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  • Firefox handles xxx.submit(), Safari doesn't ... what can be done?

    - by Prairiedogg
    I'm trying to make a pull down menu post a form when the user selects (releases the mouse) on one of the options from the menu. This code works fine in FF but Safari, for some reason, doesn't submit the form. I re-wrote the code using jquery to see if jquery's .submit() implementation handled the browser quirks better. Same result, works in FF doesn't work in safari. The following snippets are from the same page, which has some django template language mixed in. Here's the vanilla js attempt: function formSubmit(lang) { if (lang != '{{ LANGUAGE_CODE }}') { document.getElementById("setlang_form").submit(); } } Here's the jquery attempt: $(document).ready(function() { $('#lang_submit').hide() $('#setlang_form option').mouseup(function () { if ($(this).attr('value') != '{{ LANGUAGE_CODE }}') { $('#setlang_form').submit() } }); }); and here's the form: <form id="setlang_form" method="post" action="{% url django.views.i18n.set_language %}"> <fieldset> <select name="language"> {% for lang in interface_languages %} <option value="{{ lang.code }}" onmouseup="formSubmit('{{ lang.name }}')" {% ifequal lang.code LANGUAGE_CODE %}selected="selected"{% endifequal %}>{{ lang.name }}</option> {% endfor %} </select> </fieldset> </form> My question is, how can I get this working in Safari?

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  • The ethics of aggregating other peoples' content

    - by AaronBertrand
    Content theft Most of the recent - what I'll call - "discussions" about content aggregators have revolved around content theft. I'm not going to flip-flop on that topic: when you use someone else's work, you ask first, and if given the okay, you cite it. You can't take my blog article and post it on your site, implying that it is your own. Likewise, you shouldn't be taking a Books Online topic, changing three words and adding an intro sentence, and making that a blog post. I think this stuff is pretty...(read more)

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  • jqGrid: sort by index

    - by David__
    I am having trouble getting a column to sort by an index other than the 'name' value. In this case I am trying to sort the aggregation type column (values are days of the week) by the week order, rather than alphanumeric order. To do this I added an index column ('Aggregation type-index') that has the days of week an integers. However with this configuration, it fails to sort that column by index or name. Can someone point me the err in my ways? I posted all the js and css that is on the page, because I am also having two other issues, that if you notice the problem great, otherwise I'll keep hunting. I want to be able to enable the column reodering and be able to resize the grid (Both shown at http://trirand.com/blog/jqgrid/jqgrid.html under the new in 3.6 tab). Both options are not working either. <link rel="stylesheet" type="text/css" href="/static/latest_ui/themes/base/jquery.ui.all.css"/> <link rel="stylesheet" type="text/css" media="print" href="/static/css/print.css"/> <script src="/static/js/jquery-1.7.2.min.js" type="text/javascript"></script> <script src="/static/latest_ui/ui/jquery.ui.core.js"></script> <script src="/static/latest_ui/ui/jquery.ui.widget.js"></script> <script src="/static/latest_ui/ui/jquery.ui.position.js"></script> <script src="/static/latest_ui/ui/jquery.ui.button.js"></script> <script src="/static/latest_ui/ui/jquery.ui.menu.js"></script> <script src="/static/latest_ui/ui/jquery.ui.menubar.js"></script> <script src="/static/latest_ui/ui/jquery.ui.tabs.js"></script> <script src="/static/latest_ui/ui/jquery.ui.datepicker.js"></script> <script src="/static/js/custom.js"></script> <link rel="stylesheet" type="text/css" media="all" href="/static/css/custom_style.css" /> <link rel="stylesheet" type="text/css" media="all" href="/static/css/custom_colors.css" /> <link rel="stylesheet" type="text/css" media="screen" href="/static/css/ui.jqgrid.css" /> <body> <table id="grid_reports"></table> <div id='pager'></div> </body> <script src="/static/latest_ui/ui/jquery.ui.resizable.js"></script> <script src="/static/latest_ui/ui/jquery.ui.sortable.js"></script> <script src="/static/js/grid.locale-en.js" type="text/javascript"></script> <script src="/static/js/jquery.jqGrid.min.js" type="text/javascript"></script> <script src="/static/js/jqGrid_src/grid.jqueryui.js"></script> <script> $(function() { jQuery("#grid_reports").jqGrid({ sortable: true, datatype: "local", height: 500, width: 300, colNames:['Series', 'Agg Type', 'Days'], colModel:[{'index': 'By series', 'align': 'left', 'sorttype': 'text', 'name': 'By series', 'width': 65}, {'index': 'Aggregation type-index', 'align': 'left', 'sorttype': 'int', 'name': 'Aggregation type', 'width': 75}, {'index': 'Days since event', 'align': 'center', 'sorttype': 'text', 'name': 'Days since event', 'width': 50}], rowNum:50, pager: '#pager', sortname: 'Aggregation type', sortorder: 'desc', altRows: true, rowList:[20,50,100,500,10000], viewrecords: true, gridview: true, caption: "Report for 6/19/12" }); jQuery("#grid_reports").navGrid("#pager",{edit:false,add:false,del:false}); jQuery("#grid_reports").jqGrid('gridResize',{minWidth:60,maxWidth:2500,minHeight:80, maxHeight:2500}); var mydata = [{'Days since event': 132, 'Aggregation type': 'Date=Fri', 'By series': 'mean', 'Aggregation type-index': 5}, {'DIM at event': 178, 'Aggregation type': 'Date=Thu', 'By series': 'mean', 'Aggregation type-index': 4}, {'DIM at event': 172, 'Aggregation type': 'Date=Wed', 'By series': 'mean', 'Aggregation type-index': 3}, {'DIM at event': 146, 'Aggregation type': 'Date=Tue', 'By series': 'mean', 'Aggregation type-index': 2}, {'DIM at event': 132, 'Aggregation type': 'Date=Sat', 'By series': 'mean', 'Aggregation type-index': 6}, {'DIM at event': 162, 'Aggregation type': 'Date=Mon', 'By series': 'mean', 'Aggregation type-index': 1}, {'DIM at event': 139, 'Aggregation type': 'Date=Sun', 'By series': 'mean', 'Aggregation type-index': 0}]; for(var i=0;i<=mydata.length;i++) jQuery("#grid_reports").jqGrid('addRowData',i+1,mydata[i]); }); </script>

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  • what kind of relationship is there between a common wall and the rooms that located next to it?

    - by siamak
    I want to know whats the Relationship between a common wall (that are located In an adjoining room ) and the rooms. As i know the relationship between a room and its walls is Composition not Aggregation (am i right ?) And according to the definition of Composition the contained object can't be shared between two containers, whereas in aggregation it is possible. now i am confused that whats the best modeling approach to represent the relationship between a common wall and the rooms located next to it ? It would be highly Appreciated if you could provide your advices with some code. |--------|--------| Approch1: (wall class ---- room class) /Composition Approach2: wall class ----- room class /Aggregation Approch3: we have a wall class and a Common wall class , Common wall class inherits from wall class adjoining room class ---- (1) Common wall class /Aggregation adjoining room class ---- (6) wall class / composition Approach4: I am a developer not a designer :) so this is my idea : class Room { private wall _firstwall ; private wall _secondtwall; private wall _thirdwall ; private wall _commonwall ; public Room( CommonWall commonwall) { _firstwall=new Wall(); _secondtwall=new Wall(); _thirdwall=new Wall(); _commonwall=commonwall; } } Class CommonWall:Wall { //... } // in somewher : static void main() { Wall _commonWall=new Wall(); Room room1=new Room(_commonWall); Room room2=new Room(_commonWall); Room [] adjacentRoom =new Room[2]{room1,room2}; } Edit 1: I think this is a clear question but just for more clarification : The point of the question is to find out whats the best pattern or approach to model a relationship for an object that is a component of two other objects in the same time. and about my example : waht i mean by a "room" ?,surely i mean an enclosed square room with 4 walls and one door.but in this case one of these walls is a common wall and is shared between two adjacent rooms.

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  • Postgresql Data Aggregation over WAN Securely

    - by Zach
    Hey guys, Need some advice on how to proceed with this situation: My current scenario is that I have several postgresql (50+) boxes deployed throughout various locations and data centers and a beefy postgresql box setup at a homebase location. All of the deployed boxes have identical database layouts. I'm looking for a solution that would allow for a few things. I realize some of these options overlap and some might only contain mutually exclusive solutions. However, I'm interested to hear your thoughts :) Remotely query the deployed boxes and pull the results back to the homebase box for processing. Nightly (remote) "sync" or dump the deployed boxes' databases to a master database on the homebase box. Remotely push a table entry to all of the deployed boxes from the homebase box. Ensure security of data in transit, and remotely deployed boxes. Up to this point I've been floating on a homebrew multithreaded python/perl system that SSH's into these boxes remotely, which are ACL'ed off to the homebase server and pulls (or pushes) the raw query results over the ssh connection. I have even touched #2 (remote syncing) as I know that would get nasty really quick. I'm interested in any ideas for a more elegant solution that can scale up and stick to my FreeBSD/Linux environment.

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  • Generic relations missing with grappelli

    - by diegueus9
    I'm using the last svn revision of grappelli and rev 11840 of django (before multidatabases and stuff), and i'm trying to use generic relations in the admin, but doesn't work, The model: class AutorProyectoLey(DatedModel): tipo_autor = models.ForeignKey(ContentType) autor_id = models.PositiveIntegerField() content_object = generic.GenericForeignKey('tipo_autor', 'autor_id') proyecto_ley = models.ForeignKey(ProyectoLey) The admin: class AutorInline(GenericInlineModelAdmin): model = AutorProyectoLey allow_add = True ct_field = 'tipo_autor' ct_fk_field = 'autor_id' classes = ('collapse-open',) And i put this model of var inlines in another adminmodel, but the html render is : <!-- Inlines --> <!-- Submit-Row -->

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  • 2 fields unique

    - by xRobot
    I have this model: class blog(models.Model): user = models.ForeignKey(User) mail = models.EmailField(max_length=60, null=False, blank=False) name = models.CharField(max_length=60, blank=True, null=True) I want that (user,email) are unique togheter. For example: This is allowed: 1, [email protected], myblog 2, [email protected], secondblog This is NOT allowed: 1, [email protected], myblog 1, [email protected], secondblog Is this possible in Django ?

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  • why save_model method doesn't work in admin.StackedInline?

    - by FurtiveFelon
    Hi all, I have a similar problem as a previously solved problem of mine, except this time solution doesn't seem to work: http://stackoverflow.com/questions/2991365/how-to-auto-insert-the-current-user-when-creating-an-object-in-django-admin Previously i used to override the save_model to stamp the user submitting the article. Now i need to do the same for comments, it doesn't seem to work anymore. Anyone have any ideas? Thanks a lot! Jason

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  • How to use the same template for different query sets?

    - by knuckfubuck
    I'm new to Django and setting up my first site. I have a Share model and a template called share_list.html that uses an object_list like this: {% for object in object_list %} I setup haystack using their tutorial and the search template looks like this: {% for result in page.object_list %} I would like to modify the search.html template to have an include of the share_list so I don't have to repeat myself. How can I make it use the same object_list?

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  • regular expression with special chars

    - by xRobot
    I need a regular expression to validate string with one or more of these characters: a-z A-Z ' àòèéùì simple white space FOR EXAMPLE these string are valide: D' argon calabrò maryòn l' Ancol these string are NOT valide: hello38239 my_house work [tab] with me I tryed this: re.match(r"^[a-zA-Z 'òàèéìù]+$", self.cleaned_data['title'].strip()) It seems to work in my python shell but in Django I get this error: SyntaxError at /home/ ("Non-ASCII character '\\xc3' ... Why ?

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  • apache solr auto suggestions

    - by Pydev UA
    I use solr+django-haystack I set settings.HAYSTACK_INCLUDE_SPELLING = True and rebuild index I'm trying to get any suggestion using: SearchQuerySet().auto_query('tryng ani word her').spelling_suggestion() But I always get None What should I do to get at least one working suggestion ? may be I need add some configuration into solr config or have some specific data indexed ?

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  • Overriding initial value in ModelForm

    - by schneck
    Hi, in my Django (1.2) project, I want to prepopulate a field in a modelform, but my new value is ignored. This is the snippet: class ArtefactForm(ModelForm): material = CharField(widget=AutoCompleteWidget('material', force_selection=False)) def __init__(self, *args, **kwargs): super(ArtefactForm, self).__init__(*args, **kwargs) self.fields['material'].initial = 'Test' I also tried with self.base_fields, but no effect: there is always the database-value displaying in the form. Any ideas?

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  • PHP Frameworks (CodeIgnitor, Yii, CakePHP) vs. Django

    - by niting
    I have to develop a site which has to accomodate around 2000 users a day and speed is a criterion for it. Moreover, the site is a user oriented one where the user will be able to log in and check his profile, register for specific events he/she wants to participate in. The site is to be hosted on a VPS server.Although I have pretty good experience with python and PHP but I have no idea how to use either of the framework. We have plenty of time to experiment and learn one of the above frameworks.Could you please specify which one would be preferred for such a scenario considering speed, features, and security of the site. Thanks, niting

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  • List display names from django models

    - by Ed
    I have an object: POP_CULTURE_TYPES = ( ('SG','Song'), ('MV', 'Movie'), ('GM', 'Game'), ('TV', 'TV'), ) class Pop_Culture(models.Model): name = models.CharField(max_length=30, unique=True) type = models.CharField(max_length=2, choices = POP_CULTURE_TYPES, blank=True, null=True) Then I have a function: def choice_list(request, modelname, field_name): mdlnm = get.model('mdb', modelname.lower()) mdlnm = mdlnm.objects.values_list(field_name, flat=True).distinct().order_by(field_name) return render_to_response("choice_list.html", { 'model' : modelname, 'field' : field_name, 'field_list' : mdlnm }) This gives me a distinct list of all the "type" entries in the database in the "field_list" variable passed in render_to_response. But I don't want a list that shows: SG MV I want a list that shows: Song Movie I can do this on an individual object basis if I was in the template object.get_type_display But how do I get a list of all of the unique "type" entries in the database as their full names for output into a template? I hope this question was clearly described. . .

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  • Best way to re-use the same django models and admin for multiple apps

    - by kepioo
    Given a reference app ( called guide), how can I create additional apps that will reuse the same model/admin/views than guide - the motivation behind is to be able to individually control each subapp. guide guideApp1 exact same models/admin/views than guide guideApp2 exact same models/admin/views than guide in the Admin site, I should have : 1 section for guideApp1 with all the tables defined in guide, that applies to guideApp1 1 section for guideApp12 with all the tables defined in guide, that applies to guideApp2

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  • Validating ModelChoiceField in Django forms

    - by Andrey
    I'm trying to validate a form containing a ModelChoiceField: state = forms.ModelChoiceField(queryset=State.objects.all(), empty_label=None) When it is used in normal circumstances, everything goes just fine. But I'd like to protect the form from the invalid input. It's pretty obvious that I must get forms.ValidationError when I put invalid value in this field, isn't it? But if I try to submit a form with a value 'invalid' in 'state' field, I get ValueError: invalid literal for int() with base 10: 'invalid' and not the expected forms.ValidationError. What should I do? I tried to place a def clean_state(self) to check this field but that didn't work plus I don't think this is a good solution, there must be something more simple but I just missed that.

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  • Generate unique hashes for django models

    - by becomingGuru
    I want to use unique hashes for each model rather than ids. I implemented the following function to use it across the board easily. import random,hashlib from base64 import urlsafe_b64encode def set_unique_random_value(model_object,field_name='hash_uuid',length=5,use_sha=True,urlencode=False): while 1: uuid_number = str(random.random())[2:] uuid = hashlib.sha256(uuid_number).hexdigest() if use_sha else uuid_number uuid = uuid[:length] if urlencode: uuid = urlsafe_b64encode(uuid)[:-1] hash_id_dict = {field_name:uuid} try: model_object.__class__.objects.get(**hash_id_dict) except model_object.__class__.DoesNotExist: setattr(model_object,field_name,uuid) return I'm seeking feedback, how else could I do it? How can I improve it? What is good bad and ugly about it?

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  • GAE/Django Templates (0.96) filters to get LENGTH of GqlQuery and filter it

    - by Halst
    I pass the query with comments to my template: COMM = CommentModel.gql("ORDER BY created") doRender(self,CP.template,{'CP':CP,'COMM':COMM, 'authorize':authorize()}) And I want to output the number of comments as a result, and I try to do things like that: <a href="...">{{ COMM|length }} comments</a> Thats does not work (yeah, since COMM is GqlQuery, not a list). What can I do with that? Is there a way to convert GqlQuery to list or is there another solution? (first question) Second question is, how to filter this list in template? Is there a construct like this: <a href="...">{{ COMM|where(reference=smth)|length }} comments</a> so that I can get not only the number of all comments, but only comments with certain db.ReferenceProperty() property, for example. Last question: is it weird to do such things using templates?

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  • Python Django MySQLdb setup problem:: setup.py dosen't build due to incorrect location of mysql

    - by 108860375137931889948
    I'm trying to install MySQLdb for python. but when I run the setup, this is the error I get. well I know why its giving all the missing file statements, but dont know where to change the bold marked location from. Please help gaurav-toshniwals-macbook-7:MySQL-python-1.2.3c1 gauravtoshniwal$ python setup.py build running build running build_py copying MySQLdb/release.py - build/lib.macosx-10.3-fat-2.6/MySQLdb running build_ext building '_mysql' extension gcc-4.0 -arch ppc -arch i386 -isysroot /Developer/SDKs/MacOSX10.4u.sdk -fno-strict-aliasing -fno-common -dynamic -DNDEBUG -g -O3 -Dversion_info=(1,2,3,'gamma',1) -D_version_=1.2.3c1 -I/Applications/MAMP/Library/include/mysql -I/Library/Frameworks/Python.framework/Versions/2.6/include/python2.6 -c _mysql.c -o build/temp.macosx-10.3-fat-2.6/_mysql.o _mysql.c:36:23: error: my_config.h: No such file or directory _mysql.c:36:23: error: my_config.h: No such file or directory _mysql.c:38:19: error: mysql.h: No such file or directory _mysql.c:38:19:_mysql.c:39:26: error: mysqld_error.h: No such file or directory error: _mysql.c:40:20:mysql.h: No such file or directory

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  • How to manage Javascript modules in django templates?

    - by John Mee
    Lets say we want a library of javascript-based pieces of functionality (I'm thinking jquery): For example: an ajax dialog a date picker a form validator a sliding menu bar an accordian thingy There are four pieces of code for each: some Python, CSS, JS, & HTML. What is the best way to arrange all these pieces so that: each javascript 'module' can be neatly reused by different views the four bits of code that make up the completed function stay together the css/js/html parts appear in their correct places in the response common dependencies between modules are not repeated (eg: a javascript file in common) x-------------- It would be nice if, or is there some way to ensure that, when called from a templatetag, the templates respected the {% block %} directives. Thus one could create a single template with a block each for CSS, HTML, and JS, in a single file. Invoke that via a templatetag which is called from the template of whichever view wants it. That make any sense. Can that be done some way already? My templatetag templates seem to ignore the {% block %} directives. x-------------- There's some very relevant gasbagging about putting such media in forms here http://docs.djangoproject.com/en/dev/topics/forms/media/ which probably apply to the form validator and date picker examples.

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  • ContentType Issue -- Human is an idiot - Can't figure out how to tie the original model to a Content

    - by bmelton
    Originally started here: http://stackoverflow.com/questions/2650181/django-in-query-as-a-string-result-invalid-literal-for-int-with-base-10 I have a number of apps within my site, currently working with a simple "Blog" app. I have developed a 'Favorite' app, easily enough, that leverages the ContentType framework in Django to allow me to have a 'favorite' of any type... trying to go the other way, however, I don't know what I'm doing, and can't find any examples for. I'll start off with the favorite model: favorite/models.py from django.db import models from django.contrib.contenttypes.models import ContentType from django.contrib.contenttypes import generic from django.contrib.auth.models import User class Favorite(models.Model): content_type = models.ForeignKey(ContentType) object_id = models.PositiveIntegerField() user = models.ForeignKey(User) content_object = generic.GenericForeignKey() class Admin: list_display = ('key', 'id', 'user') class Meta: unique_together = ("content_type", "object_id", "user") Now, that allows me to loop through the favorites (on a user's "favorites" page, for example) and get the associated blog objects via {{ favorite.content_object.title }}. What I want now, and can't figure out, is what I need to do to the blog model to allow me to have some tether to the favorite (so when it is displayed in a list it can be highlighted, for example). Here is the blog model: blog/models.py from django.db import models from django.db.models import permalink from django.template.defaultfilters import slugify from category.models import Category from section.models import Section from favorite.models import Favorite from django.contrib.auth.models import User from django.contrib.contenttypes.models import ContentType from django.contrib.contenttypes import generic class Blog(models.Model): title = models.CharField(max_length=200, unique=True) slug = models.SlugField(max_length=140, editable=False) author = models.ForeignKey(User) homepage = models.URLField() feed = models.URLField() description = models.TextField() page_views = models.IntegerField(null=True, blank=True, default=0 ) created_on = models.DateTimeField(auto_now_add = True) updated_on = models.DateTimeField(auto_now = True) def __unicode__(self): return self.title @models.permalink def get_absolute_url(self): return ('blog.views.show', [str(self.slug)]) def save(self, *args, **kwargs): if not self.slug: slug = slugify(self.title) duplicate_count = Blog.objects.filter(slug__startswith = slug).count() if duplicate_count: slug = slug + str(duplicate_count) self.slug = slug super(Blog, self).save(*args, **kwargs) class Entry(models.Model): blog = models.ForeignKey('Blog') title = models.CharField(max_length=200) slug = models.SlugField(max_length=140, editable=False) description = models.TextField() url = models.URLField(unique=True) image = models.URLField(blank=True, null=True) created_on = models.DateTimeField(auto_now_add = True) def __unicode__(self): return self.title def save(self, *args, **kwargs): if not self.slug: slug = slugify(self.title) duplicate_count = Entry.objects.filter(slug__startswith = slug).count() if duplicate_count: slug = slug + str(duplicate_count) self.slug = slug super(Entry, self).save(*args, **kwargs) class Meta: verbose_name = "Entry" verbose_name_plural = "Entries" Any guidance?

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