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• How can I write a null ASCII character (nul) to a file with a Windows batch script?

  - by Matthew Murdoch

  I'm attempting to write an ASCII null character (nul) to a file from a Windows batch script without success. I initially tried using echo like this: echo <Alt+2+5+6> which seems like it should work (typing <Alt+2+5+6> in the command window does write a null character - or ^@ as it appears), but echo then outputs: More? and hangs until I press <Return>. As an alternative I tried using: copy con tmp.txt >nul <Alt+2+5+6><Ctrl+Z> which does exactly what I need, but only if I type it manually in the command window. If I run it from a batch file it hangs until I press <Ctrl+Z> but even then the output file is created but remains empty. I really want the batch file to stand alone without requiring (for example) a separate file containing a null character which can be copied when needed.

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• How to get file path using FileUpload to be read by FileStream?

  - by john ryan

  I have a Method that open excel file and read it through exceldatareaderClass that i have downloaded in codeplex by using filestream. Currently I just declared the exact directory where the filestream open an excel file.And it works fine. Stream stream = new FileStream("C:\\" + FileUpload.PostedFile.FileName, FileMode.Open, FileAccess.Read, FileShare.Read); Now i need to read the excel file wherever location the user place it like on windows forms fileupload.FileStream needs the exact location where the file is located. How to do this.? Example: Sample.xls is located on My Documents the file path should be like : C:\Documents and Settings\user\My Documents\ string openpath ="" ;//filepath Stream stream = new FileStream(openpath+ FileUpload.PostedFile.FileName, FileMode.Open, FileAccess.Read, FileShare.Read); Thanks in Regards

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• PHP export to text file - Only saving first line.

  - by wertz8090

  I'm trying to export some extracted $_POST information into a text file, however my code is only capturing the first variable and ignoring the rest. I'm saving the information to the text file in this manner: $values = "First Name: $fName\r\n"; $values .= "Last Name: $lName\r\n"; $values .= "Address: $address\r\n"; etc. This is the code I use to write to the text file: $fp = @fopen("person.data", "w") or die("Couldn't open person.data for writing!"); $numBytes = @fwrite($fp, $values) or die("Couldn't write values to file!"); @fclose($fp); Any ideas on why it would only save the first $values ($fName) variable but not the rest of them? It actually saves the first part of the $values string for all of them (so I see Last Name:, Address:, etc. on separate lines in the text file) but the called variables $lName and $address do not appear.

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• DOS Batch file - Copy file based on filename elements

  - by user1848356

  I need to sort alot of files based on their filename. I would like to use a batch file to do it. I do know what I want but I am not sure of the correct syntax. Example of filenames I work with: (They are all in the same directory originally) 2012_W34_Sales_Store001.pdf 2012_W34_Sales_Store002.pdf 2012_W34_Sales_Store003.pdf 2012_November_Sales_Store001.pdf 2012_November_Sales_Store002.pdf 2012_November_Sales_Store003.pdf I would like to extract the information that are located between the "_" signs and put them into a different variable each time. The lenght of the informations contained between the _ signs will be different everytime. Example: var1="2012" var2="W34" (or November) var3="Sales" var4="001" If I am able to do this, I could then copy the files to the appropriate directory using move %var1%_%var2%_%var3%_%var4%.pdf z:\%var3%\%var4%\%var1%\%var2% It would need to loop because I have Store001 to Store050. Also, there are not only Sales report, many others are available. I hope I am clear. Please help me realize this batchfile!

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• Unable to move file because it's being used by another process -- my program?

  - by joslinm

  My program is unable to File.Move or File.Delete a file because it is being used "by another process", but it's actually my own program that is using it. I use Directory.GetFiles to initially get the file paths, and from there, I process the files by simply looking at their names and processing information that way. Consequently all I'm doing is working with the strings themselves, right? Afterwards, I try to move the files to a "Handled" directory. Nearly all of them will usually move, but from time to time, they simply won't because they're being used by my program. Why is it that most of them move but one or two stick around? Is there anything I can do to try freeing up the file? There's no streams to close.

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• How to pass a file (read from Java) most effectively to a native method?

  - by soc

  Hi, I have approx. 30000 files (1MB each) which I want to put into a native method, which requires just an byte array and the size of it as arguments. I looked through some examples and benchmarks (like http://nadeausoftware.com/articles/2008/02/java_tip_how_read_files_quickly) but all of them do some other fancy things. Basically I don't care about the contents of the file, I don't want to access something in that file or the byte array or do anything else with it. I just want to put a file into a native method which accepts an byte array as fast as possible. At the moment I'm using RandomAccessFile, but that's horribly slow (10MB/s). Is there anything like byte[] readTheWholeFile(File file){ ... } which I could put into native void fancyCMethod(readTheWholeFile(myFile), myFile.length()) What would you suggest?

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• file names based on file content

  - by Mark

  So iow, some algorithm to generate a unique, reasonable length filename based on binary file content. Two files that have the same binary content should have the same name. Obviously there would be limits to this, as presumably you couldn't have unique reasonable length filenames for each of a large set of large files only differing at a handful of bit positions. But presumably there is some heuristic, best approximation to this that for example exploits known attributes of typical image files. If I had the name of some algorithm that does this I can google it and find other approaches as well.

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• How do I do this in Python (File Manipulation)?

  - by ThinkCode

  I have a bunch of HTML files in HTML folder. Those HTML files have unicode characters which I solved by using filter(lambda x: x in string.printable, line). Now how do I write the changes back to the original file? What is the best way of doing it? Each HTML file is of 30 kb in size. 1 import os, string 2 3 for file in os.listdir("HTML/"): 4 print file 5 myfile = open('HTML/' + file) 6 fileList = myfile.readlines() 9 for line in fileList: 10 #print line 11 line = filter(lambda x: x in string.printable, line) 12 myfile.close()

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• Unity3d generating a file in iOS and saving it on a linux machine

  - by N0xus

  I've done a little research and don't know if the following is possible. At the moment I have created a small application in Unity that generates an XML file. This file will be used to help set up my game. It's done in Unity due to it being cross platform with no need to re-write a single line of code. Eventually this will run on an iPad. However, my game will be running on a linux computer and I need to pass over the XML file to the computer that will be running the final game (please don't ask why I'm doing that, it's something I need to do). So what I want to know is the following: Can I generate my XML file on an iPad and have that XML file be saved, and transmitted to a linux machine, without the need to manually copy the file over. If so, how is this possible?

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• How to Fix "Read-only file system" error when I run something as sudo and try to make a folder/file?

  - by Andrew

  When I try to save something or rename a file/folder it say this error " Read-only file system" or run something as root in the terminal it say this error sudo: unable to open /var/lib/sudo/"My User Name"/0: Read-only file system W: Not using locking for read only lock file /var/lib/dpkg/lock E: Unable to write to /var/cache/apt/ E: The package lists or status file could not be parsed or opened. When I make a Folder the error dialog in the details with Nautilus is this: Error creating directory: Read-only file system I would show you I picture of it but it isn't even letting my save onto my flash drive. Please help me.

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• Corrupted 7z file

  - by KI4JGT

  I recently wanted to try out Fedora. So I transfered all my files to it via USB. Then I got frustrated with it, placed all my files in a 7z archive and then copied them back to the drive. Now, every time I try to open the archive, "an error occurred while loading the archive" Thanks for your help [edit] There is no password on the archive. ls -alF file.7z -rw-r--r-- 1 jesse jesse 2422670837 Nov 3 22:58 file.7z 7z t file.7z 7-Zip [64] 9.20 Copyright (c) 1999-2010 Igor Pavlov 2010-11-18 p7zip Version 9.20 (locale=en_US.UTF-8,Utf16=on,HugeFiles=on,4 CPUs) Processing archive: jesse.7z Error: Can not open file as archive $ 7z l file.7z | head -15 7-Zip [64] 9.20 Copyright (c) 1999-2010 Igor Pavlov 2010-11-18 p7zip Version 9.20 (locale=en_US.UTF-8,Utf16=on,HugeFiles=on,4 CPUs) Error: jesse.7z: Can not open file as archive Errors: 1

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• Tip #13 java.io.File Surprises

  - by ByronNevins

  There is an assumption that I've seen in code many times that is totally wrong.  And this assumption can easily bite you.  The assumption is: File.getAbsolutePath and getAbsoluteFile return paths that are not relative.  Not true!  Sort of.  At least not in the way many people would assume.  All they do is make sure that the beginning of the path is absolute.  The rest of the path can be loaded with relative path elements.  What do you think the following code will print? public class Main {    public static void main(String[] args) {        try {            File f = new File("/temp/../temp/../temp/../");            File abs  = f.getAbsoluteFile();            File parent = abs.getParentFile();            System.out.println("Exists: " + f.exists());            System.out.println("Absolute Path: " + abs);            System.out.println("FileName: " + abs.getName());            System.out.printf("The Parent Directory of %s is %s\n", abs, parent);            System.out.printf("The CANONICAL Parent Directory of CANONICAL %s is %s\n",                        abs, abs.getCanonicalFile().getParent());            System.out.printf("The CANONICAL Parent Directory of ABSOLUTE %s is %s\n",                        abs, parent.getCanonicalFile());            System.out.println("Canonical Path: " + f.getCanonicalPath());        }        catch (IOException ex) {            System.out.println("Got an exception: " + ex);        }    }} Output: Exists: trueAbsolute Path: D:\temp\..\temp\..\temp\..FileName: ..The Parent Directory of D:\temp\..\temp\..\temp\.. is D:\temp\..\temp\..\tempThe CANONICAL Parent Directory of CANONICAL D:\temp\..\temp\..\temp\.. is nullThe CANONICAL Parent Directory of ABSOLUTE D:\temp\..\temp\..\temp\.. is D:\tempCanonical Path: D:\ Notice how it says that the parent of d:\ is d:\temp !!!The file, f, is really the root directory.  The parent is supposed to be null. I learned about this the hard way! getParentXXX simply hacks off the final item in the path. You can get totally unexpected results like the above. Easily. I filed a bug on this behavior a few years ago[1].   Recommendations: (1) Use getCanonical instead of getAbsolute.  There is a 1:1 mapping of files and canonical filenames.  I.e each file has one and only one canonical filename and it will definitely not have relative path elements in it.  There are an infinite number of absolute paths for each file. (2) To get the parent file for File f do the following instead of getParentFile: File parent = new File(f, ".."); [1] http://bt2ws.central.sun.com/CrPrint?id=6687287

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• How to access shared folders from file editors?

  - by Marchosius

  I am running a xampp server on one of my other computers, and when using the brows functionality from text editors like gedit, bluefish and Eclipse/Aptana studio I can access the shares I made for the sites running on the server. Even when I right click-edit with-application with the the file browser it does not open the file in the editor. How can get this to work without having to copy the file over from the share then edit and then upload again after I am done? Similar issue when trying to upload a file to hosting server direct from the file server I have with filezilla. with this I also need to copy the file over to my pc and then from there upload to the hosting server with filezilla. EDIT: For eclipse I found a build in functionality to do this. (new-remote system connection-Enter the access details) Nothing yet on FileZilla Hope my Question is clear

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• How to change the default editor of a specific file type in JDeveloper

  - by [email protected]

  When you open a file in JDeveloper, the mode that is used as the default might not be what you as a developer want.  If, for example, every time you open a .jsp(x) file you click on the source tab at the bottom of the window so that you can edit the jsp(x) file in source code mode, you may want to consider changing the default editor for that file type.  This is easy to do in the JDeveloper tool preferences and can be a time saver in the long run, since some editors can take a while to start up and if you don't need them often, this would just be lost time.  Here are the steps:  From the JDeveloper menu, select Tools->Preferences...Select "File Types" in the tree component on the left side of the preferences dialog.Click on the "Default Editors" tab.Scroll to the file type you want to change.In the details section at the bottom of the dialog, use the "Default Editor" select list to change the default to your liking.

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• Incremental file system backups

  - by brunopereira81

  I use Virtual Box a lot for distro / applications testing purposes. One of the features I simply love about it is virtual machines snapshots, its saves a state of a virtual machine and is able to restore it to its former glory if something you did went wrong without any problems and without consuming your all hard disk space. On my live systems I know how to create a 1:1 image of the file system but all the solutions I'v known will create a new image of the complete file system. Are there any programs / file systems that are capable of taking a snapshot of a current file system, save it on another location but instead of making a complete new image it creates incremental backups? To easy describe what I want, it should be as dd images of a file system, but instead of only a full backup it would also create incremental. I am not looking for clonezilla, etc. It should run within the system itself with no (or almost none) intervention from the user, but contain all the data of the file systems.

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• Conecting bash script with a txt file

  - by cathy

  I have a txt file with 100+ lines called page1.txt; odd lines are urls and even lines are url names. I have a bash file already created that checks urls for completion. Except right now, the process is really manual because I have to modify the bash every time I need to check a url. So I need to connect the bash to the txt using the variable url. $url should get all the odd lines from page1.txt and check if the link is complete or not. Also, how would I write a variable called name that derives from the url the 7 digits? bash file manually: url=http://www.-------------/-/8200233/1/ name=8200233 lynx -dump $url > $name.txt I would prefer if the bash file could add "Complete/In-Complete " at the beginning of every even line in the page1.txt file but a new text file could be also created to keep track of the Completes/In-completes.

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• How Hackers Can Disguise Malicious Programs With Fake File Extensions

  - by Chris Hoffman

  File extensions can be faked – that file with an .mp3 extension may actually be an executable program. Hackers can fake file extensions by abusing a special Unicode character, forcing text to be displayed in reverse order. Windows also hides file extensions by default, which is another way novice users can be deceived – a file with a name like picture.jpg.exe will appear as a harmless JPEG image file. Can Dust Actually Damage My Computer? What To Do If You Get a Virus on Your Computer Why Enabling “Do Not Track” Doesn’t Stop You From Being Tracked

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• How to remove unused usings from class file ?

  - by Samir R. Bhogayta

  When we create a .cs file means code file class is automatically create. That .cs file means class has default usings for namespace. using System;using System.Collections.Generic;using System.Linq;using System.Web;using System.Web.UI;using System.Web.UI.WebControls; We don't use all namespaces  in that class so we have to remove unused namespaces from file. We can remove  namespace manually but it takes time and need full knowledge of class library so we can use Visual Studio . Step 1:  Right Click in .cs File. Step 2:  Move on Organize usings. Step 3: Click on Remove Unused Usings. After that we have only those namespaces in the file these are using.  

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• Force Unity to open any file with any program

  - by Strae

  When you drag a file to the Unity launcher, only the applications that are supposed to open that file will remain active, while all others become deactivated. Is it possible to configure Unity to ignore that setting and open the file, no matter what extension the file has, with any of the applications on the launcher? I'd be glad to get an unsupported file type from the application when I make a mistake instead of losing a bunch of time configuring what application can open what file (that's because it is no longer possible to add a custom application/path in the Open with... menu)

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• OSX: The item XYZ.txt~ can’t be moved to the Trash because it can’t be deleted

  - by dsg

  I'm trying to delete a file under OSX Lion, but can't. I get the following message: The item XYZ.txt~ can’t be moved to the Trash because it can’t be deleted. Here's what I've tried: select file and press COMMAND + DELETE (I get the message above.) renaming the file in finder (There is no option to rename the file.) sudo ls -a in a terminal (The file does not appear.) sudo rm XYZ.txt~ (I get "No such file or directory".) How do I remove this file? EDIT The file went away after restarting. My guess is that it was a glitch in finder.

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• How can I only have a single move command in a batch file?

  - by PeanutsMonkey

  I have an existing batch file that attempts to move files from 2 directories to 2 different locations. At the moment these are called as 2 separate move commands. I am wanting to simply the code further and was wondering if there was a way to do so @echo off for %%a in (C:\Test\*.*) do if "%%~xa" == "" move /Y "C:\Test\%%~na%%~xa" "D:\Done" for %%i in (C:\Sample\*.*) do if "%%~xi" == "" move /Y "C:\Sample\%%~ni%%~xi" "D:\Done"

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• How do I set advanced file associations in Windows 7?

  - by Dan O

  It used to be in Windows XP that I could make Warcraft III files load automatically into the game by double clicking on them. This association was made by going to file associations ADVANCED area and using this line: "C:\Program Files\Warcraft III\War3.exe" -loadfile "%1" Note that it takes an argument and an option. However, in Windows 7, the "Default Programs" "Set Associations" area doesn't seem to have this advanced area. Can I still get these files to open automatically?

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• Powershell Copy-Item fails silently

  - by R W

  I have a powershell 2.0 script running on Windows Server 2008 R2 64bit that copies some Hyper-V .vhd files to another server as a 'backup solution'. The script gets a list of the .vhd's to copy then iterates over that list to copy them using Copy-Item. It also writes some logging info to a file as well. The files are copied to another server (Windows Server 2003 Sp2) into a directory compressed with NTFS compression. One of the files isn't copied. It's relatively big ~ 68Gb. The others are 20Gb or less. The wierd thing is that during the copy process the file appears on the destination server and the log file generated seems to indicate the file is copied due to the difference in the times of the log file entries. I see no error messages on the log file and nothing in the event log of either machine. Here's the code that does the copy. Get-ChildItem $VMSource *.vhd -Recurse | foreach-object { $time = Get-Date -format HH.mm.ss Add-Content $logFileName "$time : File Copy ($_) started" $fullname = $_.FullName Add-Content $logFileName "$time : Copying $fullname to $VMDestination" Copy-Item $fullname $VMDestination -Force -ErrorAction SilentlyContinue -ErrorVariable errors foreach($error in $errors) { if ($error.Exception -ne $null) { Add-Content $logFileName "'tERROR COPYING FILE : $($error.Exception)" } } $time = Get-Date -format HH.mm.ss Add-Content $logFileName "$time : File Copy ($_) finished" } I can only think there's some problem with copying a file that big to a compressed directory maybe? Any ideas?

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• How can I convert a large ANSI text file to UTF-8?

  - by mjustin

  For a database migration I need a tool which can convert a 1 GB file from Ansi codepage to UTF8 on Windows. Maybe I can use sed (given that I know all search and replace values), but is there something included in GNU or Windows tools?

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• gnu coreutils split verbose flushed?

  - by 130490868091234

  When using the GNU coreutils split command with verbose mode, how can I make the lines that appear in the STDOUT be flushed with respect to the time when the file has finally been created? Fore example, running it like this: ~/coreutils/bin/split --verbose -d -u -l 10000000 1>out & tail -f out creating file `x00' creating file `x01' creating file `x02' [...] I would have expected the line creating file 'x00' to have appeared in file out after the file has been completely written, but instead, it seems like nothing is written into out until the whole file has been finally processed. Is there a way to change this behavior?

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