Search Results

Search found 4688 results on 188 pages for 'django pagination'.

Page 78/188 | < Previous Page | 74 75 76 77 78 79 80 81 82 83 84 85  | Next Page >

  • Matching blank entries in django queryset for optional field with corresponding ones in a required

    - by gramware
    I have a django queryset in my views whose values I pack before passing to my template. There is a problem when the queryset returns none since associated values are not unpacked. the quersyet is called comments. Here is my views.py def forums(request ): post_list = list(forum.objects.filter(child='0')&forum.objects.filter(deleted='0').order_by('postDate')) user = UserProfile.objects.get(pk=request.session['_auth_user_id']) newpostform = PostForm(request.POST) deletepostform = PostDeleteForm(request.POST) DelPostFormSet = modelformset_factory(forum, exclude=('child','postSubject','postBody','postPoster','postDate','childParentId')) readform = ReadForumForm(request.POST) comments =list( forum.objects.filter(deleted='0').filter(child='1').order_by('childParentId').values('childParentId').annotate(y=Count('childParentId'))) if request.user.is_staff== True : staff = 1 else: staff = 0 staffis = 1 if newpostform.is_valid(): topic = request.POST['postSubject'] poster = request.POST['postPoster'] newpostform.save() return HttpResponseRedirect('/forums') else: newpostform = PostForm(initial = {'postPoster':user.id}) if request.GET: form = SearchForm(request.GET) if form.is_valid(): query = form.cleaned_data['query'] post_list = list((forum.objects.filter(child='0')&forum.objects.filter(deleted='0')&forum.objects.filter(Q(postSubject__icontains=query)|Q(postBody__icontains=query)|Q(postDate__icontains=query)))or(forum.objects.filter(deleted='0')&forum.objects.filter(Q(postSubject__icontains=query)|Q(postBody__icontains=query)|Q(postDate__icontains=query)).values('childParentId'))) if request.method == 'POST': delpostformset = DelPostFormSet(request.POST) if delpostformset.is_valid(): delpostformset.save() return HttpResponseRedirect('/forums') else: delpostformset = DelPostFormSet(queryset=forum.objects.filter(child='0', deleted='0')) """if readform.is_valid(): user=get_object_or_404(UserProfile.objects.all()) readform.save() else: readform = ReadForumForm()""" post= zip( post_list,comments, delpostformset.forms) paginator = Paginator(post, 10) # Show 10 contacts per page # Make sure page request is an int. If not, deliver first page. try: page = int(request.GET.get('page', '1')) except ValueError: page = 1 # If page request (9999) is out of range, deliver last page of results. try: post = paginator.page(page) except (EmptyPage, InvalidPage): post = paginator.page(paginator.num_pages) return render_to_response('forum.html', {'post':post, 'newpostform': newpostform,'delpost':delpostformset, 'username':user.username, 'comments':comments, 'user':user, },context_instance = RequestContext( request )) I realised that the issue was with the comments queryset comments =list( forum.objects.filter(deleted='0').filter(child='1').order_by('childParentId').values('childParentId').annotate(y=Count('childParentId'))) which will only returns values for posts that have comments. so i now need a way to return 0 comments when a value in post-list post_list = list(forum.objects.filter(child='0')&forum.objects.filter(deleted='0').order_by('postDate')) does not have any comments (optional field). Here is my models.py class forum(models.Model): postID = models.AutoField(primary_key=True) postSubject = models.CharField(max_length=100) postBody = models.TextField() postPoster = models.ForeignKey(UserProfile) postDate = models.DateTimeField(auto_now_add=True) child = models.BooleanField() childParentId = models.ForeignKey('self',blank=True, null=True) deleted = models.BooleanField() def __unicode__(self): return u' %d' % ( self.postID)

    Read the article

  • Django : presenting a form very different from the model and with multiple field values in a Django-

    - by sebpiq
    Hi ! I'm currently doing a firewall management application for Django, here's the (simplified) model : class Port(models.Model): number = models.PositiveIntegerField(primary_key=True) application = models.CharField(max_length=16, blank=True) class Rule(models.Model): port = models.ForeignKey(Port) ip_source = models.IPAddressField() ip_mask = models.IntegerField(validators=[MaxValueValidator(32)]) machine = models.ForeignKey("vmm.machine") What I would like to do, however, is to display to the user a form for entering rules, but with a very different organization than the model : Port 80 O Not open O Everywhere O Specific addresses : --------- delete field --------- delete field + add address field Port 443 ... etc Where Not open means that there is no rule for the given port, Everywhere means that there is only ONE rule (0.0.0.0/0) for the given port, and with specific addresses, you can add as many addresses as you want (I did this with JQuery), which will make as many rules. Now I did a version completely "handmade", meaning that I create the forms entirely in my templates, set input names with a prefix, and parse all the POSTed stuff in my view (which is quite painful, and means that there's no point in using a web framework). I also have a class which aggregates the rules together to easily pre-fill the forms with the informations "not open, everywhere, ...". I'm passing a list of those to the template, therefore it acts as an interface between my model and my "handmade" form : class MachinePort(object): def __init__(self, machine, port): self.machine = machine self.port = port @property def fully_open(self): for rule in self.port.rule_set.filter(machine=self.machine): if ipaddr.IPv4Network("%s/%s" % (rule.ip_source, rule.ip_mask)) == ipaddr.IPv4Network("0.0.0.0/0"): return True else : return False @property def partly_open(self): return bool(self.port.rule_set.filter(machine=self.machine)) and not self.fully_open @property def not_open(self): return not self.partly_open and not self.fully_open But all this is rather ugly ! Do anyone of you know if there is a classy way to do this ? In particular with the form... I don't know how to have a form that can have an undefined number of fields, neither how to transform these fields into Rule objects (because all the rule fields would have to be gathered from the form), neither how to save multiple objects... Well I could try to hack into the Form class, but seems like too much work for such a special case. Is there any nice feature I'm missing ?

    Read the article

  • getting Cannot identify image file when trying to create thumbnail in django

    - by Mo J. Mughrabi
    Am trying to create a thumbnail in django, am trying to build a custom class specifically to be used for generating thumbnails. As following from StringIO import StringIO from PIL import Image class Thumbnail(object): source = '' size = (50, 50) output = '' def __init__(self): pass @staticmethod def load(src): self = Thumbnail() self.source = src return self def generate(self, size=(50, 50)): if not isinstance(size, tuple): raise Exception('Thumbnail class: The size parameter must be an instance of a tuple.') self.size = size # resize properties box = self.size factor = 1 fit = True image = Image.open(self.source) # Convert to RGB if necessary if image.mode not in ('L', 'RGB'): image = image.convert('RGB') while image.size[0]/factor > 2*box[0] and image.size[1]*2/factor > 2*box[1]: factor *=2 if factor > 1: image.thumbnail((image.size[0]/factor, image.size[1]/factor), Image.NEAREST) #calculate the cropping box and get the cropped part if fit: x1 = y1 = 0 x2, y2 = image.size wRatio = 1.0 * x2/box[0] hRatio = 1.0 * y2/box[1] if hRatio > wRatio: y1 = int(y2/2-box[1]*wRatio/2) y2 = int(y2/2+box[1]*wRatio/2) else: x1 = int(x2/2-box[0]*hRatio/2) x2 = int(x2/2+box[0]*hRatio/2) image = image.crop((x1,y1,x2,y2)) #Resize the image with best quality algorithm ANTI-ALIAS image.thumbnail(box, Image.ANTIALIAS) # save image to memory temp_handle = StringIO() image.save(temp_handle, 'png') temp_handle.seek(0) self.output = temp_handle return self def get_output(self): return self.output.read() the purpose of the class is so i can use it inside different locations to generate thumbnails on the fly. The class works perfectly, I've tested it directly under a view.. I've implemented the thumbnail class inside the save method of the forms to resize the original images on saving. in my design, I have two fields for thumbnails. I was able to generate one thumbnail, if I try to generate two it crashes and I've been stuck for hours not sure whats the problem. Here is my model class Image(models.Model): article = models.ForeignKey(Article) title = models.CharField(max_length=100, null=True, blank=True) src = models.ImageField(upload_to='publication/image/') r128 = models.ImageField(upload_to='publication/image/128/', blank=True, null=True) r200 = models.ImageField(upload_to='publication/image/200/', blank=True, null=True) uploaded_at = models.DateTimeField(auto_now=True) Here is my forms class ImageForm(models.ModelForm): """ """ class Meta: model = Image fields = ('src',) def save(self, commit=True): instance = super(ImageForm, self).save(commit=True) file = Thumbnail.load(instance.src) instance.r128 = SimpleUploadedFile( instance.src.name, file.generate((128, 128)).get_output(), content_type='image/png' ) instance.r200 = SimpleUploadedFile( instance.src.name, file.generate((200, 200)).get_output(), content_type='image/png' ) if commit: instance.save() return instance the strange part is, when i remove the line which contains instance.r200 in the form save. It works fine, and it does the thumbnail and stores it successfully. Once I add the second thumbnail it fails.. Any ideas what am doing wrong here? Thanks Update: I tried earlier doing the following but I still got the same error class ImageForm(models.ModelForm): """ """ class Meta: model = Image fields = ('src',) def save(self, commit=True): instance = super(ImageForm, self).save(commit=True) instance.r128 = SimpleUploadedFile( instance.src.name, Thumbnail.load(instance.src).generate((128, 128)).get_output(), content_type='image/png' ) instance.r200 = SimpleUploadedFile( instance.src.name, Thumbnail.load(instance.src).generate((200, 200)).get_output(), content_type='image/png' ) if commit: instance.save() return instance

    Read the article

  • Jquery pagination

    - by Oliver Bayes-Shelton
    Hi , I have my code working etc for the pagination plugin but I have a slight error. When I add a table above my table which works with the sorter and pagination the pagination does not work. I think it is because that the table above it is taking the all the features and not using them. So is there a way to define which table to use like using a ID ? If any one could give an example it would be great. This is the code I am using http://tablesorter.com/addons/pager/jquery.tablesorter.pager.js

    Read the article

  • hibernate pagination mechanism

    - by haicnpmk44
    I am trying to use Hibernate pagination for my query (PostgreSQL ) i set setFirstResult(0), setMaxResults(20) for my sql query. My code like below: Session session = getSessionFactory().getCurrentSession(); session.beginTransaction(); Query query = session.createQuery("select id , customer_name , address from tbl_customers "); query.setFirstResult(0); query.setMaxResults(20); List<T> entities = query.list(); session.getTransaction().commit(); but when viewing SQL hibernate log, i still see full sql query: Hibernate: select customer0_.id as id9_, customer0_.customer_name as dst2_9_, customer0_.addres as dst3_9_ from tbl_customers customer0_ Why there is no LIMIT OFFSET in query of Hibernate pagination SQL log? Does anyone know about Hibernate pagination mechanism? I guess that Hibernate will select all data, put data into Resultset, and then paging in Resultset, right?

    Read the article

  • Apache cannot find mysql database modules

    - by user809857
    I've created a simple django project and setup a mysql database. My simple project just creates an entry on the database. The project works fine when I use the built in development server provided by django (runserver) and it works well. But when I deployed the project on Apache and mod_Wsgi (Ubuntu server), django could not find 'books', which is in this case my table in the database. The mysql database that I use in runserver and apache are just the same. I also did rebuild the database using sqlall,validate and syncdb of django but still i get the error. What could be wrong with what I'm doing? Thanks

    Read the article

  • Apache cannot find mysql database modules

    - by user809857
    I've created a simple django project and setup a mysql database. My simple project just creates an entry on the database. The project works fine when I use the built in development server provided by django (runserver) and it works well. But when I deployed the project on Apache and mod_Wsgi (Ubuntu server), django could not find 'books', which is in this case my table in the database. The mysql database that I use in runserver and apache are just the same. I also did rebuild the database using sqlall,validate and syncdb of django but still i get the error. What could be wrong with what I'm doing? Thanks

    Read the article

  • MySQL efficiency as it relates to the database/table size

    - by mlissner
    I'm building a system using django, Sphinx and MySQL that's very quickly becoming quite large. The database currently has about 2000 rows, and I've written a program that's going to populate it with another 40,000 rows in a couple days. Since the database is live right now, and since I've never had a database with this much information in it, I'm worried about some things: Is adding all these rows going to seriously degrade the efficiency of my django app? Will I need to go back through it and optimize all my database calls so they're doing things more cleverly? Or will this make the database slow all around to the extent that I can't do anything about it at all? If you scoff at my 40k rows, then, my next question is, at what point SHOULD I be concerned? I will likely be adding another couple hundred thousand soon, so I worry, and I fret. How is sphinx going to feel about all this? Is it going to freak out when it realizes it has to index all this data? Or will it be fine? Is this normal for it? If it is, at what point should I be concerned that it's too much data for Sphinx? Thanks for any thoughts.

    Read the article

  • Select those objects whose related objects IDs are *all* in given string

    - by Jannis
    Hi Django people, I want to build a frontend to a recipe database which enables the user to search for a list of recipes which are cookable with the ingredients the user supplies. I have the following models class Ingredient(models.Model): name = models.CharField(max_length=100, unique=True) slug = models.SlugField(max_length=100, unique=True) importancy = models.PositiveSmallIntegerField(default=4) […] class Amount(models.Model): recipe = models.ForeignKey('Recipe') ingredient = models.ForeignKey(Ingredient) […] class Rezept(models.Model): name = models.CharField(max_length=100) slug = models.SlugField() instructions = models.TextField() ingredients = models.ManyToManyField(Ingredient, through=Amount) […] and a rawquery which does exactly what I want: It gets all the recipes whose required ingredients are all contained in the list of strings that the user supplies. If he supplies more than necessary, it's fine too. query = "SELECT *, COUNT(amount.zutat_id) AS selected_count_ingredients, (SELECT COUNT(*) FROM amount WHERE amount.recipe_id = amount.id) AS count_ingredients FROM amount LEFT OUTER JOIN amount ON (recipe.id = recipe.recipe_id) WHERE amount.ingredient_id IN (%s) GROUP BY amount.id HAVING count_ingredient=selected_count_ingredient" % ",".join([str(ingredient.id) for ingredient in ingredients]) rezepte = Rezept.objects.raw(query) Now, what I'm looking for is a way that does not rely on .raw() as I would like to do it purely with Django's queryset methods. Additionally, it would be awesome if you guys knew a way of including the ingredient's importancy in the lookup so that a recipe is still shown as a result even though one of its ingredients (that has an importancy of 0) is not supplied by the user.

    Read the article

  • Dynamically setting the queryset of a ModelMultipleChoiceField to a custom recordset

    - by Daniel Quinn
    I've seen all the howtos about how you can set a ModelMultipleChoiceField to use a custom queryset and I've tried them and they work. However, they all use the same paradigm: the queryset is just a filtered list of the same objects. In my case, I'm trying to get the admin to draw a multiselect form that instead of using usernames as the text portion of the , I'd like to use the name field from my account class. Here's a breakdown of what I've got: # models.py class Account(models.Model): name = models.CharField(max_length=128,help_text="A display name that people understand") user = models.ForeignKey(User, unique=True) # Tied to the User class in settings.py class Organisation(models.Model): administrators = models.ManyToManyField(User) # admin.py from django.forms import ModelMultipleChoiceField from django.contrib.auth.models import User class OrganisationAdminForm(forms.ModelForm): def __init__(self, *args, **kwargs): from ethico.accounts.models import Account self.base_fields["administrators"] = ModelMultipleChoiceField( queryset=User.objects.all(), required=False ) super(OrganisationAdminForm, self).__init__(*args, **kwargs) class Meta: model = Organisation This works, however, I want queryset above to draw a selectbox with the Account.name property and the User.id property. This didn't work: queryset=Account.objects.all().order_by("name").values_list("user","name") It failed with this error: 'tuple' object has no attribute 'pk' I figured that this would be easy, but it's turned into hours of dead-ends. Anyone care to shed some light?

    Read the article

  • Blocking error in celery

    - by dmitry
    I have no idea what's this. Python 2.7 + django-1.5.1 + httpd + rabbitmq + django-celery==3.0.17 Tasks are not executed because of some error. Below is celery's log. Maybe someone has faced it before. [2013-06-24 17:10:03,792: CRITICAL/MainProcess] Can't decode message body: AttributeError("'JoinInfo' object has no attribute '__dict__'",) (type:u'application/x-python-serialize' encoding:u'binary' raw:'\'\\x80\\x02}q\\x01(U\\x07expiresq\\x02NU\\x03utcq\\x03\\x88U\\x04argsq\\x04cdjango.contrib.auth.models\\nUser\\nq\\x05)\\x81q\\x06}q\\x07(U\\x08usernameq\\x08X\\x19\\x00\\x00\\[email protected]\\nfirst_nameq\\tX\\x05\\x00\\x00\\x00BibbyU\\tlast_nameq\\nX\\x08\\x00\\x00\\x00OffshoreU\\r_client_cacheq\\x0bccopy_reg\\n_reconstructor\\nq\\x0ccbongoregistration.models\\nClient\\nq\\rc__builtin__\\nobject\\nq\\x0eN\\x87Rq\\x0f}q\\x10(h\\nX\\x08\\x00\\x00\\x00OffshoreU\\x1bpurchase_confirmation_emailq\\x11X\\x1f\\x00\\x00\\[email protected]\\x1dpurchase_confirmation_email_1q\\x12X!\\x00\\x00\\[email protected]\\x06_stateq\\x13cdjango.db.models.base\\nModelState\\nq\\x14)\\x81q\\x15}q\\x16(U\\x06addingq\\x17\\x89U\\x02dbq\\x18U\\x07defaultq\\x19ubU\\x0buser_ptr_idq\\x1aJ\\xb4\\xa2\\x03\\x00U\\x08is_staffq\\x1b\\x89U\\x08postcodeq\\x1cX\\x08\\x00\\x00\\x00AB11 5BSU\\x0cdegree_limitq\\x1dK\\x06U\\x07messageq\\x1eX\\xd1E\\x00\\x00<table id="container" style="margin: 0px; padding: 0px; width: 100%; background-color: #ffffff;" cellspacing="0" cellpadding="0"... (22911b)'') Traceback (most recent call last): File "/opt/www/MyProject-main/eggs/kombu-2.5.10-py2.7.egg/kombu/messaging.py", line 556, in _receive_callback decoded = None if on_m else message.decode() File "/opt/www/MyProject-main/eggs/kombu-2.5.10-py2.7.egg/kombu/transport/base.py", line 147, in decode self.content_encoding, accept=self.accept) File "/opt/www/MyProject-main/eggs/kombu-2.5.10-py2.7.egg/kombu/serialization.py", line 187, in decode return decode(data) File "/opt/www/MyProject-main/eggs/kombu-2.5.10-py2.7.egg/kombu/serialization.py", line 74, in pickle_loads return load(BytesIO(s)) AttributeError: 'JoinInfo' object has no attribute '__dict__'

    Read the article

  • Firefox handles xxx.submit(), Safari doesn't ... what can be done?

    - by Prairiedogg
    I'm trying to make a pull down menu post a form when the user selects (releases the mouse) on one of the options from the menu. This code works fine in FF but Safari, for some reason, doesn't submit the form. I re-wrote the code using jquery to see if jquery's .submit() implementation handled the browser quirks better. Same result, works in FF doesn't work in safari. The following snippets are from the same page, which has some django template language mixed in. Here's the vanilla js attempt: function formSubmit(lang) { if (lang != '{{ LANGUAGE_CODE }}') { document.getElementById("setlang_form").submit(); } } Here's the jquery attempt: $(document).ready(function() { $('#lang_submit').hide() $('#setlang_form option').mouseup(function () { if ($(this).attr('value') != '{{ LANGUAGE_CODE }}') { $('#setlang_form').submit() } }); }); and here's the form: <form id="setlang_form" method="post" action="{% url django.views.i18n.set_language %}"> <fieldset> <select name="language"> {% for lang in interface_languages %} <option value="{{ lang.code }}" onmouseup="formSubmit('{{ lang.name }}')" {% ifequal lang.code LANGUAGE_CODE %}selected="selected"{% endifequal %}>{{ lang.name }}</option> {% endfor %} </select> </fieldset> </form> My question is, how can I get this working in Safari?

    Read the article

  • Can rel="next" and rel="prev" can be ignored in blog listings

    - by Saahil Sinha
    We have a blog - which is current spread to 9 pages, every page has a unique title - page 1, page 2, page 3 and so on. Also, as it's a blog, every page has unique 10 listing entry on one page. Is rel="prev" and rel="next" can be safely ignored as all these are listing and not content pages of article. What I read in all through Google Search is that rel="next" and rel="prev" should be applicable on where the content is spread across multiple pages. But - as it's a blog, it has blog listings and every listing has unique content This is the blog: http://www.mycarhelpline.com/index.php?option=com_easyblog&view=latest&Itemid=91. May recommend, if by ignoring rel="next" and rel="prev" - are we inviting Google to treat the blog listing pages as duplicate.

    Read the article

  • jquery pagination

    - by user295189
    We are using jquery for pagination. We are pulling millions of records from the database and then th jquery does the pagination on the front end. that is a very slow process. Can someone advice us of a solution in php and jquery where we pull 50 records at a time? Thanks

    Read the article

  • Google webmaster showing duplicate meta descriptions for search directory

    - by Mike Flynn
    What is the best way to get rid of this error in Google Webmasters? Do I really need to add "- Page 2" at the end of the descripton? Page Description Kansas basketball tournaments posted by organizations and teams for youth, AAU, and NCAA certified e Pages /youth-basketball-tournaments/kansas /youth-basketball-tournaments/kansas?page=2 /youth-basketball-tournaments/kansas?page=3 /youth-basketball-tournaments/kansas?page=9

    Read the article

  • What is the best way to implement paginated text editing in Python?

    - by W.F
    I'm trying to build a formatted text editor in python. I need the editor to be paginated on edit mode. Same as in all popular word processors - when the user is editing the document what he/she sees is a representation of the actual, physical, page. I've tried looking into PySide but I can't find any ready solution to this, nor I can work out a way to do it myself. I am totally open to new technologies, so if you think Python is not the right choice here I would love to hear about new stuff (especially when I'm this new to UI coding). It only needs to be cross-platform and let me do rapid development (hence me looking for an out-of-the-box solution to this). Please suggest the best way to implement this. Please also note that I am looking for either a ready solution or an advice on how to tackle this. Thank you very much !

    Read the article

  • How to dynamically change pagination urls in ExtJS?

    - by Tom Schaefer
    I have two data grids. The first auto-loads a list of items (json data store). OnCellClick the first grid fires a dynamically parametrized url and loads data into the second grid. It works fine, but the pagination of the second grid does not focus the new context. What shall I do to make the pagination work with the new url?

    Read the article

  • Showing pagination with only single page using will_paginate

    - by James
    I'm using will_paginate as standard, but it only shows the pagination controls (< 1 2 etc) when there's more than one page to display. Normally, this would be what is wanted, but I want to see the pagination controls (for UI consistency and to get round an annoying CSS quirk in the system I'm working on) even when there's only 1 page to display (showing < 1 ). Is this possible?

    Read the article

  • wayfinder, paginator, or breadcrumb?

    - by LOTUSMS
    My question is fairly simple. I've heard one or two people call it a "wayfinder" and I personally call it "breadcrumb", then again "paginator" can also fit the bill. Bottom line is I can't seem to find what I need because I am not coming up with the right term. What I want is the following: I have a site with a multiple-pages form. I want my users to see the steps through the form. I searched for all three terms and nothing I can use has shown. I could build one from scratch but I am interested in what is out there. Someone may have done a better job than I will be doing. Any idea on what to call this and if you have a link I can check out, that will be bonus Thanks

    Read the article

  • Generic relations missing with grappelli

    - by diegueus9
    I'm using the last svn revision of grappelli and rev 11840 of django (before multidatabases and stuff), and i'm trying to use generic relations in the admin, but doesn't work, The model: class AutorProyectoLey(DatedModel): tipo_autor = models.ForeignKey(ContentType) autor_id = models.PositiveIntegerField() content_object = generic.GenericForeignKey('tipo_autor', 'autor_id') proyecto_ley = models.ForeignKey(ProyectoLey) The admin: class AutorInline(GenericInlineModelAdmin): model = AutorProyectoLey allow_add = True ct_field = 'tipo_autor' ct_fk_field = 'autor_id' classes = ('collapse-open',) And i put this model of var inlines in another adminmodel, but the html render is : <!-- Inlines --> <!-- Submit-Row -->

    Read the article

  • 2 fields unique

    - by xRobot
    I have this model: class blog(models.Model): user = models.ForeignKey(User) mail = models.EmailField(max_length=60, null=False, blank=False) name = models.CharField(max_length=60, blank=True, null=True) I want that (user,email) are unique togheter. For example: This is allowed: 1, [email protected], myblog 2, [email protected], secondblog This is NOT allowed: 1, [email protected], myblog 1, [email protected], secondblog Is this possible in Django ?

    Read the article

  • why save_model method doesn't work in admin.StackedInline?

    - by FurtiveFelon
    Hi all, I have a similar problem as a previously solved problem of mine, except this time solution doesn't seem to work: http://stackoverflow.com/questions/2991365/how-to-auto-insert-the-current-user-when-creating-an-object-in-django-admin Previously i used to override the save_model to stamp the user submitting the article. Now i need to do the same for comments, it doesn't seem to work anymore. Anyone have any ideas? Thanks a lot! Jason

    Read the article

  • How to use the same template for different query sets?

    - by knuckfubuck
    I'm new to Django and setting up my first site. I have a Share model and a template called share_list.html that uses an object_list like this: {% for object in object_list %} I setup haystack using their tutorial and the search template looks like this: {% for result in page.object_list %} I would like to modify the search.html template to have an include of the share_list so I don't have to repeat myself. How can I make it use the same object_list?

    Read the article

< Previous Page | 74 75 76 77 78 79 80 81 82 83 84 85  | Next Page >