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  • Random Excel bug when referencing a different sheet

    - by Matteo
    I am getting a very strange error anytime I try to use a formula pointing to a cell in a different sheet from the active one (even as simple as "=Sheet2!A1"). This started happening all of a sudden, and without any change in the system - only I seem to having started having the problem since I started using a workbook from another colleague with the same issue. I'm running Excel 2003 SP3 on XP. With little variants, whenever I reference a cell in a different sheet, from any formula, and then press Enter, the formula gets written on a different cell from the one I was editing it in, and throws a REF error. Example: I start editing in cell A1 of Sheet 1, type "=", then move the cursor to cell B2 of Sheet 2 (that may contain any value), and press Enter. At this stage you would expect cell A1 in Sheet 1 to contain formula "=Sheet2!B2" and display the value in that cell. Instead what happens is that the cell remains empty, and another random cell of Sheet 1 gets populated with something like "=Sheet2!#REF!" throwing an error. Interestingly, the error does not happen when I manually type the cell reference in (ie. without moving the cursor to the second sheet). Hope this is making any sense - any ideas are welcome! Thanks.

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  • MySQL – Introduction to CONCAT and CONCAT_WS functions

    - by Pinal Dave
    MySQL supports two types of concatenation functions. They are CONCAT and CONCAT_WS CONCAT function just concats all the argument values as such SELECT CONCAT('Television','Mobile','Furniture'); The above code returns the following TelevisionMobileFurniture If you want to concatenate them with a comma, either you need to specify the comma at the end of each value, or pass comma as an argument along with the values SELECT CONCAT('Television,','Mobile,','Furniture'); SELECT CONCAT('Television',',','Mobile',',','Furniture'); Both the above return the following Television,Mobile,Furniture However you can omit the extra work by using CONCAT_WS function. It stands for Concatenate with separator. This is very similar to CONCAT function, but accepts separator as the first argument. SELECT CONCAT_WS(',','Television','Mobile','Furniture'); The result is Television,Mobile,Furniture If you want pipeline as a separator, you can use SELECT CONCAT_WS('|','Television','Mobile','Furniture'); The result is Television|Mobile|Furniture So CONCAT_WS is very flexible in concatenating values along with separate. Reference: Pinal Dave (http://blog.sqlauthority.com)Filed under: MySQL, PostADay, SQL, SQL Authority, SQL Query, SQL Tips and Tricks, T SQL

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  • SQL SERVER – Caption the Cartoon Contest – Last 2 Days

    - by pinaldave
    Developer’s life is very interesting, we often want to start my day early at a job so we can go home early. However, the day never comes as the life of the developer is always about working late hours. If the developer goes to the office early – there are good chances that his co-workers will come late. Additionally, I am confident that there will be always something urgent for developers or DBA to solve right at the time they are ready to go home. This is the life of the developers!  Here is the interesting story of a DBA who was about to go to the home. He had to take his girlfriend to a movie and dinner in 30 minutes. However, his manager asks him to fix the performance related issues with their production server. In normal case, he had only two choices a) Job or b) Girlfriend. Well, our super hero DBA decided to use efficient tools and improve the performance of the production server in merely 30 minutes. When he was done, his manager was absolutely surprised by his efficiency and accuracy of the work. He asked him following question - Here is the contest – you need to guess what was the answer of our Super Hero DBA. If you guess the answer correct you may win Star Wars R2-D2 Inflatable Remote Controlled device. Additionally, if you Download DB Optimizer before Dec 8, 2012 – you will be eligible for USD 25 Amazon Gift Card (there are total 10 such awards). Please do not leave comments in this thread – to participate in the contest – please leave a comment here in the original contest page. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Puzzle, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • How to log error queries in mysql?

    - by Kaizoku
    I know that there is general_log that logs all queries, but I want to find out which query has an error, and get the error message. I have tried running an error query on purpose, but it logs as a normal query and doesn't report it with error. Any ideas?

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  • SQL SERVER – Using RAND() in User Defined Functions (UDF)

    - by pinaldave
    Here is the question I received in email. “Pinal, I am writing a function where we need to generate random password. While writing T-SQL I faced following issue. Everytime I tried to use RAND() function in my User Defined Function I am getting following error: Msg 443, Level 16, State 1, Procedure RandFn, Line 7 Invalid use of a side-effecting operator ‘rand’ within a function. Here is the simplified T-SQL code of the function which I am using: CREATE FUNCTION RandFn() RETURNS INT AS BEGIN DECLARE @rndValue INT SET @rndValue = RAND() RETURN @rndValue END GO I must use UDF so is there any workaround to use RAND function in UDF.” Here is the workaround how RAND() can be used in UDF. The scope of the blog post is not to discuss the advantages or disadvantages of the function or random function here but just to show how RAND() function can be used in UDF. RAND() function is directly not allowed to use in the UDF so we have to find alternate way to use the same function. This can be achieved by creating a VIEW which is using RAND() function and use the same VIEW in the UDF. Here is the step by step instructions. Create a VIEW using RAND function. CREATE VIEW rndView AS SELECT RAND() rndResult GO Create a UDF using the same VIEW. CREATE FUNCTION RandFn() RETURNS DECIMAL(18,18) AS BEGIN DECLARE @rndValue DECIMAL(18,18) SELECT @rndValue = rndResult FROM rndView RETURN @rndValue END GO Now execute the UDF and it will just work fine and return random result. SELECT dbo.RandFn() GO In T-SQL world, I have noticed that there are more than one solution to every problem. Is there any better solution to this question? Please post that question as a comment and I will include it with due credit. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Function, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology Tagged: technology

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  • Font oddity - is this a bug?

    - by avenas8808
    I have Windows 7 Ultimate Home Edition, installed some new fonts recently (I do graphic design etc.) and have noticed some of them don't display in Windows/Fonts via the control panel, Appearance and Personalization. And when they do occur they always have FONTNAME_0.ttf (is this always common for TTF files?). I have 1306 fonts according to FontFrenzy but it doesn't show all of them via the Appearance and Personalization control panel. Also, in C:\Windows\Fonts, the fonts only show as the file name, e.g. arial.ttf (but for some odd reason arial_0.ttf appears, same for other fonts). Why is this, and anyone else had this problem before!

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  • SQL SERVER – Fix Visual Studio Error : Connections to SQL Server files (.mdf) require SQL Server Express 2005 to function properly. Please verify the installation of the component or download from the URL

    - by pinaldave
    In one of the virtual environment while I was trying to add SQL Server Database (.mdf) file to asp.net project I encountered following error: Connections to SQL Server files (.mdf) require SQL Server Express 2005 to function properly. Please verify the installation of the component or download from the URL:  For a long time I am using SQL Server 2012 but this error was a bit interesting to me. I realize that there should not be any need of the SQL Server 2005 installation. I quickly figured out that I can remove this error if I do as mentioned below: Open Microsoft Visual Studio Select Tools >> Options >> Database Tools >> Data Connections Enter the name of an installed instance in “SQL Server Instance Name” field. Click OK If you do not know the instance name, you can follow either of the options. 1) Use the command line sqlcmd utility 2) Using SQL Server Management Studio Is there any other way to resolve this error? Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Error Messages, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology Tagged: sqlcmd, Visual Studio

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  • SQL SERVER – FIX ERROR – Cannot connect to . Login failed. The login is from an untrusted domain and cannot be used with Windows authentication. (Microsoft SQL Server, Error: 18452)

    - by pinaldave
    Just a day ago, I was doing small attempting to connect to my local SQL Server using IP 127.0.0.1. The IP is of my local machine and SQL Server is installed on the local box as well. However, whenever I try to connect to the server it gave me following strange error. Cannot connect to 127.0.0.1. Login failed. The login is from an untrusted domain and cannot be used with Windows authentication. (Microsoft SQL Server, Error: 18452) The reason was indeed strange as I was trying to connect from local box to local box and it said my login was from an untrusted domain. As my system is not part of any domain, this was really confusing to me. Another thing was that I have been always able to connect always using 127.0.0.1 to SQL Server and this was a bit strange to me. I started to think what did I change since it  last time I connected to SQL Server. Suddenly I remembered that I had modified my computer’s host file for some other purpose. Solution: I opened my host file and immediately added entry like 127.0.0.1 localhost. Once I added it I was able to reconnect to SQL Server as usual. The location of the host file is C:\Windows\System32\drivers\etc. You will find file with the name hosts in it, make sure to open it with notepad. If you are part of a domain and your organization is using active directory, make sure that your account is added properly to active directory as well have proper security permissions to execute the task. Reference : Pinal Dave (http://blog.SQLAuthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Error Messages, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Linux: Apple Wireless A1314 Fn key not registered, looks like software bug

    - by ramplank
    I'm trying to set up my Apple Wireless Keyboard with my Kubuntu systems. These are PC hardware powered by Intel Atom and Intel i5 respectively. The keyboard has a US keyboard layout and has model number A1314 written on the back. It takes two AA batteries. I'm saying that because it appears there are multiple types of model A1314. I have tried this on a 10.04, 11.04, 11.10 and 12.04 system with no success. Every time using a bluetooth dongle and the KDE bluetooth notification tray applet, the keyboard can be connected. In both cases it shows up as "Apple Wireless Keyboard". Almost everything works as expected, in fact, I'm typing on it right now. But one thing doesn't: The Fn key. I'd like to use Fn + Down Arrow as PgDn / Page Down, I understand this is default behaviour on Apple keyboards. And of course I'd like the same for Page Up, Home and End. I'll stick to Page Down in my example. I used the xev tool to see the keycodes the system receives, and if I press on Fn nothing happens, and nothing is registered. If I press Fn + Down Arrow, xev only registers the down arrow. Here's the output from my 11.04 system to illustrate: Press just the Fn key: no output Press Down Arrow key: KeyPress event, serial 36, synthetic NO, window 0x4400001, root 0x15d, subw 0x4400002, time 2699773, (44,45), root:(1352,298), state 0x10, keycode 116 (keysym 0xff54, Down), same_screen YES, XLookupString gives 0 bytes: XmbLookupString gives 0 bytes: XFilterEvent returns: False KeyRelease event, serial 36, synthetic NO, window 0x4400001, root 0x15d, subw 0x4400002, time 2699860, (44,45), root:(1352,298), state 0x10, keycode 116 (keysym 0xff54, Down), same_screen YES, XLookupString gives 0 bytes: XFilterEvent returns: False Press Fn+Down Arrow Keys together: KeyPress event, serial 36, synthetic NO, window 0x4400001, root 0x15d, subw 0x4400002, time 2701548, (44,45), root:(1352,298), state 0x10, keycode 116 (keysym 0xff54, Down), same_screen YES, XLookupString gives 0 bytes: XmbLookupString gives 0 bytes: XFilterEvent returns: False KeyRelease event, serial 36, synthetic NO, window 0x4400001, root 0x15d, subw 0x4400002, time 2701623, (44,45), root:(1352,298), state 0x10, keycode 116 (keysym 0xff54, Down), same_screen YES, XLookupString gives 0 bytes: XFilterEvent returns: False I've been searching this forum and other Linux-related forums for hours but I still have not found a solution. I mostly found advice on how to fix this when using an actual apple laptop or desktop, but I don't have that. They said to try something like the following echo 2 > /sys/module/hid_apple/ ... But since there's no hid_apple directory present on my systems, I've needed to modprobe hid_apple first. That didn't help either. I'm cool with changing some config files, or compiling my own patched kernel if that's necessary. I currently have a 10.04 and 12.04 system available to test. The same issue occurs when hooked up to Windows 7. Fn key still does nothing, not by itself or in combination with other keys. With some AutoHotkey fiddling, I was able to confirm the key is registered as pressed, but ignored by default. A custom AutoHotkey script can fix that. But AutoHotkey is only for Windows, I want my problem fixed on Linux. Hooked up to an iPad 2 it only works in combination with the F1-F12 keys. Not with the arrow keys. If the screen of the ipad is off, and I press just the Fn key, the screen will come on, so the key itself is registered as pressed. So to sum up my question: Can anyone help me get Page Up, Page Down, Home and End to work on this keyboard, when that requires me to use an Fn key which is currently not registered?

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  • Password manager bug with Firefox 3.6.13

    - by Nicolas Buduroi
    I'm having trouble with the latest Firefox (3.6.13) password manager. For a website I'm working on, it doesn't fill the password field for any login credential saved. I've looked into the options "Saved passwords" list and they are all there with the correct passwords. I thought at first that the website was blocking this feature in some way, but the password managers in Chrome (on the same Windows 7 machine) and Iceweasel (in a virtual Debian 6 machine) work well. Any idea about what could cause this problem?

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  • Firefox - bizarre bug

    - by pulancheck1988
    So... this happens to my Firefox browser in like 5 days after I install it. After I reinstall it behaves normal. It doesn't display all sites like this. Same site on Explorer looks as expected. Restarting the browser doesn't seem to help. I do have installed 2 plugins or add-ons (Adblock & VideoHelper) but I'm almost sure this doesn't explain it. and I didn't messed with the settings. So... anyone?

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  • Nginx: bug using if in location, how do I rectify

    - by Quintin Par
    I am using nginx in reverse proxy mode. In my server section I have this code to set expire and cache control of my static files. location ~* ^.+\.(css|js|png|gif)$ { access_log off; expires max; add_header Cache-Control public; if (!-f $request_filename) { proxy_pass http://localhost:82; } } This is quite obviously creating issues. Can someone help me correct this code to use try_files or rewrite?

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  • Bind9 not doing anything with forwarded query responses?

    - by Rykaro
    I have a Bind DNS server that is the local production DNS server and a Windows 2008 R2 domain controller which provides DNS for a lab environment with the domain xyz.lab. I've configured the Bind DNS to forward DNS requests for the domain xyz.lab to the Windows DNS server with this config: zone "xyz.lab" { type forward; forward only; forwarders { x.x.x.x; }; }; zone "x.x.x.in-addr.arpa" { type forward; forward only; forwarders { x.x.x.x; }; }; And Bind options are (the all_internal acl includes the subnets of both the production and lab networks as well as the loopback of the bind server): allow-query { all_internal; }; allow-recursion { all_internal; }; allow-transfer { none; }; notify no; minimal-responses yes; version "unknown"; Unfortunately, when I do an nslookup or dig on the bind server for a host on the lab domain, the request times out. The logs on the Windows 2008 DNS server show it receiving the query and responding to it and a network packet trace shows the query responses arriving at the Bind DNS server. The servers reside on the same switch with a router providing connectivity between the layer 3 subnets (production and lab are on different subnets) and there is a round trip time of between 3ms and 5ms on pings between the two servers, so I don't think there is an issue with latency causing a timeout of the query. In summary a query-response arrives back at the Bind server and the nslookup/dig times-out. Why does the Bind DNS not seem to be doing anything with the query responses when it receives them?

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  • How to give default values for the sum, count if no data exist in mysql query which uses group by?

    - by Salil
    I am using following query which works fine for me except one problem SELECT f.period as month, sum(p.revenue * ((100-q.rate)/100)) as revenue ,count(distinct q.label) as tot_stmt FROM files f, reports p, rates q,albums a where f.period in ('2010-06-01','2010-05-01','2010-04-01','2010-03-01') and f.period_closed = true and q.period = f.period and a.id = q.album_id and p.file_id = f.id and p.upc = a.upc and p.revenue is not null GROUP BY month ORDER BY month DESC O/P = month            revenue     tot_stmt 2010-06-01     10.00         2 2010-05-01     340.47       2 I want result like following month            revenue     tot_stmt 2010-06-01     10.00         2 2010-05-01     340.47       2 2010-04-01     0.00           0 2010-03-01     0.00           0 Regards, Salil Gaikwad

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  • There is insufficient system memory to run this query when creating temporary table

    - by phenevo
    StringBuilder query = new StringBuilder(); query.Append("CREATE TABLE #Codes (Code nvarchar(100) collate database_default ) "); query.Append("Insert into #Codes (Code) "); int lengthOfCodesArray = targetCodes.Length; for (int index = 0; index < lengthOfCodesArray; index++) { string targetCode = targetCodes[index]; query.Append("Select N'" + targetCode + "' "); if (index != lengthOfCodesArray - 1) { query.Append("Union All "); } } query.Append("drop table #Codes "); on: cmd.ExecuteReader() I get There is insufficient system memory to run this query when creating temporary table But weird thing is that, when I have 25k codes is ok, when 5k I get this error. Initial size is 262 MB. Lengt of each code is average 15.

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  • Strange UIKit bug, table view row stays selected

    - by Can Berk Güder
    I'm facing what appears to be a UIKit bug, and it takes the combination of two less commonly used features to reproduce it, so please bear with me here. I have quite the common view hierarchy: UITabBarController -> UINavigationController -> UITableViewController and the table view controller pushes another table view controller onto the navigation controller's stack when a row is selected. There's absolutely nothing special or fancy in the code here. However, the second UITableViewController, the "detail view controller" if you will, does two things: It sets hidesBottomBarWhenPushed to YES in its init method, so the tab bar is hidden when this controller is pushed: - (id)initWithStyle:(UITableViewStyle)style { if(self = [super initWithStyle:style]) { self.hidesBottomBarWhenPushed = YES; } return self; } It calls setToolbarHidden:NO animated:YES and setToolbarHidden:YES animated:YES on self.navigationController in viewWillAppear: and viewWillDisappear: respectively, causing the UIToolbar provided by UINavigationController to be displayed and hidden with animations: - (void)viewWillAppear:(BOOL)animated { [super viewWillAppear:animated]; [self.navigationController setToolbarHidden:NO animated:YES]; } - (void)viewWillDisappear:(BOOL)animated { [super viewWillDisappear:animated]; [self.navigationController setToolbarHidden:YES animated:YES]; } Now, if the second UITableViewController was pushed by selecting the row at the bottom of the screen (it doesn't have to be the last row) in the first controller, this row does not automatically get deselected when the user immediately or eventually returns to the first controller. Further, the row cannot be deselected by calling deselectRowAtIndexPath:animated: on self.tableView in viewWillAppear: or viewDidAppear: in the first controller. I'm guessing this is a bug in UITableViewController's drawing code which of course only draws visible rows, but unfortunately fails to determine correctly if the bottommost row will be visible in this case. I failed to find anything on this on Google or OpenRadar, and was wondering if anyone else on SO had this problem or knew a solution/workaround.

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  • Workaround for GNU Make 3.80 eval bug

    - by bengineerd
    I'm trying to create a generic build template for my Makefiles, kind of like they discuss in the eval documentation. I've run into a known bug with GNU Make 3.80. When $(eval) evaluates a line that is over 193 characters, Make crashes with a "Virtual Memory Exhausted" error. The code I have that causes the issue looks like this. SRC_DIR = ./src/ PROG_NAME = test define PROGRAM_template $(1)_SRC_DIR = $$(SRC_DIR)$(1)/ $(1)_SRC_FILES = $$(wildcard $$($(1)_SRC_DIR)*.c) $(1)_OBJ_FILES = $$($(1)_SRC_FILES):.c=.o) $$($(1)_OBJ_FILES) : $$($(1)_SRC_FILES) # This is the problem line endef $(eval $(call PROGRAM_template,$(PROG_NAME))) When I run this Makefile, I get gmake: *** virtual memory exhausted. Stop. The expected output is that all .c files in ./src/test/ get compiled into .o files (via an implicit rule). The problem is that $$($(1)_SRC_FILES) and $$($(1)_OBJ_FILES) are together over 193 characters long (if there are enough source files). I have tried running the make file on a directory where there is only 2 .c files, and it works fine. It's only when there are many .c files in the SRC directory that I get the error. I know that GNU Make 3.81 fixes this bug. Unfortunately I do not have the authority or ability to install the newer version on the system I'm working on. I'm stuck with 3.80. So, is there some workaround? Maybe split $$($(1)_SRC_FILES) up and declare each dependency individually within the eval?

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  • asp.net updatepanel inside hidden panel possible bug

    - by MakkyNZ
    Hi The javascript generated by the asp.net SciptManager control seems to have a bug and cant handle hidden UpdatePanels. A javascript error is thrown when a control within one updated panel tries to make another update panel visible. Is this a bug with ASP.Net ajax? And does anyone have any ideas how to get around this? heres is an example of when im trying to to <script type="text/C#" runat="server"> protected void LinkButton1_Click(object sender, EventArgs e) { Panel1.Visible = true; } </script> <asp:ScriptManager ID="ScriptManager1" runat="server"> </asp:ScriptManager> <asp:UpdatePanel ID="UpdatePanel1" runat="server"> <ContentTemplate> <asp:LinkButton ID="LinkButton1" runat="server" OnClick="LinkButton1_Click" Text="Show Panel"></asp:LinkButton> </ContentTemplate> </asp:UpdatePanel> <asp:Panel ID="Panel1" runat="server" Visible="false"> <asp:UpdatePanel ID="UpdatePanel2" runat="server"> <ContentTemplate> blah bla blah </ContentTemplate> </asp:UpdatePanel> </asp:Panel> this is the javascript error that gets thrown when clicking on the "LinkButton1" link. This error comes from the javascript that is generated by the asp.net ScriptManager control Error: Sys.InvalidOperationException: Could not find UpdatePanel with ID 'ctl00_ContentPlaceHolder1_UpdatePanel2'

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  • Possible bug in ASP.net UpdatePanel control?

    - by Ben Robinson
    I have come across what seems to be an annoying bug with asp.net UpdatePanels in 2 seperate projects. If you have some kind of autopostback enabled control that can cause all of the controls in the update panel to have visible=false set, resulting in an empty update panel. When you change the autopostback control back to the postion that would re enable all of the controls in the update panel, it simply does not make a call back to the server and the update panel does not update. If you do anything else that makes a call back on the same page, then the update panel contents magically appear. It is as if asp.net has decided the update panel is empty so there is no point maikng a callback, even though making the call back would fill the updatepanel with content. The only way round this is to add a style of display:none to the controls instead of setting visible=false property. Then it works fine. Has anyone else encountered this problem? Is it a bug as i suspect or is it likely i am doing soemthing wrong? I haven't got time to post example code at the moment as the code i am using is too wrapped up in other unrealted things, if people think it would help i will create a simple example and post it when I get time.

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  • SQL - query inside NOT IN takes longer than the complete query ??

    - by Aleksandar Tomic
    Hi every1, I'm using NOT IN inside my SQL query. For example: select columnA from table1 where columnA not in ( select columnB from table2) How is it possible that this part of the query select columnB from table2 takes 30sec to complete, but the whole query above takes 0.1sec to complete?? Shouldn't the complete query take 30sec + ? BTW, both queries return valid results. Thanks! Answers to Comments Is it because the second query hasn't actually completed but has only returned back the first 'x' rows (out of a very large table?) No, the query is completed after 30 seconds, not to many rows returned (eg. 50). But @Aleksandar wondered why the question congaing the performance killer was so fast. my point exactly Also how long does select distinct columnB from table2 take to execute? actually, the original query is "select distinct...

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  • Weird bug with C++ lambda expressions in VS2010

    - by Andrei Tita
    In a couple of my projects, the following code: class SmallClass { public: int x1, y1; void TestFunc() { auto BadLambda = [&]() { int g = x1 + 1; //ok int h = y1 + 1; //c2296 int l = static_cast<int>(y1); //c2440 }; int y1_copy = y1; //it works if you create a local copy auto GoodLambda = [&]() { int h = y1_copy + 1; //ok int l = this->y1 + 1; //ok }; } }; generates error C2296: '+' : illegal, left operand has type 'double (__cdecl *)(double)' or alternatively error C2440: 'static_cast' : cannot convert from 'double (__cdecl *)(double)' to 'int' You get the picture. It also happens if catching by value. The error seems to be tied to the member name "y1". It happened in different classes, different projects and with (seemingly) any type for y1; for example, this code: [...] MyClass y1; void TestFunc() { auto BadLambda = [&]()->void { int l = static_cast<int>(y1); //c2440 }; } generates both these errors: error C2440: 'static_cast' : cannot convert from 'MyClass' to 'int' No user-defined-conversion operator available that can perform this conversion, or the operator cannot be called error C2440: 'static_cast' : cannot convert from 'double (__cdecl *)(double)' to 'int' There is no context in which this conversion is possible It didn't, however, happen in a completely new project. I thought maybe it was related to Lua (the projects where I managed to reproduce this bug both used Lua), but I did not manage to reproduce it in a new project linking Lua. It doesn't seem to be a known bug, and I'm at a loss. Any ideas as to why this happens? (I don't need a workaround; there are a few in the code already). Using Visual Studio 2010 Express version 10.0.40219.1 Sp1Rel.

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  • CakePHP 1.26: Bug in 'Security' component?

    - by Steve
    Okay, for those of you who may have read this earlier, I've done a little research and completely revamped my question. I've been having a problem where my form requests get blackholed by the Security component, although everything works fine when the Security component is disabled. I've traced it down to a single line in a form: <?php echo $form->create('Audition');?> <fieldset> <legend><?php __('Edit Audition');?></legend> <?php echo $form->input('ensemble'); echo $form->input('position'); echo $form->input('aud_date'); // The following line works fine... echo $form->input('owner'); // ...but the following line blackholes when Security included // and the form is submitted: // echo $form->input('owner', array('disabled'=>'disabled'); ?> </fieldset> <?php echo $form->end('Submit');?> (I've commented out the offending line for clarity) I think I'm following the rules by using the form helper; as far as I can tell, this is a bug in the Security component, but I'm too much of a CakePHP n00b to know for sure. I'd love to get some feedback, and if it's a real bug, I'll submit it to the CakePHP team. I'd also love to know if I'm just being dumb and missing something obvious here.

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  • jQuery Accordion + Anchor Tag 'stuck as block' bug?

    - by DA
    Sample page: http://jsbin.com/ohuze/2 This is a simple jQuery UI Accordion. Each accordion panel has an UL (an OL works the same) with this markup: <ol> <li><a href="">Lorep ipsum dolor lorem ipsum dolor lorem ipsum dolor</a>?</li> <li><a href="">Lorep ipsum dolor lorem ipsum dolor lorem ipsum dolor</a>?</li> </ol> In IE6, you'll see that the <a> tag appears to be getting rendered as a block element, so the question mark ends up being pushed outside and not at the end of the line of text. In addition, the bullet and/or list item number is now bottom-aligned with the text rather than top-aligned. I've narrowed it down to the javascript that executes to make the accordion. It's not an issue with jQuery's CSS as disabling that, alone, doesn't resolve the issue. Anyone know what might be going on in IE6 to cause this rendering issue? UPDATE: Apparently, this is also an IE7 issue. UPDATE 2: After some more playing, I've narrowed things down a bit more: the bug has nothing to do with lists. The issue is any anchor tag within a jQuery Accordion will appear as display: block (even though it appears that the CSS still indicates display: inline) the bug has nothing to do with the actual CSS that jQuery UI uses to create the accordion. I created a test page that uses the fully rendered jQuery Accordion post-processed source code and the accompanying CSS. In that situation, the anchor tags remain inline. In conclusion: It appears that the process of rendering the accordion via javascript is messing up the display of the anchor tags. It may be a show/hide issue?

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  • Bizarre Bug with our Rails app in IE

    - by Callmeed
    We're experiencing a really bizarre bug in our Rails 2.3.4 app. This bug only happens in Internet Explorer (7 and 8). Here's what happens: A new customer creates an account at https://domain.com/signup/free (notice no subdomain) Their account is identified by a subdomain like "example.domain.com" After signing up, they get a welcome screen with a link to their account's home page They follow the link, then click the "log in" button and attempt to login Even though they provide valid credentials, the app redirects back to their account's root url ... they can never reach their admin area The only way they can login (on IE) is by quitting and re-opening IE ... then it works fine ... Something with their initial session is preventing them from logging in. If it matters, we are using restful_authentication and the ssl_requirement plugin ... I'm not sure if one or both of those has a problem with IE but we are stumped here. Also, I've read IE has an issue with subdomains that contain underscores ... this isn't what's going on.

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  • CodeIgniter pagination with this->db->query

    - by cyberfly
    Hi all, How to use the codeigniter with $this-db-query() method? If i use active record class i would do like this: $query = $this->db->get('tb_cash_transaction',$num,$offset); $this->db->order_by("CURRENCY_ID", "asc"); Now i am using the $this-db-query() $query = "SELECT * FROM tb_cash_transaction, tb_currency, tb_user where tb_cash_transaction.CURRENCY_ID=tb_currency.CURRENCY_ID and tb_cash_transaction.USER_ID=tb_user.USER_ID and TYPE='cash_out'"; $query = $this->db->query($query); How to implement it? Thank you.

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