How do I determine if a property was overriden?
- by Benjamin
Hello I am doing a project that where I need to register all the properties, because of the system being so huge it would require a lot of work to register all the properties that i want to be dependent for the purpose of Xaml.
The goal is to find all properties that are on the top of the tree.
so basically
public class A{
public int Property1 { get; set; }
}
public class B : A{
public int Property2 { get; set; }
public virtual int Property3 { get; set; }
}
public class C : B{
public override int Property3 { get; set; }
public int Property4 { get; set; }
public int Property5 { get; set; }
}
The end result would be something like this
A.Prorperty1
B.Property2
B.Property3
C.Property4
C.Property5
If you notice I don't want to accept overridden properties because of the way I search for the properties if I do something like this
C.Property3 for example and it cannot find it it will check C's basetype and there it will find it.
This is what I have so far.
public static void RegisterType( Type type )
{
PropertyInfo[] properties = type.GetProperties( BindingFlags.Public | BindingFlags.Instance | BindingFlags.DeclaredOnly | BindingFlags.GetProperty | BindingFlags.SetProperty );
if ( properties != null && properties.Length > 0 )
{
foreach ( PropertyInfo property in properties )
{
// if the property is an indexers then we ignore them
if ( property.Name == "Item" && property.GetIndexParameters().Length > 0 )
continue;
// We don't want Arrays or Generic Property Types
if ( (property.PropertyType.IsArray || property.PropertyType.IsGenericType) )
continue;
// Register Property
}
}
}
What I want are the following:
Public properties, that are not overridden, not static, not private
Either get and set properties are allowed
They are not an array or a generic type
They are the top of the tree ie C class in the example is the highest (The property list example is exactly what I am looking for)
They are not an indexer property ( this[index] )
Any help will be much appreciated =).
