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  • MySQL: Creating table with FK error (errno 150)

    - by Peter Bailey
    I've tried searching on this error and nothing I've found helps me, so I apologize in advance if this is a duplicate and I'm just too dumb to find it. I've created a model with MySQL Workbench and am now attempting to install it to a mysql server. Using File Export Forward Engineer SQL CREATE Script... it outputs a nice big file for me, with all the settings I ask for. I switch over to MySQL GUI Tools (the Query Browser specifically) and load up this script (note that I'm going form one official MySQL tool to another). However, when I try to actually execute this file, I get the same error over and over SQLSTATE[HY000]: General error: 1005 Can't create table './srs_dev/location.frm' (errno: 150) "OK", I say to myself, something is wrong with the location table. So I check out the definition in the output file. SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0; SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0; SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='TRADITIONAL'; -- ----------------------------------------------------- -- Table `state` -- ----------------------------------------------------- DROP TABLE IF EXISTS `state` ; CREATE TABLE IF NOT EXISTS `state` ( `state_id` INT NOT NULL AUTO_INCREMENT , `iso_3166_2_code` VARCHAR(2) NOT NULL , `name` VARCHAR(60) NOT NULL , PRIMARY KEY (`state_id`) ) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `brand` -- ----------------------------------------------------- DROP TABLE IF EXISTS `brand` ; CREATE TABLE IF NOT EXISTS `brand` ( `brand_id` INT UNSIGNED NOT NULL AUTO_INCREMENT , `name` VARCHAR(45) NOT NULL , `domain` VARCHAR(45) NOT NULL , `manager_name` VARCHAR(100) NULL , `manager_email` VARCHAR(255) NULL , PRIMARY KEY (`brand_id`) ) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `location` -- ----------------------------------------------------- DROP TABLE IF EXISTS `location` ; CREATE TABLE IF NOT EXISTS `location` ( `location_id` INT UNSIGNED NOT NULL AUTO_INCREMENT , `name` VARCHAR(255) NOT NULL , `address_line_1` VARCHAR(255) NULL , `address_line_2` VARCHAR(255) NULL , `city` VARCHAR(100) NULL , `state_id` TINYINT UNSIGNED NULL DEFAULT NULL , `postal_code` VARCHAR(10) NULL , `phone_number` VARCHAR(20) NULL , `fax_number` VARCHAR(20) NULL , `lat` DECIMAL(9,6) NOT NULL , `lng` DECIMAL(9,6) NOT NULL , `contact_url` VARCHAR(255) NULL , `brand_id` TINYINT UNSIGNED NOT NULL , `summer_hours` VARCHAR(255) NULL , `winter_hours` VARCHAR(255) NULL , `after_hours_emergency` VARCHAR(255) NULL , `image_file_name` VARCHAR(100) NULL , `manager_name` VARCHAR(100) NULL , `manager_email` VARCHAR(255) NULL , `created_date` TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP , PRIMARY KEY (`location_id`) , CONSTRAINT `fk_location_state` FOREIGN KEY (`state_id` ) REFERENCES `state` (`state_id` ) ON DELETE NO ACTION ON UPDATE NO ACTION, CONSTRAINT `fk_location_brand` FOREIGN KEY (`brand_id` ) REFERENCES `brand` (`brand_id` ) ON DELETE NO ACTION ON UPDATE NO ACTION) ENGINE = InnoDB; CREATE INDEX `fk_location_state` ON `location` (`state_id` ASC) ; CREATE INDEX `fk_location_brand` ON `location` (`brand_id` ASC) ; CREATE INDEX `idx_lat` ON `location` (`lat` ASC) ; CREATE INDEX `idx_lng` ON `location` (`lng` ASC) ; Looks ok to me. I surmise that maybe something is wrong with the Query Browser, so I put this file on the server and try to load it this way ] mysql -u admin -p -D dbname < path/to/create_file.sql And I get the same error. So I start to Google this issue and find all kinds of accounts that talk about an error with InnoDB style tables that fail with foreign keys, and the fix is to add "SET FOREIGN_KEY_CHECKS=0;" to the SQL script. Well, as you can see, that's already part of the file that MySQL Workbench spat out. So, my question is then, why is this not working when I'm doing what I think I'm supposed to be doing? Version Info: # MySQL: 5.0.45 GUI Tools: 1.2.17 Workbench: 5.0.30

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  • Meaning of Execute_priv on mysql.db table

    - by Ben Reisner
    I created user 'restriceduser' on my mysql server that is 'locked down'. The mysql.user table has a N for all priveledges for that account. The mysql.db table has Y for only Select, Insert, Update, Delete, Create, Drop; all other privileges are N for that account. I tried to create a stored procedure and then grant him access to run only that procedure, no others, but it does not work. The user receives: Error: execute command denied to user 'restricteduser'@'%' for routine 'mydb.functionname' The stored procedure: CREATE DEFINER = 'restriceduser'@'%' FUNCTION `functionname`(sIn MEDIUMTEXT, sformat MEDIUMTEXT) RETURNS int(11) NOT DETERMINISTIC CONTAINS SQL SQL SECURITY DEFINER COMMENT '' BEGIN .... END; The grant statement I tried: GRANT EXECUTE ON PROCEDURE mydb.functionname TO 'restricteduser'@'%'; I was able to work around by modifying his mysql.db entry with update mysql.db set execute_priv='Y' where user='restricteduser' This seems to be more then I want, because it opens up permissions for him to run any stored procedure in that database, while I only wanted him to have permissions to run the designated function. Does anyone see where my issue may lie?

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  • Why use MySQL over flatfiles?

    - by John
    A friend and I were debating about whether he should use MySQL or a flatfile database for his website's backend. I told him to go with MySQL because it was structured, held records well, and was consistent. He on the other hand said that he would rather go for speed. Reading files is a lot quicker than connecting to MySQL and it made me wonder whether he was right. For example, why not just create a folder for each table, like so: users/ groups/ posts/, within the folders have the files named by ID (1, 2, 3) and then for the data use a format like so: username: John\npassword: e2fc714c4727ee9395f324cd2e7f331f\nemail: [email protected]? In other words, what are the advantages of MySQL over flatfiles?

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  • mysql query building output taking a long time

    - by user121196
    I have a simple query that does select * from t limit 1; on a remote mysql server. I use squirrel(mysql client) to run it, it shows: Query 1 of 1 elapsed time (seconds) - Total: 22.047, SQL query: 1.047, Building output: 21 why does building output take such a long time? what does this process do? when running from mysql command line, the whole process takes 0.3 secs (also remotely)

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  • ASP.NET error when trying to configure ListView + SqlDatasource for a MySql Table

    - by stighy
    Hi, i'm using ASP.NET + a MySql Db. I'm trying to configure a ListView so i've written: <asp:SqlDataSource ID="dsDatiUtente" runat="server" ConnectionString="Server=12.28.136.29;Database=mydb;Uid=m111d1;Pwd=fake;Pooling=false;" ProviderName="MySql.Data.MySqlClient" SelectCommand="SELECT * FROM user WHERE idUser=@IdUser" / At the beginning of my aspx page i've added <%@ Import Namespace="MySql.Data.MySqlClient" %> But if i click to the sqldatasource and click "Refresh Schema" i got this error: "Unable to retrive schema.... Unable to find the requested .Net Framework data provider" For instance, i've installed it , but i've also uninstalled old version, then installed new versions. In my project i simple copy Mysql dll into "bin" folder, then add a reference to that dll. I'm not sure is the corrected way... I need to have the "refreshed schema" to permit vs.net to build automatically my listview ... if i can't to "auto build" listview, i have to write all code by hand, and it is a too expensive work me :( What i'm wrong ? Thank you!

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  • Intermittent "No Database Selected" in PHP/MySQL?

    - by ANE
    Have a PHP/MySQL form with a dropdown box containing a list of 350 names. When any random name is selected, sometimes it works & displays info about that name from the database, and sometimes the form gives the error "No Database Selected". Here's what I've tried, pretty much grasping at straws as I'm not a programmer: Increasing max_connections in /etc/my.cnf from 200 to 2000 (even though only 4-5 connections are made and it's a lightly used server) Changing mysql_pconnect to mysql_connect Adding the word true to this connection string: $mysql = mysql_pconnect($hostname_mysql, $username_mysql, $password_mysql, true) or trigger_error(mysql_error(),E_USER_ERROR); Changing the word require_once to require on this line: [?php require('/home/user/Connections/mysql.php'); ?] Enabling MySQL & PHP query & error logging. (no errors logged) Here is the code: [removed old bad code] Update: Working answer from Rob Apodaca below.

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  • MySQL dual license behavior

    - by jromero
    Hi SO, I'm running a commercial(closed source) Web App development for the first time. Initially I considered MySQL the most feasible option for a DB, until I get quite confused about its dual license behavior. If I want a commercial application do I still can use the GPL version of MySQL or I must get a license? The same question in a different way: If I use MySQL's GPL version does that force me to license the whole app under GPL? Either case I would go with PostgreSQL, I just want to make really really sure about this. Even in SO I've seen related("duplicates") questions but never a clear answer... All other tools I'm gonna use to code the project are licensed under BSD or MIT. Just in case, the role of MySQL in the project is merely as relational DB to store persistent data and query it. I'd really appreciate if someone can clarify this for me. Regards, thanks in advanced.

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  • Local use of MySQL database

    - by waanders
    Hi all, Is it possible to use MySQL local? I mean NOT at a server. I read a lot about MySQL on a webserver with PHP, Joomla etc. I want to program a piece of software and use a database local to store results. Can I use MySQL for that? If so, is ther anyware on the net a good tutorial how to do that?

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  • MySQL LEFT JOIN error

    - by Alex
    Hello, I've got some SQL that used to work with an older MySQL version, but after upgrading to a newer MySQL 5 version, I'm getting an error. Here's the SQL: SELECT portfolio.*, projects.*, types.* FROM projects, types LEFT JOIN portfolio ON portfolio.pfProjectID = projects.projectID WHERE projects.projectType = types.typeID AND types.typeID = #URL.a# ORDER BY types.typeSort, projects.projectPriority ASC and the new error I'm receiving: Unknown column 'projects.projectID' in 'on clause' How can I convert this to compatible SQL for the newer MySQL version? Thanks very much!

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  • PHP won't parse MySQL statements

    - by Hussain
    I just installed Apache 2.2.15/PHP 5.3.2/MySQL 5.1.44 on Windows Vista. Apache is working fine, PHP is functional, and MySQL works on the CLI. However, when I try to access MySQL via PHP, I get an error (Fatal error: Call to undefined function mysql_connect()). extension=php_mysql.dll and extension=php_mbstring.dll are uncommented in the php.ini file, and PHP is in the system path. There is no libmysql.dll in either the top level PHP directory or the ext directory. There's a libmySQL.dll file in the MySQL bin directory (which is also in the system path); I tried renaming it, but that doesn't do anything Also, in case anyone wants to know, I originally installed PHP using the MSI installer, but it was missing some DLLs, so I installed from the zip file. I think I've exhausted all my options. Any help on this problem would be very appreciated. Thanks in advance.

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  • Restore Mysql database query is not working in ASP.NET, C#

    - by santhosha
    We are using Mysql.exe to restore database by the following query string cmd ="-h" + ViewState["host"].ToString() + " " + "-u" + ViewState["user"].ToString() + " " + "-p" + ViewState["password"].ToString() + " " + ViewState["dbName"].ToString() + "<" + " " + Server.MapPath("BackupFiles/") + path; The same query is executing in MySql command prompt but we are not able to restore using the above query in VisualStudio .Net, we have tried MysqlImport.exe to do the restore but it was no use. we are newbie to MySql if any help would be appreciated.

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  • Virtual Developer Day: MySQL - July 31st

    - by Cassandra Clark - OTN
    Virtual Developer Day: MySQL is a one-stop shop for you to learn all the essential MySQL skills. With a combination of presentations and hands-on lab experience, you’ll have the opportunity to practice in your own environment and gain more in-depth knowledge to successfully design, develop, and manage your MySQL databases.This FREE virtual event has two tracks tailored for both fresh and experienced MySQL users. Attend the sessions on July 31st and sharpen your skills to: Develop your new applications cost-effectively using MySQL Improve performance of your existing MySQL databases Manage your MySQL environment more efficiently When? Wednesday, July 31, 2013Mumbai 10:30 a.m. (GMT +5:30) - 2:30 p.m.Singapore 1:00 p.m. (GMT +8:00) - 5:00 p.m.Sydney 3:00 p.m. (GMT +10:00) - 7:00 p.m. Register TODAY! 

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  • Reset auto increment column value in script mysql

    - by Lucia
    Hi, I have two mysql tables, one needs to start its auto-increment column id with the last value of the last inserted row in the other table (plus 1). According to mysql manual you can restart the value of an auto increment column like this: mysql ALTER TABLE tbl AUTO_INCREMENT = 100; However, this is not possible: mysql ALTER TABLE tb2 AUTO_INCREMENT = (SELECT MAX(id) FROM tbl1); I need to perform something like this because I'm filling the tables using a script. Is there another way to achieve it?

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  • MySql.Data.MySqlClient.MySqlException: There is no 'root'@'%' registered

    - by user2963902
    i run web application on iis 6 , windows server 2003 , mysql database. first it was working fine, but when i reconfigured the mysql server with the same password it gave me this message error when i want to enter any page in browser : "MySql.Data.MySqlClient.MySqlException: There is no 'root'@'%' registered". i checked the app connection it's the same, as though the app doesn't see the localhost , because "dbforge" sometimes give me this message: "connection localhost cannot be found" but when i doubleclick the connection it opens as root. any idea to solve this problem

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  • Use WampServer's MySQL as a real MySQL for going on the net.

    - by Auxiliary
    Is this a right thing to do? I am using the Apache/Tomcat that comes with the liferay portal bundle and I used the MySQL that comes with WampServer at home but now I want to transfer my portal to a real Server and I wanted to know whether I could still use the Wamp's MySQL or should I install a real MySQL (What's the difference?) Thanks in advance.

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  • how to debug MySql stored procs without breaking control flow from application

    - by M.Taha Masood
    Is there a way to do the following: I have a MySQL DB , and there are many stored procs written in it as well. I use MySQL client library in C to connect to this DB and amongst other things , call the stored procedures. Is there a way to set breakpoints in the stored procedures such that when the call is made from C program ( using mySql client library ) into the stored proc , then control flow is halted in the C program and we can step into the stored proc called to whatever level of nesting and insspecting variables etc ( like any decent C debugged provides )? Is there ANY way to do the above ? Through some third party tool or the like if not through plain MySql . Help is appreciated. thanks

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  • Memory Allocation Error in MySQL

    - by Chinjoo
    I am using MySql ODBC driver with .Net 3.5. I have created a stored procedure in MySQl which accepts around 15 parameters with types like datetime, varchar, Int32, Int64 etc.. When I run the SP from the query window with the arguments provided, it runs fine. But whwn I test using the .Net application, it gives exception with "Memory allocation error", MySQL native error code is 4001. Any help will be much appreciated.

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  • MySQL Hashing Function Implementation

    - by Jonas Stevens
    I know that php has md5(), sha1(), and the hash() functions, but I want to create a hash using the MySQL PASSWORD() function. So far, the only way I can think of is to just query the server, but I want a function (preferably in php or Perl) that will do the same thing without querying MySQL at all. For example: MySQL hash - 464bb2cb3cf18b66 MySQL5 hash - *01D01F5CA7CA8BA771E03F4AC55EC73C11EFA229 Thanks!

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  • Missing parameter error after running MySql query

    - by annelie
    Hello, I'm completely new to MySql and haven't used SqlDataSource with UpdateParameters before, so I'm probably missing something very obvious. When trying to update a record, the update does happen but then throws an error saying "'id' parameter is missing at the statement". So the query works and the database gets updated as it should, but an error is thrown afterwards. These are the update parameters: <UpdateParameters> <asp:Parameter Name="business_name" Type="string" Size="256" /> <asp:Parameter Name="addr_line_1" Type="string" Size="256" /> <asp:Parameter Name="addr_line_2" Type="string" Size="256" /> <asp:Parameter Name="addr_line_3" Type="string" Size="256" /> <asp:Parameter Name="postcode" Type="string" Size="32" /> <asp:Parameter Name="county" Type="string" Size="128" /> <asp:Parameter Name="town_city" Type="string" Size="256" /> <asp:Parameter Name="tl_url" Type="string" Size="256" /> <asp:Parameter Name="customer_id" Type="string" Size="16" /> <asp:Parameter Name="region_id" Type="Int16" /> <asp:Parameter Name="description" Type="string" Size="1024" /> <asp:Parameter Name="approval_status" Type="string" Size="1" /> <asp:Parameter Name="tl_user_name" Type="string" Size="256" /> <asp:Parameter Name="phone" Type="string" Size="50" /> <asp:Parameter Name="uploaders_own" Type="Int16" /> </UpdateParameters> Here's the update statement: UPDATE myTable SET business_name = ?, addr_line_1 = ?, addr_line_2 = ?, addr_line_3 = ?, postcode = ?, county = ?, town_city = ?, tl_url = ?, customer_id = ?, region_id = ?, description = ?, approval_status = ?, tl_user_name = ?, phone = ?, uploaders_own = ? WHERE id = " + id Here's the stack trace: [InvalidOperationException: 'id' parameter is missing at the statement] CoreLab.MySql.r.a() +775 CoreLab.MySql.r.a(Int32& A_0, ArrayList& A_1) +448 CoreLab.MySql.x.e() +398 CoreLab.MySql.x.o() +89 CoreLab.MySql.MySqlCommand.a(CommandBehavior A_0, IDisposable A_1, Int32 A_2, Int32 A_3) +1306 CoreLab.Common.DbCommandBase.ExecuteDbDataReader(CommandBehavior behavior) +310 System.Data.Common.DbCommand.ExecuteReader() +12 CoreLab.Common.DbCommandBase.ExecuteNonQuery() +64 System.Web.UI.WebControls.SqlDataSourceView.ExecuteDbCommand(DbCommand command, DataSourceOperation operation) +386 System.Web.UI.WebControls.SqlDataSourceView.ExecuteUpdate(IDictionary keys, IDictionary values, IDictionary oldValues) +325 System.Web.UI.DataSourceView.Update(IDictionary keys, IDictionary values, IDictionary oldValues, DataSourceViewOperationCallback callback) +92 System.Web.UI.WebControls.DetailsView.HandleUpdate(String commandArg, Boolean causesValidation) +837 System.Web.UI.WebControls.DetailsView.HandleEvent(EventArgs e, Boolean causesValidation, String validationGroup) +509 System.Web.UI.WebControls.DetailsView.OnBubbleEvent(Object source, EventArgs e) +95 System.Web.UI.Control.RaiseBubbleEvent(Object source, EventArgs args) +37 System.Web.UI.WebControls.DetailsViewRow.OnBubbleEvent(Object source, EventArgs e) +113 System.Web.UI.Control.RaiseBubbleEvent(Object source, EventArgs args) +37 System.Web.UI.WebControls.LinkButton.OnCommand(CommandEventArgs e) +118 System.Web.UI.WebControls.LinkButton.RaisePostBackEvent(String eventArgument) +135 System.Web.UI.WebControls.LinkButton.System.Web.UI.IPostBackEventHandler.RaisePostBackEvent(String eventArgument) +10 System.Web.UI.Page.RaisePostBackEvent(IPostBackEventHandler sourceControl, String eventArgument) +13 System.Web.UI.Page.RaisePostBackEvent(NameValueCollection postData) +175 System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) +1565 Does anyone know what I'm doing wrong? Thanks, Annelie

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  • MySQL forgot about automatically creating an index for a foreign key?

    - by bobo
    After running the following SQL statements, you will see that, MySQL has automatically created the non-unique index question_tag_tag_id_tag_id on the tag_id column for me after the first ALTER TABLE statement has run. But after the second ALTER TABLE statement has run, I think MySQL should also automatically create another non-unique index question_tag_question_id_question_id on the question_id column for me. But as you can see from the SHOW INDEXES statement output, it's not there. Why does MySQL forget about the second ALTER TABLE statement? By the way, since I have already created a unique index question_id_tag_id_idx used by both question_id and tag_id columns. Is creating a separate index for each of them redundant? mysql> DROP DATABASE mydatabase; Query OK, 1 row affected (0.00 sec) mysql> CREATE DATABASE mydatabase; Query OK, 1 row affected (0.00 sec) mysql> USE mydatabase; Database changed mysql> CREATE TABLE question (id BIGINT AUTO_INCREMENT, html TEXT, PRIMARY KEY(id)) ENGINE = INNODB; Query OK, 0 rows affected (0.05 sec) mysql> CREATE TABLE tag (id BIGINT AUTO_INCREMENT, name VARCHAR(10) NOT NULL, UNIQUE INDEX name_idx (name), PRIMARY KEY(id)) ENGINE = INNODB; Query OK, 0 rows affected (0.05 sec) mysql> CREATE TABLE question_tag (question_id BIGINT, tag_id BIGINT, UNIQUE INDEX question_id_tag_id_idx (question_id, tag_id), PRIMARY KEY(question_id, tag_id)) ENGINE = INNODB; Query OK, 0 rows affected (0.00 sec) mysql> ALTER TABLE question_tag ADD CONSTRAINT question_tag_tag_id_tag_id FOREIGN KEY (tag_id) REFERENCES tag(id); Query OK, 0 rows affected (0.10 sec) Records: 0 Duplicates: 0 Warnings: 0 mysql> ALTER TABLE question_tag ADD CONSTRAINT question_tag_question_id_question_id FOREIGN KEY (question_id) REFERENCES question(id); Query OK, 0 rows affected (0.13 sec) Records: 0 Duplicates: 0 Warnings: 0 mysql> SHOW INDEXES FROM question_tag; +--------------+------------+----------------------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+ | Table | Non_unique | Key_name | Seq_in_index | Column_name | Collation | Cardinality | Sub_part | Packed | Null | Index_type | Comment | +--------------+------------+----------------------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+ | question_tag | 0 | PRIMARY | 1 | question_id | A | 0 | NULL | NULL | | BTREE | | | question_tag | 0 | PRIMARY | 2 | tag_id | A | 0 | NULL | NULL | | BTREE | | | question_tag | 0 | question_id_tag_id_idx | 1 | question_id | A | 0 | NULL | NULL | | BTREE | | | question_tag | 0 | question_id_tag_id_idx | 2 | tag_id | A | 0 | NULL | NULL | | BTREE | | | question_tag | 1 | question_tag_tag_id_tag_id | 1 | tag_id | A | 0 | NULL | NULL | | BTREE | | +--------------+------------+----------------------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+ 5 rows in set (0.01 sec) mysql>

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  • MySQL PHP incompatibility.

    - by Evernoob
    Ok maybe I've overlooked something really simple here, but I can't seem to figure this out. I'm running WAMP locally, but connecting to a remote MySQL database. The local version of PHP is the latest 5.3.0. One of the remote databases, being version 5.0.45 works fine. However, the other remote database I'm trying to connect to, which is version 5.0.22 throws the following error before dying: Warning: mysql_connect() [function.mysql-connect]: OK packet 6 bytes shorter than expected. PID=5880 in ... Warning: mysql_connect() [function.mysql-connect]: mysqlnd cannot connect to MySQL 4.1+ using old authentication in ... WTF? UPDATE: Reverting to PHP 5.2.* i.e. anything lower than 5.3.0 resolves the problem completely. As long as I am not running 5.3.0 I can connect to both databases. I'm not sure what the explanation is for this weirdness.

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  • Adding a Line Break in mySQL INSERT INTO text

    - by james
    Hi Could someone tell me how to add a new line in a text that i enter in a mySql table. I tried using the '\n in the line i entered with INSERT INTO statement but '\n is shown as it is. Actually i have created a table in Ms Access with some data. Ms Access adds new line with '\n. I am converting Ms Access table data into mySql . But when i convert, the '\n is ignored and all the text is shown in one single line when i display it from mySql table on a php form. Can anyone tell me how mySQL can add a new line in a text ? Awaiting response Thanks !!

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  • Hibernate Communications Link Failure in Restlet-Hibernate Based Java application powered by MySQL

    - by Vatsala
    Let me describe my question - I have a Java application - Hibernate as the DB interfacing layer over MySQL. I get the communications link failure error in my application. The occurence of this error is a very specific case. I get this error , When I leave mysql server unattended for more than approximately 6 hours (i.e. when there are no queries issued to MySQL for more than approximately 6 hours). I am pasting a top 'exception' level description below, and adding a pastebin link for a detailed stacktrace description. javax.persistence.PersistenceException: org.hibernate.exception.JDBCConnectionException: Cannot open connection - Caused by: org.hibernate.exception.JDBCConnectionException: Cannot open connection - Caused by: com.mysql.jdbc.exceptions.jdbc4.CommunicationsException: Communications link failure - The last packet successfully received from the server was 1,274,868,181,212 milliseconds ago. The last packet sent successfully to the server was 0 milliseconds ago. - Caused by: com.mysql.jdbc.exceptions.jdbc4.CommunicationsException: Communications link failure - The last packet successfully received from the server was 1,274,868,181,212 milliseconds ago. The last packet sent successfully to the server was 0 milliseconds ago. - Caused by: java.net.ConnectException: Connection refused: connect the link to the pastebin for further investigation - http://pastebin.com/4KujAmgD What I understand from these exception statements is that MySQL is refusing to take in any connections after a period of idle/nil activity. I have been reading up a bit about this via google search, and came to know that one of the possible ways to overcome this is to set values for c3p0 properties as c3p0 comes bundled with Hibernate. Specifically, I read from here http://www.mchange.com/projects/c3p0/index.html that setting two properties idleConnectionTestPeriod and preferredTestQuery will solve this for me. But these values dont seem to have had an effect. Is this the correct approach to fixing this? If not, what is the right way to get over this? The following are related Communications Link Failure questions at stackoverflow.com, but I've not found a satisfactory answer in their answers. http://stackoverflow.com/questions/2121829/java-db-communications-link-failure http://stackoverflow.com/questions/298988/how-to-handle-communication-link-failure Note 1 - i dont get this error when I am using my application continuosly. Note 2 - I use JPA with Hibernate and hence my hibernate.dialect,etc hibernate properties reside within the persistence.xml in the META-INF folder (does that prevent the c3p0 properties from working?)

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  • Host...not allowed error in ODBC connection, while connecting to an online MySQL database

    - by sqlchild
    I have downloaded MySQL ODBC Connector 5.1. Now am trying to setup the DSN. But am getting the error: Connection Failed : [HY000] [MySQL] [ODBC 5.1 Driver]Host '117.x.x.x' is not allowed to connect to this MySQL server My server url is server.myweb.com - this name am entering in the TCP/IP Server and Port =3306. I have also entered the userid and password , which is the one which i enter when i open www.myweb.com/cpanel Is this a version problem? Should the version of MySQL on my server also be 5.1, i.e. the one of the ODBC? Please help.

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