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• dmidecode showing more ram slots than available?

  - by Jestep

  I have some failing RAM in a server and I ran dmidecode to figure out what tyoe of RAM I needed to replace it with. The server has 6 RAM slots, 4 of which are in use. When I run dmidecode this is what I get. dmidecode 2.10 SMBIOS 2.4 present. Handle 0x001F, DMI type 17, 27 bytes Memory Device Array Handle: 0x001E Error Information Handle: No Error Total Width: 72 bits Data Width: 64 bits Size: 2048 MB Form Factor: DIMM Set: 1 Locator: JXXX Bank Locator: DIMM 00 Type: DDR2 Type Detail: Synchronous Speed: 667 MHz Manufacturer: Not Specified Serial Number: Not Specified Asset Tag: Not Specified Part Number: Not Specified Handle 0x0020, DMI type 17, 27 bytes Memory Device Array Handle: 0x001E Error Information Handle: No Error Total Width: 72 bits Data Width: 64 bits Size: 2048 MB Form Factor: DIMM Set: 1 Locator: JXXX Bank Locator: DIMM 01 Type: DDR2 Type Detail: Synchronous Speed: 667 MHz Manufacturer: Not Specified Serial Number: Not Specified Asset Tag: Not Specified Part Number: Not Specified Handle 0x0021, DMI type 17, 27 bytes Memory Device Array Handle: 0x001E Error Information Handle: No Error Total Width: Unknown Data Width: Unknown Size: No Module Installed Form Factor: DIMM Set: 1 Locator: JXXX Bank Locator: DIMM 02 Type: DDR2 Type Detail: Synchronous Speed: 667 MHz Manufacturer: Not Specified Serial Number: Not Specified Asset Tag: Not Specified Part Number: Not Specified Handle 0x0022, DMI type 17, 27 bytes Memory Device Array Handle: 0x001E Error Information Handle: No Error Total Width: Unknown Data Width: Unknown Size: No Module Installed Form Factor: DIMM Set: 1 Locator: JXXX Bank Locator: DIMM 03 Type: DDR2 Type Detail: Synchronous Speed: 667 MHz Manufacturer: Not Specified Serial Number: Not Specified Asset Tag: Not Specified Part Number: Not Specified Handle 0x0023, DMI type 17, 27 bytes Memory Device Array Handle: 0x001E Error Information Handle: No Error Total Width: 72 bits Data Width: 64 bits Size: 2048 MB Form Factor: DIMM Set: 1 Locator: JXXX Bank Locator: DIMM 10 Type: DDR2 Type Detail: Synchronous Speed: 667 MHz Manufacturer: Not Specified Serial Number: Not Specified Asset Tag: Not Specified Part Number: Not Specified Handle 0x0024, DMI type 17, 27 bytes Memory Device Array Handle: 0x001E Error Information Handle: No Error Total Width: 72 bits Data Width: 64 bits Size: 2048 MB Form Factor: DIMM Set: 1 Locator: JXXX Bank Locator: DIMM 11 Type: DDR2 Type Detail: Synchronous Speed: 667 MHz Manufacturer: Not Specified Serial Number: Not Specified Asset Tag: Not Specified Part Number: Not Specified Handle 0x0025, DMI type 17, 27 bytes Memory Device Array Handle: 0x001E Error Information Handle: No Error Total Width: Unknown Data Width: Unknown Size: No Module Installed Form Factor: DIMM Set: 1 Locator: JXXX Bank Locator: DIMM 12 Type: DDR2 Type Detail: Synchronous Speed: 667 MHz Manufacturer: Not Specified Serial Number: Not Specified Asset Tag: Not Specified Part Number: Not Specified Handle 0x0026, DMI type 17, 27 bytes Memory Device Array Handle: 0x001E Error Information Handle: No Error Total Width: Unknown Data Width: Unknown Size: No Module Installed Form Factor: DIMM Set: 1 Locator: JXXX Bank Locator: DIMM 13 Type: DDR2 Type Detail: Synchronous Speed: 667 MHz Manufacturer: Not Specified Serial Number: Not Specified Asset Tag: Not Specified Part Number: Not Specified Does anyone know why it would show 8 slots, with 4 empty instead of 6 slots with 2 empty? Also, but my records and by other tools, the server has 16Gb and not 8Gb in it currently. grep MemTotal /proc/meminfo MemTotal: 16435808 kB The board is a Tyan S5372-LC, running CentOS 5.4 x64. Also, my error log is showing errors in bank 6. Is there any way to determine which slot bank 6 is in via: dmidecode?

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• Runtime error of TASM language help!

  - by dominoos

  .model small .stack 400h .data message db "hello. ", 0ah, 0dh, "$" firstdigit db ? seconddigit db ? thirddigit db ? number dw ? newnumber db ? anumber dw 0d bnumber dw 0d Firstn db 0ah, 0dh, "Enter first 3 digit number: ","$" secondn db 0ah, 0dh, "Enter second 3 digit number: ","$" messageB db 0ah, 0dh, "HCF of two number is: ","$" linebreaker db 0ah, 0dh, ' ', 0ah, 0dh, '$' .code Start: mov ax, @data ; establish access to the data segment mov ds, ax ; mov number, 0d mov dx, offset message ; print the string "yob choi 0648293" mov ah, 9h int 21h num: mov dx, offset Firstn ; print the string "put 1st 3 digit" mov ah, 9h int 21h ;run JMP FirstFirst ; jump to FirstFirst FirstFirst: ;first digit mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov firstdigit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, doubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer mov cx, 100d ;This is so we can calculate 100*1st digit +10*2nd digit + 3rd digit mul cx ;start to accumulate the 3 digit number in the variable imul cx ;it is understood that the other operand is ax ; the result will use both dx::ax ;dx will contain only leading zeros add anumber, ax ;save ;Second Digit mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov seconddigit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, boubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer mov cx, 10d ;continue to accumulate the 3 digit number in the variable mul cx ;it is understood that the other operand is ax, containing first digit ;the result will use both dx::ax ;dx will contain only leading zeros. add anumber, ax ;save ;third Digit mov ah, 1d ;samething as above int 21h ; mov thirddigit, al ; sub al, 30h ; cbw ; add anumber, ax ; jmp num2 ;go to checks Num2: mov dx, offset secondn ; print the string "put 2nd 3 digits" mov ah, 9h int 21h ;run JMP SecondSecond SecondSecond: ;first digit mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov firstdigit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, doubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer mov cx, 100d ;This is so we can calculate 100*1st digit +10*2nd digit + 3rd digit mul cx ;start to accumulate the 3 digit number in the variable imul cx ;it is understood that the other operand is ax ; the result will use both dx::ax ;dx will contain only leading zeros add bnumber, ax ;save ;Second Digit mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov seconddigit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, boubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer mov cx, 10d ;continue to accumulate the 3 digit number in the variable mul cx ;it is understood that the other operand is ax, containing first digit ;the result will use both dx::ax ;dx will contain only leading zeros. add bnumber, ax ;save ;third Digit mov ah, 1d ;samething as above int 21h ; mov thirddigit, al ; sub al, 30h ; cbw ; add bnumber, ax ; jmp compare ;go to compare compare: CMP ax, anumber ;comparing numbB and Number JA comp1 ;go to comp1 if anumber is bigger CMP ax, anumber ; JB comp2 ;go to comp2 if anumber is smaller CMP ax, anumber ; JE equal ;go to equal if two numbers are the same JMP compare ;go to compare (avioding error) comp1: SUB ax, anumber; subtract smaller number from bigger number JMP compare ; comp2: SUB anumber, ax; subtract smaller number from bigger number JMP compare ; equal: mov ah, 9d ;make linkbreak after the 2nd 3 digit number mov dx, offset linebreaker int 21h mov ah, 9d ;print "HCF of two number is:" mov dx, offset messageB int 21h mov ax,anumber ;copying 2nd number into ax add al,30h ; converting to ascii mov newnumber,al ; copying from low part of register into newnumb mov ah, 2d ;bios code for print a character mov dl, newnumber ;we had saved the ascii code here int 21h ;call to bios JMP exit; exit: mov ah, 4ch int 21h ;exit the program End hi, this is a program that finds highest common factor of 2 different 3digit number. if i put 200, 235,312 (low numbers) it works fine. but if i put 500, 550, 654(bigger number) the program crashes after the 2nd 3digit number is entered. can you help me to find out what problem is?

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• How to find the list of all available packages along with the lastest version number available in the repositories?

  - by Avinash Raj

  I want to list all the packages(installed or not installed) along with the latest version number available in the repositories. For example: The output of apt-cache policy chromium-browser shows like below $ apt-cache policy chromium-browser chromium-browser: Installed: (none) Candidate: 34.0.1847.116-0ubuntu2 Version table: 34.0.1847.116-0ubuntu2 0 500 http://ftp.cuhk.edu.hk/pub/Linux/ubuntu/ trusty/universe amd64 Packages So the latest version of chromium-browser package available in the repository is 34.0.1847.116-0ubuntu2. Like that, i want to list the version number along with the package names that are available in repositories. And all i want to do this through command-line. I want the output to be like this, chromium-browser 34.0.1847.116-0ubuntu2 xxxxxxxxxxxxxx yyyyyyyyyyy ............ ............

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• Why don't computers store decimal numbers as a second whole number?

  - by SomeKittens

  Computers have trouble storing fractional numbers where the denominator is something other than a solution to 2^x. This is because the first digit after the decimal is worth 1/2, the second 1/4 (or 1/(2^1) and 1/(2^2)) etc. Why deal with all sorts of rounding errors when the computer could have just stored the decimal part of the number as another whole number (which is therefore accurate?) The only thing I can think of is dealing with repeating decimals (in base 10), but there could have been an edge solution to that (like we currently have with infinity).

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• Can I find out the number of searches on a given keyword, per state?

  - by Philippe

  I know that Google tells you how many times a certain keyword is used in a search. You can use the Google Keyword Tool for that. This tool also allows you to find out the number of "local" searches: this is the number of times a person from a given country searches for this keyword. My questions: can you also find out how many searches originate from a given American state ? In the Keyword Tool, I can only select countries, not states. Any other systems I can use to determine where people are searching for a given keyword?

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• php , SimpleXML, while loop

  - by Michael

  I'm trying to get some information from ebay api and store it in database . I used simple xml to extract the information but I have a small issue as the information is not displayed for some items . if I make a print to the simple_xml I can see very well that the information is provided by ebay api . I have $items = "220617293997,250645537939,230485306218,110537213815,180519294810"; $number_of_items = count(explode(",", $items)); $xml = $baseClass->getContent("http://open.api.ebay.com/shopping?callname=GetMultipleItems&responseencoding=XML&appid=Morcovar-c74b-47c0-954f-463afb69a4b3&siteid=0&version=525&IncludeSelector=ItemSpecifics&ItemID=$items"); writeDoc($xml, "api.xml"); //echo $xml; $getvalues = simplexml_load_file('api.xml'); // print_r($getvalue); $number = "0"; while($number < 6) { $item_number = $getvalues->Item[$number]->ItemID; $location = $getvalues->Item[$number]->Location; $title = $getvalues->Item[$number]->Title; $price = $getvalues->Item[$number]->ConvertedCurrentPrice; $manufacturer = $getvalues->Item[$number]->ItemSpecifics->NameValueList[3]->Value; $model = $getvalues->Item[$number]->ItemSpecifics->NameValueList[4]->Value; $mileage = $getvalues->Item[$number]->ItemSpecifics->NameValueList[5]->Value; echo "item number = $item_number <br>localtion = $location<br>". "title = $title<br>price = $price<br>manufacturer = $manufacturer". "<br>model = $model<br>mileage = $mileage<br>"; $number++; } the above code returns item number = localtion = title = price = manufacturer = model = mileage = item number = 230485306218 localtion = Coventry, Warwickshire title = 2001 LAND ROVER RANGE ROVER VOGUE AUTO GREEN price = 3635.07 manufacturer = Land Rover model = Range Rover mileage = 76000 item number = 220617293997 localtion = Crawley, West Sussex title = 2004 CITROEN C5 HDI LX RED price = 3115.77 manufacturer = Citroen model = C5 mileage = 76000 item number = 180519294810 localtion = London, London title = 2000 VOLKSWAGEN POLO 1.4 SILVER 16V NEED GEAR BOX price = 905.06 manufacturer = Right-hand drive model = mileage = Standard Car item number = localtion = title = price = manufacturer = model = mileage = As you can see the information is not retrieved for a few items ... If I replace the $number manually like " $item_number = $getvalues-Item[4]-ItemID;" works well for any number .

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• Java language convention; getters/setters

  - by Skogen

  Public class Example { private int number; public Example(int number){ this.number = number; } public int getNumber(){ return number; } public void setNumber(int number){ this.number = number; } public static void main(String[] args){ Example e = new Example(5); What is preffered when accessing a variable within its own class; "e.number" or "e.getNumber()" ?

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• What Are Some Tips For Writing A Large Number of Unit Tests?

  - by joshin4colours

  I've recently been tasked with testing some COM objects of the desktop app I work on. What this means in practice is writing a large number (100) unit tests to test different but related methods and objects. While the unit tests themselves are fairly straight forward (usually one or two Assert()-type checks per test), I'm struggling to figure out the best way to write these tests in a coherent, organized manner. What I have found is that copy and Paste coding should be avoided. It creates more problems than it's worth, and it's even worse than copy-and-paste code in production code because test code has to be more frequently updated and modified. I'm leaning toward trying an OO-approach using but again, the sheer number makes even this approach daunting from an organizational standpoint due to concern with maintenance. It also doesn't help that the tests are currently written in C++, which adds some complexity with memory management issues. Any thoughts or suggestions?

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• How do I figure out the minimum number of swaps to sort a list in-place?

  - by sova

  In-place sorting is essentially swapping elements without using extra storage, correct? How can I find the minimum number of swaps required for a list? A C D Q R Z E // input | | | > > > <<< // movement A C D E Q R Z // output Swapping: A C D Q R Z E swap Q with E, ACDERZQ swap R with Q, ACDEQZR swap R with Z, ACDEQRZ. done. 3 swaps. Shifting items left or right is essentially swapping, but I want the optimal number for plucking an item out of line and switching its place with another.

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• True / false evaluation doesn't work as expected in Scheme

  - by ron

  I'm trying to compare two booleans : (if (equal? #f (string->number "123b")) "not a number" "indeed a number") When I run this in the command line of DrRacket I get "not a number" , however , when I put that piece of code in my larger code , the function doesn't return that string ("not a number") , here's the code : (define (testing x y z) (define badInput "ERROR") (if (equal? #f (string->number "123b")) "not a number" "indeed a number") (display x)) And from command line : (testing "123" 1 2) displays : 123 Why ? Furthermore , how can I return a value , whenever I choose ? Here is my "real" problem : I want to do some input check to the input of the user , but the thing is , that I want to return the error message if I need , before the code is executed , because if won't - then I would run the algorithm of my code for some incorrect input : (define (convert originalNumber s_oldBase s_newBase) (define badInput "ERROR") ; Input check - if one of the inputs is not a number then return ERROR (if (equal? #f (string->number originalNumber)) badInput) (if (equal? #f (string->number s_oldBase)) badInput) (if (equal? #f (string->number s_newBase)) badInput) (define oldBase (string->number s_oldBase)) (define newBase (string->number s_newBase)) (define outDecimal (convertIntoDecimal originalNumber oldBase)) (define result "") ; holds the new number (define remainder 0) ; remainder for each iteration (define whole 0) ; the whole number after dividing (define temp 0) (do() ((= outDecimal 0)) ; stop when the decimal value reaches 0 (set! whole (quotient outDecimal newBase)) ; calc the whole number (set! temp (* whole newBase)) (set! remainder (- outDecimal temp)) ; calc the remainder (set! result (appending result remainder)) ; append the result (set! outDecimal (+ whole 0)) ; set outDecimal = whole ) ; end of do (if (> 1 0) (string->number (list->string(reverse (string->list result))))) ) ;end of method This code won't work since it uses another method that I didn't attach to the post (but it's irrelevant to the problem . Please take a look at those three IF-s ... I want to return "ERROR" if the user put some incorrect value , for example (convert "23asb4" "b5" "9") Thanks

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• how to find missing rows in oracle

  - by user203212

  Hi, I have a table called 2 tables create table ORDERS ( ORDER_NO NUMBER(38,0) not null, ORDER_DATE DATE not null, SHIP_DATE DATE null, SHIPPING_METHOD VARCHAR2(12) null, TAX_STATUS CHAR(1) null, SUBTOTAL NUMBER null, TAX_AMT NUMBER null, SHIPPING_CHARGE NUMBER null, TOTAL_AMT NUMBER null, CUSTOMER_NO NUMBER(38,0) null, EMPLOYEE_NO NUMBER(38,0) null, BRANCH_NO NUMBER(38,0) null, constraint ORDERS_ORDERNO_PK primary key (ORDER_NO) ); and create table PAYMENTS ( PAYMENT_NO NUMBER(38,0) NOT NULL, CUSTOMER_NO NUMBER(38,0) null, ORDER_NO NUMBER(38,0) null, AMT_PAID NUMBER NULL, PAY_METHOD VARCHAR(10) NULL, DATE_PAID DATE NULL, LATE_DAYS NUMBER NULL, LATE_FEES NUMBER NULL, constraint PAYMENTS_PAYMENTNO_PK primary key (PAYMENT_NO) ); I am trying to find how many late orders each customer have. the column late_days in PAYMENTS table has how many days the customer is late for making payments for any particular order. so I am making this query SELECT C.CUSTOMER_NO, C.lname, C.fname, sysdate, COUNT(P.ORDER_NO) as number_LATE_ORDERS FROM CUSTOMER C, orders o, PAYMENTS P WHERE C.CUSTOMER_NO = o.CUSTOMER_NO AND P.order_no = o.order_no AND P.LATE_DAYS>0 group by C.CUSTOMER_NO, C.lname, C.fname That means, I am counting the orders those have any late payments and late_days0. But this is giving me only the customers who have any orders with late_days0, but the customers who does not have any late orders are not showing up. so if one customer has 5 orders with late payments then it is showing 5 for that customer, but if a customer have 0 late orders,that customer is not selected in this query. Is there any way to select all the customers , and if he has any late orders, it will show the number and also if he does not have any late orders, it will show 0.

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• Why is it an issue that it takes 2 digits to represent the number 10 in decimal?

  - by Crizly

  So we use hexadecimal which has the advantage of going up to 15 in single digits A-F, but why is it an issue that it takes 2 digits to represent the number 10 in decimal? I was reading up about hexadecimal and I came across these 2 lines: Base 16 suggests the digits 0 to 15, but the problem we face is that it requires 2 digits to represent 10 to 15. Hexadecimal solves this problem by using the letters A to F. My question is, why do we care how many digits it takes to represent 15? What is the importance of this number, and how does denoting it with a single character have any value?

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• polymorphism in C++

  - by user550413

  I am trying to implement the next 2 functions Number& DoubleClass::operator+( Number& x); Number& IntClass::operator+(Number& x); I am not sure how to do it..(their unidirectionality is explained below): class IntClass; class DoubleClass; class Number { //return a Number object that's the results of x+this, when x is either //IntClass or DoubleClass virtual Number& operator+(Number& x) = 0; }; class IntClass : public Number { private: int my_number; //return a Number object that's the result of x+this. //The actual class of the returned object depends on x. //If x is IntClass, then the result if IntClass. //If x is DoubleClass, then the results is DoubleClass. public: Number& operator+(Number& x); }; class DoubleClass : public Number { private: double my_number; public: //return a DoubleClass object that's the result of x+this. //This should work if x is either IntClass or DoubleClass Number& operator+( Number& x); };

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• How to Limit the Number of Lines and Characters in a Textarea with Cross Browser Support?

  An article on how to limit the number of lines and characters in a textarea with cross browser support.

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• Common and maximum number of virtual machines per server?

  - by Rabarberski

  For a project I am trying to get real-life estimates for the number of virtual machines per server, both typically and maximally. Of course, the maximum number of VMs would be depending on the type of applications (disk intensive, network intensive, ...), and server hardware (like number of cores, memory, ...), but still it would be useful to know if a typical maximum is about 10, 20 or 30 VMs per server. Can anybody give practical numbers?

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• Can mod_fcgid maintain a hard-minimum number of available appserver processes?

  - by user9795

  ...and if so, how? I'm using Apache2 + mod_fcgid to serve a perl Catalyst application, on a box that I own, and I'd like for mod_fcgid to maintain a minimum number of spun-up processes ready to go. The docs say that FcgidMinProcessesPerClass only enforces a minimum number of processes that will be retained in a process class after finishing requests How do I get apache to start up with a certain number of appserver subprocesses on an idle server without using artificial load to get there?

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• Thunderbird 3: show total number of items in folder?

  - by Charles Roper

  In Thunderbird 3, is it possible to show the total number of items in a folder, rather than just the number of unread items?

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• What is the max supported number of SATA devices (using cable adapters) on a Dell SAS 6/iR adapter?

  - by Zac B

  I've got a Dell SAS 6/iR PCI-E adapter. I don't have a multiplier backplane. I'm planning on connecting SATA (non SAS) drives. If I buy cable adapters only (ones that split a SAS connector on the card to a certain number of SATA cables), how many drives can I connect to this card? The way I see it, there are two limitations: a limitation imposed by the theoretical max number of devices supported on the card (which I've dug through the specs to find, but haven't seen yet), and a limitation imposed by the number of SAS plugs on the card multiplied by the number of SATA cables that come out of the highest-multiplying splitter I can buy. The answer to my question would be the minimum of those two limitations. I've seen 4x SATA coming out of some splitters; are there any that have more? Alternatively, if this is an RTFM question, does anyone have a good link to a "this is how SAS works, this is how you figure out the max number of devices, and this is how the concepts of 'ports', 'lanes', 'endpoint devices', and 'connectors' all relate in SAS-land" document? I've looked around on the Dell docs, but haven't found anything that explains this to someone at my level of understanding of SAN/enterprise storage technologies. Cheers!

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• How is starting and ending row number of a Range obtained?

  - by Robert Kerr

  Given a user-selected Range, what is the simplest way to determine the starting row number, and ending row number? Range.Address returns a string containing any number of possible formats. There has to be something simpler. Desired: Dim oRange As Range Dim startRow As Integer Dim endRow As Integer oRange = Range("A1:X50") startRow = oRange.Address.StartRow endRow = oRange.Address.EndRow of course, those properties do not exist. I want to do the same to return column letters.

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• Wondering about the Windows 7 serial number my laptop has, and its uses.

  - by overmann

  So that's the serial number of my pre-installed windows copy, I take it. But am I allowed to use it again when, say, I don't know, my system gets crippled by a sneaky virus? If I format my computer and install windows starter again from a USB drive (speculating. I've never format before, I suppose is completely possible) Is that serial number still valid? I'm talking about the number printed on the back of my laptop.

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• What is the typical maximum number of database connections for Oracle running on Windows server ?

  - by Sake

  We are maintaining a database server that serve a large number of clients. Each client typically running serveral client-applications. The total number of connections to the database server (Oracle 9i) is reaching 800 connections on peak load. The windows 2003 server is starting to run out of memory. We are now planning to move to 64bit Windows in order to gain higher memory capability. As a developer I suggest moving to multi-tier architecture with conneciton pooling, which I believe is a natural solution to this problem. However, in order to support my idea, I want the information on: what exactly is the typical number of connections allowed for Oracle database ? What is the problem when the number connections is too high ? Too much memory comsumption ? or too many sockets opened ? or too many context switching between threads ? To be a little bit specific, how could Oracle Forms application scale to thousand of users without facing this problem ? Shall Oracle RAC applied to this case ? I'm sure the answer to this question should depend on quite a number of factors, like the exact spec of the hardware being used. I'm expecting a rough estimation or some experience from the real world.

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• How do I find the Serial Number of a USB Drive?

  - by jamuraa

  I'm trying to re-enable USB Autoplay in a secure way, by installing a program on each of the computers that I use so that I can run my launcher (PStart in this case) whenever I plug in my specific USB drive. The tool that I'm using to enable this - AutoRunGuard - needs the serial number of the USB drive that I am using. I can't figure out where to find this in Windows. Ideally I would not need to install and run a separate program to do this (seemingly) simple task. Since this is a pretty easy question, bonus points if you also tell me how to discover it in Linux as well. What steps do I need to take to retrieve a USB Drive's serial number? UPDATE: Just incase people come here looking for the answer for AutoRunGuard, I discovered that they don't want the USB device serial number, but the volume serial number. The drive serial can be found by going into the command line, navigating to the drive, and executing dir. The volume serial number is found in the top two lines - use it without the dash.

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• how to know which display number for the variable DISPLAY to be exported when ssh to server

  - by insidepower

  When i ssh to server using -X, i always confuse about which display number i should export. It seems to me sometimes the display number has been used by something, so what i can do is only export DISPLAY=localhost:0 && xclock export DISPLAY=localhost:1 && xclock export DISPLAY=localhost:2 && xclock export DISPLAY=localhost:... until the clock appear. Then i will use that display number. Each time log in to the server, the display number which is able to tunnel the gui data correct would be different. I know many of such similar questions has been asked and answer. However I couldn't find answer to my question, anyone know about it? Thanks!

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• How to auto dial 9+Number on Cisco 7941 redial?

  - by NotDan

  Is it possible to set up a Cisco 7941 phone to dial 9 before the redial number? When I view missed calls, and try to redial one of the numbers, it always fails because it doesn't dial 9 first. I have to write the number down and then manually dial the 9 and then the number.

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• Algorithm to add two digits to the end of a number to calculate a specific modulus?

  - by Jim

  So, lets say I have a number 123456. 123456 % 97 = 72. How can I determine what two digits need to be added to the end of 123456 such that the new number % 97 = 1? Note--it must always be two digits. For example, 12345676 % 97 = 1. In this case, I need to add the digits "76" to the end of the number. (This is for IBAN number calculation.)

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