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• jQuery syntax for changing the value of a table cell

  - by cf_PhillipSenn

  I have a table where every row has a unique id. The last table cell has class="status" where I want to show the user the result of their action. In my $.ajax call, I have: ,success: function(result){ $('tr#'+result).td('.status').text('Updated'); }; result is the id of the row that was updated. It's just throwing an error message that says $( and that's all.

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• Animation in a table view cell

  - by theomen

  I'm not sure if it is possible to achieve, but my costumer wants that when user taps a table view cell, an animation of a UIView sliding from left to right is committed, leaving the content under the UIView visible. My concern is about how to trigger gesture recognizer added to the upper UIVIew for the animation and do not enter in conflict with didSelectRowatIndex: table view delegate method. Is it possible to achieve? Mant thanks!

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• Java Dynamic Binding

  - by Chris Okyen

  I am having trouble understanding the OOP Polymorphic principl of Dynamic Binding ( Late Binding ) in Java. I looked for question pertaining to java, and wasn't sure if a overall answer to how dynamic binding works would pertain to Java Dynamic Binding, I wrote this question. Given: class Person { private String name; Person(intitialName) { name = initialName; } // irrelevant methods is here. // Overides Objects method public void writeOutput() { println(name); } } class Student extends Person { private int studentNumber; Student(String intitialName, int initialStudentNumber) { super(intitialName); studentNumber = initialStudentNumber; } // irrellevant methods here... // overides Person, Student and Objects method public void writeOutput() { super.writeOutput(); println(studentNumber); } } class Undergaraduate extends Student { private int level; Undergraduate(String intitialName, int initialStudentNumber,int initialLevel) { super(intitialName,initialStudentNumber); level = initialLevel; } // irrelevant methods is here. // overides Person, Student and Objects method public void writeOutput() { super.writeOutput(); println(level); } } I am wondering. if I had an array called person declared to contain objects of type Person: Person[] people = new Person[2]; person[0] = new Undergraduate("Cotty, Manny",4910,1); person[1] = new Student("DeBanque, Robin", 8812); Given that person[] is declared to be of type Person, you would expect, for example, in the third line where person[0] is initialized to a new Undergraduate object,to only gain the instance variable from Person and Persons Methods since doesn't the assignment to a new Undergraduate to it's ancestor denote the Undergraduate object to access Person - it's Ancestors, methods and isntance variables... Thus ...with the following code I would expect person[0].writeOutput(); // calls Undergraduate::writeOutput() person[1].writeOutput(); // calls Student::writeOutput() person[0] to not have Undergraduate's writeOutput() overidden method, nor have person[1] to have Student's overidden method - writeOutput(). If I had Person mikeJones = new Student("Who?,MikeJones",44,4); mikeJones.writeOutput(); The Person::writeOutput() method would be called. Why is this not so? Does it have to do with something I don't understand about relating to arrays? Does the declaration Person[] people = new Person[2] not bind the method like the previous code would?

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• Java Grade Calculator program for class kepp geting the error "Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException." [migrated]

  - by user2880621

  this is my first question I've posted. I've used this site to look at other questions to help with similar problems I've had. After some cursory looking I couldn't find quite the answer I was looking for so I decided to finally succumb and create an account. I am fairly new to java, only a few weeks into my first class. Anyway, my project is to create a program which takes any amount of students and their grades, and then assign them a letter grade. The catch is, however, that it is on a sort of curve and the other grades' letter are dependent on the the highest. Anything equal to or 10 points below the best grade is an a, anything 11-20 points below is a b, and so on. I am to use an array, but I get this error when ran "Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException." I will go ahead and post my code down below. Thanks for any advice you may be able to give. package grade.calculator; import java.util.Scanner; /** * * @author nichol57 */ public class GradeCalculator { /** * @param args the command line arguments */ public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.println("Enter the number of students"); int number = input.nextInt(); double[]grades = new double [number]; for (int J = number; J >=0; J--) { System.out.println("Enter the students' grades"); grades[J] = input.nextDouble(); } double best = grades[0]; for (int J = 1; J < number; J++) { if (grades[J] >= best){ best = grades[J]; } } for (int J = 0;J < number; J++){ if (grades[J] >= best - 10){ System.out.println("Student " + J + " score is " + grades[J] + " and grade is " + "A"); } else if (grades[J] >= best - 20){ System.out.println("Student " + J + " score is " + grades[J] + " and grade is " + "B"); } else if (grades[J] >= best - 30) { System.out.println("Student " + J + " score is " + grades[J] + " and grade is " + "C"); } else if (grades[J] >= best - 40) { System.out.println("Student " + J + " score is " + grades[J] + " and grade is " + "D"); } else { System.out.println("Student " + J + " score is " + grades[J] + " and grade is " + "F"); } } // end for loop for output }// end main method }

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• Should the 12-String be in it's own class and why?

  - by MayNotBe

  This question is regarding a homework project in my first Java programming class (online program). The assignment is to create a "stringed instrument" class using (among other things) an array of String names representing instrument string names ("A", "E", etc). The idea for the 12-string is beyond the scope of the assignment (it doesn't have to be included at all) but now that I've thought of it, I want to figure out how to make it work. Part of me feels like the 12-String should have it's own class, but another part of me feels that it should be in the guitar class because it's a guitar. I suppose this will become clear as I progress but I thought I would see what kind of response I get here. Also, why would they ask for a String[] for the instrument string names? Seems like a char[] makes more sense. Thank you for any insight. Here's my code so far (it's a work in progress): public class Guitar { private int numberOfStrings = 6; private static int numberOfGuitars = 0; private String[] stringNotes = {"E", "A", "D", "G", "B", "A"}; private boolean tuned = false; private boolean playing = false; public Guitar(){ numberOfGuitars++; } public Guitar(boolean twelveString){ if(twelveString){ stringNotes[0] = "E, E"; stringNotes[1] = "A, A"; stringNotes[2] = "D, D"; stringNotes[3] = "G, G"; stringNotes[4] = "B, B"; stringNotes[5] = "E, E"; numberOfStrings = 12; } } public int getNumberOfStrings() { return numberOfStrings; } public void setNumberOfStrings(int strings) { if(strings == 12 || strings == 6) { if(strings == 12){ stringNotes[0] = "E, E"; stringNotes[1] = "A, A"; stringNotes[2] = "D, D"; stringNotes[3] = "G, G"; stringNotes[4] = "B, B"; stringNotes[5] = "E, E"; numberOfStrings = strings; } if(strings == 6) numberOfStrings = strings; }//if else System.out.println("***ERROR***Guitar can only have 6 or 12 strings***ERROR***"); } public void getStringNotes() { for(int i = 0; i < stringNotes.length; i++){ if(i == stringNotes.length - 1) System.out.println(stringNotes[i]); else System.out.print(stringNotes[i] + ", "); }//for }

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• Should the 12-String be in it's own class and why? Java

  - by MayNotBe

  This is my first question here. I will amend it as instructed. This is regarding a homework project in my first Java programming class (online program). The assignment is to create a "stringed instrument" class using (among other things) an array of String names representing instrument string names ("A", "E", etc). The idea for the 12-string is beyond the scope of the assignment (it doesn't have to be included at all) but now that I've thought of it, I want to figure out how to make it work. Part of me feels like the 12-String should have it's own class, but another part of me feels that it should be in the guitar class because it's a guitar. I suppose this will become clear as I progress but I thought I would see what kind of response I get here. Also, why would they ask for a String[] for the instrument string names? Seems like a char[] makes more sense. Thank you for any insight. Here's my code so far (it's a work in progress): public class Guitar { private int numberOfStrings = 6; private static int numberOfGuitars = 0; private String[] stringNotes = {"E", "A", "D", "G", "B", "A"}; private boolean tuned = false; private boolean playing = false; public Guitar(){ numberOfGuitars++; } public Guitar(boolean twelveString){ if(twelveString){ stringNotes[0] = "E, E"; stringNotes[1] = "A, A"; stringNotes[2] = "D, D"; stringNotes[3] = "G, G"; stringNotes[4] = "B, B"; stringNotes[5] = "E, E"; numberOfStrings = 12; } } public int getNumberOfStrings() { return numberOfStrings; } public void setNumberOfStrings(int strings) { if(strings == 12 || strings == 6) { if(strings == 12){ stringNotes[0] = "E, E"; stringNotes[1] = "A, A"; stringNotes[2] = "D, D"; stringNotes[3] = "G, G"; stringNotes[4] = "B, B"; stringNotes[5] = "E, E"; numberOfStrings = strings; } if(strings == 6) numberOfStrings = strings; }//if else System.out.println("***ERROR***Guitar can only have 6 or 12 strings***ERROR***"); } public void getStringNotes() { for(int i = 0; i < stringNotes.length; i++){ if(i == stringNotes.length - 1) System.out.println(stringNotes[i]); else System.out.print(stringNotes[i] + ", "); }//for }

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• how i got the name of the string variable in the strange attempt to debug unknown variable ?

  - by justjoe

  i got several variable. One is variable string, object, and array. $mystring = "hello im input"; $myobject = new userclass; $myarray = array ( 0 = 'zero', 1 = "one"); i want to create a new array with its variable name as key before send it to as function parameter with it's first line use extract function. the multi_array will be like this multi_array = array ( 'mystring' = "hello im input", 'myobject' = new userclass, 'myarray' = array ( 0 = 'zero', 1 = "one") ) i use key to get the name of array and getclass to get the name of object. But how i got the name of the string variable ? function i_do_extract($multi_array) { extract($multi_array); // Do Rest }

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• javascript arrays: adding entries

  - by Lyon

  Hi, I'm not sure how I would do this in Javascript. I want to create an array that would contain any number of error messages from my form. I read on websites that you define the key for that array when adding new entries. // Javascript var messages = new Array(); messages[0] = 'Message 1'; How can I add entries into my array using a similar method I normally do in PHP // PHP $messages = array(); $messages[] = 'Message 1'; // automatically assigned key 0 $messages[] = 'Message 2'; // automatically assigned key 1 Is it possible to emulate that in Javascript? I don't want to have to define the number of entries in my array as it can vary. Thanks for helping me out on this very basic js question. -Lyon

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• How do i merge the arrays in a particular format?

  - by Pankaj Khurana

  Hi, I have following arrays: 1) for total placed Array ( [0] => Array ( [centers] => Array ( [name] => delhi [id] => 1 ) [0] => Array ( [totalplaced] => 8 ) ) [1] => Array ( [centers] => Array ( [name] => mumbai [id] => 2 ) [0] => Array ( [totalplaced] => 1 ) ) ) 2) for total working Array ( [0] => Array ( [centers] => Array ( [name] => delhi [id] => 1 ) [0] => Array ( [totalworking] => 4 ) ) [1] => Array ( [centers] => Array ( [name] => mumbai [id] => 2 ) [0] => Array ( [totalworking] => 1 ) ) ) 3) for total trained Array ( [0] => Array ( [centers] => Array ( [name] => delhi [id] => 1 ) [0] => Array ( [totaltrained] => 8 ) ) [1] => Array ( [centers] => Array ( [name] => mumbai [id] => 2 ) [0] => Array ( [totaltrained] => 1 ) ) ) I wanted to merge these arrays so that the resultant array should look like this [newarray] => Array( [0] => Array ( [centers] => Array ( [name] => delhi [id] => 1 [totalplaced] => 8 [totalworking] => 4 [totaltrained] => 8 ) ) [1]=> Array( [centers] => Array ( [name] => mumbai [id] => 2 [totalplaced] => 1 [totalworking] => 1 [totaltrained] => 1 ) ) ) This is the tabular representation of the above data which i want to display centername totalplaced totalworking totaltrained delhi 8 4 8 mumbai 1 1 1 Please help me on this. Thanks Pankaj Khurana

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• Improving the running time of Breadth First Search and Adjacency List creation

  - by user45957

  We are given an array of integers where all elements are between 0-9. have to start from the 1st position and reach end in minimum no of moves such that we can from an index i move 1 position back and forward i.e i-1 and i+1 and jump to any index having the same value as index i. Time Limit : 1 second Max input size : 100000 I have tried to solve this problem use a single source shortest path approach using Breadth First Search and though BFS itself is O(V+E) and runs in time the adjacency list creation takes O(n2) time and therefore overall complexity becomes O(n2). is there any way i can decrease the time complexity of adjacency list creation? or is there a better and more efficient way of solving the problem? int main(){ vector<int> v; string str; vector<int> sets[10]; cin>>str; int in; for(int i=0;i<str.length();i++){ in=str[i]-'0'; v.push_back(in); sets[in].push_back(i); } int n=v.size(); if(n==1){ cout<<"0\n"; return 0; } if(v[0]==v[n-1]){ cout<<"1\n"; return 0; } vector<int> adj[100001]; for(int i=0;i<10;i++){ for(int j=0;j<sets[i].size();j++){ if(sets[i][j]>0) adj[sets[i][j]].push_back(sets[i][j]-1); if(sets[i][j]<n-1) adj[sets[i][j]].push_back(sets[i][j]+1); for(int k=j+1;k<sets[i].size();k++){ if(abs(sets[i][j]-sets[i][k])!=1){ adj[sets[i][j]].push_back(sets[i][k]); adj[sets[i][k]].push_back(sets[i][j]); } } } } queue<int> q; q.push(0); int dist[100001]; bool visited[100001]={false}; dist[0]=0; visited[0]=true; int c=0; while(!q.empty()){ int dq=q.front(); q.pop(); c++; for(int i=0;i<adj[dq].size();i++){ if(visited[adj[dq][i]]==false){ dist[adj[dq][i]]=dist[dq]+1; visited[adj[dq][i]]=true; q.push(adj[dq][i]); } } } cout<<dist[n-1]<<"\n"; return 0; }

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• jqGrid with JSON data renders table as empty

  - by jgreep

  I'm trying to create a jqgrid, but the table is empty. The table renders, but the data doesn't show. The data I'm getting back from the php call is: { "page":"1", "total":1, "records":"10", "rows":[ {"id":"2:1","cell":["1","image","Chief Scout","Highest Award test","0"]}, {"id":"2:2","cell":["2","image","Link Badge","When you are invested as a Scout, you may be eligible to receive a Link Badge. (See page 45)","0"]}, {"id":"2:3","cell":["3","image","Pioneer Scout","Upon completion of requirements, the youth is invested as a Pioneer Scout","0"]}, {"id":"2:4","cell":["4","image","Voyageur Scout Award","Voyageur Scout Award is the right after Pioneer Scout.","0"]}, {"id":"2:5","cell":["5","image","Voyageur Citizenship","Learning about and caring for your community.","0"]}, {"id":"2:6","cell":["6","image","Fish and Wildlife","Demonstrate your knowledge and involvement in fish and wildlife management.","0"]}, {"id":"2:7","cell":["7","image","Photography","To recognize photography knowledge and skills","0"]}, {"id":"2:8","cell":["8","image","Recycling","Demonstrate your knowledge and involvement in Recycling","0"]}, {"id":"2:10","cell":["10","image","Voyageur Leadership ","Show leadership ability","0"]}, {"id":"2:11","cell":["11","image","World Conservation","World Conservation Badge","0"]} ]} The javascript configuration looks like so: $("#"+tableId).jqGrid ({ url:'getAwards.php?id='+classId, dataType : 'json', mtype:'POST', colNames:['Id','Badge','Name','Description',''], colModel : [ {name:'awardId', width:30, sortable:true, align:'center'}, {name:'badge', width:40, sortable:false, align:'center'}, {name:'name', width:180, sortable:true, align:'left'}, {name:'description', width:380, sortable:true, align:'left'}, {name:'selected', width:0, sortable:false, align:'center'} ], sortname: "awardId", sortorder: "asc", pager: $('#'+tableId+'_pager'), rowNum:15, rowList:[15,30,50], caption: 'Awards', viewrecords:true, imgpath: 'scripts/jqGrid/themes/green/images', jsonReader : { root: "rows", page: "page", total: "total", records: "records", repeatitems: true, cell: "cell", id: "id", userdata: "userdata", subgrid: {root:"rows", repeatitems: true, cell:"cell" } }, width: 700, height: 200 }); The HTML looks like: <table class="awardsList" id="awardsList2" class="scroll" name="awardsList" /> <div id="awardsList2_pager" class="scroll"></div> I'm not sure that I needed to define jsonReader, since I've tried to keep to the default. If the php code will help, I can post it too.

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• Rich Text Editor in Table view

  - by pubudu

  Im try to implement rich text editor in table view cell. before this i test rich text editor using web view.it work fine I want to put this web view inside my costume cell. i did it, but it not working (bold , italic ... styles) how can i pass stringByEvaluatingJavaScriptFromString:@"document.execCommand(\"Bold\") this command to webview in cell i did like this in viewContoller - (IBAction)clickbold:(id)sender { static NSString *CellIdentifier = @"Cell1"; Cell *cell = [_tableview dequeueReusableCellWithIdentifier:CellIdentifier]; cell = [_tableview cellForRowAtIndexPath:0]; [cell.webView stringByEvaluatingJavaScriptFromString:@"document.execCommand(\"Bold\")"]; [_tableview beginUpdates]; [_tableview endUpdates]; } - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *CellIdentifier = @"Cell1"; Cell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; { NSBundle *bundle = [NSBundle mainBundle]; NSURL *indexFileURL = [bundle URLForResource:@"index" withExtension:@"html"]; [cell.tableview loadRequest:[NSURLRequest requestWithURL:indexFileURL]]; cell.webView.delegate = self; [cell.webView stringByEvaluatingJavaScriptFromString:@"document.execCommand(\"Italic\")"]; return cell; } return cell; } my html file like this <html> <head> <script> function myFunction() { window.location.href = "myclick://buttonClicked"; } function onKEYPRESS() { window.location.href = "onkeypress://buttonClicked"; } </script> </head> <body> <body> <div id="content" contenteditable="true" style="font-family:Arial" onfocus="myFunction()" onkeypress="onKEYPRESS()">TEXT TEXT </div> </body> </html>

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• Graphical glitches when adding cells and scrolling with UITableView

  - by Daniel I-S

  I am using a UITableView to display the results of a series of calculations. When the user hits 'calculate', I wish to add the latest result to the screen. This is done by adding a new cell to a 'results' section. The UITableViewCell object is added to an array, and then I use the following code to add this new row to what is displayed on the screen: [thisView beginUpdates]; [thisView insertRowsAtIndexPaths:[NSArray arrayWithObject:newIndexPath] withRowAnimation: UITableViewRowAnimationFade]; [thisView endUpdates]; This results in the new cell being displayed. However, I then want to immediately scroll the screen down so that the new cell is the lowermost cell on-screen. I use the following code: [thisView scrollToRowAtIndexPath:newIndexPath atScrollPosition:UITableViewScrollPositionBottom animated:YES]; This almost works great. However, the first time a cell is added and scrolled to, it appears onscreen only briefly before vanishing. The view scrolls down to the correct place, but the cell is not there. Scrolling the view by hand until this invisible new cell's position is offscreen, then back again, causes the cell to appear - after which it behaves normally. This only happens the first time a cell is added; subsequent cells don't have this problem. It also happens regardless of the combination of scrollToRowAtIndexPath and insertRowsAtIndexPath animation settings. There is also a problem where, if new cells are added repeatedly and quickly, the new cells stop 'connecting up'. The lowermost cell in a group is supposed to have rounded corners, and when a new cell is added these turn into square corners so that there is a clean join with the next cell in the group. In this case, however, a cell often does not lose its rounded edges despite not being the last cell anymore. This also gets corrected once the affected area moves offscreen and back. This method of adding and scrolling would be perfect for my application if it weren't for these weird glitches. Any ideas as to what I may be doing wrong?

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• Help adding a backgroundView to UITableViewCell

  - by Alex

  I'm getting really desperate trying to add a UIImageView to UITableViewCell.backgroundView. All my efforts have resulted in this crappy rendering: It looks like the cell's label's white background is sitting on top of cell's background and covering portions of it. I tried setting the label's background color to clear, or some other color and it does not have any event. It is always white. The reason I know it's the text label's background causing this white area is that if I don't do [cell setText:@"Cell text here"]; the white area is gone and I see just the cell's background image. Here's the code that I'm using. The table view is added in the .xib file and UITableView is added to UIViewController: - (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView { return 1; } - (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section { return [myCollection.items count]; } - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { NSUInteger rowIndex = indexPath.row; static NSString *CellIdentifier = @"Cell"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier] autorelease]; cell.backgroundView = [[UIImageView alloc] initWithImage:[UIImage imageNamed:@"darkCellBackground.png"]]; cell.selectedBackgroundView = [[UIImageView alloc] initWithImage:[UIImage imageNamed:@"darkCellBackground.png"]]; } [cell setText:@"Cell text here"]; return cell; } - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { // Navigation logic may go here. Create and push another view controller. // AnotherViewController *anotherViewController = [[AnotherViewController alloc] initWithNibName:@"AnotherView" bundle:nil]; // [self.navigationController pushViewController:anotherViewController]; // [anotherViewController release]; [tableView deselectRowAtIndexPath:indexPath animated:YES]; } - (BOOL)tableView:(UITableView *)tableView canEditRowAtIndexPath:(NSIndexPath *)indexPath { return NO; } I'm sure I'm doing something wrong but cant quite figure out what.

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• 2D Array of 2D Arrays (C# / XNA) [on hold]

  - by Lemoncreme

  I want to create a 2D array that contains many other 2D arrays. The problem is I'm not quite sure what I'm doing but this is the initialization code I have: int[,][,] chunk = new int[64, 64][32, 32]; For some reason Visual Studio doesn't like this and says that it's and 'invalid rank specifier'. Also, I'm not sure how to use the nested arrays once I've declared them... Some help and some insight, please?

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• ASP.NET MVC: ModelBinding Multiple File Uploads to an Array

  - by HeartattacK

  Note: Cross posted from Heartysoft.com. Permalink In this article, Ashic Mahtab shows how to model bind multiple file uploads to a single array action parameter in ASP.NET MVC.

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• Making Linux Server Directories More Readable, Add to Perl's @INC Array

  Tip of the Trade: Anyone who has encountered the Perl @INC array in the context of a 'cannot find module' error knows the value of being able to see a list of directories on you Linux server. Here's how to access @INC and find obscurely located modules before they are lost.

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• Tab completion COMP_WORDS bad array subscript

  - by Senthil Kumaran

  I have upgraded my Ubuntu to 10.04 and I am facing this problem of COMP_WORDS bad array subscript when I press TAB for certain completion. I thought, it is a bug with bash-completion package and I purged it. But even after that, I still face this. If it is a bug with bash package, how I can resolve it? https://bugs.launchpad.net/ubuntu/+source/bash-completion/+bug/366446 It is difficult for a developer to live with this bug in the system.

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• Android Array Lag?

  - by Mike

  I am making a platform game for Android. It is sort of a tile based game. I added bullets and enemies with AI and a bunch of tile types. I created a simple map with no Enemies. Everything was running well and smooth until I shot a bunch of bullets randomly everywhere. A couple of hundreds of bullets later, the FPS lowered. I made a test to find out if the bullets were the problem so I made another simple map with just a tile to stand on and left it for a while. Minutes later, I played around with it a bit to check if the FPS changed and it didnt. I reloaded the same map and shot a lot of bullets. Minutes later, the FPS was visibly lower even after the number of bullets were zero. Points to note: Programmed FPS is 30 Tested on a Samsung Galaxy Y and Samsung Galaxy W Any tile, enemy, bullet that is off screen is not drawn to prevent lag Bullets collide with Tiles (if they dont collide with in 450 frames, they are removed from the array) I used List bullets = new ListArray(); I used bullets.add(new Bullet(x, y, params...)); I used for(...){ if(...){ bullets.remove(i); } } Code for bullet: private void drawBullets(Canvas canvas) { for (int i = 0; i < bullets.size(); i++) { Bullet b = bullets.get(i); b.update(canvas); //updates physics if (b.t > blm) { //if the bullet is past its expiry bullets.remove(i); i--; } else { if (svx((b.x)) > 0 && svx(b.x) < width && svy((b.y)) > 0 && svy(b.y) < height) { // if bullet is not off screen b.draw(canvas); // draw the bullet } } } } I tried searching for solutions and references but I have no luck. I'm guessing that the lag has something to do with the Array and the Bullets or Classes that I've loaded? I'm not sure! Someone please help! Thanks in advance! :)

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• Java - Finding distance between player and tile in array

  - by Corey

  What is the best way performance wise to do this? When I click a tile I want it to get the distance and if I am close enough I can interact with the tile. One way would be to find the tile by doing mouse / tile width when I click correct? But then how would I get that tiles position? I know how to find the distance I just don't know how to get a certain tiles position from the array when I click it

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• unset the array

  - by zahir hussain

  just i intersect the two array... $c=array_intersect($a,$b); ? then i would like to unset the array elements which are same element in two array.... or i would like to unset the array element which are same element in array... thanks advance

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• Sorting an array of objects in ActionScript 3

  - by vitto

  Hi, I'm trying to sort an array of objects with ActionScript 3. The array is like this: var arr:Array = new Array (); arr.push ({name:"John", date:"20080324", message:"Hi"}); arr.push ({name:"Susan", date:"20090528", message:"hello"}); can I do something with Array.sort(...) method?

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• What are the differences between these Array methods

  - by Sir Psycho

  These static Array methods have me puzzled. They seem to do the same things. Are they available for older legacy code? Array.IndexOf Array.FindIndex Array.LastIndexOf Array.FindLastIndex

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• What is the equivalent of YUI 3's Y.Array() in jQuery

  - by Sudar

  What is the equivalent of YUI 3's Y.Array in jQuery? Y.Array() takes array like inputs and converts them into array. More info at http://developer.yahoo.com/yui/3/api/yui-array.js.html

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• If exist in array (php)

  - by Glister

  There are two arrays, that are given for $link from foreach. One time $link must be a first arrow, and a third - the second. So: 1 array: Array ( [width] => 800 [height] => 1142 [hwstring_small] => height='96' width='67' [file] => 2010/04/white-1051279.jpg [sizes] => Array ( [thumbnail] => Array ( [file] => white-1051279-100x150.jpg [width] => 100 [height] => 150 ) [medium] => Array ( [file] => white-1051279-200x285.jpg [width] => 200 [height] => 285 ) ) [image_meta] => Array ( [aperture] => 0 [credit] => [camera] => [caption] => [created_timestamp] => 0 [copyright] => [focal_length] => 0 [iso] => 0 [shutter_speed] => 0 [title] => ) ) 2 array: Array ( [width] => 50 [height] => 50 [hwstring_small] => height='50' width='50' [file] => 2010/04/images1.jpeg [image_meta] => Array ( [aperture] => 0 [credit] => [camera] => [caption] => [created_timestamp] => 0 [copyright] => [focal_length] => 0 [iso] => 0 [shutter_speed] => 0 [title] => ) ) The difference - first one has [sizes]. Searching for a way to detect, is there [sizes] in given array. Tryed if (in_array("[sizes]", $link)) { } else { }, but it doesnt work. Thanks.

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