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  • PHP session corrupt

    - by Baversjo
    Using symfony framework 1.4 I have created a website. I'm using sfguard for authentication. Now, this is working great on WAMP (windows). I can login to several accounts on different browsers and use the website. I have ubuntu server 9.10 running apache (everything up to date and default configuration). On my server, when I login to the website in one browser it works great. When I on my other computer login with another user account on the public website, the login is successful. But when I refresh/go to another page the first user is shown as logged in instead! Also, when I press logout, It's not showing that I'm logged out after page load. When I press f5 again I'm logged out. As mentioned, all this works as expected on my local installation. I'm thinking there something wrong with my PHP session configuration on my ubuntu server, but I've never touched it.. Please help me. This is a school project and I'm presenting it today :(

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  • Facebook API - Detect if session is active OR NOT active

    - by Tom Doe
    I'm sure I'm simply overlooking something in the Facebook API docs. Basically, after I've loaded the FB Graph, I need to know if the session is active... I cannot simply assume they're logged out and simply re-render if they're logged in once the 'auth.statusChange' event is triggered. I need to know right off the bat. Below is the code that I've used. Most importantly the FB.getLoginStatus/getAuthResponse/getAccessToken don't work like I'd expect; essentially where it indicates, when invoked, whether they're logged in or out. (function(d) { // Create fb-root var fb_root = document.createElement('div'); fb_root.id = "fb-root"; document.getElementsByTagName('body')[0].appendChild( fb_root ); // Load FB Async var js, id = 'facebook-jssdk', ref = d.getElementsByTagName('script')[0]; if (d.getElementById(id)) {return;} js = d.createElement('script'); js.id = id; js.async = true; js.src = "//connect.facebook.net/en_US/all.js"; ref.parentNode.insertBefore(js, ref); // App config-data var config = { appId : XXXX, cookie: true, status: true, frictionlessRequests: true }; window.fbAsyncInit = function() { // This won't work. // I can't assume they're logged out and rely on this to tell me they're logged in. FB.Event.subscribe('auth.statusChange', function(response) {}); // Init FB.init(config); // These do not inidicate if the user is logged out :( FB.getLoginStatus(function(response) { }); FB.getAuthResponse(function(response) { }); FB.getAccessToken(function(response) { }); }; }(document)); Any help is much appreciated. :)

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  • PHP session token can be used multipletimes?

    - by kornesh
    I got page A which is a normal HTML page and page which is an AJAX response page. And I want to prevent CSRF attacks by tokens. Lets say I use this method for an autocomplete form, is it possible to use same token multiple times (of course the session is only set one time) because i tired this method but the validation keep failing after the first suggestion (obviously the token has changed, somehow) page A <?php session_start(); $token = md5(uniqid(rand(), TRUE)); $_SESSION['token'] = $token; ?> <input id="token" value="<?php echo $token; ?>" type="hidden"></input> <input id="autocomplete" placeholder="Type something"></input> .... The form is autosubmitted every time theres a change using Jquery. page B <?php session_start(); if($_REQUEST['token'] == $_SESSION['token']){ echo 'Im working fine'; } ?>

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  • login script in php using session variables

    - by kracekumar
    ? username: '; } else { $user=$_POST['user']; $query="select name from login where name='$user'"; $result=mysql_query($query) or die(mysql_error()); $rows=mysql_num_rows($result)or die(mysql_error()); session_start(); //echo "results"; $username=mysql_fetch_array($result) or die(mysql_error()); $fields=mysql_num_fields($result) or die(mysql_error()); echo "username:$username[0]"; $_SESSION['username']=$username[0]; $sesion_username=$_SESSION['username']; //echo "rows:$rows"." "."fields:$fields"; echo""."username:$sesion_username"; } ? i wanted to create a site where user can login and upload their details depending on their user name have stored their details in a database,the problem i am facing is two people 'a' and 'b' login one after other session_variable $_SESSION['username'] will have 'b's' username ,so i can't display 'a's' details now. . . . what i want to achieve is when a user logins in i want to store his name and other details in session variable and navigate him according and display his details

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  • globals and locals in python exec()

    - by hawkettc
    Hi, I'm trying to run a piece of python code using exec. my_code = """ class A(object): pass print 'locals: %s' % locals() print 'A: %s' % A class B(object): a_ref = A """ global_env = {} local_env = {} my_code_AST = compile(my_code, "My Code", "exec") exec(my_code_AST, global_env, local_env) print local_env which results in the following output locals: {'A': <class 'A'>} A: <class 'A'> Traceback (most recent call last): File "python_test.py", line 16, in <module> exec(my_code_AST, global_env, local_env) File "My Code", line 8, in <module> File "My Code", line 9, in B NameError: name 'A' is not defined However, if I change the code to this - my_code = """ class A(object): pass print 'locals: %s' % locals() print 'A: %s' % A class B(A): pass """ global_env = {} local_env = {} my_code_AST = compile(my_code, "My Code", "exec") exec(my_code_AST, global_env, local_env) print local_env then it works fine - giving the following output - locals: {'A': <class 'A'>} A: <class 'A'> {'A': <class 'A'>, 'B': <class 'B'>} Clearly A is present and accessible - what's going wrong in the first piece of code? I'm using 2.6.5, cheers, Colin * UPDATE 1 * If I check the locals() inside the class - my_code = """ class A(object): pass print 'locals: %s' % locals() print 'A: %s' % A class B(object): print locals() a_ref = A """ global_env = {} local_env = {} my_code_AST = compile(my_code, "My Code", "exec") exec(my_code_AST, global_env, local_env) print local_env Then it becomes clear that locals() is not the same in both places - locals: {'A': <class 'A'>} A: <class 'A'> {'__module__': '__builtin__'} Traceback (most recent call last): File "python_test.py", line 16, in <module> exec(my_code_AST, global_env, local_env) File "My Code", line 8, in <module> File "My Code", line 10, in B NameError: name 'A' is not defined However, if I do this, there is no problem - def f(): class A(object): pass class B(object): a_ref = A f() print 'Finished OK' * UPDATE 2 * ok, so the docs here - http://docs.python.org/reference/executionmodel.html 'A class definition is an executable statement that may use and define names. These references follow the normal rules for name resolution. The namespace of the class definition becomes the attribute dictionary of the class. Names defined at the class scope are not visible in methods.' It seems to me that 'A' should be made available as a free variable within the executable statement that is the definition of B, and this happens when we call f(), but not when we use exec(). This can be more easily shown with the following - my_code = """ class A(object): pass print 'locals in body: %s' % locals() print 'A: %s' % A def f(): print 'A in f: %s' % A f() class B(object): a_ref = A """ which outputs locals in body: {'A': <class 'A'>} A: <class 'A'> Traceback (most recent call last): File "python_test.py", line 20, in <module> exec(my_code_AST, global_env, local_env) File "My Code", line 11, in <module> File "My Code", line 9, in f NameError: global name 'A' is not defined So I guess the new question is - why aren't those locals being exposed as free variables in functions and class definitions - it seems like a pretty standard closure scenario.

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  • Changes to data inside class not being shown when accessed from outside class.

    - by Hypatia
    I have two classes, Car and Person. Car has as one of its members an instance of Person, driver. I want to move a car, while keeping track of its location, and also move the driver inside the car and get its location. However, while this works from inside the class (I have printed out the values as they are calculated), when I try to access the data from main, there's nothing there. I.e. the array position[] ends up empty. I am wondering if there is something wrong with the way I have set up the classes -- could it be a problem of the scope of the object? I have tried simplifying the code so that I only give what is necessary. Hopefully that covers everything that you would need to see. The constructer Car() fills the offset array of driver with nonzero values. class Car{ public: Container(float=0,float=0,float=0); ~Container(); void move(float); void getPosition(float[]); void getDriverPosition(float[]); private: float position[3]; Person driver; float heading; float velocity; }; class Person{ public: Person(float=0,float=0,float=0); ~Person(); void setOffset(float=0,float=0,float=0); void setPosition(float=0,float=0,float=0); void getOffset(float[]); void getPosition(float[]); private: float position[3]; float offset[3]; }; Some of the functions: void Car::move(float time){ float distance = velocity*time; location[0] += distance*cos(PI/2 - heading); location[1] += distance*sin(PI/2 - heading); float driverLocation [3]; float offset[3]; driver->getOffset(offset); for (int i = 0; i < 3; i++){ driverLocation[i] = offset[i] + location[i]; } } void Car::getDriverPosition(float p[]){ driver.getPosition(p); } void Person::getPosition(float p[]){ for (int i = 0; i < 3; i++){ p[i] = position[i]; } } void Person::getOffset(float o[]){ for (int i = 0; i < 3; i++){ o[i] = offset[i]; } } In Main: Car * car = new Car(); car->move(); float p[3]; car->getDriverPosition(p); When I print driverLocation[] inside the move() function, I have actual nonzero values. When I print p[] inside main, all I get are zeros.

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  • Php static variables across sessions

    - by pistacchio
    Hi, In ASP.NET if I declare a variable (or object) static (or if I make a singleton) I can have it persist across multiple sessions of multiple users (it it registered in a server scope) so that I don't have to initialize it at every request. Is there such a feature in PHP? Thanks

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  • Javascript/ajax/php question: sending from server to client works, sending from client to server fai

    - by Jeroen Willemsen
    Hey All, Sorry for reposting(Admins, please delete the other one!). since you guys have been a great help, I was kinda hoping that you could help me once again while having the following question: I am currently trying to work with AJAX by allowing a managerclass in PHP to communicate via an XmlHttpobject with the javascript on the clientside. However, I can send something to the client via JSON, but I cannot read it at the clientside. In fact I am getting the error that the "time" is an undefined index in Session. So I was wondering: what am I doing wrong? The javascriptcode for Ajax: <script type="text/javascript"> var sendReq = GetXmlHttpObject(); var receiveReq = GetXmlHttpObject(); var JSONIn = 0; var JSONOut= 0; //var mTimer; //function to retreive xmlHTTp object for AJAX calls (correct) function GetXmlHttpObject() { var xmlHttp=null; try { // Firefox, Opera 8.0+, Safari xmlHttp=new XMLHttpRequest(); } catch (e) { // Internet Explorer try { xmlHttp=new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { xmlHttp=new ActiveXObject("Microsoft.XMLHTTP"); } } return xmlHttp; } //Gets the new info from the server function getUpdate() { if (receiveReq.readyState == 4 || receiveReq.readyState == 0) { receiveReq.open("GET", "index.php?json="+JSONIn+"&sid=$this->session", true); receiveReq.onreadystatechange = updateState; receiveReq.send(null); } } //send a message to the server. function sendUpdate(JSONstringsend) { JSONOut=JSONstringsend; if (sendReq.readyState == 4 || sendReq.readyState == 0) { sendReq.open("POST", "index.php?json="+JSONstringsend+"&sid=$this->session", true); sendReq.setRequestHeader('Content-Type','application/x-www-form-urlencoded'); alert(JSONstringsend); sendReq.onreadystatechange = updateCycle; sendReq.send(JSONstringsend); } } //When data has been send, update the page. function updateCycle() { getUpdate(); } function updateState() { if (receiveReq.readyState == 4) { // JSONANSWER gets here (correct): var JSONtext = sendReq.responseText; // convert received string to JavaScript object (correct) alert(JSONtext); var JSONobject = JSON.parse(JSONtext); // updates date from the JSONanswer (correct): document.getElementById("dateview").innerHTML= JSONobject.date; } //mTimer = setTimeout('getUpdate();',2000); //Refresh our chat in 2 seconds } </script> The function that actually uses the ajax code: //datepickerdata $(document).ready(function(){ $("#datepicker").datepicker({ onSelect: function(dateText){ var JSONObject = {"date": dateText}; var JSONstring = JSON.stringify(JSONObject); sendUpdate(JSONstring); }, dateFormat: 'dd-mm-yy' }); }); </script> And the PHP code: private function handleReceivedJSon($json){ $this->jsonLocal=array(); $json=$_POST["json"]; $this->jsonDecoded= json_decode($json, true); if(isset($this->jsonDecoded["date"])){ $_SESSION["date"]=$this->jsonDecoded["date"]; $this->useddate=$this->jsonDecoded; } if(isset($this->jsonDecoded["logout"])){ session_destroy(); exit("logout"); } header("Last-Modified: " . gmdate( "D, d M Y H:i:s" ) . "GMT" ); header("Cache-Control: no-cache, must-revalidate" ); header("Pragma: no-cache" ); header("Content-Type: text/xml; charset=utf-8"); exit($json); }

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  • The Use-Case Driven Approach to Change Management

    - by Lauren Clark
    In the third entry of the series on OUM and PMI’s Pulse of the Profession, we took a look at the continued importance of change management and risk management. The topic of change management and OUM’s use-case driven approach has come up in few recent conversations. So I thought I would jot down a few thoughts on how the use-case driven approach aids a project team in managing the project’s scope. The use-case model is one of several tools in OUM that is used to establish and manage the project's scope.  Because a use-case model can be understood by both business and IT project team members, it can serve as a bridge for ongoing collaboration as well as a visual diagram that encapsulates all agreed-upon functionality. This makes it a vital artifact in identifying changes to the project’s scope. Here are some of the primary benefits of using the use-case model as part of the effort for establishing and managing project scope: The use-case model quickly communicates scope in a straightforward manner. All project stakeholders can have a common foundation for the decisions regarding architecture and design and how they relate to the project's objectives. Once agreed upon, the model can be put under change control and any updates to the model can then be quickly identified as potentially affecting the project’s scope.  Changes requested or discovered later in the project can be analyzed objectively for their impact on project's budget, resources and schedule. A modular foundation for the design of the software solution can be established in Elaboration.  This permits work to be divided up effectively and executed in so that the most important and riskiest use-cases can be tackled early in the project. The use-case model helps the team make informed decisions about implementation priorities, which allows effective allocation of limited project resources.  This is very helpful in not only managing scope, but in doing iterative and incremental planning which relies heavily on the ability to identify project priorities. Bottom line is that the use-case model gives the project team solid understanding of scope early in the project.  Combine this understanding with effective project management and communication and you have an effective tool for reducing the risk of overruns in budget and/or time due to out of control scope changes. Now that you’ve had a chance to read these thoughts on the use-case model and project scope, please let me know your feedback based on your experience.

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  • Why can't Java/C# implement RAII?

    - by mike30
    Question: Why can't Java/C# implement RAII? Clarification: I am aware the garbage collector is not deterministic. So with the current language features it is not possible for an object's Dispose() method to be called automatically on scope exit. But could such a deterministic feature be added? My understanding: I feel an implementation of RAII must satisfy two requirements: 1. The lifetime of a resource must be bound to a scope. 2. Implicit. The freeing of the resource must happen without an explicit statement by the programmer. Analogous to a garbage collector freeing memory without an explicit statement. The "implicitness" only needs to occur at point of use of the class. The class library creator must of course explicitly implement a destructor or Dispose() method. Java/C# satisfy point 1. In C# a resource implementing IDisposable can be bound to a "using" scope: void test() { using(Resource r = new Resource()) { r.foo(); }//resource released on scope exit } This does not satisfy point 2. The programmer must explicitly tie the object to a special "using" scope. Programmers can (and do) forget to explicitly tie the resource to a scope, creating a leak. In fact the "using" blocks are converted to try-finally-dispose() code by the compiler. It has the same explicit nature of the try-finally-dispose() pattern. Without an implicit release, the hook to a scope is syntactic sugar. void test() { //Programmer forgot (or was not aware of the need) to explicitly //bind Resource to a scope. Resource r = new Resource(); r.foo(); }//resource leaked!!! I think it is worth creating a language feature in Java/C# allowing special objects that are hooked to the stack via a smart-pointer. The feature would allow you to flag a class as scope-bound, so that it always is created with a hook to the stack. There could be a options for different for different types of smart pointers. class Resource - ScopeBound { /* class details */ void Dispose() { //free resource } } void test() { //class Resource was flagged as ScopeBound so the tie to the stack is implicit. Resource r = new Resource(); //r is a smart-pointer r.foo(); }//resource released on scope exit. I think implicitness is "worth it". Just as the implicitness of garbage collection is "worth it". Explicit using blocks are refreshing on the eyes, but offer no semantic advantage over try-finally-dispose(). Is it impractical to implement such a feature into the Java/C# languages? Could it be introduced without breaking old code?

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  • Sharing cookies/session from WebView to HttpClient doesn't work

    - by Toni Kanoni
    I know this question has been asked a hundred times, and I've read and tried for 2 hours now, but I can't find my error :-( I am trying to create a simple webbrowser and therefore have a webview, where I login on a site and get access to a picture area. With help of a DefaultHttpClient, I want to make it possible to download pictures in the secured area. Therefore I am trying to share the cookies from the webview and pass them on to the HttpClient, so that it is authenticated and able to download. But whatever I try and do, I always get a 403 response back... Basically the steps are the following: 1) Enter URL, webview loads website 2) Enter login details in a form 3) Navigate to picture and long hold for context menu 4) Retrieve the image URL and pass it on to AsynTask for downloading Here's the code of the AsyncTask with the Cookie stuff: protected String doInBackground(String... params) { //params[0] is the URL of the image try { CookieManager cookieManager = CookieManager.getInstance(); String c = cookieManager.getCookie(new URL(params[0]).getHost()); BasicCookieStore cookieStore = new BasicCookieStore(); BasicHttpContext localContext = new BasicHttpContext(); localContext.setAttribute(ClientContext.COOKIE_STORE, cookieStore); String[] cookieParts = null; String cookies[] = null; cookies = c.split(";"); for(int i=0;i<cookies.length;i++) { cookieParts = cookies[i].split("="); BasicClientCookie sessionCookie = new BasicClientCookie(cookieParts[0].trim(), cookieParts[1].trim()); sessionCookie.setDomain(new URL(params[0]).getHost()); cookieStore.addCookie(sessionCookie); } DefaultHttpClient httpClient = new DefaultHttpClient(); httpClient.setCookieStore(cookieStore); HttpGet pageGet = new HttpGet(new URL(params[0]).toURI()); HttpResponse response = httpClient.execute(pageGet, localContext); if(response.getStatusLine().getStatusCode() == HttpStatus.SC_OK) -- NEVER Happens, always get 403 .) One of the problems is that the webview saves some cookies for the host *www.*example.com, but the image-URL to download (params[0]) is *static.*example.com. The line cookieManager.getCookie(new URL(params[0]).getHost()); returns null, because there is no cookie for static.example.com, but only for www.example.com. .) When I manually say cookieManager.getCookie("www.example.com"); I get some cookies back, which I add to the HttpClient cookie store: There are 5 cookies added - testcookie = 0 - PHPSESSID = 320947238someGibberishSessionId - email = [email protected] - pass = 32423te32someEncodedPassGibberish - user = 345542 So although these cookies, a session ID and other stuff, get added to the HttpClient, it never get's through to download an image. Im totally lost... though I guess that it either has something to do with the cookies domains, or that Im still missing other cookies. But from where the heck should I know which cookies exist in the webview, when I have to specify a specific URL to get a cookie back?? :-( Any advice?

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  • How do you hide/show UISearchBar's scope bar with animation?

    - by zekel
    I want to show no scope bar when the table is empty (before the search bar edits for the first time), no scope bar when it's editing, and finally show it when editing done. I know about the UISearchBarDelegate protocol, but I don't know how to show/hide the scope bar with animation. I know UISearchBar has setShowsScopeBar:, but no setShowsScopeBar:animated: the way it does for setShowsCancelButton:animated.

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  • How are exceptions allocated on the stack caught beyond their scope?

    - by John Doe
    In the following code, the stack-based variable 'ex' is thrown and caught in a function beyond the scope in which ex was declared. This seems a bit strange to me, since (AFAIK) stack-based variables cannot be used outside the scope in which they were declared (the stack is unwound). void f() { SomeKindOfException ex(...); throw ex; } void g() { try { f(); } catch (SomeKindOfException& ex) { //Handling code... } } I've added a print statement to SomeKindOfException's destructor and it shows that ex is destructed once it goes out of scope in f() but then it's caught in g() and destructed again once it goes out of scope there as well. Any help?

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  • Set a specific stylesheet based on session variable in javascript

    - by user2371301
    I have an option for a user to select his/her own theme while logged into the system and this theme is set in a MYSQL Database and called each time the user logs in, this is called by: <?php $_SESSION['SESS_THEME_NAME']; ?> Now, I had this working in a PHP file but I need it to work in Javascript instead unfortunately. And I need some help. I looked at the code using the developers tools on Google Chrome and looks like the above code is not resolving within the javascript file. Which makes sense because you can't access session variables within a javascript file (as I found by searching Google.) The code is basically supposed to set the specific stylesheet based on the value extracted from the MYSQL database. So if the database says Default the script needs to tell the webpage to use the default.css file. And so on and so forth. My attempt at writing this is as follows: var themName="<?php $_SESSION['SESS_THEME_NAME']; ?>"; if (themeName == "Default") { document.write("<link re='stylesheet' type='text/css' href='css/mws-theme.css'>"); }; if (themeName == "Army") { document.write("<link rel='stylesheet' type='text/css' href='css/mws-theme-army.css'>"); }; if (themeName == "Rocky Mountains") { document.write("<link rel='stylesheet' type='text/css' href='css/mws-theme-rocky.css'>"); }; if (themeName == "Chinese Temple") { document.write("<link rel='stylesheet' type='text/css' href='css/mws-theme-chinese.css'>"); }; if (themeName == "Boutique") { document.write("<link rel='stylesheet' type='text/css' href='css/mws-theme-boutique.css'>"); }; if (themeName == "Toxic") { document.write("<link rel='stylesheet' type='text/css' href='css/mws-theme-toxic.css'>"); }; if (themeName == "Aquamarine") { document.write("<link rel='stylesheet' type='text/css' href='css/mws-theme-aquamarine.css'>"); }; Any help once so ever would be awesome and much much appreciated! I am reaching a deadline :/

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  • Is it ok to return a reference of a function scope static variable?

    - by kartik
    I wanted to know if that has any ill effects under any circumsatnce. For ex: Ex1: void* func1() { void* p_ref = NULL; //function scope static variable static int var1 = 2; p_ref = &var1; return p_ref; } Ex2: //file scope static variable static int var2 = 2; void* func2() { void* p_ref = NULL; var2 = 3; p_ref = &var2; return p_ref; } So in the above two cases what is the difference apart from the fact that var1 is function scope and var2 is file scope. Thanks in advance.

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  • session variable values are not being passed between pages

    - by ravi nankani
    hi, i am a little new to php and although i have managed to pass values of session variables before this piece of code is leaving me puzzled <form action="team_reg2.php" method="post" name="form1" class="cent" id="form1"> Team Registration "; print "member$i"; print "\n"; print "\n"; print "Please enter only id\n"; } ? now this will pass via post to team_reg2.php echo " please note your team id is 1 "; echo " your team members are : "; for($i=1;$i<=$num;$i++) { $name='mem'.$i; echo "$_POST[$name]"; } } else { $str="select * from $query where ("; for($i=1;$i<=$num;$i++) { $name='mem'.$i; $text="p_id='$_POST[$name]'"; if($i==1) $str=$str.$text; else $str=$str.' or '.$text; } $str=$str.')'; $query2=$str; echo "$str"; // echo "$query2"; $que=mysql_query($query2,$con) or die(mysql_error()); $num=mysql_num_rows($que); if($num!=0) { while($result=mysql_fetch_array($que)) { echo "$result[p_id] is already registered in team $result[t_id]"; } //include("reg_team.html"); } else if($num==0) { //echo $query; $query2="select max(t_id) from $query"; $que=mysql_query($query2,$con) or die(mysql_error()); //echo "$que"; $result=mysql_fetch_array($que); $max=$result['max(t_id)']; $max++; $num=$_SESSION['max_team']; for($i=1;$i<=$num;$i++) { $name='mem'.$i; if($_POST[$name]!="") { $query2="insert into $query values($max,'$_POST[$name]')"; $que=mysql_query($query2,$con); } } echo " please note your team id is $max "; echo " your team members are : "; for($i=1;$i<=$num;$i++) { $name='mem'.$i; echo "$_POST[$name]"; } } } ? i have done session_start(); at the beginning of the page itself. The problem is that echoing $_SESSION variables in second file is not printing anything. someone please explain me whats going on. thank you

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  • In NHIbernate, why does SaveOrUpdate() update the Version, but SaveOrUpdateCopy() doesn't?

    - by Daniel T.
    I have a versioned entity, and this is what happens when I use SaveOrUpdate() vs. SaveOrUpdateCopy(): // create new entity var entity = new Entity{ Id = Guid.Empty }); Console.WriteLine(entity.Version); // prints out 0 // save the new entity GetNewSession(); entity.SaveOrUpdate(); Console.WriteLine(entity.Version); // prints out 1 GetNewSession(); // loads the persistent entity into the session, so we have to use // SaveOrUpdateCopy() to merge the following transient entity var dbEntity = Database.GetAll<Entity>(); // new, transient entity used to update the persistent entity in the session var newEntity = new Entity{ Id = Guid.Empty }); newEntity.SaveOrUpdateCopy(); Console.WriteLine(entity.Version); // prints out 1, but should be 2 Why is the version number is not updated for SaveOrUpdateCopy()? As I understand it, the transient entity is merged with the persistent entity. The SQL calls confirm that the data is updated. At this point, shouldn't newEntity become persistent, and the version number incremented?

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  • How to avoid an HttpException due to timeout

    - by Dan
    I'm working on a website powered by .NET asp/C# code. The clients require that sessions have a 25 minute timeout. However, sometimes the site is used, and a user stays connected for long periods of time (longer than 25 mins). Session_End is triggered: protected void Session_End(Object sender, EventArgs e) { Hashtable trackingInformaiton = (Hashtable)Application["trackingInformation"]; trackingInformaiton.Remove(Session["trackingID"]); } The user returns some time later, but when they interact with the website, they get an error, and we get this email notification: User: Unauthenticated User Error: System.Web.HttpException Description: Failed to load viewstate. The control tree into which viewstate is being loaded must match the control tree that was used to save viewstate during the previous request... The telling part of the stack trace is System.Web.UI.Control.AddedControl. Apparently, the server has thrown away the session data, and is sending new data, but the client is trying to deal with old data. Hence the error that "the control tree into which viewstate is being loaded [doesn't] match the control tree that was used to save the viewstate during the prevoius request." So here's the question. How can I force instruct the user's browser to redirect to a "you're logged out" screen when the connection times out? (Is it something I should add to the Session_End method?)

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  • Athentication Problem - not recognizing 'else' - Ruby on rails...

    - by bgadoci
    I can't seem to figure out what I am doing wrong here. I have implemented the Super Simple Authentication from Ryan Bates tutorial and while the login portion is functioning correctly, I can't get an error message and redirect to happen correctly for a bad login. Ryan Bates admits in his comments he left this out but can't seem to implement his recommendation. Basically what is happening is that when someone logs in correctly it works. When a bad password is entered it does the same redirect and flashes 'successfully logged in' thought they are not. The admin links do not show (which is correct and are the links protected by the <% if admin? %) but I need it to say 'failed login' and redirect to login path. Here is my code: SessionsController class SessionsController < ApplicationController def create if session[:password] = params[:password] flash[:notice] = 'Successfully logged in' redirect_to posts_path else flash[:notice] = "whoops" redirect_to login_path end end def destroy reset_session flash[:notice] = 'Successfully logged out' redirect_to posts_path end end ApplicationController class ApplicationController < ActionController::Base helper_method :admin? protected def authorize unless admin? flash[:error] = "unauthorized request" redirect_to posts_path false end end def admin? session[:password] == "string0826" end helper :all # include all helpers, all the time protect_from_forgery # See ActionController::RequestForgeryProtection for details # end

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  • Validation with State Pattern for Multi-Page Forms in ASP.NET

    - by philrabin
    I'm trying to implement the state pattern for a multi-page registration form. The data on each page will be accumulated and stored in a session object. Should validation (including service layer calls to the DB) occur on the page level or inside each state class? In other words, should the concrete implementation of IState be concerned with the validation or should it be given a fully populated and valid object? See "EmptyFormState" class below: namespace Example { public class Registrar { private readonly IState formEmptyState; private readonly IState baseInformationComplete; public RegistrarSessionData RegistrarSessionData { get; set;} public Registrar() { RegistrarSessionData = new RegistrarSessionData(); formEmptyState = new EmptyFormState(this); baseInformationComplete = new BasicInfoCompleteState(this); State = formEmptyState; } public IState State { get; set; } public void SubmitData(RegistrarSessionData data) { State.SubmitData(data); } public void ProceedToNextStep() { State.ProceedToNextStep(); } } //actual data stored in the session //to be populated by page public class RegistrarSessionData { public string FirstName { get; set; } public string LastName { get; set; } //will include values of all 4 forms } //State Interface public interface IState { void SubmitData(RegistrarSessionData data); void ProceedToNextStep(); } //Concrete implementation of IState //Beginning state - no data public class EmptyFormState : IState { private readonly Registrar registrar; public EmptyFormState(Registrar registrar) { this.registrar = registrar; } public void SubmitData(RegistrarSessionData data) { //Should Validation occur here? //Should each state object contain a validation class? (IValidator ?) //Should this throw an exception? } public void ProceedToNextStep() { registrar.State = new BasicInfoCompleteState(registrar); } } //Next step, will have 4 in total public class BasicInfoCompleteState : IState { private readonly Registrar registrar; public BasicInfoCompleteState(Registrar registrar) { this.registrar = registrar; } public void SubmitData(RegistrarSessionData data) { //etc } public void ProceedToNextStep() { //etc } } }

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  • Authentication Problem - not recognizing 'else' - Ruby on rails...

    - by bgadoci
    I can't seem to figure out what I am doing wrong here. I have implemented the Super Simple Authentication from Ryan Bates tutorial and while the login portion is functioning correctly, I can't get an error message and redirect to happen correctly for a bad login. Ryan Bates admits in his comments he left this out but can't seem to implement his recommendation. Basically what is happening is that when someone logs in correctly it works. When a bad password is entered it does the same redirect and flashes 'successfully logged in' thought they are not. The admin links do not show (which is correct and are the links protected by the <% if admin? %) but I need it to say 'failed login' and redirect to login path. Here is my code: SessionsController class SessionsController < ApplicationController def create if session[:password] = params[:password] flash[:notice] = 'Successfully logged in' redirect_to posts_path else flash[:notice] = "whoops" redirect_to login_path end end def destroy reset_session flash[:notice] = 'Successfully logged out' redirect_to posts_path end end ApplicationController class ApplicationController < ActionController::Base helper_method :admin? protected def authorize unless admin? flash[:error] = "unauthorized request" redirect_to posts_path false end end def admin? session[:password] == "123456" end helper :all # include all helpers, all the time protect_from_forgery # See ActionController::RequestForgeryProtection for details # end

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  • How to use sessions in PDO?

    - by Byakugan
    I am still redoing and getting rid of old mysql_* commands in my code. I tried to transfer my session login form old code and this is what I got so far: public function login($user, $password) { if (!empty($user) && !empty($password)) { $password = $web->doHash($user, $password); // in this function is (return sha1(strtoupper($user).':'.strtoupper($password)) $stmt = $db_login->prepare("SELECT * FROM account WHERE username=:user AND pass_hash=:password"); $stmt->bindValue(':user', $user, PDO::PARAM_STR); $stmt->bindValue(':password', $password, PDO::PARAM_STR); $stmt->execute(); $rows = $stmt->rowCount(); if ($rows > 0) { $results_login = $stmt->fetch(PDO::FETCH_ASSOC); $_SESSION['user_name'] = $results_login['username']; $_SESSION['user_id'] = $results_login['id']; return true; } else { return false; } } else { return false; } } After that I am using checks if user logged on site: public function isLogged() { return (!empty($_SESSION['user_id']) && !empty($_SESSION['user_name'])); } But it seems - this function returns always empty because $_SESSION does not exists in PDO? And of course logout is used in this form on my sites: public function logout() { unset($_SESSION['user_id']); unset($_SESSION['user_name']); } But I think PDO has different way of handling session? I did not find any so what is it can i somehow add $_SESSION in PDO withou changing code much? I am using variables $_SESSION['user_name'] and $_SESSION['user_id'] in all over my web project. Summary: 1) How to use sessions in PDO correctly? 2) What is difference between using $stmt->fetch(PDO::FETCH_ASSOC); and $stmt->fetchAll(); Thank you.

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  • Google Analytics - Goals - Advanced Segments - Does it keep cookies for tracking visitors?

    - by Kuko
    Hi there, I am working with Google Analytics - Goals and Funnels for quite sometime, but one thing is is not clear for me. I would very much appreciate if you could help me. We are advertising on several sites rotating several different ads. Our main goal is to collect as many sign-ups (new users) as possible for as low price as possible. We use to advertise the way, that each ad has the same URL where to land, but contains different parameter (e.g. http://www.brautpunkt.de/?ref=fb01 or ..... .de/?ref=adw03). My question is: If I am looking at the goals (Goals Overview), filtering it through Advanced Segments (Landing Page contains /?ref=fb01) is this subset of goals done only by the users who registered in the same session after they came on our site directly from the ad? or also by those users who came first time through this ad (/?ref=fb01), didn't register in the same session but came directly for example on the other day and register than? Thank you very much in advance for your advice. Peter

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  • Strange problem with PHP and sessions

    - by Jhorra
    So the basis of this page is I set a session value when the page loads, and clear it on any other page they visit. Then the page can make an ajax call to download a file. If the session value matches the value I pass through the URL I allow them to download the file. If not I return a 404 error. I was having some weird issues, so I removed the 404 and set it to echo out the values instead to see what I was getting. Here is the top of the code on the page: $code = $this->_request->getParam('code'); $confirm = $_SESSION['mp3_code']; echo $code."-1-".$confirm; if($code != $confirm) echo $code."-2-".$confirm;//header("HTTP/1.1 404 Not Found"); else { Here is what displays on the page from the ajax call 12723430-1-12723430-2- As you can see when it echos out the first time they exist, then somehow after I compare them and it fails you see that it echos out blank values like they suddenly ceased to exist. Any ideas?

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