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  • RTF template coding, XSLT coding

    - by sujith
    I have the below requirement <data> <dataset1> <number>1</number> <name>red</name> <number>2</number> <name>Yellow</name> <number>3</number> <name>black</name> <number>4</number> <name>Violet</name> </dataset1> <dataset2> <index>1</index> <index>2</index> <index>3</index> <index>4</index> </dataset2> </data> I need to loop through dataset2 take the index value, compare it with the value of number tag in dataset1. If a match occurs then display value of corresponding name tag. I need to get the output in rtf format. Please give BI tags or relevent xslt code to do the same. Thanks in advance.

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  • HELP with XML to XML transformation using XSLT.

    - by kaniths
    Am a rookie trying XSLT and XML tranformations for the first time. To start off, i tried a simple sample programs. I expected the Output in Tree format (maintaining the hierarchy) instead i just get " KING" in single line... What could be the problem? PS: I use XMLSpy. Any guideline would be great full. Thanks :) Input XML: <ROWSET> <ROW> <EMPNO>7839</EMPNO> <ENAME>KING</ENAME> </ROW> </ROWSET> XSL used for transformation: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" encoding="UTF-8" indent="yes" omit-xml-declaration="no"/> <xsl:template match="/"> <Invitation> <To> <xsl:value-of select="ROWSET/ROW/ENAME"/> </To> </Invitation> </xsl:template>

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  • How to Create Element in XSLT When Copying Using Templates

    - by John Dumont
    Hello, I'm trying to create an element in an XML where the basic content is copied and modified. My XML is something like <root> <node> <child>value</child> <child2>value2</child2> </node> <node2>bla</node2> </root> The number of children of node may change as well as the children of root. The XSLT should copy the whole content, modify some values and add some new. The copying and modifying is no problem: <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> <xsl:output method="xml" encoding="UTF-8"/> <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> </xsl:stylesheet> (+ further templates for modifications). But how do I add a new element in this structure on some path, e.g. I want to add an element as the last element of the "node" node. The "node" element itself always exists.

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  • XSLT string replace

    - by aximili
    I don't really know XSL but I need to fix this code, I have reduced it to make it simpler. I am getting this error Invalid XSLT/XPath function on this line <xsl:variable name="text" select="replace($text,'a','b')"/> This is the XSL <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:inm="http://www.inmagic.com/webpublisher/query" version='1.0'> <xsl:output method="text" encoding="UTF-8"/> <xsl:preserve-space elements="*"/> <xsl:template match="text()"></xsl:template> <xsl:template match="mos"> <xsl:apply-templates/> <xsl:for-each select="mosObj"> 'Notes or subject' <xsl:call-template name="rem-html"><xsl:with-param name="text" select="SBS_ABSTRACT"/></xsl:call-template> </xsl:for-each> </xsl:template> <xsl:template name="rem-html"> <xsl:param name="text"/> <xsl:variable name="text" select="replace($text,'a','b')"/> </xsl:template> </xsl:stylesheet> Can anyone tell me what's wrong with it? Thanks in advance.

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  • XSLT pass node into CDATA JS

    - by davomarti
    I have the following xml <AAA> <BBB>Total</BBB> </AAA> Transforming it with the following xslt using the xsl:copy-of tag, because I want to use the xml to create a xml doc in js. <xsl:template match="/"> <![CDATA[ function myFunc() { xmlStr = ']]><xsl:copy-of select="/"/><![CDATA['; } ]]> </xsl:template> The output looks like this function myFunc() { xmlStr = '<AAA> <BBB>Total</BBB> </AAA>'; } JS doesn't like this because of the missing semicolons ending the lines. How can I fix my xsl to get the below result: function myFunc() { xmlStr = '<AAA><BBB>Total</BBB></AAA>'; } I've tried normalize-space() and translate() but they strip the tags from the xml. Thanks!

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  • How to decode a html string using xslt

    - by John ClearZ
    I am trying to style an rss feed using xslt. I want to display an image that is stored in the tag on the feed. The problem is it is encoded to display as text on the page instead of being rendered. The following is an example of part of the string. 1). <description>&lt;img src="http&amp;#58;&amp;#47;&amp;#47;buavhw.blu.livefilestore.com&amp;#47;y1ppCokLxFJSG2cmyPdvg... I had to add extra coding to the string above to get it to appear properly here. The string below is how it appears when I paste it directly into the text box. 2). <description><img src="http&#58;&#47;&#47;buavhw.blu.livefilestore.com&#47;y1ppCokLxFJSG2cmyPdvg... If I copy and paste it again from the preview window it only then becomes the following string. 3). <description><img src="http://buavhw.blu.livefilestore.com/y1ppCokLxFJSG2cmyPdvg...

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  • Problem in using xpath with xslt having distinct values

    - by AB
    I have XML like, <items> <item> <products> <product>laptop</product> <product>charger</product> <product>Cam</product> </products> </item> <item> <products> <product>laptop</product> <product>headphones</product> <product>Photoframe</product> </products> </item> <item> <products> <product>laptop</product> <product>charger</product> <product>Battery</product> </products> </item> </items> and I am using xslt on it //can't change xpath as getting it from somewhere else <xsl:param name="xparameter" select="items/item[products/product='laptop' and products/product='charger']"></xsl:param> <xsl:template match="/"> <xsl:for-each select="$xparameter"> <xsl:for-each select="products/product[not(.=preceding::product)]"> <xsl:sort select="."></xsl:sort> <xsl:value-of select="." ></xsl:value-of>, </xsl:for-each> </xsl:for-each> </xsl:template> I want the output to be laptop charger cam Battery But I m not getting the result as I m expecting...distinct values is working fine ..something is getting wrong when I am adding that and claus

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  • XSLT line counter - is it that hard?

    - by Mr AH
    I have cheated every time I've needed to do a line count in XSLT by using JScript, but in this case I can't do that. I simply want to write out a line counter throughout an output file. This basic example has a simple solution: <xsl:for-each select="Records/Record"> <xsl:value-of select="position()"/> </xsl:for-each> Output would be: 1 2 3 4 etc... But what if the structure is more complex with nested foreach's : <xsl:for-each select="Records/Record"> <xsl:value-of select="position()"/> <xsl:for-each select="Records/Record"> <xsl:value-of select="position()"/> </xsl:for-each> </xsl:for-each> Here, the inner foreach would just reset the counter (so you get 1, 1, 2, 3, 2, 1, 2, 3, 1, 2 etc). Does anyone know how I can output the position in the file (ie. a line count)?

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  • XSLT how to merge some lists of parameters

    - by buggy1985
    Hi, I have an URL Structure like this: http://my.domain.com/generated.xml?param1=foo&param2=bar&xsl=path/to/my.xsl The generated XML will be transformed using the given XSL Stylesheet. The two other parameters are integrated too like this: <root> <params> <param name="param1">foo</param> <param name="param2">bar</param> </param> ... </root> Now I want to create with XSLT a link with a new URI that keeps the existing parameters and adds one or multiple new parameters like page=3 or sort=DESC. If the given parameter already exists, it should be replaced. I'm not sure how to do this. How to pass multiple (optional) parameters to a template. How to merge two lists of parameters. Any ideas? Thanks ;)

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  • Using XSLT to Find Nodes Given a Set of Parameters

    - by davecardwell
    Sorry about the title—wasn’t sure how to word it. Basically I have some XML like this: <countries> <country handle="bangladesh"/> <country handle="india"/> <country handle="pakistan"/> </countries> And some XSLT like this (which doesn’t work): <xsl:template match="/countries"> <xsl:param name="popular"/> <xsl:apply-templates select="country[count($popular/country[@handle = current()/@handle]) &gt; 0]" /> </xsl:template> <xsl:template match="/countries/country"> … </xsl:template> I want to pass in a list of popular destinations like this: <popular> <country handle="india"/> <country handle="pakistan"/> </popular> …to the /countries template and have it only operate on the ones in the $popular param. At the moment this simply does nothing. Changing the selector to country[true()] operates on them all, so at least I know the basic structure is right. Any ideas? I think I may be getting confused by what is currently “current()”.

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  • Actually XSLT Lookup (Store variables during loop and use in it another template)

    - by krisvandenbergh
    Is there a way to store a variable/param during a for-each loop in a sort of array, and use it in another template, namely <xsl:template match="Foundation.Core.Classifier.feature">. All the classname values that appear during the for-each should be stored. How would you implement that in XSLT? Here's my current code. <xsl:for-each select="Foundation.Core.Class"> <xsl:for-each select="Foundation.Core.ModelElement.name"> <xsl:param name="classname"> <xsl:value-of select="Foundation.Core.ModelElement.name"/> </xsl:param> </xsl:for-each> <xsl:apply-templates select="Foundation.Core.Classifier.feature" /> </xsl:for-each> Here's the template in which the classname parameters should be used. <xsl:template match="Foundation.Core.Classifier.feature"> <xsl:for-each select="Foundation.Core.Attribute"> <owl:DatatypeProperty rdf:ID="{Foundation.Core.ModelElement.name}"> <rdfs:domain rdf:resource="$classname" /> </owl:DatatypeProperty> </xsl:for-each> </xsl:template> The input file can be found at http://krisvandenbergh.be/uml_pricing.xml

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  • Grouping XSLT nodes via transformation

    - by scott
    I'm trying to create a page like this via XSLT transformation. Pages page1 page2 Links link1 link2 Here is the xml <siteMenu> <Pages> <title>page1</title> </Pages> <Pages> <title>page2</title> </Pages> <Links> <title>link1</title> </Links> <Links> <title>link2</title> </Links> </siteMenu> I tried using <xsl:for-each select="*"> and <xsl:for-each-group select="*" group-by="@v"> but that gives me every element, but how can i separate them out based on the parent node?

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  • XSLT: insert parameter value inside of an html attribute

    - by usr
    How to make the following code insert the youtubeId parameter: <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp "&#x00A0;"> ]> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxml="urn:schemas-microsoft-com:xslt" xmlns:YouTube="urn:YouTube" xmlns:umbraco.library="urn:umbraco.library" exclude-result-prefixes="msxml umbraco.library YouTube"> <xsl:output method="xml" omit-xml-declaration="yes"/> <xsl:param name="videoId"/> <xsl:template match="/"> <a href="{$videoId}">{$videoId}</a> <object width="425" height="355"> <param name="movie" value="http://www.youtube.com/v/{$videoId}&amp;hl=en"></param> <param name="wmode" value="transparent"></param> <embed src="http://www.youtube.com/v/{$videoId}&amp;hl=en" type="application/x-shockwave-flash" wmode="transparent" width="425" height="355"></embed> </object>$videoId {$videoId} {$videoId} <xsl:value-of select="/macro/videoId" /> </xsl:template> </xsl:stylesheet> As you can see I have experimented quite a bit. <xsl:value-of select="/macro/videoId" /> actually outputs the videoId but all other occurences do not. This must be an easy question to answer but I just cannot get it to work.

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  • XSLT - How to select top a to top b

    - by user812241
    how can I extract the first 2 C-Values ('Baby' and 'Cola') where B is 'RED'. Input instance is: <Root> <A> <B>BLACK</B> <C>Apple</C> </A> <A> <B>RED</B> <C>Baby</C> </A> <A> <B>GREEN</B> <C>Sun</C> </A> <A> <B>RED</B> <C>Cola</C> </A> <A> <B>RED</B> <C>Mobile</C> </A> </Root> Output instance must be: <Root> <D>Baby</D> <D>Cola</D> </Root> I thought about the combination of for-each and global variables. But in XSLT it is not possible to change the value for a global variable to break the for-each. I have no idea anymore.

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  • XSLT special characters

    - by Apurv
    In the following XSL transformation how do I output the '<' and '' symbol? Input XML: <TestResult bugnumber="3214" testname="display.methods::close->test_ManyInvoke" errortype="Failure"><ErrorMessage><![CDATA[calling close() method failed - expected:<2>]]></ErrorMessage> XSLT: <xsl:template match="TestResult"> <xsl:variable name="errorMessage"> <xsl:value-of select="ErrorMessage" disable-output-escaping="yes"/> </xsl:variable> <Test name='{@testname}'> <TestResult> <Passed>false</Passed> <State>failure</State> <Metadata> <Entry name='bugnumber' value='{@bugnumber}' /> </Metadata> <TestOutput> <Metadata> <Entry name='ErrorMessage' value='{$errorMessage}' /> </Metadata> </TestOutput> </TestResult> </Test> </xsl:template> Output XML: <Test name="display.methods::close-&gttest_ManyInvoke"> <TestResult> <Passed>false</Passed> <State>failure</State> <Metadata> <Entry name="bugnumber" value="3214"/> </Metadata> <TestOutput> <Metadata> <Entry name="ErrorMessage" value="calling close() method failed - expected:&lt;2&gt;"/> </Metadata> </TestOutput> </TestResult> </Test>

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  • XSLT for-each from query results

    - by Ben Record
    I've been on a hunt for a while trying to find a solution to this but I cannot find anywhere that addresses this problem. I'm running a SQL query through XSLT which will return three rows. Here is the query: <query name="OrderedProductNames" rowElementName ="OrderedItem"> <sql> <![CDATA[ select OrderedProductName, Quantity from Orders_ShoppingCart where OrderNumber = 101689 // Hard coded order number for testing purposes. ]]> </sql> </query> Ideally, I would like to iterate through each row returned and do a choose when which is tested on a variable from the current row being inspected in the for-each loop, but I am not entirely sure thhis is possible. My secondary thought would be to use the for-each loop as a way to inject hidden HTML input elements with the values I would need, then I could write a javascript function to complete what I'm trying to do. Any suggestion on how I would go about completing either task would be greatly appreciated.

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  • How can I build value for "for-each" expression in XSLT with help of parameter

    - by Artic
    I need to navigate through this xml tree. <publication> <corporate> <contentItem> <metadata>meta</metadata> <content>html</content> </contentItem> <contentItem > <metadata>meta1</metadata> <content>html1</content> </contentItem> </corporate> <eurasia-and-africa> ... </eurasia-and-africa> <europe> ... </europe> </publication> and convert it to html with this stylesheet <ul> <xsl:variable name="itemsNode" select="concat('publicationManifest/',$group,'/contentItem')"></xsl:variable> <xsl:for-each select="$itemsNode"> <li> <xsl:value-of select="content"/> </li> </xsl:for-each> </ul> $group is a parameter with name of group for example "corporate". I have an error with compilation of this stylsheet. SystemID: D:\1\contentsTransform.xslt Engine name: Saxon6.5.5 Severity: error Description: The value is not a node-set Start location: 18:0 What the matter?

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  • Problem in using xpath with xslt having distint values

    - by AB
    I have XML like, <items> <item> <products> <product>laptop</product> <product>charger</product> <product>Cam</product> </products> </item> <item> <products> <product>laptop</product> <product>headphones</product> <product>Photoframe</product> </products> </item> <item> <products> <product>laptop</product> <product>charger</product> <product>Battery</product> </products> </item> </items> and I am using xslt on it //can't change xpath as getting it from somewhere else <xsl:param name="xparameter" select="items/item[products/product='laptop' and products/product='charger']"></xsl:param> <xsl:template match="/"> <xsl:for-each select="$xparameter"> <xsl:for-each select="products/product[not(.=preceding::product)]"> <xsl:sort select="."></xsl:sort> <xsl:value-of select="." ></xsl:value-of>, </xsl:for-each> </xsl:for-each> </xsl:template> I want the output to be laptop charger cam Battery But I m not getting the result as I m expecting...distinct values is working fine ..something is getting wrong when I am adding that and claus

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  • XSLT: change node inner text.

    - by nabo
    I need to transform the following xml doc: <a> <b/> <c/> myText </a> into this: <a> <b/> <c/> differentText </a> So, i wrote this XSLT document <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="xml" version="1.0" omit-xml-declaration="no" /> <xsl:template match="/a/text()"> <a> <b/> <c/> differentText </a> </xsl:template> </xsl:stylesheet> This way, i get the following result: <?xml version="1.0" encoding="utf-8"?> <a> <b /><c /> differentText </a> <a> <b /><c /> differentText </a> <a> <b /><c /> differentText </a> The result appears repeated 3 times because 3 matches are being done.. Why? I could i fix it? Thanks

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  • xslt check for alpha numeric character

    - by Newcoma
    I want to check if a string contains only alphanumeric characters OR '.' This is my code. But it only works if $value matches $allowed-characters exactly. I use xslt 1.0. <xsl:template name="GetLastSegment"> <xsl:param name="value" /> <xsl:param name="separator" select="'.'" /> <xsl:variable name="allowed-characters">ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz.</xsl:variable> <xsl:choose> <xsl:when test="contains($value, $allowed-characters)"> <xsl:call-template name="GetLastSegment"> <xsl:with-param name="value" select="substring-after($value, $separator)" /> <xsl:with-param name="separator" select="$separator" /> </xsl:call-template> </xsl:when> <xsl:otherwise> <xsl:value-of select="$value" /> </xsl:otherwise> </xsl:choose> </xsl:template>

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  • dynamic HREF attribute by XSLT

    - by ofortuna
    Can anyone plese advice how I can have dynamic HREF attribute in the place of http://abc.com by XSLT in following code snippet? <xsl:for-each select="MenuItems/mainmenu"> <a href="http://abc.com"> <span><xsl:value-of select="menuName"/></span> </a> </xsl:for-each> sample xml <MenuItems> <mainmenu> <menuID>1</menuID> <menuName>Home</menuName> <menuLink>http://aaa.com</menuLink> <subMenuList> <menuID>2</menuID> <menuName>Home</menuName> <menuLink>http://a1.com</menuLink> </subMenuList> <subMenuList> <menuID>3</menuID> <menuName>List of RCCs</menuName> <menuLink>http://a2.com</menuLink> </subMenuList> <subMenuList> <menuID>4</menuID> <menuName>Turnover Workout</menuName> <menuLink>http://a3.com</menuLink> </subMenuList> </mainmenu> <MenuItems>

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  • Selecting unique elements using XSLT.

    - by AJ
    I have the following XML: <option> <title>ABC</title> <desc>123</desc> </option> <option> <title>ABC</title> <desc>12345</desc> </option> <option> <title>ABC</title> <desc>123</desc> </option> <option> <title>EFG</title> <desc>123</desc> </option> <option> <title>EFG</title> <desc>456</desc> </option> Using XSLT, I want to transform it into: <choice> <title>ABC</title> <desc>123</desc> <desc>12345</desc> </choice> <choice> <title>EFG</title> <desc>123</desc> <desc>456</desc> </choice>

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  • XSLT apply attribute depending on position

    - by Burt
    I am using XSLT for a website based on the 960 grid css framework. I have columns of divs that span across the page if it is the first div in a row it should have a class first applied, if it is the middle one then no class and if it is the 3rd in the row it should have the class last applied. I am really scratching my head as the best way to go about this any help is appreciated. Below is the structure I want to end up with, the numbers inside the divs represent the position. <div class="container_12"> <div id="main-content" class="alpha grid_12" style="margin-bottom: 20px;"> <div class="grid_4 alpha"> 1 </div> <div class="grid_4 "> 2 </div> <div class="grid_4 omega"> 3 </div> <div class="grid_4 alpha"> 4 </div> </div> </div>

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  • Counting unique XML element attributes using XSLT

    - by patrick_corrigan
    I've just started using XSLT and am trying to figure this out. Your help would be greatly appreciated. Example XML file <purchases> <item id = "1" customer_id = "5"> </item> <item id = "2" customer_id = "5"> </item> <item id = "7" customer_id = "4"> </item> </purchases> Desired HTML Output: <table> <tr><th>Customer ID</th><th>Number of Items Purchased</th></tr> <tr><td>5</td><td>2</td></tr> <tr><td>4</td><td>1</td></tr> </table> Customer with id number 5 has bought 2 items. Customer with id number 4 has bought 1 item.

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  • xslt broken: pattern does not match

    - by krisvandenbergh
    I'm trying to query an xml file using the following xslt: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#" xmlns:rdfs="http://www.w3.org/2000/01/rdf-schema#" xmlns:bpmn="http://dkm.fbk.eu/index.php/BPMN_Ontology"> <!-- Participants --> <xsl:template match="/"> <html> <body> <table> <xsl:for-each select="Package/Participants/Participant"> <tr> <td><xsl:value-of select="ParticipantType" /></td> <td><xsl:value-of select="Description" /></td> </tr> </xsl:for-each> </table> </body> </html> </xsl:template> </xsl:stylesheet> Here's the contents of the xml file: <?xml version="1.0" encoding="utf-8"?> <?xml-stylesheet type="text/xsl" href="xpdl2bpmn.xsl"?> <Package xmlns="http://www.wfmc.org/2008/XPDL2.1" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" Id="25ffcb89-a9bf-40bc-8f50-e5afe58abda0" Name="1 price setting" OnlyOneProcess="false"> <PackageHeader> <XPDLVersion>2.1</XPDLVersion> <Vendor>BizAgi Process Modeler.</Vendor> <Created>2010-04-24T10:49:45.3442528+02:00</Created> <Description>1 price setting</Description> <Documentation /> </PackageHeader> <RedefinableHeader> <Author /> <Version /> <Countrykey>CO</Countrykey> </RedefinableHeader> <ExternalPackages /> <Participants> <Participant Id="008af9a6-fdc0-45e6-af3f-984c3e220e03" Name="customer"> <ParticipantType Type="RESOURCE" /> <Description /> </Participant> <Participant Id="1d2fd8b4-eb88-479b-9c1d-7fe6c45b910e" Name="clerk"> <ParticipantType Type="ROLE" /> <Description /> </Participant> </Participants> </Package> Despite, the simple pattern, the foreach doesn't work. What is wrong with Package/Participants/Participant ? What do I miss here? Thanks a lot!

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