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  • Printing Stdout In Command Line App Without Overwriting Pending User Input

    - by Chris S
    In a basic Unix-shell app, how would you print to stdout without disturbing any pending user input. e.g. Below is a simple Python app that echos user input. A thread running in the background prints a counter every 1 second. import threading, time class MyThread( threading.Thread ): running = False def run(self): self.running = True i = 0 while self.running: i += 1 time.sleep(1) print i t = MyThread() t.daemon = True t.start() try: while 1: inp = raw_input('command> ') print inp finally: t.running = False Note how the thread mangles the displayed user input as they type it (e.g. hell1o wo2rld3). How would you work around that, so that the shell writes a new line while preserving the line the user's currently typing on?

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  • Learning Linux screencasts

    - by Dmitriy Nagirnyak
    Hi, I am trying to get started with Linux. There are number of books (many of which are just man pages), some of them provide good overview so I can dig deeper online then. What I would like is to find number of screencasts that would cover basics of Linux commands, server administration, commonly performed tasks etc (no GUI, only terminal). I want to watch the screencasts to "get it quicker" and then use a book or online resources to "dig it deeper". Any recommendations? Thanks, Dmitriy.

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  • Redirect output to file

    - by Algorist
    Hi, I have a shell script which is currently running and was running from past 8 hours. It will complete only by tomorrow evening. At the end of the program, it will print 2 million words to standard output. I am running the program on the screen. I forgot to redirect the output to a file. I know I won't be able to copy the data from the window. Is there a way to output the command to a file. I don't want to restart the program. Any thoughts?? Thank you. Bala

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  • Display contents of a file in the parent directory

    - by Sharjeel Sayed
    I have a command which lists Weblogic instances directories on a server.I want to display contents of a file in the parent directory of each directory listed. An additional feature would be to display the name of the file in addition to displaying the contents /usr/ucb/ps auwwx | grep weblogic | tr ' ' '\n' | grep security.policy | grep domain | awk -F'=' '{print $2}' | sed -e 's/weblogic.policy//' -e 's/security\///' | sort The output of the above command looks like this /opt/<some_directory>/<domain_name>/<app_name>/ /opt/<some_directory>/<domain_name>/<app_name>/ I want to cat a file somefile.cf in the directory

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  • Using inotify-tools and ruby to push uploads to Cloud Files

    - by Christian
    Hi Guys, I wrote a few scripts to monitor an uploads directory for changes, then capture the file uploaded/changed and push it to cloud files using a ruby script. This all works well 95% of the time, the only exception is that occasionally, ruby fails with a 'file does not exist' exception. I am assuming that the ruby 'push' script is being called before the file is 100% in its new location, so the script is being called a little prematurely. I tried adding a little function to my script to check if the file exists, if it doesn't, sleep 5 then try again, but this seems to snowball and eventually dies. I then just added a sleep 2 to all calls, but it hasn't helped as I now get the 'file does not exist' error again. #!/bin/sh function checkExists { if [ ! -e "$1" ] then sleep 5 checkExists $1 fi } inotifywait -mr --timefmt '%d/%m/%y-%H:%M' --format '%T %w %f' -e modify,moved_to,create,delete /home/skylines/html/forums/uploads | while read date dir file; do cloudpath=${dir:20}${file} localpath=${dir}${file} #checkExists $localpath sleep 2 ruby /home/cbiggins/bin/pushToCloud.rb skylinesaustralia.com $cloudpath $localpath echo "${date} ruby /home/cbiggins/bin/pushToCloud.rb skylinesaustralia.com $cloudpath $localpath" >> /var/log/pushToCloud.log done I am looking for any suggestions to help me make this 100% stable (eventually, I'll serve the uploaded files from Cloud FIles, so I need to make sure its perfect) Thanks in advance!

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  • Macports sudo expands ~ to /var/root in python

    - by calavera
    This might be a bit dev-heavy for the site... but here goes. I installed the macports version of sudo. All is well, except for one thing. Using python 2.6 to expand ~ to the user's home directory results in a different output than the version of sudo that comes with Snow Leopard. For example consider the following python code: #expand_home_dir.py import os os.path.expanduser('~') Below are 3 different calls of the code listed above. The first call using sudo is using the Macports version because my $PATH begins with /opt/local/bin: robert$ python2.6 expand_home_dir.py /Users/robert robert$ sudo python2.6 expand_home_dir.py /var/root robert$ /usr/bin/sudo python2.6 expand_home_dir.py /Users/robert Any idea why this is happening?

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  • Cygwin command not found bad characters found in .bashrc 357\273\277

    - by mytwocents
    Hello, I'm new to Cygwin, I just installed it and attempted to set some simple environment variables. However, when I open the command shell, I get the error "#357\273\277 command not found" I found an article that discusses what the problem is and how to "discover" the hidden bad character: http://mblog.lib.umich.edu/DataDiscussions/archives/2010/01/index.html but I don't know how to resolve the issue by removing the character (which I validated was a problem in my .bashrc file using the od command). I attempted to change the preferences view in Notepad++ to UTF-8 and ANSI to no avail, but the file was not altered at all. Any help would be appreciated...

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  • SED - Regular Expression over multiple lines

    - by herrherr
    Hi there, I'm stuck with this for several hours now and cycled through a wealth of different tools to get the job done. Without success. It would be fantastic, if someone could help me out with this. Here is the problem: I have a very large CSV file (400mb+) that is not formatted correctly. Right now it looks something like this: Alan Smithee ist ein Anagramm von „The [...] „Alan Smythee“, und „Adam Smithee“." ,Alan Smithee Die Aussagenlogik ist der Bereich der Logik, der sich mit [...] ihrer Teilaussagen bestimmen. ,Aussagenlogik As you can probably see the words ",Alan Smithee" and ",Aussagenlogik" should actually be on the same line as the foregoing sentence. Then it would look something like this: Alan Smithee ist ein Anagramm von „The Smitheeeee [...] „Alan Smythee“, und „Adam Smithee“.,Alan Smithee Die Aussagenlogik ist der Bereich der Logik, der sich mit [...] ihrer Teilaussagen bestimmen.,Aussagenlogik Please note that the end of the sentence can contain quotes or not. In the end they should be replaced too. Here is what I came up with so far: sed -n '1h;1!H;${;g;s/\."?.*,//g;p;}' out.csv > out1.csv This should actually get the job done of matching the expression over multiple lines. Unfortunately it doesn't :) The expression is looking for the dot at the end of the sentence and the optional quotes plus a newline character that I'm trying to match with .*. Help much appreciated. And it doesn't really matter what tool gets the job done (awk, perl, sed, tr, etc.). Thanks, Chris

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  • Linux/OpenSSL:Send find output to openssl

    - by Starsky
    I am trying to send the output from the find command to OpenSSL in order to find out when certificates expire. This finds the files find . -name \*.pem -type f This generates the cert info I want openssl x509 -in certname.pem -noout -enddate Can I merge these two? Thanks for your help.

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  • SSH login with expect(1). How to exit expect and remain in SSH?

    - by Koroviev
    So I wanted to automate my SSH logins. The host I'm with doesn't allow key authentication on this server, so I had to be more inventive. I don't know much about shell scripting, but some research showed me the command 'expect' and some scripts using it for exactly this purpose. I set up a script and ran it, it worked perfectly to login. #!/usr/bin/env expect -f set password "my_password" match_max 1000 spawn ssh -p 2222 "my_username"@11.22.11.22 expect "*?assword:*" send -- "$password\r" send -- "\r" expect eof Initially, it runs as it should. Last login: Wed May 12 21:07:52 on ttys002 esther:~ user$ expect expect-test.exp spawn ssh -p 2222 [email protected] [email protected]'s password: Last login: Wed May 12 15:44:43 2010 from 20.10.20.10 -jailshell-3.2$ But that's where the success ends. Commands do not work, but hitting enter just makes a new line. Arrow keys and other non-alphanumeric keys produce symbols like '^[[C', '^[[A', '^[OQ' etc.[1] No other prompt appears except the two initially created by the expect script. Any ignored commands will be executed by my local shell once expect times out. An example: -jailshell-3.2$ whoami ls pwd hostname (...time passes, expect times out...) esther:~ user$ whoami user esther:~ ciaran$ ls Books Documents Movies Public Code Downloads Music Sites Desktop Library Pictures expect-test.exp esther:~ ciaran$ pwd /Users/ciaran esther:~ ciaran$ hostname esther.local As I said, I have no shell scripting experience, but I think it's being caused because I'm still "inside of" expect, but not "inside of" SSH. Is there any way to terminate expect once I've logged in, and have it hand over the SSH session to me? I've tried commands like 'close' and 'exit', after " send -- "\r" ". Yeah, they do what I want and expect dies, but it vindictively takes the SSH session down with it, leaving me back where I started. What I really need is for expect to do its job and terminate, leaving the SSH session back in my hands as if I did it manually. All help is appreciated, thanks. [1] I know there's a name for this, but I don't know what it is. And this is one of those frightening things which can't be googled, because the punctuation characters are ignored. As a side question, what's the story here?

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  • Is it possible to distribute STDIN over parallel processes?

    - by Erik
    Given the following example input on STDIN: foo bar bar baz === qux bla === def zzz yyy Is it possible to split it on the delimiter (in this case '===') and feed it over stdin to a command running in parallel? So the example input above would result in 3 parallel processes (for example a command called do.sh) where each instance received a part of the data on STDIN, like this: do.sh (instance 1) receives this over STDIN: foo bar bar baz do.sh (instance 2) receives this over STDIN: qux bla do.sh (instance 3) receives this over STDIN: def zzz yyy I suppose something like this is possible using xargs or GNU parallel, but I do not know how.

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  • cpio VS tar and cp

    - by Tim
    I just learned that cpio has three modes: copy-out, copy-in and pass-through. I was wondering what are the advantages and disadvantages of cpio under copy-out and copy-in modes over tar. When is it better to use cpio and when to use tar? Similar question for cpio under pass-through mode versus cp. Thanks and regards!

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  • Proper way to set PYTHONPATH (including precedence)

    - by Wells
    In .bashrc I have: export PYTHONPATH=/home/wells/py-mlb I've verified this is actually being set. so, in this directory is another directory called 'py_mlb'- the actual module. So I go python -v and then import py_mlb but it does: >>> import py_mlb import py_mlb # directory /usr/local/lib/python2.6/dist-packages/py_mlb Then I do import sys and print sys.path and I see: >>> print sys.path ['', '/usr/local/lib/python2.6/dist-packages/python_memcached-1.44-py2.6.egg', '/usr/local/lib/python2.6/dist-packages/pymc-2.1alpha-py2.6-linux-i686.egg', '/usr/local/lib/python2.6/dist-packages/nose-0.11.1-py2.6.egg', '/home/wells/py-mlb', '/usr/lib/python2.6', '/usr/lib/python2.6/plat-linux2', '/usr/lib/python2.6/lib-tk', '/usr/lib/python2.6/lib-old', '/usr/lib/python2.6/lib-dynload', '/usr/lib/python2.6/dist-packages', '/usr/local/lib/python2.6/dev-packages', '/usr/lib/pymodules/python2.6', '/usr/lib/pymodules/python2.6/gtk-2.0', '/usr/local/lib/python2.6/dist-packages'] So my path from .bashrc IS in there, and from the look of it it's even before dist-packages but it's importing the module from dist-packages. How can I finagle this so the PYTHONPATH as defined by .bashrc takes precedence? Thanks!

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  • Unix file naming convention for effective tab completion?

    - by thebossman
    I feel like I often name files in such a way that my computer constantly beeps while I program because the tab completion is ambiguous. Before doing a lot of Unix programming, I tended to name related files with the same prefix to indicate their relation. Now I must re-think my approach to folder and file structures and names to program more effectively. What heuristics or rules do you apply when programming to simplify tab completion? Do you use any tools to make tab completion smoother (e.g., emacs icicles)?

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  • expr non-numeric argument shell script

    - by Kimi
    The below check is not working : expr non-numeric argument shell script. Always it is going to else. Please tell me what is the mistake. Earlier I was no using while so the same thing was woring fine now suddenly when I did put it in the while loop it is no working. echo "`${BOLD}` ***** Checking Memory Utilization User*****`${UNBOLD}`" echo "===================================================" IFS='|' cat configMachineDetails.txt | grep -v "^#" | while read MachineType UserName MachineName do export MEMORY_USAGE1=`ssh -f -T ${UserName}@${MachineName} prstat -t -s rss 1 2 | tr '%' ' '| awk '$5>5.0'` export LEN=`echo "$MEMORY_USAGE1"|wc -l` export CNPROC=`echo "$MEMORY_USAGE1"|grep "NPROC"|wc -l` export CTotal=`echo "$MEMORY_USAGE1"|grep "Total"|wc -l` **if [ $LEN = `expr $CNPROC + $CTotal` ] then echo "`${BOLD}`**************All usages are normal !!!!!! *************`${UNBOLD}`" else echo "`${BOLD}`**** Memory(%) is more than 5% in MachineType $MachineType UserName $UserName MachineName $MachineName *******`${UNBOLD}`" echo "====================================================" echo "$MEMORY_USAGE1" fi** done

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  • Replace string in one file with contents of a second file

    - by jag7720
    I have two files: fileA: date >> /root/kvno.out kvno serverXXX\$ >> /root/kvno.out fileB: foobar I need to create a new file, fileC, with the same contents as fileA, except with the string XXX being replaced with the contents of fileB: date >> /root/kvno.out kvno serverfoobar\$ >> /root/kvno.out I'd like to do this using sed. I tried some of the examples I found but I only get the contents of fileB in fileC.

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  • matching files with regular expressions

    - by Javier
    Dear all, I have an input file with a list of movies (Note that there might be some repeated entries): American_beauty__1h56mn38s_ As_Good_As_It_Gets As_Good_As_It_Gets _DivX-ITA__Casablanca_M_CURTIZ_1942_Bogart-bergman_ Capote_EN_DVDRiP_XViD-GeT-AW _DivX-ITA__Casablanca_M_CURTIZ_1942_Bogart-bergman_ I would to find the corresponding match (line number) from another reference file for each of the entries in the first file: American beauty.(1h56mn38s) As Good As It Gets Capote.EN.DVDRiP.XViD-GeT-AW [DivX-ITA] Casablanca(M.CURTIZ 1942 Bogart-bergman) Quills (2000)(7.4) The desired output would be something like (Reference Movie + Line number from the Reference File): American beauty.(1h56mn38s) 1 As Good As It Gets 2 As Good As It Gets 2 [DivX-ITA] Casablanca(M.CURTIZ 1942 Bogart-bergman) 4 Capote.EN.DVDRiP.XViD-GeT-AW 3 [DivX-ITA] Casablanca(M.CURTIZ 1942 Bogart-bergman) 4 Basically, the difference between the entries in both files is that some characters such as: blank spaces, parenthesis, points, etc. have been replaced by underscores. Does anybody could shed some light on it? Best wishes, Javier

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  • Linux tail only whole words

    - by Andrew
    Hello, I need to print last 20 characters of string, but only whole words. Delimiter is a space "". Let's consider this example: string="The quick brown fox jumps over the lazy dog" echo $string | tail -c20 returns s over the lazy dog. And I need it to return over the lazy dog instead. Do you know how to accomplish that? Thanks!

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  • How to use a variable in an awk expression

    - by lugte098
    I'm trying to make this command: sed bla bla filename | awk '{printf "%s %s_entry_%.3f %.3f %.3f %.3f",$1,$3,$4,$5,$6,$7}' But the thing is, i want the %.3f part to be variable. So in one case it could be %.3f and in another it could be %.3f %.3f %.3f. So i'll just use a static one in my example code for clarity. So if i want 4 of these %.3f and put them in variable $values like so: values="%.3f %.3f %.3f %.3f" Then how can i put this string in the awk expression, without making awk to just put literally "${values}" in there. The following is my non-working-attempt: sed bla bla filename | awk '{printf "%s %s_entry_${values}",$1,$3,$4,$5,$6,$7}'

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