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  • Returning modified data to a template

    - by Duncan
    I need to amend QuerySet data when i return it to a template. for example, model.objects.all() returns a date (with other fields), but i also want to return the number of days since that date has passed. This is so that in the template, i can say "you last logged in 4 days ago". What is the best way to do this?

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  • Django | django-socialregistration error

    - by MMRUser
    I'm trying to add the facebook connect feature to my site, I decided to use django socialregistration.All are setup including pyfacebook, here is my source code. settings.py MIDDLEWARE_CLASSES = ( 'django.middleware.common.CommonMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'facebook.djangofb.FacebookMiddleware', 'socialregistration.middleware.FacebookMiddleware', ) urls.py (r'^callback/$', 'fbproject.fbapp.views.callback'), views.py def callback(request): return render_to_response('canvas.fbml') Template <html> <body> {% load facebook_tags %} {% facebook_button %} {% facebook_js %} </body> </html> but when I point to the URL, I'm getting this error Traceback (most recent call last): File "C:\Python26\lib\site-packages\django\core\servers\basehttp.py", line 279, in run self.result = application(self.environ, self.start_response) File "C:\Python26\lib\site-packages\django\core\servers\basehttp.py", line 651, in __call__ return self.application(environ, start_response) File "C:\Python26\lib\site-packages\django\core\handlers\wsgi.py", line 241, in __call__ response = self.get_response(request) File "C:\Python26\lib\site-packages\django\core\handlers\base.py", line 73, in get_response response = middleware_method(request) File "build\bdist.win32\egg\socialregistration\middleware.py", line 13, in process_request request.facebook.check_session(request) File "C:\Python26\lib\site-packages\facebook\__init__.py", line 1293, in check_session self.session_key_expires = int(params['expires']) ValueError: invalid literal for int() with base 10: 'None' Django 1.1.1 *Python 2.6.2*

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  • Manditory read-only fields in django

    - by jamida
    I'm writing a test "grade book" application. The models.py file is shown below. class Student(models.Model): name = models.CharField(max_length=50) parent = models.CharField(max_length=50) def __unicode__(self): return self.name class Grade(models.Model): studentId = models.ForeignKey(Student) finalGrade = models.CharField(max_length=3) I'd like to be able to change the final grade for several students in a modelformset but for now I'm just trying one student at a time. I'm also trying to create a form for it that shows the student name as a field that can not be changed, the only thing that can be changed here is the finalGrade. So I used this trick to make the studentId read-only. class GradeROForm(ModelForm): studentId = forms.ModelChoiceField(queryset=Student.objects.all()) def __init__(self, *args, **kwargs): super(GradeROForm,self).__init__(*args, **kwargs) instance = getattr(self, 'instance', None) if instance and instance.id: self.fields['studentId'].widget.attrs['disabled']='disabled' def clean_studentId(self): instance = getattr(self,'instance',None) if instance: return instance.studentId else: return self.cleaned_data.get('studentId',None) class Meta: model=Grade And here is my view: def modifyGrade(request,student): student = Student.objects.get(name=student) mygrade = Grade.objects.get(studentId=student) if request.method == "POST": myform = GradeROForm(data=request.POST, instance=mygrade) if myform.is_valid(): grade = myform.save() info = "successfully updated %s" % grade.studentId else: myform=GradeROForm(instance=mygrade) return render_to_response('grades/modifyGrade.html',locals()) This displays the form like I expect, but when I hit "submit" I get a form validation error for the student field telling me this field is required. I'm guessing that, since the field is "disabled", the value is not being reported in the POST and for reasons unknown to me the instance isn't being used in its place. I'm a new Django/Python programmer, but quite experienced in other languages. I can't believe I've stumbled upon such a difficult to solve problem in my first significant django app. I figure I must be missing something. Any ideas?

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  • Invalidating Memcached Keys on save() in Django

    - by Zack
    I've got a view in Django that uses memcached to cache data for the more highly trafficked views that rely on a relatively static set of data. The key word is relatively: I need invalidate the memcached key for that particular URL's data when it's changed in the database. To be as clear as possible, here's the meat an' potatoes of the view (Person is a model, cache is django.core.cache.cache): def person_detail(request, slug): if request.is_ajax(): cache_key = "%s_ABOUT_%s" % settings.SITE_PREFIX, slug # Check the cache to see if we've already got this result made. json_dict = cache.get(cache_key) # Was it a cache hit? if json_dict is None: # That's a negative Ghost Rider person = get_object_or_404(Person, display = True, slug = slug) json_dict = { 'name' : person.name, 'bio' : person.bio_html, 'image' : person.image.extra_thumbnails['large'].absolute_url, } cache.set(cache_key) # json_dict will now exist, whether it's from the cache or not response = HttpResponse() response['Content-Type'] = 'text/javascript' response.write(simpljson.dumps(json_dict)) # Make sure it's all properly formatted for JS by using simplejson return response else: # This is where the fully templated response is generated What I want to do is get at that cache_key variable in it's "unformatted" form, but I'm not sure how to do this--if it can be done at all. Just in case there's already something to do this, here's what I want to do with it (this is from the Person model's hypothetical save method) def save(self): # If this is an update, the key will be cached, otherwise it won't, let's see if we can't find me try: old_self = Person.objects.get(pk=self.id) cache_key = # Voodoo magic to get that variable old_key = cache_key.format(settings.SITE_PREFIX, old_self.slug) # Generate the key currently cached cache.delete(old_key) # Hit it with both barrels of rock salt # Turns out this doesn't already exist, let's make that first request even faster by making this cache right now except DoesNotExist: # I haven't gotten to this yet. super(Person, self).save() I'm thinking about making a view class for this sorta stuff, and having functions in it like remove_cache or generate_cache since I do this sorta stuff a lot. Would that be a better idea? If so, how would I call the views in the URLconf if they're in a class?

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  • Formatting inline many-to-many related models presented in django admin

    - by Jonathan
    I've got two django models (simplified): class Product(models.Model): name = models.TextField() price = models.IntegerField() class Invoice(models.Model): company = models.TextField() customer = models.TextField() products = models.ManyToManyField(Product) I would like to see the relevant products as a nice table (of product fields) in an Invoice page in admin and be able to link to the individual respective Product pages. My first thought was using the admin's inline - but django used a select box widget per related Product. This isn't linked to the Product pages, and also as I have thousands of products, and each select box independently downloads all the product names, it quickly becomes unreasonably slow. So I turned to using ModelAdmin.filter_horizontal as suggested here, which used a single instance of a different widget, where you have a list of all Products and another list of related Products and you can add\remove products in the later from the former. This solved the slowness, but it still doesn't show the relevant Product fields, and it ain't linkable. So, what should I do? tweak views? override ModelForms? I Googled around and couldn't find any example of such code...

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  • Django ModelForm is giving me a validation error that doesn't make sense

    - by River Tam
    I've got a ModelForm based on a Picture. class Picture(models.Model): name = models.CharField(max_length=100) pub_date = models.DateTimeField('date published') tags = models.ManyToManyField('Tag', blank=True) content = models.ImageField(upload_to='instaton') def __unicode__(self): return self.name class PictureForm(forms.ModelForm): class Meta: model = Picture exclude = ('pub_date','tags') That's the model and the ModelForm, of course. def submit(request): if request.method == 'POST': # if the form has been submitted form = PictureForm(request.POST) if form.is_valid(): return HttpResponseRedirect('/django/instaton') else: form = PictureForm() # blank form return render_to_response('instaton/submit.html', {'form': form}, context_instance=RequestContext(request)) That's the view (which is being correctly linked to by urls.py) Right now, I do nothing when the form submits. I just check to make sure it's valid. If it is, I forward to the main page of the app. <form action="/django/instaton/submit/" method="post"> {% csrf_token %} {{ form.as_p }} <input type="submit" value"Submit" /> </form> And there's my template (in the correct location). When I try to actually fill out the form and just validate it, even if I do so correctly, it sends me back to the form and says "This field is required" between Name and Content. I assume it's referring to Content, but I'm not sure. What's my problem? Is there a better way to do this?

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  • int() error in django views

    - by Hulk
    def displaydata(request): response_dict = {} offset = int(request.GET.get('iDisplayStart')) There is an error as, int() argument must be a string or a number at the above said line (i.e,`request.GET.get('iDisplayStart')) And in the template code, $(document).ready(function() { $.ajaxSetup({ cache: false }); oTable = $('#qp_table').dataTable( { "aoColumns": [ {"sWidth": "5%" }, {"sWidth": "35%" }, {"sWidth": "27%" }, {"sWidth": "15%"}, { "bSortable": false, "sWidth": "0%"}, {"bSortable": false, "sWidth": "0%"} ], "aaSorting": [[0, 'asc']], "bProcessing": true, "bServerSide": true, "sAjaxSource": "/diaplaydata/", "bJQueryUI": true, "sPaginationType": "full_numbers", "bFilter": false, "oLanguage" : { "sZeroRecords": "No data found", "sProcessing" : "Fetching Data" } });

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  • Django Formset management-form validation error

    - by gramware
    I have a form and a formset on my template. The problem is that the formset is throwing validation error claiming that the management form is "missing or has been tampered with". Here is my view @login_required def home(request): user = UserProfile.objects.get(pk=request.session['_auth_user_id']) blogz = list(blog.objects.filter(deleted='0')) delblog = modelformset_factory(blog, exclude=('poster','date' ,'title','content')) if request.user.is_staff== True: staff = 1 else: staff = 0 staffis = 1 if request.method == 'POST': delblogformset = delblog(request.POST) if delblogformset.is_valid(): delblogformset.save() return HttpResponseRedirect('/home') else: delblogformset = delblog(queryset=blog.objects.filter( deleted='0')) blogform = BlogForm(request.POST) if blogform.is_valid(): blogform.save() return HttpResponseRedirect('/home') else: blogform = BlogForm(initial = {'poster':user.id}) blogs= zip(blogz,delblogformset.forms) paginator = Paginator(blogs, 10) # Show 25 contacts per page # Make sure page request is an int. If not, deliver first page. try: page = int(request.GET.get('page', '1')) except ValueError: page = 1 # If page request (9999) is out of range, deliver last page of results. try: blogs = paginator.page(page) except (EmptyPage, InvalidPage): blogs = paginator.page(paginator.num_pages) return render_to_response('home.html', {'user':user, 'blogform':blogform, 'staff': staff, 'staffis': staffis, 'blog':blogs, 'delblog':delblogformset}, context_instance = RequestContext( request )) my template {%block content%} <h2>Home</h2> {% ifequal staff staffis %} {% if form.errors %} <ul> {% for field in form %} <H3 class="title"> <p class="error"> {% if field.errors %}<li>{{ field.errors|striptags }}</li>{% endif %}</p> </H3> {% endfor %} </ul> {% endif %} <h3>Post a Blog to the Front Page</h3> <form method="post" id="form2" action="" class="infotabs accfrm"> {{ blogform.as_p }} <input type="submit" value="Submit" /> </form> <br> <br> {% endifequal %} <div class="pagination"> <span class="step-links"> {% if blog.has_previous %} <a href="?page={{ blog.previous_page_number }}">previous</a> {% endif %} <span class="current"> Page {{ blog.number }} of {{ blog.paginator.num_pages }}. </span> {% if blog.has_next %} <a href="?page={{ blog.next_page_number }}">next</a> {% endif %} </span> <form method="post" action="" class="usertabs accfrm"> {{delblog.management_form}} {% for b, form in blog.object_list %} <div class="blog"> <h3>{{b.title}}</h3> <p>{{b.content}}</p> <p>posted by <strong>{{b.poster}}</strong> on {{b.date}}</p> {% ifequal staff staffis %}<p>{{form.as_p}}<input type="submit" value="Delete" /></p>{% endifequal %} </div> {% endfor %} </form> {%endblock%}

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  • Django - Form validation error

    - by Igor G.
    Hello, I have a model like this: class Entity(models.Model): entity_name = models.CharField(max_length=100) entity_id = models.CharField(max_length=30, primary_key=True) entity_parent = models.CharField(max_length=100, null=True) photo_id = models.CharField(max_length=100, null=True) username = models.CharField(max_length=100, null=True) date_matched_on = models.CharField(max_length=100, null=True) status = models.CharField(max_length=30, default="Checked In") def __unicode__(self): return self.entity_name class Meta: app_label = 'match' ordering = ('entity_name','date_matched_on') verbose_name_plural='Entities' I also have a view like this: def photo_match(request): ''' performs an update in the db when a user chooses a photo ''' form = EntityForm(request.POST) form.save() And my EntityForm looks like this: class EntityForm(ModelForm): class Meta: model = Entity My template's form returns a POST back to the view with the following values: {u'username': [u'admin'], u'entity_parent': [u'PERSON'], u'entity_id': [u'152097'], u'photo_id': [u'2200734'], u'entity_name': [u'A.J. McLean'], u'status': [u'Checked Out'], u'date_matched_on': [u'5/20/2010 10:57 AM']} And form.save() throws this error: Exception in photo_match: The Entity could not be changed because the data didn't validate. I have been trying to figure out why this is happening, but cannot pinpoint the exact problem. I can change my Entities in the admin interface just fine. If anybody has a clue about this I would greatly appreciate it! Thanks, Igor

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  • Django javascript escape characters

    - by Hulk
    There is a text area in which the data is entered as, 122 //Enter button pushed Address Name //Enter button pushed 1 And the same is tored in the db.And the data is fetched in views and returned it to template as, <script> {% for i in dict.row_arr %} var ii= ('{{ i }}'); row_arr.push( ii ); {% endfor %} </script> Here there is an error as Error: unterminated string literal Line: 40, Column: 12 Source Code: var ii= ('1212 And when the html source shows up as, var ii= ('1212 1 21 11212121212'); row_arr.push( ii ); How should the escape function be applied here. Thanks..

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  • Reorganizing many to many relationships in Django

    - by Galen
    I have a many to many relationship in my models and i'm trying to reorganize it on one of my pages. My site has videos. On each video's page i'm trying to list the actors that are in that video with links to each time they are in the video(the links will skip to that part of the video) Here's an illustration Flash Video embedded here Actors... Ted smith: 1:25, 5:30 jon jones: 5:00, 2:00 Here are the pertinent parts of my models class Video(models.Model): actor = models.ManyToManyField( Actor, through='Actor_Video' ) # more stuff removed class Actor_Video(models.Model): actor = models.ForeignKey( Actor ) video = models.ForeignKey( Video) time = models.IntegerField() Here's what my Actor_Video table looks like, maybe it will be easier to see what im doing id actor_id video_id time (in seconds) 1 1 3 34 2 1 3 90 i feel like i have to reorganize the info in my view, but i cant figure it out. It doesn't seem to be possible in the template using djangos orm. I've tried a couple things with creating dictionaries/lists but i've had no luck. Any help is appreciated. Thanks.

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  • django forms in diferent contexts

    - by z3a
    I'm in a middle of a problem, I have a url like /account/login that displays a login form. I need to include this form in another template that have a different url. I tried to use {%include%} but this don't work, the form is not shown. Any one have a clue about this??

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  • Manually listing objects in Django (problem with field ordering)

    - by Chris
    I'm having some trouble figuring out the best/Djangoic way to do this. I'm creating something like an interactive textbook. It has modules, which are more or less like chapters. Each module page needs to list the topics in that module, grouped into sections. My question is how I can ensure that they list in the correct order in the template? Specifically: 1) How to ensure the sections appear in the correct order? 2) How to ensure the topics appear in the correct order in the section? I imagine I could add a field to each model purely for the sake of ordering, but the problem with that is that a topic might appear in different modules, and in whatever section they are in there they would again have to be ordered somehow. I would probably give up and do it all manually were it not for the fact that I need to have the Topic as object in the template (or view) so I can mark it up according to how the user has labeled it. So I suppose my question is really to do with whether I should create the contents pages manually, or whether there is a way of ordering the query results in a way I haven't thought of. Thanks for your help!

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  • Django - markup parser in template or view?

    - by Amit Ron
    I am building a website where my pages are written in MediaWiki Markup, for which I have a working parser function in Python. Where exactly do I parse my markup: in the view's code, or in the template? My first guess would be something like: return render_to_response( 'blog/post.html', {'post': post, 'content': parseMyMarkup(post.content) }) Is this the usual convention, or should I do something different?

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  • Setting Meta tags for a website

    - by Pankaj Upadhyay
    I have made an Asp.net MVC website and am not well versed about SEO techniques, so I want a little guidance in setting the appropriate meta tags for the website. My website is dynamic and has two types of Pages: Category and Product There are two tables in the database for Category and Product. Looking into the future, I added these fields beforehand to both the tables : -- MetaTitle--MetaDescription--MetaKeywords On both the Category and Product pages, these values are retrieved and set as following <meta name="description" content="@ViewBag.MetaDescription" /> <meta name="title" content="@ViewBag.MetaTitle" /> <meta name="keywords" content="@ViewBag.MetaKeywords" /> For better SEO how will you set up these meta tags. Will you include the site name in all three fields ? Right now, the Product page's MetaTitle, MetaDescription and MetaKeywords don't include the website name. If possible, can you provide me sample values that should be set for better SEO performance keeping the business name in mind.

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  • django views question

    - by Hulk
    In my django views i have the following def create(request): query=header.objects.filter(id=a)[0] a=query.criteria_set.all() logging.debug(a.details) I get an error saying 'QuerySet' object has no attribute 'details' in the debug statement .What is this error and what should be the correct statemnt to query this.And the model corresponding to this is as follows where as the models has the following: class header(models.Model): title = models.CharField(max_length = 255) created_by = models.CharField(max_length = 255) def __unicode__(self): return self.id() class criteria(models.Model): details = models.CharField(max_length = 255) headerid = models.ForeignKey(header) def __unicode__(self): return self.id() Thanks..

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  • Django url parameters

    - by Hulk
    How to pass two paramters in urls in django <script> url=/toolbox/display/" + id + "2"; window.location=url; </script> Also how is this handeled in urls.py (r'^display/(?P<rid>\d+)/(?P<param>\d+)/$', 'table_display'), In views, def table_display(request,rid,param): print param //This should print 2

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  • Django forms "not" using forms from models

    - by zubinmehta
    I have a form generated from various models and the various values filled go and sit in some other table. Hence, in this case I haven't used the inbuilt Django forms(i.e. I am not creating forms from models ). Now the data which is posted from the self made form is handled by view1 which should clean the data accordingly. How do I go about it and use the various functions clean and define validation errors (and preferably not do validation logic in the view itself!)

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  • Extended Django base-class with multiple instances

    - by Gijs
    I'm modeling a simple movie database using Django. models.py defines a base model Person. I extend Person into Actor and Director, which works as I imagined. Persons must be unique. When (in the Admin) I create an instance of Actor, and this person is also a Director, it won't save because of the unique = True. Any ideas how to solve this problem? (generic foreign keys?) Thx

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  • Django: How to get current user in admin forms

    - by lazerscience
    In Django's ModelAdmin I need to display forms customized according to the permissions an user has. Is there a way of getting the current user object into the form class, so that i can customize the form in its __init__ method? I think saving the current request in a thread local would be a possibility but this would be my last resort think I'm thinking it is a bad design approach....

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  • Django filter vs exclude

    - by Enrico
    Is there a difference between filter and exclude in django? If I have self.get_query_set().filter(modelField=x) and I want to add another criteria, is there a meaningful difference between to following two lines of code? self.get_query_set().filter(user__isnull=False, modelField=x) self.get_query_set().filter(modelField=x).exclude(user__isnull=True) is one considered better practice or are they the same in both function and performance?

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  • Django User model, adding function

    - by Hellnar
    Hello, I want to add a new function to the default User model of Django for retrieveing a related list of Model type. Such Foo model: class Foo(models.Model): owner = models.ForeignKey(User, related_name="owner") likes = models.ForeignKey(User, related_name="likes") ........ #at some view user = request.user foos= user.get_related_foo_models() Hwo can this be achieved ?

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  • How to store an integer leaded by zeros in django

    - by Oscar Carballal
    Hello, I'm trying to store a number in django that looks like this: 000001 My problem is that if I type this inside an IntegerField it gets converted to "1" without the leading zeros. I've tried also with a DecimalField with the same result. How can I store the leading zeros whithout using a CharField? (I need to manipulate that number in it's integer form)

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  • How to make custom join query with Django ?

    - by xRobot
    I have these 2 models: genre = ( ('D', 'Dramatic'), ('T', 'Thriller'), ('L', 'Love'), ) class Book(models.Model): title = models.CharField(max_length=100) genre = models.CharField(max_length=1, choices=genre) class Author(models.Model): user = models.ForeignKey(User, unique=True) born = models.DateTimeField('born') book = models.ForeignKey(Book) I need to retrieve first_name and last_name of all authors of dramatic's books. How can I do this in django ?

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