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  • Django User M2M relationship

    - by Antonio
    When trying to syncdb with the following models: class Contact(models.Model): user_from = models.ForeignKey(User,related_name='from_user') user_to = models.ForeignKey(User, related_name='to_user') class Meta: unique_together = (('user_from', 'user_to'),) User.add_to_class('following', models.ManyToManyField('self', through=Contact, related_name='followers', symmetrical=False)) I get the following error: Error: One or more models did not validate: auth.user: Accessor for m2m field 'following' clashes with related m2m field 'User.followers'. Add a related_name argument to the definition for 'following'. auth.user: Reverse query name for m2m field 'following' clashes with related m2m field 'User.followers'. Add a related_name argument to the definition for 'following'. auth.user: The model User has two manually-defined m2m relations through the model Contact, which is not permitted. Please consider using an extra field on your intermediary model instead. auth.user: Accessor for m2m field 'following' clashes with related m2m field 'User.followers'. Add a related_name argument to the definition for 'following'. auth.user: Reverse query name for m2m field 'following' clashes with related m2m field 'User.followers'. Add a related_name argument to the definition for 'following'.

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  • How to change a Linux user password from python

    - by Vaulor
    I'm having problems with changing a Linux user's password from python. I've tried so many things, but I couldn't manage to solve the issue, here is the sample of things I've already tried: sudo_password is the password for sudo, sudo_command is the command I want the system to run, user is get from a List and is the user who I want to change the password for, and newpass is the pass I want to assign to 'user' user = list.get(ANCHOR) sudo_command = 'passwd' f = open("passwordusu.tmp", "w") f.write("%s\n%s" % (newpass, newpass)) f.close() A=os.system('echo -e %s|sudo -S %s < %s %s' % (sudo_password, sudo_command,'passwordusu.tmp', user)) print A windowpass.destroy() 'A' is the return value for the execution of os.system, in this case 256. I tried also A=os.system('echo %s|sudo -S %s < %s %s' % (sudo_password, sudo_command,'passwordusu.tmp', user)) but it returns the same error code. I tried several other ways with 'passwd' command, but whithout succes. With 'chpasswd' command I 've tried this: user = list.get(ANCHOR) sudo_command = 'chpasswd' f = open("passwordusu.tmp", "w") f.write("%s:%s" % (user, newpass)) f.close() A=os.system('echo %s|sudo -S %s < %s %s' % (sudo_password, sudo_command,'passwordusu.tmp', user)) print A windowpass.destroy() also with: A=os.system('echo %s|sudo -S %s:%s|%s' % (sudo_password, user, newpass, sudo_command)) @;which returns 32512 A=os.system("echo %s | sudo -S %s < \"%s\"" % (sudo_password, sudo_command, "passwordusu.tmp")) @;which returns 256 I tried 'mkpasswd' and 'usermod' too like this: user = list.get(ANCHOR) sudo_command = 'mkpasswd -m sha-512' os.system("echo %s | sudo -S %s %s > passwd.tmp" % (sudo_password,sudo_command, newpass)) sudo_command="usermod -p" f = open('passwd.tmp', 'r') for line in f.readlines(): newpassencryp=line f.close() A=os.system("echo %s | sudo -S %s %s %s" % (sudo_password, sudo_command, newpassencryp, user)) @;which returns 32512 but, if you go to https://www.mkpasswd.net , hash the 'newpass' and substitute for 'newpassencryp', it returns 0 which theoretically means it has gone right, but so far it doesn't changes the password. I've searched on internet and stackoverflow for this issue or similar and tried what solutions exposed, but again,without success. I would really apreciate any help, and of course, if you need more info i'll be glad to supply it! Thanks in advance.

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  • apache sendmail: trying to change user "from" address from apache to domain account

    - by Wes
    I apologize if I am asking a question already answered, but my problem isn't really that I haven't found an answer. I have, in fact, found a half-dozen different "solutions" to my problem, tried them all, in various combinations, and have been consistently unsuccessful. The goal All I want to do is change the envelope "from" address for all email sent from [email protected] to [email protected], always. What I've already done I am running Apache, PHP, and sendmail on CentOS 5.5, [email protected]. We have an SMTP server at 192.168.0.4. The domain's email accounts are all at @domain.org. I have successfully set up "smart host" using this line in the sendmail.mc file: define(`SMART_HOST', `192.168.0.4')dnl Then I set up masquerading, and was hopeful this would solve it. I have this in the .mc file: FEATURE(`masquerade_entire_domain')dnl FEATURE(`masquerade_envelope')dnl FEATURE(`allmasquerade')dnl MASQUERADE_AS(`domain.org')dnl MASQUERADE_DOMAIN(`domain.org.')dnl MASQUERADE_DOMAIN(`localhost.localdomain.')dnl This rewrites "to" addresses, but not "from" addresses. Testing from the command line: sendmail -v [email protected] Always is shown from the local user (in this case root, or my local user account). I had read that "sendmail" command sometimes bypasses masquerading. Nevertheless, using the "mail" command has the same result. After that, I have explored several "solutions", including: mailertable virtusertable FEATURE(`accept_unresolvable_domains')dnl LOCAL_DOMAIN(`localhost.localdomain')dnl FEATURE(`genericstable')dnl /etc/mail/access file /etc/mail/local-host-names file /etc/mail/trusted-users file All to no affect. The last thing I've tried So, I decided to go in a different direction, and try to set the envelope "from" address via PHP, using either the configuration in /etc/php.ini, or adding the -f parameter to the mail() function or to sendmail command. If I run this command: sendmail -v -f [email protected] [email protected] I get this error in /var/log/maillog: Mar 30 08:56:16 localhost sendmail[24022]: p2UCuE8w024022: [email protected], size=5, class=0, nrcpts=1, msgid=<[email protected]>, relay=user@localhost Mar 30 08:56:19 localhost sendmail[24022]: p2UCuE8w024022: [email protected], [email protected] (500/502), delay=00:00:05, xdelay=00:00:03, mailer=relay, pri=30005, relay=[192.168.0.4] [192.168.0.4], dsn=5.1.1, stat=User unknown Mar 30 08:56:19 localhost sendmail[24022]: p2UCuE8w024022: p2UCuE8x024022: DSN: User unknown Mar 30 08:56:23 localhost sendmail[24022]: p2UCuE8x024022: [email protected], delay=00:00:04, xdelay=00:00:04, mailer=relay, pri=31029, relay=[192.168.0.4] [192.168.0.4], dsn=2.0.0, stat=Sent (Ok: queued as B5E2E40E0A2) Which is basically a "User unknown" 550 error. Help Please help. What do I need to change? Should I just start over in the sendmail.mc file? It has a ton of config options stuffed in it, over days of trying things. Why is changing the envelope "from" address via the command line generating a "User unknown" error?

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  • How to get Alfresco login ticket without user password, but with impersonating user with user principal name (UPN)

    - by dok
    I'm writing a DLL that has function for getting Alfresco login ticket without using user password, using only a user principal name (UPN). I’m calling alfresco REST API service /wcservice. I use NTLM in Alfresco. I’m impersonating users using WindowsIdentity constructor as explained here http://msdn.microsoft.com/en-us/library/ms998351.aspx#paght000023_impersonatingbyusingwindowsidentity. I checked and user is properly impersonated (I checked WindowsIdentity.GetCurrent().Name property). After impersonating a user, I try to make HttpWebRequest and set its credentials with CredentialsCache.DefaultNetworkCredentials. I get the error: The remote server returned an error: (401) Unauthorized. at System.Net.HttpWebRequest.GetResponse() When I use new NetworkCredential("username", "P@ssw0rd") to set request credentials, I get Alfresco login ticket (HttpStatusCode.OK, 200). Is there any way that I can get Alfresco login ticket without user password? Here is the code that I'm using: private string GetTicket(string UPN) { WindowsIdentity identity = new WindowsIdentity(UPN); WindowsImpersonationContext context = null; try { context = identity.Impersonate(); MakeWebRequest(); } catch (Exception e) { return e.Message + Environment.NewLine + e.StackTrace; } finally { if (context != null) { context.Undo(); } } } private string MakeWebRequest() { string URI = "http://alfrescoserver/alfresco/wcservice/mg/util/login"; HttpWebRequest request = WebRequest.Create(URI) as HttpWebRequest; request.CookieContainer = new CookieContainer(1); //request.Credentials = new NetworkCredential("username", "p@ssw0rd"); // It works with this request.Credentials = CredentialCache.DefaultNetworkCredentials; // It doesn’t work with this //request.Credentials = CredentialCache.DefaultCredentials; // It doesn’t work with this either try { using (HttpWebResponse response = request.GetResponse() as HttpWebResponse) { StreamReader sr = new StreamReader(response.GetResponseStream()); return sr.ReadToEnd(); } } catch (Exception e) { return (e.Message + Environment.NewLine + e.StackTrace); } } Here are records from Alfresco stdout.log (if it helps in any way): 17:18:04,550 DEBUG [app.servlet.NTLMAuthenticationFilter] Processing request: /alfresco/wcservice/mg/util/login SID:7453F7BD4FD2E6A61AD40A31A37733A5 17:18:04,550 DEBUG [web.scripts.DeclarativeRegistry] Web Script index lookup for uri /mg/util/login took 0.526239ms 17:18:04,550 DEBUG [app.servlet.NTLMAuthenticationFilter] New NTLM auth request from 10.**.**.** (10.**.**.**:1229) 17:18:04,566 DEBUG [app.servlet.NTLMAuthenticationFilter] Processing request: /alfresco/wcservice/mg/util/login SID:7453F7BD4FD2E6A61AD40A31A37733A5 17:18:04,566 DEBUG [web.scripts.DeclarativeRegistry] Web Script index lookup for uri /mg/util/login took 0.400909ms 17:18:04,566 DEBUG [app.servlet.NTLMAuthenticationFilter] Received type1 [Type1:0xe20882b7,Domain:<NotSet>,Wks:<NotSet>] 17:18:04,566 DEBUG [app.servlet.NTLMAuthenticationFilter] Client domain null 17:18:04,675 DEBUG [app.servlet.NTLMAuthenticationFilter] Sending NTLM type2 to client - [Type2:0x80000283,Target:AlfrescoServerA,Ch:197e2631cc3f9e0a]

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  • Security Tips for super user in Ubuntu 11.10?

    - by Gaurav_Java
    Ubuntu is a relatively safe but this should not prevent you to be vigilant. I'm working on securing Ubuntu 11.10 and was looking for every tip to secure my Ubuntu 11.10 and upcoming version 12.04. I go through this question . But my Question is Begin as Super User and as Normal user also. Which is Best tools which I can use for preventing my data? What Services and features I Enable Manually after installing ubuntu ? What security measure I should take? What i don't do ? What are other precaution some takes as super user? what are Normal security stay patched in ubuntu? and if i am missing something then please add them

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  • T-SQL User-Defined Functions: the good, the bad, and the ugly (part 1)

    - by Hugo Kornelis
    So you thought that encapsulating code in user-defined functions for easy reuse is a good idea? Think again! SQL Server supports three types of user-defined functions. Only one of them qualifies as good. The other two – well, the title says it all, doesn’t it? The bad: scalar functions A scalar user-defined function (UDF) is very much like a stored procedure, except that it always returns a single value of a predefined data type – and because of that property, it isn’t invoked with an EXECUTE statement,...(read more)

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  • Default file permissions for php user www-data

    - by John Isaacks
    I have a php installed on my ubuntu machine. The web root is /var/www I set the permissions for this folder like so: sudo chown -R ftpuser:www-data /var/www ftpuser is the user I set up so I can ftp to /var/www from another machine on the network. www-data is the user php uses. I double checked using whoami from php. Whenever I ftp upload a new file to the machine the group has no permissions to the file. So when I try to access it in my browser via machine-name/new-file.php I am told permission denied and I have to go and chmod the new file. I am wondering if there is a way I can default the www-data user/group to have access permissions to new files so I don't have to keep chmod every new file?

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  • Problem with gnome-shell-extensions-user-theme

    - by sodiumnitrate
    I'm trying to install themes with gnome tweak, and I need to install gnome-shell-extensions-user-theme because otherwise I cannot see the shell extensions tab. However, I cannot install shell extensions. I have tried to install by adding the PPA with the following: sudo add-apt-repository ppa:webupd8team/gnome3 Then, sudo apt-get update Finally, when I try to install: sudo apt-get install gnome-shell-extensions-user-theme It gives an error: The following packages have unmet dependencies: gnome-shell-extensions-user-theme : Depends: gnome-shell-extensions-common but it is not going to be installed E: Unable to correct problems, you have held broken packages. I am convinced that there is a problem with the package. So I went on and tried to install the extensions from the website: https://extensions.gnome.org/ But even though I use Firefox (15.0), I cannot see the "switch" that is being mentioned to install the extension. Maybe the version of Firefox is too new. Is there any workaround that you know of? (By the way, I use Ubuntu 12.04, freshly downloaded and installed.)

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  • T-SQL User-Defined Functions: the good, the bad, and the ugly (part 1)

    - by Hugo Kornelis
    So you thought that encapsulating code in user-defined functions for easy reuse is a good idea? Think again! SQL Server supports three types of user-defined functions. Only one of them qualifies as good. The other two – well, the title says it all, doesn’t it? The bad: scalar functions A scalar user-defined function (UDF) is very much like a stored procedure, except that it always returns a single value of a predefined data type – and because of that property, it isn’t invoked with an EXECUTE statement,...(read more)

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  • Using Validation Groups Inside ASP.NET User Controls

    - by bipinjoshi
    Validation groups allow you to validate data entry controls in groups. Server controls such as validation controls, Button and TextBox have ValidationGroup property that takes a string value. All the server controls having the same ValidationGroup value act as one validation group. Validation groups come handy in situations where you wish to validate only a small set of controls from many controls housed on a Web Form. Using validation groups is quite easy and straightforward. However, if you have a validation group inside a user control and there are more than one user control instances on a Web Form you face some problem.http://www.binaryintellect.net/articles/13427d3d-1f98-4dc0-849b-72e95b8b66a2.aspx 

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  • Operation not permitted for chown : For a domain user directory

    - by Lunar Mushrooms
    I am trying to change ownership of a domain user home directory, which is mounted over nfs. Current user/group for that folder is nobody/nogroup. The following chown command is issued from "root" user shell. But I am getting permission error. How to resolve this ? sudo chown -Rv VANILLA\\userone:VANILLA\\domain^users /lhome/VANILLA/userone chown: changing ownership of `/lhome/VANILLA/userone': Operation not permitted failed to change ownership of `/lhome/VANILLA/userone' from nobody:nogroup to VANILLA\userone:VANILLA\domain^users My OS is Ubuntu LTS 12.04 32 bit.

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  • Product Support Webcast for Existing Customers: Oracle Webcenter Portal 11g User & Administration Tips

    - by John Klinke
    Register for our upcoming Advisor Webcast 'Oracle WebCenter Portal 11g: User & Administration Tips' scheduled for November 12, 2013 at 11:00 am, Eastern Standard Time (8:00 am Pacific Standard Time, 4:00 pm GMT Time, 5:00 pm Europe Time). This 1-hour session is recommended for technical and functional users who use Oracle WebCenter Portal to build company portals using run-time tools.Topics will include:• Whats new in 11.1.1.8 of WebCenter Portal• Terminology Changes• Using the Portal once its built• Setting up Self Registration (Admins)• End User Experience• Development Environment• Patching InformationFor more information and to register for this Advisor Webcast, please see Oracle WebCenter Portal 11g: User & Administration Tips (Doc ID 1585902.1).

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  • User prompts (MessageBox) with MVVM

    - by mukapu
    The problem statement: I am tired of thinking how to show a simple message box or user prompt and act based on the response in Model-View-View-Model (MVVM). Common approaches: - It's ok, let's just do this one thing from ViewModel and mock this out for unit testing - Design my own dialog, then what to do from there - Can I write something in view code behind, ah yes, that seems to be the only way out, as anyway MVVM is still not matured...  - and what not?   I am pretty much one among the few frustrated out in this world looking for some convincing answers. I think we can do it a little neater without having the feeling of violating any of our self defined rules! Solution: The Control - Implement a simple control with no designer visibility. - Allow a property to be bound to tell when to show the MessageBox - Provide command binding for possible user actions, Yes, No, Cancel... How do I Use? - Just place the necessary XAML tags in the view - Implement the command for all user actions in the View Model - Run unit tests on the commands

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  • Entity Framework: Connecting to a mdf user database file via localDB during script execution

    - by Marko Apfel
    Problem If you run the “Generate database from model” wizard and execute the generated script the destination database could be the wrong one (for instance master of the SQL Server). Solution To use an own mdf attachable user database some connection information must specified during script execution. Execute your script opens the dialog “Connect to Server”. Press “Options” and go to the second tab “Connection Properties”. Select “Browse server” in the “Connect to database” dropdown box: Confirm the information dialog with “Yes”. In the following dialog you could choose your user database. Now the schema is created in the user database.

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  • I have lost sudo privileges in Ubuntu 13.04 [duplicate]

    - by Fredca
    This question already has an answer here: How do I add myself back as a sudo user? 3 answers I have lost sudo privileges in Ubuntu 13.04 these are the responses I get user@user-desktop:~$ sudo sudo: effective uid is not 0, is sudo installed setuid root? user@user-desktop:~$ groups user user : user adm cdrom sudo dip plugdev lpadmin sambashare user@user-desktop:~$ su user Password: su: Authentication failure user@user-desktop:~$ who am i user pts/0 2013-10-24 08:54 (:0.0) user@user-desktop:~$ why can't I invoke sudo if one of my groups is sudo? also I have noticed that /etc/sudoers needs sudo privileges. sudoers.so doesn't exist in /usr/lib but does in /usr/lib/sudo is this correct in 13.04? Please note that the user is already a member of both sudo and adm groups.

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  • Locate a user's bashrc file

    - by Starkers
    Really confused. Upon running cat etc/passwd I have found this: postgres:x:117:126:PostgreSQL administrator,,,:/var/lib/postgresql:/bin/bash meaning I have a postgres user, right? I want to change the bashrc environment file of this user to make commands available to it. /var/lib/postgresql doesn't contain a bashrc file, and /bin/bash doesn't contain it either, so I don't really know what's going on. All I know is a created postgres using the useradd command, so why do I have some weird user with no home directory? So confused :(

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  • How can I make WSUS less invasive for our users?

    - by Cypher
    We have WSUS pushing updates out to our user's workstations, and things are going relatively well with one annoying caveat: there seems to be an issue with a pop-up being displayed in front of some users informing them that their machine will be rebooted in 15 minutes, and they have nothing to say about it: This may be because they did not log out the prior night. Nevertheless, this is a bit too much and is very counter-productive for our users. Here is a bit about our environment: Our users are running Windows XP Pro and are part of an Active Directory Domain. WSUS is being applied via Group Policy. Here is a snapshot of the GPO that is enforcing the WSUS rules: Here is how I want WSUS to work (ideally - I'll take whatever can get me close): I want updates to automatically download and install every night. If a user is not logged in, I would like the machine to reboot. If a user is logged in, I would like their machine not to reboot, but instead wait until the next "installation period" where it can perform any other needed installations and reboot then (provided the a user account is not still logged in). If a user is to be prompted for reboot, it should only happen once per day (if possible), but every time they are prompted, they must have a way to postpone the reboot. I do not want users to be forced to restart their computer whenever the computer thinks it should happen (unless it's after an update installation and there are no logged in users). That doesn't seem productive to force a system restart in the midst of a person's workday. Is there something that I can do with the GPO that would help make WSUS less intrusive? Even if it gave the user an option to Restart Later - that would be better than what is happening now.

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  • Run Java application as a different user [on hold]

    - by Harihar Das
    I need to run a few perl scripts from a Java GUI application. I am using Runtime API to do that. However, few of the perl scripts need to run under a specific user account to have special credentials to access specialized resources (e.g. Database, Files). I have heard of alleviating user access using UAC. But till now I am not able to find the solution. Please help me on how to run a process under a different user login. Is there anything similar to c# impersonization in Java?

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  • Remembering user credentials in standalone Application

    - by srk
    I'm developing a standalone application using java, I have a Login screen, wherein user enters his username and password. For each instance of the application, user have to enter his credentials. From a usability standpoint, I thought of keeping a remember me check Button. My question is, as I am not using any database, how do I persist the user details. I have some rough thoughts, storing them in a property file and retrieving. I think there may be better approaches than the one I had. Any Ideas and suggestions?

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  • GPO - Setting not applied, although policy is applied

    - by Kenny Bones
    This is rather strange. In our domain we have several terminal servers and this morning a user reported that no drives are mapped when he logs on to the terminal server. So, I checked Group Policy Results and compare two users. Both users have the exact same policies applied. But for this particular user, the Script section under User Configuration - Policies - Windows Settings is just not there. For the other user, which this is working fine for, it says under the Script section that Winning GPO is Terminal2008, which is the GPO that contains the script section. And the Terminal2008 GPO is applied to both users. Also, the loopback processing is set to Replace. What could be the cause for this? I've never seen this particular issue before. I mean, both users are in the same OU, they log on to the same terminal server and the same policies are applied to both. They do not however have the exact same group memberships, but should that matter? It's not stated that the script should be run only if the user is a member of a certain group either. Not sure if that could be done through that specific setting either.All I know is, the very same policies are applied to both users, in the same OU and the same computer. Meaning, the same policies should be applied? Edit: I just ran Group Policy Results on one of the other terminal servers, which are also in the same OU, and the Scripts section is there! This means that this particular user don't get this setting when he's logged onto this particular server. What could be the cause of this?

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  • How to redirect user into mobile website?

    - by iLa
    Hi how to redirect the user into mobile site when the user accessing from mobile. Say example i have site called www.mysite.com. Now, a person accessing a website from mobile it should redirect to www.mysite.com/mobile or www.m.mysite.com. I put some research in google that we can redirect using javascript to get the user agent(browser) if(mobile browser) { //redirect to www.mysite.com/mobile } else if(normal browser) { //redirect to www.mysite.com } or using screen resolution if(screen resolution < 800 ) { //redirect to www.mysite.com/mobile } else if(screen resolution > 800) { //redirect to www.mysite.com } I think It will not work If it is the case of javascript disable. Can we do this using .htaccess or php stuff? Is there any standard mechanism to do this?

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  • Creating a user called 'root'

    - by pnp
    I am creating Virtual Machines using the ubuntu-vm-builder. The syntax goes something like this: ubuntu-vm-builder kvm precise \ --domain newvm \ --dest newvm \ --arch i386 \ --hostname hostnameformyvm \ --mem 256 \ --user john \ --pass doe \ --ip 192.168.0.12 \ --mask 255.255.255.0 \ --net 192.168.0.0 \ --bcast 192.168.0.255 \ --gw 192.168.0.1 \ --dns 192.168.0.1 \ --mirror http://archive.localubuntumirror.net/ubuntu \ --components main,universe \ --addpkg acpid \ --addpkg vim \ --addpkg openssh-server \ --addpkg avahi-daemon \ --libvirt qemu:///system ; I need to enable the 'root' user account after creating each of my VMs (and supply a password for it). I was just wondering whether I can take this short-cut of supplying the username (--user) as root in this command itself. If I supply username as root to create my VMs, am I creating/enabling the root user, or just creating a user named as root? p.s.: any better ways to achieve my task are also welcome. But I don't want to manually meddle with each VM after its creation

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  • Who created that user?

    - by AaronBertrand
    Twitter has provided some great fodder for blog content lately. And twice this week, I've found an excuse to take advantage of the default trace. Tonight @meltondba asked: I'm trying to find who created a user act in a DB It is true, SQL Server doesn't really keep track of who created objects, such as user accounts in a database. You can get some of this information from the default trace, though, since it tracks EventClass 109 (Audit Add DB User). If you run this code: USE [master] ; GO CREATE LOGIN...(read more)

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  • Identifying connected lines drawn free-hand by a user

    - by rawrgoesthelion
    I have a series of 'images' described by a mixture of connected lines and curves. Users will draw on the screen, free hand, and my goal is to break their drawing down into a series of lines and curves that can be matched with the 'images' in my set. For the sake of simplicity, let's assume this is occurring on a touch screen. These lines will be connected. Each time the user's finger moves, the dx and dy is recorded. The drawing is considered complete and analyzed when the user's finger leaves the screen. I'm having trouble figuring out a good way to break the user's drawing down into lines. Is there any well known approach to this problem, a C++ library that solves it, or any good articles/technical papers on how to achieve this?

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  • Oracle Endeca User Interface Design Pattern Library Available

    - by ultan o'broin
    Yes! The Oracle Endeca User Interface Design Pattern Library is now available for all fans of great UI design solutions for search, discovery, and navigation! The patterns explain and show some great UI realizations and include consumer world examples we can relate to. Thanks to the Oracle Endeca team and Applications UX who worked closely together to bring this great user experience resource back out to customers and partners who want to build cutting edge apps, sites, and integrations. Some great insights into how these UI design patterns can bring magical information discovery and more to users, as well as what makes Endeca people tick, are available from the Usable Apps blog Oracle Endeca User Experience: From Putting the E in E-Commerce to Magical Information Discovery.

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