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  • howto distinguish composition and self-typing use-cases

    - by ayvango
    Scala has two instruments for expressing object composition: original self-type concept and well known trivial composition. I'm curios what situations I should use which in. There are obvious differences in their applicability. Self-type requires you to use traits. Object composition allows you to change extensions on run-time with var declaration. Leaving technical details behind I can figure two indicators to help with classification of use cases. If some object used as combinator for a complex structure such as tree or just have several similar typed parts (1 car to 4 wheels relation) than it should use composition. There is extreme opposite use case. Lets assume one trait become too big to clearly observe it and it got split. It is quite natural that you should use self-types for this case. That rules are not absolute. You may do extra work to convert code between this techniques. e.g. you may replace 4 wheels composition with self-typing over Product4. You may use Cake[T <: MyType] {part : MyType} instead of Cake { this : MyType => } for cake pattern dependencies. But both cases seem counterintuitive and give you extra work. There are plenty of boundary use cases although. One-to-one relations is very hard to decide with. Is there any simple rule to decide what kind of technique is preferable? self-type makes you classes abstract, composition makes your code verbose. self-type gives your problems with blending namespaces and also gives you extra typing for free (you got not just a cocktail of two elements but gasoline-motor oil cocktail known as a petrol bomb). How can I choose between them? What hints are there? Update: Let us discuss the following example: Adapter pattern. What benefits it has with both selt-typing and composition approaches?

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  • SQL SERVER – Subquery or Join – Various Options – SQL Server Engine Knows the Best – Part 2

    - by pinaldave
    This blog post is part 2 of the earlier written article SQL SERVER – Subquery or Join – Various Options – SQL Server Engine knows the Best by Paulo R. Pereira. Paulo has left excellent comment to earlier article once again proving the point that SQL Server Engine is smart enough to figure out the best plan itself and uses the same for the query. Let us go over his comment as he has posted. “I think IN or EXISTS is the best choice, because there is a little difference between ‘Merge Join’ of query with JOIN (Inner Join) and the others options (Left Semi Join), and JOIN can give more results than IN or EXISTS if the relationship is 1:0..N and not 1:0..1. And if I try use NOT IN and NOT EXISTS the query plan is different from LEFT JOIN too (Left Anti Semi Join vs. Left Outer Join + Filter). So, I found a case where EXISTS has a different query plan than IN or ANY/SOME:” USE AdventureWorks GO -- use of SOME SELECT * FROM HumanResources.Employee E WHERE E.EmployeeID = SOME ( SELECT EA.EmployeeID FROM HumanResources.EmployeeAddress EA UNION ALL SELECT EA.EmployeeID FROM HumanResources.EmployeeDepartmentHistory EA ) -- use of IN SELECT * FROM HumanResources.Employee E WHERE E.EmployeeID IN ( SELECT EA.EmployeeID FROM HumanResources.EmployeeAddress EA UNION ALL SELECT EA.EmployeeID FROM HumanResources.EmployeeDepartmentHistory EA ) -- use of EXISTS SELECT * FROM HumanResources.Employee E WHERE EXISTS ( SELECT EA.EmployeeID FROM HumanResources.EmployeeAddress EA UNION ALL SELECT EA.EmployeeID FROM HumanResources.EmployeeDepartmentHistory EA ) When looked into execution plan of the queries listed above indeed we do get different plans for queries and SQL Server Engines creates the best (least cost) plan for each query. Click on image to see larger images. Thanks Paulo for your wonderful contribution. Reference : Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, Readers Contribution, SQL, SQL Authority, SQL Joins, SQL Optimization, SQL Performance, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • python: variable not getting defined after several conditionals

    - by Protean
    For some reason this program is saying that 'switch' is not defined. What is going on? #PYTHON 3.1.1 class mysrt: def __init__(self): self.DATA = open('ORDER.txt', 'r') self.collect = 0 cache1 = str(self.DATA.readlines()) cache2 = [] for i in range(len(cache1)): if cache1[i] == '*': if self.collect == 0: self.collect = 1 elif self.collect == 1: self.collect = 0 elif self.collect == 1: cache2.append(cache1[i]) self.ORDER = cache2 self.ARRAY = [] self.GLOBALi = 0 self.GLOBALmax = range(len(self.ORDER)) self.GLOBALc = [] self.GLOBALl = [] def sorter(self, array): CACHE_LIST_1 = [] CACHE_LIST_2 = [] i = 0 for ORDERi in range(len(self.ORDER)): for ARRAYi in range(len(array)): CACHE = array[ARRAYi] if CACHE[self.GLOBALi] == self.ORDER[ORDERi]: CACHE_LIST_1.append(CACHE) else: CACHE_LIST_2.append(CACHE) for i in range(len(CACHE_LIST_1)): if CACHE_LIST_1[0] == CACHE_LIST_1[i] or range(len(CACHE_LIST_1)) == 1: switch = 1 print ('1') else: switch = 0 print ('0') break if switch == 1: self.GLOBALl += CACHE_LIST_1 + self.GLOBALc self.GLOBALi = 0 self.GLOBALc = [] else: self.GLOBALi += 1 self.GLOBALc += CACHE_LIST_2 mysrt.sorter(CACHE) return (self.GLOBALl) #GLOBALi =0 # if range(len(self.GLOBALc)) =! range(len(self.ARRAY)) array = ['ape', 'cow','dog','bat'] ORDER_FILE = [] mysort = mysrt() print (mysort.sorter(array))

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  • generate correctly a self signed certificate Zimbra

    - by rkmax
    I have a Single mail server with Zimbra 8.0.0 for generate certificate I'm following Generate the cert. ORG=MyOrganization CN=mail.mydomain.com COUNTRY=myCountry CITY=myCity /opt/zimbra/bin/zmcertmgr createcrt -new -days 365 -subject "/C=$COUNTRY/ST=N/A/L=$CITY/O=$ORG/OU=ZCS/CN=$CN" /opt/zimbra/bin/zmcertmgr deploycrt self -allserver su - zimbra "zmcontrol restart" Veririficate with /opt/zimbra/bin/zmcertmgr viewdeployedcrt. i can see the new cert In Chrome go to https://mail.mydomain.com and export the .cer test in a Windows client certutil.exe -addstore root \path\to\exported.cert root "Root Certification Authorities trusted" You can add a root certificate to the root store CertUtil:-addstore command error: 0x8007000d (WIN32: 13) CertUtil: Invalid data. even from chrome i've tried to add the cert without successful results. can anyone help me with this problem?

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  • Creating self-signed SSL on IIS - Remote access problem

    - by ile
    I followed these instructions to create self-signed ssl: http://www.visualwin.com/SelfSSL/ (I opened SelfSSL and typed selfssl /T) When I access https: //localhost/ than it works, but when I try to access it remotely (i set up my router to port forward to localhost), for example https: //myip the page does not load. Also, I noticed one other thing. When I access localhost locally then I am asked to enter user/pass, but if I access remotely the I get the following warning: Under Construction The site you were trying to reach does not currently have a default page. It may be in the process of being upgraded and configured. ... I don't know if it is related with this but I hope someone know the answer. Thanks, Ile

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  • Why am I getting a " instance has no attribute '__getitem__' " error?

    - by Kevin Yusko
    Here's the code: class BinaryTree: def __init__(self,rootObj): self.key = rootObj self.left = None self.right = None root = [self.key, self.left, self.right] def getRootVal(root): return root[0] def setRootVal(newVal): root[0] = newVal def getLeftChild(root): return root[1] def getRightChild(root): return root[2] def insertLeft(self,newNode): if self.left == None: self.left = BinaryTree(newNode) else: t = BinaryTree(newNode) t.left = self.left self.left = t def insertRight(self,newNode): if self.right == None: self.right = BinaryTree(newNode) else: t = BinaryTree(newNode) t.right = self.right self.right = t def buildParseTree(fpexp): fplist = fpexp.split() pStack = Stack() eTree = BinaryTree('') pStack.push(eTree) currentTree = eTree for i in fplist: if i == '(': currentTree.insertLeft('') pStack.push(currentTree) currentTree = currentTree.getLeftChild() elif i not in '+-*/)': currentTree.setRootVal(eval(i)) parent = pStack.pop() currentTree = parent elif i in '+-*/': currentTree.setRootVal(i) currentTree.insertRight('') pStack.push(currentTree) currentTree = currentTree.getRightChild() elif i == ')': currentTree = pStack.pop() else: print "error: I don't recognize " + i return eTree def postorder(tree): if tree != None: postorder(tree.getLeftChild()) postorder(tree.getRightChild()) print tree.getRootVal() def preorder(self): print self.key if self.left: self.left.preorder() if self.right: self.right.preorder() def inorder(tree): if tree != None: inorder(tree.getLeftChild()) print tree.getRootVal() inorder(tree.getRightChild()) class Stack: def __init__(self): self.items = [] def isEmpty(self): return self.items == [] def push(self, item): self.items.append(item) def pop(self): return self.items.pop() def peek(self): return self.items[len(self.items)-1] def size(self): return len(self.items) def main(): parseData = raw_input( "Please enter the problem you wished parsed.(NOTE: problem must have parenthesis to seperate each binary grouping and must be spaced out.) " ) tree = buildParseTree(parseData) print( "The post order is: ", + postorder(tree)) print( "The post order is: ", + postorder(tree)) print( "The post order is: ", + preorder(tree)) print( "The post order is: ", + inorder(tree)) main() And here is the error: Please enter the problem you wished parsed.(NOTE: problem must have parenthesis to seperate each binary grouping and must be spaced out.) ( 1 + 2 ) Traceback (most recent call last): File "C:\Users\Kevin\Desktop\Python Stuff\Assignment 11\parseTree.py", line 108, in main() File "C:\Users\Kevin\Desktop\Python Stuff\Assignment 11\parseTree.py", line 102, in main tree = buildParseTree(parseData) File "C:\Users\Kevin\Desktop\Python Stuff\Assignment 11\parseTree.py", line 46, in buildParseTree currentTree = currentTree.getLeftChild() File "C:\Users\Kevin\Desktop\Python Stuff\Assignment 11\parseTree.py", line 15, in getLeftChild return root[1] AttributeError: BinaryTree instance has no attribute '__getitem__'

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  • Join .doc files into one .doc (with keeping the original format of every document)

    - by Shiki
    I have about ~50 .doc files, that look perfect (they are extracted with Able2Extract). Now I want to join these 50 files into one huge .doc. I've tried using Word's in-built "Insert" feature, but that messed up the whole format. I want to keep everything I have. Like just document1 - document2 - document3. Nothing "intelligent" or "smart" needed during the conversion, just the capability of joining them. (Thus making them all searchable, that's the ultimate aim.) I don't mind if the method/solution applies a single blank page at every document end either.

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  • How do I use a self encrypting drive?

    - by Unique_Key
    I recently purchased a Micron RealSSD c400 self encrypting drive, and I am having a few issues when trying to get it recognized by my laptop (HP Elitebook 8440p running Windows 7 x64; also tried on a custom-built desktop). When I try to initialize the drive from disk management, I get a CRC error; also, when attempting to partition it from Windows setup, the program can't create the partitions. I also tried with UBCD, nothing. I assume this is due to drive security, but I haven't been able to find much information about this online; do I need a management software or something? I'm completely stumped here. EDIT As requested, when I try partitioning the device from Windows setup I get a 0x80300024 error; when I try initializing it from disk management, I get a "Data error (cyclic redundancy check)" message, and the event log shows the following under System: Source: VDS Basic Provider, message: unexpected failure. error code 490@01010004 (2x) Source: Virtual Disk Service, message: VDS fails to write boot code on a disk during clean operation. Error code: 80070001@02070008 (1x) Source: Disk, message: The device \Device\Harddisk2\DR2 has a bad block (2x) The security logs show nothing related. Also, when attempting to configure it from UBCD (utility: HDAT2), I get an error along the lines of "can't edit partition information" or something to that tune.

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  • Left Outer Join - SQL2005

    - by Dan beadle
    I thought I knew enough SQL, but I am having problem with a left outer join. I have an expense detail record that needs to link to a table by dept and account_code. The query looks something like this: select Detail.Spend, Budget.BudgetAmt from detail left outer join budget on detail.dept = budget.dept AND dept.account_code = budget.account_code This works great as long as there is a record that exactly matches the join conditions. But sometimes, there is no matching budget item. I want to get back the Detail.Spend from the details table with nulls for the budgetAmt. Instead, I don't get this record at all. Isn't Left Outer Join supposed to return the left (detail) table when there is no match? Is there something different when multiple criteria are used as I do here? Thanks

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  • problem with a join

    - by Luca Romagnoli
    I have this code: int se = (int) settings.GruppoSegreteria; var acc = db.USR_Accounts.Where( p => p.ID_Gruppo == se); var segreterie = from s in db.USR_Utenti join h in acc on s.ID equals h.USR_UtentiReference select s; And this error: The type of one of the expressions in the join clause is incorrect. Type inference failed in the call to 'Join' I don't understand it. Can you help me? thanks

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  • mysql join Two tables to get records

    - by Saranya
    Hai guys, I have two tables Incharge and property. My property table has three fields 1stIncharge,2ndIncharge and 3rdIncharge. InchargeId is set as foreign key for all the above fields in the property table.. How to write a select statement that joins both the table.. I ve tried a bit but no result select P.Id,P.Name,P.1stIncharge,P.2ndIncharge,P.3rdIncharge,I.Id from Property as P join Incharge as I where (\\How to give condition here \\) Guys 3 fields P.1stIncharge, P.2ndIncharge, P.3rdIncharge has foreign key I.Id Edit: select P.Id,P.Name,P.1stIncharge,P.2ndIncharge,P.3rdIncharge,I1.Id from Property as P inner join Incharge as I1 on I1.Id=P.1stIncharge inner join Incharge as I2 on I2.Id=P.2ndIncharge inner join Incharge as I3 on I3.Id=P.3rdIncharge and this query working

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  • Deleting rows with MySQL LEFT JOIN

    - by fabrik
    Hello! I have two tables, one for job deadlines, one for describe a job. Each job can take a status and some statuses means the jobs' deadlines must be deleted from the other table. I can easily SELECT the jobs/deadlines that meets my criteria with a LEFT JOIN: SELECT * FROM `deadline` LEFT JOIN `job` ON deadline.job_id = job.job_id WHERE `status` = 'szamlazva' OR `status` = 'szamlazhato' OR `status` = 'fizetve' OR `status` = 'szallitva' OR `status` = 'storno' (status belongs to job table not deadline) But when i'd like to delete these rows from deadline, MySQL throws an error. My query is: DELETE FROM `deadline` LEFT JOIN `job` ON deadline.job_id = job.job_id WHERE `status` = 'szamlazva' OR `status` = 'szamlazhato' OR `status` = 'fizetve' OR `status` = 'szallitva' OR `status` = 'storno' MySQL error says nothing: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'LEFT JOIN `job` ON deadline.job_id = job.job_id WHERE `status` = 'szaml' at line 1 How can i turn my SELECT into a working DELETE query? Thanks, fabrik

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  • Join two tables with same # of row but sorted for NULL

    - by VISQL
    I need to join two tables with the same number of rows. Each table has 1 column. There is NO CONNECTING COLUMN to reference for a join. I need to join them side by side because each table was sorted separately so that numeric values are at the top in descinding order. The Table Earners has income values from say 200K down to 0. I cannot just select using 2 cases, because then I will have my first row with Incomes above 100K, but the first 20 or so entries in the second row are NULL. I want the second row to also be sorted descending. I looked up using ORDER BY within CASE but there is no such thing. I have tried to read about row_number() but none of the examples seem to match or make sense. drop table #20plus select case when Income >= 20000 AND Income < 100000 then Income end as 'mula' into #20plus from Earners order by mula desc drop table #100plus select case when Income >= 100000 then Income end as 'dinero' into #100plus from Earners order by dinero desc Select A.dinero, B.mula FROM #100plus as A JOIN #20plus as B ON A.????? = B.????? Since both A and B are sorted descending, moving all NULL to the bottom, what can I reference to join the two tables? Previous output using one SELECT statement with 2 CASE statements dinero mula 2.12688e+007 NULL 1.80031e+007 NULL 1.92415e+006 NULL … … NULL 93530.7 NULL 91000 NULL 84500 Desired output using one SELECT statement after creating two temp TABLES dinero mula 2.12688e+007 93530.7 1.80031e+007 91000 1.92415e+006 84500 … 82500 NULL 82000 NULL … NULL NULL This is Microsoft SQL Server 2008. I'm super new to this, so please give an answer as clear and simplified as possible. Thank you.

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  • SQL - Multiple join conditions using OR?

    - by Brandi
    I have a query that is using multiple joins. The goal is to say "Out of table A, give me all the customer numbers in which you can match table A's EmailAddress with either email_to or email_from of table B. Ignore nulls, internal emails, etc.". It seems like it would be better to use an or condition in the join than multiple joins since it is the same table. When I try to use AND/OR it does not give the behaviour I expect... AND finishes in a reasonable time, but yields no results (I know that there are matches, so it must be some flaw in my logic) and OR never finishes (I have to kill it). Here is example code to illustrate the question: --my original query SELECT DISTINCT a.CustomerNo FROM A a WITH (NOLOCK) LEFT JOIN B e WITH (NOLOCK) ON a.EmailAddress = e.email_from RIGHT JOIN B f WITH (NOLOCK) ON a.EmailAddress = f.email_to WHERE a.EmailAddress NOT LIKE '%@mydomain.___' AND a.EmailAddress IS NOT NULL AND (e.email_from IS NOT NULL OR f.email_to IS NOT NULL) Here is what I tried, (I am attempting logical equivalence): SELECT DISTINCT a.CustomerNo FROM A a WITH (NOLOCK) LEFT JOIN B e WITH (NOLOCK) ON a.EmailAddress = e.email_from OR a.EmailAddress = e.email_to WHERE a.EmailAddress NOT LIKE '%@mydomain.___' AND a.EmailAddress IS NOT NULL AND (e.email_from IS NOT NULL OR e.email_to IS NOT NULL) So my question is two-fold: Why does having AND in the above query work in a few seconds and OR goes for minutes and never completes? What am I missing to make a logically equivalent statement that has only one join?

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  • Left Join Returning Extra Rows T-SQL?

    - by davemackey
    I have the following query: select * from ACADEMIC a left join RESIDENCY r on a.PEOPLE_CODE_ID = r.PEOPLE_CODE_ID where a.ACADEMIC_TERM='Fall' and r.ACADEMIC_TERM='Fall' and a.ACADEMIC_SESSION='' and a.ACADEMIC_YEAR = (Select Year(GetDate())) and r.ACADEMIC_YEAR = (Select Year(GetDate())) and (CLASS_LEVEL LIKE 'FR%' OR a.CLASS_LEVEL LIKE 'SO' OR a.CLASS_LEVEL LIKE 'JR' OR a.CLASS_LEVEL LIKE 'SR%') and r.RESIDENT_COMMUTER='R' For each person in the database it returns two rows with identical information. Yet, when I do the same query without the left join: select * from ACADEMIC a where a.ACADEMIC_TERM='Fall' and a.ACADEMIC_SESSION='' and a.ACADEMIC_YEAR = (Select Year(GetDate())) and (CLASS_LEVEL LIKE 'FR%' OR a.CLASS_LEVEL LIKE 'SO' OR a.CLASS_LEVEL LIKE 'JR' OR a.CLASS_LEVEL LIKE 'SR%') ORDER BY PEOPLE_ID It returns only one row for each person. I'm doing a left join - why is it adding an extra row? Shouldn't it only do that if I add a right join?

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  • MySQL LEFT OUTER JOIN virtual table

    - by user1707323
    I am working on a pretty complicated query let me try to explain it to you. Here is the tables that I have in my MySQL database: students Table --- `students` --- student_id first_name last_name current_status status_change_date ------------ ------------ ----------- ---------------- -------------------- 1 John Doe Active NULL 2 Jane Doe Retread 2012-02-01 students_have_courses Table --- `students_have_courses` --- students_student_id courses_course_id s_date e_date int_date --------------------- ------------------- ---------- ---------- ----------- 1 1 2012-01-01 2012-01-04 2012-01-05 1 2 2012-01-05 NULL NULL 2 1 2012-01-10 2012-01-11 NULL students_have_optional_courses Table --- `students_have_optional_courses` --- students_student_id optional_courses_opcourse_id s_date e_date --------------------- ------------------------------ ---------- ---------- 1 1 2012-01-02 2012-01-03 1 1 2012-01-06 NULL 1 5 2012-01-07 NULL Here is my query so far SELECT `students_and_courses`.student_id, `students_and_courses`.first_name, `students_and_courses`.last_name, `students_and_courses`.courses_course_id, `students_and_courses`.s_date, `students_and_courses`.e_date, `students_and_courses`.int_date, `students_have_optional_courses`.optional_courses_opcourse_id, `students_have_optional_courses`.s_date, `students_have_optional_courses`.e_date FROM ( SELECT `c_s_a_s`.student_id, `c_s_a_s`.first_name, `c_s_a_s`.last_name, `c_s_a_s`.courses_course_id, `c_s_a_s`.s_date, `c_s_a_s`.e_date, `c_s_a_s`.int_date FROM ( SELECT `students`.student_id, `students`.first_name, `students`.last_name, `students_have_courses`.courses_course_id, `students_have_courses`.s_date, `students_have_courses`.e_date, `students_have_courses`.int_date FROM `students` LEFT OUTER JOIN `students_have_courses` ON ( `students_have_courses`.`students_student_id` = `students`.`student_id` AND (( `students_have_courses`.`s_date` >= `students`.`status_change_date` AND `students`.current_status = 'Retread' ) OR `students`.current_status = 'Active') ) WHERE `students`.current_status = 'Active' OR `students`.current_status = 'Retread' ) `c_s_a_s` ORDER BY `c_s_a_s`.`courses_course_id` DESC ) `students_and_courses` LEFT OUTER JOIN `students_have_optional_courses` ON ( `students_have_optional_courses`.students_student_id = `students_and_courses`.student_id AND `students_have_optional_courses`.s_date >= `students_and_courses`.s_date AND `students_have_optional_courses`.e_date IS NULL ) GROUP BY `students_and_courses`.student_id; What I want to be returned is the student_id, first_name, and last_name for all Active or Retread students and then LEFT JOIN the highest course_id, s_date, e_date, and int_date for the those students where the s_date is since the status_change_date if status is 'Retread'. Then LEFT JOIN the highest optional_courses_opcourse_id, s_date, and e_date from the students_have_optional_courses TABLE where the students_have_optional_courses.s_date is greater or equal to the students_have_courses.s_date and the students_have_optional_courses.e_date IS NULL Here is what is being returned: student_id first_name last_name courses_course_id s_date e_date int_date optional_courses_opcourse_id s_date_1 e_date_1 ------------ ------------ ----------- ------------------- ---------- ---------- ------------ ------------------------------ ---------- ---------- 1 John Doe 2 2012-01-05 NULL NULL 1 2012-01-06 NULL 2 Jane Doe NULL NULL NULL NULL NULL NULL NULL Here is what I want being returned: student_id first_name last_name courses_course_id s_date e_date int_date optional_courses_opcourse_id s_date_1 e_date_1 ------------ ------------ ----------- ------------------- ---------- ---------- ------------ ------------------------------ ---------- ---------- 1 John Doe 2 2012-01-05 NULL NULL 5 2012-01-07 NULL 2 Jane Doe NULL NULL NULL NULL NULL NULL NULL Everything is working except one thing, I cannot seem to get the highest students_have_optional_courses.optional_courses_opcourse_id no matter how I form the query Sorry, I just solved this myself after writing this all out I think it helped me think of the solution. Here is the solution query: SELECT `students_and_courses`.student_id, `students_and_courses`.first_name, `students_and_courses`.last_name, `students_and_courses`.courses_course_id, `students_and_courses`.s_date, `students_and_courses`.e_date, `students_and_courses`.int_date, `students_optional_courses`.optional_courses_opcourse_id, `students_optional_courses`.s_date, `students_optional_courses`.e_date FROM ( SELECT `c_s_a_s`.student_id, `c_s_a_s`.first_name, `c_s_a_s`.last_name, `c_s_a_s`.courses_course_id, `c_s_a_s`.s_date, `c_s_a_s`.e_date, `c_s_a_s`.int_date FROM ( SELECT `students`.student_id, `students`.first_name, `students`.last_name, `students_have_courses`.courses_course_id, `students_have_courses`.s_date, `students_have_courses`.e_date, `students_have_courses`.int_date FROM `students` LEFT OUTER JOIN `students_have_courses` ON ( `students_have_courses`.`students_student_id` = `students`.`student_id` AND (( `students_have_courses`.`s_date` >= `students`.`status_change_date` AND `students`.current_status = 'Retread' ) OR `students`.current_status = 'Active') ) WHERE `students`.current_status = 'Active' OR `students`.current_status = 'Retread' ) `c_s_a_s` ORDER BY `c_s_a_s`.`courses_course_id` DESC ) `students_and_courses` LEFT OUTER JOIN ( SELECT * FROM `students_have_optional_courses` ORDER BY `students_have_optional_courses`.optional_courses_opcourse_id DESC ) `students_optional_courses` ON ( `students_optional_courses`.students_student_id = `students_and_courses`.student_id AND `students_optional_courses`.s_date >= `students_and_courses`.s_date AND `students_optional_courses`.e_date IS NULL ) GROUP BY `students_and_courses`.student_id;

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  • LINQ-to-SQL - Join, Count

    - by ile
    I have following query: var result = ( from role in db.Roles join user in db.Users on role.RoleID equals user.RoleID where user.CreatedByUserID == userID orderby user.FirstName ascending select new UserViewModel { UserID = user.UserID, PhotoID = user.PhotoID.ToString(), FirstName = user.FirstName, LastName = user.LastName, FullName = user.FirstName + " " + user.LastName, Email = user.Email, PhoneNumber = user.Phone, AccessLevel = role.Name }); Now, I need to modify this query... Other table I have is table Deals. I would like to count how many deals user created last month and last year. I tried something like this: var result = ( from role in db.Roles join user in db.Users on role.RoleID equals user.RoleID //join dealsYear in db.Deals on date.Year equals dealsYear.DateCreated.Year join dealsYear in ( from deal in db.Deals group deal by deal.DateCreated into d select new { DateCreated = d.Key, dealsCount = d.Count() } ) on date.Year equals dealsYear.DateCreated.Year into dYear join dealsMonth in ( from deal in db.Deals group deal by deal.DateCreated into d select new { DateCreated = d.Key, dealsCount = d.Count() } ) on date.Month equals dealsMonth.DateCreated.Month into dMonth where user.CreatedByUserID == userID orderby user.FirstName ascending select new UserViewModel { UserID = user.UserID, PhotoID = user.PhotoID.ToString(), FirstName = user.FirstName, LastName = user.LastName, FullName = user.FirstName + " " + user.LastName, Email = user.Email, PhoneNumber = user.Phone, AccessLevel = role.Name, DealsThisYear = dYear, DealsThisMonth = dMonth }); but here is even syntax not correct. Any idea? Btw, is there any good book of LINQ to SQL with examples?

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  • error with linq join

    - by Luca Romagnoli
    I have this linq query: var segreterie = from s in db.USR_Utenti join h in db.USR_Accounts on new {s.ID, settings.GruppoSegreteria} equals new {h.USR_UtentiReference,h.ID_Gruppo} select s; that has this problem: The type of one of the expressions in the join clause is incorrect. Type inference failed in the call to 'Join'. how can i do to solve it?

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  • Why is my left join not returning nulls?

    - by Griz
    In sql server 2008, I have the following query: select c.title as categorytitle, s.title as subcategorytitle, i.title as itemtitle from categories c join subcategories s on c.categoryid = s.categoryid left join itemcategories ic on s.subcategoryid = ic.subcategoryid left join items i on ic.itemid = i.itemid where (ic.isactive = 1 or ic.isactive is null) and i.siteid = 132 order by c.title, s.title I am trying to get items in their subcategories, but I still want to return a record if there are no items in the category or subcategory. Subcategories that have no items are never returned. What am I doing wrong? Thank you EDIT Modified query with a second left join and where clause, but it's still not returning nulls. :/

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  • join query with lowstock products with another table in magento

    - by muralikalpana
    I want to display some attributes in reports/products/lowstock grid. here how can i join another table with lowstock product id? here is the query /** @var $collection Mage_Reports_Model_Resource_Product_Lowstock_Collection */ $collection = Mage::getResourceModel('reports/product_lowstock_collection') ->addAttributeToSelect('*') ->setStoreId($storeId) ->filterByIsQtyProductTypes() ->joinInventoryItem('qty') ->joinInventoryItem('low_stock_date') ->useManageStockFilter($storeId) ->useNotifyStockQtyFilter($storeId) ->setOrder('qty', Varien_Data_Collection::SORT_ORDER_ASC); here i have to join with this productid with another table. i am not getting results if i use this query. $collection->getSelect()->join(array('t2' => 'lowstockorders'),'lowstock_inventory_item.product_id = t2.product_id','t2.product_id'); please anybody tell me how to join these tables thanks, murali

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  • multiple join query in entity framework

    - by gvLearner
    I have following tables tasks id | name | proj_id 1 | task1 | 1 2 | task2 | 1 3 | task3 | 1 projects id | name 1 | sample proj1 2 | demo project budget_versions id | version_name| proj_id 1 | 50 | 1 budgets id | cost | budget_version_id | task_id 1 | 3000 | 1 | 2 2 | 5000 | 1 | 1 I need to join these tables to get a result as below task_id | task_name | project_id | budget_version | budget_id | cost 1 | task1 | 1 | 1 | 2 |5000 2 | task2 | 1 | 1 | 1 |3000 3 | task3 | 1 | NULL | NULL |NULL select tsk.id,tsk.name, tsk.project_id, bgtver.id, bgt.id, bgt.cost from TASK tsk left outer join BUDGET_VERSIONS bgtver on tsk.project_id= bgtver.project_id left outer join BUDGETS bgt on bgtver.id = bgt.budget_version_id and tsk.id = bgt.task_id where bgtver.id = 1

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  • How can I transition from being a "9-5er" to being self-employed?

    - by Stephen Furlani
    Hey, I posted this question last fall about moonlighting, and I feel like I've got a strong case to make to start transitioning from being a Full-Time Employee to being self-employed. So much so, that I find it hard to concentrate at work on the things I'm supposed to be doing. However, self-employment comes with things like no health benefits or guaranteed income... so I don't feel like I can just quit. (At least not in this economy with a house and family). I'm already working 40hrs/wk on my main job, going to school to get my MS, and trying to freelance on weekends and evenings, but I want to give it more time. If I can't take LWOP or just work less than 40hrs/wk I feel like I have to give up self-employment because I just can't give my day job all my best. Would it be reasonable to ask my employer if they can cut my hours (and pay)? Is there something else I can/should do? Has anyone done this transition and had it turn out well? or bad? I am in the USA and I understand answers are not legal advice. Thanks!

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  • Reach self hosted server from LAN

    - by Freefri
    I have a self hosted server with Apache2 pointed with the domain example.com. I have also some virtual servers www.example.com, cloud.examle.com, etc. This server is in my LAN, and when I try to acces to my server within the lan throw www.examle.com y get my router's configuration page. From outside the LAN www.example.com and cloud.examle.com works properly. From inside the LAN 192.168.1.33 (server internal IP) shows the default webpage (www.examle.com), but I can not get cloud.examle.com I also have a LAN name server in 192.168.1.33 with bind9. I set up my gateway 192.168.1.1 with my LAN-NS as primary NS I solve this problem creating a new dns zone in the NS. This are my config files: ;ZONE-1 $ORIGIN . $TTL 86400 ; 1 day home.lan. IN SOA server.home.lan. hostmaster.home.lan. ( 2008080901 ; serial 8H ; refresh 4H ; retry 4W ; expire 1D ; minimum ) home.lan. IN NS server.home.lan. $ORIGIN home.lan. ; Set the address for localhost.home.lan localhost IN A 127.0.0.1 router IN A 192.168.1.1 server IN A 192.168.1.33 mypc IN A 192.168.1.132 ;ZONE-2 $ORIGIN . $TTL 86400 ; 1 day example.com. IN SOA www.example.com hostmaster.home.lan. ( 2008080902 ; serial 8H ; refresh 4H ; retry 4W ; expire 1D ; minimum ) example.com. IN NS 192.168.1.33 $ORIGIN examle.com. localhost IN A 127.0.0.1 www IN A 192.168.1.33 cloud IN A 192.168.1.33 My DNS and my names are working properly now My question are: What do you think about my solution? Can I change the A zone with CNAME to server.home.lan (this is the domain in the LAN to the server)? How can I set a default IP for all my whatever.example.com?

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  • Join mp4 files in linux

    - by Jose Armando
    I want to join two mp4 files to create a single one. The video streams are encoded in h264 and the audio in aac. I can not re-encode the videos to another format due to computational reasons. Also, I cannot use any gui programs, all processing must be performed with linux command line utilities. FFmpeg cannot do this for mpeg4 files so instead I used MP4Box e.g. MP4Box -add video1.mp4 -cat video2.mp4 newvideo.mp4 unfortunately the audio gets all mixed up. I thought that the problem was that the audio was in aac so I transcoded it in mp3 and used again MP4Box. In this case the audio is fine for the first half of newvideo.mp4 (corresponding to video1.mp4) but then their is no audio and I cannot navigate in the video also. My next thought was that the audio and video streams had some small discrepancies in their lengths that I should fix. So for each input video I splitted the video and audio streams and then joined them with the -shortest option in ffmpeg. thus for the first video I ran avconv -y -i video1.mp4 -c copy -map 0:0 videostream1.mp4 avconv -y -i video1.mp4 -c copy -map 0:1 audiostream1.m4a avconv -y -i videostream1.mp4 -i audiostream1.m4a -c copy -shortest video1_aligned.mp4 similarly for the second video and then used MP4Box as previously. Unfortunately this didn't work either. The only success I had was when I joined the video streams separetely (i.e. videostream1.mp4 and videostream2.mp4) and the audio streams (i.e. audiostream1.m4a and audiostream2.m4a) and then joined the video and audio in a final file. However, the synchronization is lost for the second half of the video. Concretelly, there is a 1 sec delay of audio and video. Any suggestions are really welcome.

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