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  • Should the 12-String be in it's own class and why?

    - by MayNotBe
    This question is regarding a homework project in my first Java programming class (online program). The assignment is to create a "stringed instrument" class using (among other things) an array of String names representing instrument string names ("A", "E", etc). The idea for the 12-string is beyond the scope of the assignment (it doesn't have to be included at all) but now that I've thought of it, I want to figure out how to make it work. Part of me feels like the 12-String should have it's own class, but another part of me feels that it should be in the guitar class because it's a guitar. I suppose this will become clear as I progress but I thought I would see what kind of response I get here. Also, why would they ask for a String[] for the instrument string names? Seems like a char[] makes more sense. Thank you for any insight. Here's my code so far (it's a work in progress): public class Guitar { private int numberOfStrings = 6; private static int numberOfGuitars = 0; private String[] stringNotes = {"E", "A", "D", "G", "B", "A"}; private boolean tuned = false; private boolean playing = false; public Guitar(){ numberOfGuitars++; } public Guitar(boolean twelveString){ if(twelveString){ stringNotes[0] = "E, E"; stringNotes[1] = "A, A"; stringNotes[2] = "D, D"; stringNotes[3] = "G, G"; stringNotes[4] = "B, B"; stringNotes[5] = "E, E"; numberOfStrings = 12; } } public int getNumberOfStrings() { return numberOfStrings; } public void setNumberOfStrings(int strings) { if(strings == 12 || strings == 6) { if(strings == 12){ stringNotes[0] = "E, E"; stringNotes[1] = "A, A"; stringNotes[2] = "D, D"; stringNotes[3] = "G, G"; stringNotes[4] = "B, B"; stringNotes[5] = "E, E"; numberOfStrings = strings; } if(strings == 6) numberOfStrings = strings; }//if else System.out.println("***ERROR***Guitar can only have 6 or 12 strings***ERROR***"); } public void getStringNotes() { for(int i = 0; i < stringNotes.length; i++){ if(i == stringNotes.length - 1) System.out.println(stringNotes[i]); else System.out.print(stringNotes[i] + ", "); }//for }

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  • How should I refactor switch statements like this (Switching on type) to be more OO?

    - by Taytay
    I'm seeing some code like this in our code base, and want to refactor it: (Typescript psuedocode follows): class EntityManager{ private findEntityForServerObject(entityType:string, serverObject:any):IEntity { var existingEntity:IEntity = null; switch(entityType) { case Types.UserSetting: existingEntity = this.getUserSettingByUserIdAndSettingName(serverObject.user_id, serverObject.setting_name); break; case Types.Bar: existingEntity = this.getBarByUserIdAndId(serverObject.user_id, serverObject.id); break; //Lots more case statements here... } return existingEntity; } } The downsides of switching on type are self-explanatory. Normally, when switching behavior based on type, I try to push the behavior into subclasses so that I can reduce this to a single method call, and let polymorphism take care of the rest. However, the following two things are giving me pause: 1) I don't want to couple the serverObject with the class that is storing all of these objects. It doesn't know where to look for entities of a certain type. And unfortunately, the identity of a type of ServerObject varies with the type of ServerObject. (So sometimes it's just an ID, other times it's a combination of an id and a uniquely identifying string, etc). And this behavior doesn't belong down there on those subclasses. It is the responsibility of the EntityManager and its delegates. 2) In this case, I can't modify the ServerObject classes since they're plain old data objects. It should be mentioned that I've got other instances of the above method that take a parameter like "IEntity" and proceed to do almost the same thing (but slightly modify the name of the methods they're calling to get the identity of the entity). So, we might have: case Types.Bar: existingEntity = this.getBarByUserIdAndId(entity.getUserId(), entity.getId()); break; So in that case, I can change the entity interface and subclasses, but this isn't behavior that belongs in that class. So, I think that points me to some sort of map. So eventually I will call: private findEntityForServerObject(entityType:string, serverObject:any):IEntity { return aMapOfSomeSort[entityType].findByServerObject(serverObject); } private findEntityForEntity(someEntity:IEntity):IEntity { return aMapOfSomeSort[someEntity.entityType].findByEntity(someEntity); } Which means I need to register some sort of strategy classes/functions at runtime with this map. And again, I darn well better remember to register one for each my my types, or I'll get a runtime exception. Is there a better way to refactor this? I feel like I'm missing something really obvious here.

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  • Should Equality be commutative within a Class Hierachy?

    - by vossad01
    It is easy to define the Equals operation in ways that are not commutative. When providing equality against other types, there are obviously situations (in most languages) were equality not being commutative is unavoidable. However, within one's own inheritance hierarchy where the root base class defines an equality member, a programmer has more control. Thus you can create situations where (A = B) ? (B = A), where A and B both derive from base class T Substituting the = with the appropriate variation for a given language. (.Equals(_), ==, etc.) That seems wrong to me, however, I recognize I may be biased by background in Mathematics. I have not been in programming long enough to know what is standard/accepted/preferred practice when programming. Do most programmers just accept .Equals(_)may not be commutative and code defensibly. Do they expect commutativity and get annoyed if it is not. In short, when working in a class hierarchy, should effort me made to ensure Equality is commutative?

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  • Did Bjarne Stroustrup create the terms constructor/destructor when talking about objects?

    - by user104971
    I was watching this keynote and Bjarne Stroustrup (Creator of C++) claims that he hadn't yet invented the words constructor and destructor yet when he was giving an example of RAII. http://www.youtube.com/watch?v=IYBLXBJr0HU I know the concept of construction and destruction has been around a lot longer (even in C, a function that allocates and returns a struct and then a function that frees it etc.), but was Bjarne really the first to invent the terms?

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  • Deleting a game object

    - by Balls
    I tried doing this but it cause an access violation. void GameObjectFactory::Update() { for( std::list<GameObject*>::iterator it=gameObjectList.begin() ..... (*it)->Update(); } void Bomb::Update() { if( time == 2.0f ) { gameObjectFactory->Remove( this ); } } void GameObjectFactory::Remove( ... ) { gameObjectList.remove( ... ); } My thoughts would be to mark the object to be dead then let the factory handle it the on next frame for deletion. Is it the best and fastest way? What do you think?

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  • A programmer who doesn't get to program - where to turn? [closed]

    - by Just an Anon
    I'm in my mid 20's, and have been working as a full time programmer / developer for the last ~6 years, with several years of part-time freelancing before this, and three straight years of freelancing in the middle of this short career. I work mostly with PHP and the Drupal framework. By and large, I focus on programming custom pieces of functionality; these, of course, vary greatly from project to project. I've got years of solid experience with OOP (have done some Java & C# years ago, too) including intensive experience with front-end development, and even some design work. I've lead small teams (2-4 people) of developers. And of course, given the large amount of freelancing, I've got decent project- & client-management skills. My problem is staying motivated at any place of employment. In the time mentioned I've worked (full-time) at six local companies. The longest I've stayed at any company was just over a year. I find that I'll get hired and be very excited and motivated for the first few months, but the work quickly gets "stale." By that I mean that the interesting components (ie. the programming) get done, and the rest of the work turns into boring cleanup (move a button, add text, change colours, add a field). I don't get challenged, and I don't feel like I'm learning anything new. This happens repeatedly time and time again, and I always end up leaving for either a new opportunity, or to freelance. I'm wondering if perhaps I've painted myself into a corner with the rather niche work market (although with very high demand and good compensation) and need to explore other career choices. Another possibility is that I may be choosing the wrong places of employment, mostly small agencies, and need to look into working for a larger, more established firm. I find programming, writing code, and architecting solutions very rewarding. When I'm working on an interesting problem I lose all sense of time and 14-16 hours can fly by like minutes. I get the same exciting feeling when I'm doing high-level planning of a complex system, breaking up the work and figuring out how everything will tie-in together. I absolutely hate doing small, "stupid" changes that pose no challenge, yet seem to make up more and more of my work. I want to find a workplace where I will get to work on such tasks, be challenged, and improve in all areas of product development. This maybe a programming job, management, architecture of desktop apps, or may be managing a taco stand on a beach in Mexico - I don't know, and I need some advice and real-world feedback. What are some job areas worth exploring? The requirements are fairly simple: working with computers interacting with others challenging decent pay (I'm making just short of 90k / year with a month of vacation & some benefits, and would like to stay in this range, but am willing to take a temporary cut in pay for a more interesting position) Any advice would be much appreciated!

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  • Should the 12-String be in it's own class and why? Java

    - by MayNotBe
    This is my first question here. I will amend it as instructed. This is regarding a homework project in my first Java programming class (online program). The assignment is to create a "stringed instrument" class using (among other things) an array of String names representing instrument string names ("A", "E", etc). The idea for the 12-string is beyond the scope of the assignment (it doesn't have to be included at all) but now that I've thought of it, I want to figure out how to make it work. Part of me feels like the 12-String should have it's own class, but another part of me feels that it should be in the guitar class because it's a guitar. I suppose this will become clear as I progress but I thought I would see what kind of response I get here. Also, why would they ask for a String[] for the instrument string names? Seems like a char[] makes more sense. Thank you for any insight. Here's my code so far (it's a work in progress): public class Guitar { private int numberOfStrings = 6; private static int numberOfGuitars = 0; private String[] stringNotes = {"E", "A", "D", "G", "B", "A"}; private boolean tuned = false; private boolean playing = false; public Guitar(){ numberOfGuitars++; } public Guitar(boolean twelveString){ if(twelveString){ stringNotes[0] = "E, E"; stringNotes[1] = "A, A"; stringNotes[2] = "D, D"; stringNotes[3] = "G, G"; stringNotes[4] = "B, B"; stringNotes[5] = "E, E"; numberOfStrings = 12; } } public int getNumberOfStrings() { return numberOfStrings; } public void setNumberOfStrings(int strings) { if(strings == 12 || strings == 6) { if(strings == 12){ stringNotes[0] = "E, E"; stringNotes[1] = "A, A"; stringNotes[2] = "D, D"; stringNotes[3] = "G, G"; stringNotes[4] = "B, B"; stringNotes[5] = "E, E"; numberOfStrings = strings; } if(strings == 6) numberOfStrings = strings; }//if else System.out.println("***ERROR***Guitar can only have 6 or 12 strings***ERROR***"); } public void getStringNotes() { for(int i = 0; i < stringNotes.length; i++){ if(i == stringNotes.length - 1) System.out.println(stringNotes[i]); else System.out.print(stringNotes[i] + ", "); }//for }

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  • Multiple parameters vs single parameter(object with multiple properties)

    - by Shwetanka
    I have an Entity Student with following properties - (name, joinedOn, birthday, age, batch, etc.) and a function fetchStudents(<params>). I want to fetch students based on multiple filters. In my method I have two ways to pass filters. Pass all filters as params to the method Make a class StudentCriteria with filters as fields and then pass the object of this class While working in java I always go with the second option but recently I'm working in php and I was advised to go with the first way. I am unable to figure out which way is better in maintaining the code, reusability and performance wise. Thanks.

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  • PHP class data implementation

    - by Bakanyaka
    I'm studying OOP PHP and have watched two tutorials that implement user login\registration system as an example. But implementation varies. Which way will be more correct one to work with data such as this? Load all data retrieved from database as array into a property called something like _data on class creation and further methods operate with this property Create separate properties for each field retrieved from database, on class creation load all data fields into respective properties and operate with that properties separately? Then let's say I want to create a method that returns a list of all users with their data. Which way is better? Method that returns just an array of userdata like this: Array([0]=>array([id] => 1, [username] => 'John', ...), [1]=>array([id] => 2, [username] => 'Jack', ...), ...) Method that creates a new instance of it's class for each user and returns an array of objects

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  • Is "If a method is re-used without changes, put the method in a base class, else create an interface" a good rule-of-thumb?

    - by exizt
    A colleague of mine came up with a rule-of-thumb for choosing between creating a base class or an interface. He says: Imagine every new method that you are about to implement. For each of them, consider this: will this method be implemented by more than one class in exactly this form, without any change? If the answer is "yes", create a base class. In every other situation, create an interface. For example: Consider the classes cat and dog, which extend the class mammal and have a single method pet(). We then add the class alligator, which doesn't extend anything and has a single method slither(). Now, we want to add an eat() method to all of them. If the implementation of eat() method will be exactly the same for cat, dog and alligator, we should create a base class (let's say, animal), which implements this method. However, if it's implementation in alligator differs in the slightest way, we should create an IEat interface and make mammal and alligator implement it. He insists that this method covers all cases, but it seems like over-simplification to me. Is it worth following this rule-of-thumb?

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  • IXRepository and test problems

    - by Ridermansb
    Recently had a doubt about how and where to test repository methods. Let the following situation: I have an interface IRepository like this: public interface IRepository<T> where T: class, IEntity { IQueryable<T> Query(Expression<Func<T, bool>> expression); // ... Omitted } And a generic implementation of IRepository public class Repository<T> : IRepository<T> where T : class, IEntity { public IQueryable<T> Query(Expression<Func<T, bool>> expression) { return All().Where(expression).AsQueryable(); } } This is an implementation base that can be used by any repository. It contains the basic implementation of my ORM. Some repositories have specific filters, in which case we will IEmployeeRepository with a specific filter: public interface IEmployeeRepository : IRepository<Employee> { IQueryable<Employee> GetInactiveEmployees(); } And the implementation of IEmployeeRepository: public class EmployeeRepository : Repository<Employee>, IEmployeeRepository // TODO: I have a dependency with ORM at this point in Repository<Employee>. How to solve? How to test the GetInactiveEmployees method { public IQueryable<Employee> GetInactiveEmployees() { return Query(p => p.Status != StatusEmployeeEnum.Active || p.StartDate < DateTime.Now); } } Questions Is right to inherit Repository<Employee>? The goal is to reuse code once all implementing IRepository already been made. If EmployeeRepository inherit only IEmployeeRepository, I have to literally copy and paste the code of Repository<T>. In our example, in EmployeeRepository : Repository<Employee> our Repository lies in our ORM layer. We have a dependency here with our ORM impossible to perform some unit test. How to create a unit test to ensure that the filter GetInactiveEmployees return all Employees in which the Status != Active and StartDate < DateTime.Now. I can not create a Fake/Mock of IEmployeeRepository because I would be testing? Need to test the actual implementation of GetInactiveEmployees. The complete code can be found on Github

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  • Vertex Array Object (OpenGL)

    - by user5140
    I've just started out with OpenGL I still haven't really understood what Vertex Array Objects are and how they can be employed. If Vertex Buffer Object are used to store vertex data (such as their positions and texture coordinates) and the VAOs only contain status flags, where can they be used? What's their purpose? As far as I understood from the (very incomplete and unclear) GL Wiki, VAOs are used to set the flags/status for every vertex, following the order described in the Element Array Buffer, but the wiki was really ambiguous about it and I'm not really sure about what VAOs really do and how I could employ them.

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  • Which order to define getters and setters in? [closed]

    - by N.N.
    Is there a best practice for the order to define getters and setters in? There seems to be two practices: getter/setter pairs first getters, then setters (or the other way around) To illuminate the difference here is a Java example of getter/setter pairs: public class Foo { private int var1, var2, var3; public int getVar1() { return var1; } public void setVar1(int var1) { this.var1 = var1; } public int getVar2() { return var2; } public void setVar2(int var2) { this.var2 = var2; } public int getVar3() { return var3; } public void setVar3(int var3) { this.var3 = var3; } } And here is a Java example of first getters, then setters: public class Foo { private int var1, var2, var3; public int getVar1() { return var1; } public int getVar2() { return var2; } public int getVar3() { return var3; } public void setVar1(int var1) { this.var1 = var1; } public void setVar2(int var2) { this.var2 = var2; } public void setVar3(int var3) { this.var3 = var3; } } I think the latter type of ordering is clearer both in code and in class diagrams but I do not know if that is enough to rule out the other type of ordering.

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  • [PHP] Making a good singleton registry class structure which hold your objects

    - by Saif Bechan
    I am working on a web application in PHP. I have a singleton class called registry. This class will hold all the objects i need throughout my application, such as loader classes, template classes, database, classes, etc. When an object of the registry class is created I send it an array with the classes it need to load: // Create the registry $registry = registry::singleton(); // Store those core objects $registry->storeObjects(Array('session','db','page','template','errors')); In this example I only put some of the classes, to get the basic idea. Now I have some classes in the registry that use each other. For example the 'errors' object uses the 'page' object. Now I was wondering if it is a good practice to make an instance of the registry object in the errors object. Like this; class errors{ private $registry; public function __construct(){ $this->registry = registry::singleton(); } } So there is an instance of the registry object, inside an object of the registry object. This does not sound like a good idea to me. Anyone have a suggestion how to model such a thing?

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  • Javascript "this" variable confusion

    - by Assaf M
    Hi I am currently reading the book "Javascript: The Good Parts" and was playing with Functions. I produced a test script to test some properties and I am somewhat confused by the results. Here is the code: <h3>Object</h3> <div style="padding-left: 10px;"> <script type="text/javascript"> function outterF() { document.writeln("outterF.this = " + this + "<br>"); function innerF() { document.writeln("innerF.this = " + this + "<br>"); return this; }; var inner = innerF(); return this; } document.writeln("<b>From Inside:</b><br>"); var outF = outterF(); var inF = outF.inner; document.writeln("<br>"); document.writeln("<b>From Outside:</b><br>"); document.writeln("outterF.this = " + outF + "<br>"); document.writeln("innerF.this = " + inF + "<br>"); </script> </div> Result is: Object From Inside: outterF.this = [object Window] innerF.this = [object Window] From Outside: outterF.this = [object Window] innerF.this = undefined Notice that outF.inner returns "undefined", is that some kind of a language bug? Obviously, outF.inner points to Window object that has nothing to do with my object but shouldn't it be at least pointing to a Function object instead? Thanks -Assaf

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  • C# - Calling ToString() on a Reference Type

    - by nfplee
    Given two object arrays I need to compare the differences between the two (when converted to a string). I've reduced the code to the following and the problem still exists: public void Compare(object[] array1, object[] array2) { for (var i = 0; i < array1.Length; i++) { var value1 = GetStringValue(array1[i]); var value2 = GetStringValue(array2[i]); } } public string GetStringValue(object value) { return value != null && value.ToString() != string.Empty ? value.ToString() : ""; } The code executes fine no matter what object arrays I throw at it. However if one of the items in the array is a reference type then somehow the reference is updated. This causes issues later. It appears that this happens when calling ToString() against the object reference. I have updated the GetStringValue method to the following (which makes sure the object is either a value type or string) and the problem goes away. public string GetStringValue(object value) { return value != null && (value.GetType().IsValueType || value is string) && value.ToString() != string.Empty ? value.ToString() : ""; } However this is just a temporary hack as I'd like to be able to override the ToString() method on my reference types and compare them as well. I'd appreciate it if someone could explain why this is happening and offer a potential solution. Thanks

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  • Java: Comparing a class with another within that class using a my own .equals

    - by user1670252
    I am making a method .equals replacing the equals method used. It accepts a object. I want it to check if that object equals the class that runs the .equals class. I know I want to compare all the private methods I have to that object. Is there a way to do this without making another private class to get the private variables from the object? How do I do this to compare equality not identity? I am stuck on this. Do i have to use == to compare? Also looking online i see others use recursion. If this is the way i have to do it can you show and explain it to me? so an example i have public boolean equals(Object o) { this is in a class we will call bobtheBuilder (first thing to pop in my head) I want to check if the object o is equal to the class he has private object array and a private int. I assume I want to check if the array and int of this class equal the array and int of the object.

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  • Why can't I set a layout for a page in a QStackedWidget in designer?

    - by cppguy
    Steps to reproduce in designer for Qt 4.8.0 I create a new dialog form in Qt Designer I add a QStackedWidget to the dialog I set the layout of the dialog to make the stacked layout size with the dialog I add a few controls to page one in the stacked widget I select the first page in the stacked widget in the right hand tree view of controls The icon next to that page (which is a QWidget) shows the page is missing a layout When I click one of the layout buttons above, it doesn't change the layout of the page QWidget, it changes the layout of the dialog even though I had explicitly selected the page. Is this a bug in designer? Am I missing something? I really don't want to add the layouts programatically as that prevents me from being able to layout the pages in designer in the same .ui file

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  • Core Data managed object context thread synchronisation

    - by Ben Reeves
    I'm have an issue where i'm updating a many-to-many relationship in a background thread, which works fine in that threa, but when I send the object back to the main thread the changes do not show. If I close the app and reopen the data is saved fine and the changes show on the main thread. Also using [context lock] instead of a different managed object context works fine. I have tried NSManagedObjectContext: - (BOOL)save:(NSError **)error; - (void)refreshObject:(NSManagedObject *)object mergeChanges:(BOOL)flag; at different stages throughout the process but it doesn't seem to help. My core data code uses the following getter to ensure any operations are thread safe: - (NSManagedObjectContext *) managedObjectContext { NSThread * thisThread = [NSThread currentThread]; if (thisThread == [NSThread mainThread]) { //Main thread just return default context return managedObjectContext; } else { //Thread safe trickery NSManagedObjectContext * threadManagedObjectContext = [[thisThread threadDictionary] objectForKey:CONTEXT_KEY]; if (threadManagedObjectContext == nil) { threadManagedObjectContext = [[[NSManagedObjectContext alloc] init] autorelease]; [threadManagedObjectContext setPersistentStoreCoordinator: [self persistentStoreCoordinator]]; [[thisThread threadDictionary] setObject:threadManagedObjectContext forKey:CONTEXT_KEY]; } return threadManagedObjectContext; } } and when I pass object between threads i'm using -(NSManagedObject*)makeSafe:(NSManagedObject*)object { if ([object managedObjectContext] != [self managedObjectContext]) { NSError * error = nil; object = [[self managedObjectContext] existingObjectWithID:[object objectID] error:&error]; if (error) { NSLog(@"Error makeSafe: %@", error); } } return object; } Any help appreciated

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  • Html.DropDownListFor<> and complex object in ASP.NET MVC2

    - by dagda1
    Hi, I am looking at ASP.NET MVC2 and trying to post a complex object using the new EditorFor syntax. I have a FraudDto object that has a FraudCategory child object and I want to set this object from the values that are posted from the form. Posting a simple object is not a problem but I am struggling with how to handle complex objects with child objects. I have the following parent FraudDto object whcih I am binding to on the form: public class FraudDto { public FraudCategoryDto FraudCategory { get; set; } public List<FraudCategoryDto> FraudCategories { get; private set; } public IEnumerable<SelectListItem> FraudCategoryList { get { return FraudCategories.Select(t => new SelectListItem { Text = t.Name, Value = t.Id.ToString() }); } The child FraudCategoryDto object looks like this: public class FraudCategoryDto { public int Id { get; set; } public string Name { get; set; } } On the form, I have the following code where I want to bind the FraudCategoryDto to the dropdown. The view is of type ViewPage: <td class="tac"> <strong>Category:</strong> </td> <td> <%= Html.DropDownListFor(x => x.FraudCategory, Model.FraudTypeList)%> </td> I then have the following controller code: [HttpPost] public virtual ViewResult SaveOrUpdate(FraudDto fraudDto) { return View(fraudDto); } When the form is posted to the server, the FraudCategory property of the Fraud object is null. Are there any additional steps I need to hook up this complex object? Cheers Paul

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  • C++ Program Flow: Sockets in an Object and the Main Function

    - by jfm429
    I have a rather tricky problem regarding C++ program flow using sockets. Basically what I have is this: a simple command-line socket server program that listens on a socket and accepts one connection at a time. When that connection is lost it opens up for further connections. That socket communication system is contained in a class. The class is fully capable of receiving the connections and mirroring the data received to the client. However, the class uses UNIX sockets, which are not object-oriented. My problem is that in my main() function, I have one line - the one that creates an instance of that object. The object then initializes and waits. But as soon as a connection is gained, the object's initialization function returns, and when that happens, the program quits. How do I somehow wait until this object is deleted before the program quits? Summary: main() creates instance of object Object listens Connection received Object's initialization function returns main() exits (!) What I want is for main() to somehow delay until that object is finished with what it's doing (aka it will delete itself) before it quits. Any thoughts?

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  • Listview Row Overlap Problem

    - by rgrandy
    I just updated my app and I am getting some odd complaints from people who update it. I am only getting complaints from people with non-stock android phones (phones that manufacturers have modified...HTC phones, cliq, pulse, etc), other phones like the Droid, Nexus work fine. My app (Photo Frame Deluxe) has a list in it with a Image View, Text View, View (spacer) and checkbox, all in a row. What happens on the affected phones is that the rows start overlapping and it cuts the top half of everything off. My layout code for this is below, I am pulling my hair out on this, what might I have wrong in this layout. Why does this work on some phones and not on others? Any help would be appreciated. Row Layout: <?xml version="1.0" encoding="UTF-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="wrap_content" android:orientation="horizontal"> <ImageView android:id="@+id/photorowIcon" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_gravity="center_vertical" android:paddingTop="10dp" android:paddingBottom="10dp" android:paddingRight="5dp" /> <TextView android:id="@+id/photorowText" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_gravity="center_vertical" /> <View android:layout_width="0px" android:layout_height="wrap_content" android:layout_weight="1"/> <CheckBox android:id="@+id/photorowCheckBox" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_gravity="center_vertical" android:focusable="false" android:focusableInTouchMode="false" /> </LinearLayout> Layout Row is inserted in: <?xml version="1.0" encoding="UTF-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="fill_parent" android:orientation="vertical"> <LinearLayout android:layout_width="fill_parent" android:layout_height="wrap_content" android:background="@drawable/title1_gradient" android:orientation="vertical"> <TextView android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="Select Photos to Display:" android:textSize="20sp" android:textStyle="bold" android:textColor="#FFFFFFFF" android:paddingLeft="5dp" android:paddingRight="5dp" android:paddingTop="5dp" /> <TextView android:layout_width="fill_parent" android:layout_height="wrap_content" android:id="@+id/folderName" android:textSize="15sp" android:textStyle="bold" android:textColor="#FFFFFFFF" android:paddingLeft="5dp" android:paddingRight="5dp" android:paddingBottom="5dp" /> <View android:layout_width="fill_parent" android:layout_height="1px" android:background="#406C6C6C"/> </LinearLayout> <ListView android:id="@android:id/list" android:layout_width="fill_parent" android:layout_height="0px" android:layout_weight="1" android:drawSelectorOnTop="false" android:paddingLeft="5dp" android:paddingRight="5dp" /> <LinearLayout android:layout_width="fill_parent" android:layout_height="wrap_content" android:orientation="vertical" android:layout_gravity="bottom"> <LinearLayout android:layout_width="fill_parent" android:layout_height="wrap_content" android:orientation="horizontal" android:layout_gravity="bottom" android:background="#FF6C6C6C" android:padding="5dp"> <Button android:layout_width="fill_parent" android:layout_height="wrap_content" android:id="@+id/ok" android:text="OK"/> </LinearLayout> </LinearLayout> </LinearLayout>

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  • [android] How to center buttons on screen horizontally and vertically plus equidistant apart?

    - by marc
    I've been racking my brain (android newbie here, so not hard to do) for awhile trying to figure out how to accomplish this: Desired Layout using a RelativeLayout or something other than AbsoluteLayout which is what this was created with. I'm coming from a Windows programming background where the device adjusts the 'absolute' positioning for you and GUI layout was a non-issue. The first layout works great in the emulator, but doesn't format for my Nexus One or any other screen that differs from the emulator size. I expected this because it's absolutely positioned, but haven't found a solution that will format correctly for different screen sizes. My goal is to have the layout work for different screen sizes and in portrait / landscape. Here's the Code that I'm currently using: [main.xml] <?xml version="1.0" encoding="utf-8"?> <AbsoluteLayout android:layout_width="fill_parent" android:layout_height="fill_parent" xmlns:android="http://schemas.android.com/apk/res/android" > <Button android:id="@+id/Button01" android:layout_width="188px" android:layout_height="100px" android:text="A" android:layout_y="50px" android:layout_x="65px" android:textSize="48sp"/> <Button android:id="@+id/Button02" android:layout_width="188px" android:layout_height="100px" android:text="B" android:layout_y="175px" android:layout_x="65px" android:textSize="48sp"/> <Button android:id="@+id/Button03" android:layout_width="188px" android:layout_height="100px" android:text="C" android:layout_y="300px" android:layout_x="65px" android:textSize="48sp"/> </AbsoluteLayout> Using tidbits from other questions here, I came up with this, it’s closer, but not there yet. <?xml version="1.0" encoding="utf-8"?> <TableLayout android:gravity="center" android:id="@+id/widget49" android:layout_width="fill_parent" android:layout_height="fill_parent" android:orientation="vertical" xmlns:android="http://schemas.android.com/apk/res/android" > <Button android:id="@+id/Button01" android:layout_width="0dip" android:layout_weight="1" android:text="A" android:textSize="48sp"/> <Button android:id="@+id/Button02" android:layout_width="0dip" android:layout_weight="1" android:text="B" android:textSize="48sp"/> <Button android:id="@+id/Button03" android:layout_width="0dip" android:layout_weight="1" android:text="C" android:textSize="48sp"/> </TableLayout> Here’s a picture of the TableLayout: Another Attempt Any help / guidance would be greatly appreciated.

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  • PagerView overlapping PagerTabStrip / PagerTitleStrip

    - by user1256169
    I've been trying for about a week to get my PagerView not to overlap the TitleStrip. I've tried absolutely everything I can think of, and one StackOverflow question that looked like the same question, had an answer that wasn't applicable. It appears that both the PagerTitleStrip and the TextView start at 0,0 (left,top) Any help would be appreciated. Note that I can't use any XML (inc Layout.xml) so it's all done programatically. Here's a full working example of my problem: package com.example.projname; import android.app.Activity; import android.os.Bundle; import android.support.v4.view.PagerAdapter; import android.support.v4.view.PagerTabStrip; import android.support.v4.view.ViewPager; import android.view.Gravity; import android.view.View; import android.view.ViewGroup; import android.view.ViewGroup.LayoutParams; import android.widget.TextView; public class MainActivity extends Activity { @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); MyPagerAdapter myPagerAdapter = new MyPagerAdapter(); PagerTabStrip myPagerTabStrip = new PagerTabStrip(this); myPagerTabStrip.setGravity(Gravity.TOP); ViewPager viewPager = new ViewPager(this); viewPager.addView(myPagerTabStrip, LayoutParams.MATCH_PARENT, LayoutParams.WRAP_CONTENT); viewPager.setAdapter(myPagerAdapter); setContentView(viewPager); } class MyPagerAdapter extends PagerAdapter { public final String[] Titles = { "Title One", "Title Two", "Title Three", "Title Four", "Title Five" }; @Override public int getCount() { return Titles.length; } @Override public boolean isViewFromObject(View view, Object object) { return (view == object); } @Override public CharSequence getPageTitle(int position) { return Titles[position]; } @Override public Object instantiateItem(ViewGroup container, int position) { TextView textView = new TextView(getApplicationContext()); String myString = new String("Page " + (position + 1) + "\r\n"); textView.setText(myString + myString + myString + myString + myString + myString); container.addView(textView); return textView; } @Override public void destroyItem(ViewGroup container, int position, Object object) { container.removeView((View) object); } } } Edit: Adding a screenshot of the problem:

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  • Website column width

    - by keks
    Hi, I am interested what column widths you would suggest for two-column and three-column websites. For example if we consider two-column layout (total width 1000px), some possible widths would be: 900-100, 800-200, 750-250, 700-300, 600-400. Which layout is best for usability, possible ad placements, widget integration?

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