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  • Get table row based on radio button using prototype/javascript

    - by David Buckley
    I have an html table that has a name and a radio button like so: <table id="cars"> <thead> <tr> <th>Car Name</th> <th></th> </tr> </thead> <tbody> <tr> <td class="car">Ford Focus</td> <td><input type="radio" id="selectedCar" name="selectedCar" value="8398"></td> </tr> <tr> <td class="car">Lincoln Navigator</td> <td><input type="radio" id="selectedCar" name="selectedCar" value="2994"></td> </tr> </tbody> </table> <input type="button" value="Select Car" onclick="selectCar()"></input> I want to be able to select a radio button, then click another button and get the value of the radio button (which is a unique ID) as well as the car name text (like Ford Focus). How should I code the selectCar method? I've tried a few things like: val1 = $('tr input[name=selectedCar]:checked').parent().find('#cars').html(); val1 = $("td input[name='selectedCar']:checked").parents().find('.cars').html(); val1 = $('selectedCar').checked; but I can't get the proper values. I'm using prototype, but the solution can be plain javascript as well.

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  • ASP.NET AsyncPostBackTrigger disables button's OnClick function???

    - by hahuang65
    I saw another post like this: http://stackoverflow.com/questions/1795621/asyncpostbacktrigger-disables-buttons But I don't really know what to make of it. The accepted answer was poorly typed. Basically, I have a button with an OnClick function. I also have a UpdatePanel, with is AsyncPostBackTrigger set to that same button. It seems that if I do this, my Button no longer does ANYTHING. I guess it's because I have a Page_Load() event... Can anyone explain why this is? And how should I set up my webpage if I can't use the Page_Load() function? Oh and if I put my Button in a UpdatePanel, it also won't do anything, probably because of the same reason. This is a section of my code: <asp:FileUpload id="FileUploadControl" runat="server" /> <asp:Button runat="server" id="UploadButton" text="Upload" OnClick="uploadClicked" /> <br /><br /> <asp:Label runat="server" id="StatusLabel" text="Upload status: " /> <br /> <asp:UpdatePanel ID="UpdatePanel2" runat="server" updatemode="Conditional" > <ContentTemplate> <asp:DropDownList ID="songList" runat="server" /> </ContentTemplate> <Triggers> <asp:AsyncPostBackTrigger ControlID="RefreshButton" /> </Triggers> </asp:UpdatePanel> Thanks in advance.

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  • How to get Facebook Login Button To Display "Logout"

    - by Will Merydith
    I apologize ahead of time if this is clearly documented somewhere on the FB developer site - but I can't find it (so please link me if appropriate). I've implemented the FB login button on a website using GAE + Python. Here is the HTML: <fb:login-button></fb:login-button> <div id="fb-root"></div> <script src="http://connect.facebook.net/en_US/all.js"></script> <script> FB.init({appId: 'ad16a806fc10bef5d30881322e73be68', status: true, cookie: true, xfbml: true}); FB.Event.subscribe('auth.sessionChange', function(response) { if (response.session) { // A user has logged in, and a new cookie has been saved } else { // The user has logged out, and the cookie has been cleared } }); </script> Currently the behavior is - if I click on the "login" button, I am asked to allow the application access to FB. Which I then choose, "OK". But then the login button is still showing "login" and not "logout". How do I implement that? On the server or client side?

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  • JqueryUI dialog box causes button to lose styling

    - by superexsl
    Hey everyone, I'm using JQueryUI dialog boxes and, while it works, it seems to remove any CSS styling on the button that opens the dialog. I have to manually refresh the page to get the styling back. An example button which launches the dialog: (button_submit is my CSS theme and launc_popup is used to detect the button click in JQuery. <asp:Button ID="btnLaunch" CssClass="button_sub launch_popup" runat="server" Text="Dialog..." CausesValidation="false" OnClientClick="return false;" /> My jquery: $('.launch_popup').click(function() { $("#dialog-form").dialog("open"); }); My dialog-form: $("#dialog-form").dialog({ autoOpen: false, height: 300, width: 300, modal: true, buttons: { 'Close': function() { $(this).dialog('close'); } } }); This happens to all the buttons that open dialogs. Is there a way to 'restyle' the button without refreshing the page? (It's in an updatepanel if that makes a difference, although this bit's client-side so not sure if that should affect it). Thanks for any help

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  • Facebook like button not going back side on the fixed div

    - by Lahiru Chathuranga
    I added a Facebook like button to my website.My website has a fixed div on top of the page(blue color div in the image). The like button is below that(in a div which can scroll) My problem is when the page is scroll down the like button comes on top of the fixed div(blue color).I want to scroll it from the backside of the div.How can I do that? There are couple of screenshots I added Before Scroll After Scroll Here is my code of the fixed div <script type="text/javascript"> function got_to_signup(){ window.location.href = "view/policy"; } </script> <div id="fb-root"></div> <script>(function(d, s, id) { var js, fjs = d.getElementsByTagName(s)[0]; if (d.getElementById(id)) return; js = d.createElement(s); js.id = id; js.src = "//connect.facebook.net/en_GB/all.js#xfbml=1&appId=368003049941951"; fjs.parentNode.insertBefore(js, fjs); }(document, 'script', 'facebook-jssdk'));</script> <div style="width:100%;background-color:#0094d6;" > <div id="dd" style="background-color:#0094d6; width:100%; height:75px;position:fixed; " class="center "><div id="a" style="width:1010px; height:75px; background-color:#000000;background:url(xx.png); background-repeat:no-repeat; font-family:Arial, Helvetica, sans-serif; font-size:11px; color:#003; " class="inner div_border"> <table width="1010" border="0" > <tr > <td width="15%" rowspan="2"><a href="" style="cursor:pointer; cursor:hand;"><div style="width:200px; height:50px;background-color:none;"></div></a></td> <td width="22%" height="14">&nbsp;</td> <td width="5%">&nbsp;</td> <td width="5%">&nbsp;</td> <td width="28%">&nbsp;</td> <td width="2%">&nbsp;</td> <td width="23%">&nbsp;</td> </tr> <tr> <td colspan="4"> </td> <td colspan="2"><span style="float: right; " ><div style="background-color:#006d9e;border-radius:3px; width:250px; height:34px; display: table; vertical-align: middle; color:#FFF; "> <table width="100%" border="0" > <tr > <td width="43%" style="text-align:center"> Start to bump !</td> <td width="29%"><div id='basic-modal'><span style="float: right; " ><input name="login_btn" type="button" class="login_button basic" id="login_btn" value="Sign in" /></span></div></td> <td width="28%"><span style="float: right; " ><form id="form_reg" method="post"><input name="register_btn" type="button" class="register_button" id="register_btn" value="Sign up" onclick="got_to_signup()"/></form></span></td> </tr> </table> </div></span></td> </tr> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td>&nbsp;</td> <td>&nbsp;</td> <td>&nbsp;</td> <td>&nbsp;</td> <td style="color:#FFF; font:Arial, Helvetica, sans-serif; font-size:9px; text-align:right;"> Beta Version </td> </tr> </table> </div></div></div> here is my facebook like button code </script> <div id="fb-root"></div> <script>(function(d, s, id) { var js, fjs = d.getElementsByTagName(s)[0]; if (d.getElementById(id)) return; js = d.createElement(s); js.id = id; js.src = "//connect.facebook.net/en_GB/all.js#xfbml=1&appId=368003049941951"; fjs.parentNode.insertBefore(js, fjs); }(document, 'script', 'facebook-jssdk'));</script> <td height="21" colspan="2"> <table width="187" style="margin-left:3px;font-size:1px;background-image:url(share_back.png);background-repeat:no-repeat;border-radius:3px;" > <!--tweeter button--> <tr><td width="71"><a href="https://twitter.com/bump_lk" class="twitter-follow-button" data-show-count="false" style="float:right;">Follow @bump_lk</a> <script>!function(d,s,id){var js,fjs=d.getElementsByTagName(s)[0];if(!d.getElementById(id)){js=d.createElement(s);js.id=id;js.src="//platform.twitter.com/widgets.js";fjs.parentNode.insertBefore(js,fjs);}}(document,"script","twitter-wjs");</script></td> <!--facebook like button--> <td width="48"><div class="fb-like" data-href="https://www.facebook.com/Bump.lk" data-send="false" data-layout="button_count" data-width="10" data-show-faces="false" style="position:relative;"></div> </td></tr></table></td> <td>&nbsp;</td> <td>&nbsp;</td> <td >

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  • C#: Drag & Drop with right mouse button

    - by stefan.at.wpf
    Hello, I'd like to do Drag & Drop with the right mouse button instead with the left one. However calling DragDrop.DoDragDrop() from MouseRightButtonDown instead of MouseLeftButtonDown doesn't do the job - DragDrop.DoDragDrop looks for mouse movements while holding down the left mouse button. Any idea how to realise Drag & Drop using the right mouse button? Thanks for any hint!

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  • open iphone google maps with back button

    - by christian
    Hi, i have a webview in my iphone app where a google map location is opened like; Directions now the google map native app opens fine, but how could i add a RETURN button so it would jump back to my html page. Now i have to click my home button and the app close back to the desktop, so i have to start my webview again. in android its more easy, because there is always a back button and after viewing my gmap i simply back in my webview. thx chris

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  • Browser back button broken between hidden div's

    - by Linda
    First of all, these pages will never be on the web but will be in internal memory. They are a group of linked documents---an ebook. http://www.anmldr.com/testdivs When I click on the link in the first div, the second div becomes visible and the first div is hidden. The problem is with the browser's back button. If you then click on the back button, the URL updates but the first div does not show again. How can I correct the back button so that the first div shows? The link from the second div to the first div works fine but it is the browser back button that I do not know how to work with. Thanks, Linda P.S. These are using CSS3 so it is better to use a WebKit based browser.

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  • Javascript button

    - by Deven
    hello friends i am developing button which generate another button and this button also calls function in which its id is passed as argument but i am getting error that id is undifined even i set its id attribute before it is added to ma web page

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  • How to disable html button using JavaScript?

    - by Jack Roscoe
    Hi, I've read that you can disable (make physically unclickable) a html button simply but appending 'disable' to its tag, but not as an attribute, as follows: <input type="button" name=myButton value="disable" disabled> Since this setting is not an attribute, how can I add this in dynamically via JavaScript to disable a button that was previously enabled?

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  • JQuery How to Uncheck A radio button

    - by user281867
    Hi, I have a list of data with a radio button. Users must select a date to edit. Then I load external dynamic form into a [div] using the jquery load() function. var ID = $('input[name=BookItem]:checked').val(); $("#EditFormWrapper").load("callEditData.cfm? ID="+ID); 2 Hours AM 2 Hours PM 2 Hours AM 2 Hours PM I am having trouble uncheck the radio button when user click on cancel button (editBTNcancel). The “BookItem” radio button is on the already on the webpage before the load() call. Here s my script: $("#editBTNcancel").live("click", function(event){ event.preventDefault(); $("#EditFormWrapper").slideUp("fast").empty(); //$('.TOR2Hours').removeAttr('checked'); $('.TOR2Hours').attr('checked', false); }); I hope I clearly state my problem, any suggestion would be greatly appreciated!

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  • Simple Binding question, unable to bind to button command in a DataTemplate using MVVM Light Toolkit

    - by deliberative assembly
    I've been attempting to bind to buttons within a DataTemplate without much success. The button does not fire. Button Click works successfully outside of the DataTemplate. Yet if I create a Click="button_click" the click button is fired. The Button Content binds perfectly as well. Example to illustrate.. Why does the command not fire? Advice on how this should be handled this? The example is a simplified version of my real problem, I am currently not using a Listbox. I only recreated the same problem with a listbox..

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  • Set focus to a button in a new TabItem

    - by Jan
    I use a TabControl to display a list of items. The ItemView is a separate control I wrote. <TabControl SelectedItem="{Binding CurrentItem}" IsSynchronizedWithCurrentItem="True" ItemsSource="{Binding ItemList}"> <TabControl.ContentTemplate> <DataTemplate> <ctrls:ItemView/> </DataTemplate> </TabControl.ContentTemplate> <TabControl.ItemTemplate> <DataTemplate> <TextBlock Text="{Binding ShortItemDescription}"/> </DataTemplate> </TabControl.ItemTemplate> </TabControl> If the user presses a Button a new ViewModel is added to the list of ViewModels and the TabControl displays it as a new tab. After adding the new tab is selected. <Button Command="{Binding AddItemCommand}" Content="Add item"/> Inside of the new ViewModel is a button that needs to be focused each time a new tab is added. I have tried to use the FocusManager and the Initialized event in the ItemView but these are only called for the first time I add a new tab. <UserControl x:Class="ItemView" ... Initialized="ViewInitialized"> <Grid> ... <!-- Set focus to this button --> <Button Content="Search" Command="{Binding SearchCommand}" Name="SearchButton" Grid.Column="0" Grid.Row="0"/> </Grid> </UserControl> Any ideas?

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  • immediate=true is set on a jsf command button but still seeing validation

    - by Zack Macomber
    I have the following command button set up in a facelet: <h:commandButton action="#{addressAction.deletePreviousAddress}" value="#{bundle['button.deleteAddress']}" styleClass="deg-form-button" immediate="true"> <f:setPropertyActionListener target="#{addressAction.addressActionForm.previousAddress}" value="#{address}"> </f:setPropertyActionListener> </h:commandButton> In AddressAction, the following code gets run to delete a previous address on the form: public Enum<NavigationConstants> deletePreviousAddress() { addressActionForm.getPreviousAddresses().remove(addressActionForm.getPreviousAddress()); return NavigationConstants.addresses; } Before I made the address input components "required=true", this code worked fine and removed the previous address from the jsf form successfully. Right now, I can't successfully delete a previous address because validation is occurring and stating that the input components need to be filled in on the previous address record on the form. How can I bypass this validation? I thought the "immediate=true" attribute on the command button would have accomplished it but that's not cutting it in my case...

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  • flex setting button width to text width

    - by pfunc
    I am creating a nav in flex that pulls in buttons dynamically from xml. THe problem i am having is setting the button width to the text width. currently the buttons are all the same width and if the text is larger then it just cuts off. I've tried a few ways of doing this: Setting button width to 100% On creation of the button try to set the width of the button to the text programmatically. Something like evt.target.width = evt.target.textWidth; Anyone know the correct way to do this?

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  • database change after pressing 'X' button

    - by Anup Prakash
    What i know:- We can use Ajax to change database from javascript. So whenever we press the 'X' button on title bar it calls "onbeforeunload" event. And by this event we can change the database. But in my case, i want to change the status of user only when user click on 'X' button. Not in case of changing the page. As because changing the page is unloading the page. and closing the page is also unloading the page(As much i know). Is there any way to differentiate between closing the page and moving from one page to other page? I want to use it for changing the status of user(i.e. login/logout), whenever he presses cross button. I don't want to set status "logout" when user changes the page. I want to set status "logout" when user 'X' the button. Plese help me.

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  • Java Appending a character to a textarea

    - by adam08
    I'm looking to appends a character to a textarea in. I have a simple GUI designed to look like like a mobile phone and I want to be able to click on one of the buttons and update the textarea with that character. If I click another button, I want to be able to append that character to the first. How do I do this? Obviously right now it is just setting the character for that button in the textarea and will be replaced when another button is clicked. public void actionPerformed(ActionEvent e) { String source = e.getActionCommand(); if (source.equals("1")) { TextArea.setText("1"); } else if (source.equals("2abc")) { TextArea.setText("a"); } else if (source.equals("3def")) { TextArea.setText("e"); } else if (source.equals("4ghi")) { TextArea.setText("i"); } else if (source.equals("5jkl")) { TextArea.setText("k"); } else if (source.equals("6mno")) { TextArea.setText("o"); } else if (source.equals("7pqrs")) { TextArea.setText("s"); } else if (source.equals("8tuv")) { TextArea.setText("t"); } else if (source.equals("9wxyz")) { TextArea.setText("x"); }

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  • Facebook Like Button for a Facebook video

    - by gridsquare
    Today, i created an iframe-Tab on our Facebook Page as a landingpage. On this tab we display a video, implemented from Facebook. Now i want to add the Facebook Like Button for this video on this page, i implement the code generated by the LIKE BUTTON Developer Page. <iframe src="https://www.facebook.com/plugins/like.php?href=https%3A%2F%2Fwww.facebook.com%2Fvideo%2Fvideo.php%3Fv%3D345848348745&amp;layout=button_count&amp;show_faces=true&amp;width=100&amp;action=like&amp;font=arial&amp;colorscheme=light&amp;height=21" scrolling="no" frameborder="0" style="border:none; overflow:hidden; width:120px; height:21px;" allowTransparency="true"></iframe> Now the button where displayed, but without a count. If i click on the like button the counter getting visible (displaying +1) and jumping back then (displaying no count). Do you know, if i can use the like button directly for the Facebook URL? http://www.facebook.com/video/video.php?v=345848348745 Thank u!

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