Search Results

Search found 15563 results on 623 pages for 'django model'.

Page 66/623 | < Previous Page | 62 63 64 65 66 67 68 69 70 71 72 73  | Next Page >

  • Rails after_create callback can't access model's attributes

    - by tybro0103
    I can't access my model's attributes in the after_create callback... seems like I should be able to right? controller: @dog = Dog.new(:color => 'brown', :gender => 'male') @dog.user_id = current_user.id @dog.save model: class Dog < ActiveRecord::Base def after_create logger.debug "[DOG CREATED] color:#{color} gender:#{gender} user:#{user_id}" end end console: (all seems well) >>Dog.last =>#<Dog id: 1, color: "brown", gender: "male", user_id: 1> log: (wtf!?) ... [DOG CREATED] color: gender:male user ... Some of my attributes show up and others don't! oh no! Anyone know what I'm doing wrong? I've always been able to user after_create in such ways in the past. Note: The actual variable names and values I used were different, but the methods and code are the same.

    Read the article

  • Django save, column specified twice

    - by realshadow
    Hey, I would like to save a modified model, but I get Programming error - that a field is specified twice. class ProductInfo(models.Model): product_info_id = models.AutoField(primary_key=True) language_id = models.IntegerField() product_id = models.IntegerField() description = models.TextField(blank=True) status = models.IntegerField() model = models.CharField(max_length=255, blank=True) label = models.ForeignKey(Category_info, verbose_name = 'Category_info', db_column = 'language_id', to_field = 'node_id', null = True) I get this error because the foreign key uses as db_column language_id. If I will delete it, my object will be saved properly. I dont quite understand whats going on and since I have defined almost all of my models this way, I fear its totally wrong or maybe I just missunderstood it... Any ideas? Regards

    Read the article

  • Problems using an id from a model inside a custom sql query in Rails

    - by Thiago
    Hi there, I want to do a model class which associates to itself on Rails. Basically, a user has friends, which are also users. I typed the following inside a User model class: has_many :friends, :class_name => "User", :foreign_key => :user_id, :finder_sql => %{SELECT users.* FROM users INNER JOIN friends ON (users.id = friends.user_id OR users.id = friends.friend_id) WHERE users.id <> #{id}} But the funny fact is that it seems that this finder_sql is called twice whenever I type User.first.friends on irb. Why?

    Read the article

  • HowTo init Django model, before using it?

    - by mosg
    Hi. I'm new to python and django. Apps | Versions: Python 2.6.2 Django (working with PostgreSQL) Question: I wrote a simple model: class OperationType(models.Model): eid = models.IntegerField(unique=True) name = models.CharField(max_length=64) def __unicode__(self): tpl = 'eid="', str(self.eid), '" name="', self.name, '"' return ''.join(tpl) Now I need to initialize it, for example with this data: 0, "None" 1, "Add" 2, "Edit" 3, "Delete" But I need to initialize this data not with admin web panel, but after class model created in the same code. How to do this? Thanks for help!

    Read the article

  • WPF Composite - Expose EF model to all modules

    - by Tony
    Hi All, I have an application that uses WPF Composite, and I have an issue. I've got a big database that is attached to the application and I need it exposed to different modules as part of the application. What is the best way to expose my Entity Framework model to all my different modules and views inside them? Do I have one EF model or a separate one for each module and then only the tables that each module needs. The only problem being that some tables have a relationship and will have different views and those views will be in different modules. Any ideas how to resolve this?

    Read the article

  • Django Grouping Query

    - by Matt
    I have the following (simplified) models: class Donation(models.Model): entry_date = models.DateTimeField() class Category(models.Model): name = models.CharField() class Item(models.Model): donation = models.ForeignKey(Donation) category = models.ForeignKey(Category) I'm trying to display the total number of items, per category, grouped by the donation year. I've tried this: Donation.objects.extra(select={'year': "django_date_trunc('year', %s.entry_date)" % Donation._meta.db_table}).values('year', 'item__category__name').annotate(items=Sum('item__quantity')) But I get a Field Error on item__category__name. I've also tried: Item.objects.extra(select={"year": "django_date_trunc('year', entry_date)"}, tables=["donations_donation"]).values("year", "category__name").annotate(items=Sum("quantity")).order_by() Which generally gets me what I want, but the item quantity count is multiplied by the number of donation records. Any ideas? Basically I want to display this: 2010 - Category 1: 10 items - Category 2: 17 items 2009 - Category 1: 5 items - Category 3: 8 items

    Read the article

  • Prepopulate drop-box according to another drop-box choice in Django Admin

    - by onorua
    I have models like this: class User(models.Model): Switch = models.ForeignKey(Switch, related_name='SwitchUsers') Port = models.ForeignKey(Port) class Switch(models.Model): Name = models.CharField(max_length=50) class Port(models.Model): PortNum = models.PositiveIntegerField() Switch = models.ForeignKey(Switch, related_name = "Ports") When I'm in Admin interface and choose Switch from Switches available, I would like to have Port prepopulated accordingly with Ports from the related Switch. As far as I understand I need to create some JS script to prepopulate it. Unfortunately I don't have this experience, and I would like to keep things simple as it possible and don't rewrite all Django admin interface. Just add this functionality for one Field. Could you please help me with my problem? Thank you.

    Read the article

  • What is the difference between MVC model 1 and model 2?

    - by Alex Ciminian
    I've recently discovered that MVC is supposed to have two different flavors, model one and model two. I'm supposed to give a presentation on MVC1 and I was instructed that "it's not the web based version, that is refered to as MVC2". As the presentations are about design patterns in general, I doubt that this separation is related to Java (I found some info on Sun's site, but it seemed far off) or ASP. I have a pretty good understanding of what MVC is and I've used several (web) frameworks that enforce it, but this terminology is new to me. How is the web-based version different from other MVC (I'm guessing GUI) implementations? Does it have something to do with the stateless nature of HTTP? Thanks, Alex

    Read the article

  • Rails Model multiple column uniqueness

    - by Jty.tan
    I am making a Viewer model with belongs_to :users belongs_to :orders that joins the models Users and Orders with a :has_many :through => :viewers. And the Viewer model has the attributes of user_id and order_id. How would I set it up so that new viewers are only accepted if both user_id and order_id are unique in the same row? I remember in MySQL being able to do so with a flag (although I can't for the life of me remember what it was), but I'm not sure how to do it with Rails. Can I do something like (for Viewer.rb) validates_uniqueness_of :user_id, :scope => :order_id?

    Read the article

  • Django filter with two constraints on related model

    - by BJ Homer
    I have a django app with models as follows: A Question model An Answer model, with a ForeignKey back to the Question. (A question can have multiple answers.) A Flag model, with a ForeignKey to the Answer. (An answer can be flagged as inappropriate.) All of the above also have a user field, defining the user that created that object. I'm trying to get a list of all Questions with answers from the current user which have been flagged. I tried this: Question.objects.filter(answer__user=user).\ filter(answer__flag__isnull=True).distinct() … but I believe that will return a list of Questions with answers from the current user and with answers which have been flagged, but will not necessarily guarantee that it is the user's answer that has been flagged. Is there an easy way to do this? Basically, I want to make the answer part of the filter refer to the same answer on both of them. Please let me know if something is unclear.

    Read the article

  • MVC Entity Model not showing my table

    - by Jessica
    I have a database with multiple tables, and some basic relationships. Here is an example of the problem I am having: My Database: **Org** ID Name etc **Detail1** ID D1name **Org_Detail1** Org_ID Detail1_ID **Detail2** ID D2Name **Org_Detail2** Org_ID Detial1_ID BooleanField My problem is, the Org_detail1 table is not showing up in the entity model, but the Org_Details2 table does. I thought it may have been because the Org_Detail1 table only contains two ID fields that are both primary keys, while the Org_Details2 table contains 2 primary key ID fields as well as a boolean field. If I add a dummy field to Org_detail1 and update it, it still won't show up and wont allow me to add a new entity relating to the Org_Detail1 table. The table won't even show up in the list, but it is listed under the tables. Is there any solution to get this table to appear in my model?

    Read the article

  • Rails 2.3.2: Accessing Model Specific Data in Another Model

    - by Gimli
    I'm using Rails 2.3.2 and using Paperclip to upload photos. I'm also using a slightly customized subdomain_accounts.rb to set some account-specific variables. My question is this: How can I set the bucket used in Paperclip to be dependent on the current account? Since this looks to be a model attribute set up early on, how can I override it later? Thanks.

    Read the article

  • Django Admin: Many-to-Many listbox doesn't show up with a through parameter

    - by NP
    Hi All, I have the following models: class Message(models.Model): date = models.DateTimeField() user = models.ForeignKey(User) thread = models.ForeignKey('self', blank=True, null=True) ... class Forum(models.Model): name = models.CharField(max_length=24) messages = models.ManyToManyField(Message, through="Message_forum", blank=True, null=True) ... class Message_forum(models.Model): message = models.ForeignKey(Message) forum = models.ForeignKey(Forum) status = models.IntegerField() position = models.IntegerField(blank=True, null=True) tags = models.ManyToManyField(Tag, blank=True, null=True) In the admin site, when I go to add/change a forum, I don't see the messages listbox as you'd expect. However, it shows up if I remove the 'through' parameter in the ManyToManyField declaration. What's up with that? I've registered all three models (plus Tag) to the admin site in admin.py. TIA

    Read the article

  • Django: Update order attribute for objects in a queryset

    - by lazerscience
    I'm having a attribute on my model to allow the user to order the objects. I have to update the element's order depending on a list, that contains the object's ids in the new order; right now I'm iterating over the whole queryset and set one objects after the other. What would be the easiest/fastest way to do the same with the whole queryset? def update_ordering(model, order): """ order is in the form [id,id,id,id] for example: [8,4,5,1,3] """ id_to_order = dict((order[i], i) for i in range(len(order))) for x in model.objects.all(): x.order = id_to_order[x.id] x.save()

    Read the article

  • Filter across three tables using Django

    - by Vanessa MacDougal
    I have 3 django models, where the first has a foreign key to the second, and the second has a foreign key to the third. Like this: class Book(models.Model): year_published = models.IntField() author = models.ForeignKey(Author) class Author(models.Model): author_id = models.AutoField(primary_key=True) name = models.CharField(max_length=50) agent = models.ForeignKey(LitAgent) class LitAgent(models.Model): agent_id = models.AutoField(primary_key=True) name = models.CharField(max_length=50) I want to ask for all the literary agents whose authors had books published in 2006, for example. How can I do this in Django? I have looked at the documentation about filters and QuerySets, and don't see an obvious way. Thanks.

    Read the article

  • CakePhp: model recursive associations and find

    - by Petecocoon
    Hello to everybody! I've some trouble with a find() on a model on CakePhp. I have three model relationed in this way: Project(some_fields, item_id) ------belongsTo----- Item(some_fields, item_id) ------belongsTo----- User(some_fields campi, nickname) I need to do a find() and retrieve all fields from project, a field from Item and the nickname field from User. This is my code: $this->set('projects', $this->Project->find('all', array('recursive' => 2))); but my output doesn't contains the user object. I've tried with Containable behaviour but the output is the same. What is broken? Many many Thanks Peter

    Read the article

  • Single database with multiple instances of Django

    - by jwesonga
    I have a Django project where the company will have a main site like www.ourcompany.org and a bunch of sub-domains like project.ourcompany.org. Content appearing in the sub-domains like case studies should also appear in the main site. I've decided to use multiple instances of Django BUT one database for each sub-domain so that I can have some flexibility and take advantage of the Sites framework. What I'm not sure of is how to access the models across the multiple instances. If I have a model: class CaseStudy(models.Model): title=models.CharField(max_length=100) site=models.ManyToMany(Site) Do I need to create this model in every instance so that I can have access to the object?

    Read the article

  • How best can I extract a logical model from a physical DB model

    - by Dean
    We have made substantial changes to our physical DB, now as it is the ne dof the project I would like to abstract a logical model from this, to allow me to generate schemas for both Oracle and SQL Server. Can anyone guide me as to the best way to achieve this. I was hoping TOAD data modeller would help but I can't seem to see any options to do what I require?

    Read the article

  • Define Rails Model Persistent Attributes in Model File

    - by Kevin Sylvestre
    I recently played with MongoDB in Rails using Mongoid. I like the ability to define attributes for models within the model file (as opposed to in migrations): class Person include Mongoid::Document field :name, :type => String field :birthday, :type => Date end For projects that cannot use a schema-less database, does a similar feature exist? Any gems or plugins that generate schemas from a similar syntax would be greatly appreciated. Thanks.

    Read the article

  • django many to many validation when add()

    - by Julien
    Hi i have a Category model with parent/child self relation For primary category and sub categories : class Place(models.Model): name = models.CharField(_("name"), max_length=100) categories = models.ManyToManyField("Category", verbose_name=_("categories")) class Category(models.Model): name = models.CharField(_("name"), max_length=100) parent = models.ForeignKey('self', blank=True, null=True, related_name='child_set') i need to prevent orphans, to prevent this kind of errors (in admin web interface) c_parent = Category(name='Restaurant') c_parent.save() c_child = Category(name="Japanese restaurant", parent=c_parent) c_child.save() place1 = Place (name="Planet sushi") place1.save() place1.categories.add(c_parent) place1.categories.add(c_child) So now we have a new Place called "Planet sushi", it's a Restaurant (root category), and a Japanese Restaurant (sub category) but i want to prevent this kind of things : place2 = Place (name="Tokyofood") place2.save() place2.categories.add(c_child) because parent is not set, or is not the correct parent category where can i do form validation for the admin ? and other forms (because any user can add a new place and will have to choose correct categories for)

    Read the article

  • Django ORM dealing with MySQL BIT(1) field

    - by Carles Barrobés
    In a Django application, I'm trying to access an existing MySQL database created with Hibernate (a Java ORM). I reverse engineered the model using: $ manage.py inspectdb > models.py This created a nice models file from the Database and many things were quite fine. But I can't find how to properly access boolean fields, which were mapped by Hibernate as columns of type BIT(1). The inspectdb script by default creates these fields in the model as TextField and adds a comment saying that it couldn't reliably obtain the field type. I changed these to BooleanField but it doesn't work (the model objects always fetch a value of true for these fields). Using IntegerField won't work as well (e.g. in the admin these fields show strange non-ascii characters). Any hints of doing this without changing the database? (I need the existing Hibernate mappings and Java application to still work with the database).

    Read the article

  • Can't call method in model table class using Doctrine with Zend Framework

    - by Jeremy Hicks
    I'm using Doctrine with Zend Framework. For my model, I'm using a base class, the regular class (which extends the base class), and a table class. In my table class, I've created a method which does a query for records with a specific value for one of the fields in my model. When I try and call this method from my controller, I get an error message saying, "Message: Unknown method Doctrine_Table::getCreditPurchases". Is there something else I need to do to call functions in my table class? Here is my code: class Model_CreditTable extends Doctrine_Table { /** * Returns an instance of this class. * * @return object Model_CreditTable */ public static function getInstance() { return Doctrine_Core::getTable('Model_Credit'); } public function getCreditPurchases($id) { $q = $this->createQuery('c') ->where('c.buyer_id = ?', $id); return $q->fetchArray(); } } // And then in my controller method I have... $this->view->credits = Doctrine_Core::getTable('Model_Credit')->getCreditPurchases($ns->id);

    Read the article

  • Rails Model has_many with multiple foreign_keys

    - by Kenzie
    Relatively new to rails and trying to model a very simple family "tree" with a single Person model that has a name, gender, father_id and mother_id (2 parents). Below is basically what I want to do, but obviously I can't repeat the :children in a has_many (the first gets overwritten). class Person < ActiveRecord::Base belongs_to :father, :class_name => 'Person' belongs_to :mother, :class_name => 'Person' has_many :children, :class_name => 'Person', :foreign_key => 'mother_id' has_many :children, :class_name => 'Person', :foreign_key => 'father_id' end Is there a simple way to use has_many with 2 foreign keys, or maybe change the foreign key based on the object's gender? Or is there another/better way altogether? Thanks!

    Read the article

  • Getting the value from an array in the model in rails

    - by slythic
    Hi all, I have a relatively simple problem. I have a model named Item which I've added a status field. The status field will only have two options (Lost or Found). So I created the following array in my Item model: STATUS = [ [1, "Lost"], [2, "Found"]] In my form view I added the following code which works great: <%= collection_select :item, :status, Item::STATUS, :first, :last, {:include_blank => 'Select status'} %> This stores the numeric id (1 or 2) of the status in the database. However, in my show view I can't figure out how to convert from the numeric id (again, 1 or 2) to the text equivalent of Lost or Found. Any ideas on how to get this to work? Is there a better way to go about this? Many thanks, Tony

    Read the article

< Previous Page | 62 63 64 65 66 67 68 69 70 71 72 73  | Next Page >