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• Hibernate3: Self-Referencing Objects

  - by monojohnny

  Need some help on understanding how to do this; I'm going to be running recursive 'find' on a file system and I want to keep the information in a single DB table - with a self-referencing hierarchial structure: This is my DB Table structure I want to populate. DirObject Table: id int NOT NULL, name varchar(255) NOT NULL, parentid int NOT NULL); Here is the proposed Java Class I want to map (Fields only shown): public DirObject { int id; String name; DirObject parent; ... For the 'root' directory was going to use parentid=0; real ids will start at 1, and ideally I want hibernate to autogenerate the ids. Can somebody provide a suggested mapping file for this please; as a secondary question I thought about doing the Java Class like this instead: public DirObject { int id; String name; List<DirObject> subdirs; Could I use the same data model for either of these two methods ? (With a different mapping file of course). --- UPDATE: so I tried the mapping file suggested below (thanks!), repeated here for reference: <hibernate-mapping> <class name="my.proj.DirObject" table="category"> ... <set name="subDirs" lazy="true" inverse="true"> <key column="parentId"/> <one-to-many class="my.proj.DirObject"/> </set> <many-to-one name="parent" class="my.proj.DirObject" column="parentId" cascade="all" /> </class> ...and altered my Java class to have BOTH 'parentid' and 'getSubDirs' [returning a 'HashSet']. This appears to work - thanks, but this is the test code I used to drive this - I think I'm not doing something right here, because I thought Hibernate would take care of saving the subordinate objects in the Set without me having to do this explicitly ? DirObject dirobject=new DirObject(); dirobject.setName("/files"); dirobject.setParent(dirobject); DirObject d1, d2; d1=new DirObject(); d1.setName("subdir1"); d1.setParent(dirobject); d2=new DirObject(); d2.setName("subdir2"); d2.setParent(dirobject); HashSet<DirObject> subdirs=new HashSet<DirObject>(); subdirs.add(d1); subdirs.add(d2); dirobject.setSubdirs(subdirs); session.save(dirobject); session.save(d1); session.save(d2);

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• wxpython PyGridTableBase

  - by nozkan

  Hi, I want to use editable choice editor with PyGridTableBase. When I edit a cell it is crashing What is error in my code? My python code: import wx import wx.grid as gridlib class MyTableBase(gridlib.PyGridTableBase): def __init__(self): gridlib.PyGridTableBase.__init__(self) self.data = {0:["value 1", "value 2"], 1:["value 3", "value 4", "value 5"]} self.column_labels = [unicode(u"Label 1"), unicode(u"Label 2"), unicode(u"Label 3")] self._rows = self.GetNumberRows() self._cols = self.GetNumberCols() def GetColLabelValue(self, col): return self.column_labels[col] def GetNumberRows(self): return len(self.data.keys()) def GetNumberCols(self): return len(self.column_labels) def GetValue(self, row, col): try: if col > self.GetNumberCols(): raise IndexError return self.data[row][col] except IndexError: return None def IsEmptyCell(self, row, col): if self.data[row][col] is not None: return True else: return False def GetAttr(self, row, col, kind): attr = gridlib.GridCellAttr() editor = gridlib.GridCellChoiceEditor(["xxx", "yyy", "zzz"], allowOthers = True) attr.SetEditor(editor) attr.IncRef() return attr class MyDataGrid(gridlib.Grid): def __init__(self, parent): gridlib.Grid.__init__(self, parent, wx.NewId()) self.base_table = MyTableBase() self.SetTable(self.base_table) if __name__ == '__main__': app = wx.App(redirect = False) frame = wx.Frame(None, wx.NewId(), title = u"Test") grid_ = MyDataGrid(frame) frame.Show() app.MainLoop()

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• Single player 'pong' game

  - by Jam

  I am just starting out learning pygame and livewires, and I'm trying to make a single-player pong game, where you just hit the ball, and it bounces around until it passes your paddle (located on the left side of the screen and controlled by the mouse), which makes you lose. I have the basic code, but the ball doesn't stay on the screen, it just flickers and doesn't remain constant. Also, the paddle does not move with the mouse. I'm sure I'm missing something simple, but I just can't figure it out. Help please! Here's what I have: from livewires import games import random games.init(screen_width=640, screen_height=480, fps=50) class Paddle(games.Sprite): image=games.load_image("paddle.bmp") def __init__(self, x=10): super(Paddle, self).__init__(image=Paddle.image, y=games.mouse.y, left=10) self.score=games.Text(value=0, size=25, top=5, right=games.screen.width - 10) games.screen.add(self.score) def update(self): self.y=games.mouse.y if self.top<0: self.top=0 if self.bottom>games.screen.height: self.bottom=games.screen.height self.check_collide() def check_collide(self): for ball in self.overlapping_sprites: self.score.value+=1 ball.handle_collide() class Ball(games.Sprite): image=games.load_image("ball.bmp") speed=5 def __init__(self, x=90, y=90): super(Ball, self).__init__(image=Ball.image, x=x, y=y, dx=Ball.speed, dy=Ball.speed) def update(self): if self.right>games.screen.width: self.dx=-self.dx if self.bottom>games.screen.height or self.top<0: self.dy=-self.dy if self.left<0: self.end_game() self.destroy() def handle_collide(self): self.dx=-self.dx def end_game(self): end_message=games.Message(value="Game Over", size=90, x=games.screen.width/2, y=games.screen.height/2, lifetime=250, after_death=games.screen.quit) games.screen.add(end_message) def main(): background_image=games.load_image("background.bmp", transparent=False) games.screen.background=background_image paddle_image=games.load_image("paddle.bmp") the_paddle=games.Sprite(image=paddle_image, x=10, y=games.mouse.y) games.screen.add(the_paddle) ball_image=games.load_image("ball.bmp") the_ball=games.Sprite(image=ball_image, x=630, y=200, dx=2, dy=2) games.screen.add(the_ball) games.mouse.is_visible=False games.screen.event_grab=True games.screen.mainloop() main()

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• HOW TO: Draggable legend in matplotlib

  - by Adam Fraser

  QUESTION: I'm drawing a legend on an axes object in matplotlib but the default positioning which claims to place it in a smart place doesn't seem to work. Ideally, I'd like to have the legend be draggable by the user. How can this be done? SOLUTION: Well, I found bits and pieces of the solution scattered among mailing lists. I've come up with a nice modular chunk of code that you can drop in and use... here it is: class DraggableLegend: def __init__(self, legend): self.legend = legend self.gotLegend = False legend.figure.canvas.mpl_connect('motion_notify_event', self.on_motion) legend.figure.canvas.mpl_connect('pick_event', self.on_pick) legend.figure.canvas.mpl_connect('button_release_event', self.on_release) legend.set_picker(self.my_legend_picker) def on_motion(self, evt): if self.gotLegend: dx = evt.x - self.mouse_x dy = evt.y - self.mouse_y loc_in_canvas = self.legend_x + dx, self.legend_y + dy loc_in_norm_axes = self.legend.parent.transAxes.inverted().transform_point(loc_in_canvas) self.legend._loc = tuple(loc_in_norm_axes) self.legend.figure.canvas.draw() def my_legend_picker(self, legend, evt): return self.legend.legendPatch.contains(evt) def on_pick(self, evt): if evt.artist == self.legend: bbox = self.legend.get_window_extent() self.mouse_x = evt.mouseevent.x self.mouse_y = evt.mouseevent.y self.legend_x = bbox.xmin self.legend_y = bbox.ymin self.gotLegend = 1 def on_release(self, event): if self.gotLegend: self.gotLegend = False ...and in your code... def draw(self): ax = self.figure.add_subplot(111) scatter = ax.scatter(np.random.randn(100), np.random.randn(100)) legend = DraggableLegend(ax.legend()) I emailed the Matplotlib-users group and John Hunter was kind enough to add my solution it to SVN HEAD. On Thu, Jan 28, 2010 at 3:02 PM, Adam Fraser wrote: I thought I'd share a solution to the draggable legend problem since it took me forever to assimilate all the scattered knowledge on the mailing lists... Cool -- nice example. I added the code to legend.py. Now you can do leg = ax.legend() leg.draggable() to enable draggable mode. You can repeatedly call this func to toggle the draggable state. I hope this is helpful to people working with matplotlib.

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• Beginner problems with references to arrays in python 3.1.1

  - by Protean

  As part of the last assignment in a beginner python programing class, I have been assigned a traveling sales man problem. I settled on a recursive function to find each permutation and the sum of the distances between the destinations, however, I am have a lot of problems with references. Arrays in different instances of the Permute and Main functions of TSP seem to be pointing to the same reference. from math import sqrt class TSP: def __init__(self): self.CartisianCoordinates = [['A',[1,1]], ['B',[2,2]], ['C',[2,1]], ['D',[1,2]], ['E',[3,3]]] self.Array = [] self.Max = 0 self.StoredList = ['',0] def Distance(self, i1, i2): x1 = self.CartisianCoordinates[i1][1][0] y1 = self.CartisianCoordinates[i1][1][1] x2 = self.CartisianCoordinates[i2][1][0] y2 = self.CartisianCoordinates[i2][1][1] return sqrt(pow((x2 - x1), 2) + pow((y2 - y1), 2)) def Evaluate(self): temparray = [] Data = [] for i in range(len(self.CartisianCoordinates)): Data.append([]) for i1 in range(len(self.CartisianCoordinates)): for i2 in range(len(self.CartisianCoordinates)): if i1 != i2: temparray.append(self.Distance(i1, i2)) else: temparray.append('X') Data[i1] = temparray temparray = [] self.Array = Data self.Max = len(Data) def Permute(self,varray,index,vcarry,mcarry): #Problem Class array = varray[:] carry = vcarry[:] for i in range(self.Max): print ('ARRAY:', array) print (index,i,carry,array[index][i]) if array[index][i] != 'X': carry[0] += self.CartisianCoordinates[i][0] carry[1] += array[index][i] if len(carry) != self.Max: temparray = array[:] for j in range(self.Max):temparray[j][i] = 'X' index = i mcarry += self.Permute(temparray,index,carry,mcarry) else: return mcarry print ('pass',mcarry) return mcarry def Main(self): out = [] self.Evaluate() for i in range(self.Max): array = self.Array[:] #array appears to maintain the same reference after each copy, resulting in an incorrect array being passed to Permute after the first iteration. print (self.Array[:]) for j in range(self.Max):array[j][i] = 'X' print('I:', i, array) out.append(self.Permute(array,i,[str(self.CartisianCoordinates[i][0]),0],[])) return out SalesPerson = TSP() print(SalesPerson.Main()) It would be greatly appreciated if you could provide me with help in solving the reference problems I am having. Thank you.

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• Windows 8.1 Will Start Encrypting Hard Drives By Default: Everything You Need to Know

  - by Chris Hoffman

  Windows 8.1 will automatically encrypt the storage on modern Windows PCs. This will help protect your files in case someone steals your laptop and tries to get at them, but it has important ramifications for data recovery. Previously, “BitLocker” was available on Professional and Enterprise editions of Windows, while “Device Encryption” was available on Windows RT and Windows Phone. Device encryption is included with all editions of Windows 8.1 — and it’s on by default. When Your Hard Drive Will Be Encrypted Windows 8.1 includes “Pervasive Device Encryption.” This works a bit differently from the standard BitLocker feature that has been included in Professional, Enterprise, and Ultimate editions of Windows for the past few versions. Before Windows 8.1 automatically enables Device Encryption, the following must be true: The Windows device “must support connected standby and meet the Windows Hardware Certification Kit (HCK) requirements for TPM and SecureBoot on ConnectedStandby systems.”  (Source) Older Windows PCs won’t support this feature, while new Windows 8.1 devices you pick up will have this feature enabled by default. When Windows 8.1 installs cleanly and the computer is prepared, device encryption is “initialized” on the system drive and other internal drives. Windows uses a clear key at this point, which is removed later when the recovery key is successfully backed up. The PC’s user must log in with a Microsoft account with administrator privileges or join the PC to a domain. If a Microsoft account is used, a recovery key will be backed up to Microsoft’s servers and encryption will be enabled. If a domain account is used, a recovery key will be backed up to Active Directory Domain Services and encryption will be enabled. If you have an older Windows computer that you’ve upgraded to Windows 8.1, it may not support Device Encryption. If you log in with a local user account, Device Encryption won’t be enabled. If you upgrade your Windows 8 device to Windows 8.1, you’ll need to enable device encryption, as it’s off by default when upgrading. Recovering An Encrypted Hard Drive Device encryption means that a thief can’t just pick up your laptop, insert a Linux live CD or Windows installer disc, and boot the alternate operating system to view your files without knowing your Windows password. It means that no one can just pull the hard drive from your device, connect the hard drive to another computer, and view the files. We’ve previously explained that your Windows password doesn’t actually secure your files. With Windows 8.1, average Windows users will finally be protected with encryption by default. However, there’s a problem — if you forget your password and are unable to log in, you’d also be unable to recover your files. This is likely why encryption is only enabled when a user logs in with a Microsoft account (or connects to a domain). Microsoft holds a recovery key, so you can gain access to your files by going through a recovery process. As long as you’re able to authenticate using your Microsoft account credentials — for example, by receiving an SMS message on the cell phone number connected to your Microsoft account — you’ll be able to recover your encrypted data. With Windows 8.1, it’s more important than ever to configure your Microsoft account’s security settings and recovery methods so you’ll be able to recover your files if you ever get locked out of your Microsoft account. Microsoft does hold the recovery key and would be capable of providing it to law enforcement if it was requested, which is certainly a legitimate concern in the age of PRISM. However, this encryption still provides protection from thieves picking up your hard drive and digging through your personal or business files. If you’re worried about a government or a determined thief who’s capable of gaining access to your Microsoft account, you’ll want to encrypt your hard drive with software that doesn’t upload a copy of your recovery key to the Internet, such as TrueCrypt. How to Disable Device Encryption There should be no real reason to disable device encryption. If nothing else, it’s a useful feature that will hopefully protect sensitive data in the real world where people — and even businesses — don’t enable encryption on their own. As encryption is only enabled on devices with the appropriate hardware and will be enabled by default, Microsoft has hopefully ensured that users won’t see noticeable slow-downs in performance. Encryption adds some overhead, but the overhead can hopefully be handled by dedicated hardware. If you’d like to enable a different encryption solution or just disable encryption entirely, you can control this yourself. To do so, open the PC settings app — swipe in from the right edge of the screen or press Windows Key + C, click the Settings icon, and select Change PC settings. Navigate to PC and devices -> PC info. At the bottom of the PC info pane, you’ll see a Device Encryption section. Select Turn Off if you want to disable device encryption, or select Turn On if you want to enable it — users upgrading from Windows 8 will have to enable it manually in this way. Note that Device Encryption can’t be disabled on Windows RT devices, such as Microsoft’s Surface RT and Surface 2. If you don’t see the Device Encryption section in this window, you’re likely using an older device that doesn’t meet the requirements and thus doesn’t support Device Encryption. For example, our Windows 8.1 virtual machine doesn’t offer Device Encryption configuration options. This is the new normal for Windows PCs, tablets, and devices in general. Where files on typical PCs were once ripe for easy access by thieves, Windows PCs are now encrypted by default and recovery keys are sent to Microsoft’s servers for safe keeping. This last part may be a bit creepy, but it’s easy to imagine average users forgetting their passwords — they’d be very upset if they lost all their files because they had to reset their passwords. It’s also an improvement over Windows PCs being completely unprotected by default.     

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• Encrypting a non-linux partition with LUKS.

  - by linuxn00b

  I have a non-Linux partition I want to encrypt with LUKS. The goal is to be able to store it by itself on a device without Linux and access it from the device when needed with an Ubuntu Live CD. I know LUKS can't encrypt partitions in place, so I created another, unformatted partition of the EXACT same size (using GParted's "Round to MiB" option) and ran this command: sudo cryptsetup luksFormat /dev/xxx Where xxx is the partition's device name. Then I typed in my new passphrase and confirmed it. Oddly, the command exited immediately after, so I guess it doesn't encrypt the entire partition right away? Anyway, then I ran this command: sudo cryptsetup luksOpen /dev/xxx xxx Then I tried copying the contents of the existing partition (call it yyy) to the encrypted one like this: sudo dd if=/dev/yyy of=/dev/mapper/xxx bs=1MB and it ran for a while, but exited with this: dd: writing `/dev/mapper/xxx': No space left on device just before writing the last MB. I take this to mean the contents of yyy was truncated when it was copied to xxx, because I have dd'd it before, and whenever I have dd'd to a partition of the exact same size, I never get that error. (and fdisk reports they are the same size in blocks). After a little Googling I discovered all luksFormat'ted partitions have a custom header followed by the encrypted contents. So it appears I need to create a partition exactly the size of the old one + however many bytes a LUKS header is. What size should the destination partition be, no. 1, and no. 2, am I even on the right track here? UPDATE I found this in the LUKS FAQ: I think this is overly complicated. Is there an alternative? Yes, you can use plain dm-crypt. It does not allow multiple passphrases, but on the plus side, it has zero on disk description and if you overwrite some part of a plain dm-crypt partition, exactly the overwritten parts are lost (rounded up to sector borders). So perhaps I shouldn't be using LUKS at all?

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• Encrypting your SQL Server Passwords in Powershell

  - by laerte

  A couple of months ago, a friend of mine who is now bewitched by the seemingly supernatural abilities of Powershell (+1 for the team) asked me what, initially, appeared to be a trivial question: "Laerte, I do not have the luxury of being able to work with my SQL servers through Windows Authentication, and I need a way to automatically pass my username and password. How would you suggest I do this?" Given that I knew he, like me, was using the SQLPSX modules (an open source project created by Chad Miller; a fantastic library of reusable functions and PowerShell scripts), I merrily replied, "Simply pass the Username and Password in SQLPSX functions". He rather pointed responded: "My friend, I might as well pass: Username-'Me'-password 'NowEverybodyKnowsMyPassword'" As I do have the pleasure of working with Windows Authentication, I had not really thought this situation though yet (and thank goodness I only revealed my temporary ignorance to a friend, and the embarrassment was minimized). After discussing this puzzle with Chad Miller, he showed me some code for saving passwords on SQL Server Tables, which he had demo'd in his Powershell ETL session at Tampa SQL Saturday (and you can download the scripts from here). The solution seemed to be pretty much ready to go, so I showed it to my Authentication-impoverished friend, only to discover that we were only half-way there: "That's almost what I want, but the details need to be stored in my local txt file, together with the names of the servers that I'll actually use the Powershell scripts on. Something like: Server1,UserName,Password Server2,UserName,Password" I thought about it for just a few milliseconds (Ha! Of course I'm not telling you how long it actually took me, I have to do my own marketing, after all) and the solution was finally ready. First , we have to download Library-StringCripto (with many thanks to Steven Hystad), which is composed of two functions: One for encryption and other for decryption, both of which are used to manage the password. If you want to know more about the library, you can see more details in the help functions. Next, we have to create a txt file with your encrypted passwords:$ServerName = "Server1" $UserName = "Login1" $Password = "Senha1" $PasswordToEncrypt = "YourPassword" $UserNameEncrypt = Write-EncryptedString -inputstring $UserName -Password $PasswordToEncrypt $PasswordEncrypt = Write-EncryptedString -inputstring $Password -Password $PasswordToEncrypt "$($Servername),$($UserNameEncrypt),$($PasswordEncrypt)" | Out-File c:\temp\ServersSecurePassword.txt -Append $ServerName = "Server2" $UserName = "Login2" $Password = "senha2" $PasswordToEncrypt = "YourPassword" $UserNameEncrypt = Write-EncryptedString -inputstring $UserName -Password $PasswordToEncrypt $PasswordEncrypt = Write-EncryptedString -inputstring $Password -Password $PasswordToEncrypt "$($Servername),$($UserNameEncrypt),$($PasswordEncrypt)" | Out-File c:\temp\ ServersSecurePassword.txt -Append .And in the c:\temp\ServersSecurePassword.txt file which we've just created, you will find your Username and Password, all neatly encrypted. Let's take a look at what the txt looks like: .and in case you're wondering, Server names, Usernames and Passwords are all separated by commas. Decryption is actually much more simple:Read-EncryptedString -InputString $EncryptString -password "YourPassword" (Just remember that the Password you're trying to decrypt must be exactly the same as the encrypted phrase.) Finally, just to show you how smooth this solution is, let's say I want to use the Invoke-DBMaint function from SQLPSX to perform a checkdb on a system database: it's just a case of split, decrypt and be happy!Get-Content c:\temp\ServerSecurePassword.txt | foreach { [array] $Split = ($_).split(",") Invoke-DBMaint -server $($Split[0]) -UserName (Read-EncryptedString -InputString $Split[1] -password "YourPassword" ) -Password (Read-EncryptedString -InputString $Split[2] -password "YourPassword" ) -Databases "SYSTEM" -Action "CHECK_DB" -ReportOn c:\Temp } This is why I love Powershell.

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• Encrypting and decrypting single file with master password and passphrase

  - by Iori

  Last night my system shutdown unexpectedly and when i restart it, it gave me superblock error. will then i fixed a little but. i was able to retrive my encrypted files which i encrypted my pgp public key but i was not able to retrive my private key or public key now i have ecrypted file which cannot be open because i have lost my private key. is there any way that i can encrypt my file by providing only master password and passphrase and no physical key or private key and when i am on another computer i can easily open it my same master password and passphrase. Thanks in advance

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• Walmart's Mobile Self-Checkout

  - by David Dorf

  Reuters recently reported that Walmart was testing an iPhone-based self-checkout at a store near its headquarters.  Consumers scan items as they're placed in the physical basket, then the virtual basket is transferred to an existing self-checkout station where payment is tendered.  A very solid solution, but not exactly original. Before we go further, let's look at the possible cost savings for Walmart.  According to the article: Pushing more shoppers to scan their own items and make payments without the help of a cashier could save Wal-Mart millions of dollars, Chief Financial Officer Charles Holley said on March 7. The company spends about $12 million in cashier wages every second at its Walmart U.S. stores. Um, yeah. Using back-of-the-napkin math, I calculated Walmart's cashiers are making $157k per hour.  A more accurate statement would be saving $12M per year for each second saved on the average transaction time.  So if this self-checkout approach saves 2 seconds per transaction on average, Walmart would save $24M per year on labor.  Maybe.  Sometimes that savings will be used to do other tasks in the store, so it may not directly translate to less employees. When I saw this approach demonstrated in Sweden, there were a few differences, which may or may not be in Walmart's plans.  First, the consumers were identified based on their loyalty card.  In order to offset the inevitable shrink, retailers need to save on labor but also increase basket size, typically via in-aisle promotions.  As they scan items, retailers should target promos, and that's easier to do if you know some shopping history.  Last I checked, Walmart had no loyalty program. Second, at the self-checkout station consumers were randomly selected for an audit in which they must re-scan all the items just like you do at a typical self-checkout.  If you were found to be stealing, your ability to use the system can be revoked.  That's a tough one in the US, especially when the system goes wrong, either by mistake or by lying.  At least in my view, the Swedes are bit more trustworthy than the people of Walmart. So while I think the idea of mobile self-checkout has merit, perhaps its not right for Walmart.

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• What is the proper name for this design pattern in Python?

  - by James

  In Python, is the proper name for the PersonXXX class below PersonProxy, PersonInterface, etc? import rest class PersonXXX(object): def __init__(self,db_url): self.resource = rest.Resource(db_url) def create(self,person): self.resource.post(person.data()) def get(self): pass def update(self): pass def delete(self): pass class Person(object): def __init__(self,name, age): self.name = name self.age = age def data(self): return dict(name=self.name,age=self.age)

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• self referencing tables, good or bad?

  - by NimChimpsky

  Representing geographical locations within an application, the design of the underlying data model suggests two clear options (or maybe more?). One table with a self referencing parent_id column uk - london (london parent id = UK id) or two tables, with a one to many relationship using a foreign key. My preference is for one self-refercing table as it easily allows to extend into as many sub regions as required. IN general do people veer away from self referencing tables, or are they A-OK ?

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• Creating deterministic key pairs in javascript for use in encrypting/decrypting/signing messages

  - by SlickTheNick

  So I have been searching everywhere and havn't been able to find anything with the sufficient information I need.. so Im a bit stumped on this one at the moment What I am trying to do is create a public/private key pair (like PGP) upon a users account creation, based on their passphrase and a random seed. The public key would be saved on the server, and ideally the private key would never be seen by the server whatsoever. The user could then sign in, and send a message to another user. Before the message is sent, the senders key pair would be re-generated on the fly based on their credentials (and maybe a password prompt) and used to encrypt the message. The receiver would then use their own re-generated private key to decrypt said message. The server itself should never see any plaintext passwords, private keys or readable messages. Bit unsure how on how I could go about implementing this. Iv been looking into PGP, specifically openPGP.js. The main trouble I am having is being able to regenerate the key-pair based off a specific seed. PGP seems to have a random output even if the inputs are the same. Storing the private key in a cookie or in HTML5 storage or something also isnt really an option, too unreliable. Can anyone point me in the right direction?

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• Security - "Encrypting Tablespaces"

  Encrypt tablespaces transparently—without affecting performance.

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• Why is my UIImageView blurred?

  - by Denis M

  I have a really weird problem with UIImageView. I have an image (an RGB png) 45x45 pixels which I add to the view. I can see that image is blurred after added to the view. Here is the same image in the simulator (left) and in Xcode (right): I have custom UIImageView class with this initWithImage code: - (id) initWithImage:(UIImage*) image { self = [super initWithImage:image]; self.frame = CGRectMake(0, 0, 45, 45); self.contentMode = UIViewContentModeScaleAspectFit; self.quantity = 1; if (self) { self.label = [[UITextField alloc]initWithFrame:CGRectMake(0,40,45,25)]; self.label.font = [UIFont systemFontOfSize:16]; self.label.borderStyle = UITextBorderStyleNone; self.label.enabled = TRUE; self.label.userInteractionEnabled = TRUE; self.label.delegate = self; self.label.keyboardType = UIKeyboardTypeNumbersAndPunctuation; self.label.textAlignment = UITextAlignmentCenter; } self.userInteractionEnabled = TRUE; // Prepare 3 buttons: count up, count down, and delete self.deleteButton = [UIButton buttonWithType:UIButtonTypeRoundedRect]; self.deleteButton.hidden = NO; self.deleteButton.userInteractionEnabled = YES; self.deleteButton.titleLabel.font = [UIFont systemFontOfSize:20]; self.deleteButton.titleLabel.textColor = [UIColor redColor]; [self.deleteButton setTitle:@"X" forState:UIControlStateNormal]; [self.deleteButton addTarget:self action:@selector(deleteIcon:) forControlEvents:UIControlEventTouchUpInside]; self.upCountButton = [UIButton buttonWithType:UIButtonTypeRoundedRect]; self.upCountButton.hidden = NO; self.upCountButton.userInteractionEnabled = YES; [self.upCountButton setTitle:@"+" forState:UIControlStateNormal]; [self.upCountButton addTarget:self action:@selector(addQuantity:) forControlEvents:UIControlEventTouchUpInside]; self.downCountButton = [UIButton buttonWithType:UIButtonTypeRoundedRect]; self.downCountButton.hidden = YES; self.downCountButton.userInteractionEnabled = YES; [self.downCountButton setTitle:@"-" forState:UIControlStateNormal]; [self.downCountButton addTarget:self action:@selector(removeQuantity:) forControlEvents:UIControlEventTouchUpInside]; return self; } I create it like this: UIImage *desertIcon = [UIImage imageNamed:@"desert.png"]; IconObj *desertIconView = [[IconObj alloc] initWithImage:desertIcon]; desertIconView.center = CGPointMake(265,VERTICAL_POINT_ICON); desertIconView.type = [IconObj TYPE_DESERT]; [self.view addSubview:desertIconView]; [desertIconView release]; Why would the displayed image be so than the one stored in a file?

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• Self-reference entity in Hibernate

  - by Marco

  Hi guys, I have an Action entity, that can have other Action objects as child in a bidirectional one-to-many relationship. The problem is that Hibernate outputs the following exception: "Repeated column in mapping for collection: DbAction.childs column: actionId" Below the code of the mapping: <?xml version="1.0"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"> <hibernate-mapping> <class name="DbAction" table="actions"> <id name="actionId" type="short" /> <property not-null="true" name="value" type="string" /> <set name="childs" table="action_action" cascade="all-delete-orphan"> <key column="actionId" /> <many-to-many column="actionId" unique="true" class="DbAction" /> </set> <join table="action_action" inverse="true" optional="false"> <key column="actionId" /> <many-to-one name="parentAction" column="actionId" not-null="true" class="DbAction" /> </join> </class> </hibernate-mapping>

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• Fluent NHibernate Self Referencing Many To Many

  - by Jeremy

  I have an entity called Books that can have a list of more books called RelatedBooks. The abbreviated Book entity looks something likes this: public class Book { public virtual long Id { get; private set; } public virtual IList<Book> RelatedBooks { get; set; } } Here is what the mapping looks like for this relationship HasManyToMany(x => x.RelatedBooks) .ParentKeyColumn("BookId") .ChildKeyColumn("RelatedBookId") .Table("RelatedBooks") .Cascade.SaveUpdate(); Here is a sample of the data that is then generated in the RelatedBooks table: BookId RelatedBookId 1 2 1 3 The problem happens when I Try to delete a book. If I delete the book that has an ID of 1, everything works ok and the RelatedBooks table has the two corresponding records removed. However if I try to delete the book with an ID of 3, I get the error "The DELETE statement conflicted with the REFERENCE constraint "FK5B54405174BAB605". The conflict occurred in database "Test", table "dbo.RelatedBooks", column 'RelatedBookId'". Basically what is happening is the Book cannot be deleted because the record in the RelatedBooks table that has a RelatedBookId of 3 is never deleted. How do I get that record to be deleted when I delete a book? EDIT After changing the Cascade from SaveUpdate() to All(), the same problem still exists if I try to delete the Book with an ID of 3. Also with Cascade set to All(), if delete the Book with and ID of 1, then all 3 books (ID's: 1, 2 and 3) are deleted so that won't work either. Looking at the SQL that is executed when the Book.Delete() method is called when I delete the Book with an ID of 3, it looks like the SELECT statement is looking at the wrong column (which I assume means that the SQL DELETE statment would make the same mistake, therefore never removing that record). Here is the SQL for the RelatedBook SELECT relatedboo0_.BookId as BookId3_ , relatedboo0_.RelatedBookId as RelatedB2_3_ , book1_.Id as Id14_0_ FROM RelatedBooks relatedboo0_ left outer join [Book] book1_ on relatedboo0_.RelatedBookId=book1_.Id WHERE relatedboo0_.BookId=3 The WHERE statment should look something like this for thie particular case: WHERE relatedboo0_.RelatedBookId = 3 SOLUTION Here is what I had to do to get it working for all cases Mapping: HasManyToMany(x => x.RelatedBooks) .ParentKeyColumn("BookId") .ChildKeyColumn("RelatedBookId") .Table("RelatedBooks"); Code: var book = currentSession.Get<Book>(bookId); if (book != null) { //Remove all of the Related Books book.RelatedBooks.Clear(); //Get all other books that have this book as a related book var booksWithRelated = currentSession.CreateCriteria<Book>() .CreateAlias("RelatedBooks", "br") .Add(Restrictions.Eq("br.Id", book.Id)) .List<Book>(); //Remove this book as a Related Book for all other Books foreach (var tempBook in booksWithRelated) { tempBook.RelatedBooks.Remove(book); tempBook.Save(); } //Delete the book book.Delete(); }

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• nHibernate Self Join Mapping

  - by kmoo01

  Hi Guys, This is probably incredibly simple, but I just cant see the wood for the trees at the moment. For brevity, I would like to model a word object, that has related words to it (synonyms), In doing so I could have the following mappings: <class name="Word" table="bs_word"> <id name="Id" column="WordId" type="Int32" unsaved-value="-1"> <generator class="native"> <param name="sequence"></param> </generator> </id> <property name="Key" column="word" type="String" length="50" /> <many-to-one name="SynonymGroup" class="BS.Core.Domain.Synonym, BS.Core" column="SynonymId" lazy="false"/> <class name="Synonym" table="bs_Synonym"> <id name="Id" column="SynonymId" type="Int32" unsaved-value="-1"> <generator class="native"> <param name="sequence"></param> </generator> </id> <property name="Alias" column="Alias" type="String" length="50" /> <bag name="Words" cascade="none" lazy="false" inverse="true"> <key column="SynonymId" /> <one-to-many class="Word" /> </bag> Mapping it like this would mean for a given word, I can access related words (synonyms) like this: word.SynonymGroup.Words However I would like to know if it is possible to map a bag of objects on an instance of a word object...if that makes sense, so I can access the related words like this: word.Words I've tried playing around with the map element, and composite elements, all to no avail - so I was wondering if some kind person could point me in the right direction? ta, kmoo01

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• How to self-attest your programming abilities?

  - by Ivo Danihelka

  What is a good test of your smartness vs. stupidity? Is Google Code Jam a good test for that? Or would you suggest something else? I want to know whether I'm a good programmer or not.

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• Sql query to get the GrandFather name by doing a self join

  - by mahesh

  Hello all , Can any one please give me the query to get the child name and his grand fathers name For eg - if i have a table Relationships in the i have childid and fatherid columns so how will i get the grandfather, i can easily get the father name by using a join but for grandfather i need to do joins 2 times so can any one help me with this D.Mahesh

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• software engineer self improvment [closed]

  - by radi

  hi all , i am a 4th year student at software engineering department , at my faculty we study software engineering basics (unified process , uml , design patterns ) , so : what about these technics ? do i need to learn another (or new such as agile) ? what about programming languages (frameworks) ? what i need to learn ? why ? thanks

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• Need help finding a good curriculum/methodology for self-teaching to program from scratch

  - by BrotherGA2

  My friend and I have both dedicated ourselves to learning the essentials of programming by June of this year from nearly no programming experience. I have done some research and have come to the conclusion that using the Python language will be the best for us, but I am open to suggestions with good reasoning behind them. My motives for learning programming are: Potential Career Path to be able to create programs that can: solve problems; entertain, i.e. useful applications and games. Online college lectures + book (which I am willing to purchase) sounds like a good combination, but I do not know which would be most suitable for me. tl;dr: What I would like to find from the excellent people here is the following: a good, potentially best, programming course and/or book that is well structured and uses good pedagogy so that a person dedicated to learn programming may do so by following its curriculum (or use it to develop a curriculum) over the course of a few months. Thanks! (I apologize if this type of question is not considered proper etiquette, but I haven't found a consensus on this, and would like some guidance beyond the research I've already done)

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• Descendent or self selector in jQuery

  - by tttppp

  I want to search for all elements with class needle in all elements returned by jQuery('.haystack') and have tried jQuery('.haystack .needle'), but this doesn't seem to pick up the case where an element has both classes. Is there a selector that will do this?

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• Self-signed ceritificates for many users/browsers/sites

  - by Demiurg

  Here is my problem - I have a lot of users using different browsers accessing many internal web sites using https. I can create my own Certificate Authority, than create a certificate for each server and after that have all the users import it. Obviously, it cannot work in reality - there are too many users and too many sites, and some sites will be added in the future. I'm looking for a way to automate this. Is there a way to create a certificate so that all major browsers (IE, FF, Opera, Chrome and Safari) would trust it for all servers ? If so, what is the best way to install it automatically in all major browsers ?

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• Simple Self Join Query Bad Performance

  - by user1514042

  Could anyone advice on how do I improve the performance of the following query. Note, the problem seems to be caused by where clause. Data (table contains a huge set of rows - 500K+, the set of parameters it's called with assums the return of 2-5K records per query, which takes 8-10 minutes currently): USE [SomeDb] GO SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO CREATE TABLE [dbo].[Data]( [x] [money] NOT NULL, [y] [money] NOT NULL, CONSTRAINT [PK_Data] PRIMARY KEY CLUSTERED ( [x] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] ) ON [PRIMARY] GO The Query select top 10000 s.x as sx, e.x as ex, s.y as sy, e.y as ey, e.y - s.y as y_delta, e.x - s.x as x_delta from Data s inner join Data e on e.x > s.x and e.x - s.x between xFrom and xTo --where e.y - s.y > @yDelta -- when uncommented causes a huge delay Update 1 - Execution Plan <?xml version="1.0" encoding="utf-16"?> <ShowPlanXML xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" Version="1.2" Build="11.0.2100.60" xmlns="http://schemas.microsoft.com/sqlserver/2004/07/showplan"> <BatchSequence> <Batch> <Statements> <StmtSimple StatementCompId="1" StatementEstRows="100" StatementId="1" StatementOptmLevel="FULL" StatementOptmEarlyAbortReason="GoodEnoughPlanFound" StatementSubTreeCost="0.0263655" StatementText="select top 100&#xD;&#xA;s.x as sx,&#xD;&#xA;e.x as ex,&#xD;&#xA;s.y as sy,&#xD;&#xA;e.y as ey,&#xD;&#xA;e.y - s.y as y_delta,&#xD;&#xA;e.x - s.x as x_delta&#xD;&#xA;from Data s &#xD;&#xA; inner join Data e&#xD;&#xA; on e.x &gt; s.x and e.x - s.x between 100 and 105&#xD;&#xA;where e.y - s.y &gt; 0.01&#xD;&#xA;" StatementType="SELECT" QueryHash="0xAAAC02AC2D78CB56" QueryPlanHash="0x747994153CB2D637" RetrievedFromCache="true"> <StatementSetOptions ANSI_NULLS="true" ANSI_PADDING="true" ANSI_WARNINGS="true" ARITHABORT="true" CONCAT_NULL_YIELDS_NULL="true" NUMERIC_ROUNDABORT="false" QUOTED_IDENTIFIER="true" /> <QueryPlan DegreeOfParallelism="0" NonParallelPlanReason="NoParallelPlansInDesktopOrExpressEdition" CachedPlanSize="24" CompileTime="13" CompileCPU="13" CompileMemory="424"> <MemoryGrantInfo SerialRequiredMemory="0" SerialDesiredMemory="0" /> <OptimizerHardwareDependentProperties EstimatedAvailableMemoryGrant="52199" EstimatedPagesCached="14561" EstimatedAvailableDegreeOfParallelism="4" /> <RelOp AvgRowSize="55" EstimateCPU="1E-05" EstimateIO="0" EstimateRebinds="0" EstimateRewinds="0" EstimatedExecutionMode="Row" EstimateRows="100" LogicalOp="Compute Scalar" NodeId="0" Parallel="false" PhysicalOp="Compute Scalar" EstimatedTotalSubtreeCost="0.0263655"> <OutputList> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[s]" Column="x" /> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[s]" Column="y" /> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[e]" Column="x" /> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[e]" Column="y" /> <ColumnReference Column="Expr1004" /> <ColumnReference Column="Expr1005" /> </OutputList> <ComputeScalar> <DefinedValues> <DefinedValue> <ColumnReference Column="Expr1004" /> <ScalarOperator ScalarString="[SomeDb].[dbo].[Data].[y] as [e].[y]-[SomeDb].[dbo].[Data].[y] as [s].[y]"> <Arithmetic Operation="SUB"> <ScalarOperator> <Identifier> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[e]" Column="y" /> </Identifier> </ScalarOperator> <ScalarOperator> <Identifier> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[s]" Column="y" /> </Identifier> </ScalarOperator> </Arithmetic> </ScalarOperator> </DefinedValue> <DefinedValue> <ColumnReference Column="Expr1005" /> <ScalarOperator ScalarString="[SomeDb].[dbo].[Data].[x] as [e].[x]-[SomeDb].[dbo].[Data].[x] as [s].[x]"> <Arithmetic Operation="SUB"> <ScalarOperator> <Identifier> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[e]" Column="x" /> </Identifier> </ScalarOperator> <ScalarOperator> <Identifier> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[s]" Column="x" /> </Identifier> </ScalarOperator> </Arithmetic> </ScalarOperator> </DefinedValue> </DefinedValues> <RelOp AvgRowSize="39" EstimateCPU="1E-05" EstimateIO="0" EstimateRebinds="0" EstimateRewinds="0" EstimatedExecutionMode="Row" EstimateRows="100" LogicalOp="Top" NodeId="1" Parallel="false" PhysicalOp="Top" EstimatedTotalSubtreeCost="0.0263555"> <OutputList> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[s]" Column="x" /> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[s]" Column="y" /> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[e]" Column="x" /> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[e]" Column="y" /> </OutputList> <RunTimeInformation> <RunTimeCountersPerThread Thread="0" ActualRows="100" ActualEndOfScans="1" ActualExecutions="1" /> </RunTimeInformation> <Top RowCount="false" IsPercent="false" WithTies="false"> <TopExpression> <ScalarOperator ScalarString="(100)"> <Const ConstValue="(100)" /> </ScalarOperator> </TopExpression> <RelOp AvgRowSize="39" EstimateCPU="151828" EstimateIO="0" EstimateRebinds="0" EstimateRewinds="0" EstimatedExecutionMode="Row" EstimateRows="100" LogicalOp="Inner Join" NodeId="2" Parallel="false" PhysicalOp="Nested Loops" EstimatedTotalSubtreeCost="0.0263455"> <OutputList> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[s]" Column="x" /> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[s]" Column="y" /> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[e]" Column="x" /> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[e]" Column="y" /> </OutputList> <RunTimeInformation> <RunTimeCountersPerThread Thread="0" ActualRows="100" ActualEndOfScans="0" ActualExecutions="1" /> </RunTimeInformation> <NestedLoops Optimized="false"> <OuterReferences> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[e]" Column="x" /> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[e]" Column="y" /> </OuterReferences> <RelOp AvgRowSize="23" EstimateCPU="1.80448" EstimateIO="3.76461" EstimateRebinds="0" EstimateRewinds="0" EstimatedExecutionMode="Row" EstimateRows="1" LogicalOp="Clustered Index Scan" NodeId="3" Parallel="false" PhysicalOp="Clustered Index Scan" EstimatedTotalSubtreeCost="0.0032831" TableCardinality="1640290"> <OutputList> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[e]" Column="x" /> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[e]" Column="y" /> </OutputList> <RunTimeInformation> <RunTimeCountersPerThread Thread="0" ActualRows="15225" ActualEndOfScans="0" ActualExecutions="1" /> </RunTimeInformation> <IndexScan Ordered="false" ForcedIndex="false" ForceScan="false" NoExpandHint="false"> <DefinedValues> <DefinedValue> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[e]" Column="x" /> </DefinedValue> <DefinedValue> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[e]" Column="y" /> </DefinedValue> </DefinedValues> <Object Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Index="[PK_Data]" Alias="[e]" IndexKind="Clustered" /> </IndexScan> </RelOp> <RelOp AvgRowSize="23" EstimateCPU="0.902317" EstimateIO="1.88387" EstimateRebinds="1" EstimateRewinds="0" EstimatedExecutionMode="Row" EstimateRows="100" LogicalOp="Clustered Index Seek" NodeId="4" Parallel="false" PhysicalOp="Clustered Index Seek" EstimatedTotalSubtreeCost="0.0263655" TableCardinality="1640290"> <OutputList> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[s]" Column="x" /> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[s]" Column="y" /> </OutputList> <RunTimeInformation> <RunTimeCountersPerThread Thread="0" ActualRows="100" ActualEndOfScans="15224" ActualExecutions="15225" /> </RunTimeInformation> <IndexScan Ordered="true" ScanDirection="FORWARD" ForcedIndex="false" ForceSeek="false" ForceScan="false" NoExpandHint="false" Storage="RowStore"> <DefinedValues> <DefinedValue> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[s]" Column="x" /> </DefinedValue> <DefinedValue> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[s]" Column="y" /> </DefinedValue> </DefinedValues> <Object Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Index="[PK_Data]" Alias="[s]" IndexKind="Clustered" /> <SeekPredicates> <SeekPredicateNew> <SeekKeys> <EndRange ScanType="LT"> <RangeColumns> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[s]" Column="x" /> </RangeColumns> <RangeExpressions> <ScalarOperator ScalarString="[SomeDb].[dbo].[Data].[x] as [e].[x]"> <Identifier> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[e]" Column="x" /> </Identifier> </ScalarOperator> </RangeExpressions> </EndRange> </SeekKeys> </SeekPredicateNew> </SeekPredicates> <Predicate> <ScalarOperator ScalarString="([SomeDb].[dbo].[Data].[x] as [e].[x]-[SomeDb].[dbo].[Data].[x] as [s].[x])&gt;=($100.0000) AND ([SomeDb].[dbo].[Data].[x] as [e].[x]-[SomeDb].[dbo].[Data].[x] as [s].[x])&lt;=($105.0000) AND ([SomeDb].[dbo].[Data].[y] as [e].[y]-[SomeDb].[dbo].[Data].[y] as [s].[y])&gt;(0.01)"> <Logical Operation="AND"> <ScalarOperator> <Compare CompareOp="GE"> <ScalarOperator> <Arithmetic Operation="SUB"> <ScalarOperator> <Identifier> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[e]" Column="x" /> </Identifier> </ScalarOperator> <ScalarOperator> <Identifier> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[s]" Column="x" /> </Identifier> </ScalarOperator> </Arithmetic> </ScalarOperator> <ScalarOperator> <Const ConstValue="($100.0000)" /> </ScalarOperator> </Compare> </ScalarOperator> <ScalarOperator> <Compare CompareOp="LE"> <ScalarOperator> <Arithmetic Operation="SUB"> <ScalarOperator> <Identifier> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[e]" Column="x" /> </Identifier> </ScalarOperator> <ScalarOperator> <Identifier> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[s]" Column="x" /> </Identifier> </ScalarOperator> </Arithmetic> </ScalarOperator> <ScalarOperator> <Const ConstValue="($105.0000)" /> </ScalarOperator> </Compare> </ScalarOperator> <ScalarOperator> <Compare CompareOp="GT"> <ScalarOperator> <Arithmetic Operation="SUB"> <ScalarOperator> <Identifier> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[e]" Column="y" /> </Identifier> </ScalarOperator> <ScalarOperator> <Identifier> <ColumnReference Database="[SomeDb]" Schema="[dbo]" Table="[Data]" Alias="[s]" Column="y" /> </Identifier> </ScalarOperator> </Arithmetic> </ScalarOperator> <ScalarOperator> <Const ConstValue="(0.01)" /> </ScalarOperator> </Compare> </ScalarOperator> </Logical> </ScalarOperator> </Predicate> </IndexScan> </RelOp> </NestedLoops> </RelOp> </Top> </RelOp> </ComputeScalar> </RelOp> </QueryPlan> </StmtSimple> </Statements> </Batch> </BatchSequence> </ShowPlanXML>

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