Search Results

Search found 92562 results on 3703 pages for 'file object'.

Page 83/3703 | < Previous Page | 79 80 81 82 83 84 85 86 87 88 89 90  | Next Page >

• Eclipse / Aptana File Sync Solutions

  - by Brad

  Our development team uses Eclipse + Aptana to do their web development work. Currently, most of them are mapping their Eclipse projects directly to the web server. I'd rather them create a local project and use that to sync to the web server project directory they are working on. The issue is that there aren't any good solutions which is just appalling given the popularity of the two. The FileSync plugin for Eclipse is only one-way. Meaning if another developer makes a change to the file on the server, another dev isn't even notified and could overwrite the change. The File Transfer option in Aptana 2.0 doesn't support any sort of Sync, just manually uploading/downloading files. The Sync option in Aptana 1.5.1 doesn't allow you to merge files when they are different. You can only update one or the other. It does however allow you to view a diff (but only if you right click and select) and in that diff you can't make any changes. I did find a way to allow files to be uploaded to their Sync repositories in Aptana using Eclipse Monkey. However it doesn't work if a user saves multiple files at once, 'Save All', again it doesn't work. And additionally, there is no notification if a user opens a local file that has an updated copy on the server. I tried to add one using Eclipse Monkey but I couldn't find any sort of listener in the Eclipse API to do it and any Eclipse Monkey documentation is far and few between. My only solution at this point is just to let them continue to map directly to the server or ask them to do a manual download before they do any work (but again what if someone uploads a change right after they do that). Anyone have any ideas?

  Read the article

• How to determine if a file will be logically moved or physically moved.

  - by Frederic Morin

  The facts: When a file is moved, there's two possibilities: The source and destination file are on the same partition and only the file system index is updated The source and destination are on two different file system and the file need to be moved byte per byte. (aka copy on move) The question: How can I determine if a file will be either logically or physically moved ? I'm transferring large files (700+ megs) and would adopt a different behaviors for each situation. Edit: I've already coded a moving file dialog with a worker thread that perform the blocking io call to copy the file a meg at a time. It provide information to the user like rough estimate of the remaining time and transfer rate. The problem is: how do I know if the file can be moved logically before trying to move it physically ?

  Read the article

• Expando Object and dynamic property pattern

  - by Al.Net

  I have read about 'dynamic property pattern' of Martin Fowler in his site under the tag 1997 in which he used dictionary kind of stuff to achieve this pattern. And I have come across about Expando object in c# very recently. When I see its implementation, I am able to see IDictionary implemented. So Expando object uses dictionary to store dynamic properties and is it what, Martin Fowler already defined 15 years ago?

  Read the article

• Dynamically created iframe used to download file triggers onload with firebug but not without

  - by justkt

  EDIT: as this problem is now "solved" to the point of working, I am looking to have the information on why. For the fix, see my comment below. I have an web application which repeatedly downloads wav files dynamically (after a timeout or as instructed by the user) into an iframe in order to trigger the a default audio player to play them. The application targets only FF 2 or 3. In order to determine when the file is downloaded completely, I am hoping to use the window.onload handler for the iframe. Based on this stackoverflow.com answer I am creating a new iframe each time. As long as firebug is enabled on the browser using the application, everything works great. Without firebug, the onload never fires. The version of firebug is 1.3.1, while I've tested Firefox 2.0.0.19 and 3.0.7. Any ideas how I can get the onload from the iframe to reliably trigger when the wav file has downloaded? Or is there another way to signal the completion of the download? Here's the pertinent code: HTML (hidden's only attribute is display:none;): <div id="audioContainer" class="hidden"> </div> JavaScript (could also use jQuery, but innerHTML is faster than html() from what I've read): waitingForFile = true; // (declared at the beginning of closure) $("#loading").removeClass("hidden"); var content = "<iframe id='audioPlayer' name='audioPlayer' src='" + /path/to/file.wav + "' onload='notifyLoaded()'></iframe>"; document.getElementById("audioContainer").innerHTML = content; And the content of notifyLoaded: function notifyLoaded() { waitingForFile = false; // (declared at beginning of the closure) $("#loading").addClass("hidden"); } I have also tried creating the iframe via document.createElement, but I found the same behavior. The onload triggered each time with firebug enabled and never without it. EDIT: Fixed the information on how the iframe is being declared and added the callback function code. No, no console.log calls here.

  Read the article

• Iterating through folders and files in batch file?

  - by Will Marcouiller

  Here's my situation. A project has as objective to migrate some attachments to another system. These attachments will be located to a parent folder, let's say "Folder 0" (see this question's diagram for better understanding), and they will be zipped/compressed. I want my batch script to be called like so: BatchScript.bat "c:\temp\usd\Folder 0" I'm using 7za.exe as the command line extraction tool. What I want my batch script to do is to iterate through the "Folder 0"'s subfolders, and extract all of the containing ZIP files into their respective folder. It is obligatory that the files extracted are in the same folder as their respective ZIP files. So, files contained in "File 1.zip" are needed in "Folder 1" and so forth. I have read about the FOR...DO command on Windows XP Professional Product Documentation - Using Batch Files. Here's my script: @ECHO OFF FOR /D %folder IN (%%rootFolderCmdLnParam) DO FOR %zippedFile IN (*.zip) DO 7za.exe e %zippedFile I guess that I would also need to change the actual directory before calling 7za.exe e %zippedFile for file extraction, but I can't figure out how in this batch file (through I know how in command line, and even if I know it is the same instruction "cd"). Anyone's help is gratefully appreciated.

  Read the article

• C# ASP.NET FILE TRANSFER FROM LOCAL MACHINE TO ANOTHER MACHINE

  - by Imcl

  I basically want to transfer a file from the client to the file storage server without actual login to the server so that the client cannot access the storage location on the server directly. I can do this only if i manually login to the storage server through windows login. I dont want to do that. This is a Web-Based Application. Using the link below, I wrote a code for my application. I am not able to get it right though, Please refer the link and help me ot with it... http://stackoverflow.com/questions/263518/c-uploading-files-to-file-server The following is my code:- protected void Button1_Click(object sender, EventArgs e) { filePath = FileUpload1.FileName; try { WebClient client = new WebClient(); NetworkCredential nc = new NetworkCredential(uName, password); Uri addy = new Uri("\\\\192.168.1.3\\upload\\"); client.Credentials = nc; byte[] arrReturn = client.UploadFile(addy, filePath); Console.WriteLine(arrReturn.ToString()); } catch (Exception ex) { Console.WriteLine(ex.Message); } } The following line doesn't execute... byte[] arrReturn = client.UploadFile(addy, filePath); THIS IS THE ERROR I GET :- "An exception occurred during a WebClient request"

  Read the article

• Choose a local file w/o uploading the chosen file

  - by Austin Hyde

  I am making a simple development tool for myself using PHP on my local development server. I would like a way to have a simple file-chooser to select a file without uploading it, but just retaining the file path. This is useful, because I will be the only one using the tool, and so PHP will have access to the chosen file without having it uploaded. My first thought is to have a <input type="file"...>, but as far as I know, there's no way to prevent the upload from happening. Is there a way to do this?

  Read the article

• icacls giving an error message "The System cannot Find the File Specified" When executed on folder

  - by someshine

  I have a remote share in windows 7 and accessing the same share from windows 2008. I have a small script in PHP which denys the read permission on a folder in a share and again give the full permissions on that folder in the share and deletes that folder .Here the Problem is "Denying the Read Permission is working fine and again assigning full permission on that folder in the share is not working .Iam using icacls for assigning all the permissions .When i try to assign the Full permission on that folder in the share It is giving error message "The system cannot find the file specified ".When we output the command from the script and execute it on commandline it is working fine .Why is it not working from my PHP script .Please Advise me $dir_name = "testdir"; $share_path = "\\SERVERABCD\myshare"; mkdir($share_path."\$dir_name"); $path_escaped = '"'.$path.'"'; $user = getenv('USERNAME'); $cmd = 'icacls ' . $path_escaped . ' /deny ' . $user . ':(OI)(CI)(R)'; exec($cmd); //From This statement it is giving error message "the System cannot find the file Specified" $cmd = 'icacls ' . $path_escaped . ' /remove:d' .' '. $user; exec($cmd); $cmd = 'icacls ' . $path_escaped . ' /grant ' . $user . ':(OI)(CI)(F)'; exec($cmd); if(file_exists($share_path."\$dir_name")){ rmdir($share_path."\$dir_name"); } ? //This Scripts Works Fine For Files on shares where as it says "The System cannot find the file specified" for folders from second $cmd statement .

  Read the article

• Sending a file over web service from java to .net

  - by Goran

  Hello, I have built .NET 1.1 Web Service which should accept files and save them. Here is the code of the webmethod: [WebMethod] public bool SaveDocument(Byte[] docbinaryarray, string docname) { string dirPath = @"C:\Temp\WSTEST\"; if(!Directory.Exists(dirPath)) { Directory.CreateDirectory(dirPath); } string filePath = dirPath + docname; FileStream objfilestream = new FileStream(filePath, FileMode.Create, FileAccess.ReadWrite); objfilestream.Write(docbinaryarray, 0, docbinaryarray.Length); objfilestream.Close(); return true; } When I make a client in .NET with reference to this Web service everything goes great, but when a college of mine tries to send me a file from a JAVA client I don't get the actuall file. All I get is byte array with only one element. Definition of byte array for file, in WSDL looks like this: <s:element minOccurs="0" maxOccurs="1" name="docbinaryarray" type="s:base64Binary" /> He sends me base64binary and fails every time. All I get is Byte array with only one element inside.

  Read the article

• using property file along with config file to be used with mxmlc

  - by whoopy_whale

  Hi, I'm trying to run mxmlc in the following manner. mxmlc -load-config+=mycfg.xml C:\\projects\\src\\main.mxml -output myswf.swf In the config file, I want to keep some values configurable, for example the paths of the external libraries. Is it possible to include a property file into the config file and use it as {property_name} in the config file? Or is it possible to pass certain arguments from the command line itself that will override/replace the corresponding values in the config file, like the -D option in the ant command? Please provide your suggestions.

  Read the article

• How to download .exe file with progress bar - VB 2012

  - by user2839828

  I am trying to create an updater for my program which automatically download's the latest version of my program from the web. Now I want this process to be done using a progress bar (so when the download progress is at 50% the progress bar is half-way through). This is my code: Private Sub client_ProgressChanged(ByVal sender As Object, ByVal e As DownloadProgressChangedEventArgs) Dim bytesIn As Double = Double.Parse(e.BytesReceived.ToString()) Dim totalBytes As Double = Double.Parse(e.TotalBytesToReceive.ToString()) Dim percentage As Double = bytesIn / totalBytes * 100 client.Value = Int32.Parse(Math.Truncate(percentage).ToString()) End Sub Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click Dim url As String = "MY DOWNLOAD LINK" 'Download Dim client As WebClient = New WebClient AddHandler client.DownloadProgressChanged, AddressOf client_ProgressChanged AddHandler client.DownloadFileCompleted, AddressOf client_DownloadCompleted client.DownloadFileAsync(New Uri(url), "C:\Users\User\Desktop\BACKUP\TESTING\New folder\1.exe") End Sub End Class Now I know that the place where the file is saved has been inputed manually by me , but I will change that later. My problem currently is that the file is not being downloaded. However when I change the DownloadFileAsync method to DownloadFile , my program downloads the file. However with the DownloadFile method I will not be able to use the progress bar to track the download progress. Any help is much appreciated :-)

  Read the article

• Trying to write a video file using OpenCV

  - by Ted pottel

  Hi , I’m trying to use OpenCV to write a video file. I have a simple program that loads frames from a video file then accepts to save them At first the cvCreateVideoWrite always return NULL. I got a answer from your group saying it returns separate images and to try to change the file name to test0001.png, this worked. But now the cvWriteFrame function always fails, the code is CString path; path="d:\\mice\\Test_Day26_2.avi"; CvCapture* capture = cvCaptureFromAVI(path); IplImage* img = 0; CvVideoWriter *writer = 0; int isColor = 1; int fps = 25; // or 30 int frameW = 640; // 744 for firewire cameras int frameH = 480; // 480 for firewire cameras writer=cvCreateVideoWriter("d:\\mice\\test0001.png",CV_FOURCC('P','I','M','1'), fps,cvSize(frameW,frameH),isColor); if (writer==0) MessageBox("could not open writter"); int nFrames = 50; for(int i=0;i<nFrames;i++){ if (!cvGrabFrame(capture)) MessageBox("could not grab frame"); img=cvRetrieveFrame(capture); // retrieve the captured frame if (img==0) MessageBox("could not retrive data"); if (!cvWriteFrame(writer,img) ) MessageBox("could not write frame"); } cvReleaseVideoWriter(&writer); Any help would be GREAT - Ted

  Read the article

• Sql Server Backup and move backup file: How to cope with file permissions?

  - by Stefan Steinegger

  With our product we have a simple backup tool for the sql server database. This tool should just make a full backup and restore to and from any folder. Of course, the user (usually an administrator) needs permission to write to the target folder. To avoid the problem of not being able to perform a backup to a network drive, I write the backup to a temp file in the Sql Server backup directory. Then I move it to the target folder. This requires permission to delete the temporary file from the sql servers backup folder. Restore is the same in the other direction. This seemed to work fine until someone tested it on vista, where the user does not have write access to the backup folder by default. So there are many solutions to solve this, but none of them seemed to be really nice. One solution would be to find another folder for the temporary file. Both the sql server user as well as the administrator performing the backup need read and write permissions. Is there such a directory? Any other ideas? Thanks a lot.

  Read the article

• trying to read a delimited text file from resources - but it wont run

  - by Bigfatty

  I'm having a problem where instead of reading a text file from the location string, I changed it to read the text file from the resource location and it messes up my program. I've also used the insert snippet method to get most of this code, so it is safe to say I don't know what is going on. Could some one please help? 'reads the text out of a delimited text file and puts the words and hints into to separate arrays ' this works and made the program run ' Dim filename As String = Application.StartupPath + "\ProggramingList.txt" 'this dosnt work and brings back a Illegal characters in path error. dim filename as string = My.Resources.GamesList Dim fields As String() 'my text files are delimited Dim delimiter As String = "," Using parser As New TextFieldParser(filename) parser.SetDelimiters(delimiter) While Not parser.EndOfData ' Read in the fields for the current line fields = parser.ReadFields() ' Add code here to use data in fields variable. 'put the result into two arrays (the fields are the arrays im talking about). one holds the words, and one holds the corresponding hint Programingwords(counter) = Strings.UCase(fields(0)) counter += 1 'this is where the hint is at Programingwords(counter) = (fields(1)) counter += 1 End While End Using

  Read the article

• Using file() incrementally?

  - by NeedBeerStat

  I'm not sure if this is possible, I've been googling for a solution... But, essentially, I have a very large file, the lines of which I want to store in an array. Thus, I'm using file(), but is there a way to do that in batches? So that every,say, 100 lines it creates, it "pauses"? I think there's likely to be something I can do with a foreach loop or something, but I'm not sure that I'm thinking about it the right way... Like $i=0; $j=0; $throttle=100; foreach($files as $k => $v) { if($i < $j+$throttle && $i > $j) { $lines[] = file($v); //Do some other stuff, like importing into a db } $i++; $j++; } But, I think that won't really work because $i & $j will always be equal... Anyway, feeling muddled... Can someone help me think a lil' clearer?

  Read the article

• Check if an object is facing another based on angles

  - by Isaiah

  I already have something that calculates the bearing angle to get one object to face another. You give it the positions and it returns the angle to get one to face the other. Now I need to figure out how tell if on object is facing toward another object within a specified field and I can't find any information about how to do this. The objects are obj1 and obj2. Their angles are at obj1.angle and obj2.angle. Their vectors are at obj1.pos and obj2.pos. It's in the format [x,y]. The angle to have one face directly at another is found with direction(obj1.pos,obj2.pos). I want to set the function up like this: isfacing(obj1,obj2,area){...} and return true/false depending if it's in the specified field area to the angle to directly see it. I've got a base like this: var isfacing = function (obj1,obj2,area){ var toface = direction(obj1.pos,obj2.pos); if(toface+area >= obj1.angle && ob1.angle >= toface-area){ return true; } return false; } But my problem is that the angles are in 360 degrees, never above 360 and never below 0. How can I account for that in this? If the first object's angle is say at 0 and say I subtract a field area of 20 or so. It'll check if it's less than -20! If I fix the -20 it becomes 340 but x < 340 isn't what I want, I'd have to x 340 in that case. Is there someone out there with more sleep than I that can help a new dev pulling an all-nighter just to get enemies to know if they're attacking in the right direction? I hope I'm making this harder than it seems. I'd just make them always face the main char if the producer didn't want attacks from behind to work while blocking. In which case I'll need the function above anyways. I've tried to give as much info as I can think would help. Also this is in 2d.

  Read the article

• php fopen function dies, though I have file permissions set to read and write

  - by Matthew Robert Keable

  I'm following a tutorial on php, and am having difficulty getting this to work. I set the appropriate directory permissions to read and write, but every time I run this, I get the die string. The code is: $ourFileName = "testFile.txt"; $ourFileHandle = fopen($ourFileName, 'w') or die("can't open file"); fclose($ourFileHandle); As far as my basic understanding goes, if "testFile.txt" does not exist, fopen should create that file (I have basic knowledge of Python, and remember this same principle in that language). But it...it doesn't. Even if I create the aforementioned file, and put it up, that line of code still returns a die string. My hosting account does not give me permission to execute. Is this a problem? My server runs on Windows. I am using Dreamweaver CS5, on OSX 10.5.8. I've done some searching on this, and see other people having similar issues - but none of them keyed to exactly my range of problems. Being that I'm a beginner, I feel that it might be something I'm overlooking. Thanks!!

  Read the article

• Moving to an arbitrary position in a file in Python

  - by B Rivera

  Let's say that I routinely have to work with files with an unknown, but large, number of lines. Each line contains a set of integers (space, comma, semicolon, or some non-numeric character is the delimiter) in the closed interval [0, R], where R can be arbitrarily large. The number of integers on each line can be variable. Often times I get the same number of integers on each line, but occasionally I have lines with unequal sets of numbers. Suppose I want to go to Nth line in the file and retrieve the Kth number on that line (and assume that the inputs N and K are valid --- that is, I am not worried about bad inputs). How do I go about doing this efficiently in Python 3.1.2 for Windows? I do not want to traverse the file line by line. I tried using mmap, but while poking around here on SO, I learned that that's probably not the best solution on a 32-bit build because of the 4GB limit. And in truth, I couldn't really figure out how to simply move N lines away from my current position. If I can at least just "jump" to the Nth line then I can use .split() and grab the Kth integer that way. The nuance here is that I don't just need to grab one line from the file. I will need to grab several lines: they are not necessarily all near each other, the order in which I get them matters, and the order is not always based on some deterministic function. Any ideas? I hope this is enough information. Thanks!

  Read the article

• Swt file dialog too much files selected?

  - by InsertNickHere

  Hi there, the swt file dialog will give me an empty result array if I select too much files (approx. 2500files). The listing shows you how I use this dialog. If i select too many sound files, the syso will show 0. Debugging tells me, that the files array is empty in this case. Is there any way to get this work? FileDialog fileDialog = new FileDialog(mainView.getShell(), SWT.MULTI); fileDialog.setText("Choose sound files"); fileDialog.setFilterExtensions(new String[] { new String("*.wav") }); Vector<String> result = new Vector<String>(); fileDialog.open(); String[] files = fileDialog.getFileNames(); for (int i = 0, n = files.length; i < n; i++) { if( !files[i].contains(".wav")) { System.out.println(files[i]); } StringBuffer stringBuffer = new StringBuffer(); stringBuffer.append(fileDialog.getFilterPath()); if (stringBuffer.charAt(stringBuffer.length() - 1) != File.separatorChar) { stringBuffer.append(File.separatorChar); } stringBuffer.append(files[i]); stringBuffer.append(""); String finalName = stringBuffer.toString(); if( !finalName.contains(".wav")) { System.out.println(finalName); } result.add(finalName); } System.out.println(result.size()) ;

  Read the article

• Hiding System Objects in Object Explorer in SQL Server Management Studio

  While looking through the new features and improvements in SQL Server Management Studio (SSMS) we found a potentially interesting one to Hide System Objects in Object Explorer in SQL Server Management Studio. In this tip we will take a look at how to Hide System Objects in Object Explorer. Join SQL Backup’s 35,000+ customers to compress and strengthen your backups "SQL Backup will be a REAL boost to any DBA lucky enough to use it." Jonathan Allen. Download a free trial now.

  Read the article

• Cant print contents of a custom file

  - by ZaZu

  Hello, Im trying to scan contents from a random file into an array in a structure. Then I want to print those contents on screen. (NOTE: The following code is from a bigger program, this is just a sample, but all structures and arrays used are needed as declared ) The contents of the file being tested are simply: 5 4 3 2 5 3 4 2 #include<stdio.h> #define first 500 #define sec 500 struct trial{ int f; int r; float what[first][sec]; }; int trialtest(trial *test); int trialdisplay(trial *test); main(){ trial test; trialtest(&test); trialdisplay(&test); } int trialtest(trial *test){ int z,x,i; FILE *inputf; inputf=fopen("randomfile.txt","r"); for(i=0;i<5;i++){ fscanf(inputf,"%f",&(*test).what[z][x]); } fclose(inputf); return 0; } int trialdisplay(trial *test){ int i,z,x; printf("printing\n\n\n"); for (i=0;i<10;i++){ printf("%f",(*test).what[z][x]); } return 0; } The problem is, I get this error whenever I run the code .. I cant really understand whats going on : Any suggestions ? Thanks alot !

  Read the article

• Read a file address from a txt file using netbeans c

  - by Yadira Suazo

  Hi everybody. I`m having problems reading a file address from a txt file. The information seems to be corrupted when I watch it in the debugger. The code is FILE *parch; const char * vectorparch[50]; //array with 50 file paths parch = fopen("/home/irmay/NetBeansProjects/neurona/patrones/patrones.txt", "r"); for(j=0;j<50;j++){ fread ( vectorparch, sizeof ( char ), 50, parch ); propagar(vectorparch[j]); } fclose(parch); The file with paths has 50 strings is like this: "/home/irmay/NetBeansProjects/neurona/patrones/10_0.txt","/home/..." The function propagar is declared void propagar (const char * arch1) Thank you.

  Read the article

• Any Alternate way for writing to a file other than ofstream

  - by Aditya

  Hi All, I am performing file operations (writeToFile) which fetches the data from a xml and writes into a output file(a1.txt). I am using MS Visual C++ 2008 and in windows XP. currently i am using this method of writing to output file.. 01.ofstreamhdr OutputFile; 02./* few other stmts / 03.hdrOutputFile.open(fileName, std::ios::out); 04. 05.hdrOutputFile << "#include \"commondata.h\""<< endl ; 06.hdrOutputFile << "#include \"Commonconfig.h\"" << endl ; 07.hdrOutputFile << "#include \"commontable.h\"" << endl << endl ; 08. hdrOutputFile << "#pragma pack(push,1)" << endl ; 09.hdrOutputFile << "typedef struct \n {" << endl ; 10./ simliar hdrOutputFiles statements... */.. I have around 250 lines to write.. Is any better way to perform this task. I want to reduce this hdrOutputFile and use a buffer to do this. Please guide me how to do that action. I mean, buff = "#include \"commontable.h\"" + "typedef struct \n {" + ....... hdrOutputFile << buff. is this way possible? Thanks Ramm

  Read the article

• Object Dependency in SQL Server

  When a SQL Server object is created that references another SQL Server object, such as a stored procedure called from a trigger, that dependency is recorded by the database engine. This article details how to get at that dependency information.

  Read the article

• Ruby - Writing Hpricot data to a file

  - by John

  Hey everyone, I am currently doing some XML parsing and I've chosen to use Hpricot because of it's ease of use and syntax, however I am running into some problems. I need to write a piece of XML data that I have found out to another file. However, when I do this the format is not preserved. For example, if the content should look like this: <dict> <key>item1</key><value>12345</value> <key>item2</key><value>67890</value> <key>item3</key><value>23456</value> </dict> And assuming that there are many entries like this in the document. I am iterating through the 'dict' items by using hpricot_element = Hpricot(xml_document_body) f = File.new('some_new_file.xml') (hpricot_element/:dict).each { |dict| f.write( dict.to_original_html ) } After using the above code, I would expect that the output look like the following exactly like the XML shown above. However to my surprise, the output of the file looks more like this: <dict>\n", " <key>item1</key><value>12345</value>\n", " <key>item2</key><value>67890</value>\n", " <key>item3</key><value>23456</value\n", " </dict> I've tried splitting at the "\n" characters and writing to the file one line at a time, but that didn't seem to work either as it did not recognize the "\n" characters. Any help is greatly appreciated. It might be a very simple solution, but I am having troubling finding it. Thanks!

  Read the article

< Previous Page | 79 80 81 82 83 84 85 86 87 88 89 90  | Next Page >