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  • how to fix my error saying expected expression before 'else'

    - by user292489
    this program intended to read a .txt, a set of numbers, file and wwrite to another two .txt files called even amd odd as follows: #include <stdio.h> #include <stdlib.h> int main(int argc, char *argv[]) { int i=0,even,odd; int number[i]; // check to make sure that all the file names are entered if (argc != 3) { printf("Usage: executable in_file output_file\n"); exit(0); } FILE *dog = fopen(argv[1], "r"); FILE *feven= fopen(argv[2], "w"); FILE *fodd= fopen (argv[3], "w"); // check whether the file has been opened successfully if (dog == NULL) { printf("File %s cannot open!\n", argv[1]); exit(0); } //odd = fopen(argv[2], "w"); { if (i%2!=1) i++;} fprintf(feven, "%d", even); fscanf(dog, "%d", &number[i]); else { i%2==1; i++;} fprintf(fodd, "%d", odd); fscanf(dog, "%d", &number[i]); fclose(feven); fclose(fodd);

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  • Scala: Matching optional Regular Expression groups

    - by Brian Heylin
    I'm trying to match on an option group in Scala 2.8 (beta 1) with the following code: import scala.xml._ val StatementPattern = """([\w\.]+)\s*:\s*([+-])?(\d+)""".r def buildProperty(input: String): Node = input match { case StatementPattern(name, value) => <propertyWithoutSign /> case StatementPattern(name, sign, value) => <propertyWithSign /> } val withSign = "property.name: +10" val withoutSign = "property.name: 10" buildProperty(withSign) // <propertyWithSign></propertyWithSign> buildProperty(withoutSign) // <propertyWithSign></propertyWithSign> But this is not working. What is the correct way to match optional regex groups?

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  • print hierarchy data(adjacency list model) in a list(ul/ol/li)

    - by adi
    I have adjacency list model like on the page http://dev.mysql.com/tech-resources/articles/hierarchical-data.html i have make a full table containing all data ordered by level using this SELECT t1.name AS lev1, t2.name as lev2, t3.name as lev3, t4.name as lev4 FROM category AS t1 LEFT JOIN category AS t2 ON t2.parent = t1.category_id LEFT JOIN category AS t3 ON t3.parent = t2.category_id LEFT JOIN category AS t4 ON t4.parent = t3.category_id WHERE t1.name = 'ELECTRONICS'; ORDER by ..... I want to make an unordered list using php from the table Anyone can help me...

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  • Buggy Perl regular expression

    - by Tichomir Mitkov
    Hi, there I'm writing a program that has to get values from a file. In the file each line indicates an entity. Each entity has three values. For example: Value1 Value2 value3 I have a regular expresion to match them m/(.*?) (.*?) (.*?)/m; But it seems that the third value in never matched! The only way to match the third value is to add another value in the file and another "matching brackets" in the expresion. But this does not satisfy me. Thanks in Advance!

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  • xpath help substring expression

    - by NA
    Hi i have a document from which i am trying to extract a date. But the problem is within the node along with the date their is some text too. Something like <div class="postHeader"> Posted on July 20, 2009 9:22 PM PDT </div> From this tag i just want the date item not the Posted on text. something like ./xhtml:div[@class = 'postHeader'] is getting everything. and to be precise, the document i have is basically a nodelist of this elements for eg i will get 10 nodes of these elements with different date values but to be worse the problem is sometime inside these tags some random other tags also pops us like anchors etc. Can i write a universal expath which will just get the date out of the div tag?

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  • regular expression for letters, numbers and - _ .

    - by Jorre
    I'm having trouble checking in PHP if a value is is any of the following combinations letters (upper or lowercase) numbers (0-9) underscore (_) dash (-) point (.) no spaces! or other characters a few examples: OK: "screen123.css" OK: "screen-new-file.css" OK: "screen_new.js" NOT OK: "screen new file.css" I guess I need a regex for this, since I need to throw an error when a give string has other characters in it than the ones mentioned above.

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  • regular expression for emails NOT ending with replace script

    - by corroded
    I'm currently modifying my regex for this: http://stackoverflow.com/questions/2782031/extracting-email-addresses-in-an-html-block-in-ruby-rails basically, im making another obfuscator that uses ROT13 by parsing a block of text for all links that contain a mailto referrer(using hpricot). One use case this doesn't catch is that if the user just typed in an email address(without turning it into a link via tinymce) So here's the basic flow of my method: 1. parse a block of text for all tags with href="mailto:..." 2. replace each tag with a javascript function that changes this into ROT13 (using this script: http://unixmonkey.net/?p=20) 3. once all links are obfuscated, pass the resulting block of text into another function that parses for all emails(this one has an email regex that reverses the email address and then adds a span to that email - to reverse it back) step 3 is supposed to clean the block of text for remaining emails that AREN'T in a href tags(meaning it wasn't parsed by hpricot). Problem with this is that the emails that were converted to ROT13 are still found by my regex. What i want to catch are just emails that WEREN'T CONVERTED to ROT13. How do i do this? well all emails the WERE CONVERTED have a trailing "'.replace" in them. meaning, i need to get all emails WITHOUT that string. so far i have this regex: /\b([A-Z0-9._%+-]+@[A-Z0-9.-]+.[A-Z]{2,4}('.replace))\b/i but this gets all the emails with the trailing '.replace i want to get the opposite and I'm currently stumped with this. any help from regex gurus out there? MORE INFO: Here's the regex + the block of text im parsing: http://www.rubular.com/r/NqXIHrNqjI as you can see, the first two 'email addresses' are already obfuscated using ROT13. I need a regex that gets the emails [email protected] and [email protected]

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  • Why does the answer print out twice?

    - by rEgonicS
    I made a program that returns the product a*b*c where a,b,c are pythagorean triples and add up to 1000. The program does output the correct answer but does it twice. I was curious as to why this is so.After playing around with it a bit I found out that it prints out when a = 200 b = 375 c = 425. And once again when a = 375 b = 200 c = 425. *How do you put your code into a "code" block? It does it automatically for part of the code but as you can see the top portion and bottom line is left out. bool isPythagTriple(int a, int b, int c); int main() { for(int a = 1; a < 1000; a++) { for(int b = 1; b < 1000; b++) { for(int c = 1; c < 1000; c++) { if( ((a+b+c)==1000) && isPythagTriple(a,b,c) ) { cout << a*b*c << " "; break; } } } } return 0; } bool isPythagTriple(int a, int b, int c) { if( (a*a)+(b*b)-(c*c) == 0 ) return true; else return false; }

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  • Grep expression with special file names

    - by user2919185
    i am a real beginner in csh/tcsh scripting and that's why i need your help. The problem is I have to go through some regular files in directories and find those files, that have their own name in its content. In the following piece of script is cycle in which I am going through paths and using grep to find the file's name in its content. What is surely correct is $something:q - is array of paths where i have to find files. The next variable is name in which is only name of current file. for example: /home/computer/text.txt (paths) and: text.txt (name) And my biggest problem is to find names of files in their content. It's quite difficult for me to write correct grep for this, cause the names of files and directories that i am passing through are mad. Here are some of them: /home/OS/pocitacove/testovaci_adresar/z/test4.pre_expertov/!_1 /home/OS/pocitacove/testovaci_adresar/z/test4.pre_expertov/dam/$user/:e/'/-r /home/OS/pocitacove/testovaci_adresar/z/test3/skusime/ taketo/ taketo /home/OS/pocitacove/testovaci_adresar/z/test4.pre_expertov/.-bla/.-bla/.a=b /home/OS/pocitacove/testovaci_adresar/z/test4.pre_expertov/.-bla/.-bla/@ /home/OS/pocitacove/testovaci_adresar/z/test4.pre_expertov/.-bla/.-bla/: /home/OS/pocitacove/testovaci_adresar/z/test4.pre_expertov/.-bla/.-bla/'ano' foreach paths ($something:q) set name = "$paths:t" @ number = (`grep -Ec "$name" "$paths"`) if ($number != 0) then echo -n "$paths " echo $number endif @ number = 0 end

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  • [Python] OR in regular expression?

    - by www.yegorov-p.ru
    Hello. I have text file with several thousands lines. I want to parse this file into database and decided to write a regexp. Here's part of file: blablabla checked=12 unchecked=1 blablabla unchecked=13 blablabla checked=14 As a result, I would like to get something like (12,1) (0,13) (14,0) Is it possible?

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  • How to convert this procedural programming to object-oriented programming?

    - by manus91
    I have a source code that is needed to be converted by creating classes, objects and methods. So far, I've just done by converting the initial main into a separate class. But I don't know what to do with constructor and which variables are supposed to be private. This is the code : import java.util.*; public class Card{ private static void shuffle(int[][] cards){ List<Integer> randoms = new ArrayList<Integer>(); Random randomizer = new Random(); for(int i = 0; i < 8;) { int r = randomizer.nextInt(8)+1; if(!randoms.contains(r)) { randoms.add(r); i++; } } List<Integer> clonedList = new ArrayList<Integer>(); clonedList.addAll(randoms); Collections.shuffle(clonedList); randoms.addAll(clonedList); Collections.shuffle(randoms); int i=0; for(int r=0; r < 4; r++){ for(int c=0; c < 4; c++){ cards[r][c] = randoms.get(i); i++; } } } public static void play() throws InterruptedException { int ans = 1; int preview; int r1,c1,r2,c2; int[][] cards = new int[4][4]; boolean[][] cardstatus = new boolean[4][4]; boolean gameover = false; int moves; Scanner input = new Scanner(System.in); do{ moves = 0; shuffle(cards); System.out.print("Enter the time(0 to 5) in seconds for the preview of the answer : "); preview = input.nextInt(); while((preview<0) || (preview>5)){ System.out.print("Invalid time!! Re-enter time(0 - 5) : "); preview = input.nextInt(); } preview = 1000*preview; System.out.println(" "); for (int i =0; i<4;i++){ for (int j=0;j<4;j++){ System.out.print(cards[i][j]); System.out.print(" "); } System.out.println(""); System.out.println(""); } Thread.sleep(preview); for(int b=0;b<25;b++){ System.out.println(" "); } for(int r=0;r<4;r++){ for(int c=0;c<4;c++){ System.out.print("*"); System.out.print(" "); cardstatus[r][c] = false; } System.out.println(""); System.out.println(" "); } System.out.println(""); do{ do{ System.out.print("Please insert the first card row : "); r1 = input.nextInt(); while((r1<1) || (r1>4)){ System.out.print("Invalid coordinate!! Re-enter first card row : "); r1 = input.nextInt(); } System.out.print("Please insert the first card column : "); c1 = input.nextInt(); while((c1<1) || (c1>4)){ System.out.print("Invalid coordinate!! Re-enter first card column : "); c1 = input.nextInt(); } if(cardstatus[r1-1][c1-1] == true){ System.out.println("The card is already flipped!! Select another card."); System.out.println(""); } }while(cardstatus[r1-1][c1-1] != false); do{ System.out.print("Please insert the second card row : "); r2 = input.nextInt(); while((r2<1) || (r2>4)){ System.out.print("Invalid coordinate!! Re-enter second card row : "); r2 = input.nextInt(); } System.out.print("Please insert the second card column : "); c2 = input.nextInt(); while((c2<1) || (c2>4)){ System.out.print("Invalid coordinate!! Re-enter second card column : "); c2 = input.nextInt(); } if(cardstatus[r2-1][c2-1] == true){ System.out.println("The card is already flipped!! Select another card."); } if((r1==r2)&&(c1==c2)){ System.out.println("You can't select the same card twice!!"); continue; } }while(cardstatus[r2-1][c2-1] != false); r1--; c1--; r2--; c2--; System.out.println(""); System.out.println(""); System.out.println(""); for(int r=0;r<4;r++){ for(int c=0;c<4;c++){ if((r==r1)&&(c==c1)){ System.out.print(cards[r][c]); System.out.print(" "); } else if((r==r2)&&(c==c2)){ System.out.print(cards[r][c]); System.out.print(" "); } else if(cardstatus[r][c] == true){ System.out.print(cards[r][c]); System.out.print(" "); } else{ System.out.print("*"); System.out.print(" "); } } System.out.println(" "); System.out.println(" "); } System.out.println(""); if(cards[r1][c1] == cards[r2][c2]){ System.out.println("Cards Matched!!"); cardstatus[r1][c1] = true; cardstatus[r2][c2] = true; } else{ System.out.println("No cards match!!"); } Thread.sleep(2000); for(int b=0;b<25;b++){ System.out.println(""); } for(int r=0;r<4;r++){ for(int c=0;c<4;c++){ if(cardstatus[r][c] == true){ System.out.print(cards[r][c]); System.out.print(" "); } else{ System.out.print("*"); System.out.print(" "); } } System.out.println(""); System.out.println(" "); } System.out.println(""); System.out.println(""); System.out.println(""); gameover = true; for(int r=0;r<4;r++){ for( int c=0;c<4;c++){ if(cardstatus[r][c]==false){ gameover = false; break; } } if(gameover==false){ break; } } moves++; }while(gameover != true); System.out.println("Congratulations, you won!!"); System.out.println("It required " + moves + " moves to finish it."); System.out.println(""); System.out.print("Would you like to play again? (1=Yes / 0=No) : "); ans = input.nextInt(); }while(ans == 1); } } The main class is: import java.util.*; public class PlayCard{ public static void main(String[] args) throws InterruptedException{ Card game = new Card(); game.play(); } } Should I simplify the Card class by creating other classes? Through this code, my javadoc has no constructtor. So i need help on this!

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  • How to print element values when iterating through XML document in PHP

    - by pharma_joe
    I am iterating through the results of a service call to yahoo news thus: //Send service request if (!$yahooResults = file_get_contents($yahooRequest)) { echo 'Error processing service request'; } //Read result into xml document $yahooResultXml = new DOMDocument('1.0', 'UTF-8'); $yahooResultXml-loadXML($yahooResults); //Build page include_once('components/pageHeader.php'); echo 'Search Results'; //echo $yahooResultXml-saveHTML(); //Iterate over each Result node $stories = $yahooResultXml-getElementsByTagName('Result'); foreach ($stories as $story) { //Title //Summary //Url //Source //Language //Publish Date //Modification Date } include_once('components/pageFooter.php'); Each Title is in a Title node within a Result Node. I cannot figure out how to simply echo the content of the Title node!

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  • Regular expression and newline

    - by Ockonal
    Hello guys, I have such text: <[email protected]> If you do so, please include this problem report. <[email protected]> You can delete your own text from the attached returned message. The mail system <[email protected]>: connect to *.net[82.*.86.*]: Connection timed out I have to parse email from it. Could you help me with this job? upd There could be another email addresses in <%here%. There should be connection between 'The mail system' text. I need in email which goes after that text.

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  • lambda expression for a query on two tables that returns records from one table

    - by peetee
    I have two tables TableA (articles) int id int Type string name and TableB (compatibles) int linked_ID int tableA_ID TableA records: id=1, Type=0, name="ArticleA" id=2, Type=1, name="ArticleB" id=3, Type=2, name="ArticleC" id=4, Type=1, name="ArticleD" TableB records: linked_ID= 1, tableA_ID=2 linked_ID= 1, tableA_ID=3 linked_ID= 1, tableA_ID=4 TableB has a list of arcicels that are compatible to a certain article. I am quite new to queries (didn't need them in my projects yet). But as C# and WPF allow some pretty cool automation with Binding I would like to add a binding that returns the following: Give me all articles that are of Type 1 and compatible to my selected article (id=1). The simple part of it works well (articles has a list of all articles): private ObservableCollection<Article> _articles = new ObservableCollection<Article>(); [fill it with the available articles] and then: comboBoxArticles.ItemsSource = _articles.AsBindable().Where( c => c.Typ == 0 ); How can I extend the Where clause to query another table? Thanks a lot in advance.

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  • How to let an average user design a boolean expression graphically

    - by Svein Bringsli
    In our application there's a list of customers, and a list of keywords (among other things). Each customer can have a number of keywords, but it's not mandatory. So for instance, one customer can have the keywords "retail" and "chain", one can have only "contractor" and a third can have none at all. I want to let the user make a selection of customers based on these keywords, but not having to write (retail AND chain) or contractor and not wholesale I would like to make it as user-friendly as possible, and ideally with only "simple" controls, like checkboxes, comboboxes etc. Does anyone have any suggestions on how to design this? Or maybe some examples of applications where there are similar functionality?

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  • Using regular expression to trim html

    - by Tim
    Been trying to solve this for a while now. I need a regex to strip the newlines, tabs and spaces between the html tags demonstrated in the example below: Source: <html> <head> <title> Some title </title> </head> </html> Wanted result: <html><head><title>Some title</title></head></html> The trimming of the whitespaces before the "Some title" is optional. I'd be grateful for any help

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  • Why my print current date time (C language) gives different answer

    - by vodkhang
    I want to get the current date (day, mon and year). I found out there are some functions in C to do that like ctime (get the string of time), localtime and gmtime. I tried with following code but the output are different. I get this output: The date and time is Tue Apr 20 2010 (which is correct) The year is : 110 The year is : 110. Does anybody know why? int main(int argc, char** argv) { time_t now; if((now = time(NULL)) == (time_t)-1) { puts("Failure in getting time"); } else { printf("The date and time is: %s\n", ctime(&now)); printf("The year is: %ld\n", localtime(&now)->tm_year); printf("The year is: %ld\n", gmtime(&now)->tm_year); } getchar(); }

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  • regular expression and escaping

    - by pstanton
    Sorry if this has been asked, my search brought up many off topic posts. I'm trying to convert wildcards from a user defined search string (wildcard is "*") to postgresql like wildcard "%". I'd like to handle escaping so that "%" => "\%" and "\*" => "*" I know i could replace \* with something else prior to replacing * and then swap it back, but i'd prefer not to and instead only convert * using a pattern that selects it when not proceeded by \. String convertWildcard(String like) { like = like.replaceAll("%", "\\%"); like = like.replaceAll("\\*", "%"); return like; } Assert.assertEquals("%", convertWildcard("*")); Assert.assertEquals("\%", convertWildcard("%")); Assert.assertEquals("*", convertWildcard("\*")); // FAIL Assert.assertEquals("a%b", convertWildcard("a*b")); Assert.assertEquals("a\%b", convertWildcard("a%b")); Assert.assertEquals("a*b", convertWildcard("a\*b")); // FAIL ideas welcome.

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  • Regular expression to Match addresses

    - by Burfi
    I have below set of strings to be searched : 1Dept Neurosci, The Univ. of New Mexico, ALBUQUERQUE, NM; 2Mol. and Human Genet., Baylor Col. of Med., Houston,, TX; 3Psychiatry, Univ. of Texas Southwestern Med. Ctr., Dallas, TX; 4Clin. Genet., Erasmus Univ. Med. Ctr., Rotterdam, Netherlands; 5Human Genet., Emory Univ., Atlanta, GA Above is a set of addresses , which starts with a digit (used to link it to the person).Need to search all the address as : 1Dept Neurosci, The Univ. of New Mexico, ALBUQUERQUE, NM 2Mol. and Human Genet., Baylor Col. of Med., Houston,, TX 3Psychiatry, Univ. of Texas Southwestern Med. Ctr., Dallas, TX 4Clin. Genet., ErasmusUniv. Med. Ctr., Rotterdam, Netherlands 5Human Genet., Emory Univ.Atlanta, GA I have written the below Regex : \d\w+,* It only matches a digit followed by a word . How can I modify it .Please suggest is there any better way.

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  • jQuery child selector expression

    - by Saiful
    <div id="div"> <div> <!-- first level --> <div> <!-- second level --> <div>1.1</div> <!-- third level --> <div>1.2</div> </div> <div> <div></div> <div>2.2</div> </div> </div> </div> What are the jQuery selector expressions for selecting the followings: 1. div commented by first level 2. divs commented by second level 3. divs commented by third level

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