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  • Why isn't the Cache invalidated after table update using the SqlCacheDependency?

    - by Jason
    I have been trying to get SqlCacheDependency working. I think I have everything set up correctly, but when I update the table, the item in the Cache isn't invalidated. Can you look at my code and see if I am missing anything? I enabled the Service Broker for the Sandbox database. I have placed the following code in the Global.asax file. I also restart IIS to make sure it is called. void Application_Start(object sender, EventArgs e) { SqlDependency.Start(ConfigurationManager.ConnectionStrings["SandboxConnectionString"].ConnectionString); } I have placed this entry in the web.config file: <system.web> <caching> <sqlCacheDependency enabled="true" pollTime="10000"> <databases> <add name="Sandbox" connectionStringName="SandboxConnectionString"/> </databases> </sqlCacheDependency> </caching> </system.web> I call this code to put the item into the cache: protected void CacheDataSetButton_Click(object sender, EventArgs e) { using (SqlConnection sqlConnection = new SqlConnection(ConfigurationManager.ConnectionStrings["SandboxConnectionString"].ConnectionString)) { using (SqlCommand sqlCommand = new SqlCommand("SELECT PetID, Name, Breed, Age, Sex, Fixed, Microchipped FROM dbo.Pets", sqlConnection)) { using (SqlDataAdapter sqlDataAdapter = new SqlDataAdapter(sqlCommand)) { DataSet petsDataSet = new DataSet(); sqlDataAdapter.Fill(petsDataSet, "Pets"); SqlCacheDependency petsSqlCacheDependency = new SqlCacheDependency(sqlCommand); Cache.Insert("Pets", petsDataSet, petsSqlCacheDependency, DateTime.Now.AddSeconds(10), Cache.NoSlidingExpiration); } } } } Then I bind the GridView with this code: protected void BindGridViewButton_Click(object sender, EventArgs e) { if (Cache["Pets"] != null) { GridView1.DataSource = Cache["Pets"] as DataSet; GridView1.DataBind(); } } Between attempts to DataBind the GridView, I change the table's values expecting it to invalidate the Cache["Pets"] item, but it seems to stay in the Cache indefinitely.

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  • Career day in kindergarten

    - by Péter Török
    I was invited to the kindergarten group of my elder daughter to talk and answer the kids' questions about my profession. There are 26 kids of age 4-6 in the group, plus 3 teachers who are fairly scared of anything related to programming and IT themselves, but bold enough to learn new tricks. I would have about 20-30 minutes, without projector or anything. They have an old computer though, which by its look may be a 486, and I am not even sure if it's functioning. My research turned up excellent earlier threads, with lots of good tips: How would you explain your job to a 5-year old? Career Day: how do I make “computer programmer” sound cool to 8 year olds? What things can I teach a group of children about programming in one day? My situation is different from each of the above though: the latter ones are concerned with older children, while the first one is about talking to a single kid (or elder person)—a group of 20 is a whole different challenge. How can I teach the kids and their teachers about programming in a fun way?

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  • Jquery cant get facebox working inside ajax call

    - by John
    From my main page I call an ajax file via jquery, in that ajax file is some additional jquery code. Original link looks like this: <a href="/page1.php" class="guest-action notify-function"><img src="/icon1.png"></a> Then the code: $(document).ready(function(){ $('a[rel*=facebox]').facebox(); $('.guest-action').click( function() { $.get( $(this).attr('href'), function(responseText) { $.jGrowl(responseText); }); return false; }); $('.notify-function').click( function() { $(this).find('img').attr('src','/icon2.png'); $(this).attr('href','/page2.php'); $(this).removeClass('guest-action').removeClass('notify-function').attr('rel','facebox'); }); }); So basically after notify-function is clicked I am changing the icon and the url of the link, I then am removing the classes so that the click wont be ran again and add rel="facebox" to the link so that the facebox window will pop up if they try to click the new icon2.png that shows up. The problem is after I click the initial icon everything works just fine except when I try to click the new icon2.png it still executes the jgrowl code from the guest-action. But when I view the source it shows this: <a href="/page2.php" rel="facebox" class=""><img src="/icon2.png"></a> So it seemed that should work right? What am I doing wrong? I tried adding the facebox code to the main page that is calling the ajax file as well and still same issue.

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  • POSTmethod and PHP- login verification

    - by Neethusha
    I wrote a code for login verification..I got output with GET. But i need output with POST since it is more secure.pls let me know if there is any error in my code. javascript code: var xml; function verifyusernamepasswd(pass) { //pass is password that will be passed as parameter xml=new XMLHttpRequest(); var url="http://localhost/loginvalidate.php"; var para="q="+username+"&p="+pass;//username is global xml.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); xml.setRequestHeader("Content-length", para.length); xml.setRequestHeader("Connection", "close"); xml.open("POST",url,true); xml.onreadystatechange=statechanged1; xml.send(para); } function statechanged1() { if(xml.readyState==4) alert(xml.responseText); } php code: <?php $username=$_POST["q"]; $password=$_POST["p"]; $con=mysql_connect("localhost","root","blaze"); if(!$con) { die('Could not connect: '.mysql.error()); } mysql_select_db("BLAZE",$con) or die("No such Db"); $result=mysql_query("SELECT Passwword FROM USERTABLE WHERE Userhandle='$username'"); if($result==null) echo "false"; else if($result!=null) { $row=mysql_fetch_array($result); if((strcmp($row['Passwword'],$password)==0)) echo "true"; else echo "false"; } ?> the verification does not return anything, cos my alert is not displayed at all...pls tell me whats wrong....

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  • jQuery sliding animation not working

    - by Jake Zeitz
    I have three divs stacked on each other but offset so that a part of each div is visible. When one of the bottom divs is clicked I want the top div to animate out and back into the stack at the bottom, then the div that is clicked will appear at the top. So far I only have the code for when the middle div is clicked, but I cannot get it to work properly. What am I doing wrong? (I also realize that the code I wrote is probably terrible, this is the first jQuery code I have written.) The css is very very simple: .first { z-index: 3; } .second { z-index: 2; } .third { z-index: 1; } The basic html is this: <div class="first"></div> <div class="second"></div> <div class="third"></div> Here is my code: $("div.second").click(function () { $("div.first").animate({ left: "-=200px"}, {duration: "fast", complete: function () { $("div.first").removeClass("first").addClass("third").animate({left: "+=350px", top: "+=60px"}, "fast"); } }); $("div.second").animate({ left: "-=24px", top: "-=30px"}, {duration: "fast", complete: function () { $("div.second").removeClass("second").addClass("first"); } }); $("div.third").animate({ left: "-=24px", top: "-=30px"}, {duration: "fast", complete: function () { $("div.third").removeClass("third").addClass("second"); } }); }); I can get the div.first to move to the side and back. But now I can't get the classes to stay changed. What keeps happening is the div.second will remove it's class and add .first in the animation, but when the animation is complete, it acts like it still has a class of .second.

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  • Why does the following not work?

    - by Dony
    Hi, I tried to make the code #1 more terse by changing it to code #2 but it doesn't work as expected. Can anyone please tell me why it doesn't work? Thanks. Code #1 std::ostringstream q0; q0 << "(" << x << "," << y << "," << z << ")"; std::string s = q0.str(); Code #2 double x = 8.9, y = 3.4, z = -4.5; std::string s = static_cast<std::ostringstream &>( std::ostringstream() << "(" << x << "," << y << "," << z << ")").str();

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  • Problem with displaying image from DB using asp.net MVC 2

    - by Renato
    Hello! I'm having trouble with displaying image from db. I think that method for saving image is working, because I see in DB that varbinary fields have some value, and that image type is correct. Also the size of image. But when I want to display image for product i don't get anything. Just blank space.. here is my code... public byte[] GetImage(int productID) { Product product = products.GetByID(productID); byte[] imageData = product.ImageData.ToArray(); return imageData; } That code is in my controller. Second is code from view : <% if (product.ImageData != null) { %> <img src='/product/getimage/<%= Html.Encode(product.ID) %>' alt=""/> <% } %> I tried some solutions found here on stack overflow, and everyone do it like this, but it's working for them. I dont have any idea why images aren't displayed. When i look at source code of page at debugging i have : <img src='/product/getimage/18' alt=""/> I'm using .net 4.0, MVC 2, VS 2010... Thanks in advance

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  • Refactoring or Rewriting Monolithic PHP Spaghetti Codebase

    - by nategood
    I've inherited a really poorly designed PHP spaghetti code project. It's been gaining a good bit of traffic recently and is starting to have performance issues on top of the poor monolithic code base. Its maxing out performance on a chunky 16GB dedicated machine when it really shouldn't be. I'm planning on doing some performance tweaks right off the bat to help the performance issue, but this still won't really help the horrible code base. The team is small but expecting to grow very soon. I've read Joel's article on the troubles of doing a complete rewrite and see the concerns. But how bad does the code base have to be before you consider a rewrite? There is PHP handling logic interjected into what one would usually consider a "view". Even worse, in some places SQL statements are in these same files! The only real separation of presentation and logic are a few PHP scripts that serve as function libraries. These scripts do most of the ORM stuff... if you can even call it that. Trying to slowly refractor this seems like a nightmare. Open to your thoughts and opinions... however not interested in hearing, "Run away, Run away!".

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  • Cursor returns zero rows from query to table

    - by brockoli
    I've created an SQLiteDatabase in my app and populated it with some data. I can connect to my AVD with a terminal and when I issue select * from articles; I get a list of all the rows in my table and everything looks fine. However, in my code when I query my table, I get a cursor back that has my tables columns, but zero rows of data. Here is my code.. mDbHelper.open(); Cursor articles = mDbHelper.fetchAllArticles(); startManagingCursor(articles); Cursor feeds = mDbHelper.fetchAllFeeds(); startManagingCursor(feeds); mDbHelper.close(); int titleColumn = articles.getColumnIndex("title"); int feedIdColumn = articles.getColumnIndex("feed_id"); int feedTitleColumn = feeds.getColumnIndex("title"); /* Check if our result was valid. */ if (articles != null) { int count = articles.getCount(); /* Check if at least one Result was returned. */ if (articles.moveToFirst()) { In the above code, my Cursor articles returns with my 4 columns, but when I call getCount() it returns zero, even though I can see hundreds of rows of data in that table from command line. Any idea what I might be doing wrong here? Also.. here is my code for fetchAllArticles.. public Cursor fetchAllArticles() { return mDb.query(ARTICLES_TABLE, new String[] {ARTICLE_KEY_ROWID, ARTICLE_KEY_FEED_ID, ARTICLE_KEY_TITLE, ARTICLE_KEY_URL}, null, null, null, null, null); } Rob W.

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  • No Hibernate Exception on the same insert of data

    - by Mark Estrada
    Hi All, Hibernate Newbie here. I am quite unsure why I am not getting any exception when I am executing below code. On first attempt, this code creates the Book Entry on my Book Table. But my concern is that when I execute below code again, no error was pop out by Hibernate. I was in fact expecting some sort of Violation of Primary Key Constraints as what I have bee doing in JDBC code. public class BookDao { public void createBook(Book bookObj) { Session session = HibernateUtil.getSessionFactory() .getCurrentSession(); session.beginTransaction(); session.saveOrUpdate(bookObj); session.getTransaction().commit(); } } public class HibernateUtil { private static final SessionFactory sessionFactory = buildSessionFactory(); private static SessionFactory buildSessionFactory() { try { // Create the SessionFactory from hibernate.cfg.xml return new AnnotationConfiguration().configure() .buildSessionFactory(); } catch (Throwable ex) { // Make sure you log the exception, as it might be swallowed ex.printStackTrace(); throw new ExceptionInInitializerError(ex); } } public static SessionFactory getSessionFactory() { return sessionFactory; } } public class BookDBStarter { public static void main(String[] args) { Book bookHF = new Book(); bookHF.setIsbn("HF-12345"); bookHF.setName("Head First HTML"); bookHF.setPublishDate(new Date()); BookDao daoBook = new BookDao(); daoBook.createBook(bookHF); } } Is this normal hibernate way? And how will I know if my insert is successful? Any thoughts?

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  • c# "==" operator : compiler behaviour with different structs

    - by Moe Sisko
    Code to illustrate : public struct MyStruct { public int SomeNumber; } public string DoSomethingWithMyStruct(MyStruct s) { if (s == null) return "this can't happen"; else return "ok"; } private string DoSomethingWithDateTime(DateTime s) { if (s == null) return "this can't happen"; // XX else return "ok"; } Now, "DoSomethingWithStruct" fails to compile with : "Operator '==' cannot be applied to operands of type 'MyStruct' and '<null>'". This makes sense, since it doesn't make sense to try a reference comparison with a struct, which is a value type. OTOH, "DoSomethingWithDateTime" compiles, but with compiler warning : "Unreachable code detected" at line marked "XX". Now, I'm assuming that there is no compiler error here, because the DateTime struct overloads the "==" operator. But how does the compiler know that the code is unreachable ? e.g. Does it look inside the code which overloads the "==" operator ? (This is using Visual Studio 2005 in case that makes a difference). Note : I'm more curious than anything about the above. I don't usually try to use "==" on structs and nulls.

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  • iTextSharp Overlay Image

    - by pennylane
    Hi guys I have an instance where I have a logo image as part of some artwork.. If a user uploads a new logo I have a form field which is larger than the default logo. I then use that form field to position the new image. The problem is I need to set the background colour of that form field to white so that it covers the old logo in the event that the new image is smaller than the old logo.. what I have done is: foreach (var imageField in imageReplacements) { fields.SetFieldProperty(imageField.Key, "bgcolor", iTextSharp.text.Color.WHITE, null); fields.RegenerateField(imageField.Key); PdfContentByte overContent = stamper.GetOverContent(imageField.Value.PageNumber); float[] logoArea = fields.GetFieldPositions(imageField.Key); if (logoArea != null) { iTextSharp.text.Rectangle logoRect = new iTextSharp.text.Rectangle(logoArea[1], logoArea[2], logoArea[3], logoArea[4]); var logo = iTextSharp.text.Image.GetInstance(imageField.Value.Location); if (logo.Width >= logoRect.Width || logo.Height >= logoRect.Height) { logo.ScaleToFit(logoRect.Width, logoRect.Height); } logo.Alignment = iTextSharp.text.Image.ALIGN_LEFT; logo.SetAbsolutePosition(logoRect.Left, logoArea[2] + (logoRect.Height - logo.ScaledHeight) / 2); // left: logoArea[3] - logo.ScaledWidth + (logoRect.Width - logo.ScaledWidth) / 2 overContent.AddImage(logo); } } The problem with this is that the background colour of the field is set to white and the image then doesn't appear.. i remove the SetFieldProperty and RegenerateField commands and the image replacement works fine.. is there a way to set a stacking order on layers?

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  • MySQL db Audit Trail Trigger

    - by Natkeeran
    I need to track changes (audit trail) in certain tables in a MySql Db. I am trying to implement the solution suggested here. I have an AuditLog Table with the following columns: AuditLogID, TableName, RowPK, FieldName, OldValue, NewValue, TimeStamp. The mysql stored procedure is the following (this executes fine, and creates the procedure): The call to the procedure such as: CALL addLogTrigger('ProductTypes', 'ProductTypeID'); executes, but does not create any triggers (see the image). SHOW TRIGGERS returns empty set. Please let me know what could be the issue, or an alternate way to implement this. DROP PROCEDURE IF EXISTS addLogTrigger; DELIMITER $ CREATE PROCEDURE addLogTrigger(IN tableName VARCHAR(255), IN pkField VARCHAR(255)) BEGIN SELECT CONCAT( 'DELIMITER $\n', 'CREATE TRIGGER ', tableName, '_AU AFTER UPDATE ON ', tableName, ' FOR EACH ROW BEGIN ', GROUP_CONCAT( CONCAT( 'IF NOT( OLD.', column_name, ' <=> NEW.', column_name, ') THEN INSERT INTO AuditLog (', 'TableName, ', 'RowPK, ', 'FieldName, ', 'OldValue, ', 'NewValue' ') VALUES ( ''', table_name, ''', NEW.', pkField, ', ''', column_name, ''', OLD.', column_name, ', NEW.', column_name, '); END IF;' ) SEPARATOR ' ' ), ' END;$' ) FROM information_schema.columns WHERE table_schema = database() AND table_name = tableName; END$ DELIMITER ;

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  • Concurrent Programming:Should I write a sequential program first, then add thread safety?

    - by evthim
    I'm working on a project where we have to create a number of threads(actual number will be inputted in by testers (TA's)). I'm having trouble not only with the programming but also with the design, I can't wrap my head around all of the threads that will be invoked and where I might cause errors. The project is due soon so I don't want to waste time on this if it'll actually set me back, but I was wondering if I should write the program like only one thread will be running and everything should be sequential and then later go back and try to add the thread safety parts of the code? Would that take twice the original amount of time? Project Description: Note:I'm going to be as vague as possible so I don't violate any honor codes, sorry :( your program should accept n number of objectA threads, m number of objectB threads, and r number of objectC objectB threads interact with code in objectA. objectA threads interact with code in objectB and objectC objectB and objectC don't directly interact, but do so indirectly through objectA -ex: objectB needs something from objectA. objectA gets the result for that something by calling objectC my confusion stems mostly from the fact that all of this interactions will be done by m+n threads and there are various restrictions throughout the descriptions, like objectB can request something from objectA, and objectA has to wait for objectC to finish that something before returning it to objectB. Also each objectA thread can only work on one instruction from objectB at a time, etc. etc. I just want to know if I write the code so that there is only 1 objectA, 1 objectB and 1 object C, can I go back and easily modify it so that those 1's can be changed to m, n and r? Sorry again, if my description is a little bit confusing.

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  • MySQL Need some help with a query

    - by Jules
    I'm trying to fix some data by adding a new field. I have a backup from a few months ago and I have restored this database to my server. I'm looking at table called pads, its primary key is PadID and the field of importance is called RemoveMeDate. In my restored (older) database there is less records with an actual date set in RemoveMeDate. My control date is 2001-01-01 00:00:00 meaning that the record is not hidden aka visible. What I need to do is select all the records from the older database / table with the control date and join with those from the newer db /table where the control date is not set. I hope I've explained that correctly. I'll try again, with numbers. I have 80,000 visible records in the older table (with control date set) and 30,000 in the newer db/table. I need to select the 50,000 from the old database, to perform an update query. Heres my query, which I'd can't get to work as I'd like. jules-fix-reasons is the old database, jules is the newer one. select p.padid from `jules-fix-reasons`.`pads` p JOIN `jules`.`pads` ON p.padid = `jules`.`pads`.`PadID` where p.RemoveMeDate <> '2001-01-01 00:00:00' AND `jules`.`pads`.RemoveMeDate = '2001-01-01 00:00:00'

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  • read the currency format

    - by user485783
    perhaps for some people this is easy, but I want to learn There are 2 currency formats: first currency format is 1,123,123.12 and this format may be like $1,123,123.12 or 1,123,123.12€ and second currency format is 1.123.123,12 and this may be such $1.123.123,12 or 1.123.123,12€ so the difference is the placement of dots and commas The above format will be $this->value('one of the currency format insert here'); e.g. $this->value('$1,123,123.12'); or $this->value('1.123.123,12€'); that I want to know is the code if (first currency format) {use blah .. blah ..} elseif (second currency format) {use blah .. blah ..} else {/ / unsupported format} so how the code to identify whether the entry is input the first currency format or second currency format? thanks for the your pointers and ideas. UPDATED: I apologize for mistake in giving examples When I tried to test the code I have a little confused because it seems not working then I changed my prevoious parts, so that $value['amount'] it may be use first currency format 1,123,123.12 and this format may be like $1,123,123.12 or 1,123,123.12€ and second currency format 1.123.123,12 and this may be such $1.123.123,12 or 1.123.123,12€ then the value['amount'] will identify first with code like the following conditional class curr_format { private bla...bla..1 private bla...bla..2 var etc.. public function curr_format ($bla...,$and_bla..) { //then make conditional is here if (first currency format) {//use blah .. blah ..} elseif (second currency format) {//use blah .. blah ..} else {/ / unsupported format} //another codes.. at the end output as look like: $identify = new curr_format(); echo $identify->curr_format($value['amount'],$else_statement);

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  • How to detect a gamepad button press on OSX 10.5 and higher?

    - by Steph Thirion
    How do I detect a button press on a USB gamepad on OSX 10.5 and higher? I can't wrap my head around the ridiculously complex HID Manager (even though apparently it was simplified with 10.5), and the code samples at Apple have thousands of lines of code that would take days to understand and isolate what I need, so I'd appreciate if someone posts a simple, and fully coded solution for this isolated problem. EDIT: so far all answers are links to source code or semi obscure libraries for all kinds of HID devices, which will require more research time than what I'd like to invest on this. I am starting a bounty to get an actual snippet of code that solves this simple problem (using an external library or not). EDIT POS BOUNTY: thanks to all for you help; but unfortunately the answer that has been automatically selected by the system is not working for me, can't figure out why; and the author has not yet replied to my comments. Any insight would be appreciated, but until a fix is found, anyone looking for resources on this topic should take this answer with a pinch of salt.

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  • Jquery grid overlay in wordpress

    - by Anders Kitson
    I am adding this simple plugin that I have working in a static html site, and am trying to add it to a wordpress development site based off of 960 gs. The jquery code links are correct but the console gives me this error "Uncaught TypeError: Cannot call method 'addGrid' of null" I got the code from this turtorial http://www.badlydrawntoy.com/2009/04/21/960gs-grid-overlay-a-jquery-plugin/ Here is the code I am using /*<![CDATA[*/ // onload $(function() { $("body").addGrid(12, {img_path: 'img/'}); }); /*]]>*/ Here is the code for the plugin /* * @ description: Plugin to display 960.gs gridlines See http://960.gs/ * @author: badlyDrawnToy sharp / http://www.badlydrawntoy.com * @license: Creative Commons License - ShareAlike http://creativecommons.org/licenses/by-sa/3.0/ * @version: 1.0 20th April 2009 */ (function($){$.fn.addGrid=function(cols,options){var defaults={default_cols:12,z_index:999,img_path:'/images/',opacity:.6};var opts=$.extend(defaults,options);var cols=cols!=null&&(cols===12||cols===16)?cols:12;var cols=cols===opts.default_cols?'12_col':'16_col';return this.each(function(){var $el=$(this);var height=$el.height();var wrapper=$('<div id="'+opts.grid_id+'"/>').appendTo($el).css({'display':'none','position':'absolute','top':0,'z-index':(opts.z_index-1),'height':height,'opacity':opts.opacity,'width':'100%'});$('<div/>').addClass('container_12').css({'margin':'0 auto','width':'960px','height':height,'background-image':'url('+opts.img_path+cols+'.png)','background-repeat':'repeat-y'}).appendTo(wrapper);$('<div>grid on</div>').appendTo($el).css({'position':'absolute','top':0,'left':0,'z-index':opts.z_index,'background':'#222','color':'#fff','padding':'3px 6px','width':'40px','text-align':'center'}).hover(function(){$(this).css("cursor","pointer");},function(){$(this).css("cursor","default");}).toggle(function(){$(this).text("grid off");$('#'+opts.grid_id).slideDown();},function(){$(this).text("grid on");$('#'+opts.grid_id).slideUp();});});};})(jQuery);

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  • xml schema putting both sequence and all under one complexType node

    - by exiang
    Here is the xml file: <section> <number>1</number> <title>A Title goes here...</title> <code>TheCode</code> <element></element> <element></element> </section> In section node, there are number, title and code node. Their sequence must not be fixed. Then, there are multiple element under section node as well. The idea is to use the following schema: <xs:complexType name="Type-section"> <xs:all> <xs:element name="number" minOccurs="0"></xs:element> <xs:element name="code" minOccurs="1"></xs:element> <xs:element name="title" minOccurs="1"></xs:element> </xs:all> <xs:sequence> <xs:element maxOccurs="unbounded" name="element"></xs:element> </xs:sequence> </xs:complexType> But it is invalid. I just cant put "sequence" and "all" together in the same level. How can i fix it?

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  • Python modules not updating after restarting the main module.

    - by Ian
    I've recently come back to a project having had to stop for about 6 months, and after reinstalling my operating system and coming back to it I'm having all kinds of crazy things happen. I made sure to install the same version(2.6) of python that I was using before. It started by giving me strange tkinter error that I hadn't had trouble with before, the program is relatively simple and the 2 or 3 bugs that were left when i quit, I had documented and weren't related to the interface. Things got even weirder when the same error would pop up even after I had removed the offending section of code. In fact, the traceback pointed to a line that didn't even exist in the module it was referencing, eg: line 262 when the module was only 200 lines long. After just starting a completely new file for the main module and copy/pasting it finally recognized that the offending code was gone and I stopped getting the error only to find that any updates to the code I made in another module didn't show up when I restarted the program through the shell. (I didn't forget to save.) After fiddling with this, of course, the old interface error came back, only in a different section of code that had been working previously. In fact, if I revert back to the files I had six months ago, the program works fine. As soon as I change anything in the main module, however, the interface bug comes back. Here's the original error: Exception in Tkinter callback Traceback (most recent call last): File "C:\Python26\lib\lib-tk\Tkinter.py", line 1410, in __call__ return self.func(*args) File "C:\PyStuff\interface.py", line 202, in dispOne __main__.top.destroy() File "C:\Python26\lib\lib-tk\Tkinter.py", line 1938, in destroy self.tk.call('destroy', self._w) TclError: can't invoke "destroy" command: application has been destroyed I'm guessing something else is going on here other than my own poor programming. Anyone have any ideas?

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  • How can I change the Python that my Django project is using?

    - by Burak
    I have 2 versions installed in my server. I used virtualenv to install Python 2.7. I am using WSGI to deploy my project. WSGIPythonPath /home/ENV/lib/python2.7/site-packages WSGIScriptAlias / /var/www/html/my_project/wsgi.py My http.conf is like that. python -V gives Python 2.7.3 But in my projects Debug window, it says Django is using 2.6.8. Where am I wrong? UPDATE: Here is my wsgi file import os import sys sys.path.append('/var/www/html') os.environ.setdefault("DJANGO_SETTINGS_MODULE", "myproject.settings") from django.core.wsgi import get_wsgi_application application = get_wsgi_application() Python Version: 2.6.8 Python Path: ['/home/ENV/lib/python2.7/site-packages/setuptools-0.6c11-py2.7.egg', '/home/ENV/lib/python2.7/site-packages/pip-1.1-py2.7.egg', '/home/ENV/lib/python2.7/site-packages/Django-1.4-py2.7.egg', '/home/ENV/lib/python2.7/site-packages', '/usr/lib/python2.6/site-packages/pip-1.1-py2.6.egg', '/usr/lib/python2.6/site-packages/django_transmeta-0.6.7-py2.6.egg', '/usr/lib/python2.6/site-packages/ipython-0.13-py2.6.egg', '/usr/lib/python2.6/site-packages/virtualenv-1.7.2-py2.6.egg', '/usr/lib64/python26.zip', '/usr/lib64/python2.6', '/usr/lib64/python2.6/plat-linux2', '/usr/lib64/python2.6/lib-tk', '/usr/lib64/python2.6/lib-old', '/usr/lib64/python2.6/lib-dynload', '/usr/lib64/python2.6/site-packages', '/usr/lib64/python2.6/site-packages/gtk-2.0', '/usr/lib/python2.6/site-packages', '/usr/lib/python2.6/site-packages/setuptools-0.6c11-py2.6.egg-info', '/var/www/html'] In my error_log of httpd: [Tue Jul 10 20:51:29 2012] [error] python_init: Python version mismatch, expected '2.6.7', found '2.6.8'. [Tue Jul 10 20:51:29 2012] [error] python_init: Python executable found '/usr/bin/python'. [Tue Jul 10 20:51:29 2012] [error] python_init: Python path being used '/usr/lib64/python26.zip:/usr/lib64/python2.6/:/usr/lib64/python2.6/plat-linux2:/usr/lib64/python2.6/lib-tk:/usr/lib64/python2.6/lib-old:/usr/lib64/python2.6/lib-dynload'.

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  • How to accept an incoming call by clicking a button?

    - by upright
    HI, all! I'm trying to implement my own phone call handling UI. What I want to do is, if a call comes in, the incoming telephone number and a picture are displayed, and, if I press a button, the incoming call will be accepted/answered. The related codes are: @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); answerButton = (Button) findViewById(R.id.pickup); answerButton.setOnClickListener(new OnClickListener() { public void onClick(final View v) { Intent intent = new Intent("android.intent.action.ANSWER"); intent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK); startActivity(intent); } }); Sadly, the code does not work. At first, an exception is thrown if I press my answer button: ActivityNotFoundException: No Activity found to handle Intent { act=android.intent.action.ANSWER Then I added an entry in the AndroidManifest.xml: I run the app again, there is no exception anymore. However, I doubt the incoming call is not really accepted. Because if the press the Android's screen answer button (green button), the incoming call is accepted and a green button is also displayed on the upper left corner of the emulator screen, while my app doesn't. I also read the Phone app's source code in android source. There is method such as acceptCall() in the Phone class. But these codes seem difficult for me to use, because there are many imports declaration in the code, such as : import com.android.internal.telephony.Call; import com.android.internal.telephony.CallStateException; import com.android.internal.telephony.CallerInfo; import com.android.internal.telephony.CallerInfoAsyncQuery; import com.android.internal.telephony.Connection; import com.android.internal.telephony.MmiCode; import com.android.internal.telephony.Phone; And, if I add these imports in my code, there will be too many errors, such as : "The import com.android.internal.telephony cannot be resolved" What is the right and simple way for my problem? Thanks in advance!

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  • jQuery ajax form submit - how to ensure dynamically loaded form's action is used

    - by kenny99
    Hi, i'm having a problem with dynamically loaded forms - instead of using the action attribute of the newly loaded form, my jquery code is still using the action attribute of the first form loaded. I have the following code: //generic ajax form handler - calls next page load on success $('input.next:not(#eligibility)').live("click", function(){ $(".form_container form").validationEngine({ ajaxSubmit: true, ajaxSubmitFile: $(this).attr('action'), success : function() { var url = $('input.next').attr('rel'); ajaxFormStage(url); }, failure : function() { } }); }); But when the next form is loaded, the above code does not pick up the new action attribute. I have tried adding the above code to my callback on successful ajax load (shown below), but this doesn't make any difference. Can anyone help? Many thanks function ajaxFormStage(url) { var $data = $('#main_body #content'); $.validationEngine.closePrompt('body'); //close any validation messages $data.fadeOut('fast', function(){ $data.load(url, function(){ $data.animate({ opacity: 'show' }, 'fast'); '); //generic ajax form handler - calls next page load on success $('input.next:not(#eligibility)').live("click", function(){ $(".form_container form").validationEngine({ ajaxSubmit: true, ajaxSubmitFile: $(this).attr('action'), success : function() { var url = $('input.next').attr('rel'); ajaxFormStage(url); }, failure : function() { } }); }); }); });

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  • iPhone: Calling dealloc on parentViewController causes an exception

    - by arielcamus
    Hi, I'm dealing with viewDidUnload and dealloc methods and I've founded a problem when calling [super dealloc]; in parent view controller. I have a lot of view controllers with custom code which I have putted outside on a parent view controller. So, when defining my view controllers I set a reference to the super class: @interface LoginViewController : AbstractViewController Then, at the dealloc method I call the AbstractViewController dealloc method: //(Login View Controller code) - (void)dealloc { [user release]; [passwd release]; [super dealloc]; } [super dealloc] execute the following code: //(Abstract View Controller code) - (void)dealloc { [dbUtils release]; [loadingView release]; [super dealloc]; } If I simulate a memory warning on iPhone Simulator, the following exception is thrown: 2010-03-03 11:27:45.805 MyApp[71563:40b] Received simulated memory warning. 2010-03-03 11:27:45.808 MyApp[71563:40b] *** -[LoginViewController isViewLoaded]: message sent to deallocated instance 0x13b51b0 kill quit However, if I comment the [super dealloc] line in AbstractViewController the exception is not thrown and my app still running. Thank you for your help once again!

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  • PHP static function self:: in joomla JFactory class explanation?

    - by Carbon6
    Hi I'm looking at the code of Joomla and trying to figure out what exactly happends in this function. index.php makes a call to function $app = JFactory::getApplication('site'); jfactory.php code public static function getApplication($id = null, $config = array(), $prefix='J') { if (!self::$application) { jimport('joomla.application.application'); self::$application = JApplication::getInstance($id, $config, $prefix); } return self::$application; } application.php code.. public static function getInstance($client, $config = array(), $prefix = 'J') { static $instances; if (!isset($instances)) { $instances = array(); } ....... more code ........ return $instances[$client]; } Now I cannot figure out in function getApplication why is self:$application used. self::$application = JApplication::getInstance($id, $config, $prefix); $application is always null, what is the purpose of using this approach. I tryied modifying it to $var = JApplication::getInstance($id, $config, $prefix); and returnig it but it doesn't work. I would be very glad if someone with more knowledge could explain what is happening here detailed as possible. Many thanks.

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