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  • MVVM: Thin ViewModels and Rich Models

    - by Dan Bryant
    I'm continuing to struggle with the MVVM pattern and, in attempting to create a practical design for a small/medium project, have run into a number of challenges. One of these challenges is figuring out how to get the benefits of decoupling with this pattern without creating a lot of repetitive, hard-to-maintain code. My current strategy has been to create 'rich' Model classes. They are fully aware that they will be consumed by an MVVM pattern and implement INotifyPropertyChanged, allow their collections to be observed and remain cognizant that they may always be under observation. My ViewModel classes tend to be thin, only exposing properties when data actually needs to be transformed, with the bulk of their code being RelayCommand handlers. Views happily bind to either ViewModels or Models directly, depending on whether any data transformation is required. I use AOP (via Postsharp) to ease the pain of INotifyPropertyChanged, making it easy to make all of my Model classes 'rich' in this way. Are there significant disadvantages to using this approach? Can I assume that the ViewModel and View are so tightly coupled that if I need new data transformation for the View, I can simply add it to the ViewModel as needed?

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  • ASP.NET MVC: How do I validate a model wrapped in a ViewModel?

    - by Deniz Dogan
    For the login page of my website I would like to list the latest news for my site and also display a few fields to let the user log in. So I figured I should make a login view model - I call this LoginVM. LoginVM contains a Login model for the login fields and a List<NewsItem> for the news listing. This is the Login model: public class Login { [Required(ErrorMessage="Enter a username.")] [DisplayName("Username")] public string Username { get; set; } [Required(ErrorMessage="Enter a password.")] [DataType(DataType.Password)] [DisplayName("Password")] public string Password { get; set; } } This is the LoginVM view model: public class LoginVM { public Login login { get; set; } public List<NewsItem> newsItems { get; set; } } This is where I get stuck. In my login controller, I get passed a LoginVM. [HttpPost] public ActionResult Login(LoginVM model, FormCollection form) { if (ModelState.IsValid) { // What? In the code I'm checking whether ModelState is valid and this would work fine if the view model was actually the Login model, but now it's LoginVM which has no validation attributes at all. How do I make LoginVM "traverse" through its members to validate them all? Am I doing something fundamentally wrong using ModelState in this manner?

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  • My QFileSystemModel doesn't work as expected in PyQt

    - by Skilldrick
    I'm learning the Qt Model/View architecture at the moment, and I've found something that doesn't work as I'd expect it to. I've got the following code (adapted from Qt Model Classes): from PyQt4 import QtCore, QtGui model = QtGui.QFileSystemModel() parentIndex = model.index(QtCore.QDir.currentPath()) print model.isDir(parentIndex) #prints True print model.data(parentIndex).toString() #prints name of current directory childIndex = model.index(0, 0, parentIndex) print model.data(childIndex).toString() rows = model.rowCount(parentIndex) print rows #prints 0 (even though the current directory has directory and file children) The question: Is this a problem with PyQt, have I just done something wrong, or am I completely misunderstanding QFileSystemModel? According to the documentation, model.rowCount(parentIndex) should return the number of children in the current directory. The QFileSystemModel docs say that it needs an instance of a Gui application, so I've also placed the above code in a QWidget as follows, but with the same result: import sys from PyQt4 import QtCore, QtGui class Widget(QtGui.QWidget): def __init__(self, parent=None): QtGui.QWidget.__init__(self, parent) model = QtGui.QFileSystemModel() parentIndex = model.index(QtCore.QDir.currentPath()) print model.isDir(parentIndex) print model.data(parentIndex).toString() childIndex = model.index(0, 0, parentIndex) print model.data(childIndex).toString() rows = model.rowCount(parentIndex) print rows def main(): app = QtGui.QApplication(sys.argv) widget = Widget() widget.show() sys.exit(app.exec_()) if __name__ == '__main__': main()

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  • C# .NET Why does my inherited listview keep drawing in LargeIcon View ?? Because Microsoft is Evil!!

    - by Bugz R us
    I have a inherited Listview which standard has to be in Tile Mode. When using this control, the DrawItem gives e.bounds which are clearly bounds of largeIcon view ?? When debugging to check the view it is actually set to, it says it's in Tile view ?? Yet e.DrawText draws LargeIcon view ?? ......... Edit: ................. This seems only to happen when the control is placed upon another usercontrol? ......... Edit 2: ................. It gets stranger ... When i add buttons next to the list to change the view at runtime, "Tile" is the same as "LargeIcon", and "List" view is the same as "SmallIcons" ??? I've also completely removed the ownerdraw ... .......... Edit 3: ................. MSDN Documentation: Tile view Each item appears as a full-sized icon with the item label and subitem information to the right of it. The subitem information that appears is specified by the application. This view is available only on Windows XP and the Windows Server 2003 family. On earlier operating systems, this value is ignored and the ListView control displays in the LargeIcon view. Well I am on XP ya damn liars ?!? Apparently if the control is within a usercontrol, this value is ignored too ... pff I'm getting enough of this Microsoft crap .... you just keep on hitting bugs ... another day down the drain ... public class InheritedListView : ListView { //Hiding members ... mwuahahahahaha //yeah i was still laughing then [BrowsableAttribute(false)] public new View View { get { return base.View; } } public InheritedListView() { base.View = View.Tile; this.OwnerDraw = true; base.DrawItem += new DrawListViewItemEventHandler(DualLineGrid_DrawItem); } void DualLineGrid_DrawItem(object sender, DrawListViewItemEventArgs e) { View v = this.View; //**when debugging, v is Tile, however e.DrawText() draws in LargeIcon mode, // e.Bounds also reflects LargeIcon mode ???? ** }

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  • OSX Finder - Creating New Folder with Right-Click in List View

    - by JT.WK
    I am aware that when using finder in List view, I can create a new folder by right-clicking on an empty row, and pressing 'New Folder'. However, when I happen to be browsing a folder with quite a lot of files (or just enough to invoke a scrollbar), there are no blank rows, and hence nowhere that I can right-click to create a new folder. This is not a big problem, I am just a whinger who likes consistency and find this frustrating. Yes, I am aware that I can press 'Shift + Cmd + N', or can simply change the Finder view. BUT, is there a way to do this within list view? Am I missing something obvious?

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  • IE8 Compatibility View issues

    - by 08Hawkeye
    I have the IE7 emulater tag in a jsp layout. But when I bring up the page, it defaults to the IE8 view until the user clicks the Compatibility View button. I don't want the user to have to click the button to launch compatibility mode. Is there a way to force IE7 Emulation on pageLoad? I'd even like to disable the button (or any potential to toggle between IE8 standard mode/IE7 view). Thanks! //sw Update: Now the button seems to have disappeared entirely, but still defaults to IE8 standards. Where did it go?! The toolbar context menu has it as selected, but the tools dropdown menu has it grayed out. For my purposes, it is unacceptable for the user to have to use the developer tools or even click the button to trigger emulation, but I don't know why the button disappeared anyway...

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  • Mac OS X Finder - Creating New Folder with Right-Click in List View

    - by JT.WK
    I am aware that when using Finder in List view, I can create a new folder by right-clicking on an empty row, and pressing 'New Folder'. However, when I happen to be browsing a folder with quite a lot of files (or just enough to invoke a scrollbar), there are no blank rows, and hence nowhere that I can right-click to create a new folder. This is not a big problem, I am just a whinger who likes consistency and find this frustrating. Yes, I am aware that I can press Shift + Cmd + N, or can simply change the Finder view. BUT, is there a way to do this within list view? Am I missing something obvious? Edit: oh, and I'm using Snow Leopard (version 10.6) :)

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  • View another persons calendar details in Outlook 2010

    - by rwmnau
    I know how to view somebody else's calendar - there are 100 walk-throughs like this one on Google. However, this feature has changed in Outlook 2010, and you no longer get prompted for rights to view another person's calendar, and Outlook just displays their "Free/Busy" information, which doesn't help me. I'd like to request permissions to view the details of their appointments, but I can't find any place to request permissions on their calendar - Outlook 2010 just gives me "Free/Busy" rights and then appears to have no option to request additional rights. Can anybody point me in the right direction?

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  • View another persons calendar details in Outlook 2010

    - by SqlRyan
    I know how to view somebody else's calendar - there are 100 walk-throughs like this one on Google. However, this feature has changed in Outlook 2010, and you no longer get prompted for rights to view another person's calendar, and Outlook just displays their "Free/Busy" information, which doesn't help me. I'd like to request permissions to view the details of their appointments, but I can't find any place to request permissions on their calendar - Outlook 2010 just gives me "Free/Busy" rights and then appears to have no option to request additional rights. Can anybody point me in the right direction?

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  • View scheduled recordings remotely

    - by Scott
    I have one computer which is equipped with a TV tuner card. The Recorded TV folder is shared so that other computers on the network can watch recordings. Now that I am upgrading my computers to Windows 7, they have Media Center, which makes for a nicer viewing experience than a Windows Explorer folder view. I have set up Media Center on my laptop to considering the Recorded TV folder on the tuner-equipped PC as an extended library location, so now I can view all the recordings from within Media Center on the laptop. To make this experience even better, is there a way to view the list of scheduled recordings on the tuner-equipped PC from within Media Center on my laptop?

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  • Shared Exchange Calendar View

    - by Mark A Johnson
    My department creates a shared calendar for everyone to enter their out-of-office times. This requires duplicate entry for those of us who keep all our info in our own Exchange calendar. Is there a way in Exchange to create a View that's simply a combination view of multiple users' calendars? For example, we would create a view with all the departments' users calendars combined, but only those marked "out of office". Ideally, the subject line would also include the user's name, but this would not be 100% necessary.

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  • View apache server across virtual machine?

    - by Mark
    I installed VirtualBox on my Windows 7 machine. Through VirtualBox, I installed Ubuntu 9.10 with apache2. I can view http://localhost from Ubuntu, but is there anyway I can view it from my windows machine too? i.e. run the apache server on ubuntu, and view it from windows? I figured it would open a port or something that would be visible to my whole computer regardless of its virtualness, but I guess not. How do I get around this?

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  • Django manager for _set in model

    - by Daniel Johansson
    Hello, I'm in the progress of learning Django at the moment but I can't figure out how to solve this problem on my own. I'm reading the book Developers Library - Python Web Development With Django and in one chapter you build a simple CMS system with two models (Story and Category), some generic and custom views together with templates for the views. The book only contains code for listing stories, story details and search. I wanted to expand on that and build a page with nested lists for categories and stories. - Category1 -- Story1 -- Story2 - Category2 - Story3 etc. I managed to figure out how to add my own generic object_list view for the category listing. My problem is that the Story model have STATUS_CHOICES if the Story is public or not and a custom manager that'll only fetch the public Stories per default. I can't figure out how to tell my generic Category list view to also use a custom manager and only fetch the public Stories. Everything works except that small problem. I'm able to create a list for all categories with a sub list for all stories in that category on a single page, the only problem is that the list contains non public Stories. I don't know if I'm on the right track here. My urls.py contains a generic view that fetches all Category objects and in my template I'm using the *category.story_set.all* to get all Story objects for that category, wich I then loop over. I think it would be possible to add a if statement in the template and use the VIEWABLE_STATUS from my model file to check if it should be listed or not. The problem with that solution is that it's not very DRY compatible. Is it possible to add some kind of manager for the Category model too that only will fetch in public Story objects when using the story_set on a category? Or is this the wrong way to attack my problem? Related code urls.py (only category list view): urlpatterns += patterns('django.views.generic.list_detail', url(r'^categories/$', 'object_list', {'queryset': Category.objects.all(), 'template_object_name': 'category' }, name='cms-categories'), models.py: from markdown import markdown import datetime from django.db import models from django.db.models import permalink from django.contrib.auth.models import User VIEWABLE_STATUS = [3, 4] class ViewableManager(models.Manager): def get_query_set(self): default_queryset = super(ViewableManager, self).get_query_set() return default_queryset.filter(status__in=VIEWABLE_STATUS) class Category(models.Model): """A content category""" label = models.CharField(blank=True, max_length=50) slug = models.SlugField() class Meta: verbose_name_plural = "categories" def __unicode__(self): return self.label @permalink def get_absolute_url(self): return ('cms-category', (), {'slug': self.slug}) class Story(models.Model): """A hunk of content for our site, generally corresponding to a page""" STATUS_CHOICES = ( (1, "Needs Edit"), (2, "Needs Approval"), (3, "Published"), (4, "Archived"), ) title = models.CharField(max_length=100) slug = models.SlugField() category = models.ForeignKey(Category) markdown_content = models.TextField() html_content = models.TextField(editable=False) owner = models.ForeignKey(User) status = models.IntegerField(choices=STATUS_CHOICES, default=1) created = models.DateTimeField(default=datetime.datetime.now) modified = models.DateTimeField(default=datetime.datetime.now) class Meta: ordering = ['modified'] verbose_name_plural = "stories" def __unicode__(self): return self.title @permalink def get_absolute_url(self): return ("cms-story", (), {'slug': self.slug}) def save(self): self.html_content = markdown(self.markdown_content) self.modified = datetime.datetime.now() super(Story, self).save() admin_objects = models.Manager() objects = ViewableManager() category_list.html (related template): {% extends "cms/base.html" %} {% block content %} <h1>Categories</h1> {% if category_list %} <ul id="category-list"> {% for category in category_list %} <li><a href="{{ category.get_absolute_url }}">{{ category.label }}</a></li> {% if category.story_set %} <ul> {% for story in category.story_set.all %} <li><a href="{{ story.get_absolute_url }}">{{ story.title }}</a></li> {% endfor %} </ul> {% endif %} {% endfor %} </ul> {% else %} <p> Sorry, no categories at the moment. </p> {% endif %} {% endblock %}

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  • switch views using a button, going to a table view, iphone

    - by Jaime Rae
    My program has 4 buttons and each button calls a different table view. That works fine, but my problem is, the view controller I'm using brings up a table view that covers up my navigation bar and my tab bar. I need to replace that coding with something that will bring up a table and not cover up my nav and tab bars. Here is the coding I'm using: -(IBAction)buttonNorthWest { NorthWestViewController *nwController = [[NorthWestViewController alloc] initWithNibName:@"NorthWestView" bundle:nil]; self.nwViewController = nwController; [self.view insertSubview:nwViewController.view atIndex:0]; [self presentModalViewController:nwViewController animated:YES]; [nwController release]; } The [self presentModalViewController....] is the problem. Does anyone know how I can replace that code with something that keeps my nav and tab bars? Thanks, Jaime

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  • displaying web pages over web views in collection view using cocoa bindings

    - by Miraaj
    Hi all, I tried sample example given at this link - Collection View Programming Guide It is simple and it worked. Considering it as a reference I tried a simple application which will show a collection view of web views with some web page displayed over each web view. The model class has two properties: NSString *pageName, and NSURL *pageURL. I then followed each and every step written in tutorial above with required modifications but I was caught in the step - How to bind web view to collection view item? In binding tab it shows three possibilities : Editable, Hidden, Tool tip but none of these is working. Can anyone suggest me way to accomplish my requirement? Thanks, Miraaj

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  • CruiseControl failing view compilation with Asp.net MVC 2 RTM

    - by Robert Koritnik
    Tehnologies: - CruiseControlNet - Asp.net MVC 2 RTM - enabled view compilation The problem is UrlParameter.Optional setting. I can't seem to make it work when I use this setting inside a view. When I compile inside Visual Studio, everything works fine, but when CCNet uses MSBuild to compile it it fails with following error: errorCS0103: The name 'UrlParameter' does not exist in the current context pointing to the line inside my view where this parameter is set on: Html.RenderAction(...) that sets certain route parameter(s) to optional. I tried adding <%@ Assembly name="System.Web.Mvc" %> at the top of my view, but it didn't work either. It works of course when I disable view compilation, but that's not really an option. And I also don't want to set my optional parameters to string.Empty. Anyone has any hint on this?

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  • iPhone - how to find a parent View

    - by Oscar Peli
    Hi there, I need some help to find a View inside a hierarchy. Here is how I build up the View stack. Inside my first UITableViewController I push an UIViewController that contains an UITabBarController: [[self navigationController] pushViewController:itemVC animated:YES]; Inside the UITabBarController I add an UITableViewController: ISSTableViewController *graphics = (ISSTableViewController *)[tabBarController.viewControllers objectAtIndex:3]; Inside the didSelectRowAtIndexPath I present a Modal View Controller using a UINavigationController: GraficoViewController *graph = [[GraficoViewController alloc] initWithNibName:@"GraficoViewController" bundle:nil]; UINavigationController *navigationController = [[UINavigationController alloc] initWithRootViewController:graph]; [self presentModalViewController:navigationController animated:YES]; [navigationController release]; Now the (BIG) question is: I have to hide the NagivationBar of my first UITableViewController inside my last view. I tried with this: [[[[[self parentViewController] parentViewController] parentViewController] navigationController] setNavigationBarHidden:YES]; but it doesn't work. Can someone tell me how I can find my ancestor View??? Thanks.

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  • Entity Framework and Sql Server view question

    - by Sergio Romero
    Hi to all, For several reasons that I don't have the liberty to talk about, we are defining a view on our Sql Server 2005 database like so: CREATE VIEW [dbo].[MeterProvingStatisticsPoint] AS SELECT CAST(0 AS BIGINT) AS 'RowNumber', CAST(0 AS BIGINT) AS 'ProverTicketId', CAST(0 AS INT) AS 'ReportNumber', GETDATE() AS 'CompletedDateTime', CAST(1.1 AS float) AS 'MeterFactor', CAST(1.1 AS float) AS 'Density', CAST(1.1 AS float) AS 'FlowRate', CAST(1.1 AS float) AS 'Average', CAST(1.1 AS float) AS 'StandardDeviation', CAST(1.1 AS float) AS 'MeanPlus2XStandardDeviation', CAST(1.1 AS float) AS 'MeanMinus2XStandardDeviation' WHERE 0 = 1 The idea is that the Entity Framework will create an entity based on this query, which it does, but it generates it with an error that states the following: "warning 6002: The table/view 'Keystone_Local.dbo.MeterProvingStatisticsPoint' does not have a primary key defined. The key has been inferred and the definition was created as a read-only table/view." And it decides that the CompletedDateTime field will be this entity primary key. We are using EdmGen to generate the model. Is there a way not to have the entity framework include any field of this view as a primary key? Thanks for help.

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  • Modal View Controller with keyboard on landscape iPad changes location when dismissed

    - by Roi
    I present a modal view controller on my on my iPad with UIModalPresentationFormSheet presentation style and UIModalTransitionStyleCoverVertical transition style. The Modal View Controller contains a UIWebView with some TextFields on it. When the user taps one of the text fields the keyboard comes up. I have noticed that in landscape mode after the keyboard is shown, if I try to dismiss the modal view controller with animation the view changes its position from the center of the screen to the left side just before the animation starts.. This happens only if the keyboard is up and only in landscape mode on the iPad. If the user closes the modal view without pressing on any text field this doesn't happen. Anyone familiar with this strange behavior?

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  • Unable to load detached NIB in View

    - by Sheehan Alam
    I have two NIB's ParentViewController.xib ChildViewController.xib ParentViewController.xib contains a UIView and a UIViewController. ChildViewController.xib contains a UIButton I want ChildViewController.xib to load in the ParentViewController.xib's UIView I have done the following: Created @property for UIView in ParentViewController Connected File's Owner to UIView in ParentViewController Set UIViewController in ParentViewController's NIB Name property to ChildViewController in Interface Builder Set ChildViewController view property to UIView in ParentViewController I was hoping this would load ChildViewController into my UIView in ParentViewController but no luck. I did get the following warning, which could be the culprit: 'View Controller (Child View)' has both its 'NIB Name' property set and its 'view' outlet connected. This configuration is not supported. I also have added additional code in ParentViewController's viewDidLoad(): - (void)viewDidLoad { [super viewDidLoad]; ChildViewController *childViewController = [[ChildViewController alloc]initWithNibName:@"ChildViewController" bundle:nil]; childViewController.view = self.myView; } Any thoughts on why ChildViewController does not load in the UIView of ParentViewController?

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  • Open working copy file from eclipse history view

    - by Wolfgang
    The history view of eclipse shows you a list of files changed in a certain revision. When you open the context menu on one of these you have the option 'Open' which opens a view of that file in that revision. How can I open the editor for the selected file, i.e. the file in the version of the working copy, right from the history view? Background is that I want to use the history view to find files that have been changed recently to do code reviewing. People commit via subversion and I use subclipse to connect eclipse to the subversion server. Today, I must use the 'Open resource'/'Open type' function and type the name of the file that I can read from the history view.

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  • Table View rotate, but not properly (shape change)

    - by Pencrace
    Hello everyone, Here is the thing. I have a ViewController which contain a view in full window. And the program run in landscape mode. I want to put an UITableView over the full screen view but only on right half part of the screen. So I add a UITableView in my view controller, I used the Interface Builder in order to set the Table View in the upper half of the screen so It will be on the right part in LandscapeLeft mode. I searched for on a lot of forum how to rotate my Table View. And so it does... except, It get stuck on the upper half of the landscape mode, it should stick on the right half. I'm not a iPhone coder since long, so I'm a bit confused on how to solve this problem. Do you have any idea on how to resize or make the TableView rotate properly. Thanks,

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  • UIViewController prevent view from unloading

    - by Ican Zilb
    When my iPhone app receives a Memory warning the views of UIViewControllers that are not currently visible get unloaded. In one particular controller unloading the view and the outlets is rather fatal. I'm looking for a way to prevent this view from being unloaded. I find this behavior rather stupid - I have a cache mechanism, so when a memory warning comes - I unload myself tons of data and I free enough memory, but I definitely need this view untouched. I see UIViewController has a method 'unloadViewIfReloadable', which gets called when the Memory Warning comes. Does anybody know how to tell Cocoa Touch that my view is not reloadable? Any other suggestions how to prevent my view from being unloaded on Memory Warning? Thanks in advance

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  • Iphone sdk - please help , 1 view takes me 45 minutes to do :(

    - by Dave
    Hey, I've been working on a Cook Book App but each view ( or recipie page) takes about 45 minutes to complete so as you can imagine its taking forever. The problem is that I have to manually: Set up a gradient image for the back ground (Somtimes I have to add a few image backgrounds to fit the view as I often use a scroll view, not sure how this could be automated?) Put an image behind the titles "Recipe name" , "Time needed" and an image to go behind the recipie instructions ( again I might need a few of these depending on how long the description is. Creating view controllers for main sections such as "Breakfast" and "Lunch" and then I need to manually create view controllers to go in these sections. Theres got to be a way to set up a template for this? Thanks for reading all of this.

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