains one question, one question number, and a text field. Students would go on and answer the questions. This is all driven by a database table (obviously), and when a question gets answered correctly, it will close and the next question in line will appear. There will always be 10 questions on the page. Here's how the coding looks, and it works perfectly. <? $rt = mysql_query("SELECT * FROM The_Questions WHERE Status='Open' ORDER BY 'Number' LIMIT 10"); while ($row = mysql_fetch_array($rt)) { $number=$row[0]; $category = $row[1]; $question=$row[2]; $points=$row[4]; $_SESSION['number'] = $number; ?> <form action="processor.php" method="post" class="qForm"> <div class="questionCell"> <div class="question"><? echo $number; echo $question ?></div> <div class="answer">Answer: <input class="inputField" name="q1" type="text" size="40" maxlength="40" /> <input name="HHQuestion" value="Submit" type="submit" /></div> </div> </form> <? } ?> The questions appear as they should, in the correct order, and the correct limit. Everything seems to be looking fine until a question gets answered and gets processed through the processor.php action. First here's the code to the processor.php file: <?php session_start(); if(isset($_POST["HHQuestion"])){ $dbhost = 'localhost'; $dbname = 'localhost'; $dbuser = 'localhost'; $dbpass = 'localhost'; $conn = mysql_connect($dbhost, $dbuser, $dbpass); mysql_select_db($dbname, $conn); { $number1 = $_SESSION['number']; $answer=$_POST['q1']; $sql="SELECT * FROM The_Questions WHERE Number='$number1'"; $result=mysql_query($sql); $row=mysql_fetch_array($result); $question = $row[2]; echo $question .'<br>'; echo $number1.'<br>'; echo $answer; } } ?> This is NOT live yet, and for testing purposes I'm echoing the question, question number, and answer (as you can see). What's happening is that the $question and $number1 displays the last question in the array (the $answer displays correctly, meaning it displays whatever was written in the dynamic form). Can anyone tell me why that is? If I change the LIMIT number to 20, the processor.php action will display the 20th question and number, even if I was answering question 8, for example, in the dynamic form. Again, the dynamic forms are being displayed correctly, and are numbered correctly. For some unknown reason to me, the action - processor.php - is grabbing the last question in the array. Any ideas on what I'm doing wrong? I'm hoping it's a simple code change that I'm overlooking. Thanks in advance guys!

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  • My horizontal drop down with CSS, sub navigation menu items are being displayed on top of each other

    - by Rigo Collazo
    my sub navigation menu items are being displayed on top of each other here is the code: /* NAVIGATION */ .nav-bar {width: 100%; height: 80px; background-image:url(../images/bg-menu80.jpg);} .nav-hold {overflow: hidden;} .nav-list {float: right;} .nav-list li {float: left; width: auto; position: relative;} .nav-list li a {text-decoration: none; display:block; padding: 30px 7px 20px 7px; color: #f9f9f9; font-size: .9em; font-weight: bold;} .nav-list li ul {display: none;} .nav-list li a:hover {text-decoration: none; display: block; padding: 30px 7px 20px 7px; color: #000; font-size: .9em; font-weight: bold; background-color: #e7e4e4;} .nav-list li a:hover li{display: block; position: absolute; margin: 0; padding: 0;} .nav-list li a:hover li{float: left;} .nav-list li:hover li a{ background-color: #333; border-bottom: 1px solid #fff; color: #FFF;} <ul class="nav-list" id="navigation"><!--Menu list--> <li><a href="index.html">Home</a></li> <li><a href="about.html">About Us</a></li> <li> <ul><a href="members.html">Members</a> <li><a href="board.html">Board of Directors</a></li> <li><a href="committee.html">Committee</a></li> </ul></li> <li><a href="join.html">Join Us</a></li> <li><a href="events.html">Events</a></li> <li><a href="rules.html">Rules &amp; Guidelines</a></li> <li><a href="archive.html">Archive</a></li> <li><a href="contact.html">Contact Us</a></li> <li><a href="#">Login</a></li> </ul><!--ENDS Menu list-->

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  • What language/framework (technology) to use for website (flash games portal)

    - by cripox
    Hello, I know there are a lot of similar questions on the net, but because I am a newbie in web development I didn't find the solution for my specific problem. I am planing on creating a flash games portal from scratch. It is a big chance that there will be big traffic from the beginning (millions of pageviews). I want to reduce the server costs as much as possible but in the same time to not be tide to an expensive contract as there is a chance that the project will not be as successfully as I want and in that case the money would be very little. The question is : what technology to use? I don't know any web dev technology yet so it doesn't matter what I will learn. My web dev experience is a little php 8 years ago, and from then I programmed in C++ / Java- game and mobile development. I like Java and C syntax and language very much and I tend to dislike dynamic typing or non robust scripting (like php)- but I can get along if these are the best choices. The candidates are now: - Grails (my best for now) Ruby on Rails Cake PHP Other technologies (Google App Engine, Python/Django etc...) I was considering at first using pure C and compiling the web app in the server- just to squeeze more from the servers, but soon I understand that this is overkill. Next my eyes came on Ruby - as there is a lot of buzz for it's easiness of use. Next I discovered Grails and looked at Java because it is said that it is "faster". But I don't know what this "Faster" really means on my needs, so here comes the first question: 1) What will be my biggest consumption on the server, other than bandwidth, for a lot of flash content requests? Is it memory? I heard that Java needs a lot of memory, but is faster. Is it CPU? I am planning to take some daily VPS.NET nodes at first, to see if there is a demand, and if the "spike" is permanent to move to a dedicated server (serverloft.com has some good offers), else to remain with less nodes. I was also considering developing in Google App Engine- cheap or free hosting to use at first - so I can test my assumption- and also very easy to use (no need for sys administration) but the costs became high if used more ( 3 million games played / month .. x mb/ each). And the issue with Google is that it looks me in this technology. My other concern is scalability (not only for traffic/users, but as adding functionality) My plans are to release a functional site in just 4 weeks (just the basics frontend and some quick basic backend - so I can be able to modify some things and add games manually) - but then to raise it and add more things to it. I am planning to take a little different approach than other portals so I need to write it from scratch (a script will not do). 2) Will Grails take much more resources than RoR or Php server wise? I heard that making it on Java stack will be hardware expensive and is overkill if you don't make a bank application. My application will not be very complex (I hope and i will try to) but will have a lot of traffic. I also took in account using CDN for files, but the cheapest CDN found was 5c/GB (vps.net) and the cost per gb on serverloft (http://www.serverloft.com/dedizierte-server/server-details.php?products=4) is only 1.79 cents/GB and comes with the other resources either. I am new to this domain (web). I am learning the ropes and searching on the web for ~half of year but don't have any really practical experience, so I know that I must have some naive thinking and other issues that i don't know from now, so please give me any advice you want regarding anything, not just the specific questions asked. And thank you so much for such great community!

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  • How to write php code to input jsonstring and insert to sql server

    - by Romi
    i am trying to OUTPUT a Json String from the phone and to get it uploaded to the sql server i have. I Do not know how to get the output Json and write the php code... i tried many methods but couldnt find a solution. public void post(String string) { HttpClient httpclient = new DefaultHttpClient(); HttpPost httppost = new HttpPost( "http://www.hopscriber.com/xoxoxox/testphp.php"); try { List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(); nameValuePairs.add(new BasicNameValuePair("myJson", string)); httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); HttpResponse response = httpclient.execute(httppost); String str = inputStreamToString(response.getEntity().getContent()) .toString(); Log.w("SENCIDE", str); } catch (Exception e) { Toast.makeText(getBaseContext(), "notwork", Toast.LENGTH_LONG) .show(); } } private Object inputStreamToString(InputStream is) { // TODO Auto-generated method stub String line = ""; StringBuilder total = new StringBuilder(); // Wrap a BufferedReader around the InputStream BufferedReader rd = new BufferedReader(new InputStreamReader(is)); // Read response until the end try { while ((line = rd.readLine()) != null) { total.append(line); } } catch (IOException e) { e.printStackTrace(); } // Return full string return total; } it outputs a json string as [myJson=[{"name":"FriendTracker","user":"amjgp000000000000000","pack":"org.siislab.tutorial.friendtracker","perm":"org.siislab.tutorial.permission.READ_FRIENDS","level":"Normal"},{"name":"FriendTracker","user":"amjgp000000000000000","pack":"org.siislab.tutorial.friendtracker","perm":"org.siislab.tutorial.permission.WRITE_FRIENDS","level":"Normal"},{"name":"FriendTracker","user":"amjgp000000000000000","pack":"org.siislab.tutorial.friendtracker","perm":"org.siislab.tutorial.permission.FRIEND_SERVICE","level":"Normal"},{"name":"FriendTracker","user":"amjgp000000000000000","pack":"org.siislab.tutorial.friendtracker","perm":"org.siislab.tutorial.permission.FRIEND_NEAR","level":"Dangerous"},{"name":"FriendTracker","user":"amjgp000000000000000","pack":"org.siislab.tutorial.friendtracker","perm":"org.siislab.tutorial.permission.BROADCAST_FRIEND_NEAR","level":"Normal"},{"name":"FriendTracker","user":"amjgp000000000000000","pack":"org.siislab.tutorial.friendtracker","perm":"android.permission.RECEIVE_BOOT_COMPLETED","level":"Normal"},{"name":"FriendTracker","user":"amjgp000000000000000","pack":"org.siislab.tutorial.friendtracker","perm":"android.permission.READ_CONTACTS","level":"Dangerous"},{"name":"FriendTracker","user":"amjgp000000000000000","pack":"org.siislab.tutorial.friendtracker","perm":"android.permission.ACCESS_FINE_LOCATION","level":"Dangerous"},{"name":"FriendTracker","user":"amjgp000000000000000","pack":"org.siislab.tutorial.friendtracker","perm":"android.permission.WRITE_EXTERNAL_STORAGE","level":"Dangerous"},{"name":"FriendTracker","user":"amjgp000000000000000","pack":"org.siislab.tutorial.friendtracker","perm":"android.permission.READ_PHONE_STATE","level":"Dangerous"},{"name":"Tesing","user":"amjgp000000000000000","pack":"com.example.tesing","perm":"null","level":"null"},{"name":"Action Bar","user":"amjgp000000000000000","pack":"name.brucephillips.actionbarexample","perm":"null","level":"null"},.......

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  • css of pagination links

    - by fusion
    i'd like a basic idea of how to go about formatting the following paging of the search result. this is the paging code: //Create and print the Navigation bar $nav=""; $next = $page+1; $prev = $page-1; if($page > 1) { $nav .= "<div class=\"search_mainpg\"><div class=\"searchpage\" style=\"width:5%;\"><a onclick=\"showPage('','$prev'); return false;\" href=\"$self?page=" . $prev . "&q=" .urlencode($search_result) . "\">< Prev</a></div>"; $first = "<div class=\"searchpage\" style=\"width:2%;\"><a onclick=\"showPage('','1'); return false;\" href=\"$self?page=1&q=" .urlencode($search_result) . "\"> << </a></div>" ; } else { $nav .= "&nbsp;"; $first = "&nbsp;"; } for($i = 1 ; $i <= $numpages ; $i++) { if($i == $page) { $nav .= "<b>$i</b>"; }else{ $nav .= "<div class=\"searchpage\" style=\"width:2%;\"><a onclick=\"showPage('',$i); return false;\" href=\"$self?page=" . $i . "&q=" .urlencode($search_result) . "\">$i</a></div>"; } } if($page < $numpages) { $nav .= "<div class=\"searchpage\" style=\"width:5%;\"><a onclick=\"showPage('','$next'); return false;\" href=\"$self?page=" . $next . "&q=" .urlencode($search_result) . "\">Next ></a></div>"; $last = "<div class=\"searchpage\" style=\"width:2%;\"><a onclick=\"showPage('','$numpages'); return false;\" href=\"$self?page=$numpages&q=" .urlencode($search_result) . "\"> >> </a></div></div>"; } else { $nav .= "&nbsp;"; $last = "&nbsp;"; } echo $first . $nav . $last; currently, it displays like this:

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  • Split a binary file into chunks c++

    - by L4nce0
    I've been bashing my head against trying to first divide up a file into chunks, for the purpose of sending over sockets. I can read / write a file easily without splitting it into chunks. The code below runs, works, kinda. It will write a textfile and has a garbage character. Which if this was just for txt, no problem. Jpegs aren't working with said garbage. Been at it for a few days, so I've done my research, and it's time to get some help. I do want to stick strictly to binary readers, as this need to handle any file. I've seen a lot of slick examples out there. (none of them worked for me with jpgs) Mostly something along the lines of while(file)... I subscribe to the, if you know the size, use a for-loop, not a while-loop camp. Thank you for the help!! vector<char*> readFile(const char* fn){ vector<char*> v; ifstream::pos_type size; char * memblock; ifstream file; file.open(fn,ios::in|ios::binary|ios::ate); if (file.is_open()) { size = fileS(fn); file.seekg (0, ios::beg); int bs = size/3; // arbitrary. Actual program will use the socket send size int ws = 0; int i = 0; for(i = 0; i < size; i+=bs){ if(i+bs > size) ws = size%bs; else ws = bs; memblock = new char [ws]; file.read (memblock, ws); v.push_back(memblock); } } else{ exit(-4); } return v; } int main(int argc, char **argv) { vector<char*> v = readFile("foo.txt"); ofstream myFile ("bar.txt", ios::out | ios::binary); for(vector<char*>::iterator it = v.begin(); it!=v.end(); ++it ){ myFile.write(*it,strlen(*it)); } }

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  • Testing for Adjacent Cells In a Multi-level Grid

    - by Steve
    I'm designing an algorithm to test whether cells on a grid are adjacent or not. The catch is that the cells are not on a flat grid. They are on a multi-level grid such as the one drawn below. Level 1 (Top Level) | - - - - - | | A | B | C | | - - - - - | | D | E | F | | - - - - - | | G | H | I | | - - - - - | Level 2 | -Block A- | -Block B- | | 1 | 2 | 3 | 1 | 2 | 3 | | - - - - - | - - - - - | | 4 | 5 | 6 | 4 | 5 | 6 | ... | - - - - - | - - - - - | | 7 | 8 | 9 | 7 | 8 | 9 | | - - - - - | - - - - - | | -Block D- | -Block E- | | 1 | 2 | 3 | 1 | 2 | 3 | | - - - - - | - - - - - | | 4 | 5 | 6 | 4 | 5 | 6 | ... | - - - - - | - - - - - | | 7 | 8 | 9 | 7 | 8 | 9 | | - - - - - | - - - - - | . . . . . . This diagram is simplified from my actual need but the concept is the same. There is a top level block with many cells within it (level 1). Each block is further subdivided into many more cells (level 2). Those cells are further subdivided into level 3, 4 and 5 for my project but let's just stick to two levels for this question. I'm receiving inputs for my function in the form of "A8, A9, B7, D3". That's a list of cell Ids where each cell Id has the format (level 1 id)(level 2 id). Let's start by comparing just 2 cells, A8 and A9. That's easy because they are in the same block. private static RelativePosition getRelativePositionInTheSameBlock(String v1, String v2) { RelativePosition relativePosition; if( v1-v2 == -1 ) { relativePosition = RelativePosition.LEFT_OF; } else if (v1-v2 == 1) { relativePosition = RelativePosition.RIGHT_OF; } else if (v1-v2 == -BLOCK_WIDTH) { relativePosition = RelativePosition.TOP_OF; } else if (v1-v2 == BLOCK_WIDTH) { relativePosition = RelativePosition.BOTTOM_OF; } else { relativePosition = RelativePosition.NOT_ADJACENT; } return relativePosition; } An A9 - B7 comparison could be done by checking if A is a multiple of BLOCK_WIDTH and whether B is (A-BLOCK_WIDTH+1). Either that or just check naively if the A/B pair is 3-1, 6-4 or 9-7 for better readability. For B7 - D3, they are not adjacent but D3 is adjacent to A9 so I can do a similar adjacency test as above. So getting away from the little details and focusing on the big picture. Is this really the best way to do it? Keeping in mind the following points: I actually have 5 levels not 2, so I could potentially get a list like "A8A1A, A8A1B, B1A2A, B1A2B". Adding a new cell to compare still requires me to compare all the other cells before it (seems like the best I could do for this step is O(n)) The cells aren't all 3x3 blocks, they're just that way for my example. They could be MxN blocks with different M and N for different levels. In my current implementation above, I have separate functions to check adjacency if the cells are in the same blocks, if they are in separate horizontally adjacent blocks or if they are in separate vertically adjacent blocks. That means I have to know the position of the two blocks at the current level before I call one of those functions for the layer below. Judging by the complexity of having to deal with mulitple functions for different edge cases at different levels and having 5 levels of nested if statements. I'm wondering if another design is more suitable. Perhaps a more recursive solution, use of other data structures, or perhaps map the entire multi-level grid to a single-level grid (my quick calculations gives me about 700,000+ atomic cell ids). Even if I go that route, mapping from multi-level to single level is a non-trivial task in itself.

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  • Zend models and database relathionships

    - by user608341
    Hi people, i'm starting with Zend Framework and I'm a little bit confused with models and relathionships (one-to-many, many-to-many etc). The "Zend Framework Quick Start" says to create a Zend_Db_Table, a Data Mapper and finally our model class Suppose we have a database like this: table A ( id integer primary key, name varchar(50) ); table B ( id integer primary key, a_id integer references A ); then, i'll create: Application_Model_DbTable_A extends Zend_Db_Table_Abstract, Application_Model_AMapper, Application_Model_A, Application_Model_DbTable_B extends Zend_Db_Table_Abstract, Application_Model_BMapper, Application_Model_B, if I understood, i've to store the references informations in Application_Model_DbTable_A: protected $_dependentTables = array('B'); and Application_Model_DbTable_B: protected $_referenceMap = array( 'A' => array( 'columns' => array('a_id'), 'refTableClass' => 'A', 'refColums' => array('id') ) ); and my models class: class Application_Model_A { protected $_id; protected $_name; public function __construct(array $options = null) { if(is_array($options)) { $this->setOptions($options); } } public function __set($name, $value) { $method = 'set' . $name; if (('mapper' == $name) || !method_exists($this, $method)) { throw new Exception('Invalid property'); } $this->$method($value); } public function __get($name) { $method = 'get' . $name; if (('mapper' == $name) || !method_exists($this, $method)) { throw new Exception('Invalid property'); } return $this->$method(); } public function setOptions(array $options) { $methods = get_class_methods($this); foreach ($options as $key => $value) { $method = 'set' . ucfirst($key); if (in_array($method, $methods)) { $this->$method($value); } } return $this; } public function setName($name) { $this->_name = (string) $name; return $this; } public function getName() { return $this->_name; } public function setId($id) { $this->_id = (int) $id; return $this; } public function getId() { return $this->_id; } class Application_Model_B { protected $_id; protected $_a_id; public function __construct(array $options = null) { if(is_array($options)) { $this->setOptions($options); } } public function __set($name, $value) { $method = 'set' . $name; if (('mapper' == $name) || !method_exists($this, $method)) { throw new Exception('Invalid property'); } $this->$method($value); } public function __get($name) { $method = 'get' . $name; if (('mapper' == $name) || !method_exists($this, $method)) { throw new Exception('Invalid property'); } return $this->$method(); } public function setOptions(array $options) { $methods = get_class_methods($this); foreach ($options as $key => $value) { $method = 'set' . ucfirst($key); if (in_array($method, $methods)) { $this->$method($value); } } return $this; } public function setA_id($a_id) { $this->_a_id = (int) $a_id; return $this; } public function getA_id() { return $this->_a_id; } public function setId($id) { $this->_id = (int) $id; return $this; } public function getId() { return $this->_id; } it's that right?

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  • my Search method is coming up with all nulls

    - by Epic.Distortion
    Let me give a quick explanation. I took a 5 week course through a company on Java in July. They covered basic stuff, like console app, crud operations, mysql, and n-tier architecture. Since the course ended I didn't use it much because I went back to work, and other medical reasons surfaced....blah blah. I was told by the company to make a simple program to reflect what I learned. Turns out I retained very little. I decided to make a video game starage program. It would be used to stare your video games so you wouldn't have to search your bookcase(or how ever you store your games.) It is a basic console app using the crud operations with MYSQL. I can't get my search function to actually work. I have 2 layers a Presentation layer and a Logic layer. The search method allows them to search for a game by the title. when i bring run the program and use Search it only displays the title and the rest is null. here is my Presentation layer: private static Games SearchForGame() { Logic aref = new Logic(); Games g = new Games(); Scanner scanline = new Scanner(System.in); System.out.println("Please enter the name of the game you wish to find:"); g.setTitle(scanline.nextLine()); aref.SearchGame(); System.out.println(); System.out.println("Game Id: " + g.getGameId()); System.out.println("Title: " + g.getTitle()); System.out.println("Rating: " + g.getRating()); System.out.println("Platform: "+ g.getPlatform()); System.out.println("Developer: "+ g.getDeveloper()); return g; } and here is my logic layer public Games SearchGame() { Games g = new Games(); try { Class.forName(driver).newInstance(); Connection conn = DriverManager.getConnection(url+dbName,userName,password); java.sql.PreparedStatement statement = conn.prepareStatement("SELECT GameId,Title,Rating,Platform,Developer FROM games WHERE Title=?"); statement.setString(1, g.getTitle()); ResultSet rs = statement.executeQuery(); while(rs.next()){ g.setGameId(rs.getInt("GameId")); g.setTitle(rs.getString("Title")); g.setRating(rs.getString("Rating")); g.setPlatform(rs.getString("Platform")); g.setDeveloper(rs.getString("Developer")); statement.executeUpdate(); } } catch (Exception e) { e.printStackTrace(); } return g; } here is also my last results Please enter the name of the game you wish to find: Skyrim Game Id: 0 Title: Skyrim Rating: null Platform: null Developer: null any help would be greatly appreciated and thanks in advance EDIT: here is my code for my games class public class Games { public int GameId; public String Title; public String Rating; public String Platform; public String Developer; public int getGameId() { return GameId; } public int setGameId(int gameId) { return GameId = gameId; } public String getTitle() { return Title; } public String setTitle(String title) { return Title = title; } public String getRating() { return Rating; } public void setRating(String rating) { Rating = rating; } public String getPlatform() { return Platform; } public void setPlatform(String platform) { Platform = platform; } public String getDeveloper() { return Developer; } public void setDeveloper(String developer) { Developer = developer; } }

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  • style a navigation link when a particular div is shown

    - by Matt Meadows
    I have JQuery working to show a particular div when a certain link is clicked. I have managed to apply the effect I'm after with the main navigation bar through id'ing the body tag and using css to style when the id is found. However, i'd like to apply the same effect to the sub navigation when a certain div is present. How the main navigation is styled: HTML: <nav> <ul> <li id="nav-home"><a href="index.html">Home</a></li> <li id="nav-showreel"><a href="showreel.html">Showreel</a></li> <li id="nav-portfolio"><a href="portfolio.html">Portfolio</a></li> <li>Contact</li> </ul> </nav> CSS: body#home li#nav-home, body#portfolio li#nav-portfolio { background: url("Images/Nav_Underline.png") no-repeat; background-position: center bottom; color: white; } (Other links havent been added to styling as those pages are still in development) How the sub navigation is structured: <nav id="portfolioNav"> <ul> <li id="portfolio-compositing"><a id="compositingWork" href="#">Compositing</a></li> <li id="portfolio-animation"><a id="animationWork" href="#">Animation</a></li> <li id="portfolio-motionGfx"><a id="GFXWork" href="#">Motion Graphics</a></li> <li id="portfolio-3D"><a id="3DWork" href="#">3D</a></li> </ul> </nav> As you can see, its similar format to the main navigation, however i've tried the same approach and it doesn't work :( The Javascript that switches the divs on the navigation click: <script type="text/javascript"> $(document).ready(function() { $('#3DWork').click(function(){ $('#portfolioWork').load('portfolioContent.html #Portfolio3D'); }); $('#GFXWork').click(function(){ $('#portfolioWork').load('portfolioContent.html #motionGraphics'); }); $('#compositingWork').click(function(){ $('#portfolioWork').load('portfolioContent.html #PortfolioCompositing'); }); $('#animationWork').click(function(){ $('#portfolioWork').load('portfolioContent.html #PortfolioAnimation'); }); }); </script> JSFiddle for full HTML & CSS : JSFiddle File The effect I'm After:

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  • Large Data Table with first column fixed

    - by bhavya_w
    I have structure as shown in the fiddle http://jsfiddle.net/5LN7U/. <section class="container"> <section class="field"> <ul> <li> Question 1 </li> <li> question 2 </li> <li> question 3 </li> <li> question 4 </li> <li> question 5 </li> <li> question 6 </li> <li> question 7 </li> </ul> </section> <section class="datawrap"> <section class="datawrapinner"> <ul> <li><b>Answer 1 :</b></li> <li><b>Answer 2 :</b></li> <li><b>Answer 3 :</b></li> <li><b>Answer 4 :</b></li> <li><b>Answer 5 :</b></li> <li><b>Answer 6 :</b></li> <li><b>Answer 7 :</b></li> </ul> </section> </section> </section> Basically its a table structure made using divs. The first column contains a long list of questions and the second column contains answers/multiple answers which can be quite big ( there has to be horizontal scrolling in the second column.) The problem i am facing is when i scroll downwards the second column which has the horizontal scroll bar is also scrolling downward. I want horizontal scrollbar to be fixed there. as in it should be always fixed there no matter how much i scroll vertically. Much Like Google Spreadsheets: where the first column stays fixed and there's horizontal scrolling on rest of the columns with over vertical scrolling for whole of the data. I cannot used position fixed in the second column. P.S : please no lectures on using div's for making a table structure. I have my own reasons. and its kinda urgent. Thanks in advance.

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  • How can I scale movement physics functions to frames per second (in a game engine)?

    - by Richard
    I am working on a game in Javascript (HTML5 Canvas). I implemented a simple algorithm that allows an object to follow another object with basic physics mixed in (a force vector to drive the object in the right direction, and the velocity stacks momentum, but is slowed by a constant drag force). At the moment, I set it up as a rectangle following the mouse (x, y) coordinates. Here's the code: // rectangle x, y position var x = 400; // starting x position var y = 250; // starting y position var FPS = 60; // frames per second of the screen // physics variables: var velX = 0; // initial velocity at 0 (not moving) var velY = 0; // not moving var drag = 0.92; // drag force reduces velocity by 8% per frame var force = 0.35; // overall force applied to move the rectangle var angle = 0; // angle in which to move // called every frame (at 60 frames per second): function update(){ // calculate distance between mouse and rectangle var dx = mouseX - x; var dy = mouseY - y; // calculate angle between mouse and rectangle var angle = Math.atan(dy/dx); if(dx < 0) angle += Math.PI; else if(dy < 0) angle += 2*Math.PI; // calculate the force (on or off, depending on user input) var curForce; if(keys[32]) // SPACE bar curForce = force; // if pressed, use 0.35 as force else curForce = 0; // otherwise, force is 0 // increment velocty by the force, and scaled by drag for x and y velX += curForce * Math.cos(angle); velX *= drag; velY += curForce * Math.sin(angle); velY *= drag; // update x and y by their velocities x += velX; y += velY; And that works fine at 60 frames per second. Now, the tricky part: my question is, if I change this to a different framerate (say, 30 FPS), how can I modify the force and drag values to keep the movement constant? That is, right now my rectangle (whose position is dictated by the x and y variables) moves at a maximum speed of about 4 pixels per second, and accelerates to its max speed in about 1 second. BUT, if I change the framerate, it moves slower (e.g. 30 FPS accelerates to only 2 pixels per frame). So, how can I create an equation that takes FPS (frames per second) as input, and spits out correct "drag" and "force" values that will behave the same way in real time? I know it's a heavy question, but perhaps somebody with game design experience, or knowledge of programming physics can help. Thank you for your efforts. jsFiddle: http://jsfiddle.net/BadDB

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  • iframe 100% height causing vertical scrollbar

    - by Keevon
    I'm trying to layout a design that has a fixed height header at the top of the screen, and then an iframe below taking up the remaining space. The solution I came up with is as follows: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <style type="text/css"><!-- * {margin: 0;} html, body {height: 100%;width: 100%;margin: 0;padding: 0;}--></style> </head> <body> <div style="height:70px;background-color:blue;"></div> <div style="position:absolute;top:70px;bottom:0;left:0;right:0;"> <iframe src="http://www.google.com" frameborder="0" style="border:0;padding:0;margin:0;width:100%;height:100%;"></iframe> </div> </body> </html> Essentially, I'm creating an absolutely positioned div below the header and sizing it to take up the rest of the space, then putting the full size iframe in there. The problem I'm running into is that if you paste the code exactly as seen below, using XHTML Strict, in each browser (tested w/ chrome/safari/ie8) you will see a vertical scroll bar with a few pixels of white space below the div. Doing some experimenting, I found that if I remove the doctype completely it works in safari/chrome, but IE gets even worse, setting the iframe height to 300px or so. If I set the doctype to transitional, it works in safari/chrome but has the same problem as in the strict case for IE8. If I use the HTML5 doctype, it has the same problem as strict in all browsers. Finally, if I remove the iframe in any of these cases, everything is laid out just fine. Anyone have any ideas?

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  • Remotely Schedule and Stream Recorded TV in Windows 7 Media Center

    - by DigitalGeekery
    Have you ever been away from home and suddenly realized you forgot to record your favorite program? Now Windows 7 Media Center, users can schedule recordings remotely from their phones or mobile devices with Remote Potato. How it Works Remote Potato installs server software on the host computer running Windows 7 Media Center. Once the software is installed, we’ll need to do some port forwarding on the router and setup an optional dynamic DNS address. When setup is completed, we will access the application through a web based interface. Silverlight is required for Streaming recorded TV, but scheduling recordings can be done through an HTML interface. Installing Remote Potato Download and install Remote Potato on the Media Center PC. (See download link below) If you plan to stream any Recorded TV, you’ll also want to install the streaming pack located on the same page. It isn’t required to stream all shows, only shows that require the AC3 audio codec. Click Yes to allow Remote Potato to add rules to the Windows Firewall for remote access. You’ll likely need to accept a few UAC prompts. When notified that the rules were added, click OK. Remote Potato will then prompt you to allow administrator privileges to reserve a URL for it’s web server. Click Yes. Remote Potato server will start. Click on the configuration button at the right to to reveal the settings tabs.   One the General tab, you’ll have the option to run Remote Potato on startup and minimized in the System Tray. If you’re running Media Center on a dedicated HTPC, you’ll probably want to enable both startup options. Forwarding Ports on Your Router You’ll need to forward a couple ports on your router. By default, these will be ports 9080 and 9081. In this example we’re using a Linksys WRT54GL router, however, the steps for port forwarding will vary from router to router. On the Linksys configuration page, click on the Applications & Gaming Tab, and then the Port Range Forward tab. Under Application, type in a name of your choosing. In both the Start and End boxes, type the port number 9080. Enter the local IP address of your Media Center computer in the IP address column. Click the check box under Enable. Repeat the process on the next line, but this time use port 9081. When finished, click the Save Settings button. Note: It’s highly recommended that you configure the home computer running Media Center & Remote Potato with a static IP address.   Find your IP Address You’ll need to find the IP address assigned to your router from your ISP. There are many ways to do this but a quick and easy way is to visit a site like checkip.dyndns.org (link available below) The current external IP address of your router will be displayed in the browser.   Dynamic DNS This is an optional step, but  it’s highly recommended. Many routers, such as the Linksys WRT54GL we are using, support Dynamic DNS (DDNS). What Dynamic DNS allows you to do is affiliate your home router’s external IP address to a domain name. Every time your home router is assigned a a new IP address by your ISP, the domain name is updated to point to your new IP address. Remote Potato’s user interface is accessed over the Internet is by connecting to your router’s IP address followed by a colon and the port number. (Ex: XXX.XXX.XXX.XXX:9080) Instead of constantly having to look up and remember an IP address, you can use DDNS along with a 3rd party provider like DynDNS.com, to sign up for a free domain name and configure it to be updated each time your router is assigned a new IP address. Go to the DynDNS.com website (See link at the end of the article) and sign up for a free Domain name. You’ll need to register and confirm by email.   Once you’ve signed in and selected your domain name click Activate Services. You’ll get a confirmation message that your domain name has been activated.    On the Linksys WRT54GL click on the Setup tab an then DDNS. Select DynDNS.org, or TZO.com if you prefer to use their service, from the drop down list.   With DynDNS, you’ll need to fill in your username and password you signed up with at the DynDNS website and the hostname you chose. Note: You can connect over your local network with the IP Address of the computer running Remote Potato followed by a colon and the port number. Ex: 192.168.1.2:9080 Logging in Remote Potato and Recording a Show Once you connect, you’ll see the start page. To view the TV listings, click on TV Guide. You’ll then see your guide listings. There are a few ways to navigate the listings. At the top left, you can click on any of the preset time buttons to jump to  the listings at that time of the day.  Click on the arrows to the right and left of the day and date at the top center to proceed to the previous or next day. Or, jump to a specific day with the date and date buttons at the top right.   To setup a recording, click on a program.   You can choose to record the individual show or the entire series by clicking on Record Show or Record Series.   Remote Potato on Mobile Devices Perhaps the coolest feature of Remote Potato is the ability to schedule recording from your phone or mobile device. Note: For any devices or computers without Silverlight, you will be prompted to view the HTML page. Select Browse Listings. Select your program to record. In the Program Details, select Record Show to record the single episode or Record Series to record all instances of the series. You will then see a red dot on the program listing to indicate that the show is scheduled for recording.   Streaming Recorded TV Click on Recorded TV from the home screen to access your previously recorded TV programs. Click on the selection you wish to stream. Click on Play. If you receive this error message, you’ll need to install the streaming pack for Remote Potato. This is found on the same download page as installation files. (See link below) The Begin from slider allows you to start playback from the start (by default) or a different time of the program by moving the slider. The Quality (bitrate) setting  allows you to choose the quality of the playback. We found the video quality on the Normal setting to be pretty lousy, and Low was just pointless. High was the best overall viewing experience as it provided smooth quality video playback. We experienced significant stuttering during playback using the Ultra High setting.   Click Start when you are ready to begin. When playback begins you’ll see a slider at the top right.   Move the slider left or right to increase or decrease the size of the video. There’s also a button to switch to full screen.   Media Center users who travel frequently or are always on the go will likely find Remote Potato to be a blessing. Since being released earlier this year, updates for Remote Potato have come fast and furious. The latest beta release includes support for streaming music and photos. If you like those nice network TV logos, check out our article on adding TV channel logos to Windows Media Center. Downloads and Links Download Remote Potato and Streaming Pack Find your IP address Sign Up for a Domain Name at DynDNS.com Similar Articles Productive Geek Tips Schedule Updates for Windows Media CenterUsing Netflix Watchnow in Windows Vista Media Center (Gmedia)Add a Sleep Timer to Windows 7 Media CenterStartup Customizations for Media Center in Windows 7Enable Media Streaming in Windows Home Server to Windows Media Player TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips DVDFab 6 Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 FoxClocks adds World Times in your Statusbar (Firefox) Have Fun Editing Photo Editing with Citrify Outlook Connector Upgrade Error Gadfly is a cool Twitter/Silverlight app Enable DreamScene in Windows 7 Microsoft’s “How Do I ?” Videos

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  • How To Run XP Mode in VirtualBox on Windows 7 (sort of)

    - by Matthew Guay
    A few weeks ago we showed you how to run XP Mode on a Windows 7 computer without Hardware Virtualization using VMware. Some of you have been asking if it can be done in Virtual Box as well. The answer is “Yes!” and here we’ll show you how. Editor Update: Apparently there isn’t a way to activate XP Mode through VirtualBox using this method. You will however, be able to run it for 30 days. We have a new updated article on how to Install XP Mode with VirtualBox Using the VMLite Plugin.   Earlier we showed you how to run XP mode on windows 7 machines without hardware virtualization capability. Since then, a lot of you have been asking to a write up a tutorial about doing the same thing using VirtualBox.  This makes it another great way to run XP Mode if your computer does not have hardware virtualization.  Here we’ll see how to import the XP Mode from Windows 7 Professional, Enterprise, or Ultimate into VirtualBox so you can run XP in it for free. Note: You need to have Windows 7 Professional or above to use XP Mode in this manner. In our tests we were able to get it to run on Home Premium as well, but you’ll be breaking Windows 7 licensing agreements. Getting Started First, download and install XP Mode (link below).  There is no need to download Virtual PC if your computer cannot run it, so just download the XP Mode from the link on the left. Install XP mode; just follow the default prompts as usual. Now, download and install VirtualBox 3.1.2 or higher(link below).  Install as normal, and simply follow the default prompts. VirtualBox may notify you that your network connection will be reset during the installation.  Press Yes to continue. During the install, you may see several popups asking you if you wish to install device drivers for USB and Network interfaces.  Simply click install, as these are needed for VirtualBox to run correctly. Setup only took a couple minutes, and doesn’t require a reboot. Setup XP Mode in VirtualBox: First we need to copy the default XP Mode so VirtualBox will not affect the original copy.  Browse to C:\Program Files\Windows XP Mode, and copy the file “Windows XP Mode base.vhd”.  Paste it in another folder of your choice, such as your Documents folder. Once you’ve copied the file, right-click on it and click Properties. Uncheck the “Read-only” box in this dialog, and then click Ok. Now, in VirtualBox, click New to create a new virtual machine. Enter the name of your virtual machine, and make sure the operating system selected is Windows XP. Choose how much memory you want to allow the virtual machine to use.  VirtualBox’ default is 192 Mb ram, but for better performance you can select 256 or 512Mb. Now, select the hard drive for the virtual machine.  Select “Use existing hard disk”, then click the folder button to choose the XP Mode virtual drive. In this window, click Add, and then browse to find the copy of XP Mode you previously made. Make sure the correct virtual drive is selected, then press Select. After selecting the VHD your screen should look like the following then click Next. Verify the settings you made are correct. If not, you can go back and make any changes. When everything looks correct click Finish. Setup XP Mode Now, in VirtualBox, click start to run XP Mode. The Windows XP in this virtual drive is not fully setup yet, so you will have to go through the setup process.   If you didn’t uncheck the “Read-only” box in the VHD properties before, you may see the following error.  If you see it, go back and check the file to makes sure it is not read-only. When you click in the virtual machine, it will capture your mouse by default.  Simply press the right Ctrl key to release your mouse so you can go back to using Windows 7.  This will only be the case during the setup process; after the Guest Additions are installed, the mouse will seamlessly move between operating systems. Now, accept the license agreement in XP.   Choose your correct locale and keyboard settings. Enter a name for your virtual XP, and an administrative password. Check the date, time, and time zone settings, and adjust them if they are incorrect.  The time and date are usually correct, but the time zone often has to be corrected. XP will now automatically finish setting up your virtual machine, and then will automatically reboot. After rebooting, select your automatic update settings. You may see a prompt to check for drivers; simply press cancel, as all the drivers we need will be installed later with the Guest Additions. Your last settings will be finalized, and finally you will see your XP desktop in VirtualBox. Please note that XP Mode may not remain activated after importing it into VirtualBox. When you activate it, use the key that is located at C:\Program Files\Windows XP Mode\key.txt.  Note: During our tests we weren’t able to get the activation to go through. We are looking into the issue and will have a revised article showing the correct way to get XP Mode in VirutalBox working correctly soon.    Now we have one final thing to install – the VirtualBox Guest Additions.  In the VirtualBox window, click “Devices” and then select “Install Guest Additions”. This should automatically launch in XP; if it doesn’t, click Start, then My Computer, and finally double-click on the CD drive which should say VirtualBox Guest Additions. Simply install with the normal presets. You can select to install an experimental 3D graphics driver if you wish to try to run games in XP in VirtualBox; however, do note that this is not fully supported and is currently a test feature. You may see a prompt informing you that the drivers have not passed Logo testing; simply press “Continue Anyway” to proceed with the installation.   When installation has completed, you will be required to reboot your virtual machine. Now, you can move your mouse directly from Windows XP to Windows 7 without pressing Ctrl. Integrating with Windows 7 Once your virtual machine is rebooted, you can integrate it with your Windows 7 desktop.  In the VirtualBox window, click Machine and then select “Seamless Mode”.   In Seamless mode you’ll have the XP Start menu and taskbar sit on top of your Windows 7 Start and Taskbar. Here we see XP running on Virtual Box in Seamless Mode. We have the old XP WordPad sitting next to the new Windows 7 version of WordPad. Another view of everything running seamlessly together on the same Windows 7 desktop. Hover the pointer over the XP taskbar to pull up the Virtual Box menu items. You can exit out of Seamless Mode from the VirtualBox menu or using “Ctrl+L”. Then you go back to having it run separately on your desktop again. Conclusion Running XP Mode in a Virtual Machine is a great way to experience the feature on computers without Hardware Virtualization capabilities. If you prefer VMware Player, then you’ll want to check out our articles on how to run XP Mode on Windows 7 machines without Hardware Virtualization, and how to create an XP Mode for Windows 7 Home Premium and Vista. Download VirtualBox Download XP Mode Similar Articles Productive Geek Tips Install XP Mode with VirtualBox Using the VMLite PluginUsing Windows 7 or Vista Compatibility ModeMake Safari Stop Crashing Every 20 Seconds on Windows VistaForce Windows 7 / Vista to Boot Into Safe Mode Without Using the F8 KeyHow To Run Chrome OS in VirtualBox TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 PCmover Professional Enable Check Box Selection in Windows 7 OnlineOCR – Free OCR Service Betting on the Blind Side, a Vanity Fair article 30 Minimal Logo Designs that Say More with Less LEGO Digital Designer – Free Create a Personal Website Quickly using Flavors.me

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  • How To Run XP Mode in VirtualBox on Windows 7 (sort of)

    - by Matthew Guay
    A few weeks ago we showed you how to run XP Mode on a Windows 7 computer without Hardware Virtualization using VMware. Some of you have been asking if it can be done in Virtual Box as well. The answer is “Yes!” and here we’ll show you how. Editor Update: Apparently there isn’t a way to activate XP Mode through VirtualBox using this method. You will however, be able to run it for 30 days. We have a new updated article on how to Install XP Mode with VirtualBox Using the VMLite Plugin.   Earlier we showed you how to run XP mode on windows 7 machines without hardware virtualization capability. Since then, a lot of you have been asking to a write up a tutorial about doing the same thing using VirtualBox.  This makes it another great way to run XP Mode if your computer does not have hardware virtualization.  Here we’ll see how to import the XP Mode from Windows 7 Professional, Enterprise, or Ultimate into VirtualBox so you can run XP in it for free. Note: You need to have Windows 7 Professional or above to use XP Mode in this manner. In our tests we were able to get it to run on Home Premium as well, but you’ll be breaking Windows 7 licensing agreements. Getting Started First, download and install XP Mode (link below).  There is no need to download Virtual PC if your computer cannot run it, so just download the XP Mode from the link on the left. Install XP mode; just follow the default prompts as usual. Now, download and install VirtualBox 3.1.2 or higher(link below).  Install as normal, and simply follow the default prompts. VirtualBox may notify you that your network connection will be reset during the installation.  Press Yes to continue. During the install, you may see several popups asking you if you wish to install device drivers for USB and Network interfaces.  Simply click install, as these are needed for VirtualBox to run correctly. Setup only took a couple minutes, and doesn’t require a reboot. Setup XP Mode in VirtualBox: First we need to copy the default XP Mode so VirtualBox will not affect the original copy.  Browse to C:\Program Files\Windows XP Mode, and copy the file “Windows XP Mode base.vhd”.  Paste it in another folder of your choice, such as your Documents folder. Once you’ve copied the file, right-click on it and click Properties. Uncheck the “Read-only” box in this dialog, and then click Ok. Now, in VirtualBox, click New to create a new virtual machine. Enter the name of your virtual machine, and make sure the operating system selected is Windows XP. Choose how much memory you want to allow the virtual machine to use.  VirtualBox’ default is 192 Mb ram, but for better performance you can select 256 or 512Mb. Now, select the hard drive for the virtual machine.  Select “Use existing hard disk”, then click the folder button to choose the XP Mode virtual drive. In this window, click Add, and then browse to find the copy of XP Mode you previously made. Make sure the correct virtual drive is selected, then press Select. After selecting the VHD your screen should look like the following then click Next. Verify the settings you made are correct. If not, you can go back and make any changes. When everything looks correct click Finish. Setup XP Mode Now, in VirtualBox, click start to run XP Mode. The Windows XP in this virtual drive is not fully setup yet, so you will have to go through the setup process.   If you didn’t uncheck the “Read-only” box in the VHD properties before, you may see the following error.  If you see it, go back and check the file to makes sure it is not read-only. When you click in the virtual machine, it will capture your mouse by default.  Simply press the right Ctrl key to release your mouse so you can go back to using Windows 7.  This will only be the case during the setup process; after the Guest Additions are installed, the mouse will seamlessly move between operating systems. Now, accept the license agreement in XP.   Choose your correct locale and keyboard settings. Enter a name for your virtual XP, and an administrative password. Check the date, time, and time zone settings, and adjust them if they are incorrect.  The time and date are usually correct, but the time zone often has to be corrected. XP will now automatically finish setting up your virtual machine, and then will automatically reboot. After rebooting, select your automatic update settings. You may see a prompt to check for drivers; simply press cancel, as all the drivers we need will be installed later with the Guest Additions. Your last settings will be finalized, and finally you will see your XP desktop in VirtualBox. Please note that XP Mode may not remain activated after importing it into VirtualBox. When you activate it, use the key that is located at C:\Program Files\Windows XP Mode\key.txt.  Note: During our tests we weren’t able to get the activation to go through. We are looking into the issue and will have a revised article showing the correct way to get XP Mode in VirutalBox working correctly soon.    Now we have one final thing to install – the VirtualBox Guest Additions.  In the VirtualBox window, click “Devices” and then select “Install Guest Additions”. This should automatically launch in XP; if it doesn’t, click Start, then My Computer, and finally double-click on the CD drive which should say VirtualBox Guest Additions. Simply install with the normal presets. You can select to install an experimental 3D graphics driver if you wish to try to run games in XP in VirtualBox; however, do note that this is not fully supported and is currently a test feature. You may see a prompt informing you that the drivers have not passed Logo testing; simply press “Continue Anyway” to proceed with the installation.   When installation has completed, you will be required to reboot your virtual machine. Now, you can move your mouse directly from Windows XP to Windows 7 without pressing Ctrl. Integrating with Windows 7 Once your virtual machine is rebooted, you can integrate it with your Windows 7 desktop.  In the VirtualBox window, click Machine and then select “Seamless Mode”.   In Seamless mode you’ll have the XP Start menu and taskbar sit on top of your Windows 7 Start and Taskbar. Here we see XP running on Virtual Box in Seamless Mode. We have the old XP WordPad sitting next to the new Windows 7 version of WordPad. Another view of everything running seamlessly together on the same Windows 7 desktop. Hover the pointer over the XP taskbar to pull up the Virtual Box menu items. You can exit out of Seamless Mode from the VirtualBox menu or using “Ctrl+L”. Then you go back to having it run separately on your desktop again. Conclusion Running XP Mode in a Virtual Machine is a great way to experience the feature on computers without Hardware Virtualization capabilities. If you prefer VMware Player, then you’ll want to check out our articles on how to run XP Mode on Windows 7 machines without Hardware Virtualization, and how to create an XP Mode for Windows 7 Home Premium and Vista. Download VirtualBox Download XP Mode Similar Articles Productive Geek Tips Install XP Mode with VirtualBox Using the VMLite PluginUsing Windows 7 or Vista Compatibility ModeMake Safari Stop Crashing Every 20 Seconds on Windows VistaForce Windows 7 / Vista to Boot Into Safe Mode Without Using the F8 KeyHow To Run Chrome OS in VirtualBox TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 PCmover Professional Enable Check Box Selection in Windows 7 OnlineOCR – Free OCR Service Betting on the Blind Side, a Vanity Fair article 30 Minimal Logo Designs that Say More with Less LEGO Digital Designer – Free Create a Personal Website Quickly using Flavors.me

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