Search Results

Search found 82719 results on 3309 pages for 'image file'.

Page 68/3309 | < Previous Page | 64 65 66 67 68 69 70 71 72 73 74 75  | Next Page >

  • Read random lines from huge CSV file in Python

    - by jbssm
    I have this quite big CSV file (15 Gb) and I need to read about 1 million random lines from it. As far as I can see - and implement - the CSV utility in Python only allows to iterate sequentially in the file. It's very memory consuming to read the all file into memory to use some random choosing and it's very time consuming to go trough all the file and discard some values and choose others, so, is there anyway to choose some random line from the CSV file and read only that line? I tried without success: import csv with open('linear_e_LAN2A_F_0_435keV.csv') as file: reader = csv.reader(file) print reader[someRandomInteger] A sample of the CSV file: 331.093,329.735 251.188,249.994 374.468,373.782 295.643,295.159 83.9058,0 380.709,116.221 352.238,351.891 183.809,182.615 257.277,201.302 61.4598,40.7106

    Read the article

  • php, image dosn't show

    - by lolalola
    Hi, whats wrong with my code. image dosn't show in test2.php file File: test2.php: <img src = "test.php" /> File: test.php session_start(); $md5_hash = md5(rand(0,999)); $security_code = substr($md5_hash, 15, 5); $_SESSION["security_code"] = $security_code; $width = 100; $height = 20; header("Content-type: image/png"); $image = ImageCreate($width, $height); $white = ImageColorAllocate($image, 255, 255, 255); $black = ImageColorAllocate($image, 0, 0, 0); $grey = ImageColorAllocate($image, 204, 204, 204); ImageFill($image, 0, 0, $black); //Add randomly generated string in white to the image ImageString($image, 3, 30, 3, $security_code, $white); //Throw in some lines to make it a little bit harder for any bots to break imageRectangle($image,0,0,$width-1,$height-1,$grey); imageline($image, 0, $height/2, $width, $height/2, $grey); imageline($image, $width/2, 0, $width/2, $height, $grey); imagepng($image); imagedestroy($image);

    Read the article

  • CodeIgniter - Image Validation & Thumbnailing

    - by Sebhael
    I'm currently trying to create a function that validates and creates thumbnails for images on upload - but I'm quite lost on what I'm doing. I'm assuming I'm off on my terminology so I'm not really getting any search results to help point me in the right direction. My playground is a form with 6 upload fields that are required. One of these fields is for a simple 32x32 icon image, another a portrait orientation (most likely) photo, and then 4 standard desktop screenshots -- and I'm using CodeIgniter as my framework. I would like to create a function that validates/thumbnails images, and only have to call it on the validation if at all possible. I know I can achieve this per-image, since the documentation for CI is quite through on this - but to reduce redundancy I'm looking for the better option. Outside of that, I don't even actually understand in full how to manipulate images unless it's just $this-input-post('field') - then calling all functions onto this? I don't know, I'm confused and posting on the actual CI forums has yielded me nothing - so all I'm really looking for is a point in the right direction to understanding what I'm trying to achieve here. This also all might not make any sense, I know it doesn't to me - but I can explain more if needed. Thanks in advance.

    Read the article

  • Finding most recently edited file in python

    - by zztpp5521
    I have a set of folders, and I want to be able to run a function that will find the most recently edited file and tell me the name of the file and the folder it is in. Folder layout: root Folder A File A File B Folder B File C File D etc... Any tips to get me started as i've hit a bit of a wall.

    Read the article

  • How do I use File.new to find a file from Rails?

    - by Angela
    I am trying to read a file that has been saved on the /system folder using Paperclip, for example. But when I use that .url method from Paperclip to read that file using File.new, I get that the file isn't found. The directory is correct, but I still can't access it. What is the right way to find a file for File.new for example? I tried to point to other files, as well, and to no avail.

    Read the article

  • Slow WLAN file transfer between server and tablet

    - by user266985
    My file server is running Ubuntu 12.04 and I'm sharing files from it over samba. It is connected via gigabit ethernet. My desktop, running Windows 8.1, is also connected via gigabit ethernet. I can transfer files between the two and completely saturate that gigabit pipe. However, I just got a Surface Pro 2, and I'm trying to stream HD movies from my server to the device over WiFi. For some reason, I can't break much past 1.5MB/s transferring files over the network. I've tried streaming through XBMC and a standard file copy; no difference. To add the confusion, if I connect to my guest network and then use my VPN server (installed on the router) to access the file server, I get around 3.2MB/s. I've been running diagnostics to determine the root and I think I've found it but I have no idea what is causing it or how to fix it. Router: Asus RT-N66U Surface Pro 2 Network Card: Marvell Avastar 350N (Driver 19/09/2013 v14.69.24044.150) InSSIDer: Link Score: 100 Co-Channels: 0 Overlapping: 0 5GHz Network Channel: 48+44 iperf File Server as Server; Surface Pro 2 as Client - TCP Performance: Acceptable ------------------------------------------------------------ Server listening on TCP port 5001 TCP window size: 85.3 KByte (default) ------------------------------------------------------------ [ 4] local 192.168.0.90 port 5001 connected with 192.168.0.56 port 57367 [ ID] Interval Transfer Bandwidth [ 4] 0.0- 1.0 sec 10.1 MBytes 84.7 Mbits/sec [ 4] 1.0- 2.0 sec 10.4 MBytes 87.6 Mbits/sec [ 4] 2.0- 3.0 sec 10.6 MBytes 88.8 Mbits/sec [ 4] 3.0- 4.0 sec 10.7 MBytes 89.5 Mbits/sec [ 4] 4.0- 5.0 sec 10.1 MBytes 84.4 Mbits/sec [ 4] 5.0- 6.0 sec 10.2 MBytes 85.8 Mbits/sec [ 4] 6.0- 7.0 sec 7.04 MBytes 59.1 Mbits/sec [ 4] 7.0- 8.0 sec 10.8 MBytes 90.2 Mbits/sec [ 4] 8.0- 9.0 sec 10.6 MBytes 89.1 Mbits/sec [ 4] 9.0-10.0 sec 8.62 MBytes 72.3 Mbits/sec [ 4] 0.0-10.0 sec 99.2 MBytes 83.1 Mbits/sec iperf Surface Pro 2 as Server, File Server as Client Performance: Poor ------------------------------------------------------------ Client connecting to 192.168.0.56, TCP port 5001 TCP window size: 22.9 KByte (default) ------------------------------------------------------------ [ 3] local 192.168.0.90 port 40233 connected with 192.168.0.56 port 5001 [ ID] Interval Transfer Bandwidth [ 3] 0.0- 1.0 sec 1.50 MBytes 12.6 Mbits/sec [ 3] 1.0- 2.0 sec 1.50 MBytes 12.6 Mbits/sec [ 3] 2.0- 3.0 sec 1.50 MBytes 12.6 Mbits/sec [ 3] 3.0- 4.0 sec 1.25 MBytes 10.5 Mbits/sec [ 3] 4.0- 5.0 sec 1.62 MBytes 13.6 Mbits/sec [ 3] 5.0- 6.0 sec 1.50 MBytes 12.6 Mbits/sec [ 3] 6.0- 7.0 sec 1.38 MBytes 11.5 Mbits/sec [ 3] 7.0- 8.0 sec 1.50 MBytes 12.6 Mbits/sec [ 3] 8.0- 9.0 sec 1.50 MBytes 12.6 Mbits/sec [ 3] 9.0-10.0 sec 1.62 MBytes 13.6 Mbits/sec [ 3] 0.0-10.1 sec 15.0 MBytes 12.4 Mbits/sec For some reason, it gets capped and I haven't got a clue why. Any suggestions? Edit: My link speed is reported as 270Mbps by Windows. I'm less than two metres from the router with a clear line of sight.

    Read the article

  • [c++] upload image to imageshack

    - by cinek1lol
    Hi. I would like to send pictures via a program written in C + + I wrote such a thing using curl.exe WinExec("C:\\curl\\curl.exe -H Expect: -F \"fileupload=@C:\\curl\\ok.jpg\" -F \"xml=yes\" -# \"http://www.imageshack.us/index.php\" -o data.txt -A \"Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1.1) Gecko/20061204 Firefox/2.0.0.1\" -e \"http://www.imageshack.us\"", NULL); This only works that I would like to send pictures to a variable pre-loaded char (you know what I mean? first reads the pictures into a variable and then send that variable), because now I have to specify the path to the images on disk I wanted to make this program was written in C + + using the curl library, and not the exe. I found it such a program (which some have modified) #include <stdio.h> #include <string.h> #include <iostream> #include <curl/curl.h> #include <curl/types.h> #include <curl/easy.h> int main(int argc, char *argv[]) { CURL *curl; CURLcode res; struct curl_httppost *formpost=NULL; struct curl_httppost *lastptr=NULL; struct curl_slist *headerlist=NULL; static const char buf[] = "Expect:"; curl_global_init(CURL_GLOBAL_ALL); /* Fill in the file upload field */ curl_formadd(&formpost, &lastptr, CURLFORM_COPYNAME, "send", CURLFORM_FILE, "nowy.jpg", CURLFORM_END); curl_formadd(&formpost, &lastptr, CURLFORM_COPYNAME, "nowy.jpg", CURLFORM_COPYCONTENTS, "nowy.jpg", CURLFORM_END); curl_formadd(&formpost, &lastptr, CURLFORM_COPYNAME, "submit", CURLFORM_COPYCONTENTS, "send", CURLFORM_END); curl = curl_easy_init(); headerlist = curl_slist_append(headerlist, buf); if(curl) { curl_easy_setopt(curl, CURLOPT_URL, "http://www.imageshack.us/index.php"); if ( (argc == 2) && (!strcmp(argv[1], "xml=yes")) ) curl_easy_setopt(curl, CURLOPT_HTTPHEADER, headerlist); curl_easy_setopt(curl, CURLOPT_HTTPPOST, formpost); res = curl_easy_perform(curl); curl_easy_cleanup(curl); curl_formfree(formpost); curl_slist_free_all (headerlist); } system("pause"); return 0; } I will be grateful for any help

    Read the article

  • File.Exists() returns false, but not in debug

    - by Tor Haugen
    I'm being completely confused here folks, My code throws an exception because File.Exists() returns false public override sealed TCargo ReadFile(string fileName) { if (!File.Exists(fileName)) { throw new ArgumentException("Provided file name does not exist", "fileName"); } Visual studio breaks at the throw statement, and I immediately check the value of File.Exists(fileName) in the immediate window. It returns true. When I drag the breakpoint back up to the if statement and execute it again, it throws again. fileName is an absolute path to a file. I'm not creating the file, nor writing to it (it's there all along). If I paste the path into the open dialog in Notepad, it reads the file without problems. The code is executing in a background worker. It's the only complicating factor I can think of. I am positive the file has not been opened already, either in the worker thread or elsewhere. What's going on here?

    Read the article

  • How can I compress jpeg images in Java without losing any metadata in that image?

    - by guitarpoet
    I want compress jpeg files using Java. I do it like this: Read the image as BufferedImage Write the image to another file with compression rate. OK, that seems easy, but I find the ICC color profile and the EXIF information are gone in the new file and the DPI of the image is dropped from 240 to 72. It looks different from the origin image. I use a tool like preview in OS X. It can perfectly change the quality of the image without affecting other information. Can I done this in Java? At least keep the ICC color profile and let the image color look the same as the origin photo?

    Read the article

  • (C++) Loading a file into a vector

    - by Alden
    This is probably a simple question, however I am new to C++ and I cannot figure this out. I am trying to load a binary file and load each byte to a vector. This works fine with a small file, but when I try to read larger than 410 bytes the program crashes and says: This application has requested the Runtime to terminate it in an unusual way. Please contact the application's support team for more information. I am using code::blocks on windows. This is the code: #include <iostream> #include <fstream> #include <vector> using namespace std; int main() { std::vector<char> vec; std::ifstream file; file.exceptions( std::ifstream::badbit | std::ifstream::failbit | std::ifstream::eofbit); file.open("file.bin"); file.seekg(0, std::ios::end); std::streampos length(file.tellg()); if (length) { file.seekg(0, std::ios::beg); vec.resize(static_cast<std::size_t>(length)); file.read(&vec.front(), static_cast<std::size_t>(length)); } int firstChar = static_cast<unsigned char>(vec[0]); cout << firstChar <<endl; return 0; } Thank you for your help!

    Read the article

  • Java SWT - dissolve (fade) from one image to the next.

    - by carillonator
    I'm pretty new to Java and SWT, hoping to have one image dissolve into the next. I have one image now in a Label (relevant code): Device dev = shell.getDisplay(); try { Image photo = new Image(dev, "photo.jpg"); } catch(Exception e) { } Label label = new Label(shell, SWT.IMAGE_JPEG); label.setImage(photo); Now I'd like photo to fade into a different image at a speed that I specify. Is this possible as set up here, or do I need to delve more into the org.eclipse.swt.graphics api? Also, this will be a slide show that may contain hundreds of photos, only ever moving forward (never back to a previous image)---considering this, is there something I explicitly need to do in order to remove the old images from memory? Thanks!!

    Read the article

  • How can i use the Orientation correct for images

    - by user3578109
    I´m learning android/java by myself @the moment and i have a problem with a part of my app i´m learning on. I made the code with help of the www and my problem is that if i open an image from the gallery it´s send to the edit activity but in the activity pictures what are made in portrait mode are displayed always wrong (90° to the right side).... The codes are Matrix private Bitmap rotateBitmapToOrientation(Bitmap b, int orientation){ Matrix matrix = new Matrix(); matrix.postRotate(orientation); Canvas offscreenCanvas = new Canvas(); offscreenCanvas.drawBitmap(b, matrix, null); return b; } and the other one @Override protected void onActivityResult(int requestCode, int resultCode, Intent data) { super.onActivityResult(requestCode, resultCode, data); switch (requestCode) { case PICK_IMAGE_FROM_GALLERY: { if (resultCode == RESULT_OK) { Log.d(TAG, "Got Picture!"); Log.d(TAG,"File type - " + data.getType()); Uri photoUri = data.getData(); if (photoUri != null) { try { String[] filePathColumn = {MediaStore.Images.Media.DATA}; String[] orientationColumn = {MediaStore.Images.Media.ORIENTATION}; int orientation = -1; Cursor cursor = getContentResolver().query(photoUri, filePathColumn, null, null, null); cursor.moveToFirst(); int columnIndex = cursor.getColumnIndex(filePathColumn[0]); String filePath = cursor.getString(columnIndex); cursor.close(); cursor = getContentResolver().query(photoUri, orientationColumn, null, null, null); if(cursor != null && cursor.moveToFirst()){ orientation = cursor.getInt(cursor.getColumnIndex(orientationColumn[0])); } cursor.close(); HashMap<String, Integer> pRes = this.getImageResolutionSetting(); Bitmap shrunkenBitmap = FileUtilsHelper.shrinkBitmap(filePath, pRes.get("width"), pRes.get("height")); shrunkenBitmap = rotateBitmapToOrientation(shrunkenBitmap, orientation); String res = FileUtilsHelper.saveBitmapAsJpeg(shrunkenBitmap, this); Log.d(TAG,"File Path: " + res); shrunkenBitmap.recycle(); Intent editImage = new Intent(this, EditImage.class); editImage.addFlags(Intent.FLAG_ACTIVITY_FORWARD_RESULT); editImage.putExtra("stuff.path", res); startActivity(editImage); }catch(Exception e){ Toast.makeText(this, R.string.cant_save_image,Toast.LENGTH_SHORT).show(); } } } } break; } }} I don´t know what i´m doing wrong... I could really need a teacher on that :) Thx for your help dudes!!

    Read the article

  • System.IO.File.ReadAllText(path) does not read the html file.

    - by Harikrishna
    I want to read the html file.And for that I use System.IO.File.ReadAllText(path).It can read all the html file but there is one file which is not read through this function. I have also used using (StreamReader reader = File.OpenText(fileName)) { text = reader.ReadToEnd(); But still there is same problem. What is the reason can be there ? And for that what can be the solution ? Or any other way to read the file ?

    Read the article

  • Convert PDF to Image Batch

    - by tro
    I am working on a solution where I can convert pdf files to images. I am using the following example from codeproject: http://www.codeproject.com/Articles/317700/Convert-a-PDF-into-a-series-of-images-using-Csharp?msg=4134859#xx4134859xx now I tried with the following code to generate from more then 1000 pdf files new images: using Cyotek.GhostScript; using Cyotek.GhostScript.PdfConversion; using System; using System.Collections.Generic; using System.Drawing; using System.IO; using System.Linq; using System.Text; using System.Threading.Tasks; namespace RefClass_PDF2Image { class Program { static void Main(string[] args) { string outputPath = Properties.Settings.Default.outputPath; string pdfPath = Properties.Settings.Default.pdfPath; if (!Directory.Exists(outputPath)) { Console.WriteLine("Der angegebene Pfad " + outputPath + " für den Export wurde nicht gefunden. Bitte ändern Sie den Pfad (outputPath) in der App.Config Datei."); return; } else { Console.WriteLine("Output Pfad: " + outputPath + " gefunden."); } if (!Directory.Exists(pdfPath)) { Console.WriteLine("Der angegebene Pfad " + pdfPath + " zu den PDF Zeichnungen wurde nicht gefunden. Bitte ändern Sie den Pfad (pdfPath) in der App.Config Datei."); return; } else { Console.WriteLine("PDF Pfad: " + pdfPath + " gefunden."); } Pdf2ImageSettings settings = GetPDFSettings(); DateTime start = DateTime.Now; TimeSpan span; Console.WriteLine(""); Console.WriteLine("Extraktion der PDF Zeichnungen wird gestartet: " + start.ToShortTimeString()); Console.WriteLine(""); DirectoryInfo diretoryInfo = new DirectoryInfo(pdfPath); DirectoryInfo[] directories = diretoryInfo.GetDirectories(); Console.WriteLine(""); Console.WriteLine("Es wurden " + directories.Length + " verschiedende Verzeichnisse gefunden."); Console.WriteLine(""); List<string> filenamesPDF = Directory.GetFiles(pdfPath, "*.pdf*", SearchOption.AllDirectories).Select(x => Path.GetFullPath(x)).ToList(); List<string> filenamesOutput = Directory.GetFiles(outputPath, "*.*", SearchOption.AllDirectories).Select(x => Path.GetFullPath(x)).ToList(); Console.WriteLine(""); Console.WriteLine("Es wurden " + filenamesPDF.Count + " verschiedende PDF Zeichnungen gefunden."); Console.WriteLine(""); List<string> newFileNames = new List<string>(); int cutLength = pdfPath.Length; for (int i = 0; i < filenamesPDF.Count; i++) { string temp = filenamesPDF[i].Remove(0, cutLength); temp = outputPath + temp; temp = temp.Replace("pdf", "jpg"); newFileNames.Add(temp); } for (int i = 0; i < filenamesPDF.Count; i++) { FileInfo fi = new FileInfo(newFileNames[i]); if (!fi.Exists) { if (!Directory.Exists(fi.DirectoryName)) { Directory.CreateDirectory(fi.DirectoryName); } Bitmap firstPage = new Pdf2Image(filenamesPDF[i], settings).GetImage(); firstPage.Save(newFileNames[i], System.Drawing.Imaging.ImageFormat.Jpeg); firstPage.Dispose(); } //if (i % 20 == 0) //{ // GC.Collect(); // GC.WaitForPendingFinalizers(); //} } Console.ReadLine(); } private static Pdf2ImageSettings GetPDFSettings() { Pdf2ImageSettings settings; settings = new Pdf2ImageSettings(); settings.AntiAliasMode = AntiAliasMode.Medium; settings.Dpi = 150; settings.GridFitMode = GridFitMode.Topological; settings.ImageFormat = ImageFormat.Png24; settings.TrimMode = PdfTrimMode.CropBox; return settings; } } } unfortunately, I always get in the Pdf2Image.cs an out of memory exception. here the code: public Bitmap GetImage(int pageNumber) { Bitmap result; string workFile; //if (pageNumber < 1 || pageNumber > this.PageCount) // throw new ArgumentException("Page number is out of bounds", "pageNumber"); if (pageNumber < 1) throw new ArgumentException("Page number is out of bounds", "pageNumber"); workFile = Path.GetTempFileName(); try { this.ConvertPdfPageToImage(workFile, pageNumber); using (FileStream stream = new FileStream(workFile, FileMode.Open, FileAccess.Read)) { result = new Bitmap(stream); // --->>> here is the out of memory exception stream.Close(); stream.Dispose(); } } finally { File.Delete(workFile); } return result; } how can I fix that to avoid this exception? thanks for any help, tro

    Read the article

  • "File" exists or not

    - by SnailTang
    ls -il ls: cannot access éaj/p+st.ó·e: No such file or directory ls: cannot access éaj/p+st.ó·e: No such file or directory ls: cannot access é@j/p¦ft.¦·N: No such file or directory ls: cannot access é@j/p¦ft.¦·N: No such file or directory total 55456 ? -????????? ? ? ? ? ? éaj/p+st.ó·e ? -????????? ? ? ? ? ? éaj/p+st.ó·e ? -????????? ? ? ? ? ? é@j/p¦ft.¦·N ? -????????? ? ? ? ? ? é@j/p¦ft.¦·N and when i use to show these files, i get the info: p+st.ó·e p¦ft.¦·N Please, where do these files or somethings others exist. Or what makes them show here.

    Read the article

  • file association in Windows 8

    - by Robith Nuriel Haq
    Associating a file to a program should be easy in Windows. However, i find it rather difficult when I'm working on Windows 8. associating a file to a desktop application that I install on my computer is easy because the whole operation is entirely the same with that in the previous Windows releases. What I find rather difficult is associating a file to a Metro apps that I download from the store. So far, I have been using Multimedia 8 (a metro app) to open my video files. However, this app cannot handle particular files-like *.dat-that can be associated easily to desktop video applications, such as media player classic and the like. When I try to associate my DAT files to Multimedia 8, there is indeed a "look for another app on this PC" option at the bottom of the "open with" pop up. But alas, I cannot figure out how to locate my Multimedia 8 app to which I want to associate my DAT file (as well as other video files that are not yet associated to this metro app). If anyone of you knows how to locate those metro apps, please tell me. many thanks

    Read the article

  • Is this a File Header / Magic Number?

    - by Hammer Bro.
    I've got 120,000 files (way more, actually; this is just an arbitrary subset) of an unknown type. Linux file does not identify them (not that they're necessarily Linux files), nor do any other methods I've tried. There are only two hints about them that I currently have. One is that I suspect some compression is employed -- I have metadata that claims the file sizes are always some amount larger than what I observe. The other is that in 100,000 of these files, the first 16 bytes are always: ff ee ee dd 00 00 00 00 01 00 00 00 00 00 00 00 That really looks like a file header/magic number to me, but I just can't place it. Does anyone know what kind of files this would indicate? Alternatively, can anyone convince me that these suspiciously common bytes certainly do not indicate a specific file type? UPDATE I don't know the exact reverse-engineering details, but most of the files in our case are zips after the first 29(? or so) bytes are ignored. So in practice the problem is solved (we know how to process the files) but in theory the question is still unanswered -- I don't know which application routinely prepends about 29 bytes to its zips. [I'm not sure if I should leave the question open or not at this point.]

    Read the article

  • Cropping images & SEO

    - by user1181950
    So I have a page with a bunch of images with largely varying sizes. Also the layout of the page is such that the images are all in the shape of square tiles, so just resizing will cause distorted images. What I've been doing previously is when users upload images, I resize and crop them appropriately and display the new image as the thumbnail and load full image when user clicks on it. However, I just realized this is an issue with SEO as google will crawl the thumbnails and stick the thumbnails on Google Images instead of the full images. Is there any way to show a cropped/resized image but have Google Image show the full image? I can do something with css using an enclosing div and overflow:hidden, but I'd imagine the performance on that would be pretty bad. Any suggestions? Thanks! PS. I saw this (Make google index the actual image not the thumbnail), but in my case I have users continuously uploading images, and the database of images is always changing and pretty big (thousands), so sitemap will be pretty unwieldy..

    Read the article

  • Anonymous file sharing without login window, from Windows 7 server to XP clients

    - by Niten
    I'm trying to provide machines on a small LAN with read-only, anonymous access to files shared from a Windows 7 workstation (let's call it WIN7SVR). In particular, I don't want clients to have to deal with a login window when they navigate to, e.g., \\WIN7SVR in Windows Explorer, but we do not have a domain and synchronizing accounts between the server and clients would be intractable. There are both Windows 7 and Windows XP clients that need access to these shares. I got this working for Windows 7 clients by just enabling the Guest account on WIN7SVR and setting appropriate share permissions. Other Windows 7 machines automatically try logging in as Guest, it seems, so their users don't have to deal with the login window. The problem is with the XP clients--they can access the server if the user enters "Guest" in the login window, but I don't want users to have to do that. So from what I gather, in my limited understanding of Windows file sharing, this boils down to granting null sessions access to file shares on WIN7SVR. But I've had no success so far on that front. I've tried all the following in the local group policy editor on the Windows 7 server: Set Network access: Let Everyone permissions apply to anonymous users to Enabled Set Network access: Restrict anonymous access to Named Pipes and Shares to Disabled Added the names of corresponding shares to Network access: Shares that can be accessed anonymously Added "ANONYMOUS LOGON" to Access this computer from the network under User Rights Assignment Any advice would be highly appreciated... I'm mostly a Unix guy, so I feel somewhat out of my league with Windows file sharing. I do understand that any sort of anonymous access to file shares isn't generally ideal from a security standpoint, but it's the most practical solution for us in this case, and access to our network is well enough controlled that share-level security isn't a concern.

    Read the article

  • Recovering corrupted VB.NET Form file?

    - by Omega
    Good day. This question is directly related to this one I made here: http://stackoverflow.com/questions/4911099/there-is-no-editor-available-for-form1-vb-error There, I was working on my VB.NET 2010 Express application, I saved, then a blackout came and now, apparently, I can't view the designer nor code of my Form file (Form1.vb). On StackOverflow, I was recommended to check for the From1.vb file, and try to open it on Notepad. If nothing appeared, it would mean that my file was corrupted. I open it on Notepad, and I get a blank file. It is 27kb, but it only has blank spaces. So I assume it is corrupted. I was told this place was better for dealing with corrupted files, about techniques to recover them. I use Windows7, VB.NET 2010 Express. I run Windows7 on Parallels Desktop, Mac OS X. However, I do not believe that is the problem, most likely it was that damned blackout... this is the first time that happens to me. VB.NET worked just fine for me all time (about a month and half). Thank you.

    Read the article

  • Linux file server for an inexperienced admin

    - by Pat
    A charity I volunteer for wants a file server for their mostly Windows machines (about five XP and 7 machines, with some Mac laptops every now and then). For the server, I have a PC with an Intel Core 2 Duo 3GHz proc, 4GB of DDR2 400MHz RAM, and a 500 GB HDD. (I should point out that they do not currently have any server - they are just using Windows to share a folder on one of the PCs.) What is a linux distro that is easy to configure for Windows file serving yet stable and secure enough to protect sensitive data without an expert sysadmin? I'm guessing that a Debian distro would probably fit the security bill, but I don't know of any tailored to novice sysadmins. Also, are there any killer apps for making this easy to administer and set up (as a Windows file server, in particular - this answer is a good example)? Would FreeNAS be sufficient? Once it's all set up, what are the minimum measures I need to take to keep the data secure? I found this somewhat helpful answer, but it's not specific to my question of just getting a secure file server up, running, and maintained.

    Read the article

  • Modifying value of "Rating" column within Explorer for arbitrary file types

    - by Fake Name
    Basically, I have a large body of assorted media (text, images, flash files, archives, folders, etc...) and I'm attempting to organize it. Windows Explorer has a rating column, but there seems to be no way to modify the rating of the files short of opening them in their type-specific software (e.g. Media player, or Photo viewer). However, this does not work when the file is of an unsupported type (.rar, .swf ...), or a directory. I'd be more than willing to consider a file-manager replacement (I've alreadly looked at quite a few, Directory Opus, Total Commander, etc...), or even a solution that stores the rating metadata in a hidden file in each folder, or a separate database. The one real critical requirement is the ability to sort by rating, and being filetype-agnostic. Basically, is there any way to categorize a large collection of assorted files by rating that will work with any file type, including directories? - Ideally, there would be an easy way to add arbitrary columns to windows explorer, and edit them directly. However, there seems to be no way to do this. The rating column is the next best thing.

    Read the article

  • Ruby: Is there a better way to iterate over multiple (big) files?

    - by zxcvbnm
    Here's what I'm doing (sorry for the variable names, I'm not using those in my code): File.open("out_file_1.txt", "w") do |out_1| File.open("out_file_2.txt", "w") do |out_2| File.open_and_process("in_file_1.txt", "r") do |in_1| File.open_and_process("in_file_2.txt", "r") do |in_2| while line_1 = in_1.gets do line_2 = in_2.gets #input files have the same number of lines #process data and output to files end end end end end The open_and_process method is just to open the file and close it once it's done. It's taken from the pickaxe book. Anyway, the main problem is that the code is nested too deeply. I can't load all the files' contents into memory, so I have to iterate line by line. Is there a better way to do this? Or at least prettify it?

    Read the article

  • php upload image with ftp problem

    - by ntan
    Hi, I am using the code below to upload an image through ftp $sFile=$ftp_dir."/".$image_name; $image=$database_row["image"];//image is store in database $fh = tmpfile(); $fwrite($fh, $image); $uploadFile = ftp_fput($conn_id, $sFile, $fh, FTP_ASCII); fclose($fh); The ftp is creating the file and has a size BUT the file i get is not an image.When try to open on image viewer i get error. Before switch to ftp i had this code $image=$database_row["image"];//image is store in database $file = fopen( "images/".$image_name, "w" ); fwrite( $file, $image); fclose( $file ); and was working fine, but now i have to use ftp. What am i missing.

    Read the article

< Previous Page | 64 65 66 67 68 69 70 71 72 73 74 75  | Next Page >