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  • Very basic beginner Ruby question to do with elsif and ranges [migrated]

    - by MattKneale
    I've been trying to get to grasps with Ruby (for all of an hour) and this is my first language. I've got the following code: var_comparison = 5 print "Please enter a number: " my_num = Integer(gets.chomp) if my_num > var_comparison print "You picked a number greater than 5!" elsif my_num < var_comparison print "You picked a number less than 5!" elsif my_num > 99 print "Your number is too large, man." else print "You picked the number 5!" end Clearly the interpreter has no way of distinguishing between accepting the rule 5 or 99. How do I make it so that any number between 6-99 returns "You picked a number greater than 5!", but a number 100 or greater returns "Your number is too large, man!"? Do I need to specifically state a range somehow? How would I best do that? Would it by the normal range methods e.g. if my_num 6..99 or if my_num.between(6..99) ?

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  • Map rendering Libgdx Java

    - by user3165683
    Ok, so I am trying to create a 2D non-movable random tiled map. This is what I have so far: private void generateTile(){ System.out.print("tiletry1"); while(loadedTiles != 8100){ System.out.print("tiletry"); Texture currentTile = null; int tileX = 0; int tileY = 0; if (tileX == 120); tileY = 16; tileX = 0; game.batch.begin(); switch(MathUtils.random(2)){ case 0: //game.batch.draw(tile1, tileX, tileY); System.out.print("tile1"); currentTile = tile1; break; case 1: //game.batch.draw(tile2, tileX, tileY); System.out.print("tile2"); currentTile = tile2; break; case 2: //game.batch.draw(tile3, tileX, tileY); System.out.print("tile3"); currentTile = tile3; break; } tileX+=16; loadedTiles ++; game.batch.draw(currentTile, tileX, tileY); game.batch.end(); } } However, I can't see any of the tiles and the screen just looks green. This method is above my render method which I have: camera.update(); batch.setProjectionMatrix(camera.combined); Gdx.gl.glClear(GL20.GL_COLOR_BUFFER_BIT); game.batch.begin(); //other render stuff Why am I not able to see the tiles?

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  • Generate random number histogram using java

    - by Chewart
    Histogram -------------------------------------------------------- 1 ****(4) 2 ******(6) 3 ***********(11) 4 *****************(17) 5 **************************(26) 6 *************************(25) 7 *******(7) 8 ***(3) 9 (0) 10 *(1) -------------------------------------------------------- basically above is what my prgram needs to do.. im missing something somewhere any help would be great :) import java.util.Random; public class Histogram { /*This is a program to generate random number histogram between 1 and 100 and generate a table */ public static void main(String args[]) { int [] randarray = new int [80]; Random random = new Random(); System.out.println("Histogram"); System.out.println("---------"); int i ; for ( i = 0; i<randarray.length;i++) { int temp = random.nextInt(100); //random numbers up to number value 100 randarray[i] = temp; } int [] histo = new int [10]; for ( i = 0; i<10; i++) { /* %03d\t, this generates the random numbers to three decimal places so the numbers are generated with a full number or number with 00's or one 0*/ if (randarray[i] <= 10) { histo[i] = histo[i] + 1; //System.out.println("*"); } else if ( randarray[i] <= 20){ histo[i] = histo[i] + 1; } else if (randarray[i] <= 30){ histo[i] = histo[i] + 1; } else if ( randarray[i] <= 40){ histo[i] = histo[i] + 1; } else if (randarray[i] <= 50){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=60){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=70){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=80){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=90){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=100){ histo[i] = histo[i] + 1; } switch (randarray[i]) { case 1: System.out.print("0-10 | "); break; case 2: System.out.print("11-20 | "); break; case 3: System.out.print("21-30 | "); break; case 4: System.out.print("31-40 | "); break; case 5: System.out.print("41-50 | "); break; case 6: System.out.print("51-60 | "); break; case 7: System.out.print("61-70 | "); break; case 8: System.out.print("71-80 | "); break; case 9: System.out.print("81-90 | "); break; case 10: System.out.print("91-100 | "); } for (int i = 0; i < 80; i++) { randomNumber = random.nextInt(100) index = (randomNumber - 1) / 2; histo[index]++; } } } }

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  • find substring and indices in mips

    - by ccc
    im trying find out substring and first occurrence indices. but something wrong. im comparing each element of pattern array and each element of string array until pointer reach to '\0'. and if any characater found it keep in temp array. and increasing pointers +1. whats the problem. algorithm is totaly wrong ? #Note: $v0 is a symbolic name used by the assember for $2. # $a0 is a symbolic name used by the assember for $4. .data prompt_str: .asciiz "Please type a text string: " prompt_ptr: .asciiz "Please type a pattern string: " print_yes: .asciiz "Yes, there is a match." print_no: .asciiz "No, there is no match." text_str: .asciiz "Text string : " pattern_str: .asciiz "Pattern string : " print_out: .asciiz "Output to be produced :" print_dash: .asciiz "----------------------" print_index: .asciiz "Starting index :" print_msg : .asciiz "Length of longest partial match = " nl: .asciiz "\n" str : .space 81 ptr : .space 81 tmp : .space 81 .text main: la $a0, prompt_str li $v0, 4 #print_string command. syscall la $a0,str #read string li $a1,81 li $v0,8 syscall la $t0,str #move string to $t0 la $a0,prompt_ptr li $v0,4 #print pattern command syscall la $a0,ptr #read pattern li $a1,81 li $v0,8 syscall la $t1,ptr #move pattern to $t1 la $t5,tmp #move temp to $t5 lb $t2,0($t0) #pointer first element array of string lb $t3,0($t1) #pointer first element array of pattern lb $t6,0($t5) #pointer first element array of temp loop : beq $t3,$0,end_loop beq $t2,$t3,match addiu $t0,$t0,1 j loop match : move $t6,$t2 addiu $t5,$t5,1 addiu $t0,$t0,1 addiu $t1,$t1,1 j print_match print_match : la $a0,text_str #print string li $v0,4 syscall move $a0,$t0 li $v0,4 syscall la $a0,nl #print newline character li $v0,4 syscall la $a0,pattern_str #print pattern string li $v0,4 syscall move $a0,$t1 li $v0,4 syscall la $a0,nl #print newline character li $v0,4 syscall la $a0,print_out #print output line and newline character li $v0,4 syscall la $a0,nl li $v0,4 syscall la $a0,print_dash li $v0,4 syscall la $a0,print_yes li $v0,4 syscall la $a0,print_index #print starting index li $v0,4 syscall li $v0,10 syscall end_loop : li $v0,10 syscall

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  • Make Python Socket Server More Efficient

    - by BenMills
    I have very little experience working with sockets and multithreaded programming so to learn more I decided to see if I could hack together a little python socket server to power a chat room. I ended up getting it working pretty well but then I noticed my server's CPU usage spiked up over 100% when I had it running in the background. Here is my code in full: http://gist.github.com/332132 I know this is a pretty open ended question so besides just helping with my code are there any good articles I could read that could help me learn more about this? My full code: import select import socket import sys import threading from daemon import Daemon class Server: def __init__(self): self.host = '' self.port = 9998 self.backlog = 5 self.size = 1024 self.server = None self.threads = [] self.send_count = 0 def open_socket(self): try: self.server = socket.socket(socket.AF_INET6, socket.SOCK_STREAM) self.server.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1) self.server.bind((self.host,self.port)) self.server.listen(5) print "Server Started..." except socket.error, (value,message): if self.server: self.server.close() print "Could not open socket: " + message sys.exit(1) def remove_thread(self, t): t.join() def send_to_children(self, msg): self.send_count = 0 for t in self.threads: t.send_msg(msg) print 'Sent to '+str(self.send_count)+" of "+str(len(self.threads)) def run(self): self.open_socket() input = [self.server,sys.stdin] running = 1 while running: inputready,outputready,exceptready = select.select(input,[],[]) for s in inputready: if s == self.server: # handle the server socket c = Client(self.server.accept(), self) c.start() self.threads.append(c) print "Num of clients: "+str(len(self.threads)) self.server.close() for c in self.threads: c.join() class Client(threading.Thread): def __init__(self,(client,address), server): threading.Thread.__init__(self) self.client = client self.address = address self.size = 1024 self.server = server self.running = True def send_msg(self, msg): if self.running: self.client.send(msg) self.server.send_count += 1 def run(self): while self.running: data = self.client.recv(self.size) if data: print data self.server.send_to_children(data) else: self.running = False self.server.threads.remove(self) self.client.close() """ Run Server """ class DaemonServer(Daemon): def run(self): s = Server() s.run() if __name__ == "__main__": d = DaemonServer('/var/servers/fserver.pid') if len(sys.argv) == 2: if 'start' == sys.argv[1]: d.start() elif 'stop' == sys.argv[1]: d.stop() elif 'restart' == sys.argv[1]: d.restart() else: print "Unknown command" sys.exit(2) sys.exit(0) else: print "usage: %s start|stop|restart" % sys.argv[0] sys.exit(2)

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  • Simple way to decrease values without making a new attribute?

    - by Jam
    I'm making a program where you're firing a 'blaster', and I have 5 ammo. I'm blasting an alien who has 5 health. At the end I instantiate the player and make him blast 6 times to check that the program works correctly. But the way I've done it makes it so that the amount won't decrease. Is there an easy fix to this, or do I just have to make a new attribute for ammo and health? Here's what I have: class Player(object): """ A player in a shooter game. """ def blast(self, enemy, ammo=5): if ammo>=1: ammo-=1 print "You have blasted the alien." print "You have", ammo, "ammunition left." enemy.die(5) else: print "You are out of ammunition!" class Alien(object): """ An alien in a shooter game. """ def die(self, health=5): if health>=1: health-=1 print "The alien is wounded. He now has", health, "health left." elif health==0: health-=1 print "The alien gasps and says, 'Oh, this is it. This is the big one. \n" \ "Yes, it's getting dark now. Tell my 1.6 million larvae that I loved them... \n" \ "Good-bye, cruel universe.'" else: print "The alien's corpse sits up momentarily and says, 'No need to blast me, I'm dead already!" # main print "\t\tDeath of an Alien\n" hero = Player() invader = Alien() hero.blast(invader) hero.blast(invader) hero.blast(invader) hero.blast(invader) hero.blast(invader) hero.blast(invader) raw_input("\n\nPress the enter key to exit.")

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  • Problem running a Python program, error: Name 's' is not defined.

    - by Sergio Tapia
    Here's my code: #This is a game to guess a random number. import random guessTaken = 0 print("Hello! What's your name kid") myName = input() number = random.randint(1,20) print("Well, " + myName + ", I'm thinking of a number between 1 and 20.") while guessTaken < 6: print("Take a guess.") guess = input() guess = int(guess) guessTaken = guessTaken + 1 if guess < number: print("You guessed a little bit too low.") if guess > number: print("You guessed a little too high.") if guess == number: break if guess == number: guessTaken = str(guessTaken) print("Well done " + myName + "! You guessed the number in " + guessTaken + " guesses!") if guess != number: number = str(number) print("No dice kid. I was thinking of this number: " + number) This is the error I get: Name error: Name 's' is not defined. I think the problem may be that I have Python 3 installed, but the program is being interpreted by Python 2.6. I'm using Linux Mint if that can help you guys help me. Using Geany as the IDE and pressing F5 to test it. It may be loading 2.6 by default, but I don't really know. :( Edit: Error 1 is: File "GuessingGame.py", line 8, in <Module> myName = input() Error 2 is: File <string>, line 1, in <Module>

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  • Python Twisted Client Connection Lost

    - by MovieYoda
    I have this twisted client, which connects with a twisted server having an index. I ran this client from command-line. It worked fine. Now I modified it to run in loop (see main()) so that I can keep querying. But the client runs only once. Next time it simply says connection lost \n Connection lost - goodbye!. What am i doing wrong? In the loop I am reconnecting to the server, it that wrong? from twisted.internet import reactor from twisted.internet import protocol from settings import AS_SERVER_HOST, AS_SERVER_PORT # a client protocol class Spell_client(protocol.Protocol): """Once connected, send a message, then print the result.""" def connectionMade(self): self.transport.write(self.factory.query) def dataReceived(self, data): "As soon as any data is received, write it back." if data == '!': self.factory.results = '' else: self.factory.results = data self.transport.loseConnection() def connectionLost(self, reason): print "\tconnection lost" class Spell_Factory(protocol.ClientFactory): protocol = Spell_client def __init__(self, query): self.query = query self.results = '' def clientConnectionFailed(self, connector, reason): print "\tConnection failed - goodbye!" reactor.stop() def clientConnectionLost(self, connector, reason): print "\tConnection lost - goodbye!" reactor.stop() # this connects the protocol to a server runing on port 8090 def main(): print 'Connecting to %s:%d' % (AS_SERVER_HOST, AS_SERVER_PORT) while True: print query = raw_input("Query:") if query == '': return f = Spell_Factory(query) reactor.connectTCP(AS_SERVER_HOST, AS_SERVER_PORT, f) reactor.run() print f.results return if __name__ == '__main__': main()

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  • Slow Python HTTP server on localhost

    - by Abiel
    I am experiencing some performance problems when creating a very simple Python HTTP server. The key issue is that performance is varying depending on which client I use to access it, where the server and all clients are being run on the local machine. For instance, a GET request issued from a Python script (urllib2.urlopen('http://localhost/').read()) takes just over a second to complete, which seems slow considering that the server is under no load. Running the GET request from Excel using MSXML2.ServerXMLHTTP also feels slow. However, requesting the data Google Chrome or from RCurl, the curl add-in for R, yields an essentially instantaneous response, which is what I would expect. Adding further to my confusion is that I do not experience any performance problems for any client when I am on my computer at work (the performance problems are on my home computer). Both systems run Python 2.6, although the work computer runs Windows XP instead of 7. Below is my very simple server example, which simply returns 'Hello world' for any get request. from BaseHTTPServer import BaseHTTPRequestHandler, HTTPServer class MyHandler(BaseHTTPRequestHandler): def do_GET(self): print("Just received a GET request") self.send_response(200) self.send_header("Content-type", "text/html") self.end_headers() self.wfile.write('Hello world') return def log_request(self, code=None, size=None): print('Request') def log_message(self, format, *args): print('Message') if __name__ == "__main__": try: server = HTTPServer(('localhost', 80), MyHandler) print('Started http server') server.serve_forever() except KeyboardInterrupt: print('^C received, shutting down server') server.socket.close() Note that in MyHandler I override the log_request() and log_message() functions. The reason is that I read that a fully-qualified domain name lookup performed by one of these functions might be a reason for a slow server. Unfortunately setting them to just print a static message did not solve my problem. Also, notice that I have put in a print() statement as the first line of the do_GET() routine in MyHandler. The slowness occurs prior to this message being printed, meaning that none of the stuff that comes after it is causing a delay.

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  • c++ function scope

    - by Myx
    I have a main function in A.cpp which has the following relevant two lines of code: B definition(input_file); definition.Print(); In B.h I have the following relevant lines of code: class B { public: // Constructors B(void); B(const char *filename); ~B(void); // File input int ParseLSFile(const char *filename); // Debugging void Print(void); // Data int var1; double var2; vector<char* > var3; map<char*, vector<char* > > var4; } In B.cpp, I have the following function signatures (sorry for being redundant): B::B(void) : var1(-1), var2(numeric_limits<double>::infinity()) { } B::B(const char *filename) { B *def = new B(); def->ParseLSFile(filename); } B::~B(void) { // Free memory for var3 and var 4 } int B::ParseLSFile(const char *filename) { // assign var1, var2, var3, and var4 values } void B::Print(void) { // print contents of var1, var2, var3, and var4 to stdout } So when I call Print() from within B::ParseLSFile(...), then the contents of my structures print correctly to stdout. However, when I call definition.Print() from A.cpp, my structures are empty or contain garbage. Can anyone recommend the correct way to initialize/pass my structures so that I can access them outside of the scope of my function definition? Thanks.

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  • Python Ephem / Datetime calculation

    - by dassouki
    the output should process the first date as "day" and second as "night". I've been playing with this for a few hours now and can't figure out what I'm doing wrong. Any ideas? Edit I assume that the problem is due to my date comparison implementation Output: $ python time_of_day.py * should be day: event date: 2010/4/6 16:00:59 prev rising: 2010/4/6 09:24:24 prev setting: 2010/4/5 23:33:03 next rise: 2010/4/7 09:22:27 next set: 2010/4/6 23:34:27 day * should be night: event date: 2010/4/6 00:01:00 prev rising: 2010/4/5 09:26:22 prev setting: 2010/4/5 23:33:03 next rise: 2010/4/6 09:24:24 next set: 2010/4/6 23:34:27 day time_of_day.py import datetime import ephem # install from http://pypi.python.org/pypi/pyephem/ #event_time is just a date time corresponding to an sql timestamp def type_of_light(latitude, longitude, event_time, utc_time, horizon): o = ephem.Observer() o.lat, o.long, o.date, o.horizon = latitude, longitude, event_time, horizon print "event date ", o.date print "prev rising: ", o.previous_rising(ephem.Sun()) print "prev setting: ", o.previous_setting(ephem.Sun()) print "next rise: ", o.next_rising(ephem.Sun()) print "next set: ", o.next_setting(ephem.Sun()) if o.previous_rising(ephem.Sun()) <= o.date <= o.next_setting(ephem.Sun()): return "day" elif o.previous_setting(ephem.Sun()) <= o.date <= o.next_rising(ephem.Sun()): return "night" else: return "error" print "should be day: ", type_of_light('45.959','-66.6405','2010/4/6 16:01','-4', '-6') print "should be night: ", type_of_light('45.959','-66.6405','2010/4/6 00:01','-4', '-6')

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  • Python optimization problem?

    - by user342079
    Alright, i had this homework recently (don't worry, i've already done it, but in c++) but I got curious how i could do it in python. The problem is about 2 light sources that emit light. I won't get into details tho. Here's the code (that I've managed to optimize a bit in the latter part): import math, array import numpy as np from PIL import Image size = (800,800) width, height = size s1x = width * 1./8 s1y = height * 1./8 s2x = width * 7./8 s2y = height * 7./8 r,g,b = (255,255,255) arr = np.zeros((width,height,3)) hy = math.hypot print 'computing distances (%s by %s)'%size, for i in xrange(width): if i%(width/10)==0: print i, if i%20==0: print '.', for j in xrange(height): d1 = hy(i-s1x,j-s1y) d2 = hy(i-s2x,j-s2y) arr[i][j] = abs(d1-d2) print '' arr2 = np.zeros((width,height,3),dtype="uint8") for ld in [200,116,100,84,68,52,36,20,8,4,2]: print 'now computing image for ld = '+str(ld) arr2 *= 0 arr2 += abs(arr%ld-ld/2)*(r,g,b)/(ld/2) print 'saving image...' ar2img = Image.fromarray(arr2) ar2img.save('ld'+str(ld).rjust(4,'0')+'.png') print 'saved as ld'+str(ld).rjust(4,'0')+'.png' I have managed to optimize most of it, but there's still a huge performance gap in the part with the 2 for-s, and I can't seem to think of a way to bypass that using common array operations... I'm open to suggestions :D

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  • Python opening a file and putting list of names on separate lines

    - by Jeremy Borton
    I am trying to write a python program using Python 3 I have to open a text file and read a list of names, print the list, sort the list in alphabetical order and then finally re-print the list. There's a little more to it than that BUT the problem I am having is that I'm supposed to print the list of names with each name on a separate line Instead of printing each name on a separate line, it prints the list all on one line. How can I fix this? def main(): #create control loop keep_going = 'y' #Open name file name_file = open('names.txt', 'r') names = name_file.readlines() name_file.close() #Open outfile outfile = open('sorted_names.txt', 'w') index = 0 while index < len(names): names[index] = names[index].rstrip('\n') index += 1 #sort names print('original order:', names) names.sort() print('sorted order:', names) #write names to outfile for item in names: outfile.write(item + '\n') #close outfile outfile.close() #search names while keep_going == 'y' or keep_going == 'Y': search = input('Enter a name to search: ') if search in names: print(search, 'was found in the list.') keep_going = input('Would you like to do another search Y for yes: ') else: print(search, 'was not found.') keep_going = input('Would you like to do another search Y for yes: ') main()

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  • LDAP query using Python: always no result

    - by Grey
    I am trying to use python to query LDAP server, and it always returns me no result. and anyone help me find what wrong with my python code? it runs fine without excpetions, and it always has no result. i played around with the filter like "cn=partofmyname" but just no luck. thanks for help import ldap try: l = ldap.open("server") l.protocol_version = ldap.VERSION3 l.set_option(ldap.OPT_REFERRALS, 0) output =l.simple_bind("cn=username,cn=Users,dc=domian, dc=net",'password$R') print output except ldap.LDAPError, e: print e baseDN = "DC=rim,DC=net" searchScope = ldap.SCOPE_SUBTREE ## retrieve all attributes - again adjust to your needs - see documentation for more options retrieveAttributes = None Filter = "(&(objectClass=user)(sAMAccountName=myaccount))" try: ldap_result_id = l.search(baseDN, searchScope, Filter, retrieveAttributes) print ldap_result_id result_set = [] while 1: result_type, result_data = l.result(ldap_result_id, 0) if len(result_data) == 0: print 'no reslut' break else: for i in range(len(result_set)): for entry in result_set[i]: try: name = entry[1]['cn'][0] email = entry[1]['mail'][0] phone = entry[1]['telephonenumber'][0] desc = entry[1]['description'][0] count = count + 1 print "%d.\nName: %s\nDescription: %s\nE-mail: %s\nPhone: %s\n" %\ (count, name, desc, email, phone) except: pass ## here you don't have to append to a list ## you could do whatever you want with the individual entry #if result_type == ldap.RES_SEARCH_ENTRY: # result_set.append(result_data) # print result_set except ldap.LDAPError, e: print e l.unbind()

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  • python on apache - getting 404

    - by Kirby
    I edited this question after i found a solution... i need to understand why the solution worked instead of my method? This is likely to be a silly question. I tried searching other questions that are related... but to no avail. i am running Apache/2.2.11 (Ubuntu) DAV/2 SVN/1.5.4 PHP/5.2.6-3ubuntu4.5 with Suhosin-Patch mod_python/3.3.1 Python/2.6.2 i have a script called test.py #! /usr/bin/python print "Content-Type: text/html" # HTML is following print # blank line, end of headers print "hello world" running it as an executable works... /var/www$ ./test.py Content-Type: text/html hello world when i run http://localhost/test.py i get a 404 error. What am i missing? i used this resource to enable python parsing on apache. http://ubuntuforums.org/showthread.php?t=91101 From that same thread... the following code worked.. why? #!/usr/bin/python import sys import time def index(req): # Following line causes error to be sent to browser # rather than to log file (great for debug!) sys.stderr = sys.stdout #print "Content-type: text/html\n" #print """ blah1 = """<html> <head><title>A page from Python</title></head> <body> <h4>This page is generated by a Python script!</h4> The current date and time is """ now = time.gmtime() displaytime = time.strftime("%A %d %B %Y, %X",now) #print displaytime, blah1 += displaytime #print """ blah1 += """ <hr> Well House Consultants demonstration </body> </html> """ return blah1

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  • Python : How to close a UDP socket while is waiting for data in recv ?

    - by alexroat
    Hello, let's consider this code in python: import socket import threading import sys import select class UDPServer: def __init__(self): self.s=None self.t=None def start(self,port=8888): if not self.s: self.s=socket.socket(socket.AF_INET, socket.SOCK_DGRAM) self.s.bind(("",port)) self.t=threading.Thread(target=self.run) self.t.start() def stop(self): if self.s: self.s.close() self.t.join() self.t=None def run(self): while True: try: #receive data data,addr=self.s.recvfrom(1024) self.onPacket(addr,data) except: break self.s=None def onPacket(self,addr,data): print addr,data us=UDPServer() while True: sys.stdout.write("UDP server> ") cmd=sys.stdin.readline() if cmd=="start\n": print "starting server..." us.start(8888) print "done" elif cmd=="stop\n": print "stopping server..." us.stop() print "done" elif cmd=="quit\n": print "Quitting ..." us.stop() break; print "bye bye" It runs an interactive shell with which I can start and stop an UDP server. The server is implemented through a class which launches a thread in which there's a infinite loop of recv/*onPacket* callback inside a try/except block which should detect the error and the exits from the loop. What I expect is that when I type "stop" on the shell the socket is closed and an exception is raised by the recvfrom function because of the invalidation of the file descriptor. Instead, it seems that recvfrom still to block the thread waiting for data even after the close call. Why this strange behavior ? I've always used this patter to implements an UDP server in C++ and JAVA and it always worked. I've tried also with a "select" passing a list with the socket to the xread argument, in order to get an event of file descriptor disruption from select instead that from recvfrom, but select seems to be "insensible" to the close too. I need to have a unique code which maintain the same behavior on Linux and Windows with python 2.5 - 2.6. Thanks.

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  • AFNetworking iOS

    - by Jeromiin
    I have a problem with a request in my app, I want to receive a json but because of the completion block my "PRINT 2" is print before my "PRINT 1" and of course my "PRINT 2" is null. I want the contrary and my "PRINT 2" to be filled but I can't manage to do it. -(void) makeConnection { NSURL *url = [NSURL URLWithString:[@"http://monsite.com/iPhonej/verifPseudo.php?login="stringByAppendingString:[_loginField.text stringByAppendingString:[@"&password=" stringByAppendingString:_passField.text]]]]; NSURLRequest *request = [NSURLRequest requestWithURL:url]; AFHTTPRequestOperation *operation = [[AFHTTPRequestOperation alloc] initWithRequest:request]; operation.responseSerializer = [AFJSONResponseSerializer serializer]; [operation setCompletionBlockWithSuccess:^(AFHTTPRequestOperation *operation, id responseObject) { self.response = (NSDictionary *)responseObject; NSLog(@"PRINT 1 : %@", self.response[@"la"][@"reponse"][0][@"rep"]); [_dataLock lock]; } failure:^(AFHTTPRequestOperation *operation, NSError *error) { NSLog(@"Request Failed: %@, %@", error, error.userInfo); }]; [operation start]; } - (IBAction)logIn:(id)sender { [self makeConnection]; NSLog(@"PRINT 2 : %@", self.response[@"la"][@"reponse"][0][@"rep"]); } I know that AFNetworking is asynchronous but is there an other way to do the request and receive my json well ? Thank you

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  • How to amend return value design in OO manner?

    - by FrontierPsycho
    Hello. I am no newb on OO programming, but I am faced with a puzzling situation. I have been given a program to work on and extend, but the previous developers didn't seem that comfortable with OO, it seems they either had a C background or an unclear understanding of OO. Now, I don't suggest I am a better developer, I just think that I can spot some common OO errors. The difficult task is how to amend them. In my case, I see a lot of this: if (ret == 1) { out.print("yadda yadda"); } else if (ret == 2) { out.print("yadda yadda"); } else if (ret == 3) { out.print("yadda yadda"); } else if (ret == 0) { out.print("yadda yadda"); } else if (ret == 5) { out.print("yadda yadda"); } else if (ret == 6) { out.print("yadda yadda"); } else if (ret == 7) { out.print("yadda yadda"); } ret is a value returned by a function, in which all Exceptions are swallowed, and in the catch blocks, the above values are returned explicitly. Oftentimes, the Exceptions are simply swallowed, with empty catch blocks. It's obvious that swalllowing exceptions is wrong OO design. My question concerns the use of return values. I believe that too is wrong, however I think that using Exceptions for control flow is equally wrong, and I can't think of anything to replace the above in a correct, OO manner. Your input, please?

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  • php link to call another php page

    - by user2086894
    i have a php page which contain this field: Delete i want when i press on the Delete to call the delcat.php and send a categoryid which is in a field in the same table. any one can help me to reach this please? here my complete table code: <table border="0" align='center' class="styled-table"> <tr class="thh"> <th class="thh">Category Code</th> <th class="thh">Category Name </th> <th class="thh">Category IMage </th> <th class="thh">Edit</th> <th class="thh">Delete</th> </tr> <?php for ($counter = 0; $row = mysql_fetch_row ($resultSet); $counter++) { print ("<tr align='center' class='trh'>"); print ("<td align='center' class='tdh'>$row[0]</td>"); print ("<td align='center' class='tdh'>$row[1]</td>"); print ("<td align='center' class='tdh'><img src='$row[2]' width='50' height='50'></td>"); print ("<td align='center' class='tdh' width='50' align='center'><a href src='#'>Edit</a></td>"); print ("<td align='center' class='tdh' width='50' align='center'><a href src='delcat.php'>Delete</a></td>"); print("</tr>"); }

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  • Python parsing error message functions

    - by user1716168
    The code below was created by me with the help of many SO veterans: The code takes an entered math expression and splits it into operators and operands for later use. I have created two functions, the parsing function that splits, and the error function. I am having problems with the error function because it won't display my error messages and I feel the function is being ignored when the code runs. An error should print if an expression such as this is entered: 3//3+4,etc. where there are two operators together, or there are more than two operators in the expression overall, but the error messages dont print. My code is below: def errors(): numExtrapolation,opExtrapolation=parse(expression) if (len(numExtrapolation) == 3) and (len(opExtrapolation) !=2): print("Bad1") if (len(numExtrapolation) ==2) and (len(opExtrapolation) !=1): print("Bad2") def parse(expression): operators= set("*/+-") opExtrapolate= [] numExtrapolate= [] buff=[] for i in expression: if i in operators: numExtrapolate.append(''.join(buff)) buff= [] opExtrapolate.append(i) opExtrapolation=opExtrapolate else: buff.append(i) numExtrapolate.append(''.join(buff)) numExtrapolation=numExtrapolate #just some debugging print statements print(numExtrapolation) print("z:", len(opExtrapolation)) return numExtrapolation, opExtrapolation errors() Any help would be appreciated. Please don't introduce new code that is any more advanced than the code already here. I am looking for a solution to my problem... not large new code segments. Thanks.

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  • How to remove empty tables from a MySQL backup file.

    - by user280708
    I have multiple large MySQL backup files all from different DBs and having different schemas. I want to load the backups into our EDW but I don't want to load the empty tables. Right now I'm cutting out the empty tables using AWK on the backup files, but I'm wondering if there's a better way to do this. If anyone is interested, this is my AWK script: EDIT: I noticed today that this script has some problems, please beware if you want to actually try to use it. Your output may be WRONG... I will post my changes as I make them. # File: remove_empty_tables.awk # Copyright (c) Northwestern University, 2010 # http://edw.northwestern.edu /^--$/ { i = 0; line[++i] = $0; getline if ($0 ~ /-- Definition/) { inserts = 0; while ($0 !~ / ALTER TABLE .* ENABLE KEYS /) { # If we already have an insert: if (inserts > 0) print else { # If we found an INSERT statement, the table is NOT empty: if ($0 ~ /^INSERT /) { ++inserts # Dump the lines before the INSERT and then the INSERT: for (j = 1; j <= i; ++j) print line[j] i = 0 print $0 } # Otherwise we may yet find an insert, so save the line: else line[++i] = $0 } getline # go to the next line } line[++i] = $0; getline line[++i] = $0; getline if (inserts > 0) { for (j = 1; j <= i; ++j) print line[j] print $0 } next } else { print "--" } } { print }

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  • In Lua, how to pass vararg to another function while also taking a peek at them?

    - by romkyns
    It seems that in Lua, I can either pass vararg on to another function, or take a peek at them through arg, but not both. Here's an example: function a(marker, ...) print(marker) print(#arg, arg[1],arg[2]) end function b(marker, ...) print(marker) destination("--2--", ...) end function c(marker, ...) print(marker) print(#arg, arg[1],arg[2]) destination("--3--", ...) end function destination(marker, ...) print(marker) print(#arg, arg[1],arg[2]) end Observe that a only looks at the varargs, b only passes them on, while c does both. Here are the results: >> a("--1--", "abc", "def") --1-- 2 abc def >> b("--1--", "abc", "def") --1-- --2-- 2 abc def >> c("--1--", "abc", "def") --1-- test.lua:13: attempt to get length of local 'arg' (a nil value) stack traceback: ...test.lua:13: in function 'c' ...test.lua:22: in main chunk [C]: ? What am I doing wrong? Am I not supposed to combine the two? Why not?

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