Multiple left joins, how to output in php
- by Dan
I have 3 tables I need to join. The contracts table is the main table, the 'jobs' and 'companies' table are extra info that can be associated to the contracts table.
so, since I want all entries from my 'contracts' table, and the 'jobs' and 'companies' data only if it exists, I wrote the query like this....
$sql = "SELECT * FROM contracts
LEFT JOIN jobs ON contracts.job_id = jobs.id
LEFT JOIN companies ON contracts.company_id = companies.id
ORDER BY contracts.end_date";
Now how would I output this in PHP? I tried this but kept getting an undefined error "Notice: Undefined index: contracts.id"...
$sql_result = mysql_query($sql,$connection) or die ("Fail.");
if(mysql_num_rows($sql_result) > 0){
while($row = mysql_fetch_array($sql_result))
{
$contract_id = stripslashes($row['contracts.id']);
$job_number = stripslashes($row['jobs.job_number']);
$company_name = stripslashes($row['companies.name']);
?>
<tr id="<?=$contract_id?>">
<td><?=$job_number?></td>
<td><?=$company_name?></td>
</tr>
<?
}
}else{
echo "No records found";
}
Any help is appreciated.
