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  • Why won't my control accept keyboard input?

    - by Mason Wheeler
    I've built a custom control that I'm trying to send input to. It will accept mouse input and report MouseDown, MouseMove and MouseUp correctly, but for whatever reason, it won't accept keyboard input. When I click on it, it doesn't receive focus, and any keys I press get interpreted by whatever control had the focus already. This is probably something really simple. The first place I thought to look was in the ControlStyle property, but the only thing I can see in the helpfile about keyboard input is csNoStdEvents, which disables it, and my control doesn't have that. So what do I need to do to make it so my control can receive input focus?

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  • Image input onclick event being fired when enter button Pressed

    - by Anthony
    I have a strange problem where an onclick event on an input image is being fired when i hit enter in input text box <form id="MyForm" action="/someaction"> <input type="image" src="someimage.jpg" onclick="doStuff();$('#MyForm').submit();" /> <input type="text" name="textInput"/> </form> When the cursor is in the text box and i hit enter, rather than the form being submitted it calls the onclick event on the image input. Any ideas whats going on ?

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  • Jquery Change event for input and select elements

    - by Abs
    Hello all, I am trying to alert something when ever a drop down box changes and when ever something is typed into an input. I don't think I can use change for input fields? What would you use for input fields? Also, what about input fields of type file? Same thing. Here is what I have so far and its not working: $('input#wrapper, select#wrapper').change(function(){ alert('You changed.'); }); Thanks all

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  • "input cannot be resolved" when added a try..catch

    - by Mark
    I originally tried to get my throw statement to work without a try catch and the userInput = input.nextInt(); line worked fine. But when I tried adding the try..catch it didn't like my input saying it cannot be resolved. I don't think my try..catch is correct yet but I am planning on tackling that after I can get this input to be recognized but I would appreciate any feedback on things you see with that as well. Thanks import java.util.Scanner; public class Program6 { public static void main(String[] args) { final int NUMBER_HIGH_LIMIT = 100; final int NUMBER_LOW_LIMIT = 10; int userInput; try { System.out.print("Enter a number between 10 and 100: "); userInput = input.nextInt();//Says input cannot be resolved Verify v = new Verify(NUMBER_HIGH_LIMIT, NUMBER_LOW_LIMIT); } catch(NumberHighException exception) { userInput = 0; } catch(NumberLowException exception) { userInput = 0; } } }

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  • Count number of empty input boxes in table row

    - by Daniel Brink
    How do you calculate the number of input boxes with no value in a table row using jquery? example: <table id="table1"> <tr class="data" id="row5"> <td><input type="text" value="20%" /></td> <td><input type="text" value="10%" /></td> <td><input type="text" value="" /></td> <td><input type="text" /></td> </tr> <table> I'm looking for answer = 2

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  • Stop an input field in a form from being submitted

    - by Acorn
    I'm writing some javascript that will insert some input fields into a form on a website. The thing is, I don't want those input fields to affect the form in any way, I don't want them to be submitted when the form is submitted, I only want my javascript to have access to their values. Is there some way I could add some input fields into the middle of a form and not have them submitted when the form is submitted? Obviously the ideal thing would be for the input fields to not be in the form element, but I want the layout of my resulting page to have my inserted input fields appear between elements of the original form.

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  • Reporting sanitized user input to the user via AJAX

    - by JimBo
    I am writing some code to give live feedback to the user on the validation of a form using AJAX. I have got it checking length and if the field is empty. Now I want it to sanitize the users input and if the sanatized input differs from the users original input then tell them which characters are not allowed. The code I have written so far works except some characters most notably a '£' symbol result in no response. I think it relates to json_encode and its encoding. Here is the code: $user_input = 'asdfsfs£'; $strip_array = str_split(strip($user_input)); $orig_array = str_split($user_input); $diff_array = array_diff($orig_array,$strip_array); $diff_str = implode(', ',$diff_array); $final = json_encode($diff_str); function strip($input){return htmlentities(strip_tags($input),ENT_QUOTES);} Hope someone can figure out a solution.

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  • input tags with array

    - by Dumbledore of flash
    Hi , Recently i am doing a project in which i encountered a strange problem this is the program which previous programmer did MPAN <input name="mpan[]" id="mpan[]" value="" maxlength="2" size="2" > ///this one to read <input name="mpan[]" id="mpan[]" value="" maxlength="3" size="3"> <input name="mpan[]" id="mpan[]" value="" maxlength="3" size="3"> <input name="mpan[]" id="mpan[]" value="" maxlength="2" size="2"> ///this one to read <input name="mpan[]" id="mpan[]" value="" maxlength="11" size="12"> i have to read it from a javascript what i did 1) document.getElementById("mpan").value == not reading script does not work 2) document.getElementById("mpan[]").value == reading first one 3) document.getElementById("mpan[0]").value == script does not work 4) document.getElementById("mpan[3]").value == script does not work can any body tell me how to read this from a javascript program

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  • get the list and input from one function and run them in different function

    - by rookie
    i have a programm that generate the list and then i ask them to tell me what they want to do from the menu and this is where my problem start i was able to get the input form the user to different function but when i try to use the if else condition it doesn't check, below are my code def menu(x,l): print (x) if x == 1: return make_table(l) if x == 2: y= input("enter a row (as a number) or a column (as an uppercase letter") if y in [ "1",'2','3']: print("Minmum is:",minimum(y,l)) if x== 3: print ('bye') def main(): bad_filename = True l =[] while bad_filename == True: try: filename = input("Enter the filename: ") fp = open(filename, "r") for f_line in fp: f_str=f_line.strip() f_str=f_str.split(',') for unit_str in f_str: unit=float(unit_str) l.append(unit) bad_filename = False except IOError: print("Error: The file was not found: ", filename) #print(l) condition=True while condition==True: print('1- open\n','2- maximum') x=input("Enter the choice") menu(x,l) main() from the bottom function i can get list and i can get the user input and i can get the data and move it in second function but it wont work after that.thank you

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  • change value of input element!

    - by Lina
    is it able to "override/overwrite" an input element fixed value using javascript and/or jquery? i.e. if i have an input element like this: <div id="myDiv"> <input type="text" name="inputs" value="someValue" /> </div> is it possible to make a jquery object of that element and then change its value to something else then rewrite the jquery object to the dom?? i'm trying but obviously i haven't got good results! i've been trying something like this: $('input').val("someOtherDynamicValue"); var x = $('input'); $("#myDiv").html(x);

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  • PHP Form (post) Repeating input in a tabel

    - by Sef
    Hello, I have a form (with post method) that takes the following input: - a certain name - a number - 3 checkboxes All this input gets generated and calculated in a table.(html code within the php) Everything gets properly calculated and displayed in a table. So my question: How do i make it possible after giving all those input to give in more input? Meaning i have made a hyperlink that goes back to the form itself (where i can give the input). So i can give in new data, and after submiting that again the table now contains 2 rows of values insteed of just 1. Not really sure what exactly i need for this. Regards.

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  • jQuery validation: how to customize trigger and response

    - by user302307
    I am new with jQuery. I have a servlet based application which render an HTML form. This form is submitted via a function and the submit button IS NOT submit button in HTML. It's a regular button that calls a javascript function to do the submission. When running the submission function, the servlet also run a function called doCheck() which is in javascript. This doCheck() function can be defined per page basis. if doCheck returns false, then the servlet will stop the submission; else it will submit the form. I want to use jQuery validation to fit the servlet application. Is there a way to customize jQuery validation to be triggered manually (ie. only when doCheck() is executed) but at the same time provides continuous check on the UI (ie. if one type invalid number in date field, it will gives the appropriate msg when onblur event happen)? Is there a way to make jQuery validation return true or false? Thank you.

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  • Validation without ServiceLocator

    - by Dmitriy Nagirnyak
    Hi, I am getting back again and again to it thinking about the best way to perform validation on POCO objects that need access to some context (ISession in NH, IRepository for example). The only option I still can see is to use S*ervice Locator*, so my validation would look like: public User : ICanValidate { public User() {} // We need this constructor (so no context known) public virtual string Username { get; set; } public IEnumerable<ValidationError> Validate() { if (ServiceLocator.GetService<IUserRepository>().FindUserByUsername(Username) != null) yield return new ValidationError("Username", "User already exists.") } } I already use Inversion Of control and Dependency Injection and really don't like the ServiceLocator due to number of facts: Harder to maintain implicit dependencies. Harder to test the code. Potential threading issues. Explicit dependency only on the ServiceLocator. The code becomes harder to understand. Need to register the ServiceLocator interfaces during the testing. But on the other side, with plain POCO objects, I do not see any other way of performing the validation like above without ServiceLocator and only using IoC/DI. So the question would be: is there any way to use DI/IoC for the situation described above? Thanks, Dmitriy.

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  • Custom Validation Attribute with Custom Model Binder in MVC 2

    - by griegs
    I apologise for the amount of code I have included. I've tried to keep it to a minimum. I'm trying to have a Custom Validator Attribute on my model as well as a Custom Model binder. The Attribute and the Binder work great seperately but if I have both, then the Validation Attribute no longer works. Here is my code snipped for readability. If I leave out the code in global.asax the custom validation fires but not if I have the custom binder enabled. Validation Attribute; public class IsPhoneNumberAttribute : ValidationAttribute { public override bool IsValid(object value) { //do some checking on 'value' here return true; } } Useage of the attribute in my model; [Required(ErrorMessage = "Please provide a contact number")] [IsPhoneNumberAttribute(ErrorMessage = "Not a valid phone number")] public string Phone { get; set; } Custom Model Binder; public class CustomContactUsBinder : DefaultModelBinder { protected override void OnModelUpdated(ControllerContext controllerContext, ModelBindingContext bindingContext) { ContactFormViewModel contactFormViewModel = bindingContext.Model as ContactFormViewModel; if (!String.IsNullOrEmpty(contactFormViewModel.Phone)) if (contactFormViewModel.Phone.Length > 10) bindingContext.ModelState.AddModelError("Phone", "Phone is too long."); } } Global asax; System.Web.Mvc.ModelBinders.Binders[typeof(ContactFormViewModel)] = new CustomContactUsBinder();

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  • Django server side AJAX validation

    - by MMRUser
    Hi, Recently I'm trying to implement a simple Django application that include one server side AJAX validation, it's a simple form input field (username). I have used a pre-built in line AJAX validation library which uses jQuery. So the code goes like this HTML snippet <form id="simpleform" method="post" action="/done/"> Username:<input value="" class="validate[required,custom[noSpecialCaracters],length[0,20],ajax[ajaxUser]]" type="text" name="user" id="user" /> <input class="submit" type="submit" value="Validate"/> </form> The server side code snippet (embedded in to a php script) /* RECEIVE VALUE */ $validateValue=$_POST['validateValue']; $validateId=$_POST['validateId']; $validateError=$_POST['validateError']; /* RETURN VALUE */ $arrayToJs = array(); $arrayToJs[0] = $validateId; $arrayToJs[1] = $validateError; if($validateValue =="testname"){ // validate?? $arrayToJs[2] = "true"; // RETURN TRUE echo '{"jsonValidateReturn":'.json_encode($arrayToJs).'}'; // RETURN ARRAY WITH success }else{ for($x=0;$x<1000000;$x++){ if($x == 990000){ $arrayToJs[2] = "false"; echo '{"jsonValidateReturn":'.json_encode($arrayToJs).'}'; // RETURN ARRAY WITH ERROR } } } So my question is that how do I get this in to Python code (in order to use in Django environment) how do I get the user name from the input field in to the back end,I think the server side script snippet already does it but I want to know how to use this in my Pyhon code,and this is my first time using jQuery and I do need to use this same exact validation library. Your valuable corporation is needed. Thanks.

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  • jQuery Validation error...

    - by Povylas
    Hi, I have been struggling with this jQuery Validation Plugin. Here is the code: <script type="text/javascript"> $(function() { var validator = $('#signup').validate({ errorElement: 'span', rules: { username: { required: true, minlenght: 6 //remote: "check-username.php" }, password: { required: true, minlength: 5 }, confirm_password: { required: true, minlength: 5, equalTo: "#password" }, email: { required: true, email: true }, agree: "required" }, messages: { username: { required: "Please enter a username", minlength: "Your username must consist of at least 6 characters" //remote: "Somenoe have already chosen nick like this." }, password: { required: "Please provide a password", minlength: "Your password must be at least 5 characters long" }, confirm_password: { required: "Please provide a password", minlength: "Your password must be at least 5 characters long", equalTo: "Please enter the same password as above" }, email: "Please enter a valid email address", agree: "Please accept our policy" } }); var root = $("#wizard").scrollable({size: 1, clickable: false}); // some variables that we need var api = root.scrollable(); $("#data").click(function() { validator.form(); }); // validation logic is done inside the onBeforeSeek callback api.onBeforeSeek(function(event, i) { if($("#signup").valid() == false){ return false; }else{ return true; } $("#status li").removeClass("active").eq(i).addClass("active"); }); //if tab is pressed on the next button seek to next page root.find("button.next").keydown(function(e) { if (e.keyCode == 9) { // seeks to next tab by executing our validation routine api.next(); e.preventDefault(); } }); $('button.fin').click(function(){ parent.$.fn.fancybox.close() }); }); </script> And here is the error: $.validator.methods[method] is undefined http://www.vvv.vhost.lt/js/jquery-validate/jquery.validate.min.js Line 15 I am completely confused... Maybe some kind of handler is needed? I would be grateful for any kind of answer.

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  • Postback not working with ASP.NET Routing (Validation of viewstate MAC failed)

    - by Robert
    Hi. I'm using the ASP.NET 3.5 SP1 System.Web.Routing with classic WebForms, as described in http://chriscavanagh.wordpress.com/2008/04/25/systemwebrouting-with-webforms-sample/ All works fine, I have custom SEO urls and even the postback works. But there is a case where the postback always fails and I get a: Validation of viewstate MAC failed. If this application is hosted by a Web Farm or cluster, ensure that configuration specifies the same validationKey and validation algorithm. AutoGenerate cannot be used in a cluster. Here is the scenario to reproduce the error: Create a standard webform mypage.aspx with a button Create a Route that maps "a/b/{id}" to "~/mypage.aspx" When you execute the site, you can navigate http://localhost:XXXX/a/b/something the page works. But when you press the button you get the error. The error doen't happen when the Route is just "a/{id}". It seems to be related to the number of sub-paths in the url. If there are at least 2 sub-paths the viewstate validation fails. You get the error even with EnableViewStateMac="false". Any ideas? Is it a bug? Thanks

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  • Form submits but by passing the form validation when button.click is used

    - by Cuty Pie
    I am using form validation plugin as well as html5 attribute=recquired with input type=button or submit and fancybox.when button is clicked ,both validation proceedures work(notification of empty inputs appeare),but instead of this notification ,form is submitted. If I dont use button.click function but use simple submit.then validation works perfectly plugin==http://validatious.org/ javascript function $(document).ready(function() { $('#send').click(function() { $(this).attr("value", 'Applying...'); var id = getParam('ID'); $.ajax({ type:'POST', url:"send.php", data:{option:'catapply', tittle:$('#tittle').val(), aud:aud, con:con, adv:adv, mid:$('#mid').val(), aud2:aud, cid:$('#cid').val(), scid:$('#scname option[selected="saa"]').val(), gtt:$('input[name=gt]:radio:checked').val(), sr:$(":input").serialize() + '&aud=' + aud}, success:function(jd) { $('#' + id).fadeOut("fast", function() { $(this).before("<strong>Success! Your form has been submitted, thanks :)</strong>"); setTimeout("$.fancybox.close()", 1000); }); } }); }); }); AND Html is here <form id="form2" class="validate" style="display: none" > <input type='submit' value='Apply' id="send" class="sendaf validate_any" name="jobforming"/>

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  • jquery form validation, and submit-on-change

    - by Bee
    I want to make all my settings forms across my site confirm that changes are saved, kinda like facebook does if you make changes in a form and then try to navigate away without saving. So I'm disabling the submit button on the forms only enabling if the values change. I then prompt the user to hit save before they leave the page in the case that they do have changes pending. var form = $('form.edit'); if(form.length > 0) { var orig_str = form.serialize(); $(':submit',form).attr('disabled','disabled'); form.on('change keyup', function(){ if(form.serialize() == orig_str) { setConfirmUnload(false); $(':submit',form).attr('disabled','disabled'); } else { setConfirmUnload(true); $(':submit',form).removeAttr('disabled') } }); $('input[type=submit]').click(function(){ setConfirmUnload(false); }); } function setConfirmUnload(on) { window.onbeforeunload = (on) ? unloadMessage : null; } function unloadMessage() { return 'If you navigate away from this page without saving your changes, they will be lost.'; } One of these forms needs some additional validation which I do using jQuery.validate library. e.g. if i wanted to ensure the user can't double submit the form on accident by double clicking on submit or somesuch (the actual validation in question is for a credit-card form and not this simple): $('form').validate({ submitHandler: function(form) { $(':submit', form).attr('disabled','disabled'); form.submit(); } }); Unfortunately both bits are trying to bind to submit button and they're interfering with each other such that the submit button remains disabled no matter what I do and it is impossible to submit the form at all. Is there some way to chain the validations together or something? Or some other way to avoid re-writing the validation code to repeat the "did you change anything in the form" business?

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  • JQuery modal box form validation

    - by vikitor
    Hi, I was using a view to create an object for my specific project, but now I have to adapt this to another requirements, such as the creation of this object must be integrated in the creation of another one. The thing is, that this object must be created before starting to create the other one, and the way of doing it will be poping up a modal dialog box with JQuery with the form to create it. I've got to adapt the creation and it works fine, except for the validation messages. It is made in the controller like : if (not.NotName.Trim().Length == 0) { ModelState.AddModelError("NotName", "Name is required"); } if (_notification.checkIfExists(not.NotName, not.NotRecID)) { ModelState.AddModelError("NotName", "Notification already exists"); } And before with a normal view it worked fine, but now I'm not able to get the validation messages as I did. How can you get this validation messages thrown by the controller in the Modal Box? Because now when I made a mistake on purpose in the form in order to get the error it doesn't appear. I've seen the error is displayed in the site, because I've seen it on firebug, but it doesn't appear in my model box. How can I retrieve this errors? Do you know any tutorial that could help me with this? Thank you

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  • XForms and multiple inputs for same model tag

    - by iHeartGreek
    Hi! I apologize ahead of time if I am not asking this properly.. it is hard to put into words what I am asking.. I have XForms model such as: <file> <criteria> <criterion></criterion> </criteria> </file> I want to have multiple input text boxes that create a new criterion tag. user interface such as: <xf:input ref="/file/criteria/criterion" model="select_data"> <xf:label>Select</xf:label> </xf:input> <xf:input ref="/file/criteria/criterion" model="select_data"> <xf:label>Select</xf:label> </xf:input> <xf:input ref="/file/criteria/criterion" model="select_data"> <xf:label>Select</xf:label> </xf:input> And I would like the XML output to look like this (once user has entered in info): <file> <criteria> <criterion>AAA</criterion> <criterion>BBB</criterion> <criterion>CCC</criterion> </criteria> </file> The way I have it doesn't work, as it sees the 3 input fields to be referring all to the same criterion tag. How do I differentiate? Thanks! I hope that made some sense! BEGIN FIRST EDIT Thanks for the responses for the basic text box! However, I now need to do this with a listbox. But for the life of me, I can't figure out how. I read somewhere to use with the xforms:select and deselect events.. but I didn't know where to place them, and the places I tried gave me very weird behaviour. I am currently implementing the following: <xf:select ref="instance('criteria_data')/criteria/criterion" selection="" appearance="compact" > <xf:label>Choose criteria</xf:label> <xf:itemset nodeset="instance('criteria_choices')/choice"> <xf:label ref="@label"></xf:label> <xf:value ref="."></xf:value> </xf:itemset> </xf:select> However when multiple choices are submitted, all selection values are inserted into the same node, separated by spaces. For example: If AAA and BBB and FFF were selected from listbox, it would result in the following XML: <criterion>AAA BBB FFF</criterion> How do I change my code to have each selection be in a separate node? i.e. I want it to look like this: <criterion>AAA</criterion> <criterion>BBB</criterion> <criterion>FFF</criterion> Thanks! END FIRST EDIT BEGIN SECOND EDIT: For the listboxes (ie xf:select appearance="compact") I ended up allowing the spaces to occur in the same node and then just transformed that xml using xsl to generate a properly formatted new xml doc (with separate individual nodes). Unfortunately, I did not find a less cumbersome solution by inserting them originally into separate nodes. The selected answer works very well for text boxes however, hence why I selected it as the answer. END SECOND EDIT

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  • jQuery validation plugin: valid() does not work with remote validation ?

    - by a-dilla
    I got started by following this awesome tutorial, but wanted to do the validation on on keyup and place my errors somewhere else. The remote validation shows its own error message at the appropriate times, making me think I had it working. But if I ask specifically if a field with remote validation is valid, it says no, actually, its not. In application.js I have this... $("#new_user").validate({ rules: { "user[login]": {required: true, minlength: 3, remote: "/live_validations/check_login"}, }, messages: { "user[login]": {required: " ", minlength: " ", remote: " "}, } }); $("#user_login").keyup(function(){ if($(this).valid()){ $(this).siblings(".feedback").html("0"); }else{ $(this).siblings(".feedback").html("1"); } }) And then this in the rails app... def check_login @user = User.find_by_login(params[:user][:login]) respond_to do |format| format.json { render :json => @user ? "false" : "true" } end end I think that my problem might have everything to do with this ticket over at jQuery, and tried to implement that code, but, being new to jQuery, it's all a bit over my head. When I say bit, I mean way way. Any ideas to fix it, or a new way to look at it, would be a big help.

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  • Google Apps, SPF, softfail problem (validates with validation tools, but still softfails otherwise)

    - by mq.chen
    Hi, I guess this is probably a commonly asked and boring question but I'm really at a loss and I don't know what else to do. This might be a duplicate of other questions, but none of the solutions worked for me. I've Googled around and read just about anything I could find but I'm still puzzled as to why it doesn't work. The gist of my problem is that I have set-up Google Apps for a client of mine with the domain fintan.dk. Everthing works just excellent, except emails sent from *@fintan.dk (either with the Gmail web-interface or desktop client) to a non-Google Apps email gets a softfail (I have sent to my University email, an email hosted at MediaTemple and even Hotmail). The emails gets a pass when sent to a Google Apps or Gmail address though... (All emails from that domain are sent via email clients.) So this is what I have done so far: I've added the SPF record Google recommended (v=spf1 include:_spf.google.com ~all), waited several days hoping it would a DNS update delay problem. Now, three days later there is no change. I have verified the settings in the desktop clients several times. I have validated the records with validation tools like the SPF Query Tool, [email protected] and [email protected]. All of them validate and gives a pass, saying there shouldn't be a problem, but strangely there still is. So, I really don't know what else to do. Any help is very much appreciated. Thank you in advance!

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  • TGT validation fails, but only for one user

    - by wzzrd
    I'm seeing the weirdest thing here. I have a couple of RHEL3, 4 and 5 machines that validate user credentials through Kerberos with an Active Directoy domain controller as their KDC. This works for all of my users, save one. There is one account that is unable to log into RHEL3 Linux machines and generates the following errors there: May 31 13:53:19 mybox sshd(pam_unix)[7186]: authentication failure; logname= uid=0 euid=0 tty=ssh ruser= rhost=10.0.0.1 user=user May 31 13:53:20 mybox sshd[7186]: pam_krb5: TGT verification failed for `user' May 31 13:53:20 mybox sshd[7186]: pam_krb5: authentication fails for `user' Other accounts, like my own, are fine: May 31 17:25:30 mybox sshd(pam_unix)[12913]: authentication failure; logname= uid=0 euid=0 tty=ssh ruser= rhost=10.0.0.1 user=myuser May 31 17:25:31 mybox sshd[12913]: pam_krb5: TGT for myuser successfully verified May 31 17:25:31 mybox sshd[12913]: pam_krb5: authentication succeeds for `myuser' May 31 17:25:31 mybox sshd(pam_unix)[12915]: session opened for user myuser by (uid=0) As you can see, TGT validation fails. This only happens for this specific account, not for any other. The failing useraccount's password has been reset, I inspected both user objects in Active Directory, but I see nothing out of the ordinary. If I have the failing useraccount log into a RHEL4 or 5 box, there is not problem, so it must be RHEL3 specific, but the fact that only one account suffers from this, alludes me. Maybe someone has seen this before?

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  • Creating my own Stack

    - by Malaken
    I am creating my own stack for my data structures class. For our assignment we are using the assignment to convert a real-time infix equation into a postfix equation. I thought my program: took input determines if it was digit or number(operand) prints it out determines if input is operator (+,-,/,*) adds to stack or prints out, depending on stack precedence Instead it prints out the operands as expect, but I get this error when I enter an operator .../dorun.sh line 33: 4136 Segmentation fault sh "$" [code] #include using namespace std; class DishWell{ public: char ReturnEnd(){ return Well.back(); } void Push(char x){ Well.push_back(x); } void Pop(){ Well.pop_back(); } bool IsEmpty(){ return Well.empty(); } private: vector<char> Well; }; #include <iostream> bool Precidence(char Input, char Stack){ int InputPrecidence,StackPrecidence; switch (Input){ case '*': InputPrecidence = 4; break; case '/': InputPrecidence = 4; break; case '+': InputPrecidence = 3; break; case '-': InputPrecidence = 3; break; case '(': InputPrecidence = 2; break; default: InputPrecidence = 0; } switch (Stack){ case '*': StackPrecidence = 4; break; case '/': StackPrecidence = 4; break; case '+': StackPrecidence = 3; break; case '-': StackPrecidence = 3; break; case '(': StackPrecidence = 2; break; default: StackPrecidence = 0; } if(InputPrecidence>StackPrecidence) return true; else return false; } int main(int argc, char** argv) { DishWell DishTray; char Input; bool InputFlag; InputFlag = true; while(InputFlag){ cin>>Input; if((((Input>='a'&&Input<='z')||(Input>='A'&&Input<='Z'))|| (Input>='0'&&Input<='9')))//If Digit or Number cout<<Input; if((Input=='*'||Input=='/'||Input=='+'||Input=='-')){//if operand if(Precidence(Input,DishTray.ReturnEnd())) DishTray.Push(Input); else if(!Precidence(Input,DishTray.ReturnEnd())) cout<<Input; } else if(!((((Input>='a'&&Input<='z')||(Input>='A'&&Input<='Z'))|| (Input>='0'&&Input<='9')))||((Input=='*'||Input=='/'||Input=='+'||Input=='-')))//if not digit/numer or operand InputFlag = false; } while(!DishTray.IsEmpty()){ cout<<DishTray.ReturnEnd(); DishTray.Pop(); } return 0; [code] My code is very length, I know, but I appreciate help. Especially any times for efficency or future coding. Thanks again P.S. Dr. Zemoudeh, this is your student Macaire

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